I really need help on this.
Earth's rotation is crucial to understanding the Coriolis effect. The Equator is where Earth rotates more quickly than the poles. There at Equator, Earth is larger.
Equatorial areas therefore move at a speed of around 1,600 km/h (1,000 mph) in a 24-hour period to complete a revolution. Earth rotates slowly towards to the poles, at 0.00008 km/h (0.00005 mi/h).
Low-pressure systems called cyclones draw air towards their "eye" or central region. Fluids representing high-pressure systems in the Northern Hemisphere pass low-pressure regions to the right.
Air masses are deflected when they're drawn inside cyclones from across all sides, giving the appearance that a hurricane is rotating clockwise. Trade winds refer to these air masses' recurrent circulation patterns.
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A net force of 500 newtons causes
an object to accelerate at a rate of
5.0 m/s2. What is the mass of the
object?
A - 100 kg
B - .20kg
C - 600 kg
D - 2500 kg
Answer:
The answer is option AExplanation:
To find the mass of an object given it's acceleration and the force acting on it we use the formula
[tex]mass = \frac{force}{acceleration} \\ [/tex]
From the question
force = 500 N
acceleration = 5.0 m/s²
We have
[tex]mass = \frac{500}{5} \\ [/tex]
We have the final answer as
100 kgHope this helps you
What happens when light hits a transparent material like water or glass? What is
the phenomenon called?
HELP
When two objects collide and stick together, what will happen to their speed, assuming momentum is conserved?
Answer:
They will move more slowly.
Explanation:
When the two objects stick together, they can be treated like one larger mass. By increasing mass, and keeping momentum the same, velocity must decrease (a larger object moves slower if all other variables stay the same) by p = mv.
Types of muscle tissue includes
Skeletal muscle
Cardiac muscle
Smooth muscle
All of the above
Answer:
D. all of the above
Explanation:
hope it helps
If this piece of abductin is 3.1 mm thick and has a cross-sectional area of 0.49 cm2 , how much potential energy does it store when compressed 1.5 mm ?
Complete question:
A scallop forces open its shell with an elastic material called abductin, whose Young's modulus is about 2.0×10⁶ N/m2 .
If this piece of abductin is 3.1 mm thick and has a cross-sectional area of 0.49 cm2 , how much potential energy does it store when compressed 1.5 mm ?
Answer:
The elastic potential energy of the material is 0.036 J
Explanation:
Given;
Young's modulus, E = 2.0×10⁶ N/m²
Thickness of the abductin, l = 3.1 mm = 0.0031 m
compression of the abductin, x = 1.5 mm = 0.0015 m
area, A = 0.49 cm² = 0.49 x 10⁻⁴ m²
Young's modulus for elastic material is given by;
[tex]E = \frac{stress}{strain} = \frac{Fl}{Ax} \\\\ E = \frac{F}{x}*\frac{l}{A}\\\\ E = k*\frac{l}{A}\\\\k = \frac{AE}{l}\\\\k = \frac{(0.49 x10^{-4})(2*10^6)}{0.0031}\\\\ k = 31,612.9 \ N/m[/tex]
The elastic potential energy of the material is given by;
U = ¹/₂kx²
U = ¹/₂(31,612.9)(0.0015)²
U = 0.036 J
Therefore, the elastic potential energy of the material is 0.036 J
Explain why a golf ball that is hit on the moon travels much farther than a golf ball that is hit with the same force on Earth.
Answer:
the reason why is that if it is hit with the same force the moon has a lot less gravity than the earth dose so the golf ball will hit the ground on earth first before the golf ball on moon dose
Dillon wants to go to the park to play basketball. To get to the park, he must travel 9 km East, and then 6 km South, then 9 Km West. Calculate the distance
Answer:
24 km
Explanation:
9 + 9 + 6 = 24
is it better to walk or run in the rain?
Answer:
Not gonna lie. I actually had to think about this a lot XD
Running in the rain can cause you to slip and get hurt. Which I think isn't what you would want.
Walking in the rain (although it is sad), is actually a better idea than running.
Hope this helps!
Answer:
Walk
Explanation:
Running might stop you from being outside for as long, but running on wet ground will most likely result in a not-so-graceful faceplant.
A 57 kg paratrooper falls through the air. How much force is pulling him down?
Answer:
Explanation:
Force = Mass * acceleration due to gravity.
Given
Mass of the paratrooper = 57kg
Acceleration due to gravity = 9.81m/s²
Required
Force pulling him down
Substitute unto formula;
F = 57 * 9.81
Force = 559.17 N
Hence the force pulling him down is 559.17N
The force pulling the paratrooper as he falls down is 558.6 N.
The given parameters;
mass of the paratrooper, m = 57 kgacceleration due to gravity, g = 9.8 m/s²The force pulling the paratrooper is force of gravity and the magnitude can be determined by applying Newton's second law of motion as shown below;
F = mg
F = 57 x 9.8
F = 558.6 N
Thus, the force pulling the paratrooper as he falls down is 558.6 N.
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For a balloon to rise in the air, the lifting force
must be greater than which force: Gravity,
Normal, or Friction?
Help please
Mark brainlist
Answer:
gravity
Explanation:
The word photokinetic means “moving in response to light”. Why does this make sense based on the two main parts (morphemes) in this word?
Explanation:
photo means light in latin
kinetic means to move
Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B.
Answer:
[tex]B=1.61\times 10^{-4}\ T[/tex]
Explanation:
The attached figure shows the path followed by an electron in the semicircular path from A to B.
Velocity of the electron is, [tex]v=1.42\times 10^6\ m/s[/tex]
It can be seen from the figure that the radius of thenpath, r = 5 cm or 0.05 m
The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,
[tex]Bqv=\dfrac{mv^2}{r}[/tex]
B is the magnitude of the magnetic field
[tex]B=\dfrac{mv}{rq}\\\\\text{Putting all the values}\\\\B=\dfrac{9.1\times 10^{-31}\times 1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}\\\\B=1.61\times 10^{-4}\ T[/tex]
So, the magnitude of the magnetic field is [tex]1.61\times 10^{-4}\ T[/tex].
The magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B will be [tex]B=1.61\times 10^-{4]\ T[/tex]
What is magnetic field?The magnetic field is defined as when the current passes through the wire, then the magnetic field is generated around the wire in a circular pattern.
The attached figure shows the path followed by an electron in the semicircular path from A to B.
The velocity of the electron is, [tex]v=1.42\times 10^6\ \frac{m}{s}[/tex]
It can be seen from the figure that the radius of then path, r = 5 cm or 0.05 m
The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,
[tex]Bqv=\dfrac{mv^2}{r}[/tex]
B is the magnitude of the magnetic field
[tex]B=\dfrac{mv}{rq}[/tex]
[tex]B=\dfrac{9.1\times 10^{-31}\times1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}[/tex]
[tex]B=1.61\times 10^{-4}\ T[/tex]
So, the magnitude of the magnetic field is [tex]B=1.61\times 10^-{4]\ T[/tex]
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True or false- Normally, all objects are electrically positively charged
The fuel is ignited in a model rocket sitting on a launch pad, which blasts the rocket upward. The rocket goes up because: Group of answer choices air friction pushes on the escaping fuel. the downward force of gravity is less than the downward momentum of the fuel. None of the above. the fuel pushes on the launch pad. the downward force of gravity is greater than the downward momentum of the fuel.
Answer: The fuel pushes on the launch pad.
Explanation: This is a case of Newton's Third Law of Motion which states for every action in nature, there is an opposite and equal reaction.
Inside the rocket, the fuel is combusted creating a force that exerts on the launch pad by pushing it. As a reaction, the pad pushes the rocket upward, allowing it to go up. This is an example of Newton's Third Law of motion.
Why is the sunlight not deflected when passes through either an electric field or a magnetic field?
Question 11(Multiple Choice Worth 3 points)
(01.01 LC)
Which of the following actions will decrease the gravitational force between two objects?
o
Increasing the mass of the objects
d
Increasing the density of the objects
O
Increasing the distiyance between the objects
Increasing the temperature of the objects
Answer:
Explanation:
The only thing that decreases the gravitational pull between 2 objects is if you increase the distance.
The formula is F = G*m*m/r^2
As r^2 gets larger and G and m1 and m2 remain the same, F has to get smaller because r^2 divides into G*m1*m2
Doctors were furious. Their patients didn't care about regular medicine anymore. All they wanted was a wave of Dr. Mesmer's wand. The doctors griped — and groused — and fussed — and fumed. What is most likely the meaning of the word furious?
A quietly curious B quite thrilled C mildly annoyed D extremely angry
Answer:
am pretty sure the answer is d
Which of the following represents an example of thermal energy?
O a
Saxophone
Ob
Oven
с
Powerlines
Od
Windmill
Answer:
The answer of this question is windmill
Two forces are described below:
Force 1: The squeezing force applied to remove water from a wet cloth
Force 2: The gravitational force exerted by Earth on the moon
Which statement is true about the forces? (3 points)
Both are contact forces.
Both are non-contact forces.
Force 1 is a non-contact force and Force 2 is a contact force.
Force 1 is a contact force and Force 2 is a non-contact force.
Answer:
its Force 1 is a contact force and Force 2 is a non-contact force.
Explanation:
I took the test!
Answer:
Force 1 is a contact force, Force 2 is a non-contact force :)
Explanation:
Because Force 1 is an object touching something and Force 2 is a force that is not touching something (hope this helps)
A
A penny is dropped from the top of a 200 m building and is in free fall. How long will it take
the penny to hit the ground?
Answer:
The penny will hit the ground at 6.39 seconds
Explanation:
Free Fall
The penny is dropped from a height of y=200 m. The equation of the height on a free-fall motion is given by:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
Where [tex]g=9.8\ m/s^2[/tex], and t is the time.
Solving for t:
[tex]\displaystyle t=\sqrt{\frac{2y}{g}}[/tex]
Using the value y=200:
[tex]\displaystyle t=\sqrt{\frac{2*200}{9.8}}[/tex]
t=6.39 sec
The penny will hit the ground at 6.39 seconds
Please help I don’t know how to do this
Answer:
3.176 hoursExplanation:
given:
distance = 270 km
speed = 85 km/h
find:
how long does it take to get into his audition in hours?
solution:
velocity = distance / time
85 km/h = 270 km
t
85 (t) = 270
t = 270 / 85
t = 3.176 hours
If you walk North for 40 feet and then walk East for 30 feet, what is your total distance
travelled? What is your displacement?
Answer:
The person travelled a total distance of (40+30) feet = 70 feet
Displacement= 50feet (im not positive on the displancement)
displacemeny is the shortest distance between two pionts
Explanation:
If a drag racing car accelerated at 69 miles per second in 0.25 s, what is the acceleration of the car
Answer:
acceleration is : 276 mi/s^2
(276 miles per second squared)
Explanation:
We use the formula for acceleration (a) which is the change in velocity divided by the time it took to change it:
a = (vf - vi) / t
where "vf" stands for final velocity, "vi" for initial velocity, and "t" for the time it took for the velocity to change.
In our case:
a = (69 - 0) / 0.25 = 276 mi/s^2
(276 miles per second squared)
If the length of an ax is 20 cm and the width is 5 cm what is the MA of a knife?
O 2
0 4
O 10
O6
Answer:
4
Explanation:
From the question given above, the following data were obtained from:
Length of an axe = 20 cm
Width = 5 cm
Mechanical advantage (MA) =.?
The mechanica advantage is simply defined as the ratio of the length to the width of the axe. Mathematically, it is expressed as:
Mechanical advantage = length /width
With the above formula, we can obtain the mechanical advantage of the axe as follow:
Length of an axe = 20 cm
Width = 5 cm
Mechanical advantage (MA) =.?
MA = 20/5
MA = 4
Therefore, the mechanical advantage (MA) of the axe is 4
Give reasons.
A stone thrown upward returns back to the earth surface.
Answer:
Gravity
Explanation:
Due to earths gravity, anything that goes into the air returns back to the surface unless it is given the ability to fly.
Hope this helps!
Which of the following is the primary force that shapes the Earth's landscape?
Which is the correct answer? Please help.
Answer:
i believe it is c
Explanation:
hope this helps and plz mark brainliest
A source of sound produce waves in air of wavelength 3.42m . If the speed of sound in air is 330m/s, What is the period of vibration?
Explanation:
wavelength=3.42m
velocity=330m/s
T=?
v=f×wavelength
f=330÷3.42
f=96.5Hz
T=1/f
=1/96.5
T=0.01s
A child (mass Me) pulls a sled (mass Ms) holding a baby (mass m) across the snow (assume the snow is frictionless). When the child starts the sled moving the baby brother slips off the sled instead of moving with the sled. The child tries again with a slightly smaller force and the baby stays on the sled due to the friction between the baby and the sled. Write a symbolic solution for the coefficient offriction between the baby and the sled if the maximum acceleration ofthe sled for the baby to stay on the sled is a. The solution may include the variables MC: Ms, m: a and g but does not need to have all ofthem_ The computer Ivill not recognize any other variables. Do not include any numbers (or the in your answer). Fill in the blank
Answer:
symbolic solution for the coefficient of friction between the baby and the sled is
[tex] \mu = \frac{m + M_s}{m} * \frac{a}{g}[/tex]
Explanation:
From the question we are told that
The mass of the boy is [tex]M_e =[/tex]
The mass of the shed is [tex]M_s[/tex]
The mass of the baby is [tex]m[/tex]
The maximum acceleration for the baby to stay is a
Generally the frictional force between the baby and the shed is mathematically represented as
[tex]F_f = \mu N[/tex]
Here N is the normal force acting on the baby which is mathematically represented as
[tex]N = m * g[/tex]
=> [tex]F_f = \mu * m * g[/tex]
Now for the baby not the slip off the shed the frictional force between the baby and the shed must be equal to the the force applied by the child
The force applied by the child is mathematically represented as
[tex]F = [M_s+m] * a[/tex]
So
[tex] \mu * m * g = [M_s+m] * a[/tex]
=> [tex] \mu = \frac{m + M_s}{m} * \frac{a}{g}[/tex]