Answer:
Approximately [tex]7.1 \times 10^{3}\; {\rm J}[/tex] (given: [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].)
Explanation:
To find the change in the gravitational potential energy ([tex]\text{GPE}[/tex]), use the formula:
[tex]\begin{aligned}& (\text{change in GPE}) \\ &= (\text{mass})\, (g)\, (\text{change in height})\end{aligned}[/tex].
Assume that gravitational field strength [tex]g[/tex] is constant (e.g., [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].) For an object of mass [tex]m[/tex], if the altitude of the object changes by [tex]\Delta h[/tex], the [tex]\text{GPE}[/tex] of that object would change by [tex]m\, g\, \Delta h[/tex].
In this question, the mass of Ben is [tex]m = 63.2\; {\rm kg}[/tex]. It is given that [tex]g = 9.8\; {\rm m\cdot s^{-2}} = 9.8\; {\rm N\cdot kg^{-1}}[/tex] and is constant. Since change in the altitude of Ben is [tex]\Delta h = 11.5\; {\rm m}[/tex], the change in the ([tex]\text{GPE}[/tex]) of Ben would be:
[tex]\begin{aligned} m\, g\, \Delta h &= (63.2\; {\rm kg}) \, (9.8\; {\rm N\cdot kg^{-1}})\, (11.5\; {\rm m}) \\ &\approx 7.1\times 10^{3}\; {\rm N\cdot m} = 7.1\times 10^{3}\; {\rm J} \end{aligned}[/tex].
What does a step-down transformer change in an alternating current?
Answer: A step-down transformer changes the magnitude of the voltage in an alternating current (AC) electrical signal. It reduces the voltage of the AC signal by using a winding ratio between the primary (input) and secondary (output) coils that is less than 1:1.
Explanation: For example, if the winding ratio of a step-down transformer is 1:0.5, the output voltage of the secondary coil will be half the magnitude of the input voltage of the primary coil. In this case, the transformer would change the AC voltage from a higher value to a lower value.
The transformer does not change the frequency of the AC signal, which is determined by the source of the electrical power. The transformer also does not change the waveform of the AC signal, which is typically a sinusoidal wave.
A force of 7.36 N acts on a(n) 2.1 kg object for 24.7 s. What is the object’s change in momentum? What is its change in velocity? Answer in units of N · s
Based on the data given:
the change in momentum of the object is 181.8 N.sthe change in velocity, Δv = 86.6 m/sWhat is the change in the momentum of a body?
The change in momentum of the object equals the impulse experienced by the object
Mathematically,
Impulse = change in momentum
Impulse = F • t
change in momentum = m • Δ v
F • t = m • Δ v
where
F is the force
t is the time the force acts
m is the mass of the object
Δv is the change in velocity
For the given values:
change in momentum of the object = 7.36 * 24.7
change in momentum = 181.8 N.s
Change in velocity, Δv = change in momentum / mass
Change in velocity, Δv = 181.8 / 2.1
Change in velocity, Δv = 86.6 m/s
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At what separation will two charges, each of magnitude 6.0 μC, exert a force of 0.70 N on each other?
At separation of 1470 meters, the two charges exert a force of 0.70 N on each other.
What is electric force?Electric force is the interaction between any two charged objects that can be either attractive or repelling. Newton's rules of motion, which apply to all forces, explain how each one affects the target body and how it does so. The electric force is one of the many forces that operate on objects.
We know that electric force can be mathematically defined as:
F = kQq/r²
0.70 = 9.0 × 10⁹ × (6.0×10⁻⁹)²/r²
r = 1.47 meter.
Hence, the separation between two charges is 1.47 meters.
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This theory of motivation focuses on finding the right level of stimulation. An organism tries to find behaviors that actually increase arousal because everything else bores them.
*
2 points
Cognitive Theory
Hierarchy of Needs
Drive-Reduction Model
Optimal Arousal Theory
Optimal Arousal theory focuses on finding the right level of stimulation.
What is Optimal Arousal theory?William James (1842–1910), frequently referred to as the father of psychology in the United States, made significant contributions to early studies on motivation.
James proposed a number of instincts that help with survival as the driving forces behind conduct . An instinct is a species-specific pattern of behavior that is not taught, according to biology.
But there was a lot of disagreement over what exactly constitutes instinct among James's contemporaries. James postulated a number of unique human instincts, although many of his contemporaries had different lists.
Therefore, Optimal Arousal theory focuses on finding the right level of stimulation.
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An object with a weigh of 170 N on Earth is brought to planet Oobla. Where it has a weight of 360 N. What is the gravitational field strength on Oobla
The gravitational field strength on Oobla is 20.75 m/s².
What is gravitational field strength?The gravitational field is the gravitational force exerted per unit mass on a small mass at a point in the field.
To calculate the gravitational field strength on Ooobla, we use the formula below
Formula:
W/g = W'/g'................. Equation 1Where:
W = Weight of the object on Earthg = Gravitational field strength on the Earthg' = Gravitational field strength on the OoblaW' = Weight of the object on OoblaFrom the question,
Given;
W = 170 Ng = 9.8 m/s²W' = 360 NSubstitute these values into equation 1 and solve for g'
170/9.8 = 360/g'g' = 360×9.8/170g' = 20.75 m/s²Hence, the gravitational field strength is 20.75 m/s².
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Rank the images showing the highest electric potential 1 energy to the lowest electric potential energy 4.
Answer:
3rd image, 2nd image, 1st image, 4th image
Explanation:
Not an easy question, tricky one
Electric potential energy is proportional to the magnitude of the charges (the higher the charges, the stronger the Electric potential energy(EPE)) and inversely proportional to the distance between the charges(the longer the distance, the smaller the EPE). U = kQq/r
EPE is positive in this case due to unlike charges.
Between distance and magnitude of the charges, magnitude of charges play a more significant effect than distance (due to Qq , both the magnitude of Q and q affect the EPE)
Hence. zoom in on the magnitude first.
3rd image has the largest + and -, hence greatest magnitude of charges, therefore highest EPE.
Between 1st and 2nd images, charges have the same magnitude, distance now comes to play. Distance between the charges is smaller for image 2 and the charges experience greater EPE. 1st image, the charges are further, hence smaller EPE.
For the fourth image, the magnitude of the charges is the smallest, hence smallest EPE.
Equilibrium exists in a system where three forces are acting concurrently on an object. If the system includes a 5.0-newton force due north and a 2.0-newton force due south, the third force must be?
The third force must be 3.0 newtons due north in order for equilibrium to exist in the system.
Why should equilibrium exist in system?This is so because the total of all the forces acting on the object equals the net force acting on it. The net force in this situation is 3.0 newtons due north and is calculated by subtracting the 5.0 newton force due north from the 2.0 newton force due south.In equilibrium, the net force on an object is zero.A chemical reaction is said to be in a state of north equilibrium when the reactant and product concentrations remain stable throughout time. The concentrations of the reactants and products stay unchanged, and the rate of the forward reaction is equal to the rate of the reverse reaction.To know more about equilibrium, check out :
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a boy of 40kg and a girl of a mass an unknown mass plays on a seesaw of negligible weigh. If the boy sits 300cm from the pivot and the girl sits 400m from the pivot what is the mass of the girl in order for the seesaw to be in equilibrium
The mass of the girl is 30 kg in order for the seesaw to be in equilibrium.
What is seesaw?A particular kind of lever is a seesaw, which has a long beam coupled to a pivot known as the fulcrum.
As soon as you sit on one side of the beam and apply weight on one end, the beam falls to the ground. This is because the weight of your body is being pulled down by the force of gravity, along with the beam.
Let the mass of the girl = m kg
In equilibrium;
40 kg × 300 cm = m × 400 cm
⇒ m = 30 kg.
Hence, the mass of the girl is 30 kg.
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A 500-mm-long, 16-mm-diameter rod made of a homogenous,
isotropic material is observed to increase in length by 300 mm, and
to decrease in diameter by 2.4 mm when subjected to an axial 12-
kN load. Determine the modulus of elasticity and Poisson's ratio of
the material. [20 marks]
The material has a Poisson's ratio and a modulus of elasticity of 0.25. Y=2G(1+) is the correct relationship between the Young's modulus (Y), the shear modulus (G), and the Poisson's ratio ().
What are elastic modulus and Poisson's ratio?The bulk modulus, also known as the elastic modulus K, is related to the Poisson's ratio; G as the modulus of shear; and E, Young's modulus, by the following (for isotropic solids whose properties are non-directional). The stiffness is measured by the elastic moduli. They are stress-to-strain ratios.
Determine the rod's stress level.
Determine the longitudinal strain by multiplying F A 12 by (0.016) = 59.683 MPa.
Determine the lateral strain by elongating Or 30010-3 = L mm 500 mm = = 0.0006.
-2.410-3 mm 16 mm Elateral = = -0.00015 d Determine the material's young's modulus.
& Long 59.683 MPa 0.0006 E = 99.471 GPa 100 GPa
Determine the material's poisson's ratio. & the lateral lengthens by -0.00015 0.0006 = 0.25.
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Write words with a similar meaning to the given words for old, stubble and room help me?pls
Answer:
Old = senior. geriatric. senescent. unyoung. over-the-hill.
Stubble= bristles
whiskersdesigner stubblehairfacial hairbeardfive o'clock shadowFeedbackHelen is para sailing. She sits in a seat harness which is attached by a tow rope toba speedboat. The rope makes an angle of 59.9* with the horziontal and has a tension of 364N. Determine the horziontal and vertical component of the tension force
To find the horizontal and vertical components of the tension force in para sailing, we can use the basic trigonometric ratios of sine, cosine and tangent.
How to use trigonometric ratios ?First, given the rope's angle (59.9 degrees) and the tension force (364 N), we can apply the following formula to determine the tension force's horizontal component (Fx): Fx = Tension force x cos(angle) = 364 N x cos (59.9).Next, we can use the angle of the rope and the tension force to find the vertical component (Fy) of the tension force using the formula: Fy = Tension force x sin(angle) = 364 N x sin(59.9)You must convert the angle to radians because these calculations, as you should be aware, employ radians rather than degrees.As a result, the tension force's horizontal component has the following formula: Fx = 364N x cos(59.9) = 225.98N roughly.Additionally, the vertical component of the tension force is roughly 318.6N, or Fy = 364N x sin(59.9)According to these calculations, the tension force has two components: a horizontal component that is 225.98 N and a vertical component that is 318 N.To know more about trigonometric ratios , check out :
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The sum of the x components of vectors A and B in (Figure 1 ) is
-5
4
14
6
Vectors A and B are shown in a tip to tail arrangement. Vector A begins at the origin (0,0) and ends at the x y coordinate (9,3). Vector B begins at the tip of vector A and ends at the x y coordinate (4,6).
The resultant (x,y) coordinate of vector B is (- 5, 3) and that of A is (9,3). Then, the sum of x components of vector A and B is 4.
What are vectors ?Vectors are physical quantities having both magnitude and direction. For example force, velocity, displacement etc .are vector quantities. Coordinates are used to describe the position of these vectors.
The coordinates of tail of the vector A is (0, 0) and the head is (9,3)
Then the coordinate of A is (9 -0, 3-0) = (9,3)
Similarly, the tail coordinate of B is (9,3) and head is (4,6). The coordinates of B vector is (4-9, 6-3) = (-5, 3)
Now the sum of x components of A and B is = - 5 + 9 = 4.
Therefore, option b is correct.
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A 25 kg box of roofing shingles is lifted 15 meters vertically to the top of a roof. How much work is done on the box?
Important Formulas:
[tex]F=ma[/tex]
force(measured in newtons) = mass(measured in kg) * acceleration(measured in m/s^2)
[tex]w=Fd[/tex]
work(measured in joules) = force(measured in newtons) * distance(measured in meters)
__________________________________________________________
Given:
[tex]m=25kg[/tex]
[tex]d=15m[/tex]
[tex]w=?[/tex]
We know that the acceleration due to gravity is 9.8 m/s^2.
__________________________________________________________
Finding force:
[tex]F=ma[/tex]
[tex]F=25\times9.8[/tex]
[tex]F=245N[/tex]
__________________________________________________________
Finding work:
[tex]w=Fd[/tex]
[tex]w=245\times15[/tex]
__________________________________________________________
[tex]\fbox{w = 3675 Joules}[/tex]
A force of 50N applied to the end of a lever moves that end a certain distance if the other end of the lever is moved half as far how much force does it exert?
The force exerted at other end is 100N.
Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.Mathematically, the above statement is expressed as follows:W = (F cos θ) d = F. d
Where,
W is the work done by the force.
F is the force, d is the displacement caused by force
θ is the angle between the force vector and the displacement vector
Let , F' = Force exerted on ladder at other end
d' = distance moved = d/2 (given)
i.e. W = F'd' and W = Fd
Using these two equations we get, F'd' = Fd
i.e. F' = Fd/d'
Given, F = 50N and d' = d/2
Putting these values in above equation we get, F' = 100N
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A 62.3 kg base runner begins his slide into second base while moving at a speed of 4.49 m/s. He slides so that his speed is zero just as he reaches the base. The acceleration of gravity is 9.8 m/s². What is the magnitude of the mechanical energy lost due to friction acting on the run- ner?
Answer:
628 J
Explanation:
ME = PE + KE
PE = mgh = 0, because h = 0
KEi (initial KE) = 1/2mv² = 1/2(62.3 kg)(4.49 m/s)² = 628 J
KEf (final KE) = 0, because v-final = 0
All the initial ME, which is all KE, converts to thermal E due to friction
A iguana runs back and forth along the ground. The horizontal position of the iguana in meters over time is shown
What is the displacement of the iguana between 3 s and 6 s?
m
What is the distance traveled by the iguana between 3 s and 6 s?
The displacement of the iguana between 3 s and 6 s is 6.71 meters.
The distance traveled by the iguana between 3 s and 6 s is 8.08 meters.
What are distance and displacement?Distance is the sum of an object's movements, regardless of direction.
The term "displacement" refers to a shift in an object's position.
According to the graph:
The displacement of the iguana between 3 s and 6 s
= √{ (3-6)²+(6-0)²} meters
= 6.71 meters.
The distance traveled by the iguana between 3 s and 6 s
= [ √{ (3-5)²+(6-6)²} +√{ (5-6)²+(6-0)²}] meters
= [2+ 6.08] meters
= 8.08 meters.
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convert 22.0m/s² to km/min²
22.0m/s² is equal to 78.98 km/min². Since 1 m/s² = 3.59 km/m². If we multiply 22 by this number, we get the accurate answer, according to the conversion table.
What is the acceleration unit in the SI?Acceleration is measured in meters per second2 (m/s2). Newton's Second Law, which states that "The acceleration of an object is exactly proportional to the net force acting on it and inversely proportionate to its mass," connects force (F), mass (m), and acceleration (g).
The SI unit is what?The Système International unit, or SI unit, is an acronym for the French phrase for system international. The metric system that serves as the industry standard for measurements is called the International System of Units (SI). In the advancement of science and technology, SI units are essential.
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what is the atmosphere pressure on earth will support a column of mercury about 760 mm high, since the atmosphere pressure on the surface of the planet venus is 9200 kpa (1330 pal) , about 91 times that of earth about how tall a mercury column could venus’s atmosphere support ?
The atmospheric pressure on earth is 1 atm. This pressure is equivalent to the mercuric pressure of 760 mmHg. The atmospheric pressure on the surface of Venus is 9200 kpa which is equivalent to 69017 mmHg.
What is atmospheric pressure?Pressure is the force acting per unit area. In the atmosphere, the gaseous particles and dust exerts a pressure in the atmosphere. The atmospheric pressure depends on the temperature.
There are various units for pressure. Normally the atmospheric pressure is expressed in atm unit. The mmHg pressure is based on the raise in mercuric level with respect to increase in pressure.
1 mmHg = 0.0013133 atm
hence, 760 mmHg = 1 atm
On the surface of Venus, the pressure is 9200 kilopascal.
1 mmHg = 0.133 KPa
then 9200 KPa = 9200/0.133 = 69017 mmHg pressure.
Therefore, height of mercuric column will be 69017 mm in Venus surface.
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A jug containing water at 26° C while another contains water at 82°C,if a patient wish to bath with water 40°C , the ratio of the mass of hot water to that of cold water is_
Answer:2:7
Explanation:
Quantity of heat energy before mixing= Quantity of heat energy after mixing
M1. S1.T1+ M2.S2.T2= M.S3.T3
Let, .
M1 = mass of cold water
M2 = mass of hot water
S1=S2=S3=S
M=M1+M2
T1=28,T2=82,T3= 40
M1.28 + M2.82= (M1+M2)40
M1.28 + M2.82= M1 40+M2.40
M2.82 -M2.40= M2.40–M1.28
M2.42= M1. 12
M2/M1= 12/42= 2/7
Or
M2: M1= 2:7
A hairdryer has a power of 1000W and was used for half an hour, how much did it cost with the energy price being 14p/kWh?
Answer:
12hp and 132 ml
Explanation:
12+ 132.00=12asd
A rock is thrown horizontally of a bridge at 8.00 m/s. It hits the water's surface below 3.4 seconds later. How high is the bridge? How far from the bridge does it hit the water?
I was provided with the equations:
x= v * t and y= (Vi * t)1/2 * a * t^2
Answer:
56.7m
Explanation:
horizontal velocity does not matter in this situation because it stays constant (no unbalanced force acting upon it)
a=9.81m/s^2
t=3.4s
Vi=0m/s
d=Vi*t+1/2at^2
d=1/2at^2
d=1/2*9.81m/s^2*(3.4s)^2
d=4.905m/s^2*11.56s^2
d=56.7m
a) What is the magnitude of the force F⃗ on the −10 nC charge in (Figure 1)? Express your answer using two significant figures.
b) What is the direction of the force F⃗ on the −10 nC charge in (Figure 1)? Give your answer as an angle measured cw or ccw (specify which) from the +x-axis. Express your answer in degrees. Enter a positive value if the angle is counterclockwise and negative value if the angle is clockwise.
a) The magnitude of the force F on the −10 nC charge is 0.00134 Newton.
b) The direction of the force F on the −10 nC charge is 41.99° with horizontal line.
What is electric force?Electric force is the attractive or repulsive interaction between any two charged things.
a) the magnitude of the force F on the −10 nC charge = √{k (q₁Q/r₁²)²+(q₂Q/r₂²)²}
= kQ √( (q₁/r₁²)²+ (q₂/r₂²)²}
= 9×10⁹×10×10⁻⁹ √{ (1×10⁻⁹/(0.01)²)² +(10×10⁻⁹/(0.03)²)² }
= 0.00134 Newton.
b) the direction of the force F on the −10 nC charge
= tan⁻¹( (1×10⁻⁹/(0.01)²) ÷(10×10⁻⁹/(0.03)²) )
= 41.99°
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Please give me the answer to this question
There is not enough information to determine the work done. Option iv
What is the work done?Let us note that we say that there is work done when the force that has been applied moves a distance in the direction of the force. In this case, we have been told that there is the combination of the works that is done by the object.
Now, we also have to note that we do not have other information to determine the work done such as the magnetic feild and the mass of the electron. All these are lacking in the question.
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A man drags a 10.0 kg bag of mulch at a constant speed applying a 22.5 N force at a 32-degree angle. What is the friction force acting on the bag?
The
friction
force acting on the bag is 4.36µ.
What is friction force?
The
force
preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction.
Given,
Force =F=22.5 n
Mass=m= 10 kg
mu=µ=?
(1N= 1kg m/s²)
Gravitational force =g= 9.81 m/s²
As we know,
F= µ*m*g
µ= m*g/F
= 10*9.81/ 22.5
µ= 4.36 .
Therefore, the friction force acting on the bag is 4.36.
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The bag is subject to a friction force of 4.36. A man applies a 22.5 N force at a 32° angle while dragging a 10.0 kilogram bag of mulch at a steady speed.
How much friction is there?Friction refers to the force that resists hard surface, fluid layering, and materials ingredients from gliding past one another. Friction lessens a machine's mechanical advantage, or, to put it another way, friction decreases the output to input ratio.
Force = 22.5 N
Mass = 10 kg
⇒ mu = µ (1N= 1kg m/s²)
⇒ g = 9.81 m/s²
As we know, F= µ × m × g
⇒ µ = (m × g)/F
⇒ (10 × 9.81)/ 22.5
⇒ µ = 4.36 .
Therefore, the friction force acting on the bag is 4.36.
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This theory of motivation focuses on finding the right level of stimulation. An organism tries to find behaviors that actually increase arousal because everything else bores them.
*
2 points
Cognitive Theory
Hierarchy of Needs
Drive-Reduction Model
Optimal Arousal Theory
Optimal Arousal theory focuses on finding the right level of stimulation.
What is Optimal Arousal theory?William James (1842–1910), frequently referred to as the father of psychology in the United States, made significant contributions to early studies on motivation.
James proposed a number of instincts that help with survival as the driving forces behind conduct . An instinct is a species-specific pattern of behavior that is not taught, according to biology.
But there was a lot of disagreement over what exactly constitutes instinct among James's contemporaries. James postulated a number of unique human instincts, although many of his contemporaries had different lists.
Therefore, Optimal Arousal theory focuses on finding the right level of stimulation.
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The monster wants to make himself known to the family in the cottage in chapters 9-12 of Frankenstein. He decides he can't do that until he masters something. What skill
must he master?
A. How to dress properly
B. Language
C. The rules of etiquette
D. Music
Answer:
c
Explanation:
While skiing in Jackson, Wyoming, your friend Ben (of mass 63.2 kg) started his de- scent down the bunny run, 11.5 m above the bottom of the run. If he started at rest and converted all of his gravitational potential energy into kinetic energy, what is Ben's kinetic energy at the bottom of the bunny run? Use g = 9.8 m/s² Answer in units of J.- answer :7100J part 2 of 2 What is his final velocity? Answer in units of m/s.
Answer:
12.3 m/s
Explanation:
To calculate the final velocity of Ben, we can use the equation KE = 1/2mv^2, where KE is the kinetic energy and m is the mass of Ben. Inserting the given values, we get:
7100 = 1/2 (63.2 kg) v^2
Therefore, v^2 = 7100/31.6
v = √(7100/31.6)
v = 12.3 m/s
A horse trots past you and then a fencepost that is 36m away from you. It takes the horse 11.0 sec to make this trot. What is the average velocity of the horse?
As the horse trots a fencepost that is 36m away from you in 11.0 second, the average velocity of the horse is 3.27 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
A horse trots past you and then a fencepost that is 36m away from you.
Time taken to make this trot = 11.0 second.
Hence, the average velocity of the horse is = total distance travelled/time interval
= 36/11.0 m/s
= 3.27 m/s.
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8. If the m<5 is 63°, find the
measure of <3.
The statement indicates that angle 3 seems to have a 117 degree measurement.
Short answer: What is measure?Compare of an untold amount with a fixed quantity that is known or A attribute of an item or event is measured when a number is assigned to it so that it may be compared to other things or occurrences.
Briefing:An angle is the figure produced by two photons that must intersect at a shared terminal in geometry. The symbol should indicate an angle.
The sum of the two degrees is 180 degrees but since radius 5 is 63 degrees.
Angle 3 is therefore = 180 - 63 = 117 degrees.
Consequently, angle 3 has a measure of 117 degrees.
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2. How much work is done in lifting 214kg from the floor to a shelf at a height of 6m?
Answer:
12583.2 J or 12.5832 KJ
Explanation:
Work done can be expressed as force multiplied by displacement, or
W = Fs
In this case, we can calculate the force by using F = mg.
m is the mass, 214 kg, and g is gravitational acceleration, which is 9.8 m/s/s.
So, we Calculate 214 * 9.8 to get 2097.2
The displacement is 6m.
So, by doing W = Fs, we get
2097.2 * 6 = 12583.2 Joules