write an algebraic expression for 2 less than twice a n

Answer:

-2151

Step-by-step explanation:

f(x) = –15x^2+9.

Let x = 12

f(12) = -15 ( 12)^2 +9

       = -15 (144) +9

       = -2151

Answer:

-2151

Step-by-step explanation:

F(x) = -15x^2 + 9

F(12) = -15 (12)^ 2 + 9

= -15 * 144 + 9

= -2160 + 9

= -2151

Answer:

1/12

Step-by-step explanation:

There is a 1/6 probability of getting a 3 on a dice roll because there are 6 sides, and there is a 1/2 probability of flipping a tails because there are only 2 possibilities in a coin, if you multiply these 2 values you get 1/12 which is the answer.  

Answer:

A.

Explaintion:

n=13. 13+2 = 15

I hope this helps ( :

Answer: B

Step-by-step explanation:

because 4 is the number of (n) plus the 2

Answer:

A ≥ D

Step-by-step explanation:

answer:

B. -7x2-2

add the numbers and variables together and combine like terms

Hey, actually I am new here, otherwise I was on brainly.in (India)....so can anyone tell me about some moderators here.....need help....

Answer:

Given:

Mean, u = 135

Sample size, n = 42

Sample mean, x' = 126

Standard deviation = 16

Significance level = 0.05

1) The null and alternative hypotheses:

H0 : u = 135 (the revenue per day is $135)

H1 : u < 135 (the revenue per day is less than $135)

2) In this case, we have a left tailed test.

Let's use the formula:

[tex] = \frac{x' - u}{s/ \sqrt{n}} = \frac{126 - 135}{16 / \sqrt{42}} = -3.645 [/tex]

t = - 3.645

Critical value: at a significance level of 0.05, left tailed test,

tcritical = -1.683

We reject null hypothesis, H0, since t calculated, -3.645 is less than tcritical, -1.683.

3) Given, a = 0.05, df = 41, left tailed test,

t-value = 2.02

For the corresponding confidence interval, we have:

[tex] CI = (x' - \frac{t * \sigma}{\sqrt{n}}, x' + \frac{t * \sigma}{\sqrt{n}}) [/tex]

[tex] CI = (126 - \frac{2.02 * 16}{\sqrt{42}}, 126 + \frac{2.02 * 16}{\sqrt{42}}) [/tex]

CI = (121.014, 130.986)

4) Conclusion:

We reject the estimated potential revenue advised by the consultant, H0, as it is too high, because the t-calculated falls in rejection region(i.e, less than critical value), also the upper limit of the confidence interval is less than $135.

Answer: 12

Step-by-step explanation:

If we have n people and we want to do groups of 4, the total number of different combinations is:

[tex]c = \frac{n!}{(n - 4)!4!}[/tex]

and we want find the smallest n such c > 365.

let's do it by brute force:

if n = 5, we have:

[tex]c = \frac{5!}{1!*4!} = 5[/tex]

if n = 6

[tex]c = \frac{6!}{2!*4!} = \frac{6*5}{2} = 15[/tex]

if n = 7

[tex]c = \frac{71}{3!*4!} = \frac{7*6*5}{3*2} = 35[/tex]

if n = 8

[tex]c = \frac{8!}{(4!*4!} = \frac{8*7*6*5}{4*3*2} = 70[/tex]

if n = 9

[tex]c = \frac{9!}{5!*4!} = \frac{9*8*7*6*5}{5*4*3*2} = 126[/tex]

if n = 10

[tex]c = \frac{10!}{6!*4!} = \frac{10*9*8*7}{4*3*2} = 210[/tex]

So you can see the patern here.

So we have the previous number multiplied by n and divided by n - 4

if n = 11

C = 210*11/(11- 4) = 330

if n = 12

C = 330*12/(12 - 4) = 495

Then the minimum number of members such we have more than 365 combinations is 12 members

A decimal

3.60555127546

Have a great day

Answer:

yes scalene as xy=7cm

xz=5cm

yz=2cm

Step-by-step explanation:

by the graph

hope this helps plzz mark me brainliest

Answer:

Scalene

Step-by-step explanation:

Let's find XY, XZ and YZ

XY = √[(6-5)^2 + (4-(-3)] = √[(1^2 ) + (7^2)]=√(1+49) =√50 = 7.0711

YZ = √[(5-5)^2 + (-3 -(-1))^2 ]=√[(0^2) + (-2)^2] =√(0 + 4) = 2

XZ = √[(6-5)^2 + (4-(-1)^2] = √[(1^2 ) + (5^2)]=√(1+25) =√26 = 5.099

By observation XY , XY and YZ are not the same; hence none of the sides is equal

A scalene triangle has no side equal

Answer:

22

Step-by-step explanation:

In the series 14 + 6 + (–2) + (–10) + . . . + (–154)

The gap between entities is 8.

Therefore number of entities between -10 and -154 = (154 - 10)/8 =18

Total number of terms in the series = 18 + 4 = 22

There are 22 terms in the given arithmetic series.

An arithmetic sequence is sequence of integers with its adjacent terms differing with one common difference.

If the initial term of a sequence is 'a' and the common difference is of 'd', then we have the arithmetic sequence as:

a, a + d, a +  2d, ... , a + (n+1)d, ...

Its nth term is

T_n = a + (n-1)d

(for all positive integer values of n)

In the given arithmetic series 14 + 6 + (–2) + (–10) + . . . + (–154)

The common difference between entities is 8.

Therefore, the number of entities between -10 and -154

= (154 - 10)/8

=18

The Total number of terms in the series = 18 + 4 = 22

Hence, there are 22 terms in the given arithmetic series.

Learn more about arithmetic sequence here:

https://brainly.com/question/3702506

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Answer: b/7>=26

Step-by-step explanation:

Answer:

[tex]\frac{b}{7} \geq 26[/tex]

Step-by-step explanation:

1) we are given "the quotient of b and 7", quotient means to divide and since b comes before 7 it must be [tex]\frac{b}{7}[/tex]

2) "greater than or equal to" means that the [tex]\frac{b}{7}[/tex] from earlier must be either greater than, or the same value as the following number so you use this sign: [tex]\geq[/tex]

3) 26 comes last in the problem meaning it must come after the [tex]\geq[/tex] sign

4) you then combine them together to get  [tex]\frac{b}{7} \geq 26[/tex] !

Hope this helps!

Answer:

x = 2; y = 3; z = 1

Step-by-step explanation:

For the first fertilizer (A) we can form the equation:

y + 2z = 5          

For the second fertilizer (B) we can form the equation:

x + 2y + 5z = 13

For the third fertilizer (C) we can form the equation:

x + 2z = 4

solving simulteneously:

y = 5 - 2z

x = 4 -2z

Substituting (i) and (ii) into (2)

4 - 2z + 10 -4z + 5z = 13

14-z =13, therefore z = 1

substituting z into (i) and (ii)

y = 3

x = 2

Answer:

area=πr2

Step-by-step explanation:

pie radius squared

Answer:pie r square

Step-by-step explanation:

Answer:

Sqare = 6+6+6+6 = 6*4 = 24

Rectangle = 6+6+18+18 = 12+36 = 48

24+48 = 72

The perimeter is 72.

Answer:

3x+100

Step-by-step explanation:

Answer:

[tex]V = 208\,u^{3}[/tex] (Option C)

Step-by-step explanation:

The volume of the composite figure is:

[tex]V = \frac{1}{2}\cdot (3\,u)\cdot (4\,u)\cdot (8\,u) + (5\,u)\cdot (4\,u)\cdot (8\,u)[/tex]

[tex]V = 208\,u^{3}[/tex] (Option C)

Answer:

443

Step-by-step explanation:

Answer:426.196

Step-by-step explanation:

Answer:

C) I & III

Step-by-step explanation:

Given:

Sample size, n = 18

Sample proportion = 25% = 0.25

Here, a random sample of 18 adults were chosen from the 1500 adults in town. This shows that the random condition was satisfied because the sample was drawn randomly from the general population of adults in the town.

For the normal condition to be satisfied, np should be greater than 10, ie np > 10.

In this case, np = 18 * 0.25 = 4.5

Since np is less than 10, the normal condition was not satisfied.

For the 10% condition to be satisfied, sample size should not be more than 10% of the general population.

Here, the sample size is 18 and the population is 1500. Therefore,

[tex] \frac{18}{1500} * 100 = 1.2 [/tex]

Since the sample size is 1.2% of the population which is less than 10%, the 10% condition was satisfied.

The correct option is C, because only I & III were satisfied.

Answer:

$14.64

Multiply 8 by .67 which is 5.36

Subtract 5.36 from 20.00 and that's 14.64

Answer:

14.64

Step-by-step explanation:

Have a wonderful day hope this helps

Answer:

3/k = x

Step-by-step explanation:

5kx +6 = 7kx

Subtract 5kx from each side

5kx -5kx +6 = 7kx-5kx

6 =2kx

Divide each side by 2k

6 /2k = 2kx/2k

3/k = x

Answer:

1/25 miles per minute

Step-by-step explanation:

Speed is distance divided by time

1/5 miles ÷ 5 minutes

Copy dot flip

1/5 * 1/5

1/25 miles per minute

Answer:

speed(v)=1.07

Step-by-step explanation:

v=m/s (1/5 mile is 321 m and 5 min is 300 seconds)

=321/300=1.07

Answer:

Yes 656250 is divisible by 10. Answer is 656250.

Answer:

3x-3 I think that's it.

Step-by-step explanation:

Answer:

The vertex is (1, -4)

Step-by-step explanation:

Answer:

[tex]15m^2+3[/tex]

Step-by-step explanation:

7 - 4 = 3

To add the m^2 you just add the first numbers together.

9m^2 + 6m^2 = 15m^2

Answer:

see below

Step-by-step explanation:

|x+8| ≤ 4

Separate into two equations one positive and one negative , remembering to flip the inequality for the negative

x+8 ≤ 4        x+8 ≥ -4

Subtract 8 from each side

x+8 -8 ≤ 4-8    and     x+8-8 ≥ -4-8

x ≤-4     and    x ≥ -12

Writing as one function

-12 ≤x ≤-4

|x-8|+5  ≥ 11

Subtract 5 from each side

|x-8|+5-5  ≥ 11-5

|x-8|  ≥ 6

Separate into two equations one positive and one negative , remembering to flip the inequality for the negative

x-8  ≥ 6      or      x-8 ≤  -6

Add 8 to each side

x-8+8  ≥ 6+8       or     x-8+8 ≤  -6+8

x  ≥ 14      or      x ≤  -2

Answers and Step-by-step explanations:

9. | x + 8 | ≤ 4

Remember that absolute value just denotes the distance between the argument within the absolute value signs and 0 on a number line. That means that if the item within the absolute value is negative, the absolute value of it will be the positive value because distance is always positive.

That means we have 2 cases here: x + 8 > 0 (positive) or x + 8 < 0 (negative).

Case 1: x + 8 > 0

x + 8 ≤ 4

x ≤ -4

Case 2: x + 8 < 0

-(x + 8) ≤ 4

-x - 8 ≤ 4

-x ≤ 12

x ≥ -12

Combining these two inequalities, we get:

-12 ≤ x ≤ -4

10. | x - 8 | + 5 ≥ 11

Let's isolate the absolute value expression by subtracting 5 from both sides: | x - 8 | ≥ 6

We again have two cases: x - 8 > 0 and x - 8 < 0.

Case 1: x - 8 > 0

x - 8 ≥ 6

x ≥ 14

Case 2: x - 8 < 0

-(x - 8) ≥ 6

-x + 8 ≥ 6

-x ≥ -2

x ≤ 2

Combining these two inequalities, we get:

x ≤ 2 and x ≥ 14

Answer:

A pyramid yes

a hexagon no

a pentagon no

Step-by-step explanation:

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired t-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

H₀: The incentive program does not cuts down on the number of days missed by employees, i.e. d ≥ 0.

Hₐ: The incentive program cuts down on the number of days missed by employees, i.e. d < 0.

From the information provided the data computed is as follows:

 [tex]n=10\\\bar d=-1.1\\SD_{d}=2.99[/tex]

Compute the test statistic value as follows:

 [tex]t=\frac{\bar d}{SD_{d}/\sqrt{n}}[/tex]

   [tex]=\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16[/tex]

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

[tex]p-value=P(t_{n-1}<-1.16)\\=P(t_{10-1}<-1.16)\\=P(t_{9}<-1.16)\\=0.1379[/tex]

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees