Answer: they have one path to flow
Explanation: share the same current
A rollercoaster accelerates from 10 m/s to 100 m/s2 for 25 seconds. What is the acceleration?
Answer:
A roller coasters accelerates from an initial velocity of of 6.0 m/s to a final velocity of 70 m/s over 4 seconds. What's the acceleration? Q. Acceleration only takes place when things speed up. Q. A drag racer accelerated from 0 m/s to 200 m/s in 5 s.
Explanation:
8/10
A person stands on a square pedestal whose side lengths are
1.20 m. The person and pedestal together weigh 1.84 x 103 N.
What is the pressure the person and and pedestal exert on the
floor in Pa?
Answer:
Explanation:
P = 1.84 x 10³ N / 1.20² m² = 1,277.77777... N/m²
P = 1.28 x 10³ Pa
help me i have little time left i will give brainliest
Answer:
Explanation:
Conservation of momentum
Initial momentum is zero
3.0(6.0) + 7.0v = 0
v = -18/7 = - 2.57142857...
|v| = 2.6 m/s
Anita Knapp needs to get hay to cows in a frozen field using an airplane flying 80.0 m/s, at a height of 300,m. If at the last minute, how far from the cow would she have to release the hay in order to hit the cow? *
Answer:
Explanation:
If we ignore wind resistance, the time needed for the hay to drop from vertical rest is
t = √(2h/g) = √(2(300)/9.81) = 7.82 s
d = vt = 80.0(7.82) = 626 m before passing over the cow.
A 1250 kg car is stopped at a traffic light. A 3550 kg truck moving at 8.33 m/s strikes the car from behind, causing the bumpers to lock together.
A) What is the momentum of the car-truck system before the collision?
B) What is the momentum of the car-truck system after the collision?
C) How fast do the car and truck move after the collision?
(Do NOT put any links or reproductions, I just need help with this.)
A) Before the collision, the total momentum is
(1250 kg) (0 m/s) + (3550 kg) (8.33 m/s) ≈ 29,600 kg•m/s
B) Momentum is conserved, so after the collision it is still approximately 29,600 kg•m/s.
C) If v is the speed of the locked car-truck system, then
(1250 kg) (0 m/s) + (3550 kg) (8.33 m/s) = (1250 kg + 3550 kg) v
Solve for v :
29,571.5 kg•m/s = (4800 kg) v
v ≈ 6.16 m/s
A 70 kg man is running up the stairs which is 3m high in 2s.(a)How much work is done by the man?(b)What is the power exerted by the man? (Use g = 10ms 2)
Explanation:
m = 70 kg
s = 3m
t =2s
g = 10 m/s²
(a)How much work is done by the man?
W = Fs
= mg X s
= 70 x 3 x 10
= 210 x 10
= 2100 Joule
(b)What is the power exerted by the man?
P = W/t
= 2100/2
P = 1050 Watt
Please help me answer the following image!
explain how gravitational erosion changes landforms
Answer:
Gravity can pull soil, mud, and rocks down cliffs and hillsides.
Explanation:
Gravity is responsible for erosion by flowing water and glaciers. But gravity also causes erosion directly. This type of erosion and deposition is called mass wasting.
Answer:
Erosion is another geological process that creates landforms. When mechanical and chemical weathering breaks up materials on the Earth's surface, erosion can move them to new locations. For example, wind, water or ice can create a valley by removing material. This can create new landforms.Explanation:
Hope this helps !!imagine that you have an electric car and all of the recaptured energy is put back into the battery that powers your car what speed could your car cheat from rest by using only the recaptured energy from part B
Answer:
Moving vehicles have a lot of kinetic energy, and when brakes are applied to slow a vehicle, all of that kinetic energy has to go somewhere.
Explanation:
Destination is your Destination
Answer:
woah awesome so cool
Explanation:
Answer:
woah excellent!
That’s easy please tell me!
6. The first vertebrates appeared during
a. Precambrian time
b. the Paleozoic Era
C. the Mesozoic Era
d. The Cenozoic Era
Answer:
b. the Paleozoic Era
Explanation:
The first vertebrates to appear are primitive fish in the Cambrian Period, but bony fishes with actual bony vertebratae didn't appear for another 100 million years. The Cambrian Period is the first of three periods in the Paleozoic Era. The Cambrian explosion was an event when practically all major animal phyla started appearing in the fossil record.
A change
1. Ricardo has purchased a forklift for his business. The forklift can put out 4950 W of power. If the forklift is operating at full capacity, how much work can it do in 2.40 seconds?
O 2060)
O 4950)
O 6490)
O 11,900
The work done if the forklift is operating at full capacity is 11,900 J.
We have to recall that power is defined as the rate of doing work. The rate of doing work is defined as;
Power = Work done/time taken
When;
Power = 4950 W
Time taken = 2.40 s
Work done = Power × time taken
Work done = 4950 W × 2.40 s
Work done = 11,900 J
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A common type of succession that occurs on a surface where an ecosystem has previously existed
a car moves at a speed of 30m/s to the west of 3hr, what is its displacement of the car in km?
Answer:
Explanation:
30 m/s • 3 hr •3600 s/hr / 1000 m/km = 324 km west
Which of the following changes would decrease the force between two charged particles by a factor of 9? A. Decreasing the distance between the particles by a factor of 3 B. Increasing the distance between the particles by a factor of 3 C. Increasing the amount of charge on each particle by a factor of 9 D. Decreasing the amount of charge on one of the particles by a factor of 3
Option B is correct.Increasing the distance between the particles by a factor of 3 decrease the force between two charged particles by a factor of 9.
What is electric force?The electric force between the two charges is directly proportional to the product of the charge and inversely proportional to the square of the distance between them.
The electric force is found as;
[tex]\rm F = \frac{K q_1q_2}{r^2}[/tex]
The electric force between the two charges is directly proportional to the product of the charge.
The electric force is inversely proportional to the square of the distance between them.
Increasing the distance between the particles by a factor of 3 decreases the force between two charged particles by a factor of 9
Hence, option B is correct.
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if it takes a track runner 2.16 seconds to reach a speed of 5.31 m/s from the start of a race, what is the runners acceleration?
Answer:
Explanation:
Answer:
Explanation:
An RLC circuit is used in a radio to tune into the radio lagos fm Station broadcasting at 93.5Hz. The resistance is 15ohms and the inductance is 1.6 H. Calculate the capacitance used
The characteristics of the RLC circuit allow to find the result for the capacitance at a resonance of 93.5 Hz is:
Capacitance is C = 1.8 10⁻⁶ F
A series RLC circuit reaches the maximum signal for a specific frequency, called the resonance frequency, this value depends on the impedance of the circuit.
[tex]Z^2 = R^2 + ( wL - \frac{1}{wC} )^2[/tex]
Where Z is the impedance of the circuit, R the resistance, L the inductance, C the capacitance and w the angular velocity. The negative sign is due to the fact that the current in the capacitor and the inductor are out of phase.
In the case of resonance, the impedance term completes the circuit as a resistive system.
[tex]wL - \frac{1}{wC} = 0 \\w^2 = \frac{1}{LC}[/tex]
Indicate that the inductance L = 1.6 H and the frequency f = 93.5 Hz.
Angular velocity and frequency are related.
w = 2π f
Let's substitute.
[tex]C = \frac{1}{L ( 2 \pi f)^2 }[/tex]
Let's calculate.
[tex]C = \frac{1}{1.6 \ ( 2\pi \ 93.5)^2}[/tex]
C = 1.8 10⁻⁶ F
In conclusion with the characteristics of the RLC circuits we can find the result for the capacitance at a 93.5 Hz resonance is:
Capacitance is C = 1.8 10⁻⁶ F
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During a car accident on the NJ Turnpike, the airbags deploy. A 79 kg passenger traveling at 32 m/s makes impact with the airbag over a time of 0.25 seconds. What
was the impact force experienced by the passenger?
Hi there!
Recall that:
Impulse = Δ in momentum = mΔv
Impulse = Force · time
Begin by calculating the change in momentum, or impulse.
I = mΔv = m(vf - vi)
I = (79)(0 - 32) = -2528 Ns
Now, we can use the equation relating force and time to impulse.
I = Ft
Rearrange for time:
I/F = t
-2528/0.25 = -10112 N
**OR, if magnitude ⇒ |-10112| = 10112 N
How is the çhocolate shell on the outside of the bar different from the ice cream on the inside?
Answer:
Cake Crunch (Enriched Wheat Flour [Bleached Flour, Niacin, Reduced Iron, Thiamine Mononitrate, Riboflavin, Folic Acid]), Sugar, Vegetable Shortening [Partially Hydrogenated Soybean and Cottonseed Oil], Salt, Sodium Bicarbonate, Artificial Flavor, Soy Lecithin, Soybean Oil, Coconut Oil, Sugar, Chocolate Liquor, ...
4. If a charged body is negatively charged, it has excess of _______
Answer:
Electrons
Explanation:
Electrons are negatively charged sub-atomic particles, therefore when a body's negatively charged, it means that there's more electrons than protons.
a rocket ship is moving through space at 1000 m/s. It accelerates in the same direction at 4m/s/s. What is its speed after 100 seconds
Answer:
Acceleration = (final velocity - starting velocity) / time
4 = (x-1000) / 100
<br/>x = 1400 m/s
Explanation:
The final velocity of the rocket ship which is moving with an initial velocity of 1000 m/s and acceleration of 4 m/s² after 100 seconds is 1400 m/s.
What is velocity?Velocity of a moving body is the rate of its speed. Mathematically velocity is the ratio of distance travelled to the time taken with a unit of m/s. Acceleration is the rate of change in velocity of moving body. The unit of acceleration is 4 m/s² .
Thus acceleration can be determined from the change in velocity with respect to the change in time. Now, the relation between initial velocity, acceleration, a and time, t with the final velocity is written in the equation below:
v = u + at.
Where, v is the final velocity and u be the initial velocity.
Given here the initial velocity is 1000 m/s. Acceleration of the rocket is 4 m/s² . Thus the velocity after 100 seconds is calculated as follows:
v = 1000 m/s + ( 4 m/s² × 100 s )
= 1400 m/s.
Hence, the speed of the rocket after 100 seconds will be 1400 m/s.
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How do we become children of Abraham and sons of God?
Answer:
we already are.
Explanation:
God created us, and we are the descendants of Abraham. if you want to choose to live against it, you'll be doing something similar to fighting a current. gods love is unfathomable. he is the only true God, and is our father in heaven.
Help on 9 and 10!!!!!! I’ll give 5 starts
Answer: part a is e
part b a
Explanation:
I HOPE THIS HELPS
A wheel has a radius of r = 2.0 m and it rolls down a smooth incline. The height of the incline is h = 8.0 m . What is the angular velocity ω of the wheel at the bottom of the incline?
Express your answer in radians per second.
The angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec
The angular velocity (ω) of an object is the rate at which the object's angle position is changing in relation to time.
For a wheel attached to an incline angle, the angular velocity can be computed by considering the conservation of energy theorem.
As such the total kinetic energy (K.E) and rotational kinetic energy (R.K.E) at a point is equal to the total potential energy (P.E) at the other point.
i.e.
P.E = K.E + R.K.E
[tex]\mathbf{mgh = \dfrac{1}{2}m(r \times \omega)^2 + \dfrac{1}{2}\times I \times \omega^2}[/tex]
[tex]\mathbf{gh = \dfrac{1}{2}(r \times \omega)^2 + \dfrac{1}{2}\times r^2 \times \omega^2}[/tex]
[tex]\mathbf{2 \times \dfrac{gh}{r^2} =\omega^2 + \omega^2}[/tex]
[tex]\mathbf{2 \omega^2=2 \times \dfrac{9.81 \times 8 m }{2.0 ^2} }[/tex]
[tex]\mathbf{\omega^2=\dfrac{39.24 }{2}}[/tex]
[tex]\mathbf{\omega=\sqrt{19.62 } \ rad/sec}[/tex]
[tex]\mathbf{\omega=4.429 \ rad/sec}[/tex]
Therefore, we can conclude that the angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec
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The angular velocity of the wheel depends on the mass, radius and the
mode of rotation of the wheel (with or without slipping).
The angle velocity at the bottom of the incline, ω ≈ 4.43 rad/secReasons:
The given parameters are;
Radius of the wheel, r = 2.0 m
Height of the incline, h = 8.0 m
Required:
Angular velocity of the wheel at the bottom of the incline.
Solution:
The potential energy of the wheel at the top of the hill, P.E. = m·g·h
[tex]Sum \ of \ the \ kinetic \ energy \ of \ the \ wheel, \ K.E. = \mathbf{\displaystyle \frac{1}{2} \cdot m \cdot v^2 + \frac{1}{2} \cdot I \cdot \omega ^2}[/tex]
Where;
v = The translational velocity of the wheel = ω·r
I = The moment of inertia of the wheel = m·r²
Therefore'
[tex]Sum \ of \ K.E. = \displaystyle \frac{1}{2} \cdot m \cdot (\omega \cdot r)^2 + \frac{1}{2} \cdot m \cdot r^2 \cdot \omega ^2 = \mathbf{m \cdot r^2 \cdot \omega^2}[/tex]
At the bottom of the hill, the potential energy is converted to kinetic energy
Therefore;
P.E. = Sum of K.E.
m·g·h = m·r²·ω²
g·h = r²·ω²
[tex]\displaystyle \omega = \sqrt{ \frac{g \cdot h}{r^2} } = \mathbf{ \frac{\sqrt{g \cdot h} }{r}}[/tex]
Where;
g = Acceleration due to gravity ≈ 9.81 m/s²
Therefore;
[tex]\displaystyle \omega = \frac{\sqrt{9.81 \times 8} }{2} \approx \mathbf{ 4.43}[/tex]
The angular velocity of the of the wheel at the bottom of the incline, ω ≈ 4.43 rad/secLearn more about the law of conservation of energy here:
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Two forces act on a block as shown in the picture. What is the net force of the block?
30 N to the right
30 N to the left
10 N to the left 10
10 N to the right
Answer:
10 N to the left.
Explanation:
Since the forces are acting in opposite directions, you need to calculate the difference.
20 N - 10 N = 10 N
More force is being exerted to the left. Therefore, the net force is 10 N to the left.
The maximum speed with which an 1000 kg car makes a 180-degree turn is 10 m/s. The radius of the circle through which the car is turning is 24 m. Determine the force of friction and the coefficient of friction acting upon
the car.
As a truck rounds a curve, a box in the bed of the truck slides to the side farthest from the center of the curve. This movement of the box is a result of
Answer:
inertia .
because yes
Suppose you want to make the demonstration more dramatic by attracting as much hair as possible with the balloon. Which of the following is the best choice to accomplish your goal? A. Decrease the electric force by holding the balloon closer to the hair. B. Increase the electric force by rubbing the balloon for a longer period of time. C. Decrease the electric force by using a larger balloon. D. Increase the electric force by holding the balloon farther away from the hair.
Answer:
B. Increase the electric force by rubbing the balloon for a longer period of time.
Explanation:
esse is swinging Miguel in a circle at a tangential speed of 3.50 m/s. If the radius of the circle is
0.600 m and Miguel has a mass of 11.0 kg, what is the centripetal force on Miguel? Round to the nearest whole number.
Answer:
Explanation:
F = mv²/R
F = 11.0(3.50²)/0.600 = 225 N