write the equivalent of the fraction using a denominator of 52. 2/13

Given, Option A: Hourly wage is $19 and the salesperson works 40 hours per week. So, he will earn in a week [tex]\sf = 19 \times 40 = \$760[/tex]

Now, according to option b, he will get 8% commission on weekly sales.

Let. x = the amount of weekly sales.

To earn the same amount of option A, he will have to equal the 8% of x to $760

So, [tex]\sf \dfrac{8x}{100}=760[/tex]

Or, [tex]\sf 8x= 76000[/tex]

Or, [tex]\sf x= \dfrac{76000}{8}=9500[/tex]

the salesman needs to make a weekly sales of $9,500 to earn the same amount with two options.

As Jim has $30 more than Max, as per this, Max has $270.

Let's assume Max's savings as 'x' dollars.

We have:

2/5 of Jim's savings is equal to 4/9 of Max's savings.

(2/5) * Jim's savings = (4/9) * Max's savings

We also know that Jim has $30 more than Max.

Jim's savings = Max's savings + $30

So,

(2/5) * Jim's savings = (4/9) * Max's savings

(2/5) * (Max's savings + $30) = (4/9) * Max's savings

To solve for Max's savings, we can solve this equation:

(2/5) * (x + $30) = (4/9) * x

So, for x:

(2/5) * (x + $30) = (4/9) * x

Multiplying both sides by 45 (the least common denominator of 5 and 9) to eliminate the fractions:

18(x + $30) = 20x

18x + 540 = 20x

540 = 20x - 18x

540 = 2x

x = 270

Therefore, Max has $270.

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Equating the expressions, if Li Wei can read 30 pages in an hour and Colleen Henry 24 pages an hour, they will be on the same page in 6 hours.

Equivalent expressions are two or more algebraic expressions that have the same value when the variables are substituted with real numbers.

In this situation, we can determine the time that Li Wei and Colleen Henry can be on the same page by equating the expressions representing their reading rates.

The number of pages Li Wei can read in a week = 90

The number of pages Collen can read in a week = 126

Li Wei's reading rate per hour = 30 pages

Collen's reading rate per hour = 24 pages

Let the hours that Li Wei and Colleen can be on the same page= x

The total number of pages Li Wei can read = 90 + 30x

The total number of pages Colleen can read = 126 + 24x

For Li Wei and Colleen to be on the same, the two expressions are equated.

90 + 30x = 126 + 24x

6x =  36

x = 6

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Fractions such as 12 in/ 1 ft and 1 yd/ 3ft are called unit conversion fractions

Unit conversion fractions are used to convert between different units of measurement within the same quantity.

The fraction 12 in/1 ft represents the conversion factor from inches to feet, where 12 inches is equivalent to 1 foot.

This fraction allows us to convert a certain length measured in inches to an equivalent length in feet.

Similarly, the fraction 1 yd/3 ft represents the conversion factor from yards to feet, where 1 yard is equivalent to 3 feet.

This fraction allows us to convert a certain length measured in yards to an equivalent length in feet.

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Fill in each blank so that the resulting statement is true

Fractions such as 12 in/ 1 ft and 1 yd/ 3ft are called _________fractions

The phrase "possibly some ui are not free, or even do not occur, in ϕ" refers to a logical formula or expression ϕ that contains variables ui.

When it says "possibly some ui are not free," it means that not all of the variables ui in ϕ are unrestricted or unconstrained. Some of them may have certain conditions or restrictions placed on them within the context of the formula ϕ.

On the other hand, when it says "or even do not occur, in ϕ," it means that some variables ui may not appear at all in the formula ϕ. This implies that those variables are not present or relevant in the expression ϕ and do not play a role in its interpretation or evaluation.

In summary, the phrase indicates that in the formula ϕ, some variables ui may have restrictions or conditions placed on them, while others may not be present or relevant within the context of the formula.

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Answer:

Step-by-step explanation:

cos4α + 2 Sin² 2α is a trigonometric expression that involves the cosine and sine functions of the angle α. This expression can be simplified using trigonometric identities to get:

cos4α + 2 Sin² 2α = (cos² 2α)² + 2 (Sin 2α)²

This simplification involves using the double angle identity for sine and the identity for the square of cosine.

Brainliest Pls

Answer:1

Step-by-step explanation:

cos(4α) + 2sin²(2α)

First, let's expand cos(4α)

cos(4α) = cos²(2α) - sin²(2α)

Now, let's substitute this expression back into the original equation:

cos(4α) + 2sin²(2α) = (cos²(2α) - sin²(2α)) + 2sin²(2α)

= cos²(2α) + sin²(2α)=1 by

cos²(α) + sin²(α)=1

(Can't delete my answer)

Answer:

b

Step-by-step explanation:

Answer:

The correct statement is: The temperature of the object is decreasing exponentially by 0.007% each minute.

Step-by-step explanation:

The exponential term in the function, [tex]e^{0.007 h}[/tex], is greater than 1. This means that the temperature is increasing over time.

However, the exponent is very small, so the increase in temperature is very slow. In fact, the temperature is increasing by only -0.007% each minute.

We can use the following formula to calculate the percent change in temperature each minute.

[tex]\boxed{\bold{Percent\: change = \frac{(new \:value - \:old \: value) }{ old\:value }* 100\%}}[/tex]

In this case, the new value is the temperature after one minute, and the old value is the temperature at the start of the minute.

So, the percent change in temperature is:

[tex]= \frac{10 + 160e^{-0.007 * 1} - 10) }{ 10} * 100\%[/tex]

≈ -0.007%

Therefore, the temperature of the object is decreasing exponentially by 0.007% each minute.

The integer number that represents the situation running up 24 steps is given as follows:

+24.

Integer number are numbers that can have either positive or negative signal, but are whole numbers, meaning that they have no decimal part.

For altitudes, the signs are given as follows:

In this problem, we have an increase of altitude of 24 steps, hence the integer number is given as follows:

+24.

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The side lengths for the triangle are given as follows:

Suppose that we have two points of the coordinate plane, and the ordered pairs have coordinates [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex].

The shortest distance between them is given by the equation presented as follows, derived from the Pythagorean Theorem:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Then the length AC is given as follows:

[tex]AC = \sqrt{(5 - (-7))^2 + (0 - 3)^2}[/tex]

AC = 12.4.

The length AB is given as follows:

[tex]AB = \sqrt{(-3 - (-7))^2 + (6 - 3)^2}[/tex]

AB = 5.

The length BC is given as follows:

[tex]BC = \sqrt{(5 - (-3))^2 + (6 - 0)^2}[/tex]

BC = 10.

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(a) Probability of getting a flush is 0.000546.

(b) Probability of getting three of a kind is 0.00451.

(c) Probability of getting two pairs is 0.0150.

We have,

(a)

To calculate the probability of getting a flush, we need to determine the total number of possible outcomes and the number of favorable outcomes.

Total number of balls = 11 (red) + 11 (yellow) + 11 (green) + 11 (black) = 44 balls

The number of ways to choose 4 balls (without replacement)

= 44C4 = 44! / (4! x (44 - 4)!) = 44! / (4! x 40!)

= 44 x 43 x 42 x 41 / (4 x 3 x 2 x 1)

= 7315

The number of favorable outcomes:

There are 4 different colors of balls, so we have 4 possible flushes (all red, all yellow, all green, all black).

Probability of getting a flush = Number of favorable outcomes / Total number of outcomes = 4 / 7315 ≈ 0.000546

(b)

To calculate the probability of getting three of a kind, we need to determine the total number of possible outcomes and the number of favorable outcomes.

Total number of ways to choose 4 balls = 44C4 = 7315 (as calculated in part (a)).

Number of ways to choose 3 balls of the same denomination: We have 11 denominations, so we can choose 3 balls of the same denomination in 11C1 = 11 ways.

Number of ways to choose the fourth ball of a different denomination: After choosing 3 balls of the same denomination, we have 3 denominations left from which we can choose the fourth ball. So, the number of ways to choose the fourth ball = 3.

Number of favorable outcomes = Number of ways to choose 3 balls of the same denomination x Number of ways to choose the fourth ball of a different denomination

= 11 x 3

= 33

Probability of getting three of a kind = Number of favorable outcomes / Total number of outcomes = 33 / 7315 ≈ 0.00451

(c)

To calculate the probability of getting two pairs, we need to determine the total number of possible outcomes and the number of favorable outcomes.

Total number of ways to choose 4 balls = 44C4 = 7315 (as calculated in part (a)).

Number of ways to choose the first pair: We have 11 denominations, so we can choose the first pair in 11C1 = 11 ways.

Number of ways to choose the second pair: After choosing the first pair, we have 10 denominations left from which we can choose the second pair. So, the number of ways to choose the second pair = 10.

Number of favorable outcomes

= Number of ways to choose the first pair x Number of ways to choose the second pair

= 11 x 10

= 110

Probability of getting two pairs = Number of favorable outcomes / Total number of outcomes = 110 / 7315 ≈ 0.0150

Thus,

(a) Probability of getting a flush = 4/7315 ≈ 0.000546

(b) Probability of getting three of a kind = 33/7315 ≈ 0.00451

(c) Probability of getting two pairs = 110/7315 ≈ 0.0150

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The five number summary of the data set for the box plot would be :

First, order the numbers in ascending order:

2, 8, 9, 11, 14, 15, 17, 19, 20

The minimum is the smallest number which is 2. The maximum is the largest number which is 20.

The median is the number in the middle which is 19. The Q1 is the number in the middle of the first half of the numbers which is 9. The Q3 is the number in the middle of the second half which is 19.

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Answer:

min=2

1st quartile= 8.5

median=14

3rd quartile=18

max=20

Step-by-step explanation:

The value of Sin A is 5/13.

Option A is the correct answer.

We have,

Sin A = Perpendicular / Hypotenuse

Sin A = BC / AB

And,

BC = 5

AB = 13

Substituting.

Sin A = 5/13

Thus,

The value of Sin A is 5/13.

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Our initial assumption that for every vertex u in T, the distance between u and v is greater than (n-1)/2 must be false. Thus, there must exist a vertex u in T such that the distance between u and v is at most (n-1)/2.

To prove that there exists a vertex u in tree T such that the distance between u and v is at most (n-1)/2, we can use a proof by contradiction.

Assume that for every vertex u in T, the distance between u and v is greater than (n-1)/2.

Since T is a tree with n vertices, it has n-1 edges. We can select a longest path P in T, which has a length of at least n-1. Let's denote the endpoints of this path as u and w, where u is the starting vertex and w is the ending vertex.

Now, consider the distance between u and v. Since we assumed that the distance between any vertex u and v is greater than (n-1)/2, the distance between u and v must be greater than (n-1)/2.

However, let's consider the distance between w and v. Since the path P is the longest path in the tree, the distance between w and v must be greater than or equal to the length of path P, which is at least n-1.

Now, let's consider the total number of vertices in the tree, which is n. Since n is an odd integer, (n-1)/2 is an integer as well.

If the distance between w and v is greater than or equal to n-1, and (n-1)/2 is an integer, then there must be a contradiction. This is because the distance between w and v is greater than (n-1)/2, violating our assumption.

Therefore, our initial assumption that for every vertex u in T, the distance between u and v is greater than (n-1)/2 must be false. Thus, there must exist a vertex u in T such that the distance between u and v is at most (n-1)/2.

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The total surface area of the cylinder is 414.7 cm².

The curved surface area of the cylinder is calculated as follows;

C.S.A = 2πrh

where;

The curved surface area of the cylinder is calculated as;

C.S.A = 2π(6 cm) x (5 cm)

C.S.A = 188.5 cm²

The total surface area of the cylinder is calculated as follows;

T.S.A = 2πrh + 2πr²

circular area = 2πr² = 2π x (6cm)² = 226.2 cm²

The total surface area = 188.5 cm² + 226.2 cm² = 414.7 cm²

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1 cm = 10 mm. Length of book : 28 cm. Length of book = 280 mm. This shows that measurements in mm are the same but look to have a higher number .

The conversion factor provided states that 1 cm is equal to 10 mm, which means that 1 cm is made up of 10 individual millimeters.

The length of my book in when measured in millimeters is 280 mm.

In centimeters, this is therefore:

= 280 mm / 10 cm /mm

= 28 cm

Although the numerical value appears higher when expressed in millimeters, it is important to note that the actual length of the book remains the same.

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a) The fourth and sixth data points have significantly different ratios.

a) Let's calculate the ratios:

For the first data point:

= 11.5 gallons / $25.23 = 0.4555 gallons per dollar

For the second data point:

= 7.2 gallons / $15.80 = 0.4557 gallons per dollar

For the third data point:

= 10 gallons / $21.94 = 0.4556 gallons per dollar

For the fourth data point:

= 14.3 gallons / $40.63 = 0.3519 gallons per dollar

For the fifth data point:

= 6.8 gallons / $14.92 = 0.4555 gallons per dollar

For the sixth data point:

= 9.7 gallons / $27.56 = 0.3517 gallons per dollar

However, the fourth and sixth data points have significantly different ratios.

b) If the relationship is not proportional, the data values that should be changed to make the relationship proportional are the fourth and sixth data points.

The difference in ratios could be explained by factors such as fluctuations in gas prices or differences in gas grades.

To establish a proportional relationship, it would be necessary to collect data where the price per gallon remains constant for all data points or to separate the data based on gas grades and analyze each grade separately.

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Answer:

details:

54)Write the midpoint formula::

Substitute

into

::

Swap the sides:

Swap the sides:

Multiply both sides of the equation by the common denominator:

Reduce the fractions:

Multiply both sides of the equation by the common denominator:

Reduce the fractions:

Calculate the product or quotient:

Rearrange variables to the left side of the equation:

Calculate the sum or difference:

Express solutions in ordered pairs::

(55)Write the midpoint formula::

Substitute

into

::

Swap the sides:

Swap the sides:

Multiply both sides of the equation by the common denominator:

Reduce the fractions:

Multiply both sides of the equation by the common denominator:

Reduce the fractions:

Calculate the product or quotient:

Rearrange variables to the left side of the equation:

Calculate the sum or difference:

Express solutions in ordered pairs::

(56)Write the midpoint formula::

Substitute

into

::

Swap the sides:

Swap the sides:

Multiply both sides of the equation by the common denominator:

Reduce the fractions:

Multiply both sides of the equation by the common denominator:

Reduce the fractions:

Calculate the product or quotient:

Rearrange variables to the left side of the equation:

Calculate the sum or difference:

Express solutions in ordered pairs::

(57)Write the midpoint formula::

Substitute

into

::

Swap the sides:

Swap the sides:

Multiply both sides of the equation by the common denominator:

Reduce the fractions:

Multiply both sides of the equation by the common denominator:

Reduce the fractions:

Calculate the product or quotient:

Rearrange variables to the left side of the equation:

Calculate the sum or difference:

Express solutions in ordered pairs::

The angle that is not a solution to the trigonometric equation sin(2θ) = 1 is given as follows:

a) 90º.

The trigonometric equation in the context of this problem is defined as follows:

sin(2θ) = 1

The sine assumes a value of 1 at:

90º.

Hence the solution is obtained as follows:

2θ = 90º.

θ = 45º.

The equivalent angle to 45º on the third quadrant is given as follows:

Hence 225º and -135º are also solutions to the trigonometric equation.

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To achieve a mean of 78 with four scores, the fourth score must be 90.

We need to consider the current mean, the number of tests, and the desired mean in order to find the fourth score needed to achieve a mean of 78

Let's assume the three test scores are x1, x2, and x3.

We know that the mean of these three scores is 74. So we can assume that

The sum of these numbers is 74 or

(x1 + x2 + x3)/3 = 74

Let's denote it as x4 ,to find the fourth score we will use the formula to calculate the mean:

(x1 + x2 + x3 + x4)/4 = 78

To solve for x4, we can rewrite it as:

x1 + x2 + x3 + x4 = 78 * 4

Now, we can substitute the value of the mean of the first three scores into the equation:

(x1 + x2 + x3) + x4 = 312

we know that,

(x1 + x2 + x3) = 3 * 74

or,

3 * 74 + x4 = 312

Simplifying this, we get:

222 + x4 = 312

Subtracting 222 from both sides:

x4 = 312 - 222

x4 = 90

Therefore, to achieve a mean of 78 with four scores, the fourth score must be 90.

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Dana had to pay her friend $900, 3 months ago, and she has to pay $580 in 3 months. If her friend was charging her an interest rate of 1.50% per month. $1499.45, single payment would settle both payments today.

Given:

Simple interest = Principal × Rate × Time

Simple interest = $900 × 0.015 × 3

Simple interest = $40.50

Present Value = Future Value / (1 + Rate x Time)

Present Value = $580 / (1 + 0.015 × 3)

Present Value = $580 / 1.045

Present Value = $558.95

Total amount $580 loan is $558.95.

Total amount owed = $940.50 + $558.95

Total amount owed = $1499.45

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i) The monthly basic salary of the married COAS General is Rs 79,200.

ii. Taxable Income = Rs 1,60,400 - Rs 57,920 = Rs 1,02,480

iii. The total income tax paid by him is Rs 24.8.

His taxable income can be calculated as follows:

Total Monthly Income = Rs 79,200 + Rs 2,000 + Rs 79,200 = Rs 1,60,400

EPF Contribution = 10% of Basic Salary = 10% of Rs 79,200 = Rs 7,920

Life Insurance Premium = Rs 50,000

Total Deductions = EPF Contribution + Life Insurance Premium = Rs 7,920 + Rs 50,000 = Rs 57,920

Taxable Income = Total Monthly Income - Total Deductions

Taxable Income = Rs 1,60,400 - Rs 57,920 = Rs 1,02,480

For income up to Rs 6,00,000: No income tax

For income between Rs 6,00,001 and Rs 8,00,000: 1% of the amount exceeding Rs 6,00,000

Taxable Income in this slab = Rs 2,480 (Rs 1,02,480 - Rs 6,00,000)

Income tax for this slab = 1% of Rs 2,480 = Rs 24.8

Therefore, the total income tax paid by him is Rs 24.8.

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Answer:

C

Step-by-step explanation:

the expression ! ( factorial ) has the following meaning

n! = n(n - 1)(n - 2) ... × 3 × 2 × 1

Then

4! = 4 × 3 × 2 × 1 = 24

The property that should be used to simplify the expression 1/t⁻³ is [tex]\frac{1}{a^-m}[/tex] = [tex]a^m[/tex] (where a ≠ 0). Option A

In the given scenario or expression, this property implies that 1/t⁻³ = t³. The negative exponent in the denominator becomes a positive exponent when moved to the numerator.

Here is the step-by-step solution

1/t⁻³ = 1/(t⁻³)

1/(t⁻³) = (t⁻³)⁻¹

(t⁻³)⁻¹ = t⁽⁻³⁾ˣ⁽⁻¹⁾

t⁽⁻³⁾ˣ⁽⁻¹⁾ = t³

Therefore, the simplified expression is t³.

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Answer:

x+1

Step-by-step explanation:

you have to rewrite the equestion, factor the expression, and than reduce it

Answer:

Step-by-step explanation:

To estimate the original volume of the pyramid, we can use the formula for the volume of a frustum of a pyramid:

V = (1/3)h(a^2 + ab + b^2)

Where V is the volume, h is the height of the frustum, a is the side length of the top square, and b is the side length of the bottom square.

In this case, the top square has a side length of 4 m, and the bottom square has a side length of 20 m. The height of the frustum is 12 m.

Plugging these values into the formula, we get:

V = (1/3) * 12 * (4^2 + 4*20 + 20^2)

Simplifying the equation:

V = (1/3) * 12 * (16 + 80 + 400)

V = (1/3) * 12 * 496

V = 12 * 496/3

V = 1984

Therefore, the estimated original volume of the pyramid is 1984 cubic meters.

Answer:

  23/41

Step-by-step explanation:

You want to know the fraction who failed, given they predicted they would fail.

The attached 2-way table shows the given numbers (black) and the numbers that make the totals correct (blue).

It shows 23 of the 41 who thought they would fail actually did. That fraction is ...

  23/41 . . . . failed who thought they would

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