Write a removeDuplicates() method for the LinkedList class we saw in lecture. The method will remove all duplicate elements from the LinkedList by removing the second and subsequent elements. If there is only one copy of an element, it is not removed. The list size should shrink accordingly based on the number of duplicates removed.
Answers
Answer:
removeDuplicates() function:-
//removeDuplicates() function removes duplicate elements form linked list.
void removeDuplicates() {
//declare 3 ListNode pointers ptr1,ptr2 and duplicate.
//initially, all points to null.
ListNode ptr1 = null, ptr2 = null, duplicate = null;
//make ptr1 equals to head.
ptr1 = head;
//run while loop till ptr1 points to second last node.
//pick elements one by one..
while (ptr1 != null && ptr1.next != null)
{
// make ptr2 equals to ptr1.
//or make ptr2 points to same node as ptr1.
ptr2 = ptr1;
//run second while loop to compare all elements with above selected element(ptr1->val).
while (ptr2.next != null)
{
//if element pointed by ptr1 is same as element pointed by ptr2.next.
//Then, we have found duplicate element.
//Now , we have to remove this duplicate element.
if (ptr1.val == ptr2.next.val)
{
//make duplicate pointer points to node where ptr2.next points(duplicate node).
duplicate = ptr2.next;
//change links to remove duplicate node from linked list.
//make ptr2.next points to duplicate.next.
ptr2.next = duplicate.next;
}
//if element pointed by ptr1 is different from element pointed by ptr2.next.
//then it is not duplicate element.
//So, move ptr2 = ptr2.next.
else
{
ptr2 = ptr2.next;
}
}
//move ptr1 = ptr1.next, after check duplicate elements for first node.
//Now, we check duplicacy for second node and so on.
//so, move ptr1 by one node.
ptr1 = ptr1.next;
}
}
Explanation:
Complete Code:-
//Create Linked List Class.
class LinkedList {
//Create head pointer.
static ListNode head;
//define structure of ListNode.
//it has int val(data) and pointer to ListNode i.e, next.
static class ListNode {
int val;
ListNode next;
//constructor to create and initialize a node.
ListNode(int d) {
val = d;
next = null;
}
}
//removeDuplicates() function removes duplicate elements form linked list.
void removeDuplicates() {
//declare 3 ListNode pointers ptr1,ptr2 and duplicate.
//initially, all points to null.
ListNode ptr1 = null, ptr2 = null, duplicate = null;
//make ptr1 equals to head.
ptr1 = head;
//run while loop till ptr1 points to second last node.
//pick elements one by one..
while (ptr1 != null && ptr1.next != null)
{
// make ptr2 equals to ptr1.
//or make ptr2 points to same node as ptr1.
ptr2 = ptr1;
//run second while loop to compare all elements with above selected element(ptr1->val).
while (ptr2.next != null)
{
//if element pointed by ptr1 is same as element pointed by ptr2.next.
//Then, we have found duplicate element.
//Now , we have to remove this duplicate element.
if (ptr1.val == ptr2.next.val)
{
//make duplicate pointer points to node where ptr2.next points(duplicate node).
duplicate = ptr2.next;
//change links to remove duplicate node from linked list.
//make ptr2.next points to duplicate.next.
ptr2.next = duplicate.next;
}
//if element pointed by ptr1 is different from element pointed by ptr2.next.
//then it is not duplicate element.
//So, move ptr2 = ptr2.next.
else
{
ptr2 = ptr2.next;
}
}
//move ptr1 = ptr1.next, after check duplicate elements for first node.
//Now, we check duplicacy for second node and so on.
//so, move ptr1 by one node.
ptr1 = ptr1.next;
}
}
//display() function prints linked list.
void display(ListNode node)
{
//run while loop till last node.
while (node != null)
{
//print node value of current node.
System.out.print(node.val + " ");
//move node pointer by one node.
node = node.next;
}
}
public static void main(String[] args) {
//Create object of Linked List class.
LinkedList list = new LinkedList();
//first we create nodes and connect them to form a linked list.
//Create Linked List 1-> 2-> 3-> 2-> 4-> 2-> 5-> 2.
//Create a Node having node data = 1 and assign head pointer to it.
//As head is listNode of static type. so, we call head pointer using class Name instead of object name.
LinkedList.head = new ListNode(1);
//Create a Node having node data = 2 and assign head.next to it.
LinkedList.head.next = new ListNode(2);
LinkedList.head.next.next = new ListNode(3);
LinkedList.head.next.next.next = new ListNode(2);
LinkedList.head.next.next.next.next = new ListNode(4);
LinkedList.head.next.next.next.next.next = new ListNode(2);
LinkedList.head.next.next.next.next.next.next = new ListNode(5);
LinkedList.head.next.next.next.next.next.next.next = new ListNode(2);
//display linked list before Removing duplicates.
System.out.println("Linked List before removing duplicates : ");
list.display(head);
//call removeDuplicates() function to remove duplicates from linked list.
list.removeDuplicates();
System.out.println("")
//display linked list after Removing duplicates.
System.out.println("Linked List after removing duplicates : ");
list.display(head);
}
}
Output:-
Related Questions
D State Six Impact of ICT the society
Answers
Answer:
home officebankhospital hotelExplanation:
ICT is a device that display and command information outside.
In C language
In a main function declare an array of 1000 ints. Fill up the array with random numbers that represent the rolls of a die.
That means values from 1 to 6. Write a loop that will count how many times each of the values appears in the array of 1000 die rolls.
Use an array of 6 elements to keep track of the counts, as opposed to 6 individual variables.
Print out how many times each value appears in the array. 1 occurs XXX times 2 occurs XXX times
Hint: If you find yourself repeating the same line of code you need to use a loop. If you declare several variables that are almost the same, maybe you need to use an array. count1, count2, count3, count4, … is wrong. Make an array and use the elements of the array as counters. Output the results using a loop with one printf statement. This gets more important when we are rolling 2 dice.
Answers
Answer:
The program in C is as follows:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main(){
int dice [1000];
int count [6]={0};
srand(time(0));
for (int i = 0; i < 1000; i++) {
dice[i] = (rand() %(6)) + 1;
count[dice[i]-1]++;
}
for (int i = 0; i < 6; i++) {
printf("%d %s %d %s",(i+1)," occurs ",count[i]," times");
printf("\n");
}
return 0;
}
Explanation:
This declares an array that hold each outcome
int dice [1000];
This declares an array that holds the count of each outcome
int count [6]={0};
This lets the program generate different random numbers
srand(time(0));
This loop is repeated 1000 times
for (int i = 0; i < 1000; i++) {
This generates an outcome between 1 and 6 (inclusive)
dice[i] = (rand() %(6)) + 1;
This counts the occurrence of each outcome
count[dice[i]-1]++; }
The following prints the occurrence of each outcome
for (int i = 0; i < 6; i++) {
printf("%d %s %d %s",(i+1)," occurs ",count[i]," times");
printf("\n"); }
What will MOST likely adversely impact the operations of unpatched traditional programmable-logic controllers, running a back-end LAMP server and OT systems with human-management interfaces that are accessible over the Internet via a web interface?
Answers
Answer:
The answer is "Option a and Option f"
Explanation:
The cross-site programming and Server-Side Requests fraud were activities that can have negative effects as these are assaults that directly affect your cloud-based servers via web apps. Although the remainder of an attack could be controlled with these approaches, then they can affect the encryption keys only less.
State three advantages associated with the use of diskettes in computers
Answers
1. small, portable, easy to carry
2. cheap
3. can be used to transfer data from one computer to another, useful for transferring small files
Use Python.
Complete reverse() method that returns a new character array containing all contents in the parameter reversed.
Ex: If the input array is:
['a', 'b', 'c']
then the returned array will be:
['c', 'b', 'a']
import java.util.*;
public class LabProgram {
// This method reverses contents of input argument arr.
public static char[] reverse(char[] arr) {
/* Type your code here. */
}
public static void main(String[] args) {
char [] ch = {'a','b','c'};
System.out.println(reverse(ch)); // Should print cba
}
}
Answers
Answer:
Explanation:
The code in the question is written in Java but If you want it in Python then it would be much simpler. The code below is writen in Python and uses list slicing to reverse the array that is passed as an argument to the function. The test case from the question was used and the output can be seen in the attached image below.
def reverse(arr):
reversed_arr = arr[::-1]
return reversed_arr
I need the SQL statements for these questions:
1. For each reservation, list the reservation ID, trip ID, customer number, and customer last name. Order the results by customer last name.
2. For each reservation for customer Ryan Goff, list the reservation ID, trip ID, and number of persons.
3. List the trip name of each trip that has Miles Abrams as a guide.
4. List the trip name of each trip that has the type Biking and that has Rita Boyers as a guide.
5. For each reservation that has a trip date of July 23, 2016, list the customer’s last name, the trip name, and the start location.
6. List the reservation ID, trip ID, and trip date for reservations for a trip in Maine (ME). Use the IN operator in your query.
7. Repeat Exercise 6, but this time use the EXISTS operator in your query.
8. Find the guide last name and guide first name of all guides who can lead a paddling trip. (Note: The query results should include duplicate values.)
Here are the tables:
CUSTOMER FIRST NAME POSTAL CODE CUSTOMER NUM LAST NAME ADDRESS Northfold Liam 9 Old Mill Rd Londonderry 10 NH 03053 103 Kasuma Sujata 132 Main St. #1 East Hartford CT 06108 MA 01854 Goff 164A South Bend Rd. Lowell Ryan 105 McLean Kyle 345 Lower Ave. Wolcott NY 14590 106 Morontoia Joseph 156 Scholar St Johnston 02919 107 Marchand Quinn 76 Cross Rd Bath NH 03740 108 32 Sheep stop St Edinboro PA Rulf Usch 16412 109 Caron Jean Luc 10 Greenfield St Rome ME 04963 110 Martha York Bers 65 Granite St NY 14592 112 Jones Laura 373 Highland Ave. Somerville MA 02143 115 Nu Adam 1282 Ocean Walk Ocean City Vaccari 08226 116 Murakami Iris 7 Cherry Blossom St. Weymouth MA 02188 119 Londonderry vT Chau 18 Ark Ledge Ln Clement 05148 120 Gernowski Sadie 24 stump Rd. Athens ME 04912 121 Cambridge VT Bretton-Borak Siam 10 Old Main St 122 Hefferson orlagh 132 South St. Apt 27 Manchester NH 03101 123 25 Stag Rd Fairfield Barnett Larry 06824 124 Busa Karen 12 Foster St. South Windsor CT 06074 125 51 Fredrick St Albion Peterson Becca NY 14411 126 Brown Brianne 154 Central St Vernon CT 06066 PHONE Click to Add 603-555-7563 413-555-3212 860-555-0703 781-555-8423 585-555-5321 401-555-4848 603-555-0456 814-555-5521 207-555-9643 585-555-0111 857-555-6258 609-555-5231 617-555-6665 802-555-3096 207-555-4507 802-555-3443 603-555-3476 860-555-9876 857-555-5532. 585-555-0900 860-555-3234
Answers
Answer:
Explanation:
/* From the information provided, For now will consider the name of table as TRIPGUIDES*/
/*In all the answers below, the syntax is based on Oracle SQL. In case of usage of other database queries, answer may vary to some extent*/
1.
Select R.Reservation_ID, R.Trip_ID , C.Customer_Num,C.Last_Name from Reservation R, Customer C where C.Customer_Num=R.Customer_Num ORDER BY C.Last_Name
/*idea is to select the join the two tables by comparing customer_id field in two tables as it is the only field which is common and then print the desired result later ordering by last name to get the results in sorted order*/
2.
Select R.Reservation_ID, R.Trip_ID , R.NUM_PERSONS from Reservation R, Customer C where C.Customer_Num=R.Customer_Num and C.LAST_NAME='Goff' and C.FIRST_NAME='Ryan'
/*Here, the explaination will be similar to the first query. Choose the desired columns from the tables, and join the two tables by equating the common field
*/
3.
Select T.TRIP_NAME from TRIP T,GUIDE G,TRIPGUIDES TG where T.TRIP_ID=TG.TRIP_ID and TG.GUIDE_NUM=G.GUIDE_NUM and G.LAST_NAME='Abrams' and G.FIRST_NAME='Miles'
/*
Here,we choose three tables TRIP,GUIDE and TRIPGUIDES. Here we selected those trips where we have guides as Miles Abrms in the GUIDES table and equated Trip_id from TRIPGUIDES to TRIP.TRIP_Name so that can have the desired results
*/
4.
Select T.TRIP_NAME
from TRIP T,TRIPGUIDES TG ,G.GUIDE
where T.TRIP_ID=TG.TRIP_ID and T.TYPE='Biking' and TG.GUIDE_NUM=G.GUIDE_NUM and G.LAST_NAME='Boyers' and G.FIRST_NAME='Rita'
/*
In the above question, we first selected the trip name from trip table. To put the condition we first make sure that all the three tables are connected properly. In order to do so, we have equated Guide_nums in guide and tripguides. and also equated trip_id in tripguides and trip. Then we equated names from guide tables and type from trip table for the desired results.
*/
5.
SELECT C.LAST_NAME , T.TRIP_NAME , T.START_LOCATION FROM CUSTOMER C, TRIP T, RESERVATION R WHERE R.TRIP_DATE='2016-07-23' AND T.TRIP_ID=R.TRIP_ID AND C.CUSTOMER_NUM=R.CUSTOMER_NUM
/*
The explaination for this one will be equivalent to the previous question where we just equated the desired columns where we equiated the desired columns in respective fields and also equated the common entities like trip ids and customer ids so that can join tables properly
*/
/*The comparison of dates in SQL depends on the format in which they are stored. In the upper case if the
dates are stored in the format as YYYY-MM-DD, then the above query mentioned will work. In case dates are stored in the form of a string then the following query will work.
SELECT C.LAST_NAME , T.TRIP_NAME , T.START_LOCATION FROM CUSTOMER C, TRIP T, RESERVATION R WHERE R.TRIP_DATE='7/23/2016' AND T.TRIP_ID=R.TRIP_ID AND C.CUSTOMER_NUM=R.CUSTOMER_NUM
*/
6.
Select R.RESERVATION_ID, R.TRIP_ID,R.TRIP_DATE FROM RESERVATION R WHERE R.TRIP_ID IN
{SELECT TRIP_ID FROM TRIP T WHERE STATE='ME'}
/*
In the above question, we firstly extracted all the trip id's which are having locations as maine. Now we have the list of all the trip_id's that have location maine. Now we just need to extract the reservation ids for the same which can be trivally done by simply using the in clause stating print all the tuples whose id's are there in the list of inner query. Remember, IN always checks in the set of values.
*/
7.
Select R.RESERVATION_ID, R.TRIP_ID,R.TRIP_DATE FROM RESERVATION WHERE
EXISTS {SELECT TRIP_ID FROM TRIP T WHERE STATE='ME' and R.TRIP_ID=T.TRIP_ID}
/*
Unlike IN, Exist returns either true or false based on existance of any tuple in the condition provided. In the question above, firstly we checked for the possibilities if there is a trip in state ME and TRIP_IDs are common. Then we selected reservation ID, trip ID and Trip dates for all queries that returns true for inner query
*/
8.
SELECT G.LAST_NAME,G.FIRST_NAME FROM GUIDE WHERE G.GUIDE_NUM IN
{
SELECT DISTINCT TG.GUIDE_NUM FROM TRIPGUIDES TG WHERE TG.TRIPID IN {
SELECT T.TRIP_ID FROM TRIP T WHERE T.TYPE='Paddling'
}
}
/*
We have used here double nested IN queries. Firstly we selected all the trips which had paddling type (from the inner most queries). Using the same, we get the list of guides,(basically got the list of guide_numbers) of all the guides eds which were on trips with trip id we got from the inner most queries. Now that we have all the guide_Nums that were on trip with type paddling, we can simply use the query select last name and first name of all the guides which are having guide nums in the list returned by middle query.
*/
What order? (function templates) Define a generic function called CheckOrder() that checks if four items are in ascending, neither, or descending order. The function should return -1 if the items are in ascending order, 0 if the items are unordered, and 1 if the items are in descending order. The program reads four items from input and outputs if the items are ordered. The items can be different types, including integers, strings, characters, or doubles. Ex. If the input is:
Answers
Answer:
Explanation:
The following code was written in Java and creates the generic class to allow you to compare any type of data structure. Three different test cases were used using both integers and strings. The first is an ascending list of integers, the second is a descending list of integers, and the third is an unordered list of strings. The output can be seen in the attached image below.
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Order: " + checkOrder(10, 22, 51, 53));
System.out.println("Order: " + checkOrder(55, 44, 33, 22));
System.out.println("Order: " + checkOrder("John", " Gabriel", "Daniela", "Zendaya"));
}
public static <E extends Comparable<E>> int checkOrder(E var1, E var2, E var3, E var4) {
E prevVar = var1;
if (var2.compareTo(prevVar) > 0) {
prevVar = var2;
} else {
if (var3.compareTo(prevVar) < 0) {
prevVar = var3;
} else {
return 0;
}
if (var4.compareTo(prevVar) < 0) {
return 1;
} else {
return 0;
}
}
if (var3.compareTo(prevVar) > 0) {
prevVar = var3;
}
if (var4.compareTo(prevVar) > 0) {
return -1;
}
return 0;
}
}
A recursive method may call other methods, including calling itself. Creating a recursive method can be accomplished in two steps. 1. Write the base case -- Every recursive method must have a case that returns a value or exits from the method without performing a recursive call. That case is called the base case. A programmer may write that part of the method first, and then lest. There may be multiple base cases.Complete the recursive method that returns the exponent of a given number. For e.g. given the number 5 and the exponent 3 (53) the method returns 125. Note: any number to the zero power is 1. Note: Do not code for the example. Your method must work for all given parameters! Use this as your method header: public static int raiseToPower(int base, int exponent)
Answers
Answer:
Explanation:
The following code is written in Java. It creates the raiseToPower method that takes in two int parameters. It then uses recursion to calculate the value of the first parameter raised to the power of the second parameter. Three test cases have been provided in the main method of the program and the output can be seen in the attached image below.
class Brainly {
public static void main(String[] args) {
System.out.println("Base 5, Exponent 3: " + raiseToPower(5,3));
System.out.println("Base 2, Exponent 7: " + raiseToPower(2,7));
System.out.println("Base 5, Exponent 9: " + raiseToPower(5,9));
}
public static int raiseToPower(int base, int exponent) {
if (exponent == 0) {
return 1;
} else if (exponent == 1) {
return base;
} else {
return (base * raiseToPower(base, exponent-1));
}
}
}
If you fail a course as a MAIN (residency) course, you can repeat that course as either a MAIN (residency) or an online (IG or IIG) course. True False
Answers
Answer: False
Explanation:
The statement that "you fail a course as a MAIN (residency) course, you can repeat that course as either a MAIN (residency) or an online (IG or IIG) course" is false.
It should be noted that if one fail a course as a residency course, the course can only be repeated as a main (residency) course and not an online course. When a course is failed, such course has to be repeated the following semester and this will give the person the chance to improve their GPA.
RecursionexerciseCOP 3502; Summer2021We have gone through many examples in the class and those examples are available in the slides and uploaded codes. Try to test those codes and modify as you wish for getting more clarification.In additiontry the following:---------------------------------------------------------------------------------------------------------------------------------------1.What would be the output of the following recursive function if we call rec2(5)
Answers
Answer:
The output is:
1 2 3 4 5
Explanation:
Given
See attachment for code segment
Required
The output of rec2(5)
From the attached code segment, we have the following:
The base case: if (x==0){ return;}
The above implies that, the recursion ends when the value of x gets reduced to 0
The recursion:
rec2(x-1); ---- This continually reduces x by 1 and passes the value to the function
printf("%d ", x); This prints the passed value of x
Hence, the output of rec2(5) is: 1 2 3 4 5
Write a recursive function that returns 1 if an array of size n is in sorted order and 0 otherwise. Note: If array a stores 3, 6, 7, 7, 12, then isSorted(a, 5) should return 1 . If array b stores 3, 4, 9, 8, then isSorted(b, 4) should return 0.
Answers
Answer:
The function in C++ is as follows:
int isSorted(int ar[], int n){
if ([tex]n == 1[/tex] || [tex]n == 0[/tex]){
return 1;}
if ([tex]ar[n - 1][/tex] < [tex]ar[n - 2][/tex]){
return 0;}
return isSorted(ar, n - 1);}
Explanation:
This defines the function
int isSorted(int ar[], int n){
This represents the base case; n = 1 or 0 will return 1 (i.e. the array is sorted)
if ([tex]n == 1[/tex] || [tex]n == 0[/tex]){
return 1;}
This checks if the current element is less than the previous array element; If yes, the array is not sorted
if ([tex]ar[n - 1][/tex] < [tex]ar[n - 2][/tex]){
return 0;}
This calls the function, recursively
return isSorted(ar, n - 1);
}
Add (total) all the number in the list (below) using a for loop, but skip over the number at index 3.
numbers = [10,20,30,40,50,60,100]
Answers
Answer:
The program in Python is as follows:
numbers = [10,20,30,40,50,60,100]
total = 0
for i in range(len(numbers)):
if i != 3:
total+=numbers[i]
print(total)
Explanation:
This initializes the list
numbers = [10,20,30,40,50,60,100]
Set total to 0
total = 0
This iterates through numbers
for i in range(len(numbers)):
This ensures that the index 3, are not added
if i != 3:
total+=numbers[i]
Print the calculated sum
print(total)
3. Circular, array-backed queue In the following class, which you are to complete, the backing array will be created and populated with Nones in the __init__ method, and the head and tail indexes set to sentinel values (you shouldn't need to modify __init__). Enqueuing and Dequeuing items will take place at the tail and head, with tail and head tracking the position of the most recently enqueued item and that of the next item to dequeue, respectively. To simplify testing, your implementation should make sure that when dequeuing an item its slot in the array is reset to None, and when the queue is emptied its head and tail attributes should be set to -1.
Answers
Answer:
#Implementation of Queue class
class Queue
#Implementation of _init_
def _init_(self, limit=10):
#calculate the self.data
self.data = [None] * limit
self.head = -1
self.tail = -1
#Implementation of enqueue function
def enqueue(self, val):
#check self.head - self.tail is equal to 1
if self.head - self.tail == 1:
raise NotImplementedError
#check len(self.data) - 1 is equal to elf.tail
if len(self.data) - 1 == self.tail and self.head == 0:
raise NotImplementedError
#check self.head is equal to -1
if self.head == -1 and self.tail == -1:
self.data[0] = val
self.head = 0
self.tail = 0
else:
#check len(self.data) - 1 is equal to self.tail
if len(self.data) - 1 == self.tail and self.head != 0:
self.tail = -1
self.data[self.tail + 1] = val
#increment the self.tail value
self.tail = self.tail + 1
#Implementation of dequeue method
def dequeue(self):
#check self.head is equal to self.tail
if self.head == self.tail:
temp = self.head
self.head = -1
self.tail = -1
return self.data[temp]
#check self.head is equal to -1
if self.head == -1 and self.tail == -1:
#raise NotImplementedError
raise NotImplementedError
#check self.head is not equal to len(self.data)
if self.head != len(self.data):
result = self.data[self.head]
self.data[self.head] = None
self.head = self.head + 1
else:
# resetting head value
self.head = 0
result = self.data[self.head]
self.data[self.head] = None
self.head = self.head + 1
return result
#Implementation of resize method
def resize(self, newsize):
#check len(self.data) is less than newsize
assert (len(self.data) < newsize)
newdata = [None] * newsize
head = self.head
current = self.data[head]
countValue = 0
#Iterate the loop
while current != None:
newdata[countValue] = current
countValue += 1
#check countValue is not equal to 0
if countValue != 0 and head == self.tail:
break
#check head is not equal to
#len(self.data) - 1
if head != len(self.data) - 1:
head = head + 1
current = self.data[head]
else:
head = 0
current = self.data[head]
self.data = newdata
self.head = 0
self.tail = countValue - 1
#Implementation of empty method
def empty(self):
#check self.head is equal to -1
# and self.tail is equal to -1
if self.head == -1 and self.tail == -1:
return True
return False
#Implementation of _bool_() method
def _bool_(self):
return not self.empty()
#Implementation of _str_() method
def _str_(self):
if not (self):
return ''
return ', '.join(str(x) for x in self)
#Implementation of _repr_ method
def _repr_(self):
return str(self)
#Implementation of _iter_ method
def _iter_(self):
head = self.head
current = self.data[head]
countValue = 0
#Iterate the loop
while current != None:
yield current
countValue += 1
#check countValue is not equal to zero
#check head is equal to self.tail
if countValue != 0 and head == self.tail:
break
#check head is not equal to len(self.data) - 1
if head != len(self.data) - 1:
head = head + 1
current = self.data[head]
else:
head = 0
current = self.data[head
Explanation:-
Output:
Fill in multiple blanks for [x], [y], [z]. Consider a given TCP connection between host A and host B. Host B has received all from A all bytes up to and including byte number 2000. Suppose host A then sends three segments to host B back-to-back. The first, second and third segments contain 50, 600 and 100 bytes of user data respectively. In the first segment, the sequence number is 2001, the source port number is 80, and the destination port number is 12000. If the first segment, then third segment, then second segment arrive at host B in that order, consider the acknowledgment sent by B in response to receiving the third segment. What is the acknowledgement number [x], source port number [y] and destination port number [z] of that acknowledgement
Answers
Write a RainFall class that stores the total rainfall for each of 12 months into an array of doubles. The program should have methods that return the following:
the total rainfall for the year
the average monthly rainfall
the month with the most rain
the month with the least rain
Demonstrate the class in a complete program.
Input Validation: Do not accept negative numbers for monthly rainfall figures.
import java.io.*;
import java.util.*;
public class Rainfall
{
Scanner in = new Scanner(System.in);
private int month = 12;
private double total = 0;
private double average;
private double standard_deviation;
private double largest;
private double smallest;
private double months[];
public Rainfall()
{
months = new double[12];
}
public void setMonths()
{
for(int n=1; n <= month; n++)
{
System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );
months[n-1] = in.nextInt();
}
}
public double getTotal()
{
total = 0;
for(int i = 0; i < 12; i++)
{
total = total + months[i];
}
System.out.println("The total rainfall for the year is" + total);
return total;
}
public double getAverage()
{
average = total/12;
System.out.println("The average monthly rainfall is" + average);
return average;
}
public double getLargest()
{
double largest = 0;
int largeind = 0;
for(int i = 0; i < 12; i++)
{
if (months[i] > largest)
{
largest = months[i];
largeind = i;
}
}
System.out.println("The largest amout of rainfall was" + largest +
"inches in month" + (largeind + 1));
return largest;
}
public double getSmallest()
{
double smallest = Double.MAX_VALUE;
int smallind = 0;
for(int n = 0; n < month; n++)
{
if (months[n] < smallest)
{
smallest = months[n];
smallind = n;
}
}
System.out.println("The smallest amout of rainfall was" + smallest +
"inches in month " + (smallind + 1));
return smallest;
}
public static void main(String[] args)
{
Rainfall r = new Rainfall();
r.setMonths();
System.out.println("Total" + r.getTotal());
System.out.println("Smallest" + r.getSmallest());
System.out.println("Largest" + r.getLargest());
System.out.println("Average" + r.getAverage());
}
}
Answers
Answer:
Explanation:
The code provided worked for the most part, it had some gramatical errors in when printing out the information as well as repeated values. I fixed and reorganized the printed information so that it is well formatted. The only thing that was missing from the code was the input validation to make sure that no negative values were passed. I added this within the getMonths() method so that it repeats the question until the user inputs a valid value. The program was tested and the output can be seen in the attached image below.
import java.io.*;
import java.util.*;
class Rainfall
{
Scanner in = new Scanner(System.in);
private int month = 12;
private double total = 0;
private double average;
private double standard_deviation;
private double largest;
private double smallest;
private double months[];
public Rainfall()
{
months = new double[12];
}
public void setMonths()
{
for(int n=1; n <= month; n++)
{
int answer = 0;
while (true) {
System.out.println("Enter the rainfall (in inches) for month #" + n + ":" );
answer = in.nextInt();
if (answer > 0) {
months[n-1] = answer;
break;
}
}
}
}
public void getTotal()
{
total = 0;
for(int i = 0; i < 12; i++)
{
total = total + months[i];
}
System.out.println("The total rainfall for the year is " + total);
}
public void getAverage()
{
average = total/12;
System.out.println("The average monthly rainfall is " + average);
}
public void getLargest()
{
double largest = 0;
int largeind = 0;
for(int i = 0; i < 12; i++)
{
if (months[i] > largest)
{
largest = months[i];
largeind = i;
}
}
System.out.println("The largest amount of rainfall was " + largest +
" inches in month " + (largeind + 1));
}
public void getSmallest()
{
double smallest = Double.MAX_VALUE;
int smallind = 0;
for(int n = 0; n < month; n++)
{
if (months[n] < smallest)
{
smallest = months[n];
smallind = n;
}
}
System.out.println("The smallest amount of rainfall was " + smallest +
" inches in month " + (smallind + 1));
}
public static void main(String[] args)
{
Rainfall r = new Rainfall();
r.setMonths();
r.getTotal();
r.getSmallest();
r.getLargest();
r.getAverage();
}
}
For the following 4-bit operation, assuming these register are ONLY 4-bits in size, which status flags are on after performing the following operation? Assume 2's complement representation. 1010+0110
a) с
b) Z
c) N
Answers
Answer:
All flags are On ( c, z , N )
Explanation:
Given data:
4-bit operation
Assuming 2's complement representation
Determine status flags that are on after performing 1010+0110
1 1
1 0 1 0
0 1 1 0
1 0 0 0 0
we will carry bit = 1 over
hence C = 1
given that: carry in = carry out there will be zero ( 0 ) overflow
hence V = 0
also Z = 1
But the most significant bit is N = 1
????????????????????????????????
Answers
(c) 4
Explanation:The function strpos() is a function in php that returns the position of the first occurrence of a particular substring in a string. Positions are counted from 0. The function receives two arguments. The first argument is the string from which the occurrence is to be checked. The second argument is the substring to be checked.
In this case, the string is "Get Well Soon!" while the substring is "Well"
Starting from 0, the substring "Well" can be found to begin at position 4 of the string "Get Well Soon!".
Therefore, the function strpos("Get Well Soon!", "Well") will return 4.
Then, with the echo statement, which is used for printing, value 4 will be printed as output of the code.
feature of word processing
Answers
Answer:
the word processing
Explanation:
the word is a good word
Should you remove jewelry, pens, and other metal objects before entering the magnetic resonance (MR) environment even if the equipment is not in use?
Answers
Answer:
Yes you should
Explanation:
When you are about to enter the mr the best thing you should do is to take off any form of metallic objects that you may have on you this could be a wrist watch, it could be other forms of accessories such as hair clips, keys or even coins. having any of these objects on you could cause a person to have an injury.
This is because this object could change its position when in the room also it could cause signal losses and could also make objects unclear for the radiologist
Preserving confidentiality, integrity, and availability is a restatement of the concern over interruption, interception, modification, and fabrication.
i. Briefly explain the 4 attacks: interruption, interception, modification, and fabrication.
ii. How do the first three security concepts relate to these four attacks
Answers
Answer and Explanation:
I and II answered
Interruption: interruption occurs when network is tampered with or communication between systems in a network is obstructed for illegitimate purposes.
Interception: interception occurs when data sent between systems is intercepted such that the message sent to another system is seen by an unauthorized user before it reaches destination. Interception violates confidentiality of a message.
Modification: modification occurs when data sent from a system to another system on the network is altered by an authorized user before it reaches it's destination. Modification attacks violate integrity, confidentiality and authenticity of a message.
Fabrication: fabrication occurs when an unauthorized user poses as a valid user and sends a fake message to a system in the network. Fabrication violates confidentiality, integrity and authenticity.
If you are going to refer to a few dozen classes in your application, how do
you do it?
Answers
Answer:
Explanation:
use the "includes" statement to have access to those classes :)
Select the correct statement(s) regarding decentralized (distributed) access control on a LAN. a. no centralized access process exists, and therefore each connected station has the responsibility for controlling its access b. data collisions are possible, therefore mechanisms such as CDMA/CD are required c. when a data collision occurs, the nearest station detecting the collision transmits a jamming signal d. all of the above are correct
Answers
Answer: D. all of the above are correct
Explanation:
The correct statements regarding the decentralized (distributed) access control on a LAN include:
• no centralized access process exists, and therefore each connected station has the responsibility for controlling its access
• data collisions are possible, therefore mechanisms such as CDMA/CD are required
• when a data collision occurs, the nearest station detecting the collision transmits a jamming signal.
Therefore, the correct option is all of the above.
8.7 LAB: Instrument information (derived classes)
Given main() and the Instrument class, define a derived class, StringInstrument, for string instruments.
Ex. If the input is:
Drums
Zildjian
2015
2500
Guitar
Gibson
2002
1200
6
19
the output is:
Instrument Information:
Name: Drums
Manufacturer: Zildjian
Year built: 2015
Cost: 2500
Instrument Information:
Name: Guitar
Manufacturer: Gibson
Year built: 2002
Cost: 1200
Number of strings: 6
Number of frets: 19
Answers
Answer:
Explanation:
Using the main() and Instrument class which can be found online. We can create the following StringInstrument class that extends the Instrument class itself. The only seperate variables that the StringInstrument class posses' would be the number of Strings (numStrings) and the number of frets (numFrets). Due to technical difficulties I have added the code as a seperate text file below.
Gaming related
Are SCRIMS in Pubg Mobile like a classic match but with more skilled players? Do Scrims affect your K/D?
Answers
Answer:
yes affects your K/D
Explanation:
winner winner chicken dinner
please mark me please brainliest or mark thanks
The ____ contains app buttons that allow you to quickly run the File Explorer or Microsoft Edge apps.
Answers
Explanation:
The taskbar contains app buttons that allow you to quickly run the File Explorer or Microsoft Edge apps.
Hope this helps
Because GIS is largely a computer/information science that involves working with software in the privacy of one's own workspace, users of GIS rarely must be concerned with ethics or the ethical implications of their work.
a.True
b. False
Answers
Answer:
Hmm, I think it is true
Explanation:
In confirmatory visualization Group of answer choices Users expect to see a certain pattern in the data Users confirm the quality of data visualization Users don't know what they are looking for Users typically look for anomaly in the data
Answers
Answer: Users expect to see a certain pattern in the data
Explanation:
Confirmatory Data Analysis occurs when the evidence is being evaluated through the use of traditional statistical tools like confidence, significance, and inference.
In this case, there's an hypothesis and the aim is to determine if the hypothesis is true. In this case, we want to know if a particular pattern on the data visualization conforms to what we have.
Write a statement that assigns numCoins with numNickels + numDimes. Ex: 5 nickels and 6 dimes results in 11 coins. Note: These activities may test code with different test values. This activity will perform two tests: the first with nickels = 5 and dimes = 6, the second with nickels = 9 and dimes = 0.
1 import java.util.Scanner;
2
3 public class AssigningSum {
4 public static void main(String[] args) {
5 int numCoins;
6 int numNickels;
7 int numDimes;
8
9 numNickels = 5;
10 numDimes - 6;
11
12 /* Your solution goes here
13
14 System.out.print("There are ");
15 System.out.print(numCoins);
16 System.out.println(" coins");
17 }
18 }
Answers
Answer:
Explanation:
The statement solution was added to the code and then the code was repeated in order to create the second test case with 9 nickels and 0 dimes. The outputs for both test cases can be seen in the attached image below.
import java.util.Scanner;
class AssigningSum {
public static void main(String[] args) {
int numCoins;
int numNickels;
int numDimes;
numNickels = 5;
numDimes = 6;
/* Your solution goes here */
numCoins = numNickels + numDimes;
System.out.print("There are ");
System.out.print(numCoins);
System.out.println(" coins");
// TEST CASE 2
numNickels = 9;
numDimes = 0;
/* Your solution goes here */
numCoins = numNickels + numDimes;
System.out.print("There are ");
System.out.print(numCoins);
System.out.println(" coins");
}
}
write an algorithm that reads to values, determines the largest value and prints the largest value with an identifying message
Answers
Answer:
I'm unsure of what language you are referring to, but the explanation below is in Python.
Explanation:
a = int(input("Input your first number: "))
b = int(input("Input your second number: "))
c = int(input("Input your third number: "))
maximum = max(a, b, c)
print("The largest value: ", maximum)
Print the two strings in alphabetical order. Assume the strings are lowercase. End with newline. Sample output: capes rabbits import java.util.Scanner: public class OrderStrings { public static void main (String args) { String firstString: String secondString: firstString = "rabbits" secondString = "capes" /*Your solution goes here */ return: } }import java.util.Scanner;public class OrderStrings { public static void main(String[] args) { String firstString; String secondString; firstString = "rabbit"; secondString= "capes"; //String class in java provide string comparison function, use it, and get //your work done may even use brute force i.e using for loop and compare character by // character which will not good for the programming language which already have vast //predefined number of functions if(firstString.compareTo(secondString) < 0){ System.out.println(firstString + " " + secondString); } else{ System.out.println(secondString + " " + firstString); } return; }}
Answers
Answer:
Following are the code to the given question:
import java.util.Scanner;//import package
public class OrderStrings // defining a class OrderStrings
{
public static void main(String[] args) //defining a main method
{
Scanner scnr = new Scanner(System.in);//defining a Scanner class object
String firstString;//defining a String variable
String secondString; //defining a String variable
firstString = scnr.next();//input value
secondString = scnr.next();//input value
if (firstString.compareTo(secondString) < 0)//use if to compare sting value
System.out.println(firstString + " " + secondString);//print sting value
else//else block
System.out.println(secondString + " " + firstString);//print sting value
}
}
Output:
rabbits capes
capes rabbits
Explanation:
In this code a class "OrderStrings" is defined inside the class the main method is defined that declares the two string variable that uses the input method to input the string value and after input, it uses the conditional statement. Inside this compareTo method is declared that compare string value and prints the string value.