Answer:
D. Malleable
Explanation:
Gold is metallic, with a yellow colour when in a mass, but when finely divided it may be black, ruby, or purple. It is the most malleable and ductile metal; 1 ounce (28 g) of gold can be beaten out to 300 square feet. It is a soft metal and is usually alloyed to give it more strength.
what is capacity and capacitor
Answer:
Explanation:
Capacity: the max amount that something can contain.
"the capacity of the freezer is 1.1 cubic feet"
capacitor: device for storing electrical energy, includes two conductor that are close to one another and insulated from each other. A simple example is a parallel-plate capacitor.
Source: Britannica.com
Answer:
capacitythe maximum amount that something can containcapacitora device used to store an electric charge, consisting of one or more pairs of conductors separated by an insulatorExplanation:
hope it helpslearn with brainlyHow much to spend on groceries per month for 1 person.
USDA Food Plan Spending for a Single Person
Low-cost: $222.60. Moderate-cost: $272.20.
As light from a star spreads out and weakens, do gaps form between the photons?
Answer:
ggggggfjhfbgehfe no idk yes maybe
Explanation:
Help me please........
Answer:
He must be riding on a horse named Saturday.
Explanation:
He rode Saturday on Friday, stayed in the town for 3 days and left on his horse, named Saturday.
I've heard this many times.
he left his house on a Thursday got their on a Friday and left on Saturday Explanation:
this is the best i can do
A machine has an efficiency of 60%. If the machine is required to overcome a load of 30N with a force of 20N, calculate its mechanical advantage?
Explanation:
eff = m.a/ v.r
m.a = L /E
30/ 20
= 1. 5
How is the final speed of the cart related to the pattern in the position data?
Answer:
it increases
Explanation:
The final speed of the cart increases in relation to the pattern in the position data.
What is speed?The rate at which an object moves along a path in time is defined as speed, whereas velocity is the rate and direction of movement.In other words, speed is a scalar value, whereas velocity is a vector. The symbol for velocity is v (italic), and the symbol for speed is v. (boldface). To represent average values, a bar is placed over the symbol.The ratio of an object's distance travelled (in any direction) to the time required to travel that distance. The rate at which the position of an object changes in any direction.The ratio of distance traveled to time spent traveling is defined as speed. Speed is a scalar quantity because it has only one direction and no magnitude.To learn more about velocity, refer to:
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If you wanted to study regions where star formation is currently happening you could use: a. H-alpha emission to look for O and B stars b. 21 cm radiation to find neutral hydrogen clouds c. radio emission from carbon monoxide (CO) to find molecular cloud cores d. infrared emission to identify T Tauri stars
Whenever someone want to study regions where star formation is currently happening Infrared emission to identify T Tauri stars.
What is star-forming region?A star-forming region serves as a region of the celestial sphere where predominately young stellar objects can be found and where formation is likely occurring.
Infrared emission to identify T Tauri stars can be used in determining the formation, however it should be noted that Einstein X-ray Observatory made earliest detections of X-rays from T Tauri stars.
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What is the value of the charge that experiences a force of 2.4 × 10–3 n in an electric field of 6.8 × 10–5 n/c? 1.6 × 10–7 c 2.5 × 10–3 c 2.8 × 10–3 c 3.5 × 101 c
The value of the charge will be 35 ×10¹ C. A charge is something experienced as a force in the electric and megnetic field.
what is the charge?When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.
Charges that are similar repel each other, whereas charges that are dissimilar attract each other. The term "neutral" refers to an item that has no net charge.
The given data in the problem is;
F is the electric force= 2.4 × 10-³ N
q is the electric charge=?
E is the strength of the electric field = 6.8 × 10⁻⁵ (N/C)
The electric force is given by;
[tex]\rm F =qE \\\\ \rm q= \frac{F}{E} \\\\ \rm q= \frac{2.4 \times 10^{-3}}{6.8 \times 10^{-5}} \\\\ \rm q=35 \times 10^1 \ C[/tex]
Hence the value of the charge will be 35 ×10¹ C
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Answer:
D
Explanation:
E2020
An 800 kg car exerts 4000N of applied force on a level road while
being opposed by 700 N of friction. Determine the acceleration of the car.
Answer:
a = 4.125 [m/s^2]
Explanation:
In order to calculate the value of acceleration, we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.
ΣF = m*a
where:
ΣF = sum of forces [N]
m = mass [kg]
a = acceleration [m/s^2]
Performing a summation of forces on the x-axis, we have:
4000 - 700 = m*a
4000 - 700 = 800*a
a = 4.125 [m/s^2]
The hair shaft is made up of three layers: an __ medulla , a cortex, and an ___cuticle
- absent; colored
-Colored; absent
-inner; outer
-outer ; inner
29 HELP PLEASE!!! I'LL GIVE BEAINLIST!!!
Write a paragraph using eight words from the field of science. You can use the words listed.
words:
observation
hypothesis
theory
matter
agent
experimental group
control group
temperature
particle
criteria
Answer:
observation
hypothesis
theory
matter
agent
experimental group
control group
temperature
particle
criteria
Explanation:
A common flea is recorded to have jumped as high as 21 cm. Assuming that the jump is entirely in the vertical direction and that air resistance is insignificant, calculate the time it takes the flea to reach a height of 7.0 cm.
Answer:
t = 0.12 s
Explanation:
Applying the second equation of motion under free fall,
h = ut + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]
where: h is the height, u is its initial velocity, t is the time taken and g is the gravitational force.
But, u = 0 m/s, h = 21 cm (0.21 m) and g = 9.8 m/[tex]s^{2}[/tex]. Then:
0.21 = 0 + [tex]\frac{1}{2}[/tex] x 9.8 x [tex]t^{2}[/tex]
0.21 = 4.9[tex]t^{2}[/tex]
[tex]t^{2}[/tex] = [tex]\frac{0.21}{4.9}[/tex]
= 0.04286
⇒ t = 0.2070
= 0.21 s
The time taken for the flea to jump as high as 21 cm is 0.21 s.
The time taken for the flea to reach a height of 7.0 cm (0.07 m) can be determined as;
h = ut + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]
0.07 = 0 + [tex]\frac{1}{2}[/tex] x 9.8 x [tex]t^{2}[/tex]
0.07 = 4.9[tex]t^{2}[/tex]
[tex]t^{2}[/tex] = [tex]\frac{0.07}{4.9}[/tex]
= 0.01429
t = 0.1195
= 0.12 s
What is the acceleration of a mongoose that, if from rest, can reach
speeds of 19 ft/s in 8.8 seconds?
O 2.25 s
O 174.24 ft/s/s
2.25 ft/s/s
2.25 m/s
Explanation:
Acceleration is change in velocity over time.
a = Δv / Δt
a = (19 ft/s − 0 ft/s) / 8.8 s
a = 2.16 ft/s/s
Given parameters:
Initial velocity = 0m/s
Final velocity = 19ft/s
Time taken = 8.8s
Unknown:
Acceleration
Solution:
Acceleration is the change in velocity with time of a body;
Acceleration = [tex]\frac{v - u}{t}[/tex]
v is the final velocity
u is the initial velocity
t is the time taken
input the parameters and solve;
Acceleration = [tex]\frac{19 - 0}{8.8}[/tex] = 2.16ft/s
Now, the acceleration is 2.16ft/s
what is the acceleration of the Tesla Model S in m/s²?
Answer: Tesla’s Model S Performance is the fastest-accelerating production car. The luxury sedan reaches 60 mph in just 2.4 seconds, which outperforms every supercar available today.
Explanation:
A bar magnet is falling toward the center of a loop of wire, with the north pole oriented downwards. Viewed from the same side of the loop as the magnet, as the north pole approaches the loop, what is the direction of the induced current?.
The direction of the induced current is counterclockwise.
What is Lenz law?This states that induced electric current flows in a direction such that the current opposes the change that induced it.
The direction of the induced current is counterclockwise as a result of the north pole being oriented downwards which is the opposite direction of the hands of a clock movement.
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why a body in uniform velocity is zero acceleration ?
how does a changing magnetic field affect a piece of copper wire?
Answer: When you change the direction of the current, you also change the direction of the magnetic field. Because the magnetic field created by the electric current in the wire is changing directions around the wire, it will repel both poles of the magnet by bending away from the wire.
Explanation:
what is illuminance
Answer:
The amount of luminous flux per unit area
Explanation:
An advertisement for a new car states that its top speed is 180 km/h. If it could
travel at this speed for 3h, how far would it go?
4
Answer:
Distance = speed×time = 180×3 = 540 Km
Para levantar del suelo una caja metálica de 50 Kg se emplea maquinaria que utiliza un cable inextensible e imprime una aceleración de 0,8 m/seg2. ¿Qué tensión soporta el cable y qué tiempo le tomará a la máquina levantar la caja a una altura de 10 metros? Lo necesito urgente
Answer:
T = 530 N , t = 12.65 s
Explanation:
This is an exercise on Newton's second law,
T - W = m a
where T is the tension of the cable, W the weight and the steel of the box
T = W + ma
the weight of a body is
W = m g
Let's replace
T = m g + ma
T = m (g + a)
let's calculate
T = 50 (9.8 + 0.8)
T = 530 N
To calculate the time we use
y = v₀t + ½ a t²
since the box starts from rest on the sole its initial velocity is zero
y = ½ a t2
t = √ 2y / a
let's calculate
t = √ (2 10 / 0.8)
t = 12.65 s
TRASLATE
Este es un ejercicio de la segunda ley de Newton,
T – W = m a
donde T es la tension del cable, W el peso y a la aceracion de la caja
T = W + ma
el pesode un cuerpo es
W = m g
Substituyamos
T = m g + ma
T = m ( g +a)
calculemos
T = 50 ( 9,8 + 0,8)
T = 530 N
Para calcular el tiempo usamos
y = v₀t + ½ a t²
como la caja parte del reposo en el suela su velocidad inicial es cero
y= ½ a t²
t= √ 2y/a
calculemos
t = √ (2 10/0,8)
t = 12,65 s
28 points
An electric wall clock has a second hand 15 cm long. What is the radial acceleration of the tip of this hand?
A.4.25 x 10-4 m/s2
B.5.32 10-2 m/s2
C.1.64 x 10-3 m/s2
D.3.16 x 10-3 m/s2
A water-skier with weight Fg = mg moves to the right with acceleration a. A horizontal tension force T is exerted on the skier by the rope, and a horizontal drag forcc Fa is cxertcd by thc watcr on the ski. The water also exerts a vertical lift force L on the skier. Which of the following are correct relationships between the forces exerted on the skier-ski system? Select two answers. (A) T-Fd = ma (B) L-Fg=ma (C) L- =0 (D) T- Fd 0
Answer:
The correct relationships are T-fg=ma and L-fg=0.
(A) and (C) is correct option.
Explanation:
Given that,
Weight Fg = mg
Acceleration = a
Tension = T
Drag force = Fa
Vertical force = L
We need to find the correct relationships
Using balance equation
In horizontally,
The acceleration is a
[tex]T-Fd=ma[/tex]...(I)
In vertically,
No acceleration
[tex]w=L[/tex]
[tex]mg-L=0[/tex]
Put the value of mg
[tex]L-fg=0[/tex]....(II)
Hence, The correct relationships are T-fg=ma and L-fg=0.
(A) and (C) is correct option.
In the attached picture we can see the original question.
A water-skier with weight Fg = mg moves to the right with acceleration a. A horizontal tension force T is exerted on the skier by the rope, and a horizontal drag force Fd is exerted by the water on the ski. The water also exerts a vertical lift force L on the skier. The correct relationships are:
(A) [tex]T - F_d = ma[/tex]
(C) [tex]L - F_g = 0[/tex]
A water skier is moving to the right with acceleration a. If we analyze the forces in the horizontal direction, we can identify the tensión force (T), in the direction of the movement and the drag force (Fd), opposing to the movement. According to Newton's second law of motion, the resultant of these forces is equal to the product of the mass of the water skier and its acceleration.
[tex]T - F_d = ma[/tex]
In the vertical direction, we have the weight of the water skier (Fg) and the lift force (L) exerted on the skier by the water. The resultant of these 2 forces is zero, since there is no acceleration in the vertical direction.
[tex]L - F_g = 0[/tex]
A water-skier with weight Fg = mg moves to the right with acceleration a. A horizontal tension force T is exerted on the skier by the rope, and a horizontal drag force Fd is exerted by the water on the ski. The water also exerts a vertical lift force L on the skier. The correct relationships are:
(A) [tex]T - F_d = ma[/tex]
(C) [tex]L - F_g = 0[/tex]
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A 100V battery is connected to two oppositely charged plates that are 10cm apart. i. What is the magnitude of the electric field? ii. Calculate the Electric Force exerted on a +200 C point charge. iii. What is the electric potential energy of the charge when it's 8cm and 2cm from the negatively charged plate? iv. How much work was required to move the charge from 8cm to 2cm? v. If the 10gram point charge was at rest at point A, what is the final speed at point B?
Answer:
1.) 1000 N/c
2.) 200000 N
3.) 60v
4.) 120000J
5.) 4899 m/s
Explanation:
Given that a 100V battery is connected to two oppositely charged plates that are 10cm apart.
1.) The magnitude of electric field strength is the ratio of potential difference per distance between the plates. That is,
Electric field = V/d
Electric field = 100/0.1
Electric field = 1000 wb
2.) Electric field strength is also the ratio of force per unit ccharge. That is,
Electric field = F / q
1000 = F / 200
Cross multiply
F = 1000 × 200
F = 200000 N
3.) What is the electric potential energy of the charge when it's 8cm and 2cm from the negatively charged plate?
The distance = 8cm - 2cm = 6cm
Electric field = V / d
Substitute the electric field and the distance into the formula
1000 = V / 0.06
Make V the subject of formula
V = 1000 × 0.06
V = 60 V
4.) How much work was required to move the charge from 8cm to 2cm?
Work done = VQ
Since V = 60v
Then,
Work done = 60 × 200
Work done = 120000 J
5.) If the 10 gram point charge was at rest at point A, what is the final speed at point B?
Work done = 1/2mv^2
120000 = 1/2 × 0.01 × v^2
V^2 = 120000/ 0.005
V^2 = 24000000
V = 4899 m/s
The magnitude of electric field strength has been 1000 wb.
The electric force (F) applied by 200 C charge has been 2000,000 N.
The values for electric potential energy has been 60 V.
The work done in moving the charge across the plate has been 12 kJ.
The speed of charge at point B has been 48.98 m/s.
The magnitude of electric field strength has been defined as the force per unit charge.
The expression for magnitude of electric field strength (E) has been:[tex]E=\dfrac{V}{d}[/tex]
Where, the voltage of battery, [tex]V=100\;\rm V[/tex]
The distance between plates, [tex]d=10\;\rm cm\;;0.1\;m[/tex]
Substituting the values for magnitude of electric field strength (E):
[tex]E=\dfrac{100}{0.1} \\E=1000\;\rm wb[/tex]
The magnitude of electric field strength has been 1000 wb.
The expression of electric force (F) applied by the battery has been given as:[tex]F=E\;\times\;q[/tex]
Where, the magnitude of electric field strength, [tex]E=1000\;\rm wb[/tex]
The charge for the force has been, [tex]q=200\;\rm C[/tex]
Substituting the values for electric force (F):
[tex]F=1000\;\times\;200\\F=200000\;\rm N[/tex]
The electric force (F) applied by 200 C charge has been 2000,000 N.
The electric potential energy (E) for charge has been given as:[tex]E=\dfrac{V}{d}[/tex]
The magnitude of electric field strength, [tex]E=1000\;\rm wb[/tex]
The distance between plates, [tex]d=8\rm \;cm-6\;cm\\d=2\;cm\;;0.02\;m[/tex]
Substituting the values for electric potential energy, (V):
[tex]1000=\dfrac{V}{0.0.06} \\V=1000\;\times\;0.06\\V=60\;\rm V[/tex]
The values for electric potential energy has been 60 V.
The work done (W) to move a charge has been given by:[tex]W=Vq[/tex]
Where, the electric potential energy of the battery has been, [tex]V=60\;\rm V[/tex]
The charge for the force has been, [tex]q=200\;\rm C[/tex]
Substituting the values for work done, (W):
[tex]W=60\;\times\;200\\W=12,000\;\text J\\W=12\;\rm kJ[/tex]
The work done in moving the charge across the plate has been 12 kJ.
The speed (v) of 10 g charge has been given as:[tex]W=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2W}{m} }[/tex]
Where, the work done on unit charge, [tex]W=12,000\;\rm J[/tex]
The mass of the charge, [tex]m=10\;g[/tex]
Substituting the values for calculating the speed of charge, (v):
[tex]v=\sqrt{\dfrac{2\;\times\;12,000}{10} } \\v=\sqrt{24,000}\\v=48.98\;\rm m/s[/tex]
The speed of charge at point B has been 48.98 m/s.
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The average speed of a runner in an 800 meter race was 7.0 meters per second.How long did it take the runner to complete the race?
Answer:
114.29s
Explanation:
average speed = distance/Time
Given
speed = 7m/s
distance = 800m
Required
Time taken by the runner to complete the race
From the formula:
Time = Distance/speed
Time = 800/7
Time = 114.29seconds
Hence it took the runner 114.29s to complete the race
Idris has a mass of 65 kg. He is standing on the second floor of his apartment building, 5 meters above the ground. What is his gravitational potential energy (GPE)? O A. 325J O B. 31,213 J O C. 3,185 J O D. 79.8J
Answer:A.325J
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A car is moving at 18km/hr when it accelerates at 4m/² for 2 seconds. What is the car's new velocity?
Answer:
44
Explanation:
v=u+a(t)
v=18+4(2)
v=22(2)
v=44 (where v=final velocity,u=initial velocity,a=acceleration,and t=time)
A car of mass 1500kg is brought to rest from a velocity of 25m/s by a constant force of 3,000N. Determine the change in momentum produced by the force and the time it takes for the car to come to rest.
answer:
change in momentum = 37,500kg.m/s in the opposite direction
time it takes = 12.5s
working:
u=25m/s
v=0m/s
F=ma
-3000=(1500)(a)
-3000÷1500=a
a= -2m/s^2
Change in momentum=mv-mu
(1500)(0)-(1500)(25)
= -37,500kg.m/s
relax the( - ) represents direction
v=u-at
0=25-2t
2t=25
t= 12.5s
Which zone shows the water table?
o 1
o 2
o 3
o 4
Answer:
3
Explanation:
i took the quiz
3. Similar cells work together in a_
which is part of an_
which is part_
A portable hairdryer, plugged into a 110 V outlet, has a current of 10 A flowing through it. What is its power rating