Which of these processes removes carbondioxide from the air?

Answer:

_c+_so2-_cs2+_co= Toxic

Answer:

am sorry what exactly is your question?

actual yield of ethanol = 305.0g

molar mass of sucrose = 342g

molar mass of ethanol  =46g

mass of sucrose = 665g

mole of sucrose = mass / molar mass = 665/342

mole of sucrose =1.9 mole

sucrose :  C2H5OH

       1      :  4

     1.9     : 1.9x4 =7.6 mole of C2H5OH are formed

mass (therotical yield ) of C2H5OH= mole x mass

mass (therotical yield ) of C2H5OH= 7.6 x 46 = 349.6g

percent yields of ethanol =  actual /therotical x100

=305/349.6x100 = 87.24 %

Explanation:

a. Write a balanced equation

The balanced equation for the reaction is given as;

Zn + AgNO3 → Ag + ZnNO3  

b. Interpret the equation by  particles and by moles

In this equation, 1mol of Zn reacts with 1 mol of AgNO3 to from 1 mol of Ag and 1 mol of ZnNO3

1 mol = 6.022 * 10^23 particles

c. What is the limiting reactant?

The mol ratio between both reactants is 1 : 1 from the equation.

Converting the masses given to ml;

Number of mol = Mass / Molar mass

Zn;

Number of mol = 6.70 / 65.38 = 0.1025 mol

AgNO3;

Number of mol = 27.5 / 169.87 = 0.1619 mol

The limiting reactant in this reaction is Zn. This is because Zn would get used up before AgNO3 according to the number of moles calculated.

d. What is the theoretical mass of silver that will be produced?

1 mol of Zn produces 1 mol of Ag

0.1025 mol of Zn would also produce 0.1025 mol mol of Ag

Mass = Molar mass * Number of Moles = 107.87  * 0.1025

Mass = 11.05 g

e. If the actual yield of silver was 14.1 g, what is the percent yield of the

reaction?

Percent yield = Actual Yield / Theoretical yield * 100%

Percent yield = 11.05 / 14.1  * 100 = 78.36%

Answer:

See explanation

Explanation:

The synthesis of asprin involves the;

i) Hydrolysis of Methyl salicylate

ii) Reaction of salicylic acid with acid anhydride

The chemical name of asprin is acetylsalicylic acid.

It is preferable to use an acid anhydride for ester formation with an alcohol rather than a carboxylic acid because we will not produce water which can then cause the hydrolysis of the newly formed ester.

Answer:

it's a double displacement Reaction.

Make sure the area is higher than the solvent because if it isn't, the solvent will just wash it into the solution.

Chromatography is defined as a technique for separation in which the analyte is mixed with a liquid or gaseous mobile phase and pushed through a stationary phase. Chromatography is a crucial biophysical method that makes it possible to separate, distinguish, and purify mixture's constituent parts for qualitative and quantitative study.

The sample may be lifted with more force thanks to the solvent, which also causes the sample to dissolve. Because of this, the start line in chromatography should always be above the solvent. To avoid getting an angled solvent front, it is crucial to ensure that the solvent is level and not at an angle.

Thus, make sure the area is higher than the solvent because if it isn't, the solvent will just wash it into the solution.

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Answer:

I did this TGA got it right it is bottom left corner

Explanation:

Answer:

46 g

Explanation:

First we convert 1.2 x 10²⁴ atoms of sodium into moles, using Avogadro's number:

Then we convert 2.0 moles of sodium into grams, using sodium's molar mass:

Thus, there are 46 grams in 1.2x10²⁴ atoms of sodium.

Answer: Thus 81 grams of Au is 9210 ml

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

[tex]\text{moles of Au}=\frac{81g}{196.96g/mol}=0.411moles[/tex]

1 mole of Au occupies = 22.4 L

Thus 0.411 moles of Au occupy = [tex]\frac{22.4}{1}\times 0.411=9.21L=9210ml[/tex]

81 grams of Au is 9210 ml

Answer: first you have to calculate the amount ionized. We will say it is x mol / L

then % ionization = (amount ionized / initial concentration) * 100%

x can be calculated using an ice chart

HC3H5O2           -----> H+    + C3H5O2-

Initial HC3H5O2 = 0.250  

change              = -x

equilibrium         = 0.250 - x

initial H+            = 0

change              = +x

equilibrium         = x

C3H5O2- initial   = 0

change              = +x

equilibrium         = x

Ka         = [H=][C3H5O2-] / HC3H5O2]

 1.3 * 10 ^ -5    = [x][x] / (0.250 - x)  

So 1.3 * 10 ^ -5 * (0.250 - x)   = x ^ 2  

     3.25 * 10^ -6 - (1.3 * 10^-5)x = x^2   now this is a quadratic equation and you have to rearrange it and solve for x

x^2 + 1.3 * 10^-5)x - 3.25 * 10^ -6 = 0

use the equation x = {-b (+ or -)[b^2 - 4.a.c] ^ 1/2} / 2a

you should get x = 1.80 * 10 ^ -3 or x = -1.80* 10^-3

but x can not be negative..

so x = 1.80 * 10 ^ -3

so percent ionization = (1.80 * 10 ^ -3 / 0.250) * 100%

                               =0.72 %

the other way which is more easier is  

assuming that x is very small and therefore 0.250 - x is approximately equals to 0.250  

then 1.3 * 10^-5 = x^2 / 0.250

so x^2    = 1.3 * 10^-5 * 0.250

        x   = 1.80 * 10 ^-3

then percent ionization is = (1.80 * 10 ^ -3 / 0.250) * 100%

                               =0.72 %

if the percent ionization is > 5 % you can not do that approximation. in such a case you have to solve the quadratic equation. that is why I showed both methods.

now you can do the parts b and c

b answer : percent ionization = 1.27 %  

c answer : 2.54%

good luck

Answer:

Solid

Explanation:

Molecules in solids only vibrate in place, while the other two have moving molecules

Explanation:

heyyyyyyyyy how are you sure

Answer:

pH= 1.70

Explanation:

I      4.988        0     0

C     -x             +x     +x

E     4.988 -x    x       x

8.0 x 10^-5 = X^2/ 4.988 - x

(since the X value is so small, round 4.988-x to 4.988 because X is close to zero)

8.0 x 10^-5 = x^2/4.988

x4.988           x4.988

4.0 x 10^-4 = x^2

x = .0199

pH=-log[.0199] = 1.70

Answer:

Hydroxide ions ( OH−) are negatively charged, and the formal negative charge is on the oxygen atom. Since opposite charges attract, the oxygen atoms will interact with the positive end of water's dipole.

Explanation:

Answer:b

Explanation:

Answer:

C.

Explanation:

I took the quiz and made a 100

Answer:

The forest products industry plays a major role in the Swedish economy, and accounts for between nine and 12 percent of Swedish industry's total employment, exports, sales and added value. It includes companies within the pulp and paper industry, as well as the wood-mechanical industry.

Answer:

here

Explanation:

Answer: 4

A molecule of carbon tetrafluoride, CF4 , is made up of 1 carbon atom bonded to 4 fluorine atoms. Each carbon atom weighs 12.0 amu and each fluorine atom weighs 19.0 amu so 1 CF4 molecule weighs 1×12.0 amu + 4×19.0 amu = 88.0 amu. This number, 88.0, is called the molecular weight (or molecular mass) of CF4.

Answer:

Hello ur answer is

Pyrosulphuric acid formula

Explanation:

thanks

Answer:

Hello There!!

Explanation:

The answer is=>Pyrosulphuric acid formula.

hope this helps,have a great day!!

~Pinky~

Answer:

Explanation:

+1

The overall charge on the residue ( lysine residue ) is ; ( C )  0 charge

The a-aminium group of lysine amino acid will begin deprotonating by the presence of NaOH as the pH level of the solution increases.

Given that the pKa level of a-aminium group = 9. when the pH of  the solution is buffered to 9.0 . half of the a-aminium ions that is present in the lysine amino acid will deprotonate leaving the overall charge on the lysine residue at neutral ( 0 charge ).

Hence we can conclude that the overall charge on the residue is a 0 charge.

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Answer: 5

Explanation:

I hope this helped!

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Answer: 2.00 mol

Explanation:

The balanced chemical equation is:

[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]  

According to stoichiometry :

2.00 moles of [tex]H_2[/tex] require = 1.00 moles of [tex]O_2[/tex]

Thus 2.00 moles of [tex]H_2[/tex] will require=[tex]\frac{1}{2}\times 2.00=1.00moles[/tex]  of [tex]O_2[/tex]

Thus both will act as limiting reagents and will be fully consumed.

2.00 moles of [tex]H_2[/tex] will form = 2 moles of [tex]H_2O[/tex]

Thus 2.00 moles of [tex]H_2[/tex] will form = [tex]\frac{2}{2}\times 2.00=2.00moles[/tex]  of [tex]H_2O[/tex]

  Thus 2.00 moles of [tex]H_2O[/tex] will be produced from the given masses of both reactants.

Answer:

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Explanation:

The Boyle's Law is represented by the following expression:

[tex]P\cdot V = k[/tex] (1)

Where:

[tex]P[/tex] - Pressure, in kilopascals.

[tex]V[/tex] - Volume, in cubic centimeters.

[tex]k[/tex] - Proportionality constant, in kilopascal-cubic centimeters.

By definitions of rate of change and implicit differentiation, we derive the following differential equation:

[tex]\dot P \cdot V + P\cdot \dot V = 0[/tex] (2)

Where:

[tex]\dot P[/tex] - Rate of change of the pressure, in kilopascals per minute.

[tex]\dot V[/tex] - Rate of change of the volume, in cubic centimeters per minute.

Then, we clear the rate of change of the volume within (2):

[tex]P\cdot \dot V = -\dot P\cdot V[/tex]

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

If we know that [tex]P = 180\,kPa[/tex], [tex]\dot P = 30\,\frac{kPa}{min}[/tex] and [tex]V = 300\,cm^{3}[/tex], then the rate of change of the volume is:

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

[tex]\dot V = -50\,\frac{cm^{3}}{min}[/tex]

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Answer:

cuprous chloride

Explanation:

Copper dichloride

Copper(II) chloride

Copper(II) chloride/IUPAC ID