with respect to air the refractive index of ice is 1.31 and that of rock salt is 1.54 calculate the refractive index of rock salt with respect to ice​

Explanation:

Lets say you have a ball in your hand, you raise your hand to just above your head. Now, when you did that you created potential energy that is ready to be released. you drop the ball and the ball bounces a few times off the ground. Now lets say you got a ladder and doubled the ball's height doubling the energy now stored in the ball, when you drop it the ball should bounce much higher after hitting the ground as a result of more energy being released.

Hope this helped.

Answer:

7.5 J

Explanation:

To answer the question given above, we need to determine the energy that will bring about the speed of 1 m/s. This can be obtained as follow:

Mass (m) = 15 Kg

Velocity (v) = 1 m/s

Energy (E) =?

E = ½mv²

E = ½ × 15 × 1²

E = ½ × 15 × 1

E = ½ × 15

E = 7.5 J

Therefore, to change the speed to 1 m/s, the employee must do a work of 7.5 J.

Answer:

O C. A person absorbs most of the light that hits him or her.

Explanation:

Answer:

Answer:

a. Time = 3.6 seconds

b. Time = 4.4 seconds

Explanation:

Given the following data;

Distance = 180 m

Speed = 50 m/s

a. To find the time;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the formula;

[tex]Speed = \frac{distance}{time}[/tex]

Making time the subject of formula, we have;

[tex]Time = \frac{distance}{speed}[/tex]

Substituting into the equation, we have;

[tex]Time = \frac{180}{50}[/tex]

Time = 3.6 seconds

b. Distance = 220 meters

Speed = 50 m/s

To find the time;

[tex]Time = \frac{distance}{speed}[/tex]

Substituting into the equation, we have;

[tex]Time = \frac{220}{50}[/tex]

Time = 4.4 seconds

Answer:

Effort = 540 Newton

Explanation:

Given the following data;

Load arm = 60 cm

Effort arm = 40 cm

Load = 360 N

Conversion:

100 cm = 1 meters

40 cm = 40/100 = 0.4 meters

60 cm = 60/100 = 0.6 meters

To calculate the effort that Reha should apply to lift Neha, we would use the expression;

Effort * effort arm = load * load arm

Substituting into the expression, we have;

Effort * 0.4 = 360 * 0.6

Effort * 0.4 = 216

Effort = 216/0.4

Effort = 540 Newton

Answer:

h = 1/2gt^2

Is the formula for the height of a free falling object.

Put in the numbers:

h = 1/2*9.8 (gravitational constant) * 10^2

h=490 meters.

Please note that the gravitational constant is approximate, you could also use a more specific value or 10

Answer:

w=f×s

w = 16000 J, hope this helps

Answer:

I = 20 A

Explanation:

The question says that, "A load of 6,000 C is conducted through a cross section in 5 minutes. Determining-if a current is not correct, we will find the value of?"

We have,

Charge, q = 6,000 C

Time, t = 5 minutes = 300 s

We need to find the current. We know that, the charge flowing per unit time is equal to current. So,

[tex]I=\dfrac{q}{t}\\\\I=\dfrac{6000}{300}\\\\I=20\ A[/tex]

So, the current flowing through the circuit is 20 A.

Answer:

acceleration is the vector quantity because it depends on particular direction and has magnitude

Answer:

power per square meter = 4.593 × 10^(6) W/m²

Wavelength of peak intensity = 9.67 × 10^(-7) m

Explanation:

From Stefan-Boltzmann law, total emitted power per square meter is given as;

P/A = eσT⁴

where;

P is power

A is surface area

σ = Stefan-Boltzmann constant = 5.67 × 10^(-8) W/m².k⁴

T = temperature of the body = 3000 K

e = emissivity of the substance (for ideal radiation, it has a value = 1)

Thus, Plugging in the relevant values we have;

P/A = 1 × 5.67 × 10^(-8) × (3000)^(4)

P/A = 4.593 × 10^(6) W/m²

Let's find the wavelength of peak intensity.

From wiens displacement law, we know that;

λ_m × T = b

where;

λ_m = maximum wavelength

T = Temperature

b is Wien's displacement constant = 2.9 × 10^(−3) m/K

thus;

λ_m = b/T = (2.9 × 10^(−3))/3000 = 9.67 × 10^(-7) m

Answer:

Ionosphere

Explanation:

The thermosphere reaches 600 kilometres just above mesosphere and begins immediately above the mesosphere. This layer is where the aurora and satellites appear.

The ionosphere is the comprehensive career of the mesosphere because most of the thermosphere, located 80–400 kilometres just above ground atmosphere.

Auroras — magnificent flowing streaks of light seen in the night sky – appear in this location.

Answer:

Jupiter and neptune

Explanation:

Answer:

a) The net momentum of the bullet-block system before the collision is 25 kilogram-meters per second.

b) The initial translational kinetic energy of the bullet before the collision is 625 joules.

c) The final speed of the bullet-block system after the collision is 7.143 meters per second.

d) The total energy of the bullet-block system after the collision is 89.289 joules.

e) 89.289 joules must be done to stop the bullet-block system.

f) The bullet-block system will travel 13.007 meters before stopping.

Explanation:

a) Since no external forces are applied on the system defined by the bullet and the block, then the net momentum is conserved and can be calculated by  the initial momentum of the bullet:

[tex]p = m\cdot v_{o}[/tex] (1)

Where:

[tex]p[/tex] - Net momentum, in kilogram-meters per second.

[tex]m[/tex] - Mass of the bullet, in kilograms.

[tex]v_{o}[/tex] - Initial speed of the bullet, in meters per second.

If we know that [tex]m = 0.5\,kg[/tex] and [tex]v_{o} = 50\,\frac{m}{s}[/tex], then the net momentum of the bullet-block system before the collision is:

[tex]p = (0.5\,kg)\cdot \left(50\,\frac{m}{s} \right)[/tex]

[tex]p = 25\,\frac{kg\cdot m}{s}[/tex]

The net momentum of the bullet-block system before the collision is 25 kilogram-meters per second.

b) The total energy of the bullet before the collision is its initial translational kinetic energy ([tex]K[/tex]), in joules:

[tex]K = \frac{1}{2}\cdot m \cdot v_{o}^{2}[/tex] (2)

[tex]K = \frac{1}{2}\cdot (0.5\,kg)\cdot \left(50\,\frac{m}{s} \right)^{2}[/tex]

[tex]K = 625\,J[/tex]

The initial translational kinetic energy of the bullet before the collision is 625 joules.

c) Both the bullet and the block experiments a complete inelastic collision, then the final speed of the bullet-block system is calculated solely by the Principle of Momentum Conservation:

[tex]v_{f} = \frac{m\cdot v_{o}}{m+M}[/tex] (3)

Where:

[tex]v_{f}[/tex] - Final speed, in meters per second.

[tex]M[/tex] - Mass of the block, in kilograms.

If we know that [tex]m = 0.5\,kg[/tex], [tex]v_{o} = 50\,\frac{m}{s}[/tex] and [tex]M = 3\,kg[/tex], then the final speed of the bullet-block system is:

[tex]v_{f} = \left(\frac{0.5\,kg}{0.5\,kg + 3\,kg} \right)\cdot \left(50\,\frac{m}{s} \right)[/tex]

[tex]v_{f} = 7.143\,\frac{m}{s}[/tex]

The final speed of the bullet-block system after the collision is 7.143 meters per second.

d) The total energy of the bullet-block system after the collision is the translational kinetic energy of the system ([tex]K[/tex]), in joules, is:

[tex]K = \frac{1}{2}\cdot (m + M)\cdot v_{f}^{2}[/tex] (4)

[tex]K = \frac{1}{2}\cdot (0.5\,kg + 3\,kg)\cdot \left(7.143\,\frac{m}{s} \right)^{2}[/tex]

[tex]K = 89.289\,J[/tex]

The total energy of the bullet-block system after the collision is 89.289 joules.

e) By Work-Energy Theorem, magnitude of the work done by friction must be equal to the magnitude of the translational kinetic energy of the system. Hence, 89.289 joules must be done to stop the bullet-block system.

f) The maximum travelled distance of the bullet-block after the collision can be determined by means of Work-Energy Theorem and definition of work:

[tex]W = \mu_{k}\cdot (m+M)\cdot g\cdot s[/tex] (5)

Where:

[tex]W[/tex] - Work done by friction, in joules.

[tex]g[/tex] - Gravitational acceleration, in meters per square second.

[tex]s[/tex] - Travelled distance, in meters.

[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, no unit.

If we know that [tex]m = 0.5\,kg[/tex], [tex]M = 3\,kg[/tex], [tex]\mu_{k} = 0.2[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]W = 89.289\,J[/tex], then the travelled distance of the bullet-block system is:

[tex]s = \frac{W}{\mu_{k}\cdot (m+M)\cdot g}[/tex]

[tex]s = \frac{89.289\,J}{0.2\cdot (0.5\,kg + 3\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}[/tex]

[tex]s = 13.007\,m[/tex]

The bullet-block system will travel 13.007 meters before stopping.

Explanation:

3: the electricity is generated in the permanent magnet

Answer:

Also, as stream depth increases, the hydraulic radius increases thereby making the stream more free flowing. Both of these factors lead to an increase in stream velocity. The increased velocity and the increased cross-sectional area mean that discharge increases.

Answer:

table and chair

Explanation:

In a meeting room there are tables, chairs, and other people. Which of them have temperatures

a) smaller, b) bigger and d) equal to that of air?

the temperature of tables and chairs is same as air.

Answer:

Netball is a ball sport for two teams of seven players it's rules are published in print and online by the international netball federation Games are played on a rectangular court divided into thirds with a raised goal at coach short end

Explanation:

It will help you

Answer:

Velocity = distance / time

V = 10/1

V = 10km/h

Answer:10km/h or 2.77m/s.

Explanation:

Distance =10km

Time =1h

Velocity =10/1 =10km/h

Or,

Distance =10km =10000m

Time =1h =60min = 3600s

Velocity =10000/3600 =2.77m/s

Explanation:

area=length(m) ×breadth(m) . The unit of area is expressed in terms of fundamental units m^2.thus it is derived unit

Answer:

a. V₂ = 6 V

b. 360 joules

c. The positive terminals of both the voltmeter and ammeter are connected to the positive terminal of the power source

Please see the attached drawing created with MS Visio

Explanation:

a. The voltmeter readings are;

V₁ = 12 V, V = 18 V

Given that the voltage reading, 'V', is the voltage reading across two loads with voltages, V₁ and V₂ connected in series, we have;

V = V₁ + V₂

V₂ = V - V₁

V₂ = 18 V - 12 V = 6 V

b. The reading of the ammeter, A, I = 0.5 A

The heat energy, Q  = I·V·t

Where;

t = The time = 1 minute (60 seconds)

Therefore, for the lamp L₁, where V = 12 V, we have;

Q₁ = 0.5 A × 12 V × 60 s = 360 Joules

The amount of electrical energy changed into heat and light in lamp L₁, Q₁ = 360 joules

c. The positive terminals of the voltmeter and ammeter are connected to the positive terminal of the power source

Please see attached drawing created with MS Visio

Answer:

Mechanical advantage is the measure of the force amplification achieved by using a tool , mechanical device or machine . The machine preserve the input power and supply trade off force. against movement to obtain a desired amplification in the output force .

Answer:

The ratio of load overcome by the machine to the effort applied is called mechanical advantage.

By Newton's second law, the net force acting on the crate parallel to the surface is

∑ F = mg sin(10°) - 800 N = ma

where m = 500 kg is the mass of the crate and a is the acceleration.

Solve for a :

a = ((500 kg) (9.80 m/s^2) sin(10°) - 800 N) / (500 kg)

a ≈ 0.102 m/s^2

Answer:

¿Podrías poner la pregunta en inglés por favor?

Explanation:

Answer: The given statement is True

Explanation:

A uniform motion is defined as the motion where an object is moving at a constant speed.

A non-uniform motion is defined as the motion where an object keeps changing its position and does not move at a constant speed.

We are given:

A car takes a full round of journey in a roundabout with constant speed

As the speed remains constant in a circular path, it is considered a uniform motion.

Hence, the given statement is True

Explanation:

The difference of electrical potential between two points is called the potential difference.

It is also defined as the work done in the transfer of a unit quantity of electricity from one point to the other.

The SI unit of electric potential is volt. It is denoted by V.

The gravitational force does change believe it or not, but the explaination for this is because the earths orbit is an oval (or a not circle) the closer it nears its self to the sun.