The example of an object with a non-zero kinetic energy is 'The International Space Station orbits the Earth' The correct option is C.
Kinetic energy is possessed by the objects which are in motion. The bodies at rest and which are in stationary position have zero kinetic energy. The SI units of kinetic energy is joule and CGS unit is erg.
Between things, kinetic energy is transmitted and has the potential to change into other types of energy.
The pendulum of the clock which is still has zero velocity, a boulder resting has zero velocity, car resting has zero velocity, a train parked has zero velocity.
The international space station orbiting the earth is in continuous motion so 'v' is a positive value and kinetic energy value is non-zero.
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calculate the temperature change in 200 g of water if it is heated, using 9000 cal
The heat energy for water used to raise the temperature by one degree Celsius is 4.15 J. Then temperature change in 200 g water using 9000 cal is 453 °C.
What is specific heat ?Specific heat capacity of a substance is the energy required to raise the temperature by 1 degree Celsius by one degree per one gram of the substance.
The specific heat of water is 0.415 J/°C g. Then the heat energy required by 200 g is : 200 g × 0.415 J/°Cg = 83 J/°C.
83 J of heat energy is required by 200 g of water to raise temperature by one degree Celsius. Then the temperature that can be made by 9000 cal energy is:
1 cal = 4.18 J
9000 cal = 37620 J
83 J is required for one degree. Then temperature change by 37620 J is:
37620 J/80 J°C = 453°C.
Therefore, the temperature change of water will be 453°C.
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Vector & has a magnitude of 3.2 units and makes +45° with the +x-axis. Vector b has a magnitudeof 2.4 units, and makes +290° with the +x-axis. What is the dot product of the two vectors?A) -3.2(B -2.5c 3.2D) 2.4E 5.6
a) -3.2 is the scalar product or dot product between the two vectors A and B
We know that the angle is measured from the +ve x-axis in the anti-clockwise direction.
The dot product is the multiplication of the magnitude of 2 vectors with the cosФ.
of the angle between them
Ф = Ф1 - Ф2
= 290-45
= 245°
A.B = A B cosФ
= 3.2 2.4 cos 245°
= - 3.24
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What is the ratio of the density of a material to the density of water?
The ratio of density of a material to the density of water is known as relative density or specific gravity.
According to water at 4 °C, specific gravity often refers to relative density.
A substance's specific gravity is determined by dividing its mass by the mass of an equivalent volume of water at the same pressure and temperature. The ratio of the densities of the two materials is also this.
This physical quantity does not possess units as it is a ratio of two similar physical quantities.
The relative density of water is said to be 1, ice is 0.92, sea water is 1.03.
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how is the gauge factor related to the sensitivity specification
The gauge factor and sensitivity specification are related because the sensitivity specification can be derived from the gauge factor and nominal resistance of the strain gauge
The gauge factor is a dimensionless quantity that defines the sensitivity of a strain gauge to a change in resistance as a result of mechanical strain. It is defined as the ratio of the change in electrical resistance to the original resistance per unit strain. The gauge factor is a property of the material used in the strain gauge and is typically between 2 and 3 for most metallic strain gauges.
The sensitivity specification of a strain gauge refers to the amount of change in resistance per unit of strain and is typically specified in units of ohms per microstrain. This specification can be derived from the gauge factor and the nominal resistance of the strain gauge. For example, if a strain gauge has a gauge factor of 2 and a nominal resistance of 120 ohms, its sensitivity would be 240 ohms per microstrain.
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A 40kg child sits on a seesaw 3 meters away from the pivot point. The mass of the bar is 10kg. Where should a 30kg child sit to balance the seesaw? What is the Normal Force exerted by the pivot point?
The correct answer is 4m
Imagine the seesaw is pivoted at center
Net moment about pivot= 0
30gx × 40×3 =0
Distance, x= 4m
What is distance?
The distance between two points in physical space is the length of the straight line between them, which is the shortest possible path. It is the usual meaning of distance in classical physics, including Newtonian mechanics.Straight distance is formalized mathematically as Euclidean distance in two and three dimensional space.To know more about distance, click the link given below:
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According to the question of mass, the 30kg child should sit 1.5 meters away from the pivot point.
What is mass?
Mass is a fundamental property of matter which is a measure of the amount of matter an object contains. It is usually measured in units of grams (g), kilograms (kg), or tonnes (t). Mass is related to weight, but unlike weight, mass is not affected by gravity. Mass is a scalar quantity, meaning it has magnitude but no direction. All objects, regardless of their shape or size, have mass. Mass is an intrinsic property of matter, meaning it is always the same regardless of the environment the object is in.
The Normal Force exerted by the pivot point can be calculated by using the equation F = mg, where F is the Normal Force, m is the mass of the bar and g is the acceleration due to gravity. In this case, the Normal Force is 300N (30kg x 10m/s2).
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what is the ratio of the momentum of a particle with a rest mass mo and kinetic energy ekin to the momentum of a photon of eγ = hv
The ratio of two momenta is calculated to be √( (mo² * c⁴) + (2 * mo * c² * E_kin) ) / E_γ .
The equation states that a particle with rest mass mo and kinetic energy E_kin has the following momentum:
p = √( (mo² * c²) + (2 * mo * c² * E_kin / c²) )
where, c is the speed of light.
The momentum of a photon with energy E_γ is given by the equation:
p_γ = E_γ / c
The ratio of the two momenta is:
p / p_γ = √( (mo² * c²) + (2 * mo * c² * E_kin / c²) ) / (E_γ / c)
= √( (mo² * c²) + (2 * mo * c² * E_kin / c²) ) * c / E_γ
= √( (mo² * c⁴) + (2 * mo * c² * E_kin) ) / E_γ
As the particle approaches the speed of light, its momentum approaches infinity, while the momentum of the photon remains constant.
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what is the difference between heat capacity, specific heat, and latent heat? select all statements that are true. what is the difference between heat capacity, specific heat, and latent heat? select all statements that are true. latent heat describes the amount of heat energy exchanged to change the phase of an object. specific heat and heat capacity describe the amount of heat energy required to change the temperature of an object. latent heat describes the amount of heat energy required to change the temperature of an object. specific heat depends on the mass of the object while heat capacity only depends on the material the object is made of. specific heat and heat capacity describe the amount of heat energy exchanged to change the phase of an object. heat capacity depends on the mass of the object while specific heat only depends on the material the object is made of.
The amount of energy necessary to increase a substance's temperature by 1°C (1 K) per unit mass is called its specific heat capacity. The amount of energy needed to change a substance's phase without causing a temperature change is known as latent heat.
What is specific heat ?
The amount of energy required to raise a substance's temperature by one degree Celsius per gramme is referred to as specific heat. Specific heat is typically measured in calories or joules per gramme per degree Celsius. Water, for example, has a specific heat of 1 calorie (or 4.186 joules) per gramme per degree Celsius.
The value of specific heat is unaffected by the size of the sample because it is the heat capacity per unit mass.
The term "latent heat" (L) refers to the energy that is either absorbed or released when a substance undergoes a phase change. A gas to a liquid transition, a liquid to solid transition, or the reverse is possible. ld either be from a gas to a liquid or liquid to solid and vice versa.
L = Q/m
L is the specific latent heat, Q is the heat retained or discharged and m is the mass of a substance.
1) False(During phase transition temperature does not change)
2) True
3) True
4) False (energy to change phase is latent heat)
5) False
6) True
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a bedding plane dips 190/80 with slicken lines on the surface that trend n60w. using a stereonet, determine the plunge of the lineation
The plunge of a lineation on a bedding plane can be determined by plotting the dip and strike of the bedding plane and the trend of the lineation on a stereonet.
How to do it:
Plot the bedding plane's dip and strike as a large circle on the stereonet.
Place a line on the stereonet to represent the lineation's trend.
The lineation plunge is represented by the point where the lineation line and the bedding plane circle intersect.
In this instance, the lineation trends N60W, while the bedding plane descends 190/80. Plotting these on a stereonet and locating their junction would yield the plunge.
Be aware that a stereonet is a type of graph paper used specifically for mapping and analysing geological features including bedding planes and lineations.
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Two balloons are filled to 2.0 L at 20°C. One is filled with helium gas, while the other is filled with hydrogen gas. If the pressure exerted by the balloons are the same, we can conclude that: I. The mass of each balloon including the filled gases is the same. II. The number of molecules of gas in each balloon is the same. III. The number of moles of gas in each balloon is the same.
III. There are the same number of moles of gas in each balloon. We are aware that equal volumes of various gases contain an identical number of molecules at the same pressure and temperature.
What is volume and mass?Volume is a unit used to describe how much space a substance takes up. A physical material with mass and space-occupying properties is referred to as matter. The usual measurement of volume in physical sciences like chemistry is in cubic metres (m3).V is volume, and m is mass, therefore v = V / m. Where is density, = 1 / = -1. Where R is the ideal gas constant, T is the temperature, P is the pressure, and M is the molarity, the equation is: = RT / PM = RT / P.The amount of matter in an object or substance is measured by its mass.
• Weighted in kilos and grammes (kg).
• A balance is used to calculate mass.
• Mass, unlike weight, is unaffected by variations in gravity. For instance, a massive block of ice weighs significantly less in space due to the weaker gravity, but its mass remains constant
Mass of a substance = volume × density.
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A bullet shot underwater will experience "viscous drag" and follow this velocity equation: v_x(t) = v_ie^-bt where v_i = 365 m/s and b = 0.42 s^-1. The bullet has an initial position x_i = 85.1 m at t_i = 0 s. What is the location of the bullet at time t = 0.87 seconds? What is the maximum position of the bullet (if you wait a long time, what will its position be)? What is the x component of the acceleration of the bullet 0.5 seconds after the bullet is fired?
The derivative of the velocity equation, a x(t), gives the x component of the bullet's acceleration 0.5 seconds after it is fired: a x(t) = -b * v x(t) = -b * v i * e-bt = -0.42 * 365 * e-0.5 * 0.42 m/s2.
The bullet is located at x(0.87) = x i + v i * (1 - e-bt) = 85.1 + 365 * (1 - e-0.87 * 0.42) m at time t = 0.87 seconds.
The bullet's maximum location is reached when the velocity equals zero, which happens when v x(t) = 0. We obtain t = -ln(v i/v x) / b after solving for t. When the numbers are substituted, the result is t = -ln(365/0)/0.42, which is undefined because the denominator is zero.
The derivative of the velocity equation, a x(t), gives the x component of the bullet's acceleration 0.5 seconds after it is fired: a x(t) = -b * v x(t) = -b * v i * e-bt = -0.42 * 365 * e-0.5 * 0.42 m/s2.
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An object is initially at rest and then accelerates for a time interval At. After At, the object has displaced 1.5 m in the +x-direction and has an instantaneous velocity of 3.5 m/s in the +x-direction. Using relevant expressions from the reading, determine: (a) The average acceleration of the object (b) The time it took the object to travel 1.5 meters (c) The average velocity of the object during this period of motion
a) Average acceleration of the object would be 3.5 m/s / At.
b) The time it took the object to travel 1.5 meters is (2 × distance / acceleration) ^(1/2).
c) The average velocity of the Object during this period of motion 1.5 m / time.
What is average velocity?Average velocity is a measure of the change in an object's position over a certain time period. It is calculated as the total distance traveled divided by the total time elapsed. Mathematically, it is represented as:
average velocity = (final position - initial position) / time interval
a) Average acceleration of the object can be determined using the equation:
average acceleration = change in velocity / time interval
Since the final velocity of the object is 3.5 m/s, and it was initially at rest (velocity = 0 m/s), the change in velocity is 3.5 m/s.
So,average acceleration = 3.5 m/s / At
b) The time it took the object to travel 1.5 meters can be determined using the equation:
distance = initial velocity * time + (1/2) * acceleration * time^2
Since the initial velocity was 0 m/s and the acceleration is the average acceleration determined in (a), we can rearrange the equation and solve for time:
time = (2 × distance / acceleration)^(1/2)
c) The average velocity of the Object during this period of motion can be determined using the equation:
average velocity = total distance traveled / total time elapsed
Since the object traveled a total distance of 1.5 meters and the time elapsed is the time determined in (b), we can calculate the average velocity:
average velocity = 1.5 m / time.
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When a system _____, ΔE is always negative.
a. absorbs heat and does work.
b. gives off heat and does work.
c. gives off heat and has work done on it.
d. absorbs heat and has work done on it.
e. none of the above is always negative.
The internal energy change, or E, is a metric for how much a system's internal energy shifts. If the internal energy change is negative, the system's internal energy must have dropped.
What is the easiest way to define energy?Reasons can be attributed to power generation as the power to work. People have figured out how to transform energy from one medium to some other then use it to accomplish tasks, making modern civilization possible.
From whence do we get our energy?The entirety of the world's electricity generating was made up of coal, nuclear energy, and shale gas in 2020. Renewable energy sources including wind, hydropower, solar, biogas, wind, and groundwater are also used to generate electricity.
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The internal energy change, or E, is a metric for how much a system's internal energy shifts. If the internal energy change is negative, the system's internal energy must have dropped.
What is the easiest way to define energy?
Reasons can be attributed to power generation as the power to work. People have figured out how to transform energy from one medium to some other then use it to accomplish tasks, making modern civilization possible.
From whence do we get our energy?
The entirety of the world's electricity generating was made up of coal, nuclear energy, and shale gas in 2020. Renewable energy sources including wind, hydropower, solar, biogas, wind, and groundwater are also used to generate electricity.
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Because sound is a wave, it's possible to make a diffraction grating for sound from a large board of sound-absorbing material with several parallel slits cut for sound to go through. When 11 kHz sound waves pass through such a grating, listeners 8. 0 m from the grating report "loud spots" 1. 6 m on both sides of the center. What is the spacing between the slits? Use 340 m/s for the speed of sound
The diffraction grating equation, d sin θ = mλ, is used to calculate the grating spacing, d, in a diffraction grating. The equation relates the wavelength of the wave, λ, the grating spacing, d, and the diffraction angle, θ.
The diffraction angle is defined as the angle between the incident wave and the diffracted wave as it leaves the grating. The integer, m, represents the order of the diffracted wave and can be 0, 1, 2, and so on. To determine the grating spacing, you would need to know the diffraction angle, the wavelength of the 11 kHz wave, and the value of m. The speed of sound, which is 340 m/s, can then be used to calculate the wavelength of the wave. Once the wavelength is known, the diffraction grating equation can be used to determine the grating spacing.
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In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9. 80 m/s2. Ignore air resistance.
The flea's initial velocity as it jumps is -2.45 m/s, calculated by using kinematic equations considering maximum height, acceleration due to gravity, and time.
To track down the underlying speed (v0) of the bug as it leaves the ground, we can utilize the accompanying kinematic condition:
d = vi * t + 0.5 * a * t^2
Where,
d = 0.500 m (the greatest level the insect comes to)
a = - 9.80 m/s^2 (speed increase because of gravity)
t = the time it takes for the insect to arrive at the greatest level
Since the bug hops straight up and arrives at a greatest level, its last speed by then will be 0 m/s. We can likewise utilize the accompanying condition to track down t:
vf = vi + at
Where,
vf = 0 m/s (last speed at the greatest level)
a = - 9.80 m/s^2 (speed increase because of gravity)
Subbing t from this situation into the primary condition, we can settle for the underlying speed vi:
0.500 = vi * t + 0.5 * (- 9.80) * t^2
vi * t = - 4.9 * t^2
vi = - 4.9 * t
Presently, subbing t and vi into the subsequent condition, we can settle for t:
0 = vi + (- 9.80) * t
0 = - 4.9 * t + (- 9.80) * t
9.80 * t = 4.9 * t
t = 4.9/9.80 = 0.5 s
At last, subbing t into vi = - 4.9 * t, we can track down the underlying speed:
vi = - 4.9 * 0.5 = - 2.45 m/s
Hence, the underlying speed of the insect as it leaves the ground is - 2.45 m/s.
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The complete question is:
In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80 m/s. Ignore air resistance. A flea jumps straight up to a maximum height of 0.500 m . What is its initial velocity v0 as it leaves the ground?
A bullet of mass 0,02 kg is fired horizontally into a suspended stationary wooden block of mass 1,95 kg with a velocity of 20 m-s1, as shown in the diagram. Ignore the effects of air resistance. 2.1 Define, in words, the term momentum as applied in physics. 2.2 Calculate the momentum of the bullet just before impact. The bullet is embedded in the wooden block after collision. 2.3 State the principle of conservation of linear momentum in words. 2.4 Calculate the common velocity of both the bullet and the block after collision 2.5 Is this collision ELASTIC or INELASTIC? Use appropriate calculations to explain the answer
Answer:
28.54J
Explanation:
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Class 11
>>Physics
>>Systems of Particles and Rotational Motion
>>Linear Momentum of a System of Particles
>>A bullet of mass 0.012 kg and horizontal
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A bullet of mass 0.012 kg and horizontal speed 70 ms
−1
strikes a block of wood of mass 0.4 kg and instantly comes to rest with respect to the block. The block is suspended from the ceiling by means of thin wires. Calculate the height to which the block rises. Also, estimate the amount of heat produced in the block.
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Mass of the bullet, m = 0.012 kg
Initial speed of the bullet, u
b
=70m/s
Mass of the wooden block, M=0.4 kg
Initial speed of the wooden block, u
B
=0
Final speed of the system of the bullet and the block = v m/s
Applying the law of conservation of momentum:
mu
b
+Mu
B
=(m+M)v
0.012×70+0.4×0=(0.012+0.4)v
v=0.84/0.412
=2.04 m/s
For the system of the bullet and the wooden block:
Mass of the system, m
′
=0.412 kg
Velocity of the system =2.04m/s
Height up to which the system rises = h
Applying the law of conservation of energy to this system:
Potential energy at the highest point = Kinetic energy at the lowest point
m
′
gh=(1/2)m
′
v
2
h=
2g
v
2
=
2×9.8
(2.04)
2
=0.2123m
The wooden block will rise to a height of 0.2123m.
The heat produced = Kinetic energy of the bullet - Kinetic energy of the system
=(1/2)mu
2
−(1/2)m
′
v
2
=(1/2)×0.012×(70)
2
−(1/2)×0.412×(2.04)
2
=29.4−0.857=28.54J
Let u =-121+ 2j-2k, v =j-6k, w = 6i-j + k. Which vectors, if any are (a) perpendicular? (b) Parallel?
a) Perpendicular vectors:
Two vectors are perpendicular if their dot product is equal to 0. The dot product between two vectors is defined as:
u • v = |u| |v| cos(Θ)
where Θ is the angle between the two vectors and |u| and |v| are their magnitudes. If the dot product is equal to 0, it means that the angle between the two vectors is equal to 90 degrees, so they are perpendicular.
To determine whether u, v and w are perpendicular, we can calculate the dot product between each pair of vectors.
u • v = (-121 + 2j - 2k) • (j - 6k) = -2j + 12k
u • w = (-121 + 2j - 2k) • (6i - j + k) = 2j + 6k
v • w = (j - 6k) • (6i - j + k) = -6j - 36k
Since the dot product between each pair of vectors is not equal to 0, we can conclude that u, v and w are not perpendicular to each other.
b) Parallel vectors:
Two vectors are parallel if they have the same direction or the opposite direction. To determine whether u, v and w are parallel, we can calculate the scalar multiple of one vector that would equal the other vector.
If u = kv or u = -kv, where k is a scalar, then u and v are parallel. If k = |u| / |v|, then u and v are in the same direction. If k = -|u| / |v|, then u and v are in the opposite direction.
Let's apply this to each pair of vectors:
u and v:
k = |u| / |v| = sqrt((-121 + 2j - 2k) • (-121 + 2j - 2k)) / sqrt((j - 6k) • (j - 6k)) = 11 / sqrt(73)
Since k is not equal to -|u| / |v|, we can conclude that u and v are not parallel.
u and w:
k = |u| / |w| = sqrt((-121 + 2j - 2k) • (-121 + 2j - 2k)) / sqrt((6i - j + k) • (6i - j + k)) = 11 / sqrt(97)
Since k is not equal to -|u| / |w|, we can conclude that u and w are not parallel.
v and w:
k = |v| / |w| = sqrt((j - 6k) • (j - 6k)) / sqrt((6i - j + k) • (6i - j + k)) = sqrt(73) / sqrt(97)
Since k is not equal to -|v| / |w|, we can conclude that v and w are not parallel.
Therefore, none of the vectors u, v and w are parallel to each other.
In conclusion, we found that u, v and w are neither perpendicular nor parallel to each other.
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Categorize each description below under the principle that describes that particular behavior of fluids.
Descriptions:
Describes hydraulic lifts
Describes airplane flight
Describes floating objects
Buoyant force equals weight of fluid displaced
Pressure decreases as a fluid moves faster
Pressure is the same throughout an enclosed fluid
Principles:
Archimedes' principle
Bernoulli's principle
Pascal's principle
each description below under the principle that describes that particular behavior of fluids:
Buoyant force equals weight of fluid displaced - Archimedes' principle
Pressure decreases as a fluid moves faster - Bernoulli's principle
Pressure is the same throughout an enclosed fluid - Pascal's principle
Describes hydraulic lifts - Pascal's principle
Describes airplane flight - Bernoulli's principle
Describes floating objects - Archimedes' principle
What is fluid?Fluids are defined as any material that flows in response to an applied force; hence, liquids and gases are fluids. Fluids are non-fixed-shape substances that flow readily due to enlarged intermolecular gaps. Fluids include both liquids and gases. When exposed to such a stress, a fluid, any liquid or gas, or any substance in general cannot maintain a tangential, or shearing, force and suffers a constant change in form.
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A 1250 kg car traveling at a speed of 25.0 m/s rounds a 175 m radius curve.
Assuming the road is level, determine the coefficient of static friction between the car’s tires and the road.
Assuming that the curve is banked and the road is frictionless, determine the bank angle with respect to the horizontal.
The tire's static friction coefficient with the ground is 0.3.
What is static friction?
Static friction is a force that maintains an object at rest. Static friction is defined as the resistance one encounters when attempting to move a stationary object across a surface without actually moving their body or the surface, they are moving the object across.
Give a static friction illustration.
Static friction has an impact on an object when it is resting on a surface. For instance, when hiking through the woods, there is static friction created between your shoes and the ground with each step you take.
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in the human body when the triceps applies a force to the olecranon in extending the non-supported forearm at the elbow, it exemplifies: second-class levers. none of the answers are correct. first-class levers. third-class levers.
Option d. third-class levers. When the triceps applies a force to the olecranon in extending the non-supported forearm at the elbow, it exemplifies third-class levers.
In the human body, when the rear arm muscles applies a power to the olecranon in broadening the non-upheld lower arm at the elbow, it represents second rate class switches.
A second rate class switch is a switch framework where the work (the power applied by the rear arm muscles muscle) is situated between the heap (the heaviness of the lower arm) and the support (the elbow joint). In second rate class switches, the work is typically more prominent than the heap and the development is more slow contrasted with five star switches. Nonetheless, second rate class switches give a mechanical benefit, implying that a more modest power can be utilized to move a bigger burden.
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The complete question is in the human body when the triceps applies a force to the olecranon in extending the non-supported forearm at the elbow, which of the following class levers:
a. second-class levers.
b. first-class levers.
c. none of the answer are correct.
d. third-class levers.
the position of the particle as a function of time is given by x(t) = e-(t - 3)2, where x is in meters and t is in seconds. what is the velocity of the particle, in meters per second, at t = 2.9 s?
For a particle having a position of function e^-(t - 3)², the velocity at 2.9 s is calculated to be 0.198008 m/s.
The position of a particle is denoted by a function x(t) = e^-(t - 3)², where x is the distance and t is the time.
Differentiate the function, to find velocity.
v(x) = d/dt(x) = d/dt[e^-(t - 3)²]
v(x) = e^-(t - 3)²[-2(t - 3)]
Now, substitute the value of t = 2.9 in the equation
v(2.9) = e^-(2.9 - 3)²[-2(2.9 - 3)]
v(2.9) = e^-(-0.1)²[-2(-0.1)]
Use the exponent formula a^-b = 1/a^b
v(2.9) = 1/e^(-0.1)²[0.2]
v(2.9) = 1/e^(0.01)[0.2]
Substitute the value of e^0.01 = 1.01005
v(2.9) = (1/1.01005)[0.2]
Use the arithmetic operation of division,
v(2.9) = (0.99004)[0.2]
v(2.9) = 0.198008
Therefore, the velocity of the particle is 0.198008 m/s.
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The concept of habituation is best exemplified by which of the following situations?
a. An infant recognizes her father's voice
b. A college student is no longer kept awake by her roommate's late night typing.
c. a kitten avoids a couch after being reprimanded for sitting on it
d. A rat learns to press a bar for food when a red light is flashed
e. A motorist drives at the speed limit when there is a police driver in sight on the highway
The concept of habituation is best exemplified by situation b, where a college student is no longer kept awake by her roommate's late night typing.
Habituation refers to the decrease in responsiveness to a stimulus after repeated exposure to it. This means that over time, the student becomes less and less responsive to the sound of typing, and it no longer disrupts her sleep.
Habituation is a basic form of learning and is thought to be an adaptive mechanism, allowing organisms to conserve energy by ignoring irrelevant stimuli. It is often observed in infants and young animals, but can occur in any organism that is capable of learning.
In situation a, an infant recognizes her father's voice, this is not an example of habituation, but rather an example of classical conditioning. In situation c, a kitten avoids a couch after being reprimanded for sitting on it, this is an example of classical conditioning or a form of punishment-based learning. In situation d, a rat learns to press a bar for food when a red light is flashed, this is an example of operant conditioning. And in situation e, a motorist drives at the speed limit when there is a police driver in sight on the highway, this is an example of social learning.
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etermine whether the series is convergent or divergent. [infinity] 1 9n 5 n n = 1
The series 1 9n 5 n n = 1 is a divergent series .
What are divergent series?Divergent series are mathematical series that do not have a well-defined sum. These series grow without bound and their values increase indefinitely, making it impossible to determine the exact sum. The terms in a divergent series may approach a specific value, but they never reach it, making it impossible to determine the limit of the series. This type of series is often contrasted with convergent series, which have a well-defined sum and approach a specific value as the number of terms in the series increases. Divergent series have important implications in many areas of mathematics and are often used to demonstrate the limitations of mathematical models and theories.
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15 What are the S.I. units of K so that the equation Velocity = K x density is dimensionally correct? Give your answer in terms of the basic units. (Kg ¹m45-¹)
The S.I units of K so that the equation velocity = K × density is dimensionally correct is Kg⁻¹m⁴s⁻¹
How do I determine the S.I units of K?Velocity is defined as follow:
Velocity = displacement / time
Thus, the S.I units of velocity is m/s
Density is defined as mass per unit volume i.e
Density = mass / volume
Thus, the S.I units of density is Kg/m³
With the above information, we can determine the the S.I units of K. Details below:
S.I units of velocity = m/sS.I units of density = Kg/m³S.I units of K =?Velocity = K × density
m/s = K × Kg/m³
Divide both sides by Kg/m³
K = (m/s) / (Kg/m³)
Invert
K = m/s × m³/Kg
K = m⁴/sKg
K = Kg⁻¹m⁴s⁻¹
Thus, we can conclude that the S.I units of K is Kg⁻¹m⁴s⁻¹
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In a typical IR spectrum, what name describes the units shown on the x-axis?
The units shown on the x-axis of a typical IR spectrum are usually called wavenumbers (cm⁻¹).
What is IR spectrum?An IR spectrum is a graph that displays the intensity of infrared light at different wavelengths. It is used to identify and characterize a variety of molecules. By recording the infrared spectrum of a sample, scientists can determine the molecular structure of a substance. This is because different molecular structures absorb different amounts of infrared light at different frequencies. The IR spectrum is made up of distinct peaks which correspond to specific bonds in the molecule. The position, intensity and shape of the peaks provide information on the type of bonds and the number of atoms present in the molecule.
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investigating the relationship between the vertical deflection of the cantilever and the distance at which the external force is applied on the cantilever uwc maastricht
The vertical deflection of a cantilever is the amount of bending or deformation experienced by the structure when an external force is applied to it. This external force could be due to a variety of reasons, such as a weight or a wind load.
The relationship between the vertical deflection of the cantilever and the distance at which the external force is applied is an important aspect of structural engineering and can be studied through mathematical models and simulations.
When an external force is applied to a cantilever, it creates a stress and a strain in the structure. The vertical deflection is a result of the strain experienced by the cantilever, which is proportional to the stress experienced by the structure.
The relationship between the vertical deflection and the distance at which the external force is applied is given by the equation of the beam, which can be derived using mathematical models such as the Euler-Bernoulli beam theory.
One of the key factors that affects the vertical deflection of a cantilever is the location of the external force. The farther away the external force is from the fixed end of the cantilever, the less the deflection will be. Conversely, the closer the external force is to the fixed end, the greater the deflection will be.
In conclusion, the relationship between the vertical deflection of a cantilever and the distance at which the external force is applied is an important aspect of structural engineering.
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What is the label of the parts of microscope?
the elements of a microscope's label The specimen's picture is enlarged by the eyepiece lens. Body tube or eyepiece tube. The eyepiece is kept in the tube. Nosepiece. unbiased lenses Stage Arm. Script clips. .
What is the definition and purpose of a microscope?A telescope is a tool that can be utilized to examine cells and other tiny objects. Through at least single lens in the microscope, an object's picture is enlarged. Because of the way this lens bends light, an object appears larger than it is.
Why is it crucial to recognize the components of a microscope?Before utilizing a microscope, you should become familiar with its various components because you'll need to learn where each one is located on your instrument.
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Using W = ΔU = q (Vf - Vi)
a. How much work is done in bringing a 1nC test charge from infinity to a distance of 50cm from a +1nC charge that is already in the simulation?
b. How much work is done in bringing a 1nC test charge from infinity to a distance of 50cm from a -1nC charge that is already in the simulation?
In both cases, the work done can be calculated using the equation W = ΔU = q (Vf - Vi). The only difference is the sign of the potential energy change, which determines the direction of the work done.
The equation W = ΔU = q (Vf - Vi) relates the work done (W) to the change in potential energy (ΔU) of a charged particle with charge q, moving from an initial potential (Vi) to a final potential (Vf) due to an electric field.
a. When a positive test charge (q1) is brought from infinity towards a positive fixed charge (q2), work is done against the electric field created by q2. The electric potential at a point in the field is given by V = kq/r, where k is Coulomb's constant and r is the distance from the charge. Thus, the work done in bringing the test charge from infinity to a distance of 50cm from the positive fixed charge can be calculated as follows:
Vi = kq2/r = k(1 nC)/(infinity) = 0
Vf = kq2/r = k(1 nC)/(0.5 m)
q1 = 1 nC (positive)
ΔU = q1 (Vf - Vi) = 1 nC * (k(1 nC)/(0.5 m) - 0)
W = ΔU = q1 ΔV = 1 nC * k(1 nC)/(0.5 m)
b. When a positive test charge is brought from infinity towards a negative fixed charge, work is done in the direction of the electric field created by the negative charge. The potential at a point in the field created by a negative charge is negative. Thus, the work done in bringing the test charge from infinity to a distance of 50cm from the negative fixed charge can be calculated as follows:
Vi = kq2/r = k(-1 nC)/(infinity) = 0
Vf = kq2/r = k(-1 nC)/(0.5 m)
q1 = 1 nC (positive)
ΔU = q1 (Vf - Vi) = 1 nC * (k(-1 nC)/(0.5 m) - 0)
W = ΔU = q1 ΔV = 1 nC * k(-1 nC)/(0.5 m)
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how fast should the car be traveling just as it leaves the cliff in order to just clear the river and land safely on the opposite side?
The time and speed of the vehicle needed are:
A) The vehicle ought to go at 31.9 m/s.
B) The speed of the vehicle not long before it lands on the opposite side is 37.0 m/s.
A) If it's not too much trouble, see the joined figure for a superior portrayal of the issue. At the point when the vehicle arrives at the opposite side of the waterway, its position vector will be r₁ .The parts of this vector are r₁x and r₁y.Assuming we place the beginning of the casing of reference at the edge of the bluff, the parts of the vector r₁ will be:
r₁x = 61.0 m
r₁y = - 20.0 m + 2.1 m = - 17.9 m
The conditions for the x and y-parts of the position vector of the vehicle are the accompanying:
x = x₀ + v₀ · t,y = y₀ + 1/2 · g · t²
Where:
x = flat situation at a time t.
x₀ = beginning level position.
v₀ = beginning speed.
t = time.
y = vertical situation at a time t.
y₀ = starting vertical position.
g = speed increase because of gravity (- 9.8 m/s² thinking about the vertical bearing as certain).
Utilizing the condition of the y-part of r₁, we can make the opportunity it takes the vehicle to arrive at the opposite side of the stream. We need to set aside the opportunity at which the vector r₁y is - 17.9 m:
y = y₀ + 1/2 · g · t² (y₀ = 0 in light of the fact that the beginning of the casing of reference is situated at the edge of the bluff).
y = 1/2 · g · t²
-17.9 m = - 1/2 · 9.8 m/s² · t²
-17.9 m/ - 4.9 m/s² = t²
t = 1.91 s
Presently, utilizing the condition of the x-part, we can track down the underlying speed. We know that at t = 1.91 s, the level part of the vector r1 is 61.0 m:
x = x₀ + v₀ · t (x₀ = 0 in light of the fact that the beginning of the casing of reference is situated at the edge of the precipice).
x = v₀ · t
61.0 m = v₀ · 1.91 s
v₀ = 61.0 m/1.91 s = 31.9 m/s
The vehicle ought to go at 31.9 m/s.
B) The condition of the speed vector of the vehicle is the accompanying:
v = (v₀,+g · t)
The flat part of the speed vector is v₀, 31.9 m/s.
We should compute the worth of the upward part:
v[tex]_y[/tex] = g · t
v[tex]_y[/tex] = - 9.8 m/s² · 1.91 s
v[tex]_y[/tex] = - 18.7 m/s
Then, the speed vector of the vehicle not long before it lands on the opposite side is the accompanying:
v = (31.9, - 18.7) m/s
The extent of this vector is determined as follows:
|v| = √[(31.9 m/s)² + (- 18.7 m/s)²]
|v| = 37.0 m/s
The speed of the vehicle not long before it lands on the opposite side is 37.0 m/s.
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(Complete question) is:
A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to try leaping it with his car. The side the car is on is 20.0 m above the river, whereas the opposite side is a mere 2.1 m above the river. The river itself is a raging torrent 61.0 m wide.
A) How fast should the car be traveling just as it leaves the cliff in order to just clear the river and land safely on the opposite side?
B) What is the speed of the car just before it lands safely on the other side?
standard blueprint plans and elevations are generally drawn in is______projection.
Standard blueprint plans and elevations are generally drawn in orthographic projection.
Orthographic projection is a way of creating 2D representations of 3D objects by projecting their lines and shapes onto a flat surface. In this type of projection, parallel lines in the object remain parallel in the projection and perpendicular lines appear as perpendicular. It is used in engineering, technical drawings, and computer graphics as it provides a clear and accurate representation of the object. The final image is a combination of multiple views taken from different angles, which can be combined to create a 3D representation of the object. Orthographic projections are essential for visualizing and understanding the shape and form of objects, especially in the design and construction industries.
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An electric field is given by E = E0j, where E0 is a constant. Find the potential as a function of position, taking V = 0 at y = 0.a) 2E0yb) -E0yc) E0yd) -2E0y
The correct answer is: c) E0y. The electric field E = E0j points in the positive y-direction. The electric potential difference between two points in an electric field is given by the line integral of the electric field between the points.
In this case, the potential difference V between two points (x1, y1) and (x2, y2) can be written as:
V = ∫ E · dr
where the integral is taken along the path connecting the two points. If we take the reference potential V = 0 at y = 0, then the potential at position (x, y) can be found by integrating the electric field along the path connecting (x, 0) and (x, y):
V(x, y) = ∫_0^y E0j · dj = E0y
So, the potential at position (x, y) in the electric field E = E0j is given by:
V(x, y) = E0y
So, the correct answer is: c) E0y
The electric field E = E0j is a constant electric field that points in the positive y-direction. The electric potential at any point (x, y) in the field can be found by integrating the electric field along the path connecting the reference point (x, 0) and the point of interest (x, y). In this case, the electric potential is proportional to the displacement in the y-direction, and the proportionality constant is E0, the magnitude of the electric field.
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