Why do sex cells contain only half the number of chromosomes needed for offspring? Explain

Answers

Answer 1

Answer:

None, egg cells don't have chromosomes. No, sex cells do have chromosomes. Meiosis reduces chromosome number so that sex cells (eggs and sperm) have a half set of chromosomes–one homolog of each pair. This is the haploid number.


Related Questions

When a substance easily dissolves in a liquid, it has high solubility in that liquid. When a substance does not easily dissolve in a liquid, it has low solubility in that liquid. Solubility of a gas in water describes how well the liquid can "hang on" to gas, instead of releasing it into the air. Based on the results of your experiment, do you think that CO2 has a higher solubility in hot water or cold water? Why?

Answers

Answer:

CO2 has a higher solubility in cold water

Explanation:

The solubility of gases decreases with increasing temperature,  the cold water will take up more CO2 and less will be escaping to the air. Furthermore, cold water is denser than warm water, causing it to sink.



A steel ball bearing is released from a height H and

rebounds after hitting a steel plate to a height H.

What is true about the collision with the steel plate?

Answers

Answer:

ELASTIC collision

kinetic energy is conservate

Explanation:

As the ball bounces to the same height, it can be stated that the impact with the floor is ELASTIC.

As the floor does not move the conservation of the moment

            po = pf

            -mv1 = m v2

- v1 = v2

So the speed with which it descends is equal to the speed with which it rises

Therefore the kinetic energy of the ball before and after the collision is the same

Answer:

CORRECT (SELECTED)

It is elastic since kinetic energy was conserved.

Explanation:

If a car with a mass of 5Kg, has a momentum of 25kgm/s, how fast is it travelling?

Answers

Answer:

5m/s

Explanation:

p=mv, or momentum (p) is equal to mass (m) times velocity (v).

so:

m=5Kg

p=25Kgm/s

v=p÷m

v=25÷5

v=5m/s

hoped this helped :)

Answer:

5hrs

Explanation:

Mass•Accelleration=Momentum (5kg•5hrs=25Mps)

Mass÷Momentum=Accelleration (25Mps÷5kg=5hrs)

You have five employees. They worked the following hours last week: 40, 37, 33, 25, 20. What was the mean number of hours worked?

Answers

Answer:

[tex]40 + 37 + 33 + 25 + 20 \div 5 = 155 \div 5 = 31[/tex]

Answer:

Or you could just say 31 :)

Explanation:

Sam makes six star-shaped cookies out of dough. He puts all of the cookies on a balance and measures the total weight as 36 grams. He then squeezes the cookies into one big ball and measures the weight. What is the weight of the entire ball?

Answers

Answer:

The answer is "36 grams".

Explanation:

In this question, the weight of the ball is not mentioned but is the weight of the cookies is declared, which is equal to 36 grams, and all the cookies are squeezes into the ball and after that, it calculates the overall weight so, let assume that ball weight is =0 and then the overall weight is:

[tex]=\text{weight of ball + cookies weight}\\\\=0+36 \ grams \\\\=36 \ grams[/tex]

A fault is formed by the movement of a ___ plate boundary
A.convergent
B.traditional
C.divergent
D.transform

Answers

Transform
Hope this helps

A 50 kg child is sitting on a scale on the floor of an elevator. The elevator starts at rest and accelerates down at a rate of a=−1 m/s2.Calculate the velocity of the elevator after 3 seconds.

Answers

Answer:

v=m/s m=v.s -1*3= -3 meter/second

The velocity of the elevator after 3 seconds will be equal to 3 m/s.

What are equations of motion?

We have three equations of motion that can be used to calculate components such as displacement(s), initial (u) and final velocity (v), time(t), and acceleration(a). The expressions for the three equations of motion are as follows:

First Equation of Motion :

v = u + at

Second Equation of Motion :

S = ut + (1/2) at²

The third equation of motion is:

v² - u² =2aS

Given, the initial velocity (u) of the elevator is zero as the elevator is at rest initially.

The acceleration of the elevator, a = -1 m/s² moving downward.

The  final velocity of the elevator after 3 seconds will be:

v = u + at

v = (0) + (-1 m/s²) (3 s)

v = - 3 m/s

Therefore, the velocity of the elevator after 3 seconds will be equal to 3 m/s in the downward direction.

Learn more about the equations of motion, here:

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Which element’s symbol could replace the question mark in the diagram? carbon (C) tellurium (Te) beryllium (Be) cesium (Cs)

Answers

Answer:

Tellurium

Explanation:

Answer:

Tellurium

Explanation:

1.Galileo conducted experiments from the top of the Leaning Tower of Pisa. If he dropped a piece of burlap tied into a ball with twine and a 2-pound rock at the same time, what would he have seen and why? (5 points)

Answers

Answer:

The time for both of the balls to reach the ground would be the same.

Explanation:

If no air resistance is present, the rate of descent depends only on how far the object has fallen, no matter how heavy the object is. This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height. ... In air, a feather and a ball do not fall at the same rate.

An archer defending a castle is on an 15.5 m high wall. He shoots an arrow straight down at 22.8 m/s. How much time does it take to reach the ground? (Unit = s) Watch your minus signs!​

Answers

Answer:

  about 602 milliseconds

Explanation:

The motion can be approximated by the equation ...

  y = -4.9t^2 -22.8t +15.5

where t is the time since the arrow was released, and y is the distance above the ground.

When y=0, the arrow has hit the ground.

Using the quadratic formula, we find ...

  t = (-(-22.8) ± √((-22.8)^2 -4(-4.9)(15.5)))/(2(-4.9))

  = (22.8 ± √823.64)/(-9.8)

The positive solution is ...

  t ≈ 0.60195193

It takes about 602 milliseconds for the arrow to reach the ground.

A bullet (m = .005 kg) moving at 500 m/s strikes
and sticks in a block of wood (m = 5 kg). What is
the final velocity of the wood/bullet mass?

Answers

Answer:

fif = 0.01 x 5000 = 50 N

Explanation:

u=150 m/s

v=0

m-10 y =0.01 kg

t=0.03s

s

v=utat

o= 150+a (0.03)

therefore a= -5000 m/s power 2

v power 2 = u power 2 + 2as

0=150 power 2+ 2 x (-5000) x s

therefore f=2.25 m

A 60 W light bulb has a resistance of 880 Ω
Calculate the CURRENT.
Write your answer in Amps to TWO SIGNIFICANT FIGURES

Answers

[tex]\bf{ \underline{Given:- }}[/tex]

[tex] \sf{• \: Power \: (P) = 60 \: w}[/tex]

[tex] \sf{• \: Resistance \: (R) = 880 \: Ω}[/tex]

[tex] \\ [/tex]

[tex]\bf{ \underline{To \:  Find :- }}[/tex]

[tex] \sf• \: The \: Current \: (I).[/tex]

[tex] \\ [/tex]

[tex] \huge\bf{ \underline{ Solution :- }}[/tex]

[tex] \sf We \: know \: that,[/tex]

[tex] \bf \red {\bigstar{ \: P = I^{2} R}}[/tex]

[tex] \rightarrow \sf 60 = I^{2} \times 880[/tex]

[tex] \rightarrow \sf \frac{60}{880} = I^{2} [/tex]

[tex] \rightarrow \sf I^{2} = 0.0681[/tex]

[tex] \rightarrow \sf I = \sqrt{0.0681}[/tex]

[tex] \rightarrow \sf I = 0.261 \: \: (approx.)[/tex]

[tex] \\ [/tex]

[tex]\bf The \: \: value \: \: of \: \: I \: \: is \: \: 0.261 \: \: Amps. \: \: (approx.)[/tex]

Match each term on the right to the correct definition.
A boundary formed when two plates
move past each other
1.
A.
Ocean basin
B.
Divergent bounda
2
.
A valley or depression between
continents
c.
Transform
boundary
3.
A boundary formed when two plates
collide
D.
Convergent
boundary
A boundary formed when two plates
move away from each other
A
B
С
D
II. Identification
Use the clues provided to fill in the blanks.

Answers

Answer:

Explanation:

C goes to 1

D goes to 3

B goes to 4

A goes to 2

A bike travels at 120 meters in 60 seconds. What is the speed of the bike?

Answers

Answer:

2 m/s

Explanation:

A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s2 . Of the tangential speed of the roller coaster cars is 15-7 m/s

Answers

Answer:

25.152m

Explanation:

Compete question;

A roller coaster has a loop in which the centripetal acceleration equals 9.8m/s² . If the tangential speed of the roller coaster cars is 15.7 m/s, find its radius.

centripetal acceleration a = v²/r

v is the tangential speed

r is the radius

Given

v = 15.7m/s

a = 9.8m/s²

9.8 =  15.7²/r

9.8r = 15.7²

r = 15.7²/9.8

r = 246.49/9.8

r = 25.152m

Hence the radius of the coaster is 25.152m

please help me answer this​

Answers

Answer:

W>R...............

Explanation:

.........................

Yes

(c) What would the angle of reflection be if the incident ray
was 40° from the reflecting mirror surface?

Answers

Answer:

So, if a wave hits a mirror at an angle of 36°, it will be reflected at the same angle (36°). ... An incident ray of light hits a plane mirror at an angle and is reflected back off it. The angle of reflection is equal to the angle of incidence. Both angles are measured from the normal.

Explanation:

Determine the increase in volume of 100m3 of mercury when it's temperature change from 10c to 45c the linear expansion coefficient is 6 x 10-5

Answers

Answer:

0.63m

Explanation:

Volume expansivity = change in volume/original volume×temp change

Volume expansivity p = 3x

p = ∆V/V∆t

x is the linear expansivity

Given

x = 6 x 10^-4

p = 3x

p = 3(6 x 10^-5)

p = 18×10^-5

Volume = 100m³

∆t = 45-10 = 35°C

Required

Change in volume ∆V

Substitute the given values into the formula

18×10^-5 = ∆V/100(35)

18×10^-5 =∆V/3500

∆V = 3500×0.00018

∆V = 0.63m

Hence the increase in volume of the Mercury is 0.63n

G8_SCIENCE_BSA_20_21
DOBSON, DAMIER
1 of 751 of 75 Items
Assessment started: G8_SCIENCE_BSA_20_21.
Item 1
Grade 8 Science

Session #1: Questions 1-38

1. The Herztsprung-Russell diagram shown below is used to group stars based on specific physical properties unique to each star.



Based on the diagram, which of the following describes the physical characteristics of Barnard’s Star?


hot and dim
hot and dim

cool and dim
cool and dim

hot and bright
hot and bright

cool and bright
cool and bright



























































































Item 1
Grade 8 Science

Session #1: Questions 1-38

1. The Herztsprung-Russell diagram shown below is used to group stars based on specific physical properties unique to each star.



Based on the diagram, which of the following describes the physical characteristics of Barnard’s Star?


hot and dim
hot and dim

cool and dim
cool and dim

hot and bright
hot and bright

cool and bright
cool and bright

Answers

Answer:

Do it yourself

Explanation:

gsh

Answer: cool and dim :)

Explanation:

how do you increase the ideal mechanical advantage of an inclined plane?

Answers

Answer:

The mechanical advantage increases as the slope of the incline decreases. But the load will then have to be moved a greater distance. The ideal mechanical advantage (IMA) of an inclined plane is the length of the incline divided by the vertical rise, the so-called run-to-rise ratio.

Explanation:

PLEASE MARK ME AS BRAINLIEST

In 1929, American astronomer Edwin Hubble discovered that distant galaxies were moving away from us. He found that light from distant objects in the universe shifted in frequency towards the red color on the electromagnetic spectrum, which tells us that the objects are receding away from us.
What phenomenon is described in the passage above? Select the best answer from the choices below.

a
The Doppler Shift
b
Hubble's Law
c
The Big Bang
d
Dark matter

Answers

Answer:

it is the Hubble law

Explanation:

Hubble's law, also known as the Hubble–Lemaître law, is the observation in physical cosmology that galaxies are moving away from the Earth at speeds proportional to their distance. In other words, the farther they are the faster they are moving away from Earth.

Answer:

The hubble law

is the observation in physical cosmology that galaxies are moving away from the Earth at speeds proportional to their distance. In other words, the farther they are the faster they are moving away from Earth.

which of these might be carried by the wind, which causes the weathering of rocks?

A. fog

B. mud

C. pollen

D. sand




BTW SCIENCE ISN'T IN SUBJECTS JUST SAYING​

Answers

A .

Explanation:

Tiny water drops hovering in the air are called fog. Fog is like a cloud, but it is near the ground, not high in the sky. Thick fog makes it difficult to see the surrounding landscape

we have that from the Question"which of these might be carried by the wind, which causes the weathering of rocks? " it can be said that  

Which of these might be carried by the wind, which causes the weathering of rocks will bepollen Option C

From the Question we are told

which of these might be carried by the wind, which causes the weathering of rocks?

A. fog

B. mud

C. pollen

D. sand

Generally

wind carry light and thing above the earth or at a higher altitudewhen pollen's are carried over a distance and germinate the root them self into rocks and as the grow bigger the crack rocks  thereby causing the weathering of rock

Therefore

Which of these might be carried by the wind, which causes the weathering of rocks will be

pollen

Option C

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An Olympic high diver (mass = 70 kg) stands on a platform 20 m above the surface of the water. What is the diver's gravitational potential energy?

Answers

Answer: 13720

Explanation: the equation is....

(70 kg) (9.8 m/[tex]s^{2}[/tex]) (20 m) = 13720

PLS ANSWER FAST WILL GIVE BRAINLY!! BUT ONLY IF YOU KNOW!!

Fill in the blanks


Cobalt has 27 protons, 32 neutrons and 27 electrons. What is it's atomic mass?

Answers

the atomic mass is 58

Answer:

58.933195 u or 59 u

Explanation:

Atomic mass of cobalt is 58.933195 u

Whats the word for when "velocity equals 0 and direction changes" Its 14 letters, and I have _ _ _ _ i _ _ _ _ _ h_ i _ _ t

Answers

Answer:

Maximum Height

Explanation:

The maximum height is the highest point reached by a projected body. At this point, final velocity, v of the body is equal to 0; because upward motion is at its peak and the body start to fall again.

Hence, final velocity v is always 0 at this maximum point and the direction of motion changes from upward to downward.

Final velocity at this maximum height is zero because of the directional change experied by the object and the fact that upward motion of the body terminates at this point.

9. During an egg toss, a catcher must cushion the egg by maximizing the time it takes to stop the

egg. Find the impulse applied to a 60.0-gram egg, if the egg has an initial velocity of 6.0 m/s as it

first touches the catcher's hand, and the egg is stopped within 50.0 cm.

Answers

Answer:

the impulse experienced by the egg is 0.053 kgm/s.

Explanation:

Given;

mass of the egg, m = 60 g = 0.06 kg

initial velocity of the egg, u = 6 m/s

height moved by the egg, h = 50 cm = 0.5 m

Determine the final velocity of the egg as it moves upward;

v² = u² + 2(-g)h

v² = u² - 2gh

where;

v is the final velocity

-g is negative acceleration due gravity as it moves upward

v² = 6² - 2(9.8 x 0.5)

v² = 26.2

v = √26.2

v = 5.12 m/s

The impulse applied to the egg is the change in linear momentum;

J = ΔP

ΔP = mu - mv

ΔP = m(u - v)

ΔP = 0.06(6 - 5.12)

ΔP = 0.053 kgm/s

Therefore, the impulse experienced by the egg is 0.053 kgm/s.

a variable that is changed by the researcher is called ___

Answers

an independent variable :)) hope I helped

Please help!! I'll name you brainliest!!

Answers

Answer:

b

Explanation:

in this condition the atom is not stable so in order to become stable ( trying to have the last energy level completely filled like the Nobel gases) it tends to lose or gain or share the electrons and that debend on its condition . I hope that's the right answer

A pitcher throws an overhand fastball from an approximate height of 2.65 m and at an angle of 2.5° below horizontal. The catcher catches the ball high in the strike zone, at a height of 1.02 m above the ground. If the pitcher's mound and home plate are 18.5 m apart, what is the initial velocity of the pitch?

Answers

Answer:

The initial velocity of the pitch is approximately 36.5 m/s

Explanation:

The given parameters of the thrown fastball are;

The height at which the pitcher throws the fastball, h₁ = 2.65 m

The angle direction in which the ball is thrown, θ = 2.5° below the horizontal

The height above the ground the catcher catches the ball, h₂ = 1.02 m

The distance between the pitcher's mound and the home plate = 18.5 m

Let 'u' represent the initial velocity of the pitch

From h = [tex]u_y[/tex]·t + 1/2·g·t², we have;

[tex]u_y[/tex] = The vertical velocity = u·sin(θ) = u·sin(2.5°)

h = 2.65 m - 1.02 m = 1.63 m

uₓ·t = u·cos(θ) = u·cos(2.5°) × t = 18.5 m

∴ t = 18.5 m/(u·cos(2.5°))

∴ h = [tex]u_y[/tex]·t + 1/2·g·t² =  (u·sin(2.5°))×(18.5/(u·cos(2.5°))) + 1/2·g·t²

1.63 = 8.5·tan(2.5°) + 1/2 × 9.8 × t²

t² = (1.63 - 8.5·tan(2.5°))/(1/2 × 9.8) = 0.25691469087

t = √(0.25691469087) ≈ 0.50686752763

t ≈ 0.50686752763 seconds

u = 18.5 m/(t·cos(2.5°)) = 18.5 m/(0.50686752763 s × cos(2.5°)) = 36.5334603 m/s ≈ 36.5 m/s

The initial velocity of the pitch = u ≈ 36.5 m/s.

How are rechargeable batteries recharged? (site 1)

Answers

Answer: Rechargeable batteries store energy through a reversible chemical reaction, which allows charge to be stored again after the battery has been drained.

Hope this helps (:
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