Answer:
Because Moon and Mars has no atmosphere.
Explanation:
Moon and Mars has no atmosphere, so there is no friction on the falling object due to the atmosphere. The speed of the falling object is more at Moon and Mars.
When a small object impact on the surface of moon or Mars with high speed, the size of crater is large than the earth as out earth has atmosphere.
Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m each. If Margy is walking at 1.4 m/s and accelerates at 0.20 m/s2 during
Complete question is;
Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m each. If Margy is walking at 1.4 m/s and accelerates at 0.20 m/s² during one of the running portions, what is her final velocity at the end of the 100.0 m? Round your answer to the nearest tenth.
Answer:
6.5 m/s
Explanation:
We are told that she is walking at 1.4 m/s and accelerates at 0.20 m/s².
Thus;
Initial velocity; u = 1.4 m/s
Acceleration; a = 0.2 m/s²
Distance; s = 100 m
From Newton's equation of motion, we know that;
v² = u² + 2as
Where v is final velocity.
Thus;
v² = 1.4² + 2(0.2 × 100)
v² = 41.96
v = √41.96
v ≈ 6.5 m/s
a trampoline launches a 50kg person 2m into the air. if the springs push with 1960N of force, how much displacement was there in the trampoline
Answer: 0.5 m
Explanation:
Given
Mass of the person is [tex]m=50\ kg[/tex]
Trampoline launches the person into the air up to height of [tex]h=2\ m[/tex]
Force experience by springs is [tex]F=1960\ N[/tex]
Here, the work done on displacing the springs is equivalent to the Potential energy acquired by the person i.e.
[tex]\Rightarrow F\cdot x=mgh\quad [\text{x=displacement of the trampoline}]\\\\\text{Insert the values}\\\\\Rightarrow x=\dfrac{50\times 9.8\times 2}{1960}\\\\\Rightarrow x=\dfrac{980}{1960}\\\\\Rightarrow x=0.5\ m[/tex]
Answer:
0.5
Explanation:
The force that the left team pulls with is 1000 N. If the right team's total mass is 300 kg and they accelerate by 1.2 m/s2, what is the force of resistance on the right team
Answer:
the force of resistance on the right team is 360 N
Explanation:
Given;
force of the left team, = 1000 N
total mass of the right team, m = 300 kg
acceleration of the right team, a = 1.2 m/s²
The force of resistance of the right team is calculated as;
Force = mass x acceleration
Force, F = 300 x 1.2
Force = 360 N
Therefore, the force of resistance on the right team is 360 N
Two students with masses of 40kg and 32 kg are sitting 22 m apart. What is the gravitational force of attraction between them?
I get 1.76 x 10^-10 Newton.
That's 0.000 000 000 176 Newton
Which is about 0.000 000 000 635 ounce of force pulling them together.
That's why we never notice it.
(12 points) Analysis from the point where the block is released to the point where it reaches the maximum height i) Calculate the highest height reached by the block (or the largest distance travelled along the ramp.) ii) Calculate the work done by the gravitational force. iii) Calculate the work done by the normal force. iv) Calculate the work done by the friction force.
Answer:
i) a₁ = -g (sin θ + μ cos θ), x = v₀² / 2a₁
ii) W = mg L sin θ , iii) Wₙ = 0
iv) W = - μ m g L cos θ x
Explanation:
With a drawing this exercise would be clearer, I understand that you have a block on a ramp and it is subjected to some force that makes it rise, for example the tension created by a descending block.
The movement is that when the system is released, the tension forces are greater than the friction and the component of the weight and therefore the block rises up the ramp
At some point the tension must become zero, when the hanging block reaches the ground, as the block has a velocity it rises with a negative acceleration to a point and stops where the friction force and the weight component would be in equilibrium along the way. along the plane
i) Let's use Newton's second law
the reference system is with the x axis parallel to the ramp
Axis y
N - W cos θ = 0
X axis
T - W sin θ - fr = ma
the friction force is
fr = μ N
fr = μ mg cos θ
we substitute
T - m g sin sin θ - μ mg cos θ = m a
a = T / m - g (sin θ + μ cos θ)
With this acceleration we can find the height that the block reaches, this implies that at some point the tension becomes zero, possibly when a hanging block reaches the floor.
T = 0
a₁ = -g (sin θ + μ cos θ)
v² = v₀² - 2a1 x
v = 0 at the highest point
x = v₀² / 2a₁
ii) the work of the gravitational force is
W = F .d
W = mg sin θ L
iii) the work of the normal force
the force has 90º with respect to the displacement so cos 90 = 0
Wₙ = 0
iv) friction force work
friction force always opposes displacement
W = - fr d
W = - μ m g cos θ L
For taking bath, water at 40⁰C is required. Calculate the mass of cold water at 15⁰C which is to be added in 60 Kg water at 100⁰C for bathing purpose. 1 point a) 51Kg b) 47Kg c) 44 Kg d) 39Kg
HELP PLEASE!!
When the same amount of heat is added to equal masses of water and copper at the same temperature, the copper is heated to a higher final temperature than the water. On a molecular level, what explains this difference?
A. The forces between copper atoms are stronger than the forces between water molecules.
B. The average kinetic energy of the water molecules is greater than the average kinetic energy of the copper atoms.
C. More of the heat is transferred to the kinetic energy of the copper atoms than to the kinetic energy of the water molecules.
D. More of the heat is transferred to the potential energy of the copper atoms than to the potential energy of the water molecules.
Answer:
C. More of the heat is transferred to the kinetic energy of the copper atoms than to the kinetic energy of the water molecules.
Explanation:
Both equal masses of water and copper were heated at the same temperature. Since copper is a good conductor of heat compared to water, its absorbs more heat. Which in-turn increases the rate of vibrations of the atoms in the copper mass, thus increasing their kinetic energy.
In the case of water, its molecules displaces one another after being heated to a higher temperature compared to neighboring molecules. So that the heated molecule becomes less dense and floats to the surface of water.
This property of copper makes it to be heated to a higher final temperature than the water.
If the universe is infinite, then how come there are things disappearing from the horizon? I was at a point in this video (TRUE Limits Of Humanity from Kurzgesagt) about true limits of humanity, and the narrator mentioned that (04:12) "...there is a cosmological horizon around us. Everything beyond it, is traveling faster, relative to us, than the speed of light. So everything that passes the horizon is irretrievably out of reach forever and we will never be able to interact with it again." Are they talking about how galaxies passing the horizon are physically absent, or just visually aren't there and we are unable to interact with them?
Answer:
The big rip theory
Explanation:
I believe what you are referring to is the big rip theory, in which the universe expands faster than the speed of light Kurzgesagt refers to it as a "horizon" but in reality it's a little more complicated than that. Eventually the expansion of the universe will accelerate far beyond the speed of light creating space between molecules until eventually all matter is fleeting and the entire universe is an endlessly vast cosmic void with not but the occasion molecule left from a time when things weren't so lonely.
Space weather is dominated by a stream of charged particles emanating from the sun's magnetic field, known as ______________.
Answer:
solar windExplanation:
This stream of particles emanating from sun's magnetic field is known as the solar wind.
The gas and particles come from the Sun's hot outer atmosphere, called the corona. These particles from the corona are charged with electricity.
A car's bumper is designed to withstand a 5.04-km/h (1.4-m/s) collision with an immovable object without damage to the body of the car. The bumper cushions the shock by absorbing the force over a distance. Calculate the magnitude of the average force on a bumper that collapses 0.255 m while bringing a 890-kg car to rest from an initial speed of 1.4 m/s.
Answer:
3420.39 N
Explanation:
Applying,
Fd = 1/2(mv²-mu²)................. Equation 1
Where F = force on the bumber, d = distance, m = mass of the car, v = final velocity, u = initial velocity.
make F the subject of the equation
F = (mv²-mu²)/2d............... Equation 2
From the question,
Given: m = 890 kg, v = 0 m/s (to rest), u = 1.4 m/s, d = 0.255 m
Substitute these values into equation 2
F = [(890×0²)-(890×1.4²)]/(2×0.255)
F = -1744.4/0.51
F = -3420.39 N
The negative sign denotes that the force in opposite direction to the motion of the car.
If you connected 10 of these 12V (10 W) lamps in parallel, to the 12V source, how much current would the source have to supply
Answer:
[tex]T=8.33A[/tex]
Explanation:
From the question we are told that:
Number of battery [tex]n=10[/tex]
Voltage source[tex]E=12V[/tex]
Lamp Power[tex]P=10W[/tex]
Generally the equation for Resistance is mathematically given by
[tex]R=\frac{V^2}{P}[/tex]
[tex]R=\frac{12^2}{10}[/tex]
[tex]R=14.4ohms[/tex]
Therefore
[tex]R_{eq}=\frac{14.4}{10}[/tex]
[tex]R_{eq}=1.44[/tex]
Generally the equation for Current is mathematically given by
[tex]T=\ffrac{V}{Req}[/tex]
[tex]T=\frac{12}{1.44}[/tex]
[tex]T=8.33A[/tex]
To leave the gravitational pull of the Earth, and explore other planets, satellites must have at least:
Answer:
To explore the other planets, the satellite must have the velocity more than the escape velocity.
Explanation:
The minimum velocity required by any object to escape from the earth gravitational pull is called the escape velocity.
The escape velocity for any planet depends on the mass of planet and radius of planet. It does not depends on the mass of object. The escape velocity is same for any mass for a particular planet.
So, to explore the other planets, the satellite must have the velocity more than the escape velocity.
Richard rides a bike on a road sloping downward and inclined at an angle of 30° with the horizontal. If he moves at a constant speed of 10 meters/second, calculate his vertical downward velocity.
Answer:
[tex]v_y = 5\ m/s[/tex]
Explanation:
The vertical downward component of the speed of the bike can be simply found out by using the following geometric formula:
[tex]v_y = vSin\theta[/tex]
where,
[tex]v_y[/tex] = vertical downward component of speed = ?
v = speed = 10 m/s
θ = angle of slope = 30°
Therefore,
[tex]v_y = (10\ m/s)Sin\ 30^o\\v_y = 5\ m/s[/tex]
rainfall occurs on the earth due to effect of gravity
Answer:
TrueBecause Gravity is the force of attraction between two objects, and Earth's gravity pulls matter downward, toward its center. It pulls precipitation down from clouds and pulls water downhill. Gravity also moves air and ocean water. ... Gravity pulls denser air and water downward, forcing less dense air and water to move upward.Carryonlearning
NEED THIS ASAP
Ariana is accelerating her car at a rate of 4.6 m/s2 for 10 seconds. Her starting velocity was 0 m/s.
What was her final velocity?
0 m/s
2.3 m/s
4.6 m/s
46 m/s
Answer:
46
Explanation:
v = at so 4.6 x 10 = 46
7. Explain how sound waves striking the tympanic membrane result in movement of fluids in the inner ear.
Answer:
This has been explained below.
Explanation:
Sound waves move along the auditory canal and when moving they hit the tympanic membrane making it to vibrate. this vibration would make the 3 ossicles to move. the tympanic membrane is sticked to the auditory ossicles and the stapes are joined to the oval window. as movements occur in the oval window, there would be motions happening in the cochlea
A pair of forces with equal magnitude, opposite directions, and different lines of action is called a "couple." When a couple acts on a rigid object, the couple produces a torque that does not depend on the location of the axis. The drawing shows a couple acting on a tire wrench, each force being perpendicular to the wrench. Determine an expression for the torque produced by the couple when the axis is perpendicular to the tire and passes through the following. Express your answers in terms of the magnitude F of the force and the length L of the wrench.
The drawing shows the couple acting on a tire wrench is missing and so i have attached it.
We are to find an expression for the torque when the axis is perpendicular to the tire and passes through the points A, B & C
Answer:
Point A: τ = Fl
Point B: τ = 0
Point C: - Fl
Explanation:
Formula for torque is;
τ = F × d
Where;
F is perpendicular force
d is distance.
Thus;
> At point A, it means we are taking torque about point A and so we have;
τ = (-F × 0) + (F × L)
τ = Fl
> At point B, it means we are taking torque about point B and so we have;
τ = (-F × L/2) + (F × L/2)
τ = -(FL/2) + (FL/2)
τ = 0
> At point C, it means we are taking torque about point C and so we have;
τ = (-F × L) + (F × 0)
τ = -FL
To overcome the problems that blur images and don't provide the best resolution from Earth, astronomers have started using flexible mirrors that change shape many times each second. This technique is called:
Answer:
adaptive optics
Explanation:
simple
It was found that ice cream sales decrease significantly as the temperature outside decreases; a very strong relationship was found. What is the most likely correlation coefficient from this hypothetical study
Answer:
Value closest to 1
Explanation:
It is described from the scenario above that ice cream sales decreases as the outside temperature increases, hence showing a strong relationship between both variables (icream sales and temperature). The correlation Coefficient is a metric used in regression modeling to depict the strength of relationship between two variables, (The dependent and independent variables). Correlation Coefficient ranges from (-1 to +1). With values close to 1 or - 1. Also the positive and negative signs are used to show the type of relationship between the variables. If an increase in variable A leads to a decrease in variable B, then we have negative correlation (-) ; while an increase or decrease in both variables depicts a positive correlation. The most likely correlation Coefficient for the study above will be a positive value which is close to 1 since the relationship is described as strong.
3.00 m^3 of water is at 20.0°C.
If you raise its temperature to
60.0°C, by how much will its
volume expand?
Water
B = 207•10-6 0-1
(Unit = m^3)
Answer:
[tex]\triangle V = 0.02484m^3[/tex]
Explanation:
Given
[tex]V_1 = 3.00m^3[/tex] --- initial volume
[tex]T_1 = 20.0^oC[/tex] --- initial temperature
[tex]T_2 = 60.0^oC[/tex] --- final temperature
[tex]\gamma = 207*10^{-6[/tex] --- coefficient of thermal expansion:
Required
The change in volume
To do this, we make use of cubic expansivity formula
[tex]\triangle V = \gamma * V_2 * (T_2 - T_1)[/tex]
So, we have:
[tex]\triangle V = 207 * 10^{-6} * 3.00 * (60.0 - 20.0)[/tex]
[tex]\triangle V = 207 * 10^{-6} * 3.00 * 40.0[/tex]
[tex]\triangle V = 0.02484m^3[/tex]
The volume will expand by [tex]0.02484m^3[/tex]
What is the acceleration of a motorcycle that starts from rest and reaches a velocity of 24 m/s in 8.5 seconds?
Answer:
2.82 m/s²
Explanation:
[tex]v = u + at \\ 24 = 0 + a(8.5) \\ a = 2.82 \: ms {}^{ - 2} [/tex]
The acceleration of a motorcycle is 2.82 m/s^2.
What is acceleration?Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.
Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.
Given that:
Initial velocity of the motor cycle: u = 0 m/s.
Final velocity of the motorcycle = 24 meter/second.
Time taken to reach this velocity = 8.5 second.
Hence, acceleration of the motor cycle = change in velocity/time interval
= ( final velocity - initial velocity)/time interval
= ( 24 m/s - 0 m/s)/8.5 s
= 2.82 m/s^2.
Its acceleration is 2.82 m/s^2.
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Two identical metallic sphere having unequal opposite charges are are placed
distance of 0.05m apart in air.
After bringing them in contact
with each other, they are again placed at the same distance apart, now the force of repulsion between them is 0.108 N. Calculate the final charge on each of them.
Answer:
Let the initial charges be q1 and q2 respectively.
After they come in contact, the charges are rearranged such that they acquire same charge.
let us say that charge on each of them is Q.
They are again brought apart at a distance of 0.9 m. Hence, the force between them will be given as
F = kQ2 / r2
0.025 = (9×109 x Q2) / 0.92
Q2 = 0.025 x 0.92 / 9×109
Q = 1.5 x 10-6 C
Explanation:
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If voltage , V = 100 + 6 volt and current , I = 10+ 0.2 A , then find
percentage error in R.
Explanation:
As we know, resistance is the ratio of voltage used and current flowing through the circuit. So,
R = V/IBy error calculation
∆R/R = [(∆V/V)100] + [(∆I/I)100]V = 100 ± 6% V
I = 10 ± 0.2% A
∆R/R= (5/100)×100 + (0.2/10)×100
∆R/R=5+2=7%
So, percentage error in resistance (R) = ± 7%.Answer:
Percentage error of R is ±7%
The boiling point of a substance is _72 degree Celsius. This temperature will be equivalent to Kelvin scale is-------.
Answer:
345 K
Explanation:
Temperature can be defined as a measure of the degree of coldness or hotness of a physical object.
Generally, it is measured with a thermometer and its units are Celsius (°C), Kelvin (K) and Fahrenheit (°F).
Given the following data;
Boiling point = 72°CTo convert the temperature in degree Celsius to Kelvin, we would use the following mathematical expression;
Kelvin = 273 + °C
Substituting into the formula, we have;
Kelvin = 273 + 72
Kelvin = 345 K
Therefore, the temperature of 72°C will be equivalent to 345 K on the Kelvin scale.
What happens in a series circuit when more bulbs are added? (Example: I start out with a complete series circuit with 2 bulbs. Then I add in several more wires and several more bulbs & bulb holders. Now I have a complete series circuit with 5 bulbs).
Answer:
when we add elements in a series circuit the voltage across each element decreases
Explanation:
In a series circuit the current the whole circuit is the same, since there is only one path,
resistance is the sum of the resistance of each element
R_{eq} = ∑ R_i
if we write ohm's law
V = i R_{eq}
we substitute
V = i ∑ R_i
therefore the total voltage is
V = ∑ i R_i = ∑ V_i
With this expression we see that the voltage decreases as we place more elements in the series circuit.
Specifically when we fear two elements the voltage across each element is
V_i = V / 2
when we have 5 elements the voltage across each element is
V_i = V / 5
therefore when we add elements in a series circuit the voltage across each element decreases
After landing the aeroplane's momentum becomes zero. Explain how
the law of conservation holds here.
Answer:
The law of momentum conservation can be stated as follows. For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
9. In a __________ collision, 100% of both vehicles' speed is directed towards the point of impact. A. head-on B. rear-end C. side-impact
Answer: A
Explanation:
:)
What is an electric fuse? What is the working principle of electric fuse?
where would the spaceprobe experience the strongest net (or total) gravitional force exerted on it by Earth and Mars
Answer:
r = 41.1 10⁹ m
Explanation:
For this exercise we use the equilibrium condition, that is, we look for the point where the forces are equal
∑ F = 0
F (Earth- probe) - F (Mars- probe) = 0
F (Earth- probe) = F (Mars- probe)
Let's use the equation of universal grace, let's measure the distance from the earth, to have a reference system
the distance from Earth to the probe is R (Earth-probe) = r
the distance from Mars to the probe is R (Mars -probe) = D - r
where D is the distance between Earth and Mars
[tex]G \ \frac{m \ M_{Earth}}{r^2} = G \ \frac{m \ M_{Mars}}{(D-r)^2}[/tex]
M_earth (D-r)² = M_Mars r²
(D-r) = [tex]\sqrt{ \frac{M_{Mars}}{ M_{Earth}} }[/tex] r
r ( [tex]1 + \sqrt{ \frac{M_{Mars}}{M_{Earth}} }[/tex]) = D
r = [tex]\frac{D}{ 1+ \sqrt{\frac{M_{Mars}}{ M_{Earth}} } }[/tex]
We look for the values in tables
D = 54.6 10⁹ m (minimum)
M_earth = 5.98 10²⁴ kg
M_Marte = 6.42 10²³ kg = 0.642 10²⁴ kg
let's calculate
r = 54.6 10⁹ / (1 + √(0.642/5.98) )
r = 41.1 10⁹ m
. What is a normal force? It acts against an object slowing it down. It acts perpendicular to an object. It acts with an object adding to its speed. It acts parallel to an object.
Answer:
Explanation:
This is basically asking you what the definition of Normal force is. Normal force is the force that pushes back against the weight of something that is sitting (or standing or lying) perpendicular to it. That's why, when you stand on a floor you don't crash through the floor OR go shooting up into space. The Normal force is equal but opposite to your weight. The floor exerts the normal force (pushing up and is positive) while your weight is opposing it (pushing down and is negative.) Perpendicular is the key word here, I believe.
A normal force acts perpendicular to an object. It is the force exerted by a surface to support the weight of an object resting on it.
The normal force acting against an object slowing it down or acting with an object adding to its speed, are not accurate descriptions of the normal force. The normal force primarily deals with the support of an object on a surface and is directed perpendicular to that surface.
Normal force is the force that pushes back against the weight of something that is sitting (or standing or lying) perpendicular to it. That's why, when you stand on a floor you don't crash through the floor OR go shooting up into space. The Normal force is equal but opposite to your weight. The floor exerts the normal force (pushing up and is positive) while your weight is opposing it (pushing down and is negative.)
Therefore, A normal force acts perpendicular to an object. It is the force exerted by a surface to support the weight of an object resting on it.
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