QUICK ILL GIVE BRAINLIEST
Points P(4, 7) and Q(1, 4) are two vertices of a square. Which coordinates, R and S, will make PQRS a square?
Answer:
P-4,7
Q-1,4
R-4,4
S-1,1
Step-by-step explanation:
4,4- 1,4 theres a 3 unit distance. just subtract 3 from y and you'll get the answer
  
Can someone pleaseee help if you’re correct I’ll
Give u brainlist !
Answer:
Step-by-step explanation:
Statements Reasons
1). UW bisects ∠VUX 1). Given
2). UW bisects ∠VWX 2). Given
3). ∠VUW ≅ ∠WUX 3). Definition of angle bisector
4). ∠UWV ≅ ∠UWX 4). Definition of angle bisector
5). UW ≅ UW 5). Reflexive property
6). ΔUVW ≅ ΔUXW 6). ASA postulate of congruence
Solve this help me
It is the question of class 10 Maths
Answer:
[tex]x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }[/tex]
[tex]\dfrac{9 \cdot x + 10}{3} = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3[/tex]
Therefore;
[tex]x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}[/tex]
Step-by-step explanation:
Given that we have;
[tex]x^2 - 2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} }[/tex]
[tex]x^2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} } + 2 = \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )[/tex]
[tex]x^2 = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )[/tex]
[tex]x = 3 ^{-\frac{1}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )^{\frac{1}{2} }[/tex]
[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]
[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]
[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]
[tex]x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }[/tex]
[tex]\dfrac{9 \cdot x + 10}{3} = 3 \cdot x + \dfrac{10}{3} = 3 \times \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } +\dfrac{10}{3} = \dfrac{ 3 ^{\frac{5}{3} } + 3 }{3 ^{\frac{1}{3} } } + \dfrac{10}{3}= \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } }[/tex]
[tex]\dfrac{9 \cdot x + 10}{3} =\dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } } = \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{5}{3} }+ 10 }{3 } } } = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3[/tex]
Therefore;
[tex]x^3 = \dfrac{9 \cdot x + 10}{3}[/tex]
[tex]x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}[/tex]
0.65 to 3 significant figure
Answer:
100/65 because 0.65 is a decimal number
Step-by-step explanation:
hope this helped
have a great day
Manuel bought a 3/5 of a pound of clay for the students in his pottery class. He then divided the clay into 6 equal pieces for his students to use for making vases and pots. How much did each piece weigh?
Group of answer choices
Answer:
Each piece weighed 1/10 of a pound.
Step-by-step explanation:
We have 3/5 of a pound and we want to divide it by 6 equal pieces for each student. 6 equal pieces is the same as 6/1.
In order to divide 3/5 by 6/1 we need to invert the 6/1 and multiply. So, it becomes 3/5 x 1/6. First, we multiply the numerators: 3x1=3 then we multiply the denominators: 5x6=30. The result is 3/30, which can be reduced by dividing both the numerator and denominator by 3. 3/3=1 and 30/3=10. So, the result is 1/10.
Which is the domain of y=arctan(x)
Answer:
D. All real numbers
Step-by-step explanation:
WILL MARK BRAINLIEST PLS:
Give an example of a combination of two functions, f(x) and g(x), that would result in a rational function. Be sure to identify the function type for f(x) and g(x), as well as the operation used to combine them.
Answer:
fx=3x+7 gx=5x-8
Step-by-step explanation:
here i hope this helps im not 100% sure this is what you want but its what I think
A relation is plotted as a linear function on a coordinate plane starting at point C at (3, –2) and ending at point D at (–2, 3). What is the rate of change for the linear function and what is its initial value?The rate of change is ______ and the initial value is ______.
Given:
A linear function starting at point C at (3, –2) and ending at point D at (–2, 3).
To find:
The rate of change and the initial value.
Solution:
If a linear function passes through two points [tex](x_1,y_1)\text{ and }(x_2,y_2)[/tex], then the equation of linear function is
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
The given linear function passes through (3,-2) and (-2,3). So, the equation is
[tex]y-(-2)=\dfrac{3-(-2)}{-2-3}(x-3)[/tex]
[tex]y+2=\dfrac{3+2}{-5}(x-3)[/tex]
[tex]y+2=\dfrac{5}{-5}(x-3)[/tex]
[tex]y+2=-(x-3)[/tex]
Subtracting 2 on both sides, we get
[tex]y=-x+3-2[/tex]
[tex]y=-x+1[/tex]
On comparing this equation with slope intercept form [tex]y=mx+b[/tex], where, m is slope and b is y-intercept, we get
[tex]m=-1[/tex] and [tex]b=1[/tex]
Therefore, the rate of change is -1 and the initial value is 1.
The angle lies in Quadrant II.
sin0=3/4
What is cos 0?
Answer:
cosФ is [tex]-\frac{\sqrt{7}}{4}[/tex] ⇒ B
Step-by-step explanation:
Let us solve the question using one of the identities of trigonometry
∵ sin²Ф + cos²Ф = 1
∵ sinФ = [tex]\frac{3}{4}[/tex]
→ Substitute it in the rule above to find cos Ф
∴ ([tex]\frac{3}{4}[/tex])² + cosФ² = 1
∴ [tex]\frac{9}{16}[/tex] + cosФ² = 1
→ Subtract [tex]\frac{9}{16}[/tex] from both sides
∴ cos²Ф = [tex]\frac{7}{16}[/tex]
→ Take √ for both sides
∴ cosФ = ± [tex]\frac{\sqrt{7}}{4}[/tex]
∵ Angle Ф lies on the second quadrant
∴ cosФ is a negative value
∴ cosФ = [tex]-\frac{\sqrt{7}}{4}[/tex]
∴ cosФ is [tex]-\frac{\sqrt{7}}{4}[/tex]
pls help ill give a brainly
Answer:
C. Positive 6
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
because we find the reciprocal and 9 divided by -3 and 8 divided by -4
9 divided by -3 is -3 and 8 divided by -4 is -2
so -3 times -2 is 6
Find the Valur that Would make the graphs parallel... Its alegebra please help quick i need help!
Answer:
k=8
Step-by-step explanation:
For 2 lines to be parallel, they must have the same slope. First, let's isolate y.
5y=2x+2
y=2/5x+2/5
Now, in our second equation, we must make it so that the slope is 2/5.
5(4)=20
2(4)=k
k=8
y=8/20x+10
If you simplify that, then the slope will be 2/5.
Write the expression in simpleist form PLZ WILL GIIVE BRAINLIEST
4 + 4x + 6x - 3
1. 29x + 3
2. 75x + 3
3. 22x + 1
4. 10x + 1
I need help with this
Step-by-step explanation:
income income earned working 5 hours is $50
pleaseeee helpppp !!!!!!! Mark Brianliest !!!!!!!!!!!!!!!!
Answer:
LP = 18
Step-by-step explanation:
Given that,
In ΔLPN,
LQ = 6, LM = 11 and MN = 22
We need to find the length of LP.
As QM ║PN, let QP = x
[tex]\dfrac{LQ}{LP}=\dfrac{LM}{LN}\\\\\dfrac{6}{6+x}=\dfrac{11}{11+22}\\\\\dfrac{6}{6+x}=\dfrac{11}{33}\\\\198=66+11x\\\\198-66=11x\\\\132=11x\\\\x=12[/tex]
LP = 6+x
= 6+ 12
= 18
Hence, the length of LP is 18.
Help plz plz plz plz plz !!!
HELPPPPPPPPPPPPPPPPPPP!!!
Answer:
15.13cm
Step-by-step explanation:
From that above question:
We are told that:
Lateral surface area of a right circular cone : πr√r² + h²
We are give the following parameters:
Lateral surface area = 236.64cm²
Radius = 4.75cm
We are to find the height
Making h the subject of the formula
h = √[(A/r)² - πr²]/π
h = √[(236.64/4.75)²- π ×4.75²]/π
h = 15.12975 cm
Approximately to the nearest hundredth = 15.13cm
f(x)= (x+1)/2
g(x)= 2x-1
Show your work to prove that the inverse of f(x) is g(x).
Show your work to evaluate g(f(x)).
Please help! I don't understand how to prove that they're inverse of eachother.
9514 1404 393
Answer:
g(f(x)) = x . . . so the functions are inverses
Step-by-step explanation:
Two functions f and g are inverses of each other if ...
g(f(x)) = x or f(g(x)) = x
We are asked to evaluate g(f(x)). That will be x if the functions are inverses.
g(f(x)) = g((x+1)/2) = 2((x +1)/2) -1 = (x +1) -1
g(f(x)) = x . . . . the functions are inverses
Anyone know? Thank you!!
Answer:
reflect over x axis
x+3 y+3
Step-by-step explanation:
Eric plays poker with his friends on Friday and Saturday nights. Last month he won $15, won $8, lost $12, won $23, lost $3, lost $30, and missed the last weekend. What was the net result of his playing? (Did you get that he won $1?)
Answer:
$1
Step-by-step explanation:
What is the slope of a line that is perpendicular to the line y=2x+3?
Answer: -1/2
Step-by-step explanation: whenever a line is perpendicular you take the opposite reciprocal of the current slope.
Hello!
Perpendicular lines have slopes that are opposite reciprocals.
It means we take a number, flop it over and then make it negative.
So if we have 2, we flop it over:
[tex]\frac{1}{2}[/tex]
Then, we make it negative:
[tex]-\frac{1}{2}[/tex]
That is the slope. Hope it helps
If you have any query, please ask me! :)
~A forlorn girlie
[tex]MagicalNature[/tex]
The slope of the line is -1 the y intercept is (0,-6)
Answer:
y=-1x-6
Step-by-step explanation:
you can also use y=-x-6 but its your choice
Bilal’s favorite colors are \red{\text{red}}redstart color #df0030, start text, r, e, d, end text, end color #df0030 and \green{\text{green}}greenstart color #28ae7b, start text, g, r, e, e, n, end text, end color #28ae7b. He has \red{\text{1 red shirt}}1 red shirtstart color #df0030, start text, 1, space, r, e, d, space, s, h, i, r, t, end text, end color #df0030, \green{\text{1 green shirt}}1 green shirtstart color #28ae7b, start text, 1, space, g, r, e, e, n, space, s, h, i, r, t, end text, end color #28ae7b, \red{\text{1 red hat}}1 red hatstart color #df0030, start text, 1, space, r, e, d, space, h, a, t, end text, end color #df0030, \green{\text{1 green scarf}}1 green scarfstart color #28ae7b, start text, 1, space, g, r, e, e, n, space, s, c, a, r, f, end text, end color #28ae7b, \red{\text{1 red pair of pants}}1 red pair of pantsstart color #df0030, start text, 1, space, r, e, d, space, p, a, i, r, space, o, f, space, p, a, n, t, s, end text, end color #df0030, and \green{\text{1 green pair of pants}}1 green pair of pantsstart color #28ae7b, start text, 1, space, g, r, e, e, n, space, p, a, i, r, space, o, f, space, p, a, n, t, s, end text, end color #28ae7b. Bilal selects one of these garments at random. Let AAA be the event that he selects a green garment and let BBB be the event that he chooses a scarf. Which of the following statements are true? Choose all answers that apply: Choose all answers that apply: (Choice A) A P(A\text{ | }B)=P(A)P(A | B)=P(A)P, left parenthesis, A, start text, space, vertical bar, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, the conditional probability that Bilal selects a green garment given that he has chosen a scarf is equal to the probability that Bilal selects a green garment. (Choice B) B P(B\text{ | }A)=P(B)P(B | A)=P(B)P, left parenthesis, B, start text, space, vertical bar, space, end text, A, right parenthesis, equals, P, left parenthesis, B, right parenthesis, the conditional probability that Bilal selects a scarf given that he has chosen a green garment is equal to the probability that Bilal selects a scarf. (Choice C) C Events AAA and BBB are independent events. (Choice D) D The outcomes of events AAA and BBB are dependent on each other. (Choice E) E P(A\text{ and }B)=P(A) \cdot P(B)P(A and B)=P(A)⋅P(B)P, left parenthesis, A, start text, space, a, n, d, space, end text, B, right parenthesis, equals, P, left parenthesis, A, right parenthesis, dot, P, left parenthesis, B, right parenthesis, the probability that Bilal selects a garment that is green and is a scarf is equal to the probability that Bilal selects a green garment multiplied by the probability that he selects a scarf.
Answer:
d
Step-by-step explanation:
its right on khan
Write -7/10 as a decimal.
Can someone help me plss! ?
Developmental norms are used as a benchmark to determine where one should be developmentally. Please select the best answer from the choices provided T F
Answer:
True
Step-by-step explanation:
ed 2020. I went back to check the answer so 100% right.
Answer:
tru
Step-by-step explanation:
PLEASE HELP!!! THIS IS IMPORTANT!!! ILL MARK BRAINLIEST! THIS IS 15 POINTS!!
Answer: 146n is the answer 100%
Which graph shows a line with a slope of 1/2
and a y-intercept of 2?
Answer:
1.
Step-by-step explanation:
The line goes through positive 2
Answer:
2
Step-by-step explanation:
the slope has to intercept at y=2 and slope is rise over run so you would go up 1 and over 2.
Solve x^0 someone help me please
Answer:
x = 1
Step-by-step explanation:
Four less than the sum of a number and six is ten.
Someone please help
Answer:
8
Step-by-step explanation:
since u first do six + 8 which is 14. Then u do 14 - 4 which is 10
Plz mark as brainliest
Answer:
x=2
Step-by-step explanation:
x = the number
x + 6 = 6x - 4
Solve for x and get
5x = 10
Reilly and Samantha work at frosty freeze ice cream shop. Reilly works every other day, and Samantha works every third day. Today they are working together. How many days will it be until the next time they work together?
Answer:
6 days
Step-by-step explanation:
Given that Reilly works every other day (This means that she works every 2 days) while Samantha works every third day. Today both of them are working together.
The next day none of them will be working, on the second day only Reilly would be working, on the third day only Samantha would be working, on the fourth day only Reilly would be working, on the fifth day none will be working and on the sixth day both Reilly and Samantha would be working.
This is the same as finding the least common multiple (LCM) of 2 days and 3 days which is 6 days