Answer:
1. Ice at 0 degrees C.
2. N₂ at STP.
3. N₂ at STP.
4. Water vapor at 150 degrees C and 1 atm.
Explanation:
First, we need to remember that entropy (S) is a measure of how spread out or dispersed the energy of a system is among the different possible ways that system can contain energy. The greater the dispersal, the greater is the entropy.
When the temperature is increased, the energies associated with all types of molecular motion increase. Consequently, the entropy of a system always increases with increasing temperature.
With this in mind, we consider the pairs:
1. Since the ice at 0ºC has a greater temperature than the ice at -40 ºC, the first has the higher entropy.
2. The N₂ at STP (that is, 1 atm and 25 ºC) has higher entropy than N₂ at 0ºC and 10 atm because it has a higher temperature and less pressure, which allows a greater dispersal of energy by the molecules of the gas.
3. The N₂ at STP has a higher entropy since it has a higher temperature than N₂ at 0ºC, even though it the first has a lower volume (24,4 L vs. 50 L).
4. The water vapor at 150 ºC and 1 atm have a higher temperature and a lower pressure. This means that its molecules will have an increased molecular motion than the molecules of water vapor at a lower temperature and higher pressure. Therefore, the first has the highest entropy.
Which one is most
stable.
A) primary alcohol.
B) secondary alcohol.
C) teritary alcohal.
Answer:
C
Explanation:
Tertiary alcohol should be the answer.
This is because tertiary alcohol has a less polar compound which means it is less likely to have chemical reaction with other compounds whereas primary and secondary alcohol has a higher chance of having chemical reaction with other compounds.
Answer:
I think the answer is A
Explanation:
primary alcohol has only one methyl group bonded to the central carbon atom, and the extent of decrease in partial posative charge is less, making it more prone to attack by nucleophiles. thus tertiary alcohols are more stable than primary alcohols
1. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? 2Al2O3(s)
Using the thermodynamic data provided below, calculate S° for this reaction.
S°(J/K.mol)
Al(s) 28.3
O2(g) 205.0
Al2O3(s) 50.99
2. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? Al2O3(s)
Calculate G° for this reaction, given that ?G°f of aluminum oxide is –1576.4 kJ/mol.
Answer:
Al(s) 28.3
Explanation:
Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.4Al(s) + 3O2(g) ? Al2O3(s)
AnswerAluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? 2Al2O3(s)
Using the thermodynamic data provided below, calculate S° for this reaction.
S°(J/K.mol)
Al(s) 28.3
O2(g) 205.0
Al2O3(s) 50.99
2. Aluminum forms a layer of aluminum oxide when exposed to air which protects the bulk metal from further corrosion.
4Al(s) + 3O2(g) ? Al2O3(s)
Calculate G° for this reaction, given that ?G°f of aluminum oxide is –1576.4 kJ/mol.
Answer:
Explanation:
Explanation:
Write the condensed nd structural formulas as well as the names for all isomers of C3H5Cl3.
Answer:
1) 1,1,1-trichloropropane
2) 1,1,2-trichloropropane
3) 1,2,2-trichloropropane
4) 1,2,3-trichloropropane
Explanation:
For this question, we must remember that isomers are molecules that have the same formula but different structures. For the formula [tex]C_3H_5Cl_3[/tex] we can draw a linear chain of three carbons and change the position of the chlorine atoms in the carbon chain.
With this in mind, if we put all the chlorine atoms on the same carbon we will get 1,1,1-trichloropropane. If we change an atom from chlorine to carbon 2 we will obtain 1,1,2-trichloropropane. If we move another chlorine atom to carbon two we will get 1,2,2-trichloropropane. Finally, if we put a chlorine atom in each carbon we will obtain 1,2,3-trichloropropane.
See figure one for further explanations
I hope it helps!
Benzene exists as a resonance hybrid and its bonds exhibit characteristics that are halfway between single and double bonds. Resonance hybrids are best defined as
Answer:
Explanation:
We can only talk about resonance hybrid for a compound in which more than one structure is possible based on its observed chemical properties.
There are compounds whose chemical properties can not be satisfactorily explained on the basis of a single chemical structure. In the case of such compounds, we invoke the idea of resonance.
A resonance hybrid is a single structure drawn to represent a given chemical specie which exhibits resonance behaviour and can otherwise be represented on paper in the form of an average of two or more chemical structures separated each from the next by a double-headed arrow.
Answer:
Resonance hybrids are best defined as a molecule's electron pattern cannot be described by a single structure.
Explanation:
its right
5
Select the correct answer.
Which of the following is a physical model of the Sun?
A.
an equation that describes the Sun's motion
B.
a chart that lists the temperatures of different parts of the Sun
O c.
a computer program that shows how the Sun changes over time
OD
a paragraph that describes the Sun's structure
O E.
a small yellow ball that represents the Sun
Reset
Next
Answer:
E. a small yellow ball that represents the Sun
Explanation:
key word on the question, 'physical'
HCl(aq) + NaOH(aq) ––––> NaCl(aq) + H2O(l) What volume of 0.631 M HCl is required to react with 15.8 mL of 0.321 M NaOH?
Answer:
The correct answer is 8.04 mL
Explanation:
Given the neutralization reaction:
HCl(aq) + NaOH(aq) ––––> NaCl(aq) + H₂O(l)
1 mol of HCl reacts with 1 mol of NaOH.
The number of moles of NaOH there is in 15.8 mL is calculated as follows:
0.321 mol/L x 1 L/1000 mL x 15.8 mL = 5.07 x 10⁻³ mol NaOH
Thus, we need 5.07 x 10⁻³ mol of HCl to react with 5.07 x 10⁻³ mol NaOH. We have a 0.631 M HCl solution. We calculate the volume of HCl we need by considering that 1 mol NaOH reacts with 1 mol HCl and that there are 0.631 moles of HCl in 1 liter of solution (1000 mL):
5.07 x 10⁻³ mol NaOH x 1 mol HCl/1 mol NaOH x 1000 mL/0.631 mol HCl = 8.04 mL
3. How many significant figures are in the number 805000? *
Answer:
3
Explanation:
Three significant figures
Which of the following molecules has a characteristic broad stretch at 3300 cm-1?
A) (CH3)2CHCH2OH
B) (CH3)3CH
C) (CH3)2CHCCCH3
D) (CH3)2CHCH=CH2
E) (CH3)2CHCO2CH3
Answer:
The answer is "Option A"
Explanation:
At 3300 cm-1, the wide region is equal to OH. It is a possible group of alcoholic features that includes drugs. In the given choices option a is correct that's the structure can be defined in attachment file please find it, and the wrong choice can be defined as follows:
In choice B, It is wrong because it doesn't include OH. In choice C, it uses the triple bond, that's why it is wrong. In choice D, it uses the two bonds, that's why it is wrong. In choice E, it uses the characteristic bond, that's why it is wrong.Calculate the solubility of PbF2 in water at . You'll find data in the ALEKS Data tab. Round your answer to significant digits.
Answer:
0.5 g/L.
Explanation:
Hello,
In this case, for this solubility problem, we can write for the lead (II) fluoride:
[tex]PbF_2(s)\rightleftharpoons Pb^{2+}(aq)+2F^-(aq)[/tex]
And the equilibrium expression is:
[tex]Ksp=[Pb^{2+}][F^-]^2[/tex]
Whereas Ksp of lead (II) fluoride is 3.3x10⁻⁸. In such a way, we can write the equilibrium expression in terms of the molar solubility [tex]x[/tex] as follows:
[tex]Ksp=(x)(2x)^2=3.3x10^{-8}[/tex]
Hence, solving for [tex]x[/tex] we find:
[tex]x=\sqrt[3]{\frac{3.3x10^{-8}}{4} }\\\\x=2.02x10^{-3}M[/tex]
Moreover, since the molar mass of lead (II) fluoride is 245.2 g/mol, the solubility turns out:
[tex]2.02x10^{-3}\frac{molPbF_2}{L}*\frac{245.2gPbF_2}{1molPbF_2}\\ \\0.5\frac{g}{L}[/tex]
Best regards.
One of these two substances is a liquid at room temperature and the other one is a gas. Which one is the liquid and why?
A. CH3OCH3
B. CH3CH2OH
Answer:
B. CH3CH2OH
Explanation:
Ethanol has a chemical formula of CH3CH2OH, it is the second member of the series in the alkanol family. Ethanol is a colourless, volatile liquid with a characteristic smell and taste. It is readily soluble in water in all proportions. It has a boiling point of 78° C. The physical properties such as the solubility of alkanols are affected by the presence of hydrogen bonding. The hydroxyl group is capable of bonding to other alkanol molecules. The boiling points rise with increasing molecular mass.
Hydrogen bonding helps the molecules to stick together. For example comparing the boiling point of pentane ( 36° C) with that of butan-1-ol (118° C) , the boiling point of alkanol is much higher even though the two compound are of similar relative molecular mass. This is due to the presence of hydrogen bonds in butanol.
Hydrocarbons are not soluble in water but alkanols are soluble in water because of the hydroxyl groups in the molecules can form hydrogen bond with water. Solubility of alkanol in water decreases as the number of carbon atom increases. Primary alcohol with more than five carbon atoms are insoluble in water.
Give the effect on the melting point of the presence of a cis double bond in a fatty acid.
Answer:
The cis double bond present in unsaturated fatty acids acids results in lower melting point when compared to saturated fatty acids of the same chain length.
Explanation:
Melting point of a fatty acids are affected by the length and degree of unsaturation of the hydrocarbon chain.
At room temperature, saturated fatty acids with hydrocarbon chain lengths between 12-24 are waxy solids whereas unsaturated atty acids of the same chain length are liquids. This is due to the nature of the packing of the fatty acid molecules in the saturated and unsaturated compounds.
In the saturated compounds, the molecules are tightly packed side by side with minimal steric hindrance and maximal van der Waals forces of attraction between molecules. However, in unsaturated fatty acids, the cis double bond introduces a bend or kink in the molecules which then interferes with the tight packing of the molecules and reducing interaction between molecules. Therefore, less energy is required to cause a disorder in the arrangement of unsaturated fatty acids, leading to a lowering of melting point.
Match.
The expression of concentration that provides the moles of solute per kilograms of solvent is _______.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution,the_______ is water.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the ________is sodium chloride.
If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the ________of sodium chloride would be 0.25.
A way to express concentration that provides the moles of solute per liter of solution is _______-.
Solvent
Mole fraction
solute
pH
Molarity
Molality
Answer:
Molality, Solvent, Solute, Mole fraction, Molarity.
Explanation:
The expression of concentration that provides the moles of solute per kilograms of solvent is Molality. This in the only expression referred to the solvent.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solvent is water. When water is present, it is usually considered the solvent.
A solution is made up of 0.15 grams of sodium chloride in 1 liter of water. For this solution, the Solute is sodium chloride. There can be 1 or more solutes in a solution.
If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the Mole fraction of sodium chloride would be 0.25. The mole fraction is equal to the moles of a substance divided by the total number of moles.
A way to express concentration that provides the moles of solute per liter of solution is Molarity.
Balanced chemical equations show:
the reactants entering the reaction
the products formed by the reaction
the ratios of moles needed to balance the reactants and products
all of the above
the products formed from the reaction
all of the above
Write the molecular balanced chemical equation and the net ionic equation for the reaction between Ca(OH)2(aq) and HCl(aq).
Answer:
1. Balanced Molecular equation
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + 2H2O(aq)
2. Net ionic equation
OH-(aq) + H+(aq) —> H2O(l)
Explanation:
1. Molecular balance equation for the reaction between Ca(OH)2(aq) and HCl(aq).
This is illustrated below:
Ca(OH)2(aq) + HCl(aq) —> CaCl2(aq) + H2O(aq)
There are 2 atoms of Cl on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + H2O(aq)
There are 2 atoms of H on the right side and a total of 4 atoms on the left side. It can be balance by putting 2 in front of H2O as shown below:
Ca(OH)2(aq) + 2HCl(aq) —> CaCl2(aq) + 2H2O(aq)
Therefore the equation above is balanced.
2. Net ionic equation for the reaction between Ca(OH)2(aq) and HCl(aq).
In solution, Ca(OH)2(aq) and HCl(aq) will dissociate as follow:
Ca(OH)2(aq) —> Ca2+(aq) + 2OH-(aq)
HCl(aq) —> H+(aq) + Cl-(aq)
Ca(OH)2(aq) + 2HCl(aq) —>
Ca2+(aq) + 2OH-(aq) + 2H+(aq) + 2Cl-(aq) —> Ca2+(aq) + 2Cl-(aq) + 2H2O(l)
Cancel out the spectator ions i.e Ca2+ and Cl- to obtain the net ionic equation
2OH-(aq) + 2H+(aq) —> 2H2O(l)
OH-(aq) + H+(aq) —> H2O(l)
Using the measurements in the table, determine which unidentified metal has the lowest density?
Answer:
Metal C
Explanation:
Density = mass (g)/ volume (mL, which is the same thing as cm cubed)
Divide mass by volume for each metal, the metal with the lowest value (metal C) is your answer.
Answer:
IT IS
NOT. I REPEAT - IT IS NOT> D
Explanation:
i got it wrong :(
If you are not sure about what to do during a lab activity, what should you do?
Ask someone else at your table.
Use your best judgement.
Watch to see what everyone else isdoing.
Ask the teacher.
Answer:
ask a teacher is the correct answer.
Explanation:
You must ALWAYS ask a teacher if you are not sure about what to do during a lab activity.
Answer:
It's important to ask the teacher, lab safety policies all state that if you're confused about instructions it's always good to ask the teacher to clarify them.
find the value of y in the equation Зу – 20 = 7.
[tex]3y-20=7\implies y=\frac{20+7}{3}=9[/tex].
Hope this helps.
y= 9
Explanation:
=> 3y - 20 = 7
=> 3y = 7+20
=> 3y = 27
=> y = 27/3
=> y = 9
HOPE OT HELPS. ◉‿◉
What is the definition of weight
Answer:
Weight is a noun that means a human body's mass.
For example: Joh is 168 pounds.
This is the correct definition of weight.
Here to help!
Part B
What is the symbol of the atom obtained by adding one proton to 19F?
Express your answer as an isotope
Answer:
Neon
Explanation:
A proton is the positively charged particle in the atom. The atomic number of an atom is the number of protons present in the atom while the mass number of an atom is the sum of the number of protons and neutrons in the nucleus of an atom.
If an extra proton is added to 19F, then neon is formed.
An unknown gas diffusion 0.25 times as fast as he .what is the molecules mass of the unknown gas
Answer:
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
Explanation:
identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simultaneously. After a certain amount of time, it was found that 6.23 mL of O2 had passed through the membrane, but only 3.85 mL of of the unknown gas had passed through. What is the molar mass of the unknown gas
Sodium hydroxide is a strong base. What is the pH in a 0.01 mol/dm3
solution?
a. pH=2
b. pH=12
c. pH=-2
d. pH=0.01 mol/dm3
Answer:
b. pH=12
Explanation:
Step 1: Given data
Concentration of NaOH: 0.01 mol/dm³ = 0.01 mol/L = 0.01 M
Step 2: Write the reaction for the dissociation of NaOH
NaOH is a strong base that dissociates according to the following equation.
NaOH(aq) ⇒ Na⁺(aq) + OH⁻(aq)
The molar ratio of NaOH to OH⁻ is 1:1. Then, the concentration of OH⁻ is 0.01 M.
Step 3: Calculate the pOH
pOH = -log [OH⁻] = -log 0.01 = 2
Step 4: Calculate the pH
We will use the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 -2 = 12
How many seconds (s) are needed to deposit 7.25 g of copper metal from an aqueous solution of CuCl2, using a current of 3.1 Amps.
Answer:
7,052.6secs
Explanation:
n of Cu = +2
R.A.M of Cu = 64g
m = 7.25g
I = 3.1A
F = 96500
nF = R.A.M
It = m
2*96500 = 64
3.1*t = 7.25
1,399,250 = 198.4t
t = 7,052.6secs
Which has the greatest mass?a. one atom of carbon, b. one atom of hydrogenc. one atom of lithium
Answer:
one atom of carbon
Explanation:
The relative atomic mass of elements can be used to determine their relative masses. If we look at all the options, we will notice that carbon has a relative atomic mass of 12, hydrogen has a relative atomic mass of 1 and lithium has a relative atomic mass of 7
We can now see that carbon has the greatest relative atomic mass among the options provided in the question.
PLEASE HELP WILL GIVE BRAINLIEST!!!!
Xenon-133 has a half life of 5.2 days. A 237 gram sample of Xenon is collected and stored. It is later measured to be 29.625 grams. How long has it been in storage?
A. 15.6 days
B. 39.9 days
C. 20.8 days
D. 8 days
Answer:
A. 15.6 days
Explanation:
We have a general formula used to solve for questions dealing with half life.
N(t) = No (1/2)^t/t½
Where
N(t) = Quantity of sample left after t days
No = Initial amount of sample
t½ = Half life of sample
t = Duration or time required for sample to decay
In the above question, we are asked to determine how long(time) that the sample has been in storage.
The formula for time (t) has been derived as:
t =[ t½ × In(Nt/No)] ÷ - In 2
Where
No = 237 grams
N(t) = 29.625 grams
t½ = 5.2 days
t = ????? Unknown
t = [ t½ × In(Nt/No)] ÷ - In 2
t = [ 5.2 × In(29.625/237)] ÷ - In 2
t = [5.2 × -2.0794415417] ÷ - In 2
t = -10.813096017 ÷ - ln 2
t = 15.6 days
Therefore, the sample has been in storage for 15.6 days.
A rigid tank contains 1.80 moles of nitrogen, which can be treated as an ideal gas, at a pressure of 25.5 atm. While the tank and gas maintain a constant volume and temperature, a number of moles are removed from the tank, reducing the pressure to 5.70 atm. How many moles are removed
Answer:
1.4 moles.
Explanation:
The following data were obtained from the question:
Initial mole (n1) = 1.8 moles
Initial pressure (P1) = 25.5 atm
Final pressure (P2) = 5.7 atm
Number of mole removed =?
Next, we shall obtain an expression relating pressure and number of mole together.
This is illustrated below:
From the ideal gas equation:
PV = nRT
Divide both side by V
P = nRT /V
Divide both side by n
P/n = RT/V
But volume (V) and temperature (T) are constant.
P/n = constant
P1/n1 = P2/n2
P1 is initial pressure.
P2 is final pressure.
n1 is the initial mole.
n2 is the final mole.
Next, we shall determine the final mole in tank as follow:
Initial mole (n1) = 1.8 moles
Initial pressure (P1) = 25.5 atm
Final pressure (P2) = 5.7 atm
Final mole (n2) =.?
P1/n1 = P2/n2
25.5/1.8 = 5.7/n2
Cross multiply
25.5 x n2 = 1.8 x 5.7
Divide both side by 25.5
n2 = (1.8 x 5.7) /25.5
n2 = 0.40 mole.
Therefore, the final mole in the tank is 0.40 mole.
Finally, we shall determine the number of mole that was removed as follow:
Initial mole (n1) = 1.8 moles
Final mole (n2) = 0.4 mole
Number of mole removed =?
The number of mole removed from the tank can be obtained by finding the difference between the initial mole and final mole as illustrated below:
Number of mole removed = initial mole – final mole
Number of mole removed = n1 – n2
Number of mole removed = 1.8 – 0.4
Number of mole removed = 1.4 moles
Therefore, 1.4 moles were removed from the tank.
Consider a solution made from a nonvolatile solute and a volatile solvent. Which statement is true?
a) The vapor pressure of the solution is always greater than the vapor pressure of the pure solvent.
b) The boiling point of the solution is always greater than the boiling point of the pure solvent.
c) The freezing point of the solution is always greater than the freezing point of the pure solvent.
Answer:
b) The boiling point of the solution is always greater than the boiling point of the pure solvent.
Explanation:
Hello,
In this case, when we add a nonvolatile solute to a volatile solvent which has a relatively low boiling point, we can evidence the increase of the boiling point of the resulting solution as more energy must be supplied to take the molecules from liquid to gas. This fact matches with the boiling point elevation colligative property due to the solute's addition, which states that the boiling point of the solution is always greater than the boiling point of the pure solvent, therefore, answer is b).
Best regards.
The statement true about the solution made from a nonvolatile solute and a volatile solvent is, the boiling point of the solution is always greater than the boiling point of the pure solvent. Thus option C is correct.
The boiling point of the solution can be defined as the temperature where the liquid has been converted to the gaseous state. In the solvent, the energy has been provided to the sample for the conversion of liquid molecules to gas.
The addition of a nonvolatile solute to the volatile solvent results in the addition of the molecules to the solvent. This will result in the requirement of more energy for the conversion of solvent from a liquid state to a gaseous state.
Thus, with the addition of a nonvolatile solute to the volatile solvent, the boiling point of the solution will be increased and will always be greater than the boiling point of the pure solvent.
Thus option C is correct.
For more information about the volatile solvent, refer to the link:
https://brainly.com/question/3013635
how many hydrogen atom are there in 5 moles of methyl alcohol
Answer:
20 hydrogen atoms in 5 moles of methyl alcohol.
Explanation:
Hi!
So, there are 4 hydrogen atoms in 1 mole of methyl alcohol. If you multiply 4*5, it equals to 20.
Have a great day!
Part D There is a structure for CH2CHCHCH2CHCH3 with a double bond between the first (from left to right) and the second carbons and a chlorine atom attached to the third and the fifth carbon. Spell out the full name of the compound.
Answer:
3,5-dichlorohex-1-ene
Explanation:
The compound is; H2C=CH-C(Cl)H-CH2-C(Cl)H-CH3. We can rightly call this compound by the name, 3,5-dichlorohex-1-ene.
We arrived at this name by first counting the longest parent carbon chain, that gives hexane. The compound has a double bond at the 1-position. Also, there are two substituent chlorine atoms at positions 3 and 5 in the structure, hence the name given.
At what temperature, Teq, do the forward and reverse corrosion reactions occur in equilibrium?
The chemical reaction that causes aluminum to corrode in air is given by
4Al+3O2?2Al2O3
in which at 298 K
?Hrxn? = ?3352 kJ
?Srxn = ?625.1 J/K
What is the standard Gibbs free energy for this reaction? Assume the commonly used standard reference temperature of 298 K?
What is the Gibbs free energy for this reaction at 5975K ? Assume that ?H and ?S do not change with temperature.
At what temperature, Teq, do the forward and reverse corrosion reactions occur in equilibrium?
Answer:
See explanation below.
Explanation:
We can obtain the Gibb's free energy from the formula;
∆G= ∆H - T∆S
Where;
∆G = change in free energy= the unknown
∆H= change in enthalpy = 3352 kJ
∆S= change in entropy of the solution= 625.1 J/K
T= absolute temperature = 298 K
Substituting values;
∆G= 3352 ×10^3 J - (298 K × 625.1 J/K)
∆G= 3352 ×10^3 J - 186279.8
∆G= 3.16 × 10^6 J
At 5975K,
∆G= ∆H - T∆S
∆G= 3352 ×10^3 J - (5975K × 625.1 J/K)
∆G= 3.352 ×10^6 J - 3.735 × 10^6
∆G= -3.83×10^5 J
At equilibrium, ∆G=0, Teq is given by;
0= 3352 ×10^3 J - (Teq × 625.1 J/K)
0= 3352 ×10^3 - 625.1Teq
625.1Teq = 3352 ×10^3
Teq= 3352 ×10^3/625.1
Teq= 5362.3 K
Standard Gibb's free energy at 298 & 5975K is 3.16×10⁶J and -3.83×10⁵J respectively, and temperature at equilibrium state is 5362.3 K.
How do we calculate standard Gibb's free energy?Standard Gibb's free energy of any reaction will be calculated as:
∆G° = ∆H° - T∆S°, where
∆G° = change in free energy = to find?
∆H° = change in enthalpy = 3352 kJ = 3,352 × 10³J
∆S° = change in entropy = 625.1 J/K
T = absolute temperature = 298 K
On putting all these values on the above equation, we get
∆G° = (3,352 × 10³) - (298 × 625.1) = 3.16 × 10⁶J
Gibb's free energy at 5,975 K temperature:
∆G° = (3,352 × 10³) - (5,975 × 625.1) = -3.83 × 10⁵J
At the equilibrium state value of Gibb's free energy is zero, so from the equation and given data we can calculate the value of temperature as:
0 = (3352 × 10³)J - (T × 625.1 J/K) = 5362.3 K
Hence required values are 3.16 × 10⁶J, -3.83 × 10⁵J and 5362.3 K.
To know more about Gibb's free energy, visit the below link:
https://brainly.com/question/9908454
0.200 grams of HCl is dissolved in 0.801 grams water. The density of the solution formed is 1.10 g/mL. What is the molarity of the solution
Answer:
[tex]M=6.03M[/tex]
Explanation:
Hello,
In this case, since the molarity is computed by:
[tex]M=\frac{n_{solute}}{V_{solution}}[/tex]
Whereas the solute is the hydrochloric acid, we compute the corresponding moles with its molar mass (36.45 g/mol):
[tex]n_{solute}=0.200gHCl*\frac{1molHCl}{36.45gHCl} =0.00549molHCl[/tex]
Next, since the solution contains both HCl and water, we compute the volume in liters by using its density:
[tex]V_{solution}=(0.200+0.801)g*\frac{1mL}{1.10g} *\frac{1L}{1000mL} =9.1x10^{-4}L[/tex]
Therefore, the molarity turns out:
[tex]M=\frac{0.00549mol}{9.1x10^{-4}L}\\ \\M=6.03M[/tex]
Regards.