Which variable mentioned in Table 2-1 is kept constant? a. amount of time spent swimming b. type of swimming stroke c. number of calories used d. the person swimming

Answer:

Agrophobia

Explanation:

an anxiety disorder in which someone feals anxious and scared in a public place

Answer:

3. years

Explanation:

The independent variable is the x axis of graph

The new oscillation frequency of the pendulum clock is 1.14 rad/s.

The given parameters;

The moment of inertia of the rod about the end is given as;

[tex]I_i = \frac{1}{3} ML^2[/tex]

The moment of inertia of the rod between the middle and the end is calculated as;

[tex]I_f = \int\limits^L_{L/2} {r^2\frac{M}{L} } \, dr = \frac{M}{3L} [r^3]^L_{L/2} = \frac{M}{3L} [L^3 - \frac{L^3}{8} ] = \frac{M}{3L} [\frac{7L^3}{8} ]= \frac{7ML^2}{24}[/tex]

Apply the principle of conservation of angular momentum as shown below;

[tex]I _i \omega _i = I _f \omega _f\\\\\frac{ML^2}{3} (1 \ rad/s)= \frac{7ML^2}{24} \times \omega _f\\\\\frac{24 \times ML^2}{3 \times 7 ML^2} (1 \ rad/s)= \omega _f\\\\1.14 \ rad/s = \omega _f[/tex]

Thus, the new oscillation frequency of the pendulum clock is 1.14 rad/s.

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Answer:

Hyperbolic comets originate from the Kuiper Belt.

A solvent is any substance which is able to interact with a solute and dissolve it.

A solute is any substance that is able to interact with a solvent and dissolve in it. Usually, the solute must posses similar intermolecular forces as the solvent.

For this reason, polar solutes dissolve in polar solvents while nonpolar solutes dissolve in nonpolar solvents. In polar solutes, the ions or dipoles of the solute are able to interact with the dipoles of the solvent thereby pulling the solute particles apart in order to have solvent - solute interaction.

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Answer:

its sort of like how Pounds are measured in lbs

Explanation:

Pounds are measured in lbs when they dont sound anything similar, same thing applies to gun technology.

Explanation:

We need to calculate the centripetal force:

Fc = W + F

With Fc being the centripetal force, W the weight of the boy, F the centrifugal force (apparent).

We know that we can calculate the apparent centrifugal force thank to the formula:

F = (m·v²)/r = 204N

So we can write:

Fc = W + F = 445N + 204N = 649N

Answer: Next time you create a question, add an image or PDF. Because I do not know the question. So, may you please create a new question?

Answer:

Explanation:

KEA = ½(50)5² = 625 J

KEB = ½(30)2² = 60 J

Student A has more kinetic energy.

More than ten times more kinetic energy due to both larger mass and higher velocity.

Answer:

Explanation:

If we ASSUME that a CCW torque is positive

τ = 10sin135[8.0] - 16sin90[4.0] + 19sin160[3.0] = 12 N•m

as the result is positive, the net torque is CCW.

Answer:

41.6m/s

Explanation:

P=mv

2500kg × 25m/s = 62500kgm/s

62500kgm/s ÷ 1500 kg = 41.6m/s

Answer:

A. gravitational force always true.

B, C and D could be true under the correct conditions

A conjugate acid is formed from the base  by accepting a proton from the acid .

A conjugate base is obtained from the Brownstead - Lowry acid when it looses a proton while the conjugate acid is obtained from the Brownstead - Lowry base when it accepts a proton. In the Brownstead - Lowry sense, acid base reaction involves the loss or gain of a proton.

Consider the hypothetical reaction; AH + :B ⇄ BH + :A. The specie BH is the conjugate acid while the specie  :B is the  Brownstead - Lowry base . The specie :A is the conjugate base while the specie AH is the  Brownstead - Lowry acid.

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Explanation:

Force= mass× acceleration

Force= 4×2

= 8N

Doubling the force, 8×2= 16N

16= 4 × a

a= 16/4

= 4m/s²

Answer:

The nodes of a standing wave are points where the displacement of the wave is zero at all times nodes are important for matching boundary conditions for example that the point at which a string is tied to a support has zero displacement at all times ie the point of attachment does not move consider a standing

Answer:

F = 0 N

Explanation:

The problem does not talk about any acceleration. We can just assume it always moves at a constant speed so the resultant force will be 0 newtons. Of course you could say that it accelerates for a certain amount of time, as the wind blows, but the problem doesn't tell us when to calculate the resultant force (if during the acceleration or after) + we don't have the mass of the jet.

The charge moved by this electric force is [tex]5.4 \times 10^{-5} \; Coulombs[/tex].

Given the following data:

To determine the charge:

Mathematically, the work done by an electric force in moving a charge from one point to another is given by the formula:

[tex]W = PQ[/tex]

Where:

Making Q the subject of formula, we have:

[tex]Q =\frac{W}{P}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Q =\frac{2.70 \times 10^{-3}}{50}\\\\Q =5.4 \times 10^{-5} \; Coulombs[/tex]

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Answer:

Explanation:

You want the required centripetal force to equal gravity force

if m is the mass of the satellite

ma = mv²/R

a = v²/R

F = ma = GMm/R²

a = GM/R²

v²/R = GM/R²

v² = GM/R

v = √(GM/R)

v = √(6.674 x 10⁻¹¹(5.972 x 10²⁴)/6.771 x 10⁶)

v = 7.672 x 10³ m/s

Answer:

Explanation:

Average velocity in the 24 m interval is 24 / 4 = 6 m/s

Average velocity in the 64 m interval is 64 / 4 = 16 m/s

There is a 4 second interval between the two points where average velocity equals actual velocity

a = Δv/t = (vf - vi) / t = (16 - 6) / 4 = 2.5 m/s²

s = v₀t + ½at²

24 = v₀(4) + ½(2.5)4²

4v₀ = 24 - 20

v₀ = 1 m/s

Not asked for but the velocity at the end of the first segment and beginning of the second segment is 11 m/s and final velocity is 21 m/s

A force of 50 N was applied to an object with a mass of 5 kg, then the acceleration of the object will be 10 m/s².

The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.

Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.

There are several types of acceleration :

According to the question, the given values are :

Force, F = 50 N

Mass, m = 5 kg

Force = m × a

a = 50 / 5

a = 10 m/s².

Hence, the acceleration of the object will be 10 m/s².

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Answer:

Explanation:

Work is the area under the curve between the limits

W = ½(5)(8 - 5) = 7.5 J

The work done when an object moves from 5 m to 8 m is 7.5 J.

The work done in moving an object from one point to another is equal to the product of force and displacement of the object.

W = Fs

The work done on an object is equal to area under the curve

The area between point 5 m and 8 m = ¹/₂ x (8 - 5) x 5 = 7.5 J

Thus, the work done when an object moves from 5 m to 8 m is 7.5 J.

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Answer:

1125m

Explanation:

The car moves with a uniformly accelerated motion for 20s:

s = 1/2·a·t² + v0·t + s0 (note that vo = 0 and s0 = 0, with v0 being the initial velocity and s0 the initial displacement).

So: s = 1/2·a·t²

The acceleration will be: Δv/Δt = 15m/s / 20s = 0.75 m/s²

s1 = 1/2·0.75 m/s² · (20 s)^2 = 150m

Then it continues with the velocity he acquired (v = a·t = 0.75 m/s²·20s = 15 m/s):

s2 = vt = 15m/s·50s = 750m

The final acceleration, when stopping, will be:

a = Δv/Δt = -15m/s / 30s = -1/2 m/s²

s3 = 1/2·(1/2m/s²)·(30s)² = 225m.

Now we sum s1 with s2 and s3:

s1 + s2 + s3 = 150m + 225m + 750m = 1125m

The final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east

The given parameters;

The initial momentum of the boy is calculated as follows;

[tex]P_y = m_1 u_1\\\\P_y = 25 \times 5\\\\P_y = 125 \ kgm/s \ \ north[/tex]

The initial momentum of the snowball is calculated as follows;

[tex]P_x = m_2 u_2\\\\P_x = 1 \times 15 \ \\\\P_x = 15 \ kgm/s \ \ west[/tex]

The resultant momentum of the boy and the snowball after collision is calculate as follows;

[tex]P_f = \sqrt{P_y^2 + P_x^2} \\\\P_f = \sqrt{125^2 + 15^2} \\\\P_f = 125 .9 \ kgm/s[/tex]

The final velocity of the system boy-snowball system is calculated as;

[tex]v_f(m_1 + m_2)= P_f\\\\v_f = \frac{P_f}{m_1 + m_2} \\\\v_f = \frac{125.9}{25 + 1} \\\\v_f = 4.84 \ m/s[/tex]

The direction of the boy after the collision is calculated as follows;

[tex]\theta = tan^{-1}(\frac{v_y}{v_x} )\\\\\theta = tan^{-1} (\frac{5}{15} )\\\\\theta = 18.4 \ ^0[/tex]

Thus, the final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east

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Answer:

Explanation:

as the mass cannot change, the volume per unit time is also constant so the area of the stream times the velocity is constant

If the diameter is 1 where velocity is 1.31 m/s

area is proportional to the square of the diameter    A = (π/4)d²

1²(1.31) = 0.805²(v)

v = 1.31/0.805² = 2.02 m/s

v² = u² + 2as

2.02² = 1.31² + 2(9.81)h

h = 0.120819... m

h = 12.0 cm

Hi there!

1.

Hooke's law states that:

F = -kx

k = Spring constant (N/m)

x = DISPLACEMENT from equilibrium (m)

Essentially, the force of a spring is PROPORTIONAL to its spring constant and its displacement from its equilibrium point.

2.

The force of the spring (T) is not proportional to the spring's length (l), but rather its DISPLACEMENT from its equilibrium length. (Δl)

3.

The equilibrium length is where the force of the spring (T) = 0N. Looking at the graph, the line intersects this value at l = 30cm.

4.

We can begin by looking at the given graph.

When the spring force = 4N, the total length of the spring is 35 cm.

Now, the EQUILIBRIUM length is 30 cm, so the total elongation is:

35 - 30 = 5 cm.

5.1.

If the spring elongates by 10 cm, the total length of the spring is:

30 + 10 = 40 cm

According to the graph, a length of 40 cm corresponds to a force of 8N.

5.2.

We can solve for the weight of the ball using the following:

W (weight) = m (mass) · acceleration due to gravity (10N/kg)

Using a summation of forces:

∑F = T - W

The elongation that we are solving for occurs at the equilibrium point (net force = 0 N), so:

0 = T - W

T = W = 8 N

5.3.

0 = T - Mg

T = Mg

Use the prior value of T and gravity to solve:

8 = 10M

m = 0.8 kg

Answer:

When the tides are especially weak, it is called a NEAP tide.

Explanation:

Hope this helps :)

Answer:

Neap

Explanation:

Answered!

Answer:

energy transformation

Answer: Energy Transformation & Energy Conversion.

According to the law of superposition, the statement 'it is expected to find dinosaur bones below the K-T boundary but not above'' is TRUE. This boundary separates the Cretaceous and Tertiary periods.

The law of superposition is used by paleontologists to explain a sequence of sedimentary rock layers from the oldest layer at the base to reach the surface (newer).

Moreover, the K-T boundary is a boundary that separates sediments of the Cretaceous period from the Tertiary period.

This boundary (K-T boundary) dates approximately 65 million years (Mya) ago, i.e., the period in which dinosaurs became extinct.

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Answer:

Explanation:

s = ½at²

s = ½(9.50)(29.3²) = 4,077.8275

s = 4080 m

when rounded to the three significant digits of the question numerals.

Answer:

Mechanical energy into electrical energy

Explanation:

Answer:

ExplanMechanical energy into electrical energy

SIation: