The velocity with which the sandbag strikes the ground is -28.44m/s (downward).
Given the initial velocity of balloon (u) = 5m/s
The height of balloon (h) = 40m
The acceleration is due to the gravity = g = 9.8m/s^2 acting downwards.
A sandbag is released from height h of the balloon.
The velocity of sandbag as it reaches the ground = v
We know that from Newtons laws of motion v = u + at
We know that the bag strikes the ground at y =0m,
then y = h + ut - 1/2gt^2
0 = 40 + 5t - 1/2 x 9.8 x t^2
t = 3.41s
As we know that v = u - gt
v = 5 - 9.8 x 3.41 = -28.44m/s
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complete question: A hot-air balloonist, rising vertically with a constant velocity of magnitude 5.00m/s releases a sandbag at an instant when the balloon is 40.0m above the ground. With what magnitude of velocity does it strike the ground?
how much time after the stage-two firing will it take for the rocket to fall back to the launch pad?
After 30.15 sec the stage-two firing will it take for the rocket to fall back to the launch pad.
What is projectile motion?
When a particle is thrown obliquely close to the Earth's surface, it travels along a curved path while experiencing constant acceleration. Always pointing in the direction of the Earth's center is this curving path. Such a particle's motion is referred to as projectile motion, and its trajectory is known as the projectile's trajectory.
In the first stage of a two-stage rocket, the rocket is fired from the launch pad starting from rest but with a constant acceleration of 3.50 m/s² upward. At 25.0 s after launch, the second stage fires for 10.0 s, which boosts the velocity of the rocket to 132.5 m/s upward at 35.0 s after launch.
The formula is
s = ut + 1/2at²
In the initial stage, the velocity is zero, acceleration is a = 3.50 m/s², t = 25 sec.
s = 0 ×25+ 1/2× 3.50 × 25²
s = 1,093.75 m
In the next stage, the initial velocity is 132.5 m/s and at the highest point the velocity is 0 m/s and acceleration is a = -9.8 m/s
v² - u² =2as
0² - 132.5² = 2 × (-9.8) × s
s = 895.73
The maximum height of the rocket is 1,093.75 + 895.73 = 1989.48 m
When the rocket is fall the initial velocity is u = 0 m/s, acceleration a = -9.8 m/s, s = 1989.48 m
s = ut + 1/2at²
1989.48 = 0× t + 1/2 ×9.8× t²
t² = 406.01
t = 20.15 s
The total time is 10 + 20.15 s =30.15 s
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Complete question:
In the first stage of a two-stage rocket, the rocket is fired from the launch pad starting from rest but with a constant acceleration of 3.50 m/s2 upward. At 25.0 s after launch, the second stage fires for 10.0 s, which boosts the rocket's velocity to 132.5 m/s upward at 35.0 s after launch. This firing uses up all the fuel, however, so after the second stage has finished firing, the only force acting on the rocket is gravity. Air resistance can be neglected.
How much time after the stage-two firing will it take for the rocket to fall back to the launch pad?
You are standing in the middle of the far side of the Moon. Which one of the following statements about what you can and cannot see would be true?
a. Earth would set about 14 days after rising.
b. The starts visible from tat location would be very different from the stars visible from earth at that time of year.
c. You could never see earth from that location.
d. You could never see the sun from that location.
option b. The starts visible from that location would be very different from the stars visible from Earth at that time of year. it's important to understand that the Moon is tidally locked to the Earth.
which means that it rotates on its axis at the same rate that it orbits the Earth. This results in the same side of the Moon always facing the Earth. The side facing away from the Earth is known as the far side of the Moon. Because the far side of the Moon always faces away from the Earth, you would not be able to see Earth from that location. The Sun would also be invisible as it would be hidden by the Moon itself. However, because the Moon rotates on its axis, over the course of a lunar day (which lasts about 29.5 Earth days), you would see different stars rise and set. So the stars visible from the far side of the Moon would indeed be very different from the stars visible from Earth at any given time of year.
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contrast continental collision and volcanic island arc formation. sort properties of each.
Continental collision and volcanic island arc formation are two different geological processes that result in the formation of land masses.
Continental collision:
Occurs when two continents collide and merge into a single landmass
Typically results in the creation of large mountain ranges
Involves the thickening and uplift of the Earth's crust
Often occurs over millions of years
Volcanic island arc formation:
Occurs when magma rises to the Earth's surface through a subduction zone
Typically results in the formation of chain of volcanic islands
Involves the subduction of one tectonic plate beneath another
Often occurs in an oceanic-oceanic or oceanic-continental boundary
In summary, continental collision is the result of two continents colliding and merging into a single landmass, often resulting in large mountain ranges. Volcanic island arc formation is the result of magma rising to the Earth's surface through a subduction zone, often resulting in a chain of volcanic islands.
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pull the balloon back to about the midpoint between the wall and the sweater. release it again and describe the motion of the balloon using kinematics concepts of velocity and acceleration.
In summation, the balloon's motion may be defined as an entity undergoing steady downward acceleration, with a starting velocity of zero and rising velocity as time passes.
Describe the motion of the balloon using kinematics concepts of velocity and acceleration.The motion of the balloon may be characterized using kinematic principles of velocity and acceleration when it is pushed back to the halfway between the wall and the sweater and then released. The balloon has an initial velocity of zero, v0 = 0, at the instant of release. The gravitational force pressing on it causes it to accelerate downwards. The balloon's acceleration may be described as the acceleration owing to gravity, a = 9.8 m/s2. As time passes, the balloon's velocity rises due to its acceleration. The balloon's velocity may be calculated using the equation v = v0 + at, where t denotes time. The balloon's location may be characterized by the equation x = x0 + v0t + (1/2)at2, where x0 represents the balloon's original position. The balloon's velocity will grow during its travel, reaching its maximum value at the instant it hits its lowest point. Because the balloon is only being affected upon by the constant force of gravity, its acceleration will remain constant.
Here,
In summary, the motion of the balloon can be described as an object undergoing constant acceleration in the downward direction, with an initial velocity of zero and increasing velocity as time progresses.
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what is the density of a liquid with a mass of 31.1415 g and a volume of 30.13 cm3?
The liquid with a mass of 31.1415 g and a volume of 30.13 cm³ has a density of 1.033 g/cm³.
Density is a measurement that compares the amount of matter an object has to its volume. An object with much matter in a certain volume has a high density.
The density formula and the procedure we will use is,
Mathematically, d = m/v
where, v is volume
d is density
m is mass
Mass of liquid is given as 31.1415 g.
Volume of the liquid is given as 30.13 cm³.
Placing the known values into the above equation, we have,
d = m/v = 31.1415/30.13 = 1.033 g/cm³
Thus, the density of the liquid is calculated to be 1.033 g/cm³.
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an object of mass 1 kg that is moving in a straight line on a level surface slows down from 4 m/s to rest. what is the net work done on the object?
Net work done on the object -16J.
Net work done on the object = Force x Distance
Force = mass x acceleration = 1 kg x (-4 m/s) = -4 N
Distance = Change in velocity x time = (4 m/s - 0 m/s) x 1 s = 4 m
Net work done on the object = Force x Distance
= -4 N x 4 m
= -16 J
What is work done?
Work done is the amount of energy expended to move an object a certain distance. It is calculated by multiplying the force applied to the object by the distance it is moved. Work is measured in Joules (J).
Therefore, Net work done on the object -16J.
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what is the maximum pressure (gauge) of the pressurized gas that the pipe can carry before the mercury spills out of the open end of the manometer
The maximum pressure that a pipe can carry before the mercury spills out of an open-end manometer depends on the height of the mercury column and the density of the gas.
An open-end manometer is a device used to measure fluid pressure, usually in a gas or liquid. It consists of a U-shaped tube filled with a liquid, typically mercury or water, and has one end open to the atmosphere.
The pressure of the fluid being measured is transferred to the liquid in the manometer, which results in a change in the height of the liquid column. This change in height can then be used to calculate the pressure, based on the density of the liquid and the height of the column.
The pressure can be calculated using the equation of hydrostatic pressure: Pressure = (density of mercury * acceleration due to gravity * height of mercury column).
The maximum pressure is reached when the pressure exerted by the gas in the pipe equals the pressure exerted by the mercury column, which results in the mercury spilling out of the open end of the manometer.
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what is the value for work and is it done on or by the system when 87.33 kj of heat is absorbed and the internal energy is 1,999 j?
The value for work done on the system is -89.32 kJ.
In this case, heat has been absorbed by the system, which means the internal energy of the system has increased. Internal energy is defined as the total energy of a system, including its thermal energy, kinetic energy, and potential energy.
The change in internal energy is given by the equation:
ΔU = Q - W
Where ΔU is the change in internal energy, Q is heat transfer into or out of the system, and W is work done on or by the system.
Given the information that 87.33 kJ of heat has been absorbed and the internal energy is 1,999 J, we can calculate the work done on the system:
ΔU = Q - W
ΔU = 87.33 kJ - W
ΔU = 87.33 kJ - W
ΔU = 87.33 x 10^3 J - W
ΔU = 87,330 J - W
ΔU = 87,330 J - W
ΔU = 1,999 J
87,330 J - W = 1,999 J
W = 87,330 J - 1,999 J
W = 85,331 J
W = 85.33 kJ
So the value for work done on the system is -85.33 kJ. This means that 85.33 kJ of energy has been transferred from outside the system to the system due to a force acting over a distance.
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Two cars leave an intersection at the same time, one heading east and the other heading south. Some time later the cars were 200 mi apart. If the car heading south travels 50 miles farther than the car going east, how far does the car heading east travel? round the answer to the nearest tenth.
If the car heading south travels 50 miles farther than the car going east, how far does the car heading east travel travels 150.0 miles, the problem can be solved by the formula d = rt.
The used equation is d = rt, The equation states that the distance traveled is equal to the rate times the time. This equation can be used to calculate the distance traveled by an object, given that the rate and time are known. In this case, the rate was the same for both cars and the time was the same for both cars, allowing us to calculate the distance traveled by a car heading east. Since we know that the car heading south traveled 50 miles farther than the car going east, we can subtract 50 miles from the total distance of 200 mi to find the distance traveled by car heading east. This gives us a value of 150 mi, which can be rounded to the nearest tenth to give us 150.0 miles.
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A Ferris wheel has radius 46 meters and it moves at a rate of 2 revolutions per minute. Approximate the angular velocity of the Ferris wheel ω in radians per minute. Give approximation correct to one decimal place.
The angular velocity of the Ferris wheel can be calculated using the formula ω = (2π/60) × (2 rev/min), where 2π radians is equal to 360 degrees.
What is the radians ?Radians are a unit of measure used in mathematics and trigonometry to measure angles. It is defined as the angle subtended at the center of a circle by an arc of the circumference that is equal in length to the radius of the circle. Radians are used to measure angles in both two-dimensional and three-dimensional space, and can be expressed as a ratio of the length of the arc to the radius of the circle. The most common radian measure is the radian, which is equal to 180/π degrees.
ω ≈ 0.4 rad/min
The angular velocity of the Ferris wheel can be calculated using the formula ω = (2π/60) × (2 rev/min), where 2π radians is equal to 360 degrees.
Therefore, ω = (2π/60) × (2 rev/min) = (2π/30) rad/min ≈ 0.4 rad/min.
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According to the theory of relativity, the mass m of a particle depends on its velocity v. Consider the following equation, where m0 is the mass when the particle is at rest and c is the speed of light.
The equation for the mass of a particle according to the theory of relativity is: m = m0 / (1 - (v/c)^2), where m0 is the mass when the particle is at rest and c is the speed of light.
This equation shows that the mass of a particle increases as its velocity approaches the speed of light. For example, when a particle reaches the speed of light, its mass becomes infinite.
This is why the equation for the mass of a particle includes the speed of light, as the particle's mass depends not only on its velocity, but also on the speed of light.
At very high velocities, the relativistic mass of a particle can be significantly greater than its rest mass, and this difference increases as the particle's velocity increases.
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Determine the required concentration (in percent by mass) for an aqueous ethylene glycol (C2H6O2) solution to have a boiling point of 108.3 ∘C. Express your answer using two significant figures. nothing % %
The required concentration (in percent by mass) for an aqueous ethylene glycol (C2H6O2) solution is 51 %.
What is Ethylene glycol?A helpful industrial substance called ethylene glycol can be found in a variety of consumer goods. Antifreeze, some stamp pad inks, ballpoint pens, solvents, paints, plastics, films, and cosmetics are a few examples. It may also serve as a delivery system for drugs.
Because of its pleasant flavor, ethanol is frequently consumed intentionally or by mistake. In the body, ethylene glycol decomposes into harmful substances.
The central nervous system (CNS), followed by the heart and kidneys, are the first organs that are impacted by ethylene glycol and its harmful byproducts.
Therefore, The required concentration (in percent by mass) for an aqueous ethylene glycol (C2H6O2) solution is 51 %.
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A semicircular loop of radius a carries positive charge Q distributed uniformly.(Figure 1) Find the electric field at the loop's center (point P in the figure). Hint: Divide the loop into charge elements dq as shown in the figure, and write dq in terms of the angle d theta, then integrate over theta. Express your answer in terms of i, j, k, Q, a.
The electric field at the center of the charged semicircular loop (point P) is given by: E = (k × Q) / (2 × a) × (i + j + k).
What is electric field?The electric field is a measure of the electric force exerted by a charged object on other charged objects in its vicinity. It is a vector quantity that specifies the direction and magnitude of the force that would be experienced by a unit positive charge placed in that field.
The electric field at the center of a charged circular loop can be calculated using the following steps:
Divide the loop into small charge elements dq, each at an angle dθ from the center of the loop (point P).
The electric field due to each small charge element dq at point P is given by:
dE = (k × dq × r) / (r²),
where k is Coulomb's constant, r is the distance from the charge element dq to point P, and r² = a² + (a × dθ)²
Integrating the above expression over the entire loop (from θ = 0 to θ = π), we get the total electric field at point P:
E = k × Q × (∫(a / (a² + (a × dθ)²) × dθ) from 0 to π)
Evaluating the above integral, we get:
E = (k × Q × a) / (2 × a) = (k × Q) / (2 × a)
Therefore, the electric field at the center of the charged semicircular loop (point P) is given by:
E = (k × Q) / (2 × a) × (i + j + k), where i, j, k are the unit vectors in the x, y, and z directions respectively.
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f the coefficient of static friction between the axe and the wood is ms = 0.2, determine the smallest angle u of the blade which will cause the axe to be self-locking. neglect the weight of the axe.
The smallest angle u of the blade which will cause the axe to be self-locking is θ=22.6 degree
EFy=0
2(N sin θ/2)-2(0.2N cos θ/2)=0
tan theta/2= 0.2
θ= 22.6 degree
The frame, locking hydraulic cylinder, and cam self-locking mechanism make up the self-locking system, which makes sure that the robot's traction is greater than the locking force. The locking cam, two guide wheels, a guide plate, and a connecting rod are the basic components of the cam self-locking mechanism.
We have done so succinctly and plainly. Lead screw nuts and lead screws that are self-locking cannot be moved without the use of external force. The pitch and coefficient of friction are relevant. In many instances, self-locking enables the user to do without an expensive brake.
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A box weighing 43.2 N is pulled horizontally until it slides uniformly over a
level floor. If the applied force is 6.30 N, what is the coefficient of
friction between the box and the floor?
The coefficient of friction between the box and the floor is approximately 0.852.
What do you mean by force?Force is a concept in physics that refers to a push or pull upon an object that results in a change in the object's motion. Forces can cause objects to accelerate, change direction, or change shape. In physics, a force is a vector quantity, meaning it has both magnitude and direction.
Forces can be caused by many factors, including gravity, electromagnetic fields, and the interaction between objects. They can be measured in units of Newtons (N), and the effects of forces can be described by Newton's laws of motion, which explain how objects will respond to different forces.
The coefficient of friction (μ) can be calculated using the formula:
μ = Friction force / Normal force
where the friction force is equal to the applied force minus the force due to gravity on the box:
Friction force = Applied force - Force due to gravity
The force due to gravity on the box is given by:
Force due to gravity = weight of box = 43.2 N
So, substituting these values, we get:
μ = (Applied force - 43.2 N) / 43.2 N
μ = (6.30 N - 43.2 N) / 43.2 N
μ = -36.9 N / 43.2 N
μ = -0.852
Since the coefficient of friction can only be positive, the negative sign indicates that the direction of the friction force is opposite to that of the applied force.
Therefore, the coefficient of friction between the box and the floor is approximately 0.852.
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what must the charge (sign and magnitude) of a particle of mass 1.43 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 690 n/c ? use 9.80 m/s2 for the magnitude of the free-fall acceleration.
The charge of a particle of mass 1.43 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 690 n/c.
What is gravitational force?
Gravitational force is a type of force that exists between any two objects with mass. It is the force of attraction between objects that is directly proportional to the product of their masses, and inversely proportional to the square of the distance between them. The strength of gravitational force is determined by the force of gravity, which is determined by the mass of objects and the distance between them.
Charge of Particle = q
Gravitational Force (Fg) = m * g
Electric Force (Fe) = q * E
Fg = Fe
m * g = q * E
q = (m * g) / E
q = (1.43 g * 9.80 m/s²) / (690 n/c)
q = 0.0211 C
Charge (sign and magnitude) of the particle is 0.0211 C.
Thus, The charge of a particle of mass 1.43 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 690 n/c.
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You attempt to use your multimeter to measure the electric potential difference, but the value stays at 0.00 V no matter what you do and there is an H on the screen. What's going on?
a. The multimeter is probably broken and you should give it to your instructor/TA.
b. You probably plugged in the wires incorrectly. Try using the 10A and V ports.
c. Someone pressed the "Hold" button. If you press it again, the multimeter should work correctly.
d. Someone pressed the "Handheld" button. The multimeter will only work if you hold it in your hand while using it.
Someone pressed the "Hold" button. If you press it again, the multimeter should work correctly.
When the "Hold" button is pressed on a multimeter, it temporarily freezes the measurement value displayed on the screen, even if the voltage being measured changes. This can be useful if you want to take note of a specific reading without having to continually look at the screen. If the value stays at 0.00 V and an "H" is displayed, it is likely that the "Hold" button has been pressed, and pressing it again should release it and allow the multimeter to display accurate voltage readings.
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what is the particle's angular velocity at a) t =1
At time t = 1 s, the particle's angular velocity is 6.28 rad/s (role="math" localid="1652184311109").
w = theta / t, where w = angular velocity, theta = position angle, and t = time, denotes the rate of change of an object's position angle with respect to time. Therefore, the wheel's angular velocity at t=15s t = 15 s is 8.33rad/s 8.33 r a d/s. A particle's instantaneous velocity, or v(t), is the derivative of its position relative to time. Therefore, v(t)=dxdt. This derivative is frequently represented by the symbols x(t) or just x. The amount of rotational angle (or angular displacement) made by a rotating body in one unit of time is known as its angular velocity.Omega () is used to represent it. Angular velocity is defined mathematically as rad/s = dtd. SI units are measured in radians per second.
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When a gas is turned into a liquid, the process is called?
Answer:
the process is condensation
a particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. find the velocity and speed when t = 9.
The value of velocity at t = 9 when the equation of motion is given is calculated to be -1.0123.
The given function is f(t) = (t^-1) - t, it is an equation of motion.
On derivation of the equation of motion, we get the equation of velocity.
Taking derivative on both the sides of the function,
f'(t) = d/dt[(t^-1) - t)] = d/dt(t^-1) - d/dt(t)
f'(t) = -1(t^-2) -1
f'(t) = -t^-2 - 1
f'(t) = v(t),
It can be also written as,
-1/t^2 - 1
To find out the velocity at t = 9, place the value in the above equation.
So, v(9) = -1/(9^2) - 1 = -1/81 - 1 = -0.0123-1 = -1.0123
The given question is incomplete. The complete question contains 'f(t) = (t ^-1) - t.'
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A piece of aluminium of mass 260g is cooled in a freezer. It is then dropped into 140 g of water at 5°C, causing 4.0g of water to freeze. Determine the temperature inside the freezer
Answer:
To determine the temperature inside the freezer, you need to calculate the enthalpy of fusion of the 4g of water that froze. The enthalpy of fusion of water is 334 J/g. Thus, the total enthalpy of fusion of the 4g of water is 334 J/g × 4 g = 1336 J. The total heat gained by the water and aluminium is the enthalpy of fusion of the water plus the heat gained by the aluminium by cooling it in the freezer. Since the heat gained by the aluminium is equal to the heat lost by the water, the temperature inside the freezer can be calculated using the equation Q = mcΔT, where Q is the heat transfer, m is the mass of the aluminium, and ΔT is the change in temperature. Thus, the temperature inside the freezer is 1336 J / (260g × 0.90 J/g°C) = 6.2°C
activation-synthesis theory- dreams are caused by random neural firings combined with memories
manifest conent- literal content of a dream
freuds theory of dreams- dreams can be used to access unconscious conflicts
non-rem dreams- mundane, dull, everyday events when asleep
rem dreams- illogical, bizarre, and highly visual experiences when asleep
latent content- what a dream symbolizes
The Activation-Synthesis Theory is a neurobiological way to explain the origin of dreams.
A neurobiological theory that explains the neurogenesis of dreams is called the Activation-Synthesis Theory. According to the activation-synthesis dream theory, also known as the neural activation theory, when people dream, their minds are attempting to make sense of the brain activity occurring in the brain stem. The study of nervous system cells and the function of the signals that pass through the nervous system is known as neurobiology. The brain is still quite active while dreaming. The body's biochemical and survival processes are still being carried out by the brain, which is also recharging the body for the next day. These physiological functions of survival include breathing, blood circulation, and healing. The brain stem, often known as the lower half of the brain, carries out these functions.
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you need to measure the height of a small tree. your metal measuring tape has been sitting in the sun on a hot summer day while your coworker’s measuring tape has been in an air-conditioned car.
A 25°c calibration has been applied to a steel tape measure. If a length of plastic pipe is measured with a tape measure at 15 °C outdoors, the measurement will be smaller than the real measurement.
The Temperature.
In particular, temperature is a measurement of the average kinetic energy, or energy associated with motion, of the particles that make up an item. It describes the temperature of something. However, how hot and how cold are they exactly? The usage of terms like hot and cold is not particularly scientific.
If we want to precisely express how hot or cold something is, we must utilise temperature. How hot is, for instance, molten iron? In order to respond, a physical scientist would take into account the temperature of the liquid metal. The word "temperature" should be used in place of ambiguous terms like "hot" or "cold."
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The half-life of 158O is 122 s. How long does it take for the number of 158O nuclei in a given sample to decrease to a factor of 1×10−3 of the initial value?
The time taken by 10.3 half lives is 1257 s which is equal to for the number of 15 8 O nuclei in a given sample to decrease to a factor of 8 × 10⁻⁴ of the initial value.
The equation which determines the disintegration of atoms is,
N = N₀ e⁻(λt)
where, N is the number of atoms undergoing decay
N₀ is the initial number of atoms present
λ is the rate constant
t is the time
For the number of 15 8 O nuclei in a given sample to decrease to a factor of 8 × 10⁻⁴ of the initial value, the number of half-lives decay took place be n which is given by,
2⁻ⁿ = 8 × 10⁻⁴
Taking log on both sides we have,
- n ln 2 = ln(8 × 10⁻⁴)
n = 10.3
Time taken to complete 10.3 half lives is 10.3 × 122 s = 1257 s which is equal to for the number of 15 8 O nuclei in a given sample to decrease to a factor of 8 × 10⁻⁴ of the initial value.
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does the skateboarder and the energy appear to be similar to what we saw in the previous two labs? how?
This can only be determined based on the specific labs conducted in the previous two experiments and the information provided about the current situation.
The similarity between the skateboarder and the energy observed in the previous two labs can only be determined based on the specific information and observations made during those experiments. Without any specific details about the previous two labs, it is impossible to make a comparison between the skateboarder and the energy in the current situation.
To make a comparison, we need to know the specific variables that were being studied in the previous two labs and the specific observations made. For example, if the previous two labs were studying the conservation of energy and the relationship between kinetic and potential energy, then a comparison could be made by observing the skateboarder's kinetic energy, potential energy, and total energy as he moves along the ramp.
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which of the following levers would be most effective to use to move a specific object if your only objective was a slight movement of the object? a third-class lever with a resistance arm of 20 and a force arm of 10 each lever would be just as effective as the others a second-class lever with a resistance arm of 10 and a force arm of 20 a first-class lever with a resistance arm of 10 and a force arm of 10
3rd class with RA of 20 and FA of 10 levers would be best to use to move a specific object if your only objective was speed of the object's movement.
What do you mean by speed?Speed, which is a scalar quantity, is the "speed at which an object is moving." The rate at which an object travels a distance can be thought of as its speed. A fast-moving object travels at a high speed and completes a significant distance in a brief period of time.
Miles per hour (mph), kilometres per hour (km/h), and metres per second (m/s) are the three most popular speed units (mph). The distance an object covers in a given amount of time is its speed. Speed equals distance x time is the speed equation. The metre per second, abbreviated as m/s or ms-1, is the SI unit of speed.
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QUESTION: Which of the following levers would be best to use to move a specific object if your only objective was speed of the object's movement?
A. 1st class with RA of 10 and FA of 20
B. 2nd class with RA of 10 and FA of 20
C. 3rd class with RA of 20 and FA of 10
D. each would be just as effective as the others
What is the temperature of 1000 K on the Celsius scale?
The required temperature on celsius scale when temperature on kelvin scale is given is calculated to be 726.85 °C.
The thermometer industry's two most used temperature measurement scales are the Celsius and Kelvin scales. One degree on the Celsius scale has the same value as one degree on the Kelvin scale since the temperature difference or change is the same on both measures.
The given temperature in kelvin scale is 1000K.
Let us convert it into celsius scale.
The relation between celsius scale and kelvin scale is
°C = K - 273.15
where,
°C is temperature in celsius scale
K is temperature in kelvin scale
Putting the known values into the above equation, we have,
°C = 1000 - 273.15 = 726.85 °C
Thus, the required temperature is 726.85 °C.
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the human body is made primarily of water, which has a density of 1000 kg/m3. a certain woman weighs 119 pounds. one kilogram of mass weighs about 2.2 pounds.
The woman has a volume of approximately 0.05404 m3, which is primarily made up of water.
The conversion factor between pounds and kilograms is 1 pound = 0.45359237 kilograms. So, to convert the weight of the woman from pounds to kilograms, we can use the following calculation:
119 pounds * 0.45359237 kilograms/pound = 54.04 kilograms
The density of water is 1000 kg/m3, which means that a volume of 1 m3 of water weighs 1000 kilograms. To calculate the volume of the woman, we can divide her mass by the density of water:
Volume = Mass / Density = 54.04 kilograms / 1000 kg/m3 = 0.05404 m3.
So, the woman has a volume of approximately 0.05404 m3, which is primarily made up of water.
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A satellite of mass 2,000 kg is in an elliptical orbit about the Earth: When the satellite reaches point A, which is the closest point to the Earth, its orbital radius is 1.2 x10^7 m and its orbital velocity is 7.1x 10^3 m/s. (ME = 6x10^24 kg and Re = 6.4x10^6m) - Determine the total mechanical energy of the satellite at point A assuming that the gravitational potential energy is zero at an infinite distance from the Earth.
- Determine the angular momentum of the satellite at point A.
- What is the minimum speed of the satellite at point A in order to escape from Earth?
a. The total mechanical energy is [tex]EM = -4.4*10^{14} J.[/tex]
b. The angular momentum of the satellite at point A is [tex]L = 8.5*10^{12} kg m2/s.[/tex]
c.The minimum speed of the satellite at point A in order to escape from Earth is [tex]ve = 11.2*10^{3 }m/s.[/tex]
a. The total mechanical energy of the satellite at point A is equal to the sum of its kinetic and potential energies. The kinetic energy is given by [tex]KE = \frac{1}{2} mv2,[/tex], where m is the mass of the satellite and v is the orbital velocity. The potential energy is given by [tex]PE = \frac{-GMEm}{r}[/tex], where G is the gravitational constant, M is the mass of the Earth, and r is the orbital radius. Thus, the total mechanical energy is
[tex]EM = KE + PE = \frac{1}{2} mv2, - \frac{GMEm}{r}.[/tex]. Substituting [tex]m = 2,000 kg, v = 7.1*10^{3} m/s, \\G = 6.67*10^{-11} N m2/kg2, M = 6*10^{24} kg,\\r = 1.2*10^{7} m[/tex]
we obtain[tex]EM = -4.4*10^{14} J.[/tex]
b. The angular momentum of the satellite at point A is given by L = mvr, where m, v, and r are as defined above. Substituting the given values, we obtain [tex]L = 8.5*10^{12} kg m2/s.[/tex]
c. The minimum speed of the satellite at point A in order to escape from Earth is the escape velocity, which is equal to the square root of twice the gravitational potential energy at point A. Substituting the given values for M and r, we obtain the escape velocity [tex]ve =\sqrt(2GM/r) = 11.2*10^{3 }m/s.[/tex]The minimum speed of the satellite must be greater than the escape velocity in order for it to escape from Earth.
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which of the following statements accurately represents the relationship between linear and angular motion? none of the answers are correct. linear motion of joints produces an angular motion. angular motion of joints produces the linear motion of walking, and linear motion of joints produces an angular motion. angular motion of joints produces the linear motion of walking.
The correct statement is: Angular motion of joints produces the linear motion of walking.
Angular motion is the motion of a body about a fixed point or fixed axis. It is equal to the angle passed over at the point or axis by a line drawn to the body.Relationship between linear and angular motion are as follows:Displacement – In linear motion, we use ‘s’ to quantify the linear distance travelled. In angular motion, we use ‘θ’ for the same to quantify the angular distance, and it is measured in radians.
Velocity – In linear motion, we use ‘v’ to denote velocity while in angular motion, we use ‘ω’ to indicate angular velocity. Angular velocity is the number of radians covered per second.
Acceleration – We use ‘a’ to denote linear acceleration, while we use ‘α’ to mean angular acceleration. The unit of angular acceleration is radians per second square
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