Why is it cooler to wear a white shirt than a black shirt on a hot, sunny day?

Answer: 112.5

Explanation:

divide the multiply

Explanation:

Distance = speed × time

d = (11.6 km/h) (16 min × 1 hr / 60 min)

d = 3.09 km

Answer: distance = 3.09 km

Explanation: Distance = speed × time

distance = (11.6 km/h) (16 min × 1 hr / 60 min)

distance = 3.09 km

HOPE THIS HELPS YOU..

Answer:

The frequency of the coil is 7.07 Hz

Explanation:

Given;

number of turn of the coil, N = 200 turn

area of the coil, A = 300 cm² = 0.03 m²

magnitude of magnetic field, B = 30 mT = 0.03 T

maximum value of induced emf, E = 8 V

The maximum induced emf in the coil is given by;

E = NBAω

E = NBA(2πf)

[tex]f = \frac{E_{max}}{2\pi*NBA}[/tex]

where;

f is the frequency of the coil

[tex]f = \frac{E_{max}}{2\pi*NBA}\\\\f = \frac{8}{2\pi(200)(0.03)(0.03)} \\\\f = 7.07 \ Hz[/tex]

Therefore, the frequency of the coil is 7.07 Hz

Answer:

<In the attachment>

Explanation:

There's not really much for me to say here I feel. On 7)b) you appear to let y=0 for some reason, so I redid that one without doing that just in case. Just look at what I did and take notes for the future.

Answer:

Accuracy

Explanation:

I think accuracy is more important. When it comes to vital organs in the body, the exactness of getting the measurement is paramount. Accuracy deals with getting very close, almost exact you may say, to a known standard. Precision on the other hand, deals with how easy a measurement can be retaken, reproduced or remade, irrespective of how far or close they are from the accepted norm.

From this, we can agree that precision neglects the most important factor, closeness or say, exactness. Precision isn't bothered by it. And while that can be excused in a few instances, it certainly can not be permitted when it comes to life, or organs of the body

Answer:

a) 85.1 V

b)120.4 V

c) 10.24 A

d) 602.8 W

Explanation:

The reading of the ammeter is the root mean square value of current.

a) Vrms= Irms R

Irms= 7.24 A

R= 11.5 Ω

Vrms= 7.4A × 11.5Ω

Vrms= 85.1 V

b)

Peak value of voltage (Vo)= Vrms/0.707

Vo=85.1/0.707

Vo=120.4 V

c)

Peak current= Irms/0.707

Io= 7.24/0.707

Io= 10.24 A

d) average power= Irms^2 × R

Power= (7.24)^2 ×11.5

Power= 602.8 W

Answer:

a)13.33s

b)at highest point, the centripetal acceleration has its direction at downward path towards the center of the circular path, and the radius vector has its direction upward. Then acceleration=3.555m/s^2

c)c)at lowest point the centripetal acceleration has its direction upward towards the center of the circular path, and the radius vector has its direction downward Then acceleration=3.555m/s^2

Explanation

a)number of turns= 4.5

radius= 16m

We know that the period is the time taken by the wheel to complete one turn which can be calculated using below expresion

T= t/n

Where T= period of motion

t= Time taken by the wheel to finish n turns where our n= 4.5

T= (1×60)/4.5= 13.33s

Hence the period is 13.33s

Then the speed of the woman v= 2πr/T

v= (2×π×16)/13.33

v=7.5417m/s

b)at highest point, the centripetal acceleration has its direction at downward path towards the center of the circular path, and the radius vector has its direction upward.

a= v^2/r

Where r= radius

v= speed of the woman= 7.5417m/s

a=(7.5417m/s)^2/16

a=3.555m/s^2

The centripetal acceleration and radius vector are in opposite direction

c)at lowest point the centripetal acceleration has its direction upward towards the center of the circular path, and the radius vector has its direction downward

The magnitude of the acceleration is calculated below

a= v^2/r

Where r= radius

v= speed of the woman= 7.5417m/s

a=(7.5417m/s)^2/16

a=3.555m/s^2

Answer:

It does attract

Explanation:

But due to the lack of gravitational pull of the earth he/she feels weightless I hope this helps you

Answer:

  Ф_cube /Ф_sphere = 3 /π

Explanation:

The electrical flow is

      Ф = E A

where E is the electric field and A is the surface area

Let's shut down the electric field with Gauss's law

       Фi = ∫ E .dA = [tex]q_{int}[/tex] / ε₀

the Gaussian surface is a sphere so its area is

        A = 4 π r²

the charge inside is

        q_{int} = Q

we substitute

       E 4π r² = Q /ε₀

       E = 1 / 4πε₀   Q / r²

To calculate the flow on the two surfaces

* Sphere

       Ф = E A

        Ф = 1 / 4πε₀  Q / r² (4π r²)

        Ф_sphere = Q /ε₀

* Cube

Let's find the side value of the cube inscribed inside the sphere.

In this case the radius of the sphere is half the diagonal of the cube

          r = d / 2

We look for the diagonal with the Pythagorean theorem

         d² = L² + L² = 2 L²

         d = √2 L

we substitute

          r = √2 / 2 L

          r = L / √2

          L = √2  r

now we can calculate the area of ​​the cube that has 6 faces

          A = 6 L²

          A = 6 (√2  r)²

          A = 12 r²

the flow is

          Ф = E A

          Ф = 1 / 4πε₀  Q/r²  (12r²)

          Ф_cubo = 3 /πε₀  Q

the relationship of these two flows is

         Ф_cube /Ф_sphere = 3 /π

Wave Interference or Interference of wave

Answer:

120 k/m

Explanation:

Answer: 120

Explanation:

Answer:

The  value is  [tex]n = 2.347 *10^{17} \ photons[/tex]

Explanation:

From the question we are told that

     The  amount of power delivered is  [tex]P = 4.20 \ M W = 4.20 *10^{6} \ W[/tex]

      The  time taken is  [tex]t = 16.0ns = 16.0 *10^{-9} \ s[/tex]

       The  wavelength is  [tex]\lambda = 694.3 \ nm = 694.3 *10^{-9} \ m[/tex]

Generally the energy delivered is  mathematically represented as

     [tex]E = P * t = \frac{n * h * c }{\lambda }[/tex]

Where  [tex]h[/tex] is the Planck's constant with value  [tex]h = 6.262 *10^{-34} \ J \cdot s[/tex]

           c  is the speed of light with value  [tex]c = 3.0*10^{8} \ m/s[/tex]

So  

    [tex]4.20 *10^{6} * 16*10^{-9}= \frac{n * 6.626 *10^{-34} * 3.0*10^{8} }{694.3 *10^{-9}}[/tex]

=>    [tex]n = 2.347 *10^{17} \ photons[/tex]

Answer:

The percent uncertainty in the volume   [tex]\frac{\delta V}{V} * 100 = 14.286\%[/tex]

Explanation:

From the question we are told that

   The radius is  [tex]r = 0.84 \pm 0.04 \ m[/tex]

From the given value

   The  uncertainty of  radius  is  [tex]\delta r = 0.04[/tex]

   Generally the volume of a spherical beach ball is mathematically represented as

         [tex]V = \frac{4\pi }{3}* r^3[/tex]

Now taking the log of both sides

         [tex]log V = log [\frac{4\pi}{3} ] * r^3[/tex]

=>    [tex]log V = log [\frac{4\pi}{3} ] + log( r^3)[/tex]

=>    [tex]log V = log [\frac{4\pi}{3} ] + 3log( r)[/tex]

Differentiating both sides

        [tex]\frac{1}{V} \delta V = 0 + 3 [\frac{1}{r} ] \ \delta r[/tex]

Now converting them to percentage by multiplying by 100

         [tex]\frac{\delta V}{V} * 100 = [\frac{ 3 \delta r }{r} ] \ * 100[/tex]

=>      [tex]\frac{\delta V}{V} * 100 = [\frac{ 3 * 0.04 }{ 0.84} ] \ * 100[/tex]

=>      [tex]\frac{\delta V}{V} * 100 = 14.286\%[/tex]

Answer:

5*10^8Nm

Explanation:

work done= displacement* force

Since the wind blows in the direction that the boats want to travel, all values would be positive.

10*10^3*(5*10^4)=5.00*10^8Nm

Answer:

5 x 10⁸ J

Explanation:

Recall that

Work Done = Force x Distance Traveled in the direction of the force

We are given :

Force = 5.00 x 10⁴ = 50,000 N

Distance Travelled in the direction of the force = 10.00 km = 10,000 m

Hence,

Work Done = 50,000 N x 10,000 m

= 500,000,000 J

= 5 x 10⁸ J

Answer:

Explanation:

If magnetic field exists parallel  to the direction of motion of electron , no force will act on the electrons and hence there will be no deflection in them .

In such cases , the magnitude of magnetic field is immaterial . No matter how high or low magnitude of magnetic field be , if it is parallel to the velocity of electron , it will not be deflected as the force created on them will be zero.

Only in case magnetic field  makes some angle with the direction of velocity , force will be created and electron will be deflected .

THIS IS THE COMPLETE QUESTION BELOW

With what minimum speed must you toss a 130 g ball straight up to just touch the 14-m-high roof of the gymnasium if you release the ball 1.1 m above the ground

And what speed does the ball hit the ground? Solve this problem using energy.

Answer

a)minimum speed must you toss a 130 g is 15.9090m/s

b)speed the ball hit the ground is 16.57m/s

Explanation:

a)We know that For any closed/isolated system, the total energy is CONSERVED.

K.E. lost by the ball=The change in P.E of the ball at 1.1m above the ground as well as the P.E. of the ball at 14 m-high roof

This statement can be expressed as the expression below from K.E and P.E energy formula

P.E. = mgh

K.E. = (1/2)mv^2

Therefore,

(mgh1 - mgh2)=(1/2)mv^2

Where h2=the ball height above the ground=1.1m

h1=ball height at roof of the gymnasium= 14m

Then if we substitute we have

[(10) x (0.14) x (9.81)] - [(1.1) x (0.14) x (9.81)] = (1/2)(0.14)(v^2)

16.45137=0.065V^2

V=15.9090m/s

minimum speed must you toss a 130 g is 15.9090m/s

b)To calculate the speed the ball hit the ground?

This is the highest point (14m-high roof),and the type of the energy the ball possesses is Po.tential energy only.

At the lowest point (ground), the energy the ball possesses is K.E. only.

P.E at 10m-high roof = K.E. at ground.

(14) x (0.13) x (9.81) = (1/2) x (0.13) x v^2

17.8542= 0.065V^2

V= 16.57

Therefore,And speed the ball hit the ground is 16.57m/s

Answer:

Explanation:

kinetic energy required = 1.80 MeV

= 1.8 x 10⁶ x 1.6 x 10⁻¹⁹ J

= 2.88 x 10⁻¹³ J

If v be the velocity of proton

1/2 x mass of proton x v² = 2.88 x 10⁻¹³

= .5 x 1.67 x 10⁻²⁷ x v² = 2.88 x 10⁻¹³

v² = 3.45 x 10¹⁴

v = 1.86 x 10⁷ m /s

If V be the potential difference required

V x e = kinetic energy . where e is charge on proton .

V x 1.6 x 10⁻¹⁹ = 2.88 x 10⁻¹³

V = 1.8 x 10⁶ volt .

Answer:

A) 7.37 x 10^-4 N

B) The resultant force will be towards the -x axis

Explanation:

The three masses have mass = 3500 kg

For the force of attraction between the mass at the origin and the mass -100 cm away:

distance r = 100 cm = 1 m

gravitational constant G= 6.67×10^−11 N⋅m^2/kg^2

Gravitational force of attraction [tex]F_{g}[/tex] = [tex]\frac{Gm^{2} }{r^{2} }[/tex]

where G is the gravitational constant

m is the mass of each of the masses

r is the distance apart = 1 m

substituting, we have

[tex]F_{g}[/tex] = [tex]\frac{6.67*10^{-11}*3500^{2} }{1^{2} }[/tex] = 8.17 x 10^-4 N

For the force of attraction between the mass at the origin and the mass 320 cm away

distance r = 320 cm = 3.2 m

[tex]F_{g}[/tex] = [tex]\frac{Gm^{2} }{r^{2} }[/tex]

substituting, we have

[tex]F_{g}[/tex] = [tex]\frac{6.67*10^{-11}*3500^{2} }{3.2^{2} }[/tex] = 7.98 x 10^-5 N

Resultant force = (8.17 x 10^-4 N) - (7.98 x 10^-5 N) = 7.37 x 10^-4 N

B) The resultant force will be towards the -x axis

Explanation:

Distance is the length of the path.  Displacement is the difference between the final position and the initial position.

Speed = distance / time

= (50 m + 50 m + 50 m + 50 m) / (12.3 s + 12.5 s + 12.7 s + 12.6 s)

= (200 m) / (50.1 s)

= 3.99 m/s

Velocity = displacement / time

= (50 m − 50 m + 50 m − 50 m) / (12.3 s + 12.5 s + 12.7 s + 12.6 s)

= (0 m) / (50.1 s)

= 0 m/s

Answer:

The mechanical energy of the coin has been used up in doing work against friction.

Explanation:

When two bodies in contact move against one another, friction comes to play. Friction converts energy in such a system to heat which raises the temperature of the body, with most lost to the ambient environment. Sliding the coins on the floor transfers energy from your hand into the mechanical energy of the coin as it moves across the floor. Fiction between the coin and the surface of the floor gradually slows the coin down by converting its energy to heat (which raises the temperature of the coin as detected by the thermometer) until the coin comes to a halt.

Answer:

The magnitude of the surface charge density on each plate is 6.714 x 10⁻⁸ C/m²

Explanation:

Given;

area of the parallel plates, A = 8 cm² = 8 x 10⁻⁴ m²

distance between the plates, d = 2.9 mm = 0.0029 m

potential difference applied to the plates, V = 22 V

The electric field between the plates is given by;

[tex]E = \frac{V}{d} \\\\E = \frac{22}{2.9*10^{-3}}\\\\E = 7586.207 \ V/m[/tex]

The surface charge density is given by;

σ = ε₀E

σ = (8.85 x 10⁻¹²)(7586.207)

σ = 6.714 x 10⁻⁸ C/m²

Therefore, the magnitude of the surface charge density on each plate is 6.714 x 10⁻⁸ C/m²

Your bedroom has a rectangular shape, and you want to measure its area. You use a tape that is precise to 0.001 and find that the shortest wall in the room is 3.547 long. The tape, however, is too short to measure the length of the second wall, so you use a second tape, which is longer but only precise to 0.01 . You measure the second wall to be 4.79 long. Which of the following numbers is the most precise estimate that you can obtain from your measurements for the area of your bedroom?

b)If your bedroom has a circular shape, and its diameter measured 6.32 , which of the following numbers would be the most precise value for its area?

a)30 m^2

b) 31.4 m^2

c)31.37 m^2

d)31.371 m^2

Answer:

Part A

[tex]A = 16.99 \ m^2[/tex]

Part  B

 [tex]A_r =31.37 \ m^2[/tex]

Explanation:

From the question we are told that

   The  shortest wall is  [tex]x = 3.547 \ m[/tex]

      The  length of the second wall is [tex]y = 4.79 \ m[/tex]

Generally the area is mathematically evaluated as

           [tex]A = x * y[/tex]

=>    [tex]A = 3.547 * 4.79[/tex]

=>   [tex]A = 16.99 \ m^2[/tex]

Given that the diameter is  d =  6.32

Then the area is  

         [tex]A_r = \pi \frac{d^2}{4}[/tex]

         [tex]A_r =3.142 * \frac{6.32^2}{4}[/tex]

        [tex]A_r =31.37 \ m^2[/tex]

Answer:

The self-induced emf in this inductor is 4.68 mV.

Explanation:

The emf in the inductor is given by:

[tex] \epsilon = -L\frac{dI}{dt} [/tex]

Where:

dI/dt: is the decreasing current's rate change = -18.0 mA/s (the minus sign is because the current is decreasing)

L: is the inductance = 0.260 H

So, the emf is:

[tex] \epsilon = -L\frac{dI}{dt} = -0.260 H*(-18.0 \cdot 10^{-3} A/s) = 4.68 \cdot 10^{-3} V [/tex]

Therefore, the self-induced emf in this inductor is 4.68 mV.  

I hope it helps you!

The self-induced emf in this inductor is 4.68 mv.

Here

E = -LdI/dt

here

dI/dt represents the the decreasing current's rate change = -18.0 mA/s

the minus sign is due to the current is decreasing

L represents the inductance = 0.260 H

Now the emf should be

= -0260H * (-18.0.10^-3)

=  4.68 mv

hence, The self-induced emf in this inductor is 4.68 mv.

Learn more about current here: https://brainly.com/question/17080022

Answer:

Rock cycle describes the concept in geology that shows the changes in the rock type in the geologic time.

Many processes undergoes in the rock cycle that leads to transition of rocks, the process that changes metamorphic rock to igneous rock is melting and crystallization. The metamorphic rock melts under high pressure and temperature and which crystallizes into a completely different kind of rock, called igneous rock.

Answer:

Melting followed by cooling

Answer:

4 m/s.

Explanation:

The following data were obtained from the question:

Distance travalled (d) = 20 m

Time (t) = 5 secs

Speed (S) =?

Speed is defined as the rate of change of distance moved with time. Mathematically, it is expressed as:

Speed (S) = Distance (d) /time (t)

S = d/t

With the above formula, we can easily calculate the speed of the individual as follow:

Distance travalled (d) = 20 m

Time (t) = 5 secs

Speed (S) =?

S = d/t

S = 20/5

S = 4 m/s

Therefore, the speed of the individual is 4 m/s

Answer:

Ts = 3.0×10¯² sec

Explanation:

From the question given:

Ts = 2π √(4.5×10¯² Kg / 2.0×10³ Kg/s²)

The above expression can be evaluated as follow:

Pi (π) = 3.14

Ts = 2π √(4.5×10¯² / 2.0×10³)

Ts = 2 × 3.14 √(4.5×10¯² / 2.0×10³)

Ts = 6.28 × √(2.25×10¯⁵)

Ts = 6.28 × 4.74×10¯³

Ts = 3.0×10¯² sec

Answer:

C. Weight

Explanation:

A push or pull is a force.  The force caused by gravity is called weight.

Answer:

C: Weight

Explanation: