WILL GIVE BRAINLIEST!!! (100 points) cliff divers in hawaii dive from 65 meter high cliffs. the rocks at the base of the cliff protrude 27 meters beyond the edge of the cliff. which sketch is the correct representation of the problem?
answer asap please:)

Answer:

D

Explanation:

[tex]v = \frac{covered \: distance}{time \: of \: the \: covered \: distance} \\ [/tex]

[tex]v = \frac{2400}{55} \\ [/tex]

[tex]v = \frac{24 \times 100}{5 \times 11} = \frac{24 \times 20}{11} = \frac{480}{11} \\ [/tex]

[tex]v = 43.63 \: \: \frac{m}{s} [/tex]

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And we're done...

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Answer:

The average speed is about 44 m/s

Step by Step:

[tex]S= \frac{distance}{time}\\ d= 2400m\\t = 55 seconds\\\\\frac{2400m}{55 seconds}\\\\= approximately\\ 44 m/s[/tex]

I hope you found this helpful

Answer:  Atoms are electrically neutral because they have equal numbers of protons (positively charged) and electrons (negatively charged). If an atom gains or loses one or more electrons, it becomes an ion.

Explanation:

50 m/s may squared siya sa dun sa may s

Aerodynamics is a way to reduce drag that uses car manufacturers.

Aerodynamics is the motion of the air. airplane flies cause of aerodynamics.

Aerodynamics is the study of forces that are resulted by motion of the air.

To reduce the aerodynamic drag further, the manufacturers use character lines on the exteriors of the car's body right from its concept stage. These lines help the air to pass smoothly over the body and thus, reducing the air resistance.

cars have flat vertical face in front. When it moves through air, drag force directly proportional to the velocity applies on the car which opposes motion of the car. after studding aerodynamics when we make triangular like shape to the front body of the car, it cuts the air and front air goes from side of the car which reduces oppose to the motion, and car can have more speed.  

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Answer:

the acceleration would be 5kg

Explanation:because you would do 15 divided by 5

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question

mass = 14 g

density = 7 g/mL

So we have

[tex]volume = \frac{14}{7} \\ [/tex]

We have the final answer as

Hope this helps you

Explanation:

Answer:

im awesomeee

Explanation:

.

Answer:

Doubt I'll be first but imma try

Explanation:

Answer:

Two hundred fifty kilometer 250 km

Answer: the force applied to the object and the distance the object move Work can be calculated with this equation: Work equals Force x Distance.

Explanation:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

From the question we have

force = 75 × 3

We have the final answer as

Hope this helps you

Answer:

F=ma

Plug it in:

5=10a

5/10=(10a)/10

.5m/s²=a

Explanation:

Brainliest?

Answer:

[tex]\frac{1}{2} \frac{m}{s^2}[/tex]

Explanation:

Recall the equation F = ma. We want to find a, and we already know F and m, so we can plug those in. [tex]5N = 10kg \cdot a -> a = 5N/10kg = \frac{1}{2} \frac{m}{s^2}[/tex]

Answer:

B)Lead is a solid at 310 °C

Explanation:

The melting point of a substance refers to that temperature in which the substance changes state from solid to liquid. The melting point of a substance, which is usually a temperature value, is that actual temperature the change of state occurs.

According to this question, the melting point of Lead (Pb), which is naturally a solid metal, is 327.5°C. This means that LEAD (Pb) will only change to its liquid state at exactly 327.5°C and above. Therefore, at a temperature of 310°C, which is lower than lead's melting point, Lead element will still be a solid.

Answer: The correct answer is B. Lead is a solid at 310

Explanation:

Answer:

red,orange,yellow,green,blue,indigo,violet

Explanation:

Answer:

Longest to shortest wavelength or Highest to lowest frequency

Answer:

X0   is the initial position of the object

V0 t   is the displacement of the object in time t due to its initial velocity

1/2 a t^2   is the displacement of the object in time t due to its acceleration

Adding the 3 terms (being careful with signs) gives the final position of the object at time t

Answer:

True

Explanation:

A crowbar makes our work easier by multiply effort because it belongs to first class lever.

And first class lever makes work easier by multiplying the effort

Answer:

D. 1×10⁻⁸ M

Explanation:

[H⁺] [OH⁻] = 10⁻¹⁴

(1×10⁻⁶) [OH⁻] = 10⁻¹⁴

[OH⁻] = 1×10⁻⁸

The concentration of hydroxyl ion will be  [tex]10^{-8}[/tex]M.

The amount of a chemical substance in a mixture is expressed by the substance's concentration.

Calculation of concentration.

Given data:

Concentration of H+ =  1 x [tex]10^{-6}[/tex] M.

It is known that,

[[tex]H^{+}[/tex]][[tex]OH^{-}[/tex]] = [tex]10^{-14}[/tex]M

Now, put the value of concentration of [[tex]H^{+}[/tex]] in above equation.

[1× [tex]10^{-6}[/tex]][[tex]OH^{-}[/tex]] =  [tex]10^{-14}[/tex]M

[[tex]OH^{-}[/tex]]  =   [tex]10^{-14}[/tex] / [1× [tex]10^{-6}[/tex]]M

[[tex]OH^{-}[/tex]]  = [tex]10^{-8}[/tex]M

Therefore, the concentration of hydroxyl ion will be  [tex]10^{-8}[/tex]M.

Hence, the correct answer will be an option (D).

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Answer:

a

The height is   [tex]H  = 6.74 \  m [/tex]

b

The horizontal distance is  [tex]D  = 23.74 \  m [/tex]

Explanation:

From the question we are told that

  The speed is  [tex]v  =  15 \  m/s[/tex]

  The angle is  [tex]\theta  =  40^o[/tex]

   The height of the cannon from the ground is  h  =  2 m

  The distance of the net from the ground is k  =  1 m

Generally the maximum height she reaches is mathematically represented as  

     [tex]H  =  \frac{v^2 sin^2 \theta }{2 *  g }  +  h[/tex]

=>    [tex]H  =  \frac{(15)^2 [sin (40)]^2 }{2 * 9.8}  +  2[/tex]

=>    [tex]H  = 6.74 \  m [/tex]

Generally from kinematic equation  

    [tex]s = ut + \frac{1}{2} at^2[/tex]

Here s is the displacement which is mathematically represented as

         s  =  [-(h-k)]  

    =>  s =  -(2-1)

    =>  s  = -1 m

There reason why s =  -1 m is because upward motion canceled the downward motion remaining only the distance of the net from the ground which was covered during the first half but not covered during the second half

     a =  -g = -9.8

    [tex]u  =  v sin (\theta)[/tex]

So

    [tex]-1 = (vsin 40 )t + \frac{1}{2} * (-9.8) t^2[/tex]

=>  [tex]-4.9t^2 + 9.6418t + 1 = 0[/tex]

using  quadratic formula to solve the equation we have

    [tex]t  =  2.07 \  s[/tex]

Generally distance covered along the horizontal is  

   [tex]D  =  v cos (40) *  2.07[/tex]

=>   [tex]D  =  15 cos (40) *  2.07[/tex]

=>   [tex]D  = 23.74 \  m [/tex]

The line that goes up by 1 and right/left by 1. Hope this helps

Answer: Gravitational force.

Electric force.

Magnetic force.

Nuclear force.

Frictional force.

Explanation: I learned when I had science class.

Answer:

true

Explanation:

hope this helps

Answer: true

Explanation:   when two objects collide and completely bounce apart with no lasting deformation or generation of heat, the collision is said to be elastic.

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Answer:

The term ideal machine refers to a hypothetical mechanical system in which energy and power are not lost or dissipated through friction, deformation, wear, or other inefficiencies. Hope this helped :))

Explanation:

Answer:

3.5+35

1.5+1.2

20+22

42 + 16

= 58 ¹²

The cannonball travels horizontally before it reaches the ground at an angle of 30° above the horizontal with an initial velocity of 26 m/s is 59.73 meters.

When anything is moving, its velocity tells us how quickly that something's location is changing from a certain vantage point and as measured by a particular unit of time.

If a point travels a specific distance along its path in a predetermined amount of time, its average speed throughout that time is equal to the traveled distance divided by the travel time. For instance, a train traveling 100 km in two hours is moving at an average speed of 50 km/h.

Given:

The initial velocity of a cannonball, u = 26 m/s,

Calculate the range of the cannonball by following the formula,

R = [tex]u^2[/tex]sin2θ / g

Here R is the range, and θ is the angle of projection.

Substitute the values,

R = [tex]26^2[/tex] sin2*30 / 9.8

R  = 59.73 meters

Therefore, the cannonball travels horizontally before it reaches the ground at an angle of 30° above the horizontal with an initial velocity of 26 m/s is 59.73 meters.

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