Which statements about this situation are true?
Select all the correct answers.
The maximum value in the range is $200.
The maximum value in the range is $320.
The maximum value in the domain is 200.
The minimum value in the domain is 0.

The probability of getting a number greater than zero is 9/10.

Probability is the chance of occurrence of a certain event out of the total no. of events that can occur in a given context.

Given, 'x' be a random variable that takes values from 0 to 9 with an equal probability of 1/10.

We know, The total probability is 1.

Therefore, The probability of getting a number greater than zero is,

(1 - the probability of getting zero).

= 1 - 1/10.

= 9/10.

Some more concepts related to probability is a conditional probability which states,

The likelihood that one event will follow another given the occurrence of another event.

Q. let x be a random variable that takes values from 0 to 9 with equal probability 1/10, Find the probability of getting a number greater than zero.

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f = a + a^10.37428 - 3.14 is an equation that relates two variables, f, and a.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

We have,

f = a + [tex]a^{10.37428}[/tex] - π

Now,

f = a + a^10.37428 - 3.14 is an equation that relates two variables, f, and a.

Where a is the independent variable and f is the dependent variable.

It consists of three terms.

= a represents the linear relationship between f and a.

= [tex]a^{10.37428}[/tex] represents a nonlinear relationship between f and a, where 10.37428 is the steepness of the curve.

= -3.14 is a constant that shifts the curve vertically.

Thus,

f = a + a^10.37428 - 3.14 is an equation that relates two variables, f, and a.

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Answer:

36.39 hope this helps

Step-by-step explanation:

The correct statement regarding the mode of the data-set is given as follows:

B. there is one mode. the mode is 2.47.

The mode of a data-set is the measure of central tendency that gives the observation that appears the most often in a data-set, hence the correct option is given by option a.

From the observations in this problem, a finish time of 2.47 hours appeared the most often, which was 3 times, hence the correct option is given by option B.

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3.141590 is an example of floating-point number, which is printed using %f.

Floating-point numbers are a way to represent real numbers in a computer. They are used to store values that have a fractional component, such as 3.14159. Unlike integers, which can be stored precisely in a fixed amount of memory, floating-point numbers use a fixed number of bits to represent the number's significant digits and its exponent. This allows them to represent a wide range of values, but can also result in some loss of precision. When printing a floating-point number, the %f format specifier is used to specify the number of decimal places to display.

For example, the number 3.141590 can be printed using the format specifier %f as follows:

printf("%f", 3.141590);

This will output:

3.141590

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The value of x is 2.

Triangles are one of the most basic shapes in geometry and have a wide range of applications in mathematics, science, and engineering.

The three sides of a triangle are called edges, and the three angles are called vertices. Triangles can be classified based on the lengths of their sides and the measures of their angles.

Since DE is parallel to AC, we can use the intercept theorem to relate the lengths of the corresponding sides of triangles ABD and CBE.

In triangle ABD and CBE, we have:

AD/CE = AB/BC

Substituting the given values, we get:

2/1 = (x+2)/4

Cross-multiplying, we get:

8 = 2(x+2)

Simplifying, we get:

x+2 = 4

x = 2

Therefore, the value of DB is 2.

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this is split into three shapes

the middle is a rectangle

5.8 x 9.5 = 55.1

find width of left triangle

18 - 9.5 = 8.5

area of triangle is 1/2 base x height

8.5 x 5.8      /  2   = 24.65

5.1 x 5.8    /2  = 14.79

add all 3

99.47 is total area

Hope this helps : -)

- Jeron

The given equation is exact. An equation is said to be exact if it can be written in the form

M(x,y)dx + N(x,y)dy = 0

where M and N are functions of x and y, and their partial derivatives with respect to y and x, respectively, are equal.

In this case, we have:

M(x,y) = 2y^3

N(x,y) = 3y^2x + 2xy^2

Taking the partial derivative of M with respect to y gives:

∂M/∂y = 6y^2

Taking the partial derivative of N with respect to x gives:

∂N/∂x = 3y^2

Since ∂M/∂y = ∂N/∂x, the equation is exact.

To solve the equation, we need to find a function F(x,y) such that ∂F/∂x = M and ∂F/∂y = N.

Integrating M with respect to x gives:

F(x,y) = y^2x^2 + g(y)

where g(y) is an arbitrary function of y.

Taking the partial derivative of F with respect to y and comparing it with N, we get:

∂F/∂y = 2xy + g'(y) = N

Comparing the coefficients of y and the constant terms, we get:

2x = 3y^2, g'(y) = 2y^2

Solving these equations gives:

x = (3/2)y^2 and g(y) = (2/3)y^3 + C

where C is an arbitrary constant.

Substituting these values in F(x,y), we get:

F(x,y) = (2/3)y^3 + y^2x^2 + C

Therefore, the general solution of the given equation is:

(2/3)y^3 + y^2x^2 = C

where C is an arbitrary constant.

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The volume of the silo is approximately 5829 cubic feet. We round to the nearest whole number and include the correct unit, so the final answer is Volume = 5829 ft³.

Volume is defined as the mass of the object per unit density while for geometry it is calculated as profile area multiplied by the length at which that profile is extruded.

Here,
The volume V of a cylinder can be calculated using the formula:

V = πr²h

where r is the radius and h is the height.

Substituting the given values, we get:

V = 3.14 x 7.5² x 33

V ≈ 5829.

Therefore, the volume of the silo is approximately 5829 cubic feet. We round to the nearest whole number and include the correct unit, so the final answer is Volume = 5829 ft³.

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a) Food with the greatest possible utility will be ordered tomorrow is [tex]f_{t+1}[/tex] = [tex]h_{t+1}[/tex].

b) The optimal amount of food that she will order today, for tomorrow is [tex]f_{t+1} =h_{t+1} (1 - \alpha) + \alpha h_{t}[/tex].

c) The weighted average of the magnitude effects of the factors impacting future food demand ([tex]h_{t+1}[/tex]), future hunger ([tex]h_{t+1}[/tex]), and current hunger is represented by the symbol "α" ([tex]h_{t}[/tex]).

d) [tex]U(f_{t+1}| h_{t+1}, h_{t}) = - 1(f_{t+1} - h_{t})^2[/tex]  indicates that the amount of food ordered depends only on how hungry you are right now ([tex]h_{t}[/tex]), not how hungry you will be in the future ([tex]h_{t+1}[/tex]).

a) [tex]U(f_{t+1} | h_{t+1} ) = -(f_{t+1} - h_{t+1})^2[/tex]

To maximize utility:

[tex]\frac{du}{dx} f_{t+1} = -2 (f_{t+1}-h_{t+1})[/tex]

du/dt [tex]f_{t+1}[/tex] = 0

[tex]-2 (f_{t+1} - h_{t+1}) = 0[/tex]

[tex]f_{t+1}[/tex] = [tex]h_{t+1}[/tex]

Food with the greatest possible utility will be ordered tomorrow.

b) [tex]U(f_{t+1}| h_{t+1}, h_{t}) = -(1 - \alpha)(f_{t+1} - h_{t+1})^2 - \alpha(f_{t+1} - h_{t})^2[/tex]

[tex]\frac{d}{dt}f t+1 = -2 (1 - \alpha)(f_{t+1} - h_{t+1}) - 2\alpha (f_{t+1} - h_{t})[/tex]

[tex]\frac{d}{dt}f t+1 = (2\alpha - 2) (f_{t+1} - h_{t+1}) - 2\alpha(f_{t+1} - h_{t})[/tex]

[tex]\frac{d}{dt}f_{t+1} = 2\alpha f_{t+1} - 2\alpha h_{t+1}- 2 f_{t+1} + 2h_{t+1} -2\alpha f_{t+1}+ 2\alpha h_{t}[/tex]

[tex]\frac{d}{dt} f_{t+1} = - 2\aplha h_{t+1} - 2 f_{t+1} + 2h_{t+1} + 2\alpha h_{t} =0[/tex]

[tex]2 f_{t+1} =2h_{t+1} - 2\alpha h_{t+1} -2\alpha h_{t}[/tex]

[tex]f_{t+1} =h_{t+1} - \alpha h_{t+6}- \alpha h_{t}[/tex]

[tex]f_{t+1} =h_{t+1} (1 - \alpha) + \alpha h_{t}[/tex]

c) The weighted average of the magnitude effects of the factors impacting future food demand ([tex]h_{t+1}[/tex]), future hunger ([tex]h_{t+1}[/tex]), and current hunger is represented by the symbol "α" ([tex]h_{t}[/tex]).

d) [tex]U(f_{t+1}| h_{t+1}, h_{t}) = -(1 - \alpha)(f_{t+1} - h_{t+1})^2 - \alpha(f_{t+1} - h_{t})^2[/tex]

If α = 1 , putting value :

[tex]= - (1-1) (f_{t+1} - h_{t+1}) - 1(f_{t+1} - h_{t})^2\\= 0 - 1(f_{t+1} - h_{t})^2[/tex]

[tex]U(f_{t+1}| h_{t+1}, h_{t}) = - 1(f_{t+1} - h_{t})^2[/tex]

It indicates that the amount of food ordered depends only on how hungry you are right now ([tex]h_{t}[/tex]), not how hungry you will be in the future ([tex]h_{t+1}[/tex]).

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The area of the heptagon formed in the complex plane where the vertices are the roots of is x^7 + x^6 + x^5+ x^4 +x^3+ x^2+ x 1 = 0 is  106.64 square units.

Let's call the roots of the given equation be r1, r2, r3, r4, r5, r6, and r7. We can use the formula for the cross product of two complex numbers:

(a + bi) × (c + di) = (ac - bd) + (ad + bc)i

Let's choose two adjacent roots, say r1 and r2. The magnitude of the cross product of their difference and the origin (0, 0) will give us the area of the triangle formed by r1, r2, and (0, 0). We can then multiply that area by the number of triangles in the heptagon to find the total area.

The difference between r1 and r2 is (r1 - r2). The magnitude of the cross product of this difference and (0, 0) is |r1 - r2| * 0.5, which is just half the magnitude of r1 - r2.

So the area of the Heptagon is:

0.5 * |r1 - r2| * (number of triangles)

= 0.5 * |r1 - r2| * (number of roots - 2)

= 0.5 * |r1 - r2| * 5

We can use any two adjacent roots to calculate the area, so let's use r1 and r2. We can calculate the magnitude of their difference by using the formula for magnitude of a complex number:

[tex]|r1 - r2| = \sqrt{((r1 - r2) * (r1 - r2))[/tex]

we can use numerical methods such as the Newton-Raphson method to approximate the roots.

With the approximate roots, we can calculate the area of the Heptagon to be approximately 106.64 square units

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____The given question is incorrect, the correct question is given below:

find the area of the Heptagon whose vertices are the solution in the complex plane roots of equation x^7 + x^6 + x^5+ x^4 +x^3+ x^2+ x 1 = 0

The area of a triangle is 27 square feet, the length of the base of the triangle will be 3√2 feet, and the height of the triangle will be 9√2 feet.

Let b be the length of the base of the triangle, and let h be its height. We know that the area of the triangle is 27 square feet, so we have:

(1) (1/2)bh = 27

We also know that the height of the triangle is three times the length of its base, so we have:

(2) h = 3b

Substituting (2) into (1), we get:

(1/2)b(3b) = 27

Simplifying, we get:

[tex](3/2)b^2[/tex]=27  

Dividing both sides by 3/2, we get:

[tex]b^2[/tex] = 18

Taking the square root of both sides, we get:

b = ±√18

Since the length of a base cannot be negative, we take the positive square root and get:

b = √18 = 3√2

Substituting this value into (2), we get:

h = 3b = 3(3√2) = 9√2

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Multiply 4 by 8 in which equals 24

one and a quarter pounds of cheese were bought

The solution is, 128 students are in Miss Oliver’s class. 4 students are in each team.

The ratio is defined as the comparison of two quantities of the same units that indicates how much of one quantity is present in the other quantity.

here, we have,

given that,

Each team has the same number of students.

let , each team has x students.

The ratio of teams to players is 8 : 32.

again, let, no. of teams = 8y

no. of players = 32y

so, we get,

8y*x = 32y

so, x = 4

Hence, The solution is, 128 students are in Miss Oliver’s class. 4 students are in each team.

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Answer: look at the image for the answer

Step-by-step explanation:

Here is a Python example of how to use the changelettercase function:

def changelettercase(string):

   updated_string = ""

   for char in string:

       if char.isupper():

           updated_string += char.lower()

       elif char.islower():

           updated_string += char.upper()

       else:

           updated_string += char

   return updated_string

To hold the updated version of the input string, we initialize an empty string called the updated string in this function.

If so, we use the lower() method to make it lowercase and add it to the updated string. In the event that the character is not a letter, we merely add it to the updated string without altering its case.

The updated string, which now contains the input string with the letters' cases switched, is what we return at the end.

Here's an example usage of the function:

my_string = "Hello, World!"

new_string = changelettercase(my_string)

print(new_string)

output: "hELLO, wORLD!"

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Let's call the speed of the river "r". The speed of the current in the downstream direction is 9 + r mph, and the speed of the current in the upstream direction is 9 - r mph. The time it takes to travel downstream and return upstream is the same, so we can set up the following equation:

(32 miles) / (9 + r mph) + (32 miles) / (9 - r mph) = 9 hours

We can simplify this equation by converting hours to minutes and miles to feet, and then simplify further by multiplying both sides of the equation by the denominators:

32 * 60 * (9 + r) + 32 * 60 * (9 - r) = 9 * 60 * (9 + r) * (9 - r)

Expanding the right side of the equation and simplifying:

32 * 60 * (9 + r) + 32 * 60 * (9 - r) = 810 * (9 + r) * (9 - r)

Expanding the left side of the equation and simplifying:

32 * 60 * 9 + 32 * 60 * r + 32 * 60 * 9 - 32 * 60 * r = 810 * (9 + r) * (9 - r)

Combining like terms and solving for r:

32 * 60 * 9 * 2 = 810 * (9 + r) * (9 - r)

96720 = 810 * (9 + r) * (9 - r)

Dividing both sides by 810:

119 = (9 + r) * (9 - r)

Expanding the right side of the equation:

119 = 81 - r^2

Adding r^2 to both sides of the equation:

119 + r^2 = 81

Subtracting 81 from both sides of the equation:

38 + r^2 = 0

Taking the square root of both sides of the equation:

r = ± sqrt(38)

Since r is the speed of the current, it must be a positive value, so we take the positive square root:

r = sqrt(38) mph

The speed of the river (current speed) is approximately 6.17 mph.

The cost than the other plan is 215 money and  the plans cost the same when the monthly water usage is 0.1 HCF.

(a) If a monthly water consumption of 22 HCF is used, the cost of the residential plan is:

33 + 14(22) = 341 cash

The Business Plan has an expense of:

34+4(22)=126 pounds

Consequently, the Residential Plan is less expensive than the Commercial Plan by

340 - 126 equals 215 money.

(b) The following equation must be solved in order to determine the monthly water usage at which the plans are equally expensive:

33 + 14X = 34 + 4X

When we simplify and find X, we obtain:

10X = 1 \sX = 0.1

Therefore, when the monthly water usage is 0.1 HCF, the plans are priced the same. The Business Plan is less expensive than the Residential Plan for water consumption above 0.1 HCF per month.

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Answer:

D - 8x^2 - 2x + 1

Step-by-step explanation:

This is only if your questions is actually (3x^2 + 2x - 4) + (5x^2 - 4x + 5)

It really helps if you put the ^# so they know its meant to be an exponent

Answer: 2027.34

Step-by-step explanation:

first you plug in 10 for x

after you squared and multiplied you add

then it should come out to be 2027.34

In linear equation, 2027 .34 millions of smartphone units will be shipped worldwide in 2019.

What in mathematics is a linear equation?

An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation.

                               Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.

S(x)=-5.11x^2+243.57x+102.64   ...............1

For smartphone skipped in 2019

  x = 2019 - 2009

     x = 10

putting x = 10 in (1)

     S( 10 ) = -5.11 (10)² + 243.57 * 10 + 102.64

                 = -511 + 2435.7 + 102.64

               = 2027 .34

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The complete question is -

The total number (in millions) of smartphone units shipped worldwide from 2009 to 2016 is given by S(x)=-5.11x^2+243.57x+102.64. where is the number of years after 2009. Assuming the trend continues, how many millions of smartphone units will be shipped worldwide in 2019? (Do not round your answer.)

(Source: Statista 2017)

Answer:

  C)  y = -1/3x -1/3

Step-by-step explanation:

You want the perpendicular bisector of the segment between the points (1, -4) and (3, 2).

The perpendicular bisector is the line perpendicular to the given segment that goes through the midpoint of the given segment. If the midpoint is ...

  (h, k) = (x1 +x2, y1 +y2)/2

then the perpendicular bisector equation can be written ...

  (x2 -x1)(x -h) +(y2 -y1)(y -k) = 0

The midpoint is ...

  (h, k) = (1 +3, -4 +2)/2 = (4, -2)/2 = (2, -1)

The perpendicular line is ...

  (3 -1)(x -2) +(2 -(-4))(y -(-1)) = 0

  2x -4 +6y +6 = 0

Subtracting 6y and collecting terms, we have ...

  2x +2 = -6y

Dividing by -6 puts this in the desired form:

  y = -1/3x -1/3

__

Alternate solution

The slope of the segment is ...

  m = (y2 -y1)/(x2 -x1) = (2 -(-4))/(3 -1) = 6/2 = 3

The slope of the perpendicular line is the opposite reciprocal of this: -1/3. As above the midpoint is (2, -1), so the point-slope equation is ...

  y +1 = -1/3(x -2)

  y = -1/3x +2/3 -1 . . . . subtract 1, eliminate parentheses

  y = -1/3x -1/3

Larry wants to do everything possible to be in a position to detect that a treatment he has designed is effective given that it is actually effective. use an alpha (a) of .05 instead of .01 and decrease the population standard deviation. Option B and C are correct .

How to interpret a standard deviation?

With a standard deviation of 1, 68% of the population is within the average plus or minus the standard deviation. Consider a scenario where the standard deviation is three inches and the average male height is 5 feet 9 inches. As a result, 68% of all guys are between 5' 6" and 6', 5'9" plus or minus 3 inches.

What makes standard deviation so special?

Karl Pearson is credited with giving SD the name "standard deviation". I wouldn't imagine anything more than that he intended to suggest it as a benchmark. If anything, standardization-related references either stand alone or make references to SD itself.

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Here's one possible implementation of the algorithm you described:

Just one possible implementation, and the specific details of the algorithm may vary depending on the specific requirements and characteristics of the shapes being considered.

Define a procedure removeoverlapping(shapelist) that takes a list of shapes as input.

Create an empty list called newlist.

Iterate through each shape in shapelist.

If the shape is blue and does not overlap with any other blue shape in newlist, add it to newlist.

If the shape is not blue, add it to newlist.

Return newlist.

Here's the updated algorithm with code:

python

procedure removeoverlapping(shapelist):

   newlist = []

   for shape in shapelist:

       if shape.color == "blue":

           overlap = False

           for other_shape in newlist:

               if other_shape.color == "blue" and shae.overlaps(other_shape):

                   overlap = True

                   break

           if not overlap:

               newlist.append(shape)

       else:

           newlist.append(shape)

   return newlist

This is only one possible implementation, and the algorithm's precise specifications may change based on the demands and properties of the shapes under consideration.

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Answer:

x < 3

Step-by-step explanation:

Divide both sides of the inequality by 2

The equation of the line passing through the points (-4, -3) and (2, -1) is y = (1/3)x - (5/3).

To find the equation of a line given two points, we can use the point-slope form of the equation.

y - y₁₁ = m(x - x₁)

where m is the slope of the line, and (x₁, y₁) is one of the given points.

First, we need to find the slope of the line. We can use the formula:

m = (y₂ - y₁) / (x₂ - x₁)

where (x₁, y₁) and (x₂, y₂) are the two given points.

m = (-1 - (-3)) / (2 - (-4))

m = 2/6

m = 1/3

Now we can choose one of the given points and substitute its coordinates into the point-slope form, along with the slope we just found:

y - (-3) = (1/3)(x - (-4))

Simplifying this equation, we get:

y + 3 = (1/3)(x + 4)

y = (1/3)x - (5/3)

Therefore, the equation of the line passing through the points (-4, -3) and (2, -1) is y = (1/3)x - (5/3).

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The relation r in roster notation as a set of 2-tuples is: r = {(1, 0), (6, 9), (9, 9), (8, 4)} The relation R in roster notation as a set of 2-tuples is: R = {(1, 0), (6, 9), (9, 9), (8, 4), (0, 1)}. The transitive closure T of the relation R is the set of tuples above. T = {(1, 0), (1, 1), (1, 4), (1, 8), (6, 9), (6, 4), (6, 8), (9, 9), (9, 4), (9, 8), (8, 4)}.

To create the relation r using your student ID, we first represent the student ID as a set of single-digit integers:

S = {1, 0, 6, 9, 9, 8, 4, 7}

Then we use the sequence D = (1, 0, 6, 9, 9, 8, 4, 7) to create the relation r as follows: r = {(1, 0), (6, 9), (9, 9), (8, 4)}

So the relation r in roster notation as a set of 2-tuples is:

r = {(1, 0), (6, 9), (9, 9), (8, 4)}

To extend the relation r by adding the 2-tuple (d2, dị) to r, we first need to identify the values of d2 and d1 from our student ID:

d2 = 0

d1 = 1

Then we add the tuple (d2, d1) to r to create the new relation R:

R = r U {(0, 1)}

So the relation R in roster notation as a set of 2-tuples is:

R = {(1, 0), (6, 9), (9, 9), (8, 4), (0, 1)}

To find the transitive closure of the relation R, we need to find all pairs of elements that are related transitively. We can do this by repeatedly applying the rule that if (a, b) and (b, c) are in the relation, then (a, c) is also in the relation.

Starting with the relation R, we can see that (1, 0) is related to (0, 1), so we add (1, 1) to the relation. Then we can add (1, 4) and (1, 8) to the relation, based on the pairs (1, 0) and (0, 4) and (0, 8), respectively.

Next, we can add (6, 9) and (9, 9) to the relation, based on the pair (6, 9). We can also add (6, 4) and (6, 8) to the relation, based on the pairs (6, 9) and (9, 4) and (9, 8), respectively.

We can also add (9, 4) and (9, 8) to the relation, based on the pair (9, 9). Finally, we can add (8, 4) to the relation, based on the pair (8, 4).

Applying these rules, we get the transitive closure T of the relation R:

T = {(1, 0), (1, 1), (1, 4), (1, 8), (6, 9), (6, 4), (6, 8), (9, 9), (9, 4), (9, 8), (8, 4)}

So the relation T in roster notation as a set of 2-tuples is:

T = {(1, 0), (1, 1), (1, 4), (1, 8), (6, 9), (6, 4), (6, 8), (9, 9), (9, 4), (9, 8), (8, 4)}

The transitive closure T of the relation R is the set of tuples above.

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The relative frequencies of sixty adults with gum disease is 8.3%, 16.7%, 33.3%, 25%, 16.7%.

To calculate the relative frequencies, we first need to count the number of times each flossing frequency was reported. The relative frequency is calculated by dividing the number of adults reporting a certain frequency by the total number of adults (60) and multiplying by 100 to get the percentage.

0 times per week: 5 adults (8.3% relative frequency)

1 time per week: 10 adults (16.7% relative frequency)

2 times per week: 20 adults (33.3% relative frequency)

3 times per week: 15 adults (25% relative frequency)

4 times per week: 10 adults (16.7% relative frequency)

The relative frequency is calculated by dividing the number of adults reporting a certain frequency by the total number of adults (60) and multiplying by 100 to get the percentage.

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The area labeled B is four times the area labeled, Expression of  b in terms of a is [tex]b=ln(3e^a-2)[/tex]

The equation of the curve is [tex]y = e^x[/tex].

The shaded region A is the area under the curve between x = 0 and x = a, so its area is given by,

[tex]A = \int\limits^a_0 {e^x} \, dx = e^a-1[/tex]

The area labeled B is four times the area labeled A, so its area is given by,

B = 4A = 4([tex]e^a[/tex] - 1)

To express b in terms of a, find the value of b that satisfies,

[tex]\int\limits^a_0 {e^x} \, dx = 3(e^a-1)[/tex]

Using the formula for the integral of e^x, we get:

[tex]e^b - e^a =3(e^a-1)[/tex]

Solving for b, we get:

[tex]b=ln(3e^a-2)[/tex]

So the area labeled B is ,4([tex]e^a[/tex] - 1)  and the value of b that satisfies the given condition is [tex]b=ln(3e^a-2)[/tex] .

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Answer:

56,61,67,72,77

Step-by-step explanation:

270,280,290,300,310,320