why the speed of sound in solid and liquid is not signoficantly affected by temperature

Answers

Answer 1

Explanation:

because the molecules are closer together and more tightly bonded in solids


Related Questions

Calculate the weight of an object that displaces 3 m2 of water and exerts a pressure of 500 Pa (500 N/m ).

Answers

The weight of the object from the information provided in the question is  1500 N.

We know that pressure = Force/area. We have the following information from the question;

Pressure =500 Nm-2

Area = 3 m2

Hence;

Force = Pressure × area

Force = 500 Nm-2 × 3 m2

Force = 1500 N

Hence, the weight of the object is 1500 N

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What does 1 N = ? please I need help?​

Answers

[tex]1~N = 1~ \text{kg~ms}{^{-2}[/tex]

1 N = 1 kg × m/s²

One Newton is equal to 1 kilogram multiplied by meter by second squared.

_____

Hope it helps ⚜

Which state of matter has molecules that move the most?

liquid

solid

gas

They are all the same.

Answers

Answer:

gas

Explanation:

in gaseous state molecules move the most because force of attraction between atoms are least in gaseous state

A 1300-kg car is traveling with a speed of 16.0 m/s. What is the magnitude of the horizontal net force that is required to bring the car to a halt in a distance of 38.9 m?

Answers

Answer:

F=ma,a=0.329m/second squared,m=1300kg,F=1300*0.329=4277N

Examples of energy conversion in daily life

Answers

Answer:

Energy conversion, also termed as energy transformation, is the process of changing one form of energy into another. Energy conversion occurs everywhere and every minute of the day. There are numerous forms of energy like thermal energy, electrical energy, nuclear energy, electromagnetic energy, mechanical energy, chemical energy, sound energy, etc. On the other hand, the term Energy Transformation is used when energy changes forms from one form to another. Whether the                                                                    energy is transferred or transformed, the total amount of energy doesn’t change and this is known as the Law of Conservation of Energy.

Explanation:

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a race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds , how far does it move during this time

find distance and acceleration
FAST PLEASE !!

Answers

Answer:

-1.2×10^2 m

I hope this helps you

I rode my bicycle to grandmother's house at 6 km/h in a flat road for 5 min before reach a hill. I went at 2 km/h up the hill for 3minutes. I met a friend and stopped to talk for 5 minutes. I went on at 2 km/h to my grandmother's house. Draw (plot) the v against t graph for this motion.​

Answers

The graph can be plotted based on the given information which are given

in pairs (velocity and time), and which the coordinate pairs are formed.

Please find attached the required v against t graph created with MS Excel

Reasons:

The given data are presented in a tabular form as follows;

[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 - 5 &6 \\5 - 8&2\\8 -13&0&\\13- &2&\end{array}[/tex]

The velocity time graph can be plotted using the above table values on

MS Excel using the above table elaborated as follows;

[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 &6 \\5&6\\5 &2\\8&2\\8&0\\13&0&\\13 &2&\end{array}[/tex]

The attached graph can then be created using the Insert Chart menu

after selecting the data above inputted in the spreadsheet button on MS

Excel.

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When astronomers carefully examine the planets found by Kepler and draw conclusions from the Kepler sample, what do they conclude about planets the size (radius) of Earth

Answers

Given what we know about the Kepler space program, we know that the astronomers discovered that Earth-sized planets are more common than we imagined.

Kepler was launched with the intention of getting a closer look at other planets outside of our solar system using enhanced photometrics.

The idea behind this launch was to discover more Earth-sized planets, preferably within the habitable zone of their central star.

What this mission showed astronomers, is that Earth-sized planets are more common than we could have imagined, Kepler proved this by finding over 2,662 planets to date.

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how is pure salt obtained from the sea water ?describe in brief ​

Answers

Answer:

Evaporation

Explanation:

Evaporation

Answer:

Salt from sea water is obtained by the process of evaporation. ... The sea water evaporates due to the sun's heat and solid salt is left behind. The left salt is collected and refined to get purified salt. Hence, salt is obtained from sea water by evaporation.

If you blow up a balloon, tie it off, and release it, it will fall to the ground.
Why does it fall instead of float?
NO LINKS YA FILTHY VERMINS

Answers

Answer:

carbon dioxide (what you are blowing up the balloon with) is a heavy gas. so when you fill the Balloon with it, the balloon will not float. helium is a light gas and floats. gravity takes another. part in this

If larger-diameter tires are mounted on the car instead, how will that affect the speedometer reading? The speedometer

Answers

Answer:

A speedometer is related to the number of complete revolutions.

A larger diameter tire will travel farther in one revolution.

N D = S    where N is the number of revolutions and S the distance traveled

N = S / D     so the speedometer will record less revolutions and less distance traveled if the diameter is increased and the distance traveled will be too small as compared to the actual distance traveled.

What happens in a nucleus during beta decay

The numbers of protons increases

The number of neutrons increases

The number of protons decrease

The number of protons plus the number of neutrons decreases

Answers

The number of protons plus the number of neutrons decreases

Beta decay occurs when, in a nucleus with too many protons or too many neutrons, one of the protons or neutrons is transformed into the other. In beta minus decay, a neutron decays into a proton, an electron, and an antineutrino: n Æ p + e - +.

Without friction, what is the mass of an ball accelerating at 1.8 m/sec2 to which an
an unbalanced force of 42 Newtons has been applied?
A 75.60 kg
B 00.04 kg
C 23.33 kg
D 43.80 kg

Answers

Answer:

23.33 kg

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{42}{1.8} = 23.3333... \\ [/tex]

We have the final answer as

23.33 kg

Hope this helps you

Answer:

[tex]\boxed {\boxed {\sf C. \ 23.33 \ kg}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F=ma[/tex]

The mass of the ball is unknown. The ball is accelerating at 1.8 meters per second squared. An unbalanced force of 42 Newtons is applied to the ball.

Convert the units of force. 1 Newton is equal to 1 kilogram meter per second squared, so our answer of 42 Newtons is equal to 42 kg*m/s².

F= 42 kg*m/s² a= 1.8 m/s²

Substitute the values into the formula.

[tex]42 \ kg*m/s^1 = m * 1.8 \ m/s^2[/tex]

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 1.8 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 1.8 m/s².

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} = \frac{a*1.8 \ m/s^2}{1.8 \ m/s^2}[/tex]

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} =m[/tex]

The units of meters per second squared cancel.

[tex]\frac {42 \ kg}{1.8 } =m[/tex]

[tex]23.3333333 \ kg=m[/tex]

Round to the hundredth place. The 3 in the thousandth place tells us to leave the 3 in the hundredth place.

[tex]23.33 \ kg \approx m[/tex]

The mass of the ball is approximately 23.33 kilograms.

which statement about moist air moving over a mountain is correct?

Answers

Answer:

Explanation:

The orographic effect occurs when air masses are forced to flow over high topography. As air rises over mountains, it cools and water vapor condenses. As a result, it is common for rain to be concentrated on the windward side of mountains, and for rainfall to increase with elevation in the direction of storm tracks.

The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at 3. The mercury in a barometer of a cross-sectional area 1 cm² stands at 75 cm, and the space above it is 9 cm in length. What
volume of air, measured at atmospheric pressure, would have to be admitted into the space to cause the column of the mercury
to drop to 59 cm?

Answers

The ideal gas equation and the pressure in barometer allows us to find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:

The  variation  of the volume is: ΔV = 7.67 cm³

Pressure is defined by the relationship between force and area.

       P = F / A

The ideal gas equation establishes a relationship between pressure, volume, and temperature of an ideal gas.

          PV = nR T

Where P is pressure, V is volume, and T is temperature.

Let's write this equation for two points assuming that the temperature has not changed.

          P₀ V₀ = P₁ V₁

          V₁ = [tex]\frac{P_o}{P_1} \ V_o[/tex]                 (1)

The subscript "o" is used for the start point and the subscript "1" for the end point.

The pressure in a barometer is:

         P = ρ g y

They indicate the initial height of the barometer y₀=75 cm, the distance from empty space y'₀ = 9 cm and the final height of the barometer y₁ = 59 cm.

 

The volume of the cylinder is

         V = π r² y

Let's calculate the initial volume.

         V₀ = π 1 9

         V₀ = 28.27 cm³

We substitute in equation 1.

         V₁ = [tex]\frac{\rho \ g \ y_o}{\rho \ g \ y_1} \ V_o[/tex]  

         V₁ = [tex]\frac{y_o}{y_1} \ V_o[/tex]  

Let's calculate.

        V₁ = [tex]\frac{75}{59} \ 27.27[/tex]  

        V₁ = 35.94 cm³

The volume to be incremented is

         ΔV = V₁ - V₀

         ΔV = 35.94 - 28.27

         ΔV = 7.67 cm³

Using the ideal gas equation and the pressure in barometer we can find the amount of air that we must introduce into the barometer for the change in height of the mercury column is:

The change of the volume is: ΔV = 7.67 cm³

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What happens when you want to move the boat forward? You pull the oars toward yourself.Explain why you do this.

Answers

Answer:

You pull on the oars. By the third law, the oars push back on your hands, but that’s irrelevant to the motion of the boat. The other end of each oar (the blade) pushes against the water. By the third law, the water pushes back on the oars, pushing the boat forward.

Sheeeeeeeeeeeeeeeeeeeeeeeeeeeeesh

A block of mass m is initially at rest on a rough horizontal surface when a constant force F is exerted on it, as shown. The block accelerates to the right and is moving with speed v once it has moved a distance d. Which of the following equations can be used to solve for the force of friction exerted on the block by the surface?

Answers

The equations that can be used to solve for the force of friction exerted on the block by the surface is F- f = mv² / d

The constant force F is exerted on the block of mass and it accelerates with a speed, v and covering a distance of d in the direction of the force. The force of friction is an opposing force to the applied force.

Therefore,

using Newtons third law

F - f = ma

a = v/t

t = d/v

F - f = m × v / t

F- f = m × [tex]\frac{v}{\frac{d}{v} }[/tex]

F- f = m × v²/d

Therefore,

F- f = mv² / d

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If you eat cheese are you 1 percent cheese?

Answers

Answer:

No. Exactly what you eat doesn’t make up your internal structure.

:)

Answer:

Explanation:

Light cheeses are less than 20 %, low fat cheeses are 20 to 30%, fat cheeses are 50 to 60%, double-cream cheeses are at least 60% and triple-cream cheeses are at least 75 %.

discrete packets of kinetic energy in light are called

Answers

Answer:

Photons

Explanation:

I just know

Discrete packets of kinetic energy in light are called photons. Photons are fundamental particles of light and electromagnetic radiation. The correct answer is photons.

Photons are fundamental particles of light and electromagnetic radiation. They carry energy in discrete quantities, known as quanta or packets, and exhibit both wave-like and particle-like properties.

The energy of a photon is directly proportional to its frequency, and inversely proportional to its wavelength. When light interacts with matter, it can transfer its energy to the particles it interacts with, leading to various phenomena such as absorption, reflection, and emission.

Therefore, Discrete packets of kinetic energy in light are called photons.

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If acceleration of a body starting from the rest is 0.5m/s^2 how long will it take the body to travel 400m(if u are genius answer this)​

Answers

Answer:

10s

Explanation:

The strength of the electric field 0. 5 m from a 6 µC charge is _______ N/C. (Use k = 8. 99 × 109 N•meters squared per Coulomb squared and round answer to the nearest whole number. ) 215760 539400 697976 512356.

Answers

The strength of the electric field at a distance of 0.5 m from a 6 μC punctual charge is 143,840 N/C.

We want to calculate the strength of the electric field 0.5 m (r) from a 6 μC charge (Q).

What is the electric field?

The electric field (E) is a region around a charged particle or object within which a force would be exerted on other charged particles or objects.

We can calculate the electric field at some distance from a punctual charge using the following formula.

E = (k × Q) / r²

E = [(8.99 × 10⁹ N.m².C²) × (4 ×  10⁻⁶ C)] / (0.5 m)² ≈ 143,840 N/C

where,

k is the Coulomb's law constant.

The strength of the electric field at a distance of 0.5 m from a 6 μC punctual charge is 143,840 N/C.

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Best definition of an electromagnetic wave?

A) an electromagnetic wave is a longitudinal wave with electricity

B) an electromagnetic wave is a mechanical wave

C) an electromagnetic wave is a transversal wave that has electrical and magnetic properties

Answers

Answer:

Longitudinal and mechanical waves require a medium to support their transmission:

C) is the correct answer

The Kentucky Derby is one of the most exciting horse races run every year. In 1973, the horse Secretariat set a record that still stands. This 500-kg horse ran the 2000-m track in 120 s. What was Secretariat’s average kinetic energy? (1 kJ = 1000 J)

Need answers with explanaitions please

A. 4.2 kJ
B. 8.3 kJ
C. 69.0 kJ
D. 139.0 kJ

Answers

Answer:

C.69 kJ

Explanation:

kinetic energy

[tex] = 1 \div 2mv {}^{2} [/tex]

C 69.0 kj is correct

Select the correct answer.
What represents the value of the second-best alternative that a person gives up when making a choice?
OA. marginal spending
ОВ.
marginal benefit
OC. opportunity cost
OD. marginal cost

Answers

The answer should be opportunity cost

If a net force of 24 Newtons is applied on an object of mass 6
kilograms, what will be the acceleration of the object?
a 2 m/s2
b. 6 m/s2
C 10 m/s2
d 4 m/s2

Answers

Answer:

4 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass

From the question

f = 24 N

m = 6 kg

We have

[tex]a = \frac{24}{6} = 4 \\ [/tex]

We have the final answer as

4 m/s²

Hope this helps you

Analyze the effects on a passenger riding in a car traveling at
50 km/h that collides head-on with a solid object.

Answers

Without:

The passenger will get seriously injuredColliding with the windshield at 50km/hCould result in death

With safety:

The seatbelt holds tge passengers body back so they dont collide with anythingTheir head is cushioned by the airbagThe passenger might get minor injuries but nothing serious will happen

What force causes an automobile to move.

Answers

Answer:

Thrust

Explanation:

Thrust is the force that causes a car to move in the direction that it wants to.

What is the kinetic energy of a 2,000-kg boat moving at 5.0 m/s?

Answers

Answer:

25kJ

Explanation:

K = 1/2 mv^2 = 1/2 x 2000kg x (5.0m/s)^2

= 25 x 10^3 J = 25kJ

A 46.5-kg ball has a momentum of 57.2 kg m/s. What is the ball's speed?

Answers

Answer:

1.23 m/s

Explanation:

p=mv

57.2 = 46.5v

v= 57.2/46.5

v= 1.23

If you want to verify your answer, just insert the value of v in the equation.

5. An acrobat, starting from rest, swings freely on a trapeze of
length 3.7 m (Figure 6). If the initial angle of the trapeze is
48°, use the law of conservation of energy to determine
(a) the acrobat's speed at the bottom of the swing
(b) the maximum height, relative to the initial position, to
which the acrobat can rise

Answers

The energy conservation and trigonometry we can find the results for the questions about the movement of the acrobat are;

     a) The maximum speed is v = 4.89 m / s

     b) The maximum height is h = 1.22 m

The energy conservation is one of the most fundamental principles of physics, stable that if there are no friction forces the mechanistic energy remains constant. Mechanical energy is the sum of the kinetic energy plus the potential energies.

               Em = K + U

Let's write the energy in two points.

Starting point. Highest part of the oscillation

            Em₀ = U = m g h

Final point. Lower part of the movement

            [tex]Em_f[/tex] = K = ½ m v²

Energy is conserved.

            Emo = [tex]Em_f[/tex]  

            m g h = ½ m v²

            v² = 2 gh

Let's use trigonometry to find the height, see attached.

         h = L - L cos θ

         h = L (1- cos θ)

They indicate that the initial angle is tea = 48º and the length is L = 3.7 m, let's calculate.

         h = 3.7 (1- cos 48)

          h = 1.22 m

this  is the maximum height of the movement.

Let's calculate the velocity.  

          [tex]v= \sqrt{2 \ 9.8 \ 1.22}[/tex]  

          v = 4.89 m / s

In conclusion using the conservation of energy and trigonometry we can find the results for the questions about the movement of the acrobat are;

     a) The maximum speed is v = 4.89 m / s

     b) The maximum height is h = 1.22 m

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Problem: How can we use the relationships between land surfaces and water to understand conservation of resources and pollution?Hypothesis: After completing steps 1 through 5 in your procedures, predict the number and locations of watersheds that will form in your watershed model. For example:Based on the positions of landscape features in my watershed model, I predict there will be ________ number of watersheds located at these locations in my model: __________________________________.Materials: If you would like to create your watershed model by hand, you will need the materials listed. Note: There are alternative procedures that do not require these materials.one sheet of plain white paperseveral sheets of old newspaper, or wax paper if availableone water-based marker (Note: do not use permanent marker)one spray bottle containing water (place on mist setting)digital camera, if availableProcedures:Place several sheets of newspaper or wax paper over a large flat surface, such as a kitchen counter. Use at least five sheets of paper so that you can protect your work area. Crumple the sheet of white paper into a loose wad.Uncrumple the sheet of paper so you can lay it on your work surface. The paper should not be flat but should be wrinkled and puffed up from the crumpling.Imagine the paper as a miniaturized version of mountains, hills, valleys, and other landscape features. If your paper is so flat that you can't imagine these features, you should recrumple it.Use the marker to color the major folds or ridges in the paper, as well as some of the minor folds or ridges. Do not allow the marker to color any other part of the paper.Place the paper on top of the newspaper on the counter, and then lightly mist the piece of paper with the spray bottle. Don't spray too heavily: Three to seven squirts will probably do the job.Stop misting as soon as you see some of the colored water starting to collect in some of the valleys. Watch for a few moments as stream patterns develop over the paper.If you have access to a digital camera, take a photograph of your work and include it in your Data and Observations.Record your observations of each watershed that forms in Table 1. Take note of headwaters, channels, divides, tributaries, mouths, floodplains, precipitation, and infiltration in your descriptions. Complete the Questions and Conclusion section of the lab report. 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