Answer:
see in the picture, we have Z(-3; -3)
so after a D(1/3), we have:
x' = -3.1/3 = -1
y' = -3.1/3 = -1
=> Z'(-1; -1)
Describe the steps you would take to solve the given literal equation for m as shown.
For finding the given literal equation is necessary to apply the power 2 on both sides of the given equation and after that you should rewrite the equation as a function of the variable m .
Power RulesThere are different power rules, see some them:
1. Multiplication with the same base: you should repeat the base and add the exponents.
2. Division with the same base: you should repeat the base and subctract the exponents.
3.Power. For this rule, you should repeat the base and multiply the exponents.
4. Zero Exponent. When you have an exponent equals to zero, the result must be 1.
The question gives: [tex]t=2\pi *\sqrt{\frac{m}{k}}[/tex] and from the previous equation, you should find [tex]m=\frac{kt^2}{4\pi ^2}[/tex].
STEP 1 - Applying the power 2 on both sides of the equation [tex]t=2\pi *\sqrt{\frac{m}{k}}[/tex].
[tex]t=2\pi *\sqrt{\frac{m}{k}}\\ \\ t^2=(2\pi *\sqrt{\frac{m}{k}})^2\\ \\ t^2=4\pi ^2*\frac{m}{k}[/tex]
STEP 2 - Rewriting the equation [tex]t^2=4\pi ^2*\frac{m}{k}[/tex] as a function of the variable m .
[tex]t^2=4\pi ^2*\frac{m}{k}\\ \\ t^2k=4\pi ^2m\\ \\ m=\frac{kt^2}{4\pi ^2}[/tex]
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Answer:
1. divide both sides of the equation by 2pi
2. square both sides of the equation
3. use the rule to simplify a fraction to a power
4. multiply both sides of the equation by k
Step-by-step explanation:
edg '22
Jerome solved the equation below by graphing. log subscript 2 baseline x log subscript 2 baseline (x minus 2) = 3
x = 4 would be the solution of the given problem.
I can't speak to the first part of this question, as I don't totally have context for what they're asking, but we can solve for x using one of the laws of logarithms, namely:
log.m + log.n = log.mn
Using this law, we can combine and rewrite our initial equation as
log(x^2- x) = 3
Remember that logarithms are simply another way of writing exponents. The logarithm is just another way of writing the fact . Keeping that in mind, we can express our logarithm in terms of exponents as
log(x^2- x) = 3 --> x^2- 2x = 8
2³ = 8, so we can replace the left side of our equation with 8 to get
x^2 - 2x - 8 =0
(x-4)(x+2) = 0
Hence x = 4 0r -2. As x cannot be negative so it would be 4.
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If two sides of a triangle have lengths of 8 in and 12 in what are the possible lengths
Answer:
The possible length of the third side is greater that 4ft and less that 20 ft
4<x<20
A freezer is shaped like a rectangular prism. It has a length of 8 feet and a height of 3 feet. The volume is 54 cubic feet. Find the width of the freezer.
show your work
The width of the freezer is 2.25ft
Volume of a rectangular prismThe formula for calculating the volume of rectangular prism is expressed as:
V = lwh
Given the following
length l = 8feet
w is the width
height h = 3feet
Substitute
54 = 8*3w
54 = 24w
w = 54/24
w = 2.25ft
Hence the width of the freezer is 2.25ft
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If point (4, 5) is on the graph of a function, which equation must be true?
f(5)=4
f(5,4)=9
f(4)=5
f(5,4)=1
Answer:
f(4) = 5
Step-by-step explanation:
Think about it this way
a point with an x value of 4,
this x value is put into the function,
then the function outputted a y value (or value) of 5.
So, we can name this function f(x)
Then, we let x = 4,
then the output for f(4) = 5
Answer: f(4) = 5
Step-by-step explanation:
If the point (4, 5) is on the graph of a function, this means that when you input 4 you get an output of 5.
Inputs are usually shown with the x-coordinate, and outputs are usually shown with the y-coordinate.
This means that (4, 5) is an input of 4 for an output of 5.
chegg Based on the graph of the general solution to the differential equation dy over dx equals 2 times x minus 2 times y comma which of the following statements is true
The statement which is true is the slopes are all positive in quadrant I.
Given the differential equation is dy/dx=2x-2y
A differential equation is an equation that contains at least one derivative of an unknown function, either a normal differential equation or a partial differential equation.
Given dy/dx=2x-2y
now slope=2x-2y
Along x-axis, y=0.
So, slope=2x≠0.
Since it depends upon x hence the slope along the y-axis are not horizontal.
Along y-axis, x=0.
So, slope=-2y≠0.
Since the slope along the x-axis are also not horizontal.
In quadrant I
x,y≥0
So, dy/dx≥0
Hence the slopes are all positive in quadrant I.
In quadrant IV,
x≥0,y≤0
so, dy/dx is not always positive.
This, the slope are not all positive in quadrant IV.
Hence, the slope are all positive in quadrant I for the differential equation dy/dx=2x-2y.
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the current value of a new car is 18,000. the car will depreciate 15% per year over the next 5 year. which exponential equation models this situation
The exponential equation that models this situation is:
[tex]V(t) = 18000(0.85)^t, 0 \leq t \leq 5[/tex].
What is an exponential function?A decaying exponential function is modeled by:
[tex]A(t) = A(0)(1 - r)^t[/tex]
In which:
A(0) is the initial value.r is the decay rate, as a decimal.For this problem, the parameters are:
A(0) = 18000, r = 0.15.
Hence the equation for the value of the car over the next 5 years is:
[tex]A(t) = A(0)(1 - r)^t[/tex]
[tex]A(t) = 18000(1 - 0.15)^t[/tex]
[tex]V(t) = 18000(0.85)^t, 0 \leq t \leq 5[/tex].
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URGENT! WILL GIVE BRAINLIEST!
Answer:
150 [tex]m^{2}[/tex]
Step-by-step explanation:
Consider the figure as an isosceles triangle and a rectangle combined.
ISOSCELES TRIANGLE
[tex]A = \frac{1}{2} bh[/tex]
[tex]A = \frac{1}{2} *15*12[/tex]
A = 90
RECTANGLE
[tex]A=lw[/tex]
[tex]A = 5*12[/tex]
[tex]A = 60[/tex]
60 + 90 = 150
Answer:
150m
Step-by-step explanation:
break up the polygon into a triangle and a rectangle.
Triangle:
to find the height of the triangle, subtract 5 from 20
height = 15m base = 12m
[tex]area=\frac{1}{2}bh\\ A=\frac{1}{2} (12)(15)\\A=6(15)\\A=90m[/tex]
rectangle:
[tex]A=bh\\A=12(5)\\A=60m[/tex]
Add both areas together:
[tex]90+60=150m[/tex]
Determine the perimeter of the figure.
Answer:
[tex]\huge\boxed{\sf 7x + 10\ cm}[/tex]
Step-by-step explanation:
Perimeter:Sum of all sides of a figure is the perimeter of the figure.Perimeter of the figure:= 5 + 2x + 2x + 5 + 3x
Combine like terms
= 2x + 2x + 3x + 5 + 5
= 7x + 10 cm
[tex]\rule[225]{225}{2}[/tex]
Answer:
7x + 10
Step-by-step explanation:
Perimeter is the sum of all the sides together, the distance around a shape.
3x + 5 + 2x + 2x + 5
Organize so the variables are on one side
3x + 2x + 2x + 5 + 5
Combine like terms:
7x + 10
Your answer would be: 7x + 10
I hope it helps! Have a great day!
bren~
7/11 = x/9
Round your answer to the nearest tenth.
The solution to the given fraction 7/11 = x/9 to the nearest tenth is 5.7
Fraction7/11 = x/9
cross product7 × 9 = 11 × x
63 = 11x
divide both sides by 11x = 63/11
x = 5.72727272727272
Approximately,
x = 5.7
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Determine the length of side QR in the following triangle
The length of the side QR in the task content can be determined as; 12.22cm.
What is the length of the third side QR?It follows from the task content that 2 lengths and one included angle are given in the task content. It therefore follows that the length of side QR can be evaluated by the cosine rule as follows;
QR² = 13² + 4² - (2×4×13×cos70)
QR = √149.4
QR = 12.22cm
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The length of the rectangle is 10.4cm. the perimeter of the rectangle is 28cm. calculate the area of the rectangle.
Answer:
37.44 cm²
Step-by-step explanation:
To find the width, follow these steps.
10.4*2=20.8
28-20.8=7.2
7.2/2=3.6
The width is 3.6.
To find the area, multiply the width and the length together.
10.4*3.6=37.44
The area of the rectangle is 37.44 cm²
Hope this helps!
Which expression is equivalent to (2 Superscript one-half Baseline times 2 Superscript three-fourths Baseline) squared?
RootIndex 4 StartRoot 2 cubed EndRoot
StartRoot 2 Superscript 5 EndRoot
RootIndex 4 StartRoot 4 cubed EndRoot
StartRoot 4 Superscript 5 EndRoot
Answer:
D
Step-by-step explanation:
find the only one digit number that is both a square number and a cubic number
Answer:
the only one digit number that is cube and square would be 1
Step-by-step explanation:
because 1 x1 = 1 and 1×1×1= 1
no other one digit number is both a square number and cubic number :)
hope it helps please let me know if you need more help :)
The vertices of a quadrilateral on the coordinate plane are (2, 4), (-4, -2), (-2, 4), and (4, -2). What type of quadrilateral has these vertices
Answer: Isosceles Trapezoid
Step-by-step explanation:
See the graph of the quadrilateral.
A square piece of paper measures 20
centimeters on each side. Four equally-
sized circles are going to be cut out from
the paper. What is the largest possible
area of ONE of the circles?
The largest possible area of one of the circles would be 314. 2 cm²
Area of a circleIt is important to note that the formula for finding the area of a circle is given as;
Area = [tex]\pi r^2[/tex]
From the information given, we have the sides of the square to have a value of 20cm
Also note that the measure of the sides of the square is the size of the diameter of the circle
But we need to find the radius
radius = diameter/2
radius = 20/ 2 = 10cm
Substitute value of radius into the formula for area
Area = 3. 142 × 10^2
Area = 3. 142 × 10 × 10
Area = 314. 2 cm²
The area of the circle is 314. 2cm^2
Thus, the largest possible area of one of the circles would be 314. 2 cm²
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(-4, 8) and (6, 2). Slope
Answer:
In order to go from the first point to the second, we need to rise from 4 to 7, i.e. by 3. We also need to run from -4 to -2, i.e. by 2. Therefore the slope is 32 .
Step-by-step explanation:
Quick algebra 1 question for 50 points!
Only answer if you know the answer, quick shout-out to Yeony2022, tysm for the help!
Answer:
b
Step-by-step explanation:
b shows direct variation because we can clearly tell that the slope of the graph is 1/2. The graph is also linear, and it crosses the origin (0,0).
a: This graph can be represented as y=2, and that is not a direct variation.
b: Above explanation. This graph is a direct variation.
c: This graph can be represented as x=-8, and that is not a direct variation.
d: This graph has the slope, but it does not cross the origin, so it is not a direct variation.
Answer:
Graph b
Step-by-step explanation:
Direct variation means "y varies directly as x”:
Direct variation equation:
[tex]y=kx[/tex]
where k is the (non-zero) constant of variation.
Note, therefore, that a direct variation equation passes through the origin, as when x = 0:
[tex]\implies y=k(0) \implies y=0[/tex]
Graph a
y does not change as x varies.
Therefore this graph does not model a direct variation.
Graph b
As x gets bigger, so does y. As x gets smaller, so does y.
The line passes through the origin (0, 0).
Therefore this graph models a direct variation.
Graph c
x does not change as y varies.
Therefore this graph does not model a direct variation.
Graph d
As x gets bigger, so does y. As x gets smaller, so does y.
However, the line does not pass through the origin (0, 0).
Therefore this graph does not model a direct variation.
The formula m =1/2(a+b) gives the mean M of two numbers a and b
a.express a in terms of m and b
b.hence find a when m=19 and
b=23
Answer:
a = 2m - b , a = 15
Step-by-step explanation:
(a)
m = [tex]\frac{1}{2}[/tex] (a + b) ← multiply both sides by 2 to clear the fraction
2m = a + b ( subtract b from both sides )
2m - b = a
(b)
when m = 19 and b = 23 , then
a = 2(19) - 23 = 38 - 23 = 15
a. 'a' in terms of m and b is given by: a = 2m - b.
b. when m = 19 and b = 23, the value of 'a' is 15.
a. To express a in terms of m and b, we can rearrange the mean formula:
m = (1/2)(a + b)
Now, we'll solve for 'a':
Multiply both sides by 2 to eliminate the fraction:
2m = a + b
Subtract 'b' from both sides:
2m - b = a
So, 'a' in terms of m and b is given by: a = 2m - b.
b. Now that we have the expression for 'a', we can find its value when m = 19 and b = 23:
a = 2m - b
a = 2(19) - 23
a = 38 - 23
a = 15
So, when m = 19 and b = 23, the value of 'a' is 15.
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give: ∠BDE ≅ ∠CDE and BD ≅ CD.
Prove ∠ABD ≅ ∠ACD
3) [tex]\angle ADB[/tex] and [tex]\angle BDE[/tex] are supplementary (if two angles form a linear pair, they are supplementary)
4) [tex]\angle ADC[/tex] and [tex]\angle CDE[/tex] are supplementary (if two angles form a linear pair, they are supplementary)
5) [tex]\angle ADB \cong \angle ADC[/tex] (supplements of congruent angles are congruent)
6) [tex]\triangle ADB \cong \triangle ADC[/tex] (SAS)
7) [tex]\angle ABD \cong \angle ACD[/tex] (CPCTC)
find the smallest number by which 29160 should be divided so that the quotient becomes a perfect cube
The smallest number by which 29160 should be divided so that the quotient becomes a perfect cube is 5
Perfect cube quotient of a division
The given number is 29160
Note that:
29160 can be factored into 5832
That is, 29160 = 5832 x 5
Take the cube of 5832:
[tex]\sqrt[3]{5832}=18[/tex]
Since it has been confirmed that 5832 is a perfect cube, the smallest number by which 29160 should be divided so that the quotient becomes a perfect cube is 5
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Construct a tangent to a circle through a point outside the circle using the construction tool. insert a screenshot of the construction here. alternatively, construct a tangent to a circle through a point outside the circle by hand using a compass and straightedge. leave all circle and arc markings. (10 points)
Tangent of a circle is a line which touches the circle at a point from outside the circle.
Given a tangent to a circle through a point outside the circle.
We have to draw a tangent to a circle from point outside the circle.
Tangent of a circle is a line which touches the circle at a point from outside the circle.. The point at which tangent touches the circle is known as point of contact.The radius of the circle and tangent are perprndicukar to each other at the point of contact. There cannot be any tangent to the circle through a point inside the circle. There can be one tangent to a point on the circle. The steps of drawing a tangent to a circle are as under:
1) Draw a circle with the radius neede with center O.
2) Join center of the circle O and any point P on the circle OP is the radius of the circle.
3) Draw a line perpendicular to radius OP through point P which is the intersection point of tangent and circle.
This line is the tangent to the circle at P.
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Answer:
igu
you could crop out question n use pic :)
On a number line, point D is at -6, and point E is at 8. Point F lies between points D and E. If DF: FEis 3: 1, where does point F lie on the
number line?
F is located on the number 4.5 on the number line.
Where does point F lie on the number line?We know that point D is at -6
Point E is at 8.
Point F is between D and E, such that the ratio:
DF:FE is 3:1
So if we divide the distance between D and E in 4 parts, 3 of these parts are DF, and one of these parts is FE.
First, the distance between E and D is:
distance = 8 - (-6) = 14 units.
Now, if we divide that by 4, we get:
14/4 = 3.5
Then we have:
DF = 3*(3.5) = 10.5
This means that F is at 10.5 units to the right of D, then:
F = D + 10.5 = -6 + 10.5 = 4.5
F is located on the number 4.5 on the number line.
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Answer:
4.5 is the answer :D
Step-by-step explanation:
What is the final step in solving the inequality –2(5 – 4x) < 6x – 4?
x < –3
x > –3
x < 3
x > 3
x<3
Step-by-step explanation:
–2(5 – 4x) < 6x – 4
(–10 + 8x) < 6x – 4
8x –6x < –4 + 10
2x < 6
x < 3
What divided by 4 equals 9/4
( 9/4= Divided by 4 )
Answer
16/9
Step-by-step explanation:
I don't know if this is right or not and I'm sry if its wrong
but 16/9 divided by 4 = 9/4
help what’s the answer? confused
Answer:
D. continuous
A dog gave birth to 9 puppies, of which 2 are brindle. What is the ratio of brindle puppies to non-brindled puppies?
Answer:
2:7
Step-by-step explanation:
If 2 of the puppies are brindle that leaves 7 that are not out of the nine making the ratio 2:7.
GOOD AFTERNOON BRAINLIESTS! Please help me with this question! TYSM!
- xXIndieKidXx
Answer:
Domain: All real numbers ; Range: y> -3
Step-by-step explanation:
What is the volume, measured in cubic centimeters, of the box below? Do not
include units in your answer.
5 cm
4 cm
3 cm
Answer:
v =L× b×h
=5× 4×3
=60 cubic centimeter
Kimo went into a bakery where they sell cookies for $0.75 each and brownies for $1.25 each. Kimo has $15 to spend and must buy no less than 12 cookies and brownies altogether.
a. Define the variables. (4 pts)
b. Write the system of inequalities that could be used to solve the situation. DO NOT SOLVE. (4 pts)
a) The variables are:
x = number of cookies bought.y = number of brownies bought.b)
x + y ≥ 12
x*$0.75 + y*$1.25 ≤ $15
How to write the system of inequalities?a) First we need to define the variables, in this case we have:
x = number of cookies bought.y = number of brownies bought.b) Now we want to write the system, we know that he must buy at least 12 items, then:
x + y ≥ 12
And he can spend, at most, $15, then:
x*$0.75 + y*$1.25 ≤ $15
These two inequalities conform the system of inequalities:
x + y ≥ 12
x*$0.75 + y*$1.25 ≤ $15
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