Answer:
a
Explanation:
............
..............option A
Answer:
A is the answer as electromagnetic and strong nuclear forces influence the interaction between charged particles within an atom the only difference being their intensity! Hope this helps :) and if you dont mind, mark me brainliest so i can get to the next rank :(
Calculate the peak voltage of a generator that rotates its 200-turn, 0.100 m diameter coil at 3600 rpm in a 0.800 T field.
Answer:
The peak voltage is 473.86 V
Explanation:
Given;
number of turns of generator, N = 200 turn
diameter of the coil, d = 0.1 m
radius of the coil, r = 0.05 m
Magnitude of the magnetic field, B = 0.8 T
angular frequency, ω = 3600 rpm
angular frequency, ω (rad/s) = [tex]\frac{2\pi}{60} *3600\ rpm = 377.04 \ rad/s[/tex]
The peak voltage is given by;
E = NBAω
Where;
A is the area of the coil = πr² = π (0.05)² = 7.855 x 10⁻³ m²
E = (200)(0.8)(7.855 x 10⁻³)(377.04)
E = 473.86 V
Therefore, the peak voltage is 473.86 V
How does work affect energy between objects so it can cause a change in the form of energy? Work transfers energy. Work changes energy. Work increases energy. Work decreases energy.
Answer:
Work can transfer energy between objects and cause a change in the amount of total energy. Work can transfer energy between objects and cause a change in the form of energy. ... When a spring is compressed, the energy changes from kinetic to potential.
Answer:
I think its either A or B
Explanation:
I WILL GIVE BRAINLIEST!!!! Your friend stands on the roof of her house, which is 12.2 m off the ground, and kicks a soccer ball to you so that it is initially moving horizontally at 13.9 m/s. What is its speed as it hits the ground? The time is 1.58 seconds.
Answer:
16.74 m/s
Explanation:
From the question, the parameters given are:
Height h = 12.2 metres
Initial velocity U = 13.9 m/s
Time t = 1.58 s
The range or distance covered by the ball will be
R = u^2/g
Where g = 9.8 m/s^2
R = 13.9^2/9.8
R = 193.21/9.8
R = 19.72 m
Let first calculate the acceleration by using the formula below
R = Ut + 1/2at^2
Substitute all the parameters into the formula
19.72 = 13.9 × 1.58 - 1/2 × a × 1.58^2
19.72 = 21.962 - 1.2482a
Collect the like terms
-1.2482a = 19.72 - 21.962
- 1.2482a = - 2.242
a = 2.242/1.2482
a = 1.796 m/s^2
Using equation 1 to find the final speed
V = U + at
V = 13.9 + 1.796 × 1.58
V = 13.9 + 2.838
V = 16.74 m/s
Therefore, it hit the ground at speed 16.74 m/s
Consider three widely separated galaxies in an expanding universe (look at picture below). Imagine that you are located in galaxy 1 and observe that both galaxies 2 and 3 are moving away from you. If you asked an observer in galaxy 3 to describe how galaxy 2 appears to move, what would he or she say?
Answer:
hi... I won't be able to give you a detailed explanation but here's as far as i know:
If you ask someone in galaxy 3 how galaxy 2 appears to move, they'd say that it seems to move away from them too.
Explanation:
Our universe is constantly expanding, right? But there is no central point in the whole expansion thing. A common example used to describe this is a balloon being blown up. Imagine there are little dots on the balloon. When the balloon is blow up, the dots seem to move away from each other but there isn't any one that stays where it is. So that's kind of like the universe.
Galaxy 3 will see galaxy 2 move away from it too.
I don't know a lot about this so please correct me if I'm wrong but... hope this helps.
if 1,000 J of energy is added to a steak engine, and 400 J of work is done by the engine, how much thermal energy ends up being added to the engine
Answer:
To indicate that energy has been added or removed as heat or work to a system, the internal energy of the system is calculated.
This is because:
1- the internal energy follows the formula:
ΔU = Q - W
2- the internal energy is indicated by any alternation in temperature
Therefore, the answer is:
internal energy
For a particular type of motion, the velocity is zero but the speed is a nonzero quantity. Which statement can you make about this motion
Answer:
because speed is the modulus of velocity which is a vector
the velocity to be zero it must be a round trip
Explanation:
This is because speed is the modulus of velocity which is a vector.
For the velocity to be zero it must be a round trip, therefore the resulting vector zero
On the other hand, the speed of the module is the same in both directions
Duas cargas elétricas Q¹= 15.10-seis ao quadrado C e Q² = 150.10-seis ao quadrado, estão separadas por uma distância de 0,1m, no vácuo. Determine a intensidade da força elétrica de repulsão existente entre as cargas. Dá uma força ae clã!
Answer:
The electric field intensity of electric force is [tex]1.35\times10^{7}\ N/C[/tex]
Explanation:
Given that,
First charge [tex]q_{1}=15\times10^{-6}\ C[/tex]
Second charge [tex]q_{2}=150\times10^{-6}\ C[/tex]
Distance = 0.1 m
We need to calculate the electric field intensity of electric force
Using formula of intensity of electric force
[tex]E=\dfrac{F}{q_{2}}[/tex]
[tex]E=\dfrac{kq_{1}}{r^2}[/tex]
Put the value into the formula
[tex]E=\dfrac{9\times10^{9}\times15\times10^{-6}}{(0.1)^2}[/tex]
[tex]E=13500000\ N/C[/tex]
[tex]E=1.35\times10^{7}\ N/C[/tex]
Hence, The electric field intensity of electric force is [tex]1.35\times10^{7}\ N/C[/tex]
A hollow steel shaft is to transmit 4200 n.m of torque and is to be sized so that the torsional stress does not exceed 120 mpa
A hollow steel shaft is to transmit 4200 n.m of torque and is to be sized so that the torsional stress does not exceed 120 Mpa
If the inside diameter is 70 percent of the outside diameter, what size shaft should be used?
Answer:
the preferred outer diameter of the hollow steel shaft obtained a little bit higher than 61.67 mm is 80 mm
the preferred inner diameter of the hollow steel obtained a little bit lower than 56 mm is 50 mm
Explanation:
From above;
let the inside diameter be [tex]d_i[/tex]
let the outside diameter be [tex]d_o[/tex]
Then
[tex]d_i[/tex] = 70% [tex]d_o[/tex]
[tex]\dfrac{d_i}{d_o} = \dfrac{70}{100}[/tex]
[tex]\dfrac{d_i}{d_o} =0.7[/tex] ------ (1)
to determine the outer diameter of the hollow steel shaft by using the equation of the torque, we have:
[tex]T = \dfrac{\pi}{16} \times \tau \times d_o^3 ( 1 - (\dfrac{d_i}{d_o})^4)[/tex]
where;
[tex]\tau[/tex] = torsoinal shear stress = 120 MPa
[tex]4200= \dfrac{\pi}{16} \times 120\times 10^6 \times d_o^3 ( 1 - 0.7)^4)[/tex]
[tex]4200= 0.19635 \times 120\times 10^6 \times d_o^3 (0.7599)[/tex]
[tex]4200=17904763.8 \ d_o^3[/tex]
[tex]d_o^3 = \dfrac{4200}{17904763.8}[/tex]
[tex]d_o^3 = 2.3457 \times 10^{-4}[/tex]
[tex]d_o =\sqrt[3]{2.3457 \times 10^{-4}}[/tex]
[tex]d_o =0.06167 \ m[/tex]
[tex]d_o =0.06167 \ m \times (\dfrac{1000 \ mm}{1 \ m})[/tex]
[tex]d_o =61.67 \ mm[/tex]
From the tables of A-17 of sized and Renard Numbers,
the preferred outer diameter of the hollow steel shaft obtained a little bit higher than 61.67 mm is 80 mm
However, from equation (1)
[tex]\dfrac{d_i}{d_o} =0.7[/tex] ------ (1)
replacing the value of [tex]d_o[/tex]
[tex]\dfrac{d_i}{80} =0.7[/tex]
[tex]d_i = 80 \times 0.7[/tex]
[tex]d_i = 56 \ mm[/tex]
From the tables of A-17 of sized and Renard Numbers,
the preferred inner diameter of the hollow steel obtained a little bit lower than 56 mm is 50 mm
Chemical bonds form when (A)atoms share a nucleus. (B)atoms share protons. (C)atoms share neutrons. (D)atoms share electrons.
Answer:
d) atoms share electrons
Explanation:
Atoms with relatively similar electronegativities share electrons between them and are connected by covalent bond. Atoms with large differences in the electronicnegativity transfer electron's to form ions. The ions are then attracted to each other.
Answer:
D.
Explanation:
edge
7) Is it possible to have zero distance but a nonzero displacement?
Yes or No because ...
Answer:
Hey there!
No. Displacement is always less than or equal to the distance.
Let me know if this helps :)
A driver sees a boy and his dog in the road, and it takes the driver 0.50 seconds to put on the brakes. If the car travels 14 meters during that time, what is its velocity?
Answer:
The answer would be 91.9 or 91.8635
Hope this helps
A driver sees a boy and his dog on the road, and it takes the driver 0.50 seconds to put on the brakes, If the car travels 14 meters during that time, the velocity of the car would have been 56 m/s,
What are the three equations of motion?There are three equations of motion given by Newton
The first equation is given as follows
v = u + at
the second equation is given as follows
S = ut + 1/2×a×t²
the third equation is given as follows
v² - u² = 2×a×s
As given in the problem a driver sees a boy and his dog on the road, and it takes the driver 0.50 seconds to put on the brakes, If the car travels 14 meters during that time,
t = 0.5 s , s = 14 m
By using the first equation of the motion,
v = u+at
0 = u+a×0.5
a = -2u m/s²
Now by using the second equation of motion,
s = ut+1/2at²
By substituting t=0.5 and a = -2u m/s² in the equation ,
14 = u/2-u/4 = u/4
u = 56 m/s
Thus, the velocity of the car would have been 56 m/s,
Learn more about equations of motion from here,
brainly.com/question/5955789
#SPJ2
K= 1/2mv^2
K=1/2(210kg)(10.5 m/s)^2
answer:
unit:
Answer:
11577.25 JoulesExplanation:
The expression given in the question which is
[tex]k= \frac{1}{2} mv^2[/tex]
Is the expression for the kinetic energy stored in a system and it is measured in Joules
From the expression we can see that
mass m=210 kg
velocity v= 10.5 m/s
Substituting as seen in the question we have the kinetic energy as
[tex]k= \frac{1}{2}*210*10.5^2\\\\k= \frac{1}{2}*210*110.25\\\\k= \frac{1}{2} *23152.5\\\\k= 11577.25 J[/tex]
hence the energy stored is 11577.25 Joules
need physics help! (there’s a picture)
Answer:
i. Subtract v₀² from both of the equation.
ii. Divide both side of the equation by 2
iii. Divide both side of the equation by (x – x₀)
a = (v² – v₀²) / 2(x – x₀)
Explanation:
v² = v₀² + 2a(x – x₀)
To solve for a in the expression above, do the following:
i. Subtract v₀² from both of the equation.
v² – v₀² = v₀² – v₀² + 2a(x – x₀)
v² – v₀² = 2a(x – x₀)
ii. Divide both side of the equation by 2
(v² – v₀²) /2= 2a(x – x₀)/2
(v² – v₀²) /2 = a(x – x₀)
iii. Divide both side of the equation by (x – x₀)
(v² – v₀²) /2 ÷ (x – x₀) = a(x – x₀)/(x – x₀)
(v² – v₀²) /2 × 1/ (x – x₀) = a
a = (v² – v₀²) / 2(x – x₀)
How to solve this step by step.
Answer:
a = (v² − v₀²) / (2 (x − x₀))
Explanation:
v² = v₀² + 2a(x − x₀)
Subtract v₀² from both sides.
v² − v₀² = 2a(x − x₀)
Divide both sides by 2 (x − x₀).
(v² − v₀²) / (2 (x − x₀)) = a
What are the 2 main parts of physical science
Answer:
Physical science is the study of the inorganic world. That is, it does not study living things. (Those are studied in biological, or life, science.) The four main branches of physical science are astronomy, physics, chemistry, and the Earth sciences, which include meteorology and geology.
Explanation:
1.) Identify two types of heat?
One type of heat causes a change in temperature, the other type of heat causes a change of state.
Answer:
Explanation:
Thermal Energy and Heat
Shards of ice fly from the sculptor’s chisel. As the crowd
looks on, a swan slowly emerges from a massive block of ice. As
the day wears on, however, drops of water begin to fall from the
sculpture. Drip by drip, the sculpture is transformed into a puddle of liquid water. What makes matter change from one state to
another? To answer this question, you need to think about the
particles that make up matter.
Energy Simply stated, energy is the ability to do work or cause
change. The energy of motion is called kinetic energy. Particles
within matter are in constant motion. The amount of motion of
these particles depends on the kinetic energy they possess. Particles
with more kinetic energy move faster and farther apart. Particles
with less energy move more slowly and stay closer together.
The total kinetic energy of all the particles in a sample of
matter is called thermal energy. Thermal energy, an extensive
property, depends on the number of particles in a substance as
well as the amount of energy each particle has. If either the
number of particles or the amount of energy in each particle
changes, the thermal energy of the sample changes. With identically sized samples, the warmer substance has the greater thermal energy.
Diya visited a tailor shop and bought home three cuttings of fabric A,B and C to study their properties. Diya tried burning the three fibres. Fabric A smelt of burning paper,fabric B smelt of burning hair while fabric C shrunk on burning. Can you help Diya identify fabrics A,B and C
Answer:
Rayon
Wool
Silk Yarn
Explanation:
Rayon
This is Fabric A. Rayon basically burns very quickly even quicker than fabrics like cotton and linen. Its ash is gray in color. The rayon fabric smells of burning paper when it is burnt.
Wool:
This is Fabric B. Wool is basically hard to ignite. It burns slowly. Its ash is dark in color. The wool fabric smells of burning hair when it is burnt.
Silk Yarn:
This is Fabric C. The silk yarn shrinks from the flame when it is burned. It has a grayish black ash. The silk yarn fabric smells burnt meat of when it is burnt.
34. A chain of hamburger restaurants advertises that it
has sold more than 50 billion hamburgers over the
years. Estimate how many pounds of hamburger
meat must have been used by the restaurant chain
to make 50 billion hamburgers and how many head
of cattle were required to furnish the meat for these
hamburgers.
Answer:
"12.50 × 10⁹" pounds of hamburger. The further explanation is given below.
Explanation:
Sold hamburger
= more than 50 billion
To get pounds of hamburger,
= [tex]50 \ billion\times 0.125 \ lbs[/tex]
= [tex]12.50 \ billion \ pounds[/tex]
= [tex]12.50\times 10^9 \ lb[/tex]
On divide pounds of hamburgers by pounds of burger meat through one head of cattle, we get
⇒ [tex]\frac{12.5 \ billion}{350}[/tex]
⇒ [tex]35714285 \ cattle[/tex]
Which kinds of objects emit visible light in the electromagnetic spectrum?
answer :
Visible: Our eyes detect visible light. Fireflies, light bulbs, and stars all emit visible light. Ultraviolet: Ultraviolet radiation is emitted by the Sun and are the reason skin tans and burns. "Hot" objects in space emit UV radiation as well.
Which objects emit electromagnetic waves?
All objects emit electromagnetic radiation according to their temperature. Colder objects emit waves with very low frequency (such as radio or microwaves), while hot objects emit visible light or even ultraviolet and higher frequencies.
Light of wavelength 500 nm illuminates a round 0.50-mm-diameter hole. A screen is placed 6.0 m past the slit. What is the width of the central bright circle on the screen
Answer:
14.64*10^-3 m
Explanation:
given that
Length of the wavelength, λ = 500*10^-9 m
Diameter of the hole, D = 0.5 mm
length of the slit, L = 6 m
W = 2.44 λL / D, where
W = width of the screen in m
λ = wavelength of the light in nm
L = length of the slit in m
D = diameter of the hole in m
on substituting the values, we have
W = (2.44 * 500*10^-9 * 6) / 0.5*10^-3
W = 7.32*10^-6 / 0.5*10^-3
W = 0.01464 mm
or also, 14.64*10^-3 m
Convert 0.0351 kg to mg. (1,000,000 mg = 1 kg)
Answer:
The required answer is 35100
Answer:
35100mg
Explanation: When converting bigger to smaller units, we move the decimal point to the right side. As there are 6 zeroes, The decimal point will move six places to the right. Therefore answer id 35100mg
A bowling ball starts from rest and moves 300 m down a long, downwardly angled track in 22.4 sec.a. What is its speed at the end of the track? [27 m/s]b. What is its acceleration? [l.2 m/s2]c. Sketch three graphs: Δx vs. Δt, v vs. Δt and a vs. Δt. We are interested in the initial and final values, and the general shape of the graph, (linear, exponential, etc)
Answer:
The speed at the end of the track = 27 m/s
The acceleration = 1.2 m/s²
Please find the Δx vs Δt, v vs Δt, a vs Δt
Explanation:
We have;
x = u·t + 1/2·a·t²
Where;
x = The distance = 300 m
u = The initial velocity = 0 m/s (Ball at rest)
t = The time taken = 22.4 s
Therefore;
300 = 0 + 1/2×a×22.4²
a = 2×300/22.4² = 1.19579 ≈ 1.2 m/s²
v = u + a×t
∴ v = 0 + 1.2 × 22.4 = 26.88 ≈ 27 m/s
Part of the table of values is as follows;
t, x, v
0, 0, 0
0.4, 0.095663, 0.478316
0.8, 0.382653, 0.956632
1.2, 0.860969, 1.434948
1.6, 1.530611, 1.913264
2, 2.39158, 2.39158
2.4, 3.443875, 2.869896
2.8, 4.687497, 3.348212
3.2, 6.122445, 3.826528
3.6, 7.748719, 4.304844
A exercise ball is on a table 2.5 m above the ground. What is the mass
of the ball if it has a GPE of 56.8 J?
Answer:
2.27kg
Explanation:
The Potential energy gained = Force gravity× Height
Force gravity on the ball is GPE/ height
56.8/2.5=22.72N
the mass = 22.72/10= 2.27kg
The mass of the ball when the gravitational potential energy of 56.8 J present is 2.27 kg.
What is gravitational potential energy?The potential energy is the energy by virtue of its position in the effect of gravity.
Given is an exercise ball is on a table 2.5 m above the ground. It has a gravitational potential energy of 56.8 J.
Potential energy = gravity force × height
P.E =mgh
56.8 J = m x 9.8 x 2.5
m = 2.27kg
Thus, mass of the ball is 2.27 kg.
Learn more about gravitational potential energy.
https://brainly.com/question/3884855
#SPJ1
Solue the Selmultaneous equations:
3y +2x =5 and y-5x = 13
Answer:
x=-2 and y=3
Explanation:
Isolate y and then x to get: y=13+5(-2)
Simplify to get y=3 then plug it back in to get x=-2
We can check, 9+ (-4)=5 hope this helps
Explain newton 2nd law ???
Explanation:
Newton's second law simply says that the net force on an object is equal to the object's mass times its acceleration.
∑F = ma
For example, think of a game of tug-of-war, in which two teams pull on a rope in opposite directions.
If the forces are equal (balanced), then the net force is 0 N, so Newton's second law tells us that the rope's acceleration is 0 m/s².
If the forces are not equal (unbalanced), then the net force is not 0 N, and the rope will accelerate in the direction of the net force.
9. An efficient LED light bulb uses energy at a rate of 7 watts or 7 J/second. What
total amount of electrical energy is used if the light is on for 2 hours?
Answer: 50,400 J
Explanation:
what quantity of heat will be needed to melt 3kg of ice at -2 degree Celsius to 10 degree Celsius given that S.H.C of water is 4200j/kg.k.Specific latent heat of fusion is 3.36 times 10 raised to the power 5j/k.SLC is 2100j/kg
Answer:
1.15×10⁶ J
Explanation:
Heat needed to bring the ice to 0°C:
q = mCΔT
q = (3 kg) (2100 J/kg/K) (0°C − (-2°C))
q = 12,600 J
Heat needed to melt the ice:
q = mL
q = (3 kg) (3.36×10⁵ J/kg)
q = 1,008,000 J
Heat needed to bring the water to 10°C:
q = mCΔT
q = (3 kg) (4200 J/kg/K) (10°C − 0°C)
q = 126,000 J
The total heat is:
q = 12,600 J + 1,008,000 J + 126,000 J
q = 1,146,600 J
q = 1.15×10⁶ J
Which of the following is a chemical property of matter?
combustibility
weight
electrical conductivity
odor
Answer:
The correct answer is combustibility
Explanation:
A chemical property of a matter is a property in which a matter has the tendency to change its form through chemical reaction(s).
A matter is said to have combustibility property if it can undergo combustion. Combustion is a chemical process in which a substance burns in excess oxygen to produce carbon dioxide and water.
Consider the equation below
CH₄ + O₂ ⇒ CO₂ + H₂O
The equation above shows methane burning in excess oxygen to produce carbon dioxide and water
The answer is electrical conductivity!
How fast is a skateboarder traveling if she travels 2 miles in 4 hours?
This question is asking for the speed of the skateboarder. speed= distance/time. In this question we will do 2/4 in order to get a speed of 0.5 mph.
If there is no dropped ceiling, or if the drop is not as much as the height of the recessed luminaires, you will find that the center-to-center spacing of recessed luminaires will have to be in increments of ____________________ ft.
Answer:
The answer is "4".
Explanation:
The luminaire would be recessed inside a wall, so that, dependent on the surface mountings, its top-level is flush with the ceiling. It is the hanging under the primary structural, in which the drop was an area of the above falling ceiling, that referred to its full space, because it will be generally used for the HVAC air return and the total space is also used to obfuscate piping, cabling, and ducts, that's why the middle-to-middle spacing of curved lighting systems would have to be in incremental increases of 4 ft.