Which variable can be measured with a weighing balance?

The crate will be under a net force of 95 N. Resolving the force in the x-direction yields the net force on the crate: F = 300 cos 10° - N F= 295.44-196.45, F= 95.

The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula fr = Fr/N serves as a representation of it.

The friction of a moving item is inversely proportional to the normal force and runs perpendicular to it. The type of surface the thing comes into touch with determines the amount of friction it experiences. As long as there is a point of contact, friction does not depend on the area of contact.

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There is not enough information to determine the work done. Option iv

Let us note that we say that there is work done when the force that has been applied moves a distance in the direction of the force. In this case, we have been told that there is the combination of the works that is done by the object.

Now, we also have to note that we do not have other information to determine the work done such as the magnetic feild and the mass of the electron. All these are lacking in the question.

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Answer:

12hp and 132 ml

Explanation:

12+ 132.00=12asd

Answer:

3rd image, 2nd image, 1st image, 4th image

Explanation:

Not an easy question, tricky one

Electric potential energy is proportional to the magnitude of the charges (the higher the charges, the stronger the Electric potential energy(EPE)) and inversely proportional to the distance between the charges(the longer the distance, the smaller the EPE).  U = kQq/r

EPE is positive in this case due to unlike charges.

Between distance and magnitude of the charges, magnitude of charges play a more significant effect than distance (due to Qq , both the magnitude of Q and q affect the EPE)

Hence. zoom in on the magnitude first.

3rd image has the largest + and -, hence greatest magnitude of charges, therefore highest EPE.

Between 1st and 2nd images, charges have the same magnitude, distance now comes to play. Distance between the charges is smaller for image 2 and the charges experience greater EPE. 1st image, the charges are further, hence smaller EPE.

For the fourth image, the magnitude of the charges is the smallest, hence smallest EPE.

Answer:

12.3 m/s

Explanation:

To calculate the final velocity of Ben, we can use the equation KE = 1/2mv^2, where KE is the kinetic energy and m is the mass of Ben. Inserting the given values, we get:

7100 = 1/2 (63.2 kg) v^2

Therefore, v^2 = 7100/31.6

v = √(7100/31.6)

v = 12.3 m/s

Answer:

56.7m

Explanation:

horizontal velocity does not matter in this situation because it stays constant (no unbalanced force acting upon it)

a=9.81m/s^2              

t=3.4s

Vi=0m/s

d=Vi*t+1/2at^2

d=1/2at^2

d=1/2*9.81m/s^2*(3.4s)^2

d=4.905m/s^2*11.56s^2

d=56.7m

Among electromagnetic waves, UV rays are most dangerous because exposure to these radiation cause serious problems in living organism. Thus the frequency of sound wave is 0.135 s⁻¹.

Electromagnetic wave is a wave which contain two component one is electric component and other is magnetic component. The electric and magnetic component are perpendicular to each other. There are so many wave that comes under electromagnetic wave like infrared wave , radio wave, light wave.

There is a relation between frequency of wave, and wavelength of wave

Mathematically,

speed=distance/time

where,  

ν=frequency of light

c is speed of light that is 3×10⁸m/s

λ is the wavelength of light=4.5x10² nm= 10.6 m

Substituting all the values

346 m/s =11.76m÷ t

t=0.033= 0.135 s⁻¹

Thus the frequency of sound wave is 0.135 s⁻¹.

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If an object is working against gravity, that means gravity must have the opposite sign of the object (this is why we see objects slow down at their peak height and return to us if we throw them in the air!). If the object is working with gravity, though, they must both be moving in the same direction, therefore gravitational acceleration would be the same sign as the velocity (positive or negative depending on how you define your axes).

Therefore, your answer should be C. Different sign + or - on the acceleration.

I hope this helps!

Answer: A step-down transformer changes the magnitude of the voltage in an alternating current (AC) electrical signal. It reduces the voltage of the AC signal by using a winding ratio between the primary (input) and secondary (output) coils that is less than 1:1.

Explanation: For example, if the winding ratio of a step-down transformer is 1:0.5, the output voltage of the secondary coil will be half the magnitude of the input voltage of the primary coil. In this case, the transformer would change the AC voltage from a higher value to a lower value.

The transformer does not change the frequency of the AC signal, which is determined by the source of the electrical power. The transformer also does not change the waveform of the AC signal, which is typically a sinusoidal wave.

The material has a Poisson's ratio and a modulus of elasticity of 0.25. Y=2G(1+) is the correct relationship between the Young's modulus (Y), the shear modulus (G), and the Poisson's ratio ().

The bulk modulus, also known as the elastic modulus K, is related to the Poisson's ratio; G as the modulus of shear; and E, Young's modulus, by the following (for isotropic solids whose properties are non-directional). The stiffness is measured by the elastic moduli. They are stress-to-strain ratios.

Determine the rod's stress level.

Determine the longitudinal strain by multiplying F A 12 by (0.016) = 59.683 MPa.

Determine the lateral strain by elongating Or 30010-3 = L mm 500 mm = = 0.0006.

-2.410-3 mm 16 mm Elateral = = -0.00015 d Determine the material's young's modulus.

& Long 59.683 MPa 0.0006 E = 99.471 GPa  100 GPa

Determine the material's poisson's ratio. & the lateral lengthens by -0.00015 0.0006 = 0.25.

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The linear expansion of the wrought iron is 0.0038 feet.

The linear expansion of the wrought iron is the increase in length of the wrought iron due to change or increase in temperature.

Mathematically, the formula for the linear expansion of metals is given as;

ΔL = αLΔθ

where;

The coefficient of thermal expansion of wrought iron = 0.0000067 / ⁰F

The linear expansion of the wrought iron is calculated as follows;

ΔL = αLΔθ

ΔL = ( 0.0000067/ ⁰F   x   8 ft    x   70 ⁰F )

ΔL = 0.0038 ft

Thus, the linear expansion of the wrought iron is a function of the increase in temperature of the iron and the original length of the iron.

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Explanation:

it takes the earth 24 hours to spin on it's axis once

Thus the electric field at the fourth corner of the square of side L is E4 = kQ.[2/a² + 1/a√2].

Electric field strength is a quantitative expression of the intensity of an electric field in an electric circuit at a particular location and time. The standard unit of the electric field strength is the volt per meter (V/m or V·m⁻¹). An electric field strength of 1 V/m represents a potential difference of about 1V between the two points which are separated by 1 meter distance.

We are given that:

Number of point charges = 3

Here, we shall use the superposition principle to calculate the net electric field at the fourth point, so

E4 = E1 + E2 + E3

E4 = kQ/a² + kQ/√(2a²) + kQ/a²

E4 = kQ [1/a² + 1/√(2a²) + 1/a²]

Thus the electric field at the fourth corner is  E4 = kQ [2/a² + 1/a√2].

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As the horse trots a fencepost that is 36m away from you in 11.0 second, the average velocity of the horse is 3.27 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

A horse trots past you and then a fencepost that is 36m away from you.

Time taken to  make this trot = 11.0 second.

Hence,  the average velocity of the horse is = total distance travelled/time interval

= 36/11.0 m/s

= 3.27 m/s.

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The atmospheric pressure on earth is 1 atm. This pressure is equivalent to the mercuric pressure of 760 mmHg. The atmospheric pressure on the surface of Venus is 9200 kpa which is equivalent to 69017 mmHg.

Pressure is the force acting per unit area. In the atmosphere, the gaseous particles and dust exerts a pressure in the atmosphere. The atmospheric pressure depends on the temperature.

There are various units for pressure. Normally the atmospheric pressure is expressed in atm unit. The mmHg pressure is based on the raise in mercuric level with respect to increase in pressure.

1 mmHg = 0.0013133 atm

hence, 760 mmHg = 1 atm

On the surface of Venus, the pressure is 9200 kilopascal.

1 mmHg = 0.133 KPa

then 9200 KPa = 9200/0.133 = 69017 mmHg pressure.

Therefore, height of mercuric column will be 69017 mm in Venus surface.

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Answer:

12583.2 J or 12.5832 KJ

Explanation:

Work done can be expressed as force multiplied by displacement, or

W = Fs

In this case, we can calculate the force by using F = mg.

m is the mass, 214 kg, and g is gravitational acceleration, which is 9.8 m/s/s.

So, we Calculate 214 * 9.8 to get 2097.2

The displacement is 6m.

So, by doing W = Fs, we get

2097.2 * 6 = 12583.2 Joules

The single cable will pull upward on the sign with a force of 38.3 N.

Single cable is a type of cable that is composed of a single electrical conductor. It is most commonly used in low voltage applications such as wiring for computers and domestic appliances. Single cable is typically insulated with rubber, PVC or other insulating materials. The insulator protects the conductor from short circuits and other electrical hazards.

This is because the sign is supported symmetrically by two cables, which means that the total downward force on the sign is equal to the total upward force. Since the two cables make an angle of 1.0 degrees with the horizontal, the total downward force on the sign is equal to the combined weight of the sign (38.3 N) and the two cables pulling down on it. Therefore, the single cable must pull up with a force of 38.3 N in order to keep the sign in equilibrium.

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Answer:

70.56 J

Explanation:

The increase in potential energy of the ball can be calculated using the formula:

PE = mgh

where:

PE is the increase in potential energy

m is the mass of the ball (6 kg)

g is the acceleration of gravity (9.8 m/s²)

h is the height the ball is lifted (1.2 m)

Substituting in the values, we get:

PE = (6 kg)(9.8 m/s²)(1.2 m)

This simplifies to:

PE = 70.56 J

So the increase in the ball's potential energy is 70.56 J.

Answer: It is not clear what is the power of 10 in the speed of the bullet but here is a general procedure for the question.

Explanation:

[tex]P_{bullet}=(3.22*10^{-3}kg)*(10^{?}m/s)\\P_{baseball}=P_{bullet}\\[/tex]

Therefore we can write:

[tex](0.151*10^{-3} kg)*v_{baseball}=(3.22*10^{-3}kg)*(10^{?}m/s)[/tex]

From this using the relationship:

[tex]v_{baseball}=\frac{(3.22*10^{-3}kg)*(10^?m/s)}{0.151*10^{-3}kg}[/tex]

I cannot give a precise answer since power of then for speed of the bullet is not clear. But using the above equation you can reach the answer. General form of the equation is therefore:

[tex]v_{baseball}=\frac{P_{bullet}}{m_{baseball}}[/tex]

Where m is the mass of the ball which is 0.151 g.

Answer:

Explanation:

The label that identifies a rarefaction in a longitudinal wave is B.

In a longitudinal wave, such as a wave in a spring, a rarefaction is an area where the particles of the medium are farther apart than they are in the rest of the wave. This is in contrast to a compression, which is an area where the particles of the medium are closer together than they are in the rest of the wave.

In the given illustration, the area where the rings are further apart is labeled B, so B is the label that identifies a rarefaction. The area where the rings are closer together, labeled A, is a compression. The height of the spring, labeled C, does not correspond to a rarefaction or a compression, and the distance between adjacent areas where the rings are closer together, labeled D, is not related to the concept of rarefactions or compressions.

Answer:

wavelength - C

rarefractions - B

compressions - A

Explanation:

correct on EDGE 2023

The gravitational field strength on Oobla is 20.75 m/s².

The gravitational field is the gravitational force exerted per unit mass on a small mass at a point in the field.

To calculate the gravitational field strength on Ooobla, we use the formula below

Formula:

Where:

From the question,

Given;

Substitute these values into equation 1 and solve for g'

Hence, the gravitational field strength is 20.75 m/s².

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Optimal Arousal theory  focuses on finding the right level of stimulation.

William James (1842–1910), frequently referred to as the father of psychology in the United States, made significant contributions to early studies on motivation.

James proposed a number of instincts that help with survival as the driving forces behind conduct . An instinct is a species-specific pattern of behavior that is not taught, according to biology.

But there was a lot of disagreement over what exactly constitutes instinct among James's contemporaries. James postulated a number of unique human instincts, although many of his contemporaries had different lists.

Therefore, Optimal Arousal theory  focuses on finding the right level of stimulation.

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Answer:

F = G M m / R^2 = m a

G M / R^2 = a

M = a R^2 / G

M = 1.56 N/kg * 6.35 m^2 / 6.67E10-11 N-m^2 / kg^2

M = 1.56 * 6.35 / 6.67E-11 kg

M = 1.49 * 10^11 kg

The goal kick strikes a defender racing at 5 m/s away from a goalkeeper in the back. The ball was moving at a speed of 70 m/s if it weighed 500g and the player's mass was 70k.

The goalkeeper extends the amount of time he has to hold the ball by pulling his hands back. He lessens the force (rate of change of momentum) the football exerts on him by lengthening the time.

A vector quantity, momentum. A body's momentum is equal to P=m.v if it is travelling at a speed of v while having mass m. P=mv describes the magnitude of the momentum. Because momentum is a function of mass and velocity, its unit is the product of those two quantities.

By using conservation of momentum,

Initial momentum = Final momentum

(5 x 70) + (v x 0.5) = (5.5 x 70) + (0 x 0.5)

350 + 0.5v = 385 + 0

0.5v = 35

v = 70 m/s

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22.0m/s² is equal to 78.98 km/min²​. Since 1 m/s² = 3.59 km/m². If we multiply 22 by this number, we get the accurate answer, according to the conversion table.

Acceleration is measured in meters per second2 (m/s2). Newton's Second Law, which states that "The acceleration of an object is exactly proportional to the net force acting on it and inversely proportionate to its mass," connects force (F), mass (m), and acceleration (g).

The Système International unit, or SI unit, is an acronym for the French phrase for system international. The metric system that serves as the industry standard for measurements is called the International System of Units (SI). In the advancement of science and technology, SI units are essential.

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The total work done by this force is 28.9-1457.86 N m.

Total work is the sum of all the energy expended in completing a job or task. It is the amount of effort and energy expended to accomplish a goal or complete a task. Total work can be calculated by adding up all of the individual components of the job or task, such as time, effort, and materials.

The total work done by this force can be calculated using the formula W = F * Δx, where F is the force vector, and Δx is the displacement vector. In this case, the total work done is:
W = (4.70-379, 2.09) * (4.25, 3.69-245) = (19.9-944.81, 8.00-513.05) N m
Therefore, the total work done is 28.9-1457.86 N m.

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Important Formulas:

[tex]w=Fd[/tex]

work(measured in joules) = force(measured in newtons) * distance(measured in meters)

__________________________________________________________

Given:

[tex]m=42kg[/tex]

[tex]F=225N[/tex]

[tex]d=12m[/tex]

[tex]w=Fd[/tex]

__________________________________________________________

Finding work:

[tex]w=Fd[/tex]

[tex]w=225\times12[/tex]

__________________________________________________________

[tex]\fbox{w = 2700 Joules}[/tex]

If an object is moving and the sum of all the vector forces on it is zero, then the object will move at a constant speed. The correct option is c.

A force's magnitude and direction are both represented by a force vector. This contrasts with expressing the force's magnitude alone, which is known as a scalar quantity.

Typically, a vector is represented by an arrow that points in the direction of the force and has a length proportionate to the strength of the force.

Therefore, the correct option is c, move at a constant speed.

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a) The magnitude of the force F on the −10 nC charge is  0.00134 Newton.

b) The direction of the force F on the −10 nC charge is 41.99° with horizontal line.

Electric force is the attractive or repulsive interaction between any two charged things.

a) the magnitude of the force F on the −10 nC charge = √{k (q₁Q/r₁²)²+(q₂Q/r₂²)²}

= kQ √( (q₁/r₁²)²+ (q₂/r₂²)²}

= 9×10⁹×10×10⁻⁹ √{ (1×10⁻⁹/(0.01)²)² +(10×10⁻⁹/(0.03)²)² }

= 0.00134 Newton.

b)  the direction of the force F on the −10 nC charge

= tan⁻¹( (1×10⁻⁹/(0.01)²) ÷(10×10⁻⁹/(0.03)²) )

= 41.99°

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