Answer:
e. C₃H₈(g)
Explanation:
Standard entropy is the absolute entropy of a substance at 1 atm and 25°C.
For different substances in the same phase, molecular complexity determines which ones have higher entropies.
Consider the gases CH₄, C₂H₂, C₂H₄, C₂H₆, C₃H₈. Propane (C₃H₈) has a more complex structure and hence more ways to execute molecular motions, which also increase its microstates. Therefore, propane has the greatest standard entropy.
The standard entropy of propane has been highest among the given molecules. Thus, option E is correct.
The standard entropy has been the energy possessed by the 1 mole of a pure substance at standard pressure and temperature.
The entropy has been proportional to the molecular weight and structure complexity. The molecule with higher molecular weight and structure complexity tends to have higher entropy.
In the given set of molecules, the molecular mass and structure complexity of propane has been the highest. Thus, the standard entropy of propane has been highest among the given molecules. Option E is correct.
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A student weighed 0.550 g of lithium chloride, LiCl, to use in a reaction. How many moles is this? a. 5.11 b. 42.39 c. 23.31 d. 77.08 e. 0.0130
Answer:
The answer is option eExplanation:
To find the number of moles we must first find the molar mass of LiCL
From the question
mass = 0.550g
M(Li) = 6 Cl = 35.5
Molar mass of LiCL = 6 + 35.5 = 41.5 g/mol
Then we use the formula
[tex]n = \frac{m}{M} [/tex]
where
n is the number of miles
m is the mass
M is the molar mass
So we have
[tex]n = \frac{0.550}{41.5} [/tex]
We have the final answer as
0.0130 molHope this helps you
Which of the following can't undergo aldol condensation.
(CH3)3CCHO
CH3CH2CHO
PhCOCH3
CH3COCH3
Answer:
(CH3)3CCHO
Explanation:
Carbonyl compounds that contain alpha hydrogen atoms are the only ones that can undergo aldol condensation reaction.
Aldol condensation is one of the condensation reactions in organic chemistry that occurs when an enol or an enolate ion reacts with another carbonyl compound to yield a β-hydroxyaldehyde or β-hydroxyketone, this is immediately followed by the dehydration of the product to yield a conjugated enone.
(CH3)3CCHO lacks alpha hydrogen atoms hence it does not undergo the aldol condensation.
2. (2 points) Calculate the Effective Nuclear Charge for each atom. Show all of your work for full credit. Se: Br: (1 point) Which atom is larger? (This is your claim.)
The question is incomplete. Here is the complete question.
Consider the selenium atom, Se, and the bromine atom, Br.
Write out the full electron configuration fro each atom.
Se:
Br:
Calculate the Effective Nuclear Charge for each atom. Show all of your work for full credit.
Se:
Br:
Which atom is larger?
Answer and Explanation: Electron Configuration of an atom demonstrates the shape and energy of its electrons. One of the rules used for it is given by using Madelung's Rule, in which the order of increased energy of the electrons is:
1s < 2s < 2p < 3s < 3p < 4s < 4p < 5s < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7p
Atom of Selenium (Se) has 34 electrons. Its electron configuration is
Se: [tex]1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{4}[/tex]
Atom of Bromine has 35 electrons. Its electron configuration is
Br: [tex]1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{5}[/tex]
Effective Nuclear Charge ([tex]Z_{eff}[/tex])is the net positive charge experienced by an electron in a multi-electron atom. In other words, it is the net force that helds nucleus and electrons together.
It is calculated by: [tex]Z_{eff}=Z-S[/tex]
where
Z is the atomic number, i.e., number of protons of the atom
S is the nonvalence electrons, i.e., the number of electrons between the nucleus and the electron in question.
For Selenium (Se):
From the electron configuration, the valence shell is 4 with 6 valence electrons. Nonvalence electrons is the difference between valence and total electrons:
S = 34 - 6 = 28
[tex]Z_{eff}=34-28[/tex] = 6
The Effective Nuclear Charge of Se is 6
For Bromine (Br):
The valence shell, according to the configuration, is 4 and valence electrons are 7.
S = 35 - 7 = 28
[tex]Z_{eff}=35-28[/tex] = 7
The Effective Nuclear Charge fo Br is 7.
Bromine is larger than Selenium because it has bigger Effective Nuclear Charge, which means it held its electrons more loosely and, consequently, has a larger atomic radius.
There is an electrolytic cell in which Mn2+ is reduced to Mn and Sn is oxidized to Sn2+.
A. Write an equation for the half-reaction occurring at each electrode. Express your answers as chemical equations separated by a comma. Identify all of the phases in your answer.
B. What minimum voltage is necessary to drive the reaction? Vmin =
Answer:
See explanation
Explanation:
Anode;
Sn(s) ------> Sn^2+(aq) + 2e
Cathode;
Mn^2+(aq) + 2e ------> Mn(s)
The minimum voltage required to drive the reaction is the cell voltage. The cell voltage is obtained from;
E°cell= E°cathode - E°anode
E°cell= -1.19 - (-0.14)
E°cell= -1.05 V
2 points
How many significant figures are there in the measurement 2.30 x 10^5
mm ? *
2
3
4.
5
Answer:
3.
Explanation:
Hello,
In this case, considering the given number:
[tex]2.30x10^5[/tex]
We can see that it does not have zeros to left of the first nonzero digit which is 2, therefore, we just have to consider the 2, 3 and 0 as significant figures because the right-handed zeros are actually considered. Hence, such measurement has 3 significant figures.
Give an example of an element and an example of a compound.
Answer:
an element is a atom like titanium and a compound is like a water, glucose, alcohol and salt
Explanation:
the titanium is a element and water, glucose, alcohol, and salt those are a compound
what is 31/50000 If the toxic quantity is 1.5 g of ethylene glycol per 1000 g of body mass, what percentage of ethylene glycol is fatal
Answer:
[tex]\%m=0.15\%[/tex]
Explanation:
Hello,
In this case, we are asked to compute the by mass percent representing the toxicity of ethylene glycol in the body mass. In such a way, since the by mass percent is computed with the shown below formula:
[tex]\%m=\frac{m_{ethylene \ glycol}}{m_{ethylene \ glycol}+m_{body\ mass}}*100\%[/tex]
We can use the given masses to obtain:
[tex]\%m=\frac{1.5g}{1.5g+1000g}*100\%\\ \\\%m=0.15\%[/tex]
Best regards.
A mountaineer shouts for help Half a second later (0.5 she hears the echo How far away is the rock face which is reflecting her voice (take the speed of sound to be 330 m/s
Answer:
82.5 metres
Explanation:
speed=330m|s
initial time taken =0.5÷2=0.25
distance=speed×time
330m|s × 0.25s = 82.5m
1-hexanol was prepared by reacting an alkene with either hydroboration-oxidation or oxymercuration-reduction. Draw the structure of the alkene that was used to prepare the alcohol in highest yield.
Answer:
hex-1-ene with a hydroboration-oxidation reaction
Explanation:
In this case, we can start with the structure of 1-hexanol. In this alcohol, the "OH" is on the first carbon. Thus, the alkene that this alcohol can produce must have a double bond between carbons 1 and 2, that is, hex-1-ene.
Now, it is important to know which of the reactions we can use, hydroboration-oxidation, or oxymercuration-reduction. To decide which reaction to using, we must look again at the alcohol we want to produce. In this alcohol, the "OH" is attached to a primary carbon. Therefore, the addition of the "OH" must be made on the least substituted carbon, that is, carbon number 1.
Because of this, an anti-Markovnikov reaction (a reaction in which the "OH" is added on the less substituted carbon) must be used. The reaction, which serves us then is: hydroboration-oxidation since this reaction is anti-markovnikov.
See figure 1
I hope it helps!
5. Which of the following statements about the modern
Quantum model of the atom is TRUE?
a. Electron clouds are formed by electron movement.
b. Only protons form the nucleus.
c. Protons and electrons form the nucleus.
d. Neutrons in the nucleus have a positive charge.
The mixing of which pair of reactants will result in a precipitation reaction?
A. AsI(aq) + NaOH(aq)
B. NaNO3(aq) + NH4Cl(aq)
C. K2SO4(aq) + Ba (NO3)2(aq)
D. HCl(aq) + Ca(OH)2(aq)
E. None of the above.
Answer:
B
Explanation:
Two elements, R and Q, combine to form two binary compounds. In the first compound, 14.0 g of R combines with 3.00 g of Q. In the second compound, 7.00 g of R combines with 4.50 g of Q. If the formula of the second compound is RQ3, what is the formula of the first compound?
Answer:
The formula of the first compound is RQ
Explanation:
Chemical formula is the simplest whole number ratio of moles of each element in the compound.
To determine the formula of a compound we must know the molar mass of each element (How many grams weighs a mole of the compound).
The formula of the second compound is RQ₃. That is 1 mole of R and 3 moles of Q.
1 mole of R weighs 7.00g. That means its molar mass is 7g/mol.
3 moles of Q weighs 4.50g. Its molar mass is 4.50g / 3 moles: 1.50g/mol
In the first compound, there are 14.0g = 2 moles of R
And 3.00g of Q = 2 moles of Q.
And you can think formula is:
R₂Q₂
But, as formula is the simplest whole number ratio,
The formula of the first compound is RQDraw the product of the reaction between CH3CH=CHCH3 and H2 under a platinum catalyst.
Answer:
CH₃CH₂-CH₂CH₃
Explanation:
When an alkene, R-CH=CH-R reacts with H₂ in a Pt catalyst, the analogue alkane, R-CH₂-CH₂-R, is produced (Hydrogenation of alkenes via Pt/Pd catalyst)
Thus, the reaction of CH₃CH=CHCH₃ with H₂ under a platinum catalyst produce:
CH₃CH₂-CH₂CH₃The analogue alkane
The addition of hydrogen to CH3CH=CHCH3 leads to the formation of CH3CH2CH2CH3.
An alkene is a hydrocarbon that contains a C=C double bond. An alkene undergoes addition reaction in which a molecule is added across the double bond to form a saturated hydrocarbon.
The addition of H2 to CH3CH=CHCH3 yields butane as shown in the image attached. The platinum metal serves a catalyst in the reaction.
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A coefficient is a constant by which a variable is multiplied. In chemistry, a coefficient is the number in front of a formula. (The 2 in 2CH4 is the coefficient.) The coefficients in a chemical equation represent the proportion of A) products to reactants. B) the amount of atoms in a solid phase to the amount in a liquid phase. C) mass to volume. D) molecules or atoms relative to other molecules or atoms.
Answer:
Below
Explanation:
The coefficients in a chemical reaction are called stochiometric coefficients
they represent the number of atoms or molecules they are multiplied to.
A chemical reaction has generally this form:
Reactants ⇒ productsAnswer:
Products to reactants
What is the speed 0.36
km/h in cm/s
Answer:
It's 10 cenimeters per second
Magnesium is a group 2 metal which exists as a number of isotopes and forms many compounds.
Magnesium ions produce no emission of absorption lines in the visible region of the electromagnetic spectrum. Suggest why most magnesium compounds tested in a school laboratory show traces of yellow in the flame
Answer:
Traces of sodium impurity
Explanation:
Metal ions are identified by a characteristic colour imparted to flame by the metal ion solution. Various metals have various colours which they impart to a flame.
The energy of a flame is not sufficient for the excitation of electrons of Mg to a higher energy level. As a result of this, Mg do not give any color in Bunsen flame.
However, a few tinges of yellow-orange colour which is characteristic of sodium metal do appear when magnesium ions are exposed to a flame as a consequence of traces of sodium impurity in the magnesium ion solution.
Explain why serine proteases do not catalyze hydrolysis if the amino acid at the hydrolysis site is a D-amino acid. Trypsin, for example, cleaves on the C-side of L-Arg and L-Lys, but not on the C-side of D-Arg and D-Lys. Explain why serine proteases do not catalyze hydrolysis if the amino acid at the hydrolysis site is a D-amino acid. Trypsin, for example, cleaves on the -side of L- and L-, but not on the -side of D- and D-. All the naturally occurring amino acids are D-amino acids, while active centres of serine proteases are nearly all L. All the naturally occurring amino acids are L-amino acids, while active centres of serine proteases are nearly all D. The side chains of D-Arg and D-Lys are not positioned to bind correctly at the active site. None of the above.
Answer:
D. The side chains of D-Arg and D-Lys are not positioned to bind correctly at the active site
Explanation:
Stereospecificity is the ability to distinguish between stereoisomers of of a particular compound. L- and D- structures of compounds in living organisms are usually present in only one form due to stereospecificity. For example, naturally occuring amino acids in proteins are usually present as L-isomers.
Since enzyme are proteins, their active sites are composed of L-amino acid and they show stereospecificity in the reactions they catalyze. In their binding sites, only substrates complementary in structure can bind in order for catalysis to proceed. Therefore, only amino acids in the L- configuration are complementary to the active site of enzymes.
In the case of serine proteases, The side chains of -Arg and D-Lys will not be positioned properly for binding at the binding site of serine proteases, therefore, no catalysis will occur. On the other hand, L-Arg and L-Lys can bind to the catalytic site of serine proteases since they are complementary fits to the active site of the enzymes.
Which type(s) of matter would need to be separated by chemical methods?
Answer:
solids, liquids, gases, or plasma
Explanation:
In chemistry, a chemical substance is a form of matter that has constant chemical composition and characteristic properties. It cannot be separated into components without breaking chemical bonds. Chemical substances can be solids, liquids, gases, or plasma
Calculate the molality of a 15.0% by mass solution of MgCl 2 in H 2O. The density of this solution is 1.127 g/mL. Group of answer choices
Answer:
1.86 m
Explanation:
Step 1: Calculate the mass of solute and solvent in 100 grams of solution
We have a 15.0% by mass solution of MgCl₂ (solute) in H₂O (water). In 100 g of solution, there are 15.0 g of solute and 100.0 g - 15.0 g = 85.0 g of solvent.
Step 2: Calculate the moles corresponding to 15.0 g of MgCl₂
The molar mass of MgCl₂ is 95.21 g/mol.
[tex]15.0g \times \frac{1mol}{95.21 g} = 0.158mol[/tex]
Step 3: Convert the mass of water to kilograms
We will use the relationship 1 kg = 1,000 g.
[tex]85.0g \times \frac{1kg}{1,000g} = 0.0850kg[/tex]
Step 4: Calculate the molality of the solution
[tex]m = \frac{0.158mol}{0.0850kg} = 1.86m[/tex]
The molality is 1.86 m.
Given:
Mass solution of MgCl₂ in H₂O= 15%
Density= 1.127g/mL
To find:
Molality=?
Let's solve this question step by step:
Step 1: Calculate the mass of solute and solvent in 100 grams of solution
As it is given that 15.0% by mass solution of MgCl₂ (solute) in H₂O (water).
In 100 g of solution, there are 15.0 g of solute and 100.0 g - 15.0 g = 85.0 g of solvent.
Step 2: Calculate the moles corresponding to 15.0 g of MgCl₂
The molar mass of MgCl₂ is 95.21 g/mol.
Number of moles is given mass divided by the molar mass.
[tex]\text{Number of moles}= \frac{15g}{95.21g/mol} =0.158mol[/tex]
Step 3: Convert the mass of water to kilograms.
As we know, 1 kg = 1,000 g.
[tex]=\frac{85}{1000} =0.085kg[/tex]
Step 4: Calculate the molality of the solution.
Molality is a measure of the number of moles of solute in a solution corresponding to 1 kg or 1000 g of solvent.
[tex]\text{Molality}=\frac{0.158\text{mol}}{0.085\tetx{kg}} =1.86 m[/tex]
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If this is a p1000 micropipette, then this is set to dispense [ Select]ul. If this is a p10
micropipette, then this is set to dispense [ Select ]ul.
Answer:
1000 µL; 10 µL
Explanation:
A p1000 micropipet is set to dispense 1000 µL.
A p10 micropipet set to dispense 10 µL.
Explain the differences between mass and weight among energy, heat, and enthalpy.
Answer:
If you are thinking of the thermodynamic definitions Internal energy change is defined as the heat gained by a system less the work done by the system
E = Q-W. This combination is a state function meaning it depends on the initial and final states of a system and is path independent while work and heat change are path dependent.
Enthalpy change is defined as H = E+ PV A change in Enthalpy is also a state function. The most useful factor of enthalpy is that at constant pressure The heat of reaction Q is a measure of enthalpy and is also a state function.
hope this helps !!
Iron(II) chloride is added to sodium carbonate. The reaction is described by the balanced equation below. (7 points) FeCl2(aq) + Na2CO3(aq) FeCO3(s) + 2NaCl(aq) i. Write the complete ionic equation from the balanced equation. (3 points) ii. What are the spectator ions in the reaction? (1 point) iii. Write the net ionic equation from the complete ionic equation. (2 points)
Answer:
Explanation:
FeCl₂(aq) + Na₂CO₃(aq) ⇒ FeCO₃(s) + 2NaCl(aq)
complete ionic equation
Fe⁺²(aq) + 2 Cl⁻(aq) + 2 Na⁺(aq) + CO₃⁻² (aq) ⇒ FeCO₃(s)+ 2 Na⁺(aq) +2Cl⁻(aq)
Spectator ions = Cl⁻(aq) , Na⁺(aq)
Net ionic equation
Fe⁺²(aq) + CO₃⁻² (aq) ⇒ FeCO₃(s).
The Complete ionic equation:
Fe²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + CO₃²⁻(aq) → FeCO₃(s) + 2Na⁺(aq) + 2Cl⁻(aq)
ii. Spectator ions: Na⁺(aq) and Cl⁻(aq)
iii. Net ionic equation:
Fe²⁺(aq) + CO₃²⁻(aq) → FeCO₃(s)
An ionic equation is a chemical equation that shows the dissociation of all soluble ionic compounds into their respective ions in a solution. It represents the species present in their ionic form rather than as complete compounds.
In an ionic equation, only the ions involved in the chemical reaction are shown, while the spectator ions, which do not participate in the reaction, are omitted. This type of equation provides a more focused representation of the chemical reaction occurring between the ions.
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The complete combustion of copper(I) sulphide is according to the following equation:
2Cu2S(s) + 302(g) →→2Cu2O(s) + 2SO2(g)
If the mass of Cu2S in the mixture is 14.0 g, calculate
(a) the number of molecules of oxygen gas reacted.
(b) the mass of SO2 gas produced.
(c)the volume of SO2 gas at STP
Answer:
a) 7.94 x 10²³ molecules, b) 5.62 g SO2, c) 1.97 L
Explanation:
a) We need to first convert Cu2S to moles. Since molar mass of Cu2S is 159.14 g/mol, 14.0 g = 0.0880 mol. Using molar ratios (3 mol O2/2 mol Cu2S, 0.0880 mol of Cu2S = 0.132 mol O2. Since 1 mol contains 6.02 x 10²³ molecules, 0.132 mol O2 = 7.94 x 10²² molecules O2.
b) Since the molar ratios of Cu2S to SO2 is 1:1, 0.0880 mol of Cu2S produces 0.0880 mol SO2. To convert mol to grams, we use the molar mass of SO2 (64.06 g/mol) to figure out that 0.0880 mol SO2 = 5.63 g SO2.
c) At STP, 1 mol occupies 22.4 liters. 0.0880 mol SO2 x 22.4 L/1 mol = 1.97 L
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What theory offers a description of submicroscopic properties of matter and connects them to observable macroscopic properties?
Answer:
Kinetic Molecular theory of matter
Explanation:
Answer:
The kinetic molecular theory of matter offers a description of the microscopic properties of atoms (or molecules) and their interactions, leading to observable macroscopic properties (such as pressure, volume, temperature).
Explanation:
You observe an exothermic gaseous reaction that is not spontaneous in forward direction at 1 atm and 298K. Which of the following statements about this reaction is true? a. This reaction will become spontaneous in forward direction at some temperature below 298K. b. This reaction will be spontaneous in forward direction at a higher pressure at 298K. c. This reaction will become spontaneous in forward direction at some temperature above 298K. d. This reaction is never spontaneous. e. The reverse reaction is always spontaneous.
Answer: option (a) is the correct answer
Explanation:
The complete questions says;
You observe an exothermic gaseous reaction that is not spontaneous in forward direction at 1 atm and 298K. Which of the following statements about this reaction is true? a. This reaction will become spontaneous in forward direction at some temperature below 298K. b. This reaction will be spontaneous in forward direction at a higher pressure at 298K. c. This reaction will become spontaneous in forward direction at some temperature above 298K. d. This reaction is never spontaneous. e. The reverse reaction is always spontaneous.
The Answer:
(a). This reaction will become spontaneous in forward direction at some temperature below 298K
Explanation: First of all, we can acknowledge that the reaction seen here is an exothermic one, i.e energy is released in the process outwardly and as a result temperature is reduced during this process of energy loss.
Having understood that scenario, say we reduce it's temperature by ourself than forward reaction favors and after reaching at particular temperature, therefore we can confirm this to be a spontaneous reaction.
Let us use this to confirm what we have been saying.
Given;
ΔG = ΔH - TΔS
here ΔH is negative
it is non spontaneous, which means ΔG is positive so we continuously decraeses it's temperature than at a particular temperature.
The Entropy change becomes positive and reaction becomes spontaneous and ΔG become negative.
cheers i hope this helped !!
Caprylic acid, CH₃-(CH₂)₄-CH₂-CH₂-COOH, is a fatty acid.
a. Draw the condensed structural formula for the activated form of caprylic acid
b. Indicate the α- & β-carbon atoms in caprylic acid.
c. State the number of β-oxidation cycles for the complete oxidation of caprylic acid.
d. State the number of acetyl-CoAs from the complete oxidation of caprylic acid.
Answer:
a. See figure 1
b. See figure 2
c. Three cycles
d. Four Acetyl-CoAs
Explanation:
a. Draw the condensed structural formula for the activated form of caprylic acid
For the activation of the fatty acid, an ATP molecule is needed to bind AMP in the acid group and then an Acetyl-CoA molecule to generate the activated fatty acid. (See figure 1)
b. Indicate the α- & β-carbon atoms in caprylic acid
By definition, the alpha and beta carbons are the carbons that are in positions 2 and 3 respectively to the main carbon. In this case, the main carbon is the carbon from the acid group, therefore the alpha carbon will be carbon 2 (red arrow) and the beta carbon will be carbon 3 (blue arrow). (See figure 2).
c. State the number of β-oxidation cycles for the complete oxidation of caprylic acid.
To calculate the cycles we have to use the equation:
[tex]Number~of~cycles:\frac{n}{2}-1[/tex], where n is the amount of carbons, in this case, we have 8 carbons, so:
[tex]Number~of~cycles:\frac{8}{2}-1=3[/tex]
We will have 3 cycles. (See figure 3)
d. State the number of acetyl-CoAs from the complete oxidation of caprylic acid
In the β-oxidation metabolic cycle, we have a relationship between Acetyl-CoA produced and the number of carbons:
[tex]Number~of~Acetyl~Coas:\frac{n}{2}[/tex] if n=8 we will have:
[tex]Number~of~Acetyl~Coas:\frac{8}{2}=4~Acetyl~Coas[/tex]
We will have 4 Acetyl-CoAs.
I hope it helps!
9.57: How many kilojoules of heat will be released when exactly 1 mole of manganese, Mn, is burned to form Mn3O4(s) at standard state conditions?
Answer:
459.6kj
Explanation:
the chemical equation =
3mn(s) + 2CO2(g) --- Mn3O4(s)
we have change in H to be -1378.83
we are required to find the amount of heat that is liberated for a mole of manganese.
3 moles of manganese = -1378.83
1 mole of manganese = ?
when we cross multiply, we will have a ratio that we will use to find this amount
1378.83/3 = 459.6kj
If the toxic quantity is 1.5 gg of ethylene glycol per 1000 gg of body mass, what percentage of ethylene glycol is fatal
Answer:
The percentage of ethylene glycol that is fatal is 0.15 %
Explanation:
If the toxic quantity of ethylene glycol in a 1kg or 1000 g body weight is 1.5 g then the percentage of ethylene glycol that is fatal is
[tex]\frac{1.5}{1000}[/tex] ˣ 100 = 0.15%
Hence, the percentage of ethylene glycol that is toxic for any body weight is 0.15%. This percentage is very important in various aspects of science including drug discovery and food production/processing
PRACTICE PROBLEMS
c
SOLVE Use the density formula to solve the following problems.
A sample of a substance has a volume of 60.5 mL and a density of
1.20 g/mL. What is the mass of the sample?
09
Based on the lesson how are individuals and economics similar
Answer:
HI!!
Explanation:
The correct answer is A) they both must decide how to allocate resources. Based on the lesson, individuals and economies are similar because both must decide how to allocate resources.
Answer:
A - They both must decide how to allocate resources
Explanation:
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