Which statement correctly describes the relationship between air temperature and air pressure?

-Warm air rises, creating an area of low pressure.

-Cool air sinks, creating an area of low pressure.

-Warm air sinks, creating an area of low pressure.

-Cool air rises, creating an area of low pressure.

Answers

Answer 1
warm air rises, creating an area of low pressure

Related Questions

Kyra and Pari are timing how long it takes for 1 g of sugar to dissolve in hot water. Kyra records a time of 24.3 seconds. Pari records a time of 24 seconds. Whose reading is more precise? Why?

Answers

Answer:we can say that:-A reading with more no of significant figures is considered to be more precise.Kyra recorded a reading of 24.3 sec. Since all non 0 digits are considered to be significant this reading has 3 significant figures.Pari recorded a reading of 24 sec. Since all non 0 digits are considered to be significant this reading has 3 significant figures.hence we can say that kyra's reading has more significant figures nd so it is more precise.

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Answers

Answer:

3

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why joule is called derived unit? ​

Answers

Answer:

It is also the energy dissipated as heat when an electric current of one ampere passes through a resistance of one ohm for one second. It is named after the English physicist James Prescott Joule (1818–1889).

Explanation:

7. a. How is speed related to kinetic energy?​

Answers

Increase in speed leads to increase in kinetic energy

AWARDING BRAINLIEST
Compared to water, most metals have low specific heats.



Please select the best answer from the choices provided


T

F

Answers

The answer for the question is True

Answer:

it is true

Explanation:

i think so

not really sure

The reason that worlds like the Earth are differentiated is that Group of answer choices the heat of the Sun vaporized much of their solid material early on the heaviest chunks that hit early on were able to bore through solid rock to the center the continuing impacts on a growing protoplanet eventually melted the entire body large amounts of hydrogen and helium collect around such planets a little later in their history planetesimals with different types of composition hit at different times, with the heaviest ones hitting first

Answers

Answer:

A differentiated body is a body that has been heated to the point where it is are further from the sun larger have no solid surface and have many more moons  Smaller chunks of material vaporize completely as they pass through its atmosphere

Explanation:

Hope it helps..

A body is said to be differentiated when it has been heated to the extent where it is bigger, farther from the sun, has no hard surface, and has a lot more moons. Smaller pieces of the materials entirely evaporate as they pass through their environment.

What is Planet?

An enormous, spherical celestial object known as a planet is neither a star nor a remain. The nebular theory, which states that an interstellar cloud collapses out of a nebula to form a young protostar that orbits the sun by a protoplanetary disk, is now the best argument for planet formation. By slowly accumulating material under the influence of gravity, or accretion, planets form in this disk.

The terrestrial planets Mercury, Venus, Earth, and Mars, as well as the planetary nebulae Jupiter, Saturn, Uranus, and Neptune, total at least eight planets in the Solar System. These planets all rotate around axes that seem to be inclined relative to their corresponding polar axes.

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Forms of energy! Write a brief summary about each form of energy below.
Mechanical:
Thermal:
Chemical:
Electromagnetic:
Electrical:
Nuclear:

Answers

Answer:

Hope this helps!! :D

Explanation:

Mechanical energy is power that an object gets from its position and motion. the energy released during nuclear fission or fusion, typically to make electricity.

Thermal energy is the energy given off by hot things like fire.

Chemical energy is energy stored in the bonds of chemical compounds.

Electromagnetic energy is a form of energy that is reflected or emitted from objects in the form of electrical and magnetic waves that can travel.

Electrical energy is energy derived from electric potential energy or kinetic energy.

Nuclear energy is the energy released during nuclear fission or fusion, typically used to generate electricity.

A circus stuntman holds himself straight out by his arms from a vertical pole. If the stuntman's center of gravity is located 0.75 m away from the pole and he weights 650 N, how much force do is arms have to apply if they exert their force upwards at 0.10 m away from the pole? [4875 N]

Answers

Answer: 4875 N

Explanation:

Given

Stuntman weight is [tex]W=650\ N[/tex]

His center of gravity is located at [tex]x=0.75\ m[/tex] away from pole

If he applies an upwards force at 0.10 m away from the pole

Suppose  F is the applied force

To remain vertical, the torque of weight must be canceled by the vertical force

[tex]\Rightarrow 650\times 0.75-F\times 0.10=0\\\\\Rightarrow 650\times 0.75=F\times 0.10\\\\\Rightarrow F=\dfrac{487.5}{0.10}=4875\ N[/tex]

briefly discuss university need based scholarships and explain them.​

Answers

Answer: Scholarships are given to reduce the burden of finance to be payed for academics and learning.

Explanation:

The need based scholarships are given in the following matters:

1. Research based scholarships: Scholarships should be given to meritorious students to conduct research in a particular discipline.

2. Student fails to submit fees: The student if meritorious and family is not able to fees then university can either postpone the date for fees payment or can give some concession in fees or fund the student fees for a tenure. It is a kind of scholarship for meritorious students.

3. Teacher scholarships: Teachers are allowed to learn new teaching methodologies with other institutions so that they can help students to learn well. They are provided with scholarships to avail admission in those institutions.

When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 84.0-kg man just before contact with the ground has a speed of 6.82 m/s. (a) In a stiff-legged landing he comes to a halt in 4.56 ms. Find the magnitude of the average net force that acts on him during this time. (b) When he bends his knees, he comes to a halt in 0.254 s. Find the magnitude of the average net force now. (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of the forces, find the magnitude of the force applied by the ground on the man in part (b).

Answers

Answer:

a)  F = 1.26 10⁵ N,  b)  F = 2.255 10³ N, c)   F_ {soil} = 3078 N

Explanation:

For this exercise we will use the relationship between momentum and moment

          I = Δp

          F t = p_f -p₀

a) with stiff legs, final speed is zero, initial velocity is down

         Ft = 0-p₀

         F =  m v / t

let's calculate

         F = 84.0 6.82 / 4.56 10⁻³

         F = 1.26 10⁵ N

         

b) bending the legs

         

let's calculate

         F = 84.0 6.82 / 0.254

         F = 2.255 10³ N

     

c) It is requested to calculate the force of the ground on the man

            ∑ F = F_soil -W

           F_soil = F + W

           F_ {soil} = 2.255 103 + 84 9.8

           F_ {soil} = 3078 N

Michael is driving to Starbucks from his house. He walks 9 miles South to pick up his latte. He then drives 10 miles east to COHEA. What is the displacement of Devin?

Answers

Answer:

Displacement = [tex]13.45\ \text{miles}[/tex]

Explanation:

Given that,

Michael walks 9 miles South to pick up his latte. He then drives 10 miles east to COHEA.

We need to find the displacement of Michael. We know that displacement is the shortest path covered by the object. In this case, it is given by :

[tex]d=\sqrt{10^2+9^2} \\\\d=13.45\ \text{miles}[/tex]

So, the displacement of Michael is equal to [tex]13.45\ \text{miles}[/tex].

Suppose to a scientist was able to construct a barometer with a liquid being twice denser than mercury, then how would the liquid raise at standard pressure?​

Answers

Answer:

           h = h₀/2,  the liquid column rises half the height

Explanation:

Pressure is defined as force per area,  

         P = F / A

in a barometer the force is the weights of the liquid column

         F = W = mg

         P = m g/A

if we use the definition of density

         ρ = [tex]\frac{m}{A h}[/tex]

         [tex]\frac{m}{A}[/tex] = ρ h

we substitute

         P = ρ g h

Let's use the index o for the mercury

         P₀ = ρ₀ g h₀

when we change the liquid for another with

          ρ = 2ρ₀

the pressure expression is

         P = 2ρ₀ g h

in the problem they indicate that the pressure is equal to the initial P = P₀

we substitute

           ρ₀ g h₀ = 2ρ₀ g h

           h₀ = 2h

           h = h₀/2

the liquid column rises half the height

What is the transfer of energy that occurs when a force causes an object to move?
O Energy
Force
Power
O Work

Answers

Answer:

huh? I think it's Power.....

Plzzzz help hurry plzzzzzz plzzz

Answers

Answer:

The first one is C, and the second is not clear please show another photo

Explanation:

n the railroad accident, a boxcar weighting 200 kN and traveling at 3 m/s on horizontal track slams into a stationary caboose weighting 400 kN. The collision connects the caboose to the car, and then both move together and you have found the final velocity. Apparently, initial kinetic energy of the system changes (in part, because of friction present). How much energy (in kJ) is transferred from kinetic energy to other forms of energy (e..g., thermal) in the collision

Answers

Answer:

ΔK = -6 10⁴ J

Explanation:

This is a crash problem, let's start by defining a system formed by the two trucks, so that the forces during the crash have been internal and the moment is preserved

initial instant. Before the crash

        p₀ = m v₁ + M 0

final instant. Right after the crash

        p_f = (m + M) v

        p₀ = p_f

        mv₁ = (m + M) v

        v = [tex]\frac{m}{m+M} \ v_1[/tex]

     

we substitute

        v = [tex]\frac{20}{20+40}[/tex]   3

        v = 1.0 m / s

having the initial and final velocities, let's find the kinetic energy

        K₀ = ½ m v₁² + 0

        K₀ = ½ 20 10³ 3²

        K₀ = 9 10⁴ J

        K_f = ½ (m + M) v²

        K_f = ½ (20 +40) 10³  1²

        K_f = 3 10⁴ J

the change in energy is

       ΔK = K_f - K₀

       ΔK = (3 - 9) 10⁴

       ΔK = -6 10⁴ J

The negative sign indicates that the energy is ranked in another type of energy

In a ride in an amusement park, a carriage of mass 450 kg is travelling horizontally at a speed of 18 m/s. It passes through a shallow tank containing stationary water. The tank is of length 9.3 m. The carriage leaves the tank at a speed of 13 m/s. PT 3 a.) Calculate the change in kinetic energy of the cart while it passes through the water tank J (Hint: Change

Answers

Answer:

98.

Explanation:

divide

The change in the kinetic energy of the cart is equal to 34875 J.

What is kinetic energy?

The energy which is possessed by a moving body because of its motion is known as kinetic energy. Work should be done in order to bring the change in the kinetic energy of a moving object.

The kinetic energy of a moving object can be determined from the formula mentioned below:

K.E. = ½mv²     where ‘m’ and 'v' is the mass and velocity of the object.

Given, the mass of the carriage, m = 450 Kg

The speed of the carriage, u = 18 m/s

The initial kinetic energy of the cart = (1/2) × 450 × (18)²

(K.E.)₁ = 72900 J

The final speed of the cart, v = 13 m/s

The final kinetic energy of of the cart = (1/2) × 450 × (13)²

(K.E.)₂ = 38025 J

The change in the kinetic energy of the cart = (K.E.)₂ - (K.E.)₁

Change in the kinetic energy = 72900 - 38025 = 34875 J

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Daylon's family just bought a new puppy, and Daylon decided to take him for a walk. He put the puppy in a wagon and pulled the wagon along the sidewalk. From which of these reference points does the puppy appear to be moving? 1. Daylon 2. The wagon 3. The sidewalk 4. The puppy's collar​

Answers

The puppy was not moving relative to Daylon, the wagon, or his collar.

He was moving relative to a point on the sidewalk.

Note that the puppy did NOT get his walk.

Complete the following sentence.

An animal’s genetic and observable traits are called the
_and_
dont have options

Answers

Answer:

Dominant and recessive

Explanation:

This is like 6th-grade stuff man

What would be the wavelength of the sound
when it travels through the concreate wall
with the frequency of 4500 hertz?​

Answers

Answer: 0,96 m

Explanation: speed in concrete is 4300 m/s

According to wave equation speed v = lambda × frequency

Lambda = speed /frequency

What is the speed of a 1600kg car if its momentum is 120,000kgms?

Answers

Answer:

Velocity of car = 75 m/s

Explanation:

Given:

Mass = 1,600 kg

Momentum = 120,000kgm/s

Find:

Velocity of car

Computation:

Velocity = Momentum / mass

Velocity of car = 120,000 / 1,600

Velocity of car = 75 m/s

PLZZZZZZZZZ HELPPPPP. BRAINLEST GIVEN What is a force of attraction between an object and the earth due to gravity?

Answers

Answer:

acceleration due to gravity: -9.8 m/s^2

Fg=mass of object*(-9.8)

Explanation:

This is a pretty vague question, but I'll answer as best I can.

All matter has gravity. YOU have gravity, although your gravitational pull is small. So, the force of attraction between the Earth and an object on Earth is modeled as

Force of gravity=(Gravitational constant*mass of object 1*mass of object  2)/distance between objects squared

Note that distance between an object on Earth and Earth is the radius of Earth (distance to Earth's core/center of mass)

Question: Why do you think the door opens, even if it is pushing back at equal force?

Answers

You might think that because action-reaction forces are equal and opposite that they cancel. However, action and reaction force pairs don't cancel because they act on different objects. Forces can cancel only if they act on the same object

will mark the brainiest
why is water poor conductor of heat but food conductor of electricity? pls explain

Answers

Explanation:

water contains dissolved salts which can create ions

Answer:

Water is a poor conductor of heat: Most of the heat will move in a convection current within the water at the top of the test tube, only a small fraction of it will conduct down to the ice cube.

Water doesn't need to have a large amount of impurities to act as a good conductor of electricity; even a small amount of ions can enable a source of water to conduct electric current. In a nutshell, water is able to conduct electricity due to the dissolved ions and impurities within it.

How has the work of various scientists helped us understand and create the current model of the atom?

Answers

Because no body can do all the work alone so there are many things to do.... Many experiments.... data collections... Knowledge sharing.
The first model of the atom was developed by JJ Thomson in 1904, who thought that atoms were composed purely of negatively charged electrons. In 1913, Niels Bohr proposed a model of the atom where the electrons were contained within quantized shells that orbited the nucleus.

if a car exerts a area of 3m and a force of 9N what is the pressure exerted by car

Answers

Answer:

P = 3 Pa

Explanation:

Given that,

Force exerted by the car, F = 9 N

The area of the car, A = 3 m²

We need to find the pressure exerted by the car. We know that pressure is equal to the force per unit area such that,

[tex]P=\dfrac{F}{A}\\\\P=\dfrac{9\ N}{3\ m^2}\\\\P=3\ Pa[/tex]

So, the pressure exerted by the car is equal to 3 Pa.

Which graph best represents the relationship between KE and speed?

A graph with vertical axis K E and horizontal axis Speed with a straight line sloping sharply upward.

A graph with vertical axis K E and horizontal axis Speed with a concave line sloping sharply upward.

A graph with vertical axis K E and horizontal axis Speed with a straight line sloping sharply downward.

A graph with vertical axis K E and horizontal axis Speed with a curved line going first upward and then downward.

Answers

A graph with vertical axis K E and horizontal axis Speed with a straight line sloping sharply upward.

Relationship between kinetic energy and speed

The kinetic energy of an object is directly proportional to the square of its speed which means that if kinetic energy of an object increases the speed of that object is also increases and vice versa so we can conclude that graph with vertical axis K E and horizontal axis Speed with a straight line sloping sharply upward is the right answer.

Learn more about speed here: https://brainly.com/question/4931057

Answer:

The correct answer is:

B.)

Explanation:

I did the assignment on Edge, 2022.

(See the attachment below.)

Hope this helped, good luck on the quiz! :D

If a force of 3000 N can move a crate at an acceleration of 9.2 m/s2, what is the mass of the object?

Answers

Answer:

326 kg

Explanation:

m=f/a

3000/9.2=326 kg

Two people are talking at a distance of 3.0 m from where you are, and
you measure the sound intensity as 1.1'10 W/m. Another student
is 4.0 m away from the talkers. Calculate a reasonable estimate for the
sound intensity that the other student measures.
A) 62' 10-8 W/m2
B) 1.5'10-7 W/m2
8.3' 10-8 W/m2
D) 7.8'10-7 W/m2

Answers

Answer:

The sound intensity that the other student measure, I₂ is expected to be;

A) 6.2 × 10⁻⁸ W/m²

Explanation:

The measure of sound intensity is given by the following formula;

[tex]I = \dfrac{P}{4 \cdot \pi \cdot R^2}[/tex]

[tex]\dfrac{I_2}{I_1} = \dfrac{R_1^2}{R_2^2}[/tex]

Where;

I = The intensity

R = The radius

P = The power of the sound

Whereby we have;

The distance of the two people talking, R₁ = 3.0 m

The measure of the sound intensity, I₁ = 1.1 × 10⁻⁷ W/m² (from an online source)

The distance of the other student from the two people talking, R₂ = 4.0 m

Therefore, the estimate of the sound intensity, I₂, is given as follows;

[tex]{I_2} = \dfrac{R_1^2}{R_2^2} \times {I_1}[/tex]

[tex]{I_2} = \dfrac{(3.0 \, m)^2}{(4.0 \, m)^2} \times 1.1 \times 10^{-7} \ W/m^2 = 6.1875 \times 10^{-8} \ W/m^2[/tex]

I₂ = 6.1875 × 10⁻⁸ W/m²

∴ The sound intensity that the other student measure, I₂ ≈ 6.2 × 10⁻⁸ W/m²

Which factors could be potential sources of error in the experiment? Check all that apply.

energy lost in the lever due to friction
color of the soda bottle used in the experiment
visual estimation of height of the beanbag
temperature of the lab at the time of the experiment
position of the fulcrum for the lever affecting transfer of energy

Answers

Answer:

1. energy lost in the lever due to friction

3. visual estimation of height of the beanbag

5. position of the fulcrum for the lever affecting transfer of energy

Explanation:

Edge 2021

The factors that could be potential sources of error in the experiment are

Energy lost in the lever due to frictionVisual estimation of height of the beanbag Position of the fulcrum for the lever affecting transfer of energy

Options A,C,E

What is an error in the experiment?

Error in the experiment is simply defined as the inaccuracies that prevent us from seeing an entirely correct measurement.

In conclusion, Errors in experiments are inevitable but the average is used to curtail them.

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A student makes a homemade resistor from a graphite pencil 5.00 cm long, where the graphite is 0.05 mm in diameter. The resistivity of the graphite is rho=1.38×10−5Ω/mrho=1.38×10−5Ω/m . The homemade resistor is place in series with a switch, a 10.00-mF uncharged capacitor and a 0.50-V power source. (a) What is the RC time constant of the circuit? (b) What is the potential drop across the pencil 1.00 s after the switch is closed?

Answers

Answer:

(a) RC time constant of the circuit is 6.9 × 10⁻⁶ ms

(b) The potential drop across the capacitor 1.00 s after the switch is closed is 0 V

Explanation:

The given parameters are

The length of the graphite pencil, L = 5.00 cm

The diameter of the graphite, D = 0.05 mm

The resistivity of the graphite, ρ = 1.38 × 10⁻⁵ Ω/m

The capacitance of the capacitor, C = 10.0 mF

The voltage of the power source, V = 0.50-V

(a) The RC time constant of the circuit, τ, is given as follows;

τ = R × C

Where;

R = The resistance of the graphite = L × ρ

C = The capacitance of the capacitor

∴ R = 5.00 cm × 1.38 × 10⁻⁵ Ω/m = 6.9 × 10⁻⁷ Ω

RC time constant of the circuit, τ = 6.9 × 10⁻⁷ Ω × 10.0 mF = 6.9 × 10⁻⁶ ms

RC time constant of the circuit, τ = 6.9 × 10⁻⁶ ms

(b) The potential drop after t = 1.00 s is given as follows;

[tex]i = \dfrac{V}{R} \cdot e^{-\dfrac{t}{R\cdot C} }[/tex]

Where;

I = The current in the circuit

V = The voltage in the circuit = 0.50 V

R = resistance in the circuit = 6.9 × 10⁻⁷ Ω

C = The series capacitance = 10.0 mF

t = The time taken = 1.00 s

Plugging in the variable values, gives;

[tex]I = \dfrac{0.5}{6.9 \times 10^{-7}} \cdot e^{-\dfrac{1.00}{6.9 \times 10^{-7}\times 10.0 \ mF} } = 0[/tex]

V(1) = I·R = 0 × R = 0

The potential drop across the capacitor 1.00 s after the switch is closed, V(1)  = 0 V

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