Answer:
All the data and information that was updated or added since then will be lost so it is useless to restore a Domain Controller that was backedup twelve months ago.
Explanation:
A domain conttoller back-up must be prepared on regular basis else if DC breaks, restoration of most recent database will be impossible.
What happens in the process represented by the flowchart ?
A) The person drinks water if the answer to “Thirsty?” is no.
B) The person always drinks water.
C) The person drinks water if the answer to “Thirsty?” is yes.
D) The person never drinks water.
CORRECT ANSWER: C!!!
Answer:
the person drinks water if the answer to “thirsty?” is yes
Answer:
C
Explanation:
in most operating systems what is running application called?
Answer:
I believe it is just a task. Since there exists(on windows) the Task Manager application, where you can stop any running task, I think that they are called tasks
Explanation:
In most operating systems, a running application is typically referred to as a process. A process is an instance of a program that is being executed by the operating system. It represents the execution of a set of instructions and includes the program code, data, and resources required for its execution.
Each process has its own virtual address space, which contains the program's code, variables, and dynamically allocated memory. The operating system manages and schedules these processes, allocating system resources such as CPU time, memory, and input/output devices to ensure their proper execution.
The operating system provides various mechanisms to manage processes, such as process creation, termination, scheduling, and inter-process communication.
Learn more about operating systems here:
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#SPJ6
Identify the flaws / limitations in the following ConvertToNumber method:
public static bool ConvertToNumber(string str)
{
bool canConvert = false;
try
{
int n = Int16.Parse(str);
if (n != 0)
{
canConvert = true;
}
}
catch (Exception ex)
{
}
bool retval = false;
if (canConvert == true)
{
retval = true;
}
return retval;
}
Answer:
Flaws and limitations identified in this program includes;
1.There was a not necessary usage of variable retrieval. Would have made use of canConvert.
2. Looking at the program, one will notice numerous typos. One of which is the fact that in JAVA we make use of Boolean instead of bool.
3.We rather use Integer.parseInt in JAVA and not Int16, cant make use of Int16.
4. The exception cant be printed
5. JAVA makes use of checkConversion instead of convertNumber as used in the program.
6. It cant work for decimal numbers, 0 and big integers.
Explanation:
See Answer for the detailed explaination of the flaws and limitations identified in the program.
Exact Target was acquired by Salesforce, which in turn was converted to __________.
Answer:
Salesforce Marketing Cloud.
Explanation:
Exact Target was founded by Peter McCormick, Chris Baggott and Scott Dorsey on the 15th of December, 2000 in Indianapolis, Indiana, United States of America and was later acquired by Salesforce in the year 2013 for $2.5 billion. Salesforce in turn converted Exact Target to Salesforce Marketing Cloud in the year 2014.
The Salesforce Marketing Cloud is a company that provide services such as digital marketing automation and analytics software. Salesforce Marketing Cloud softwares are sold primarily on a multi-year subscription basis and based on number of users, features enabled, and level of customer service. It is a hosted, online subscription model that provides users with services such as, consulting, mobile, implementation, email, social and digital marketing.
Assume variables SimpleWriter out and int n are already declared in each case. Write a while loop that printsA. All squares less than n. For example, if n is 100, print 0 1 4 9 16 25 36 49 64 81.B. All positive numbers that are divisible by 10 and less than n. For example, if n is 100, print 10 20 30 40 50 60 70 80 90C. All powers of two less than n. For example, if n is 100, print 1 2 4 8 16 32 64.
Answer:
This program has been written using JAVA. The code is written beloe:
// import library
import java.util.Scanner;
public category Main operate
public static void main(String[] args)
{
// scanner category
Scanner scan=new Scanner(System.in);
System.out.println("Enter Number:");
int n=scan.nextInt();
//All squares but n
System.out.println("All squares but n are: ");
int temp=0,square=0,i=0;
while(square
range
square=i*i;
if(square>=n)break;
System.out.print(square+" ");
i++;
}
//All positive numbers that are divisible by 10 but less than n
System.out.println(" ");
System.out.println(" ");
System.out.println("All positive numbers are divisible by 10 and less than n are: ");
i=1;
while(i
{
if(i%10==0)
System.out.print(i+" ");
if(i>=n)break;
i++;
}
System.out.println(" ");
System.out.println(" ");
System.out.println("All powers of 2 that are less than n are: ");
//All powers of 2 less than n
i=0;
while(i
mathematics.pow(2, i);
if(num_power
System.out.print(num_power+" ");
i++;
}
}
}
Explanation:
With SimpleWriter out and int n already declared in each case this program makes use of a while loop condition to satisfy the following;
1. All squares less than n
2. positive numbers that are divisible by 10 and less than n.
3. All powers of two less than n.
Suppose an 80286 microprocessor is in protected mode. How it is switched back
to real address mode operations.
Answer:
hardware-initiated reset
Explanation:
Once in protected mode, the 80286 is designed to remain there until it is reset by hardware.
__
External hardware can be designed so that software can cause such a reset. In the 1984 PC/AT, such hardware combined with code in the BIOS allowed real mode re-entry and returned execution control to the program that caused the reset.
The style or appearance of text is called
Answer: Font
Explanation:
Why is it important to use correct syntax?
ANSWER: D) to ensure the programs run properly and return expected results
Answer: True
Explanation:
Answer:
D
Explanation:
If your options are
a) to demonstrate a sophisticated programming style
b) to demonstrate a flexible programming style
c)to ensure that programs will work on any computer platform
d) to ensure that programs run properly and return expected results
Then yes this is very much correct!
Computer security experts devote their time and energy to the protection of sensitive data and the prevention of an outside attack on the internal network. They specialize in building secure firewalls as well as complex intrusion detection systems designed to keep intruders out. They watch and monitor the incoming message traffic very closely. But no matter how well they protect the private network from outside access without proper authority, they do not help prevent an attack by a malicious or disgruntled employee from the inside. And they cannot prevent breaches due to a simple lack of understanding of security policy by internal employees.When do YOU think an organization needs information systems security policies? Why?
Answer:
Information security policy are used for the prevention of intruders hacking a network when an organization start getting IT related attacks.
Explanation:
Information security policy are used for the prevention of intruders hacking a network when an organization start getting IT related attacks.
An information security policy are set of rules/policies designed to guide employees for the protection of the security of company information and IT systems. The reasons for these policies are:
It defines what is required from organization’s employees for the security of the IT systemsInformation security policies provide a means to secure the organization against external and internal threats Information security policies are a mechanism to for ensuring an organization’s legal and ethical responsibilities Information security policies are created to hold each employee responsible with regard to information securityWrite a C++ program that opens and reads file question2.txt. File question1.txt has 3 students and 3 grades of each. You program should read values from file and assign values to 4 variables: (string) name, (double) grade1, (double) grade2, (double) grade3. Then, it should calculate the average grade of each student with the precision of 2 (use setprecision(n) function from header file) and find maximum and minimum grade in the class. Finally, you should have a report on both: • console screen • Output file named output2.txt in the following output format: Max Grade max Min Grade min Adam ave_grade John ave_grade Bill ave_grade
Answer:
see explaination
Explanation:
#include <fstream>
#include <iostream>
#include <string>
//to set precision
#include <iomanip>
#include <bits/stdc++.h>
//structure of student is created.
struct Student
{
std::string name;
double grade1;
double grade2;
double grade3;
double Average;
// Constructor initializes semester scores to 0.
Student()
{
grade1 = 0;
grade2 = 0;
grade3 = 0;
Average = 0;
}
//Read from the file and calculate the average, min and max grade with name.
void read(std::fstream& fil)
{
std::string temp;
fil >> name;
fil >> temp;
grade1 = std::stod(temp);
fil >> temp;
grade2 = std::stod(temp);
fil >> temp;
grade3 = std::stod(temp);
Average = ((grade1 + grade2 + grade3) /3.0);
}
//write to file- name and average with precision 2.
void write(std::fstream& fil)
{
fil << name << " " << std::setprecision(2) << std::fixed << Average << std::endl;
}
//Logic to calculate the minimum grade of the class.
double min()
{
double min = grade1;
if(min > grade2)
{
min = grade2;
}
if(min > grade3)
{
min = grade3;
}
return min;
}
//Logic to calculate the maximum grade of the class.
double max()
{
double max = grade1;
if(max < grade2)
{
max = grade2;
}
if(max < grade3)
{
max = grade3;
}
return max;
}
//Print the name and average with precision 2 in the console.
void print()
{
std::cout << name << " " ;
std::cout << std::setprecision(2) << std::fixed << Average << std::endl;
}
};
//As per this question,students are set to 3.
Student students[3];
//main method.
int main()
{
// Read from the file question2.txt
std::fstream fil;
fil.open("question2.txt", std::ios::in);
for(int i = 0; i < 3; i++)
students[i].read(fil);
fil.close();
// finding the max grade of the class.
int max = students[0].max();
int temp = students[1].max();
if(max <temp)
max = temp;
temp = students[2].max();
if(max < temp)
max = temp;
// finding the min grade of the class.
int min = students[0].min();
temp = students[1].min();
if(min > temp)
min = temp;
temp = students[2].min();
if(min > temp)
min = temp;
// print the output in console.
std::cout << "Max Grade " << max << std::endl;
std::cout << "Min Grade " << min << std::endl;
for(int i = 0; i < 3; i++)
students[i].print();
// write to output file output2.txt .
fil.open("output2.txt", std::ios::out);
fil << "Max Grade " << max << std::endl;
fil << "Min Grade " << min << std::endl;
for(int i = 0; i < 3; i++)
students[i].write(fil);
fil.close();
return 0;
}
Write a program that will ask for the user to input a filename of a text file that contains an unknown number of integers. And also an output filename to display results. You will read all of the integers from the input file, and store them in an array. (You may need to read all the values in the file once just to get the total count) Using this array you will find the max number, min number, average value, and standard deviation. These results will be reported to both the screen and placed into the output file that the user choose. Output to screen and file could look like this: Read from file: 12 values Maximum value
Answer: Provided in the explanation section
Explanation:
Code provided below in a well arranged format
inputNos.txt
70
95
62
88
90
85
75
79
50
80
82
88
81
93
75
78
62
55
89
94
73
82
___________________
StandardDev.java
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class StandardDev {
public static void main(String[] args) {
//Declaring variables
String filename;
int count = 0, i = 0;
Scanner sc1 = null;
int min, max;
double mean, stdDev;
int nos[] = null;
/*
* Creating an Scanner class object which is used to get the inputs
* entered by the user
*/
Scanner sc = new Scanner(System.in);
//Getting the input entered by the user
System.out.print("Enter the name of the filename :");
filename = sc.next();
try {
//Opening the file
sc1 = new Scanner(new File(filename));
//counting no of numbers in the file
while (sc1.hasNext()) {
sc1.nextInt();
count++;
}
sc1.close();
sc1 = new Scanner(new File(filename));
//Creating an Integer based on the Count
nos = new int[count];
//Populating the values into an array
while (sc1.hasNext()) {
nos[i] = sc1.nextInt();
i++;
}
sc1.close();
//calling the methods
min = findMinimum(nos);
max = findMaximum(nos);
mean = calMean(nos);
stdDev = calStandardDev(nos, mean);
//Displaying the output
System.out.println("Read from file :" + count + " values");
System.out.println("The Minimum Number is :" + min);
System.out.println("The Maximum Number is :" + max);
System.out.printf("The Mean is :%.2f\n", mean);
System.out.printf("The Standard Deviation is :%.2f\n", stdDev);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
}
//This method will calculate the standard deviation
private static double calStandardDev(int[] nos, double mean) {
//Declaring local variables
double standard_deviation = 0.0, variance = 0.0, sum_of_squares = 0.0;
/* This loop Calculating the sum of
* square of eeach element in the array
*/
for (int i = 0; i < nos.length; i++) {
/* Calculating the sum of square of
* each element in the array
*/
sum_of_squares += Math.pow((nos[i] - mean), 2);
}
//calculating the variance of an array
variance = ((double) sum_of_squares / (nos.length - 1));
//calculating the standard deviation of an array
standard_deviation = Math.sqrt(variance);
return standard_deviation;
}
//This method will calculate the mean
private static double calMean(int[] nos) {
double mean = 0.0, tot = 0.0;
// This for loop will find the minimum and maximum of an array
for (int i = 0; i < nos.length; i++) {
// Calculating the sum of all the elements in the array
tot += nos[i];
}
mean = tot / nos.length;
return mean;
}
//This method will find the Minimum element in the array
private static int findMinimum(int[] nos) {
int min = nos[0];
// This for loop will find the minimum and maximum of an array
for (int i = 0; i < nos.length; i++) {
// Finding minimum element
if (nos[i] < min)
min = nos[i];
}
return min;
}
//This method will find the Maximum element in the array
private static int findMaximum(int[] nos) {
int max = nos[0];
// This for loop will find the minimum and maximum of an array
for (int i = 0; i < nos.length; i++) {
// Finding minimum element
if (nos[i] > max)
max = nos[i];
}
return max;
}
}
_____________________
Output:
Enter the name of the filename :inputNos.txt
Read from file :22 values
The Minimum Number is :50
The Maximum Number is :95
The Mean is :78.45
The Standard Deviation is :12.45
cheers i hope this helped !!!
____ is scientifically seeking and discovering facts.
Answer:
I believe it is science, but before you do anything with this answer, research more on it, just in case I'm wrong! :)
Explanation:
Write a loop that continually asks the user what pets the user has, until the user enters "rock", in which case the loop ends. It should acknowledge the user in the following format. For the first pet, it should say "You have a dog with a total of 1 pet(s)" if they enter dog, and so on.
Sample Run:
User enters:
lemur parrot cat rock
Outputs:
You have a lemur with a total of 1 pet(s)
You have a parrot with a total of 2 pet(s)
You have a cat with a total of 3 pet(s)
Answer:
Check the explanation
Explanation:
The Python program that frequently asks the user what pets the user has,
until the user enters "rock", in which case the loop ends can be analysed in the written codes below.
'''
# count of pets
count = 0
# read the user input
pet = input()
# loop that continues till the user enters rock
# strip is used to remove the whitespace
while pet.strip() != 'rock':
# increment the count of pets
count += 1
# output the pet name and number of pets read till now
print('You have a %s with a total of %d pet(s)' %(pet.strip(),count))
pet = input() # input the next pet
#end of program
Following are the python program to use the loop to count the number of pets until the user enters the "rock":
Program:c = 0#defining a variable c that initilzes with 0
p = input()#defining a variable p that input value
while p != 'rock':#defining a loop that check p value not equal to rock
c += 1#using c variable for counts total number of pets
print('You have a %s with a total of %d pet(s)' %(p,c))#print total number of pet
p = input() #input value
Output:
Please find the attached file.
Program Explanation:
Defining a variable "c" that is initialized with 0, which is used to count input values.In the next line, a "p" variable is declared as the input value from the user end.A while loop is declared to check that the p-value is not equal to 'rock'.Inside this loop, the "c" variable is used for counting the total number of pets, and a print method is used to print the total number of pets.Another input method is used that works until the user inputs the value that is "rock".Find out more about the loop here:
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A customer seeks to buy a new computer for private use at home. The customer primarily needs the computer to use the Microsoft PowerPoint application for the purpose of practicing presentation skills. As a salesperson what size hard disc would you recommend and why?
Answer:
at this day and age, any. My questions would focus around other applications at this point. 250 gb or larger.
Explanation:
Office 365 only uses 4 GB "Microsoft's store page", the smallest hard drives commonly available are 250 GB and larger.
1.Start vim to create a new file named pizza. vim pizza 2.Type i (lowercase i for input to put vim in Input mode and enter the following text, pressing RETURN at the end of each line. Ignore typing mistakes you make for now. Press ESCAPE when you are done typing to put vim back in Command mode. Pizza is an oven-baked, flat, round bread typically topped with a tomato sauce, cheese and various toppings. Pizza was originally invented in Naples, Italy, and the dish has since become popular in many parts of the world. (from Wikipedia) I
Answer:
vi [ -| -s ] [-l] [-L] [-R] [ -r [ filename ] ] [-S] [-t tag] [-v] [-V]
[-x] [-w] [-n ] [-C] [+command | -c command ] filename
Explanation:
See attached image file
Suppose the daytime processing load consists of 65% CPU activity and 35% disk activity. Your customers are complaining that the system is slow. After doing some research, you learn that you can upgrade your disks for $8,000 to make them 3 times as fast as they are currently. You have also learned that you can upgrade your CPU to make it 1.5 times faster for $6,000. a) Which would you choose to yield the best performance improvement for the least
amount of money?
b) Which option would you choose if you don’t care about the money, but want a
faster system?
c) What is the break-even point for the upgrades? That is, what price would be
charged for the CPU(or the disk--change only one) so the results was the same cost per 1% increase in both.
Answer:
The answer to this question can be described as follows:
Explanation:
Given data:
Performance of the CPU:
The Fastest Factor Fraction of Work:
[tex]f_1=65 \% \\\\=\frac{65}{100} \\\\ =0.65[/tex]
Current Feature Speedup:
[tex]K_1=[/tex] 1.5
CPU upgrade=6000
Disk activity:
The quickest part is the proportion of the work performed:
Current Feature Speedup:
[tex]k_2=3[/tex]
Disk upgrade=8000
System speedup formula:
[tex]s=\frac{1}{(1-f)+(\frac{f}{k})}[/tex]
Finding the CPU activity and disk activity by above formula:
CPU activity:
[tex]S_{CPU}=\frac{1}{(1-f_1)+(\frac{f_1}{k_1})} \\\\=\frac{1}{(1-0.65)+(\frac{0.65}{1.5})} \\\\=1.276 \% ...\rightarrow (1) \\[/tex]
Disk activity:
[tex]S_{DISK} = (\frac{1}{(1-f_2)+\frac{f_2}{k_2}}) \\\\ S_{DISK} = (\frac{1}{(1-0.35)+\frac{0.35}{3}}) \\\\ = -0.5\% .... \rightarrow (2)[/tex]
CPU:
Formula for CPU upgrade:
[tex]= \frac{CPU \ upgrade}{S_{CPU}}\\\\= \frac{\$ 6,000}{1.276}\\\\= 4702.19....(3)[/tex]
DISK:
Formula for DISK upgrade:
[tex]=\frac{Disk upgrade} {S_{DISK}}\\\\= \frac{\$ 8000}{-0.5 \% }\\\\= - 16000....(4)[/tex]
equation (3) and (4),
Thus, for the least money the CPU alternative is the best performance upgrade.
b)
From (3) and (4) result,
The disc choice is therefore the best choice for a quicker system if you ever don't care about the cost.
c)
The break-event point for the upgrades:
=4702.19 x-0.5
= -2351.095
From (2) and (3))
Therefore, when you pay the sum for disc upgrades, all is equal $ -2351.095
AYUDAAAA!!!!! URGENTE!!!!!!1
¿para que sirve la "BIG DATA"?
Answer:
Big data is a field that treats ways to analyze, systematically extract information from, or otherwise deal with data sets that are too large or complex to be dealt with by traditional data-processing application software. ... Big data was originally associated with three key concepts: volume, variety, and velocity.
SPANISH TRANSLATION
Big data es un campo que trata formas de analizar, extraer sistemáticamente información de, o de otra manera tratar con conjuntos de datos que son demasiado grandes o complejos para ser manejados por el software tradicional de aplicación de procesamiento de datos. ... Big data se asoció originalmente con tres conceptos clave: volumen, variedad y velocidad.
You are building a predictive solution based on web server log data. The data is collected in a comma-separated values (CSV) format that always includes the following fields: date: string time: string client_ip: string server_ip: string url_stem: string url_query: string client_bytes: integer server_bytes: integer You want to load the data into a DataFrame for analysis. You must load the data in the correct format while minimizing the processing overhead on the Spark cluster. What should you do? Load the data as lines of text into an RDD, then split the text based on a comma-delimiter and load the RDD into a DataFrame. Define a schema for the data, then read the data from the CSV file into a DataFrame using the schema. Read the data from the CSV file into a DataFrame, infering the schema. Convert the data to tab-delimited format, then read the data from the text file into a DataFrame, infering the schema.
Answer:
see explaination
Explanation:
The data is collected in a comma-separated values (CSV) format that always includes the following fields:
? date: string
? time: string
? client_ip: string
? server_ip: string
? url_stem: string
? url_query: string
? client_bytes: integer
? server_bytes: integer
What should you do?
a. Load the data as lines of text into an RDD, then split the text based on a comma-delimiter and load the RDD into DataFrame.
# import the module csv
import csv
import pandas as pd
# open the csv file
with open(r"C:\Users\uname\Downloads\abc.csv") as csv_file:
# read the csv file
csv_reader = csv.reader(csv_file, delimiter=',')
# now we can use this csv files into the pandas
df = pd.DataFrame([csv_reader], index=None)
df.head()
b. Define a schema for the data, then read the data from the CSV file into a DataFrame using the schema.
from pyspark.sql.types import *
from pyspark.sql import SparkSession
newschema = StructType([
StructField("date", DateType(),true),
StructField("time", DateType(),true),
StructField("client_ip", StringType(),true),
StructField("server_ip", StringType(),true),
StructField("url_stem", StringType(),true),
StructField("url_query", StringType(),true),
StructField("client_bytes", IntegerType(),true),
StructField("server_bytes", IntegerType(),true])
c. Read the data from the CSV file into a DataFrame, infering the schema.
abc_DF = spark.read.load('C:\Users\uname\Downloads\new_abc.csv', format="csv", header="true", sep=' ', schema=newSchema)
d. Convert the data to tab-delimited format, then read the data from the text file into a DataFrame, infering the schema.
Import pandas as pd
Df2 = pd.read_csv(‘new_abc.csv’,delimiter="\t")
print('Contents of Dataframe : ')
print(Df2)
You have been allocated a class C network address of 211.1.1.0 and are using the default subnet mask of 255.255.255.0 how many hosts can you have?
Answer:thats is so easy obviously 69
Explanation:
It is only likely for a guest to receive outstanding service at luxury brands. That's why Ritz-Carlton, Mandarin Oriental, Four Seasons, and others are the best at what they do.
Answer:
FALSE
Explanation:
Consider the following relational schema, where the primary keys are Bold,
Students(sid, sname, address, dept_id)
Courses(cid, cname, dept_id)
Departments(dept_id, dname, college)
Grades(sid, cid, year, semester, grade)
Write the following queries in SQL. Only use the tables that are absolutely needed for the corresponding query.
1. Find the sids and snames of students who took "Database" course (i.e., cname = ‘Database’) in Fall 2019.
2. Find the average grade of all the students who took "CS327" (i.e., cid=‘CS327’) in Fall 2019. You can assume grade is a numerical attribute.
3. Find the number of distinct courses offered by each department in Fall 2019.
4. Find the sids of students who have taken at least 10 different courses offered by "Computer Science" department (i.e., dname = ‘Computer Science’).
Answer:
The queries for each question are explained.
1. Find the sids and snames of students who took "Database" course (i.e., cname = ‘Database’) in Fall 2019.
The columns sid and sname are taken from students table.
The course name belong to the courses table.
The semester and year belong to the grades table.
To get the final query, all these tables need to be joined in the FROM clause using JOIN ON keywords.
select s.sid, sname
from students s join grades g on g.sid = s.sid
join courses c on g.cid = c.cid
where cname like 'database%'
and semester like 'Fall'
and year=2019
2. Find the average grade of all the students who took "CS327" (i.e., cid=‘CS327’) in Fall 2019. You can assume grade is a numerical attribute.
The grade column is taken from grades table.
The course id belongs to the grades table.
The semester and year also belong to the grades table.
The final query is formed using the grades table only.
select avg(grade)
from grades
where cid like 'CS327'
and semester like 'Fall'
and year=2019
3. Find the number of distinct courses offered by each department in Fall 2019.
The department id belongs to the courses table.
The course id belongs to the grades table.
The semester and year also belong to the grades table.
To get the final query, the courses and the grades tables are joined in the FROM clause using JOIN ON keywords.
select dept_id, count(distinct g.cid)
from courses c join grades g on c.cid = g.cid
where semester like 'Fall'
and year=2019
group by dept_id
Using the College Registration example from Section 6.7.3 as a starting point, do the following:
-Recode the logic sing CMP and conditional jump instructions (instead of the .IF and .ELSEIF directives).
-Perform range checking on the credits value; it cannot be less than 1 or greater than 30. If an invalid entry is discovered, display an appropriate error message.
-Prompt the user for the grade average and credits values.
Display a message that shows the outcome of the evaluation, such as "The student can register" or "The student cannot register".
6.7.3 example:
.data
TRUE = 1
FALSE = 0
gradeAverage WORD 275 ; test value
credits WORD 12 ; test value
OkToRegister BYTE ?
.code
main PROC
mov OkToRegister,FALSE
.IF gradeAverage > 350
mov OkToRegister,TRUE
.ELSEIF (gradeAverage > 250) && (credits <= 16)
mov OkToRegister,TRUE
.ELSEIF (credits <= 12)
mov OkToRegister,TRUE
.ENDIF
Answer:
Check the explanation
Explanation:
INCLUDE Irvine32.inc
TRUE = 1
FALSE = 0
.data
gradeAverage WORD ?
credits WORD ?
oKToRegister BYTE ?
str1 BYTE "Error: Credits must be between 1 and 30" , 0dh,0ah,0
main PROC
call CheckRegs
exit
main ENDP
CheckRegs PROC
push edx
mov OkToRegister,FALSE
; Check credits for valid range 1-30
cmp credits,1 ; credits < 1?
jb E1
cmp credits,30 ; credits > 30?
ja E1
jmp L1 ; credits are ok
; Display error message: credits out of range
E1:
mov edx,OFFSET str1
call WriteString
jmp L4
L1:
cmp gradeAverage,350 ; if gradeAverage > 350
jna L2
mov OkToRegister,TRUE ; OkToRegister = TRUE
jmp L4
L2:
cmp gradeAverage,250 ; elseif gradeAverage > 250
jna L3
cmp credits,16 ; && credits <= 16
jnbe L3
mov OkToRegister,TRUE ; OKToRegister = TRUE
jmp L4
L3:
cmp credits,12 ; elseif credits <= 12
ja L4
mov OkToRegister,TRUE ; OKToRegister = TRUE
L4:
pop edx ; endif
ret
CheckRegs ENDP
END main
The four compass points can be abbreviated by single-letter strings as "N", "E", "S", and "W". Write a function turn_clockwise that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. Here are some tests that should pass:
test(turn_clockwise("N") == "E")
test(turn_clockwise("W") == "N")
You might ask "What if the argument to the function is some other value?" For all other
cases, the function should return the value None:
test(turn_clockwise(42) == None)
test(turn_clockwise("rubbish") == None)
Answer:
The program code is written in the explanation.
Explanation:
def turn_clockwise(d):
if d=="N":
return "E"
elif d=="E":
return "S"
elif d=="S":
return "W"
elif d=="W":
return "N"
else:
return "None"
Output:
Given the following Java code:
public static boolean f(int [] arr) {
for (int i = 0; i < arr.length - 1; i++) {
for (int j = i + 1; j < arr.length; j++) {
if (arr[i] < arr[j]) // *HERE*
return false;}
return true;}
(i) Find the number of times the comparison marked by *HERE* will be evaluated for each input:
{1, 2}
{10, 20, 30}
{30, 20, 10}
{-4, 7, 1}
(ii) For an array of size ????, what is the big-oh runtime of this code in the worst case?
Answer:
See explaination
Explanation:
{1, 2}
Runs only once for 1 < 2
{10, 20, 30}
Runs 1 for 10 < 20
Runs 1 for 10 < 30
Runs 1 for 20 < 30
Total 3 times
{30, 20, 10}
Runs 1 for 30 < 20
Runs 1 for 30 < 10
Runs 1 for 20 < 10
Total 3 times
{-4, 7, 1}
Runs 1 for -4 < 7
Runs 1 for -4 < 1
Runs 1 for -7 < 1
Total 3 times
Generalizing it will run for n*(n-1)/2 so for 2 element it will run for 2*1/2 = 1
For 3 element it will run for 3*2/2 = 3 times
(ii) (3 points) For an array of size , what is the big-oh runtime of this code in the worst case?
Time complexity in Worst case is O(n^2). Reason being it uses two for loop where first loop runs for n time and the second loop runs for n*n time in worst case hence its O(n^2)
A MySetOperations is a collection of functions, on which the following set operations are defined:
myIsEmpty(A): Returns T if the set A is empty (A = Φ), F otherwise.
myDisjoint(A,B): Returns T if intersection of the set A and set B is non-empty
(A â© B â Φ), F otherwise.
myIntersection(A,B): Returns the intersection of the set A and set B (A â© B).
myUnion(A,B): Returns the union of the set A and set B (A ⪠B).
Write a collection of MySetOperations in Python.
Note: For this problem, you can use only the standard flow Python's instructions and the set build-in operations: len, in, not in, and add.
Answer:
Explanation:
The objective here is to write a collection of MySetOperations in Python.
During the process of submitting this answer after computing the program ; I keep getting a response message that goes thus "It appears that your answer contains either a link or inappropriate words. Please correct and submit again!" . In the bid to curb such dilemma , i have created a word document for the collection of MySetOperations in Python.
The document can be seen in the attached file below.
Answer each of the following with a TRUE (T) or FALSE (F).
(1) Pipelining allows instructions to execute sequentially.
(2) If you can find the value x in the cache, you can also find it in the main memory too.
(3) Only the lw instruction can access the Data Memory component.
(4) The bias in single precision is 127, while in double precision it is 1024.
(5) In a cache mapping architecture, the valid bit is always on until data is found in that specific block.
(6) Memory speed generally gets faster the farther you move from the processor.
(7) A cache is a small high speed memory that stores a subset of the information that is in RAM.
(8) The hit rate of a cache mapping architecture is calculated by doing 1 - hit penalty.
(9) Cache is the fastest type of memory.
(10) Single-cycle and multi-cycle machines differ in CPI but all the other values are the same.
Answer:
t
Explanation:
Ronaldo wants to determine if employees would prefer having bagels or
donuts at morning meetings. Which method would be best to collect this
information?
Answer:
surveys and questionnaires
Answer:
Survey
Explanation:
Create a simple program that calls a function call gradeCalculated, in the main area the user is asked to enter their grade from 0-100. (Python)
Answer:
def gradeCalculated(score):
if score < 60:
letter = 'F'
elif score < 70:
letter = 'D'
elif score < 80:
letter = 'C'
elif score < 90:
letter = 'B'
else:
letter = 'A'
return letter
def main():
grade = int(input("enter your grade from 0-100: "))
print("Letter grade for ",grade,"is:",gradeCalculated(grade))
if(grade>80):
print("You are doing good! keep it up!!")
else:
print("You have to get work hard")
main()
Explanation:
See attached image for output
"Dean wants a quick way to look up staff members by their Staff ID. In cell Q3, nest the existing VLOOKUP function in an IFERROR function. If the VLOOKUP function returns an error result, the text ""Invalid Staff ID"" should be displayed by the formula. (Hint: You can test that this formula is working by changing the value in cell Q2 to 0, but remember to set the value of cell Q2 back to 1036 when the testing is complete.)"
Answer:
ierror(VLOOKUP(Q2,CBFStaff[[Staff ID]:[Name]],2,FALSE), "Invalid Staff ID")
Explanation:
Let me try as much as I can to explain the concept or idea of iferror in vlookup.
iferror have a typically function and result like an if else statement, its syntax is IFERROR(value,value _ if _ error), this simply means that if the the error is equal to value, value is returned if not, the next argument is returned.
Having said that, feom the question we are given,
let's substitute the value with vlookup function and add an else argument, it will look exactly this way;
IFERROR(VLOOKUP(),"Invalid Staff ID")// now this will set the message if vlookup cannot find the.
On the other hand using the values given, we will have;
ierror(VLOOKUP(Q2,CBFStaff[[Staff ID]:[Name]],2,FALSE), "Invalid Staff ID")
Double any element's value that is less than controlValue. Ex: If controlValue = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}.
import java.util.Scanner; public class StudentScores { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); final int NUM_POINTS = 4; int[] dataPoints = new int[NUM_POINTS]; int controlValue; int i; controlValue = scnr.nextInt(); for (i = 0; i < dataPoints.length; ++i) { dataPoints[i] = scnr.nextInt(); } for (i = 0; i < dataPoints.length; ++i) { System.out.print(dataPoints[i] + " "); } System.out.println(); } }
Answer:
import java.util.Scanner;
public class StudentScores
{
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_POINTS = 4;
int[] dataPoints = new int[NUM_POINTS];
int controlValue;
int i;
controlValue = scnr.nextInt();
for (i = 0; i < dataPoints.length; ++i) {
dataPoints[i] = scnr.nextInt();
}
for (i = 0; i < dataPoints.length; ++i) {
System.out.print(dataPoints[i] + " ");
}
System.out.println();
for (i = 0; i < dataPoints.length; ++i) {
if(dataPoints[i] < controlValue){
dataPoints[i] = dataPoints[i] * 2;
}
System.out.print(dataPoints[i] + " ");
}
}
}
Explanation:
*Added parts highligted.
After getting the control value and values for the array, you printed them.
Create a for loop that iterates through the dataPoints. Inside the loop, check if a value in dataPoints is smaller than the contorolValue. If it is, multiply that value with 2 and assign it to the dataPoints array. Print the elements of the dataPoints
Answer:
import java.util.Scanner;
public class numm3 {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
final int NUM_POINTS = 4;
int[] dataPoints = new int[NUM_POINTS];
int controlValue;
int i;
System.out.println("Enter the control Variable");
controlValue = scnr.nextInt();
System.out.println("enter elements for the array");
for (i = 0; i < dataPoints.length; ++i) {
dataPoints[i] = scnr.nextInt();
}
for (i = 0; i < dataPoints.length; ++i) {
System.out.print(dataPoints[i] + " ");
}
System.out.println();
//Doubling elements Less than Control Variable
for (i = 0; i < dataPoints.length; ++i) {
if (dataPoints[i]<controlValue){
dataPoints[i] = dataPoints[i]*2;
}
System.out.print(dataPoints[i] + " ");
}
System.out.println(); } }
Explanation:
See the additional code to accomplish the task in bold
The trick is using an if statement inside of a for loop that checks the condition (dataPoints[i]<controlValue) If true, it multiplies the element by 2