Answer:
C
Explanation:
Gravity pulls objects towards earth's core without needing any contact with objects
explain how warm air temperatures affect the density of the air
Explanation:
As the molecules heat and move faster, they are moving apart. So air, like most other substances, expands when heated and contracts when cooled. Because there is more space between the molecules, the air is less dense than the surrounding matter and the hot air floats upward.
A physics student stands on a bathroom scale in an elevator which is not moving. The scale reads 604 N. The elevator then accelerates downward at 1.98 m/s2. What does the scale read during this acceleration?
Answer:
If we take downwards as the positive direction -
m a = m g - T difference between scale and mg is equal to acceleration
T = m (g - a)
m = 604 / 9.80 = 61.6 kg mass of student
T = 61.6 (9.80 - 1.98) = 482 N scale reading
The force when the elevator then accelerates downward at 1.98 m/s² is 725.78 N.
When the lift is stationary (at rest), the student is subject to a downward force equal to 604 N, which is caused by gravity (assumed to be equal to the student's weight according to the scale).
Given:
Force, F = 604 N
Acceleration, a = 1.98 m/s²
The mass can be computed from force and acceleration due to gravity
F = mg
604 N = mass × 9.81
mass = 604 N / 9.81
mass = 61.56 kg
The force is calculated as:
F' = ma
F' = 61.56 kg × 1.98
F' = 121.78 N
The total force is :
Total force = F +F"
Total force = 604 N + 121.78 N
Total force = 725.78 N
Hence, the force when the elevator then accelerates downward at 1.98 m/s² is 725.78 N.
To learn more about Force, here:
https://brainly.com/question/13191643
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Two objects have a gravitational force between them of 750N. The two objects now move towards
each other, the gravitational force between them
a. remains at 750N
b. increases above 750N
C. decreases below 750N
Answer:
b. increases above 750N
Explanation:
Okay
With what force will a car hit a tree if the car has a mass of 3,454 kg and it is accelerating at a rate of 5 m/s2?
Answer:
F = 17270 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by the acceleration.
ΣF = m*a
where:
F = force [N]
m = mass = 3454 [kg]
a = acceleration = 5[m/s^2]
Now replacing:
F = 3454*5
F = 17270 [N]
Sara pushes her 45 kg younger sister with a force of 300 N to the right and encounters 120 N of friction. Calculate the little sister’s acceleration. Show steps please:)
A particle is projected vertically upwards with a velocity of 34.3 m/s. For how long is the particle at a height of 49 m and above the point of projection?
Calculate the time to reach a height of 49 m:
S = V0 t - 1/2 g t^2
S = 34.3 t - 1/2 * 9.8 * t^2
4.9 t^2 - 34.3 t + 49 = 0
I get t = 2 and t = 5 as solutions of the quadratic.
We know that it takes v / a = 34.3 / 9.8 = 3.5 sec to reach maximum height.
So we have:
2 sec to reach 49 m
3.5 sec to reach max height
1.5 sec from 49 m to max height
1.5 sec from max height back down to 49 m
2 sec to fall from 49 m to ground
2 sec + 1.5 sec + 1.5 sec = 5 sec to go from ground to max height and back down to 49 m
You skip north for 12 minutes to your best friend's house that is 1.5 kilometers away. What is your average velocity?
Answer:
The average velocity is 7.5 km/h
Explanation:
Let's convert minutes to hours so our answer can be given in a common units of km/hour:
12 minutes = 12/60 hours = 0.2 hours
Now we estimate the average velocity calculating the distance travelled over the time it took:
1.5 / 0.2 km/h = 7.5 km/h
Water at the top of Horseshoe Falls (part of Niagara Falls)
is moving horizontally at 9.0 m/s as it goes off the edge and
plunges 53 m to the pool below. If you ignore air resistance,
at what angle is the falling water moving as it enters the
pool?
Answer:
[tex]\theta= (-74.42)^{\circ} C[/tex]
Explanation:
Horizontal speed of water, [tex]v_{xf}=9\ m/s[/tex]
Height, h = -53 (below pool)
We can find firstly the final vertical speed of the water using third equation of kinematics. So
[tex]v^2_{yf}=u^2_{yi}+2(-g)h\\\\v^2_{yf}=2\times -9.8\times -53\\\\v_{yf}=32.23\ m/s[/tex]
Let [tex]\theta[/tex] is the angle where the falling water moving as it enters the pool. So,
[tex]\tan\theta=\dfrac{v_{yf}}{v_{xf}}\\\\=\dfrac{-32.3}{9}\\\\=-74.42^{\circ} C[/tex]
Hence, the angle is (-74.42)°C.
Select the correct answer.
Proper technique can help prevent injuries.
A.
True
B.
False
Answer:
b
Explanation:
Answer:
false
Explanation:
A bar magnet is held vertically with its upper end a little bit below the center of a horizontal metal ring. The upper end of the magnet is its north pole, as shown in the figure. The bar magnet is now dropped. An observer views the ring from above its center. To this observer, how will the induced current in the ring behave as the magnet falls?.
Answer:
The current will flow counter-clockwise and be decreasing
Explanation:
Do you agree or disagree with Kinsey that sexuality is a fluid concept, ranging on a seven-point scale from homosexual to heterosexual? Or, do you think these are discrete constructs that have finite points where they begin and end sexuality?
Answer:
kinsey sexuailty doesn't matter because that is his or her
Explanation:
\A thin hoop with a radius of 10 cm and a mass of 3.0 kg is rotating about its center with an angular speed of 3.5 rad/s. What is its kinetic energy
The rotational or kinetic energy of the thin hoop with the given radius, mass and angular speed is 0.092J
Given the data in the question;
Mass of hoop; [tex]m = 3.0kg[/tex]Radius; [tex]r = 10cm = 0.1m[/tex]Angular speed; [tex]w = 3.5rad/s[/tex]Rotational or kinetic energy; [tex]E_{rotational} = \ ?[/tex]
Rotational energy or angular kinetic energyRotational energy or angular kinetic energy is simply kinetic energy due to the rotation of a rigid body.
It is expressed as;
[tex]E_{rotational} = \frac{1}{2}Iw^2[/tex]
Where [tex]I[/tex] is the moment of inertia around the axis of rotation and [tex]w[/tex] is the angular speed or velocity.
For the moment of inertia around the axis of rotation.
[tex]I = \frac{1}{2}mr^2[/tex]
Hence
[tex]E_{rotational} = \frac{1}{2}(\frac{1}{2}mr^2)w^2 \\\\E_{rotational} = (\frac{1}{4}mr^2)w^2[/tex]
Now, we substitute our given values into the above equation to find the rotational or kinetic energy.
[tex]E_{rotational} = (\frac{1}{4}*3.0kg * (0.1m)^2) * (3.5rad/s)^2 \\\\E_{rotational} = 0.0075kgm^2 * 12.25rad/s^2\\\\E_{rotational} = 0.092kg.m^2/s^2\\\\E_{rotational} = 0.092J[/tex]
Therefore, the rotational or kinetic energy of the thin hoop with the given radius, mass and angular speed is 0.092J
Learn more about rotational energy: https://brainly.com/question/19305456
A scientist wants to know if adults prefer watching movies in a theater or in their home. He interviews 500 people leaving a local movie theater and finds that 480 of them like watching movies in theaters. The scientist concludes that 96 percent of people like watching movies in theaters more than at home. Why is the scientist's conclusion most likely unreliable?
Not enough people were interviewed.
The investigation was based on preferences.
The investigation was not replicable.
The location of the survey introduced bias
Answer:
The location of the survey is biased.
Explanation:
If someone left a movie theater, it is most likely because he likes watching movies there. A better place to interview would be on the streets, as it’s less biased there
Answer:
It will be D/ The location of the survey introduced bias!
Explanation:
1. While cruising along a dark sketch of highway at a speed of 25 m/s, you see that a bridge ahead has been washed out. You apply the brakes and uniformly slow down to a stop in 5.0 seconds.
The velocity values are ________. (Positive/Negative)
The acceleration value is _______. (Positive/Negative)
Therefore the object must be _________. (Speeding Up/Slowing Down)
2. A poorly tuned Yugo can accelerate from rest to a speed of 28 m/s in 20 s.
The velocity values are ________. (Positive/Negative)
The acceleration value is _______. (Positive/Negative)
Therefore the object must be _________. (Speeding Up/Slowing Down)
3. A bear is sitting at rest at t=0s. At t=5s, the bear notices honey 16 m away and takes off from rest accelerating at a rate of 2 m/s2 for 4 seconds to reach the honey.
The velocity values are ________. (Positive/Negative)
The acceleration value is _______. (Positive/Negative)
Therefore the object must be _________. (Speeding Up/Slowing Down)
4. A dog runs down his driveway with an initial velocity of -5 m/s for 8 seconds, then uniformly increases his speed to -10 m/s in 5 seconds.
The velocity values are ________. (Positive/Negative)
The acceleration value is _______. (Positive/Negative)
Therefore the object must be _________. (Speeding Up/Slowing Down)
5. You are driving on the highway at a rate of 40 m/s for 10 seconds when you notice a cop in front of you. Over the next 5 seconds you uniformly slow down to 35 m/s to avoid getting a speeding ticket.
The velocity values are ________. (Positive/Negative)
The acceleration value is _______. (Positive/Negative)
Therefore the object must be _________. (Speeding Up/Slowing Down)
6. You are traveling 20 m/s when the stoplight in front of you turns red. You step on your break to uniformly slow down to a rest in 5 seconds. You are stopped at the red light for 3 seconds when the light turns green. You speed back up to 20 m/s over the next 5 seconds.
The velocity values are ________. (Positive/Negative)
The acceleration value is _______. (Positive/Negative)
Therefore the object must be _________. (Speeding Up/Slowing Down)
The velocity values are ________. (Positive/Negative)
The acceleration value is _______. (Positive/Negative)
Therefore the object must be _________. (Speeding Up/Slowing Down)
1.
The velocity values are Negative.
The acceleration value is Negative.
Therefore the object must be Speeding Up.
2.
The velocity values are Positive.
The acceleration value is Positive.
Therefore the object must be Slowing Down.
3.
The velocity values are Positive.
The acceleration value is Positive.
Therefore the object must be Slowing Down.
4.
The velocity values are Negative.
The acceleration value is Negative.
Therefore the object must be Speeding Up.
5.
The velocity values are Positive.
The acceleration value is Positive.
Therefore the object must be Slowing Down.
6.
The velocity values are Negative.
The acceleration value is Negative.
Therefore the object must be Speeding Up.
((I tried my very best I am sorry if any answers I have given are incorrect, but I wish you good luck on your Test/Quiz or whatever you may be currently working on at the time. This took a while.))In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? 214 nm 224 nm 204 nm 100 nm 234 nm
Answer:
The correct option is a: 214 nm.
Explanation:
The wavelength (λ) of the light can be calculated as follows:
[tex] \lambda = \frac{yd}{nD} [/tex] (1)
Where:
y: is the distance of the 7th bright fringe on the screen from the central fringe = 10.0 cm
d: is the distance between the slits = 3.00x10⁻⁵ m
D: is the distance between the screen and the slits = 2.00 m
n = 7
By entering all the above values into equation (1) we have:
[tex] \lambda = \frac{yd}{nD} = \frac{0.10 m*3.00 \cdot 10^{-5} m}{7*2.00 m} = 214.3 nm [/tex]
Therefore, the correct option is a: 214 nm.
I hope it helps you!
Where can you find the neutrons of an atom? in the nucleus with the protons orbiting the nucleus In the nucleus with the electrons this is not part of an atom
ANSWER PLEASE ITS A EXAM 10 POINTS PLEASE FASTTTTTTTTTTT!!!!!!!1
Answer:
Nuclease is the answer I know
I hope this is the answer
Several masses m are determined to be equal by comparing them on an equal-arm balance, and a large mass M is found to just balance two of the small ones on a similar balance. The mass M and one of the masses m are each forced to go around a bend of 1.0 m at a constant speed of 1.0 m/s. As they move around the curve their magnitudes of the forces acting on them are
Question 1 options:
a)
equal.
b)
in the ratio of 4:1.
c)
along the direction of motion.
d)
in the ratio of 2:1.
e)
zero.
Answer:
Option (d) is correct.
Explanation:
As the large mass M is found to just balance two of the small mass, m, so
[tex]M=2m\cdots(i)[/tex]
As both the masses M as well as m are forced to go around a bend of 1.0 m at a constant speed of 1.0 m/s.
So, the radius of curvature of the bend (curved path), R= 1.0 m
The speed both the masses, v= 1.0 m/s.
Naturally, without any restriction, all the masses have the tendency to move in a straight line due to its inertia, but here both the masses are moving on the curved path because of the application of the external force on them. This continuous change in the direction is due to the force by the wall of the curved path which is actually the normal reaction by the wall on both the masses.
This reaction force, [tex]F_R[/tex], balance the centrifugal force, F with which the masses have a tendency to go out of the path, the magnitude of this centrifugal force is,
[tex]F = \frac {mv^2}{R}[/tex]
Where m is the mass of the body, v is the speed at that instant, R is the radius of curvature of the path.
So, [tex]F_R=\frac {mv^2}{R}[/tex]
Now, for the small mass, m, the reaction force on it is
[tex]F_R1= \frac {mv^2}{R}[/tex]
[tex]\Rightarrow F_R1= \frac {m(1)^2}{1}[/tex]
[tex]\Rightarrow F_R1= m \cdots(ii)[/tex]
And for the bigger mass, M, the reaction force on it is
[tex]F_R2= \frac {Mv^2}{R}[/tex]
[tex]\Rightarrow F_R2= \frac {M(1)^2}{1}[/tex]
[tex]\Rightarrow F_R2= M[/tex]
By using equation (i), we have
[tex]F_R2= 2m[/tex]
[tex]\Rightarrow F_R2=2F_R1[/tex] [by using (ii)]
[tex]\Rightarrow F_R2 / F_R1 = 2/1[/tex]
So, the ratio of force acting on the bigger mass M to the magnitude of the force acting on the smaller mas m is 2:1.
Hence, option (d) is correct.
Mrs. LaCross leaves school and accidentally leaves her coffee mug on the roof of her car as shown in the picture below.
She was traveling at a constant pace until a student rushes in front of her not using the sidewalks and crosswalks and she had to slam on her brakes. The mug will then move foward
Why will this happen to her coffee mug?
Answer:
When she stops at a fast pace the energy and wind will take the cup forward and it will most likeley brake
Explanation:
I'm not entirely sure this is what you were looking for but I hope this helped!
PLEASE MARK ME AS BRAINLIEST
An Atwood machine that consists of two blocks mass (m1,m2) tied together with a massless rope that passes over a fixed pulley.If m1=m2=m. Determine the acceleration of the block of mass m2. Suppose,m1→[infinity],while m2 remains finite.What value does the magnitude of the tension approach.
Answer:
a = 0 m/s²
T = 2m₂g
Explanation:
In this scenario of a pulley with two masses hanging vertically over it, the formula of acceleration is given as follows:
a = g(m₁ - m₂)/(m₁ + m₂)
It is given that: m₁ = m₂ = m
Therefore,
a = g(m - m)/(m + m)
a = g(0)/(2m)
a = 0 m/s²
The tension of the rope in such case is given by the following formula:
T = 2m₁m₂g/(m₁ + m₂)
It is given that: m₁ = ∞
Therefore,
T = 2(∞)m₂g/(∞ + m₂)
T = ∞(2m₂g)/∞(1 + m₂/∞)
T = 2m₂g/(1 + 0)
T = 2m₂g
which vector is the sum of the vectors shown below ?
Answer:
B
Explanation:
why can't a transformer operate on a DC signal
Answer:
Transformers do not allow DC input to flow through. This is known as DC isolation. This is because a change in current cannot be generated by DC
Explanation:
Hope this helps
Answer:
a change in current cannot be generated by DC;
What is the average speed of a car that travels 100 m over 10 s?
Answer: 10m per second.
Explanation: 100/10 is 10/1, so it would be 10m per second.
Six insulated containers hold 3,750 g of water at 24°C. A small copper cylinder is placed in each container; the masses and initial temperatures of the cylinders vary as given below. Rank the containers according to the maximum temperature of the water in each container after the cylinder is added, from largest to smallest. You may assume that the cylinder is completely submerged in the water.A. m = 250 g; T = 30°CB. m = 500 g; T = 60°CC. m = 750 g; T = 90°CD. m = 500 g; T = 15°CE. m = 750 g; T = 30°CF. m = 250 g; T = 60°C
Answer:
the order from highest to lowest is C> B> F> E> A> D
Explanation:
This is an exercise in calorimetry where the heat given off by the copper cylinder is equal to the heat absorbed by the water
Q_c = m_Cu ce_Cu ΔT_Cu
Q_a = m_water Ce_water ΔT
Q_c = Q_a
m_Cu ce_Cu (T_o-T_f) = m_water ce_water (T_f - T_i)
we clear the final temperature and substitute the values
With this expression we can know the final temperature of the system, let's substitute the values that are constant throughout the calculation
With this expression we can know the final temperature of the system, let's substitute the values that are constant throughout the calculation
a) m = 0.250kg, To = 30ºC
T_{fa}=(387 0.250 30 + 376740) / (15697.5 + 387 0.250)
T_{fa}= 379642.5 / 15794.25
T_{f} = 24.04ºC
b) m = 0.500 kg, To = 60ºC
T_{fb} = (387 0.500 60 + 376740) / (15697.5 + 387 0.500)
T_{fb} = 388350/15891
T_{fb = 24.44 ° C
c) m = 0.750 kg, To = 90ºC
T_{fc}= (387 0.750 90 + 376740) / (15697.5 + 387 0.750)
T_{fc}= 402862.5 / 15987.75
T_{fc} = 25.20ºC
d) m = 0.500 kg, To = 15ºC
T_{fd} = (387 0.500 15 + 376740) / (15679.5 + 387 0.500)
T_{fd} = 379642.5 / 15891
T_{fd} = 23.89ºC
the order from highest to lowest is C> B> F> E> A> D
Brain injuries can be caused by strong linear acceleration of the head. Imaging measurements of a human head upon impact show that the magnitude of displacement of the brain relative to the skull is, at most, approximately 1 mm, independent of the magnitude of the acceleration. Studies indicate that the probability of mild traumatic brain injury (MTBI) is approximately 25% for linear accelerations of the head of 50g, where g is the acceleration due to gravity (g = 9.8 m s 2 ). The probability of MTBI is ≈100% for linear accelerations of 150g. For this problem, model the case of a bicycle accident as a human head falling straight down from rest at a height of 2 meters. Assume the ground is very hard and does not compress upon impact. Also assume constant deceleration of the brain upon impact.(a) For the case when the cyclist is not wearing a helmet, what is the deceleration that the cyclist’s head undergoes upon contact with the ground? Express your answer in g’s. What is the probability of suffering a MTBI?(b) Suppose you want to design a helmet that reduces the probability of MTBI to less than 25%. By how much must the helmet compress after impact to achieve this goal for our model assumptions? Express your answer in cm. Do typical bicycle helmets provide this amount of compression?(c) Discuss ways in which our model (a human head falling straight down from rest at a height of approximately two meters onto an incompressible surface) could overor under-estimate the probability of MTBI in a bicycle accident.
Answer:
a) a = 2000 g , b) y = 4 cm
Explanation:
a) We can solve this part using the free fall relations
Let's start by finding the speed with which it reaches the ground, just before it starts to decelerate
v₁² = v₀² + 2 g y
as it comes out of rest the initial velocity is v₀ = 0
v₁ = √ 2g y
v₁ = √ (2 9.8 2)
v₁ = 6.26 m / s
in the braking part the distance is y₂ = 1 mm = 0.001 m
v² = v₁² - 2 a y₂
when stopping its velocity is zero v = 0
a = v₁² / 2y₂
a = 6.26² / (2 0.001)
a = 1.96 10⁴ m / s²
This is the braking acceleration.
Let's look for its relationship with the acceleration of gravity
a / g = 1.96 10⁴ / 9.8
a / g = 2000
a = 2000 g
b) to reduce the injury to less than 25%, the maximum acceleration that must be a = 50g = 490 m / s²
Let's find the distance it must travel to have this acceleration
v² = v₁² - 2 a y
y = (0 + v₁²) / 2a
y = 6.26² / (2 490)
y = 0.04 m
y = 4 cm
therefore we must have a helmet that deforms 4 cm before the head stops
Most bicycle helmets provide this protection since they are quite elongated
c) The main error in the calculations is not taking into account the
resistance with the air, in this sense the speed would be less than the calculated one and our calculations would be over estimated.
The second factor is that in a fall there may be an initial velocity different from zero, so the velocity would be higher and the acceleration as well, in this case our calculations are underestimated.
7. Explain Why is the
gravitational force that
a friend exerts on you less
than the gravitational force
exerted on you by Earth?
Explanation:
F=GMm/d^2
Distance between friends and us <<<<<Distance between centre of earth and us
A drone flies 8 m/s due East with respects to the wind. The wind is blowing 6 m/s due North with respects to the ground. What is the speed of the drone with repeat to the ground?
A. 14m/s
B. 10m/s
C. 2m/s
D. 20m/s
Answer:
B. 10m/s
Explanation:
If a drone flies 8 m/s due East with respects to the wind and the wind is blowing 6 m/s due North, the speed of the drone with respect to the ground is its displacement.
Displacement is calculated using Pythagoras theorem.
d² = 8²+6²
d² = 64+36
d² = 100
Square root both sides
√d² = √100
d = 10m/s
Hence the distance of the drone with respect to the ground is 10m/s
Option B is correct
The bonds of the products store 22 kJ more energy than the bonds of the
reactants. How is energy conserved during this reaction?
O A. The reaction system absorbs 22 kJ of energy from the
surroundings.
O B. The reaction creates 22 kJ of energy when bonds form.
O C. The surroundings absorb 22 kJ of energy from the reaction
system.
D. The reaction uses up 22 kJ of energy when bonds break.
Answer:A.
Explanation: The reaction system absorbs 22kJ of energy form the surroundings
Answer: The reaction system absorbs 22 kJ of energy from the
surroundings.
Explanation: I took the test.
When a moving object collides with an object that isn’t moving , what happens to the kinetic energy of each object?
Answer:
The moving object transfers kinetic energy with the object that isn't moving.
Explanation:
Kinetic energy is a form of energy that a object or particle has by the reason of motion. Potential energy is a form of energy that a object or particle has by the reason of no movement. The object that is moving knocks down or collides with an object that isn't moving, and the object that is moving transfers kinetic energy to potential energy, and the object that wasn't moving transfers potential energy to kinetic energy.
A cave diver enters a long underwater tunnel, when her displacement with respect to the entry point is 20m,she accidentally drops her camera but she doesn't notice it missing until she is some 6m farther into the tunnel.She swims back 10m but cannot find the camera,so she decides to end the dive.How far from the entry point is she?Taking the positive direction out of the tunnel,what is her displacement vector relative to the entry point?
Answer:
3x864/y488bjehdksuwiieirjr
5. How long does it take a car to cross a 30 m wide intersection after the light turns green after waiting at a traffic light, assuming the car accelerates at a constant 2.0 m.s2. Ignore the driver’s reaction time
Answer:
S = Vo t + 1/2 a t^2 = 1/2 a t^2 V0 = 0 for a standing start
t = (2 S / a)^1.2
t = (2 * 30 / (2.0) = (30)^1/2 = 5.5 sec