Write short notes on a. Transaction Processing System (TPS)

Answer:

Explanation:

It is very important for the organisation to implement maximum security to the infrastructure. The main data totally belongs to the customers which mainly has customers' personal information and bank details. So, here are few things that needs to be look at as a security expert:

Encryption: the implementation of encryption tool to encrypt the data especially passwords and card details of the customer will be help in securing the infrastructure. Encryption makes it hard for anyone to be able decrypt the actual data.

Firewall: This is the beginning stage of implementing security to an infrastructure. Firewall will help greatly in blocking traffic that are unwanted from entering into the infrastructure. This also blocks untrusted traffic to the application server too.

SSL certificate: Implementation of SSL certificate to the website or the application will help greatly in securing and protecting the application for you against online hackers.

Every device belongs to your system must be implemented with anti-malware softwares that can able to detect malware present in the system.

Which of the following groups is NOT located on the Home tab?

Animations

Answer:

All the data and information that was updated or added since then will be lost so it is useless to restore a Domain Controller that was backedup twelve months ago.

Explanation:

A domain conttoller back-up must be prepared on regular basis else if DC breaks, restoration of most recent database will be impossible.

If Stephi owns a footwear store and she wants to create a graph of the number of sneakers sold, and she copies the Sneaker Sales query results from the database, her next step will be: pasting the query results into a spreadsheet.

Spreadsheets are known for their automatic graph-producing features. This means that if you have a result from a table that is obtained from a query, you can plot the result in any kind of graph if the table is transferred to a spreadsheet.

So, for Stephi to plot the graph, she should copy and paste the result into a spreadsheet.

Learn more about spreadsheets here:

https://brainly.com/question/4965119

#SPJ4

Answer:

With the analysis of the case, we can infer that regarding the model or algorithm of the work set, we want to reduce page faults in each individual process, guaranteeing that the set of pages are included before executing the process.

There are things that should not change, such as the set of pages used in the process or the working set as they are called, they could only change if a program moves to a different phase of execution. In this way the most suitable and profitable approach is proposed for the use of time in the processor, by avoiding bringing oagines from the hard disk and instead of this the process is executed, because otherwise it would take a long time what was observed in decreased performance.

Regarding what was mentioned in the question, it follows that 2 extremes lead to a problematic behavior, to define the first as a page fault and the second refers to a small number of processes executed.

Answer:

The second last point i.e "Data warehouse data are often stored in a dimensional databased " is the correct answer to the given question .

Explanation:

The main objective of the operation applications is implemented and enable the handling of large volumes transactions where as the data warehouses objective of the applications is implemented and enable the handling of large volumes of analytical transactions.

Answer:

The program in cpp for the given scenario is shown.

#include <iostream>

using namespace std;

int main()

{

   //variables declared to hold individual and total scores

   int score_a=0, a;

   int score_b=0, b;

   //user input taken for score

   for(int i=0; i<4; i++)

   {

       std::cout << "Enter team A score in quarter " <<(i+1)<<" : ";

       cin>>a;

       score_a = score_a+a;

       std::cout << "Team A score so far: "<< score_a <<std::endl;

       std::cout << "Enter team B score in quarter " <<(i+1)<<" : ";

       cin>>b;

       score_b = score_b+b;

       std::cout << "Team B score so far: "<< score_b <<std::endl;

   }

   //winner team decided by comparing scores

   if(score_a>score_b)

       std::cout << "Team A has won" << std::endl;

   if(score_a==score_b)

       std::cout << "It is a tie." << std::endl;

   if(score_a<score_b)

       std::cout << "Team B has won" << std::endl;

   //program ends

   return 0;

}

Explanation:

1. The integer variables are declared to hold both individual scores and the total score for both the teams.

   int score_a=0, a;

   int score_b=0, b;

2. The variables to hold total scores are initialized to 0.

3. Inside for loop, scores for both teams for all 4 quarters are taken from the user.

4. Inside the same for loop, a running total for the score of each team is computed and displayed.

score_a = score_a+a;

score_b = score_b+b;

5. Outside the loop, the total scores of both the teams are compared and the winner team is displayed. This is done using multiple if statements.

if(score_a>score_b)

       std::cout << "Team A has won" << std::endl;

   if(score_a==score_b)

       std::cout << "It is a tie." << std::endl;

   if(score_a<score_b)

       std::cout << "Team B has won" << std::endl;

6. After each message is displayed, a new line is inserted at the end using keyword, endl.

7. The program ends with a return statement.

8. The whole code is written inside main(). In cpp, it is not mandatory to write the code inside a class since cpp is not a purely object-oriented language.

9. The output is attached in an image.

Answer:

Let's implement the program using JAVA code.

import java.util.*;

import java.util.ArrayList;

import java.io.*;

public class ScrambledStrings

{

/** Scrambles a given word.

* atparam word the word to be scrambled

* atreturn the scrambled word (possibly equal to word)

* Precondition: word is either an empty string or contains only uppercase letters.

* Postcondition: the string returned was created from word as follows:

* - the word was scrambled, beginning at the first letter and continuing from left to right

* - two consecutive letters consisting of "A" followed by a letter that was not "A" were swapped

* - letters were swapped at most once

*/

public static String scrambleWord(String word)

{

// iterating through each character

for(int i=0;i<word.length()-1;)

{

//if the condition matches

if(word.charAt(i)=='A' && word.charAt(i+1)!='A'){

//swapping the characters

word=word.substring(0,i)+word.charAt(i+1)+word.charAt(i)+word.substring(i+2);

//skipping the letter

i+=1;

}

//skipping the letter

i+=1;

}

return word;

}

Explanation:

Note: Please replace the "at" on the third and fourth line with at symbol that is shift 2.

Answer:

Explanation:

import java.util.Scanner;

import java.io.*;

public class ArrayProcessing

{

public static void main(String[] args) throws IOException

{

Scanner kb = new Scanner(System.in);

String fileName;

System.out.print("Enter input filename: ");

fileName = kb.nextLine();

File file = new File(fileName);

if(!file.exists())

{

System.out.println("There is no input file called : " + fileName);

return;

}

int[] numbers = inputData(file);

printArray(numbers);

}

public static int[] inputData(File file) throws IOException

{

Scanner inputFile = new Scanner(file);

int index = 1;

int size = inputFile.nextInt();

int[] values = new int[size];

while(inputFile.hasNextInt() && index < values.length)

{

values[index] = inputFile.nextInt();

index++;

}

inputFile.close();

return values;

}

public static void printArray(int[] array)

{

int count = 1;

for (int ndx = 1; ndx < array.length; ndx++)

{

System.out.printf("%5.f\n", array[ndx]);

count++;

}

if(count == 10)

System.out.println("");

}

}

Answer:

import java.io.File;

import java.io.FileInputStream;

import java.io.FileNotFoundException;

import java.io.FileOutputStream;

import java.io.IOException;

import java.util.Scanner;

public class EncryptFileData

{

public static void main(String args[]) throws IOException, FileNotFoundException

{

String inputFileName="input.txt";

String outputFileName="EncryptedFile.txt";

String decryptFileName="DecryptedFile.txt";

byte codeValue;

Scanner sc=new Scanner(System.in);

//Accept code value from user

System.out.println("Enter the value of code");

codeValue=sc.nextByte();

//Encrypt the input file

encryptFileContent(inputFileName, codeValue,outputFileName);

//Decrypt the input file

decryptFileContent(outputFileName, codeValue,decryptFileName);

}

//function to encrypt the input file

private static void encryptFileContent(String inputFileName,

byte encodeValue, String outputFileName) throws IOException, FileNotFoundException{

File file = new File(inputFileName);

FileInputStream fin = new FileInputStream(file);

FileOutputStream fout = new FileOutputStream(outputFileName);

try{

while(fin.available() != 0){

int inData = fin.read();

//For every character in input add code value and

//write result to file "EncryptedFile.txt"

fout.write(inData+encodeValue);

}

}finally{

fin.close();

fout.close();

}

}

//function to decrypt the encrypted file

private static void decryptFileContent(String inputFileName,

byte encodeValue, String outputFileName) throws IOException, FileNotFoundException{

File file = new File(inputFileName);

FileInputStream fin = new FileInputStream(file);

FileOutputStream fout = new FileOutputStream(outputFileName);

try{

while(fin.available() != 0){

int inData = fin.read();

//For every character in encrypted file

//subtract the code value from each character and

//write it to file "DecryptedFile.txt"

fout.write(inData-encodeValue);

}

}finally{

fin.close();

fout.close();

}

}

}

Explanation:

Given the following conditions to follow in the question;

=> "The encryption program should work like a filter, reading the contents of one file, modifying the data into code, and then writing the code contents out to a second file. "

=> "The second file will be a version of the first file, but written in a secret code."

Thus, the Java code is given below(one can just copy and run it to give a sample output of: Enter the value of code 1 2.

The Java code is;

import java.io.File;

import java.io.FileInputStream;

import java.io.FileNotFoundException;

import java.io.FileOutputStream;

import java.io.IOException;

import java.util.Scanner;

public class EncryptFileData

{

public static void main(String args[]) throws IOException, FileNotFoundException

{

String inputFileName="input.txt";

String outputFileName="EncryptedFile.txt";

String decryptFileName="DecryptedFile.txt";

byte codeValue;

Scanner sc=new Scanner(System.in);

//Accept code value from user

System.out.println("Enter the value of code");

codeValue=sc.nextByte();

//Encrypt the input file

encryptFileContent(inputFileName, codeValue,outputFileName);

//Decrypt the input file

decryptFileContent(outputFileName, codeValue,decryptFileName);

}

//function to encrypt the input file

private static void encryptFileContent(String inputFileName,

byte encodeValue, String outputFileName) throws IOException, FileNotFoundException{

File file = new File(inputFileName);

FileInputStream fin = new FileInputStream(file);

FileOutputStream fout = new FileOutputStream(outputFileName);

try{

while(fin.available() != 0){

int inData = fin.read();

//For every character in input add code value and

//write result to file "EncryptedFile.txt"

fout.write(inData+encodeValue);

}

}finally{

fin.close();

fout.close();

}

}

//function to decrypt the encrypted file

private static void decryptFileContent(String inputFileName,

byte encodeValue, String outputFileName) throws IOException, FileNotFoundException{

File file = new File(inputFileName);

FileInputStream fin = new FileInputStream(file);

FileOutputStream fout = new FileOutputStream(outputFileName);

try{

while(fin.available() != 0){

int inData = fin.read();

//For every character in encrypted file

//subtract the code value from each character and

//write it to file "DecryptedFile.txt"

fout.write(inData-encodeValue);

}

}finally{

fin.close();

fout.close();

}

}

}

Answer:

Following are the method to this question:

void selectionSort(string strArr[], int s) //defining selectionSort method

{

int i,ind; //defining integer variables

string val; //defining string variable

for (i= 0; i< (s-1);i++) //defining loop to count value

  {

      ind = i; //assign loop value in ind variable

      val = strArr[i]; // strore array value in string val variable

      for (int j = i+1;j< s;j++) // defining loop to compare value

      {

          if (strArr[j].compare(val) < 0) //using if block to check value

          {

              val = strArr[j]; //store value in val variable  

              ind= j; //change index value

          }

      }

      strArr[ind] = strArr[i]; //assign string value in strArray  

      strArr[i] = val; // assign array index value

  }

}

void print(string strArr[], int s) //defining print method

{

  for (int i=0;i<s;i++) //using loop to print array values

  {

      cout << strArr[i] << endl; //print values

  }

  cout << endl;

}

Explanation:

In the above-given code, two methods "selectionsort and print" is declared, in which, both method stores two variable in its parameter, which can be described as follows:

Answer:

The answer is "Option c".

Explanation:

The Embedded T1 also known as channelized T1, it is a digital modulation system in which a T1 channel is split into 24 channels, in which each has the maximum connection speeds of 64,000 bits per second (Kbps) each of capable of supporting a specific application, which can run simultaneously to, but separately of, other programs on various channels, in this channelized T-1  the frame length is 193 bits long, and wrong choices can be described as follows:

Hi!

I'm Happy to help you today!

The answer to this would be 20%!

The reason why is because percents are simple to make! Like theres always an end percent! But its always gonna end at 100% Let me show you some examples to help you understand!

So were gonna have the end percent at 100%

Lets turn 2 into a percent!

2 = 2% because its under 100%

Now lets go into a Higher number like 1000%

So lets turn 33 into a percent!

33 = 3.3% 30 turns into 3% because of the max percent of 1000% and then 3 turns into .3% because of the max of 1000%

I hope this helps!

-LimitedLegxnd

-If you enjoyed my answer make sure to hit that Heart! Also Rate me to show others how well i did! You can do that by clicking the stars!

-Question asker mark me brainliest if you really enjoyed my answer!

Answer:

See attached images

Answer:

=> E-mail is sent using SMTP server by using command such as;

telnet smpt.server.name 25.

(Where 25 = port and telnet smpt.server.name = name of the server).

Explanation:

Date: June 2, 2020.

To: The vice president.

From: Codedmog101

SUBJECT: E-mail Forging.

Due to the recent issue going on in the company concerning an employee sending a message to you, I saddled with the responsibility of writting to you the steps an employee might have taken to create an e-mail message and make it appear to come from another employee’s account.

(1). The SMTP servers can be configured in such a way that it can be used by spammers to send message to another person(recipient) and it will look like it is not the spammer that sent it.

(2). The person spamming another person will use an unsecured SMTP servers with command such as the one given below;

telnet smpt.server.name 25.

(3). Once (2) has been connected, the spammer can then input the e-mail of the person he or she is spamming.

(4). The recipient address will be type in by the spammer too

(5). The subject, date and the body then enter.

(5). After (5) above the message will be sent to the recipient from the spammer but it will indicate another person.

These are the steps taken to create an e-mail message and make it appear to come from another employee’s account.

Best regards,

Codedmog101

Answer:

// This program is written in C++

// Comments are used for explanatory purposes

// Program starts here

#include<iostream>

using namespace std;

int main()

{

// Declare Variable name

string name;

// Prompt user for input

cout<<"Enter your name: ";

cin>>name;

// Print name

cout<<"Hello, "<<name<<"!\n";

// Print length of name

cout<<"Your name is "<<name.length()<<" letters long\n";

// Print first character

cout<<"Your name starts with a "<<name.at(0)<<"\n";

// Print last character

cout<<"Your name end with a "<<name.at(name.length()-1)<<"\n";

cout<<"Goodbye!";

return 0;

}

Answer:

The public phone box transmit electronic signals through cable while cell phones transmit electromagnetic signals wirelessly.

Explanation:

Public phone boxes are reserved booth for making calls. It uses dial tone frequency to tap to a receiver's frequency. They use a dedicated cable line to transmit electronic signals to a central automatic switch that relays the signal to the recipient's line.

A cell phone has antennas that transmits the electromagnetic wave signal to a cell tower, which in turn transmit to other towers to locate the receiver. The receiver's antenna receives the signal and connection is made.

Answer:

a. 2171

b. 2172

c .3172

Explanation:

a . As we know that sequence number is 32 bits has a two responsibility

Initially the sequence number at the client site is 2,171 that is equals to the he SYN segment i.e 2171.

b  The data segment is determined by the following formula

[tex]=sequence \ number\ in\ the\ client site\ +\ 1[/tex]

[tex]=2,171 +1[/tex]

[tex]=2172[/tex]

c As mention in the question there are  1,000 bytes of data,

so  FIN segment can be determined by the

[tex]=2171+1000+1[/tex]

[tex]=3172[/tex]

Answer: Xbox because ps4 has more people on it.

Explanation: for example if I had 2 computer and 1 computer it will be easier to make servers on the one computer

Answer:

pseudocode

Explanation:

it says the answer in the question

Answer:

B:  pseudocode

Explanation:

Answer:

The choices we make as citizens online or in real life have both positive and negative effects on others because we are social beings, who live in an interconnected world.  Every choice has some consequences on the decision maker or on others.  We make the choices, but the consequences follow natural laws, which we cannot control.  When Adam and Eve chose to disobey God, human beings down the ages lost their innocence and freedom.  When the Nazis chose to purify their race of European Jews, there was the Holocaust between 1941 and 1945.  When the Minneapolis police officer chose to slaughter George Floyd in cold blood, violent protests erupted throughout the U.S.

Another current example to buttress this is the ravaging coronavirus pandemic, which originated in Wuhan - China.  When the Chinese Communist  government chose to suppress the information about the virus as it usually does, the aftermath is the thousands of dead humans all over the world, the economic downturn, loss of jobs, virus infections with other public health side effects, plus many other untold consequences.

Had the Chinese government made a different choice, the virus could not have spread worldwide as it had.  Similarly, some citizens online choose to circulate unverifiable ("fake news") information.  Many people have been misled by their antics, some have lost their lives, while many others live in perpetual bigotry and hatred.  All these are because of individual choices.

Explanation:

Choice is a concept in decision making.  It is the judging of the merits of multiple options so that one or some of the options are selected.  When a voter votes for one candidate against others, she has made a choice (decision).  Of course, choices have consequences, which we must live with.  Choices also define our present and our future.

Answer:

Following are the code to this question:

#include <iostream> //defining header file  

using namespace std;

void numbers(ostream &outs, const string& prefix, unsigned int levels); // method declaration

void numbers(ostream &outs, const string& prefix, unsigned int levels) //defining method number

{

string s; //defining string variable

if(levels == 0) //defining condition statement that check levels value is equal to 0

{

outs << prefix << endl;  //use value

}

else //define else part

{

for(char c = '1'; c <= '9'; c++) //define loop that calls numbers method

{

s = prefix + c + '.'; // holding value in s variable  

numbers(outs, s, levels-1); //call method numbers

}

}

}

int main() //defining main method

{

numbers(cout, "THERBLIG", 2); //call method numbers method that accepts value

return 0;

}

Output:

please find the attachment.

Explanation:

Program description:

Answer:

True

Explanation:

There are usually thousands of line of code and the programmers have to account for serveral different things. For that reason, most complex games will have at least some bugs.

Answer:

A python script:

months = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

numbers = [31,28,31,30,31,30,31,31,30,31,30,31]

counter = 0

numbers_length=len(numbers)-1

while counter <= numbers_length:

month=months[counter]

number=numbers[counter]

print (month + " has " + str(number) + " days")

counter = counter+1

Explanation:

The Python script above will generate this output:

January has 31 days.

February has 28 days.

March has 31 days.

April has 30 days.

May has 31 days.

June has 30 days.

July has 31 days.

August has 31 days.

September has 30 days.

October has 31 days.

November has 30 days.

December has 31 days.

Answer:

Project life cycle is the time taken to complete a project, from start to finish.

The three project life cycles model include the following:

Explanation:

Predictive project life cycles model: In this stage, the three major constraints of the project which are the scope, time and cost are analyzed ahead of time and this analysis is well detailed and the detailed scope of the project is done right from the start of the project.

Iterative and Incremental life cycles model: In this iterative and incremental model, the project is again split into stages that can be sequential or overlapping and at the first iteration of the project, the scope is determined ahead of time.

Adaptive life cycles model: Also in this stage, the project is split up into phases but because these phases are more rapid and ever changing unlike the other models, the processes within the scope can work in parallel.

Similarities

Differences

Answer:

similarities :  They all are brought in to the world somehow.

They all have difreant stages to become an adult.

Difreances: They have difreant number of stages till they become an adult.

they all have difreant lypes of growing their bodies do.

Explanation:

Answer:

its A C E

Explanation:

Answer:

num = 0

while (num < 50):

if (num is Odd)

print(num is Odd)

num = num + 1

num = 0

repeat:

if (num is Odd)

print(num is Odd)

num = num + 1

until (num>=50)

Answer:

a form

Explanation:

it says the answer already in the question

Answer:

Intune is a software that helps windows patching and upgrades. once the computer is connected to the internet/network. Intune will download updates to a particular computer that is targeted.

Explanation:

Solution

Intune is software that provides windows patching by discovering the PC’s connected to the network, pushing latest upgrades to the PC’s and detecting their current patch level.

Intune will make the updates download in the PC targeted when the PC’s are connected to the internet. Once they are downloaded it will wait until the PC gets restarted. If not it will give a popup that updates needs to be downloaded and will provide a timeline like two hours after which the PC by itself will auto restart.

All these can automatically be managed or done by the software. only it is required to be configured in a way that the PC’s should will be updated within 1 day, and Intune will use its algorithm to calculate the restart time and do the rest work on it's own.