Answer:
The amount is [tex]x = 113.3 \ dollars[/tex]
Explanation:
From the question we are told that
The distance traveled per day is [tex]l = 109\ km = \frac{109}{1.609} = 67.74 \ mi[/tex]
The cost of one liter is [tex]c = 1.10 \ euros/liter = 1.10 * 1.26 = 1.36 \ dollars/liter[/tex]
The car's gas mileage is [tex]b = 22.0 \ mi/gal[/tex]
Generally the amount of distance covered in one week is evaluated as
[tex]z = 67.74 * 7[/tex]
[tex]z = 474.18 \ mi[/tex]
The amount of gas used in one week by the car is mathematically represented as
[tex]k = \frac{ z}{ b}[/tex]
=> [tex]k = \frac{ 474.18}{ 22}[/tex]
=> [tex]k = 22 \ gal[/tex]
converting to liters
[tex]k = 22 * 3.78541=83.28 \ liters[/tex]
Thus the amount spent on gas in one week is
[tex]x = k * c[/tex]
=> [tex]x = 83.28 * 1.36[/tex]
=> [tex]x = 113.3 \ dollars[/tex]
Which state in each of the following pairs has the higher entropy per mole of substance?
1. Ice at - 40 degrees C or ice at 0 degrees C.
2. N2 at STP or N2 at 0 degrees C and 10 atm.
3. N2 at STP or N2 at 0 degrees C in a volume of 50 L.
4. Water vapor at 150 degrees C and 1 atm or water vapor at 100 degrees C and 2 atm.
Answer:
1. Ice at 0 degrees C.
2. N₂ at STP.
3. N₂ at STP.
4. Water vapor at 150 degrees C and 1 atm.
Explanation:
First, we need to remember that entropy (S) is a measure of how spread out or dispersed the energy of a system is among the different possible ways that system can contain energy. The greater the dispersal, the greater is the entropy.
When the temperature is increased, the energies associated with all types of molecular motion increase. Consequently, the entropy of a system always increases with increasing temperature.
With this in mind, we consider the pairs:
1. Since the ice at 0ºC has a greater temperature than the ice at -40 ºC, the first has the higher entropy.
2. The N₂ at STP (that is, 1 atm and 25 ºC) has higher entropy than N₂ at 0ºC and 10 atm because it has a higher temperature and less pressure, which allows a greater dispersal of energy by the molecules of the gas.
3. The N₂ at STP has a higher entropy since it has a higher temperature than N₂ at 0ºC, even though it the first has a lower volume (24,4 L vs. 50 L).
4. The water vapor at 150 ºC and 1 atm have a higher temperature and a lower pressure. This means that its molecules will have an increased molecular motion than the molecules of water vapor at a lower temperature and higher pressure. Therefore, the first has the highest entropy.
5. When ortho-bromonitrobenzene is treated with NaOH at elevated temperature, only one product is formed. (a) Draw the product. (b) Identify the intermediate formed en route to the product. (c) Would the reaction occur if the starting compound were meta-bromonitrobenzene
Answer:
The product formed is orthonitrophenol
Explanation:
The compound orthonitrophenol is formed when ortho-bromonitrobenzene is treated with NaOH at elevated temperature.
The reaction leads to the formation of an intermediate stabilized by resonance. This intermediate can not be formed by the meta isomer because a resonance stabilized intermediate can not be formed and the product is not stabilized by intramolecular hydrogen bonding hence this reaction will not occur.
Place the following elements in order of increasing electronegativity.K Cs PA. K < P < CsB. P < Cs < KC. Cs < K < PD. P < K < CsE. Cs < P < K
Answer:
C. Cs < K < P
Explanation:
Electronegativity is the basically the tendency of an atom to attract electrons. The pauling scale is used to quantify electronegativity, the most electronegative element; fluorine has a value of 4.0 and francium, the least electronegative element has a value of 0.7
The electronegative values of the following elements are given as;
K = 0.82
Cs =0.79
P = 2.19
Arranging in order of increasing electronegativity, we have;
Cs < K < P. The correct option is;
C. Cs < K < P
Which one of the following items does NOT characterize a reducing agent? a. A reducing agent loses electrons. b. A reducing agent causes another species to be reduced. c. The oxidation number of a reducing agent increases. d. A good reducing agent is a metal in a high oxidation state, such as Mn7+.
Answer: D
Explanation:
A reducing agent is a species that reduces other compounds, and is thereby oxidized. The whole compound becomes the reducing agent. In other words, of a compound is oxidized, then they are the reducing agent. On the other hand, if the compound is reduced, it is an ozidizing agent.
Since we have established that a reducing agent is the compound being oxidized, we know that A is not our answer. An oxidized compound is losing electrons. Choice A states exactly this.
For B, this is true as we have established this already.
C is also correct. Since a reducing agent loses electrons, it becomes more positive. This makes the oxidation number increase.
D would be our correct answer. It is actually a good oxidizing agent is a metal in a high oxidation state, such as Mn⁷⁺.
Bond energy of amphetamine?
Answer:
Amphetamine | C9H13N | CID 3007 - structure, chemical names, physical and chemical properties , ... Defined Bond Stereocenter Count, 0, Computed by PubChem ... Collision Energy, 10 eV .
Which is an example of a compound?
Answer:
Octane - Formula: C8H^18 = Carbon^8 + Hydrogen^18
Explanation: Octane is a compound because there are 8 atoms of carbon and 18 atoms of hydrogen in one molecule of C8H18. There are also 8 moles of carbon and 18 moles of hydrogen.
3) Report how many significant figures each of the following numbers has and then write the number in
standard scientific notation.
Number
Number of Significant Figures
Standard Scientific Notation
0.0000620
0.05600
70820.0
309100
Answer:
Number of Significant Figures
0.0000620 = 6
0.05600 = 3
70820.0 = 5
309100 = 6
Standard Scientific Notation
0.0000620 = 6.2 * [tex]10^{-5}[/tex]
0.05600 = 5.6 * [tex]10^{-2}[/tex]
70820.0 = 7.082 * [tex]10^{4}[/tex]
309100 = 3.091 * [tex]10^{5}[/tex]
how many mole of iron will be produced from 6.20 mole of carbon monboxide reacting with excess iron oxide
Answer:
6.20 mol
Explanation:
Step 1: Write the balanced reaction
FeO + CO → Fe + CO₂
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of carbon monoxide (CO) to iron (Fe) is 1:1.
Step 3: Calculate the moles of Fe produced from 6.20 moles of CO
6.20 mol CO × (1 mol Fe/1 mol CO) = 6.20 mol Fe
Which of the following equations best represents methanol being dissolved in water
A. CH3OH(I) —> CH3+(aq) + OH-(aq)
B. CH3OH(I) —> CH3O-(aq) + H+(aq)
C. CH3OH(I) —> CH3OH(aq)
Answer: [tex]CH_3OH(l)\rightarrow CH_3OH(aq)[/tex]
Explanation:
According to the concept of “Like dissolves like”, the polar solutes dissolve in polar solvents, and non-polar solutes dissolve in non-polar solvents.
Covalent compounds which are formed by sharing of electrons between non metals, when dissolved in water, forms hydrogen bonding with water if they contain a electronegative atom along with hydrogen. Example: methanol [tex](CH_3OH)[/tex]
Ionic compounds which are made up of cations and anions, when dissolved in water, dissociate into ions. Example: [tex]NaCl[/tex]
Thus equation which best represents methanol being dissolved in water is:
[tex]CH_3OH(l)\rightarrow CH_3OH(aq)[/tex]
A nurse is preparing to administer 4300 units of Heparin which available in 2000 units/mL. How many mL should the nurse administer?
a. 12.9 mL
B. 1.29 mL
C. 2.15 mL
D. 16.0 mL
E. 3.00 mL
HELP ASAP
THANKS!
Taking into account the definition of units/mL, the correct option is option C. The nurse should administer 2.15 mL.
Heparin is an anticoagulant drug used in the treatment and prevention of blood clots caused by certain medical conditions or medical procedures. Heparin is also used before surgery to reduce the risk of blood clots. That is, this drug works by decreasing the blood's ability to clot.
The results of some medical tests are reported in units per milliliter (u/mL). This unit of concentration expresses unit of activity per unit of volume.
In this case, Heparin is available in 2,000 units/mL ands this means that for every 1 mL, there are Heparin 2,000 units.
Then you can apply the following rule of three: if 2,000 units are present for every 1 mL, 4,300 units are present in how many mL?
volume= (4,300 units× 1 mL) ÷ 2,000 unita
Solving:
volume= 2.15 mL
In summary, the correct option is option C. The nurse should administer 2.15 mL.
Learn more with this examples:
https://brainly.com/question/20366928?referrer=searchResultshttps://brainly.com/question/18030745?referrer=searchResultshttps://brainly.com/question/13956508?referrer=searchResultsAdd coefficients to the reaction summary to show the net results of glycolysis. glucose+a ADP+b Pi+c NAD+⟶x pyruvate+y ATP+z NADH You do not need to add the water and hydrogen ions necessary to balance the overall reaction.
Then, Draw the structure of pyruvate at pH 7.4.
Answer:
See figure 1
Explanation:
For this question, we can start with the structure of pyruvic acid. In this molecule, we have two functional groups, the ketone group, and a carboxylic acid group.
In the acid group, we have an acidic hydrogen. That is, this hydrogen can leave the molecule to produce a hydronium ion ([tex]H^+[/tex]).
Now, to know what is the pH at which this hydrogen leaves the molecule we must look for the pKa value. Which for the case of this molecule is 2.45
If there is a pH value greater than 2.45, the molecule will lose hydrogen. In this case, we will have a value above 2.45 (7.4), which is why the conjugated acid of pyruvic acid will be produced, which is pyruvate.
Therefore, in the structure, we will have a negative charge on the acid group.
See figure 1
I hope it helps!
During complete oxidation of the fatty acid CH3(CH2)14COOH, ________ molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle ________ times
Answer:
During complete oxidation of the fatty acid CH3(CH2)14COOH, eight molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven times.
Explanation:
In the β-oxidation of fatty acids, an acetyl-CoA molecule is removed from the fatty acid chain after every β-oxidation cycle that the fatty acid undergo, leaving behind a fatty acyl-CoA molecule shortened by two cabon atoms..
The removal of the acetyl-CoA molecule starts from the carboxyl end and shortens the fatty acid molecule by two carbon units. Successive β-oxidation cycles results in the complete oxidaton of the fatty acid molecle to acetyl -CoA molecules.
The compound CH3(CH2)14COOH, is a 16-carbon saturated fatty acid molecule known as palmitic acid.. It undergoes seven passes through the β-oxidation cycle to yield eight molecules of acetyl-CoA with each cycle yielding an acetyl-CoA molecule and a fatty acyl-CoA shortened by two carbon atoms. Finally, the seventh step yields two acetyl-CoA molecules.
During complete oxidation of CH3(CH2)14COOH, eight (8) molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven (7) times.
Cellular respiration refers to a series of metabolic reactions by which aerobic cells use the energy stored in the chemical bonds of foods and oxygen to produce ATP and carbon dioxide.Cellular respiration has three stages: glycolysis, the Krebs cycle (also called TCA or tricarboxylic acid cycle) and oxidative phosphorylation.During the TCA cycle, a fatty acid containing a hydrocarbon tail of N atoms of carbons undergoes an amount of (N/2)−1 rounds of β-oxidation to be oxidized.Palmitic acid [chemical formula: CH3(CH2)14COOH] is a fatty acid with 16 carbon atoms in which 7 successive rounds of oxidation must take place to produce 8 acetyl-CoA molecules.In conclusion, during complete oxidation of CH3(CH2)14COOH, eight (8) molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven (7) times.
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What evidence of climate change
Which is a chemical process? a. melting of lead b. dissolving sugar in water c. tarnishing of silver d. crushing of stone
Answer:
a melting of lead Is the answer
Which of these statements best explains why chemistry is reliable?
Answer:
It gives the same result when an experiment is repeated.
Explanation:
Below are the possible answers to the question:
It is biased.
It cannot be verified.
It cannot add new evidence to existing evidence.
It gives the same result when an experiment is repeated.
The correct answer would be that it gives the same result when an experiment is repeated.
If a reaction is conducted in chemistry and certain results are obtained, once a detailed procedure of the experiment is known along with all the chemicals involved, such reaction/experiment can be repeated anywhere in the world and the same result would be obtained.
The repeatability of experiments always makes the experiments to be reliable. Hence, chemistry is reliable because it gives the same result without any variation when experiments are repeated under similar conditions.
Let's find the temperature when the pressure is equal to zero. There are two ways of doing this, what are they? What is the temperature when the pressure equals zero? What is the significance of that number?
Answer:
The lower the temperature, the lower the pressure inside of the sphere. If the exact values were plotted out, a linear relationship would be apparent. Extrapolating this line to the point where there would be no pressure yields absolute zero, which is about -273.15 degrees Celsius.
which of the following best describes precision
Answer:
Good precision because he is hitting the same spot 3 times but we don't know if he is accurate. SO the answer is 2
A sample of ozone gas occupies 225 mL at 1.00 atm and 0 °C. If the volume of the gas is 625 mL at 25 °C, what is the pressure?
Answer:
[tex]P_2=0.393atm[/tex]
Explanation:
Hello,
In this case, we can use the combined ideal gas law in order to analyze its behavior as a function of changing temperature, volume and pressure:
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
Thus, since we know the volume, temperature and pressure at the initial condition, we can compute the final pressure as shown below:
[tex]P_2=\frac{P_1V_1T_2}{T_1V_2} =\frac{1.00atm*225mL*(25+273)K}{(0+273)K*625mL}\\ \\P_2=0.393atm[/tex]
Regards.
For the reaction PCl5(g) <--> PCl3(g) Cl2(g) at equilibrium, which statement correctly describes the effects of increasing pressure and adding PCl5, respectively
The given question is incomplete. The complete question is :
For the reaction [tex]PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)[/tex] at equilibrium, which statement correctly describes the effects of increasing pressure and adding [tex]PCl_5[/tex], respectively
a) Increasing pressure causes shift to reactants, adding [tex]PCl_5[/tex] causes shift to products.
b) Increasing pressure causes shift to products ,adding [tex]PCl_5[/tex] causes shift to reactants.
c) Increasing pressure causes shift to products, adding [tex]PCl_5[/tex] causes shift to products.
d) Increasing pressure causes shift to reactants,adding [tex]PCl_5[/tex] causes shift to reactants
Answer: Increasing pressure causes shift to reactants, adding [tex]PCl_5[/tex] causes shift to products.
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
For the given equation:
[tex]PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)[/tex]
a) If the pressure is increased, the volume will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. As the number of moles of gas molecules is lesser at the reactant side. So, the equilibrium will shift in the left direction. i.e. towards reactants.
b) If [tex]PCl_5[/tex] is added, the equilibrium will shift in the direction where [tex]PCl_5[/tex] is decreasing. So, the equilibrium will shift in the right direction. i.e. towards products.
Complete and balance the equation for this reaction in acidic solution.
BrO−3+Sb3+⟶Br−+Sb5+
Answer:
6 H⁺ + BrO₃⁻ + 3 Sb³⁺ ⟶ Br⁻ + 3 H₂O + 3 Sb⁵⁺
Explanation:
Step 1: Write the unbalanced reaction
BrO₃⁻ + Sb³⁺ ⟶ Br⁻ + Sb⁵⁺
Step 2: Identify both half-reactions
Reduction: BrO₃⁻ ⟶ Br⁻
Oxidation: Sb³⁺ ⟶ Sb⁵⁺
Step 3: Perform the mass balance, adding H⁺ and H₂O where appropriate
6 H⁺ + BrO₃⁻ ⟶ Br⁻ + 3 H₂O
Sb³⁺ ⟶ Sb⁵⁺
Step 4: Perform the charge balance, adding electrons where appropriate
6 H⁺ + BrO₃⁻ + 6 e⁻ ⟶ Br⁻ + 3 H₂O
Sb³⁺ ⟶ Sb⁵⁺ + 2 e⁻
Step 5: Multiply both half-reactions by numbers that assure that the number of electrons gained and lost is the same
1 × (6 H⁺ + BrO₃⁻ + 6 e⁻ ⟶ Br⁻ + 3 H₂O)
3 × (Sb³⁺ ⟶ Sb⁵⁺ + 2 e⁻)
Step 6: Add both half-reactions and cancel what is repeated in both sides
6 H⁺ + BrO₃⁻ + 3 Sb³⁺ ⟶ Br⁻ + 3 H₂O + 3 Sb⁵⁺
any help is appreciated
Answer:
1.63×10¹⁰ L.
Explanation:
We'll begin by calculating the number of mole in 125 g of silver (ii) oxide, AgO. This can be obtained as follow:
Mass of AgO = 125 g
Molar mass of AgO = 108 + 16 = 124 g/mol.
Mole of AgO =?
Mole = mass /Molar mass
Mole of AgO = 125 /124
Mole of AgO = 1.01 moles.
Next, we shall convert 6.19×10¯⁵ μmol/L to mol/L. This can be obtained as follow:
1 μmol/L = 1×10¯⁶ mol/L
Therefore,
6.19×10¯⁵ μmol/L = 6.19×10¯⁵ × 1×10¯⁶ = 6.19×10¯¹¹ mol/L
Finally, we shall determine the volume as follow:
Molarity = 6.19×10¯¹¹ mol/L
Mole of AgO = 1.01 moles
Volume =?
Molarity = mole /Volume
6.19×10¯¹¹ = 1.01/Volume
Cross multiply
6.19×10¯¹¹ × volume = 1.01
Divide both side by 6.19×10¯¹¹
Volume = 1.01/6.19×10¯¹¹
Volume = 1.63×10¹⁰ L
Therefore, the volume of the solution is 1.63×10¹⁰ L
A conversion factor set up correctly to convert 15 inches to cm is _______.
A) 100 cm/1 m.
B) 1 inch/2.54 cm.
C) 1 cm/10 mm.
D) 2.54 cm/1 inch.
E) 10 cm/1 inch.
Answer:
e is the correct one , hope I helped u
To determine the concentration of SO4 2– ion in a sample of groundwater, 100.0 mL of the sample is titrated with 0.0250 M Ba(NO3)2, forming insoluble BaSO4. If 7.48 mL of the Ba(NO3)2 solution is required to reach the end point of the titration, what is the molarity of the SO4 2–?
Answer:
1.87x10⁻³ M SO₄²⁻
Explanation:
The reaction of SO₄²⁻ with Ba²⁺ (From Ba(NO₃)₂) is:
SO₄²⁻(aq) + Ba²⁺(aq) → BaSO₄(s)
Where 1 mole of SO₄²⁻ reacts per mole of Ba²⁺
To reach the end point in this titration, we need to add the same moles of Ba²⁺ that the moles that are of SO₄²⁻.
Thus, to find molarity of SO₄²⁻ we need to find first the moles of Ba²⁺ added (That will be the same of SO₄²⁻). And as the volume of the initial sample was 100mL we can find molarity (As ratio of moles of SO₄²⁻ per liter of solution).
Moles Ba²⁺:
7.48mL = 7.48x10⁻³L ₓ (0.0250moles / L) = 1.87x10⁻⁴ moles of Ba²⁺ = Moles of SO₄²⁻
Molarity SO₄²⁻:
As there are 1.87x10⁻⁴ moles of SO₄²⁻ in 100mL = 0.1L, molarity is:
1.87x10⁻⁴ moles of SO₄²⁻ / 0.1L =
1.87x10⁻³ M SO₄²⁻Compare and contrast the characteristics of metals and nonmetals.
why graphite is a nonmetal, why it is not included in metalloid.
Graphite is a not metal because of the lack of the properties
Metals are ductile but graphite is not ductileMetals are meleable but graphite is not meleablemetal are sonorous but. graphite is not sonorousMetal are lustrous but graphite is not lustrousGraphite contains only one property of metal
metal is a good conductor of electricity but its a exception.
Because of all that reasons graphite is not included in metalloid.
Hope it helps u mate
A ballon at 2.7atm has a volume of 1.6L.What will be the volume if the pressure is reduced to 1,3atm?
Answer:
3.3 L
Explanation:
Step 1: Given data
Initial pressure (P₁): 2.7 atmInitial volume (V₁): 1.6 LFinal pressure (P₂): 1.3 atmFinal volume (V₂): ?Step 2: Calculate the final volume of the balloon
Inside the balloon we have gas. If we consider it behaves as an ideal gas, we can calculate the final volume using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 2.7 atm × 1.6 L / 1.3 atm
V₂ = 3.3 L
Calcutale Grxn for the following equation at 25°C:
4KClO3(s) → 3KClO4(s) KCl(s)
Answer:
-133.2 kJ
Explanation:
Let's consider the following balanced equation.
4 KClO₃(s) → 3 KClO₄(s) + KCl(s)
We can calculate the standard Gibbs free energy of the reaction (ΔG°rxn) using the following expression.
ΔG°rxn = 3 mol × ΔG°f(KClO₄(s)) + 1 mol × ΔG°f(KCl(s)) - 4 mol × ΔG°f(KClO₃(s))
ΔG°rxn = 3 mol × (-303.1 kJ/mol) + 1 mol × (-409.1 kJ/mol) - 4 mol × (-296.3 kJ/mol)
ΔG°rxn = -133.2 kJ
Carboxypeptidases can be used to determine the entire sequence of short peptides (<50 amino acid residues) and it starts by reacting with the C-terminal amino acid.
a. True
b. False
Answer:
A. True
Explanation:
Carboxypeptidases are enzymes which function in the digestion of short peptides known as oligopeptides in the small intestine. Oligopeptides contain between 10 to 50 amino acid residues.
The two carboxypeptidases A and B involved in the digestion of proteins in the small intestine are secreted by the exocrine glands of the pancreas.They are both zinc-containing enzymes which remove successive carboxyl-terminal (C-terminal) residues from oligopeptides until free amino acids are obtained.
Since they function in this way, they can be used to determine the entire sequence of short peptides or oligopeptides.
A chemist must prepare of aqueous copper(II) fluoride working solution. He'll do this by pouring out some aqueous copper(II) fluoride stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the copper(II) fluoride stock solution that the chemist should pour out.
Answer:
See answer below
Explanation:
First, you are not putting the whole data, however, I found an exercise very similar to this, so I'm gonna use this data, as an example, and you can use it as guide to solve yours. The exercise is the following:
A chemist must prepare 275. mL of 1967 uM aqueous copper(II) fluoride (Cur) working solution. He'll do this by pouring out some 2.63 mmol/L aqueous copper(II) fluoride stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the copper(II) fluoride stock solution that the chemist should pour out.
According to this, we want a more dilluted solution fo copper Fluoride solution. To do this, we need to know the moles that are required in the desired solution.
1967 uM in just mol/L is:
1967 uM * 1 M / 1x10⁶ uM = 1.967x10⁻³ M
Now that we have the concentration, we can calculate the moles required to prepare this solution:
moles = 1.967x10⁻³ mol/L * 0.275 L = 5.41x10⁻⁴ moles
These are the moles that we need to have to prepare this solution. Now, with the concentration of the stock solution, we just solve for the volume required:
V = moles / M
V = 5.41x10⁻⁴ / 2.63x10⁻³
V = 0.2057 L ----> 205.7 mL or 206 mL
If a brownie that measures 15 cm * 7 cm * 7 cm and has a density of 2.3 g/cm^ ^ 3 is cut in half what will happen to the density of the brownie ? *
Answer:
unchanged
Explanation:
The density of an object or of a substance is independent of the amount of substance. From the definition of density as mass per unit volume, the ratio of the mass of an object to the volume of the same object is always constant. The more the mass of the object, the more the volume, and vice-versa.
Hence, if a brownie that measures 15 cm by 7 cm by 7cm and has a density of 2.3 g/cm^3 is cut into half, both the mass and the volume would change in equal proportion and the density would remain the same.