Which of these groups of values plugged into the TVM Solver of a graphing
calculator will return the same value for PV as the expression
($415)((1 +0.003)24 – 1)?
(0.003)(1 +0.003)24
Answers
The TVM solver is a tool found in graphing calculators, that solve Time
Value of Money problems.
The group of values that will return the same value as the given expression is; D. N = 24; I% = 3.6; PV =; PMT = -415; FV = 0; P/Y = 12; C/Y = 12; PMT :ENDReasons:
In the TVM solver, we have;
I = The annual percentage rate
N = n × t
t = The number of years
PV = Present value
PMT = Payment
P/Y = Number of payments per year = n
C/Y = Number of compounding periods per year = n
The formula for monthly payment is presented as follows;
[tex]M = \mathbf{\dfrac{P \cdot \left(\dfrac{r}{n} \right) \cdot \left(1+\dfrac{r}{n} \right)^{n \times t} }{\left(1+\dfrac{r}{n} \right)^{n \times t} - 1}}[/tex]
Which gives;
[tex]P = \mathbf{\displaystyle \frac{M\cdot \left(\left(1+\dfrac{r}{n} \right)^{n \times t} - 1 \right) }{\left(\dfrac{r}{n} \right) \cdot \left(1+\dfrac{r}{n} \right)^{n \times t}}}[/tex]
Therefore, we get;
Where;
M = PMT = -415
P = PV
r = I
P/Y = n = 12
Therefore;
[tex]\displaystyle 0.003 = \frac{I}{12}[/tex]
I = 0.003 × 12 = 0.036 = 3.6%
N = n × t = 24
[tex]P = \displaystyle \frac{(415)\cdot \left(\left(1+\dfrac{I}{12} \right)^{24} - 1 \right) }{\left(\dfrac{I}{12} \right) \cdot \left(1+\dfrac{I}{12} \right)^{24}} = \mathbf{\displaystyle \frac{(415)\cdot \left(\left(1+0.003\right)^{24} - 1 \right) }{\left(0.003\right) \cdot \left(1+0.003 \right)^{24}}} = ?[/tex]
The value of the equation is the present value, PV = ?
When payment are made based on the PV, we have FV = 0
The group of values the same value as the expression[tex]\displaystyle \frac{(\$415)\cdot (1 + 0.003)^{24} - 1}{(0.003) \cdot (1 + 0.003)^{24}}[/tex], when plugged into the TVM solver of a calculator is; D. N = 24; I% = 3.6; PV =; PMT = -415; FV = 0; P/Y = 12; C/Y = 12; PMT :END
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Step-by-step explanation:
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Answer:
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What is log10(70) - The logarithm base 10 of a number is its logarithm to the base of 10 where lg(70) = 1.84509804001.
Step-by-step explanation:
log10 70
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Step-by-step explanation:
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Answers
Step-by-step explanation:
the currency does not matter (only if we get into any fractions of the main unit and have to name the fractions properly). % is usually about the number itself.
so,
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Explanation
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Step-by-step explanation:
hope that it will help you
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Step-by-step explanation:
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Step-by-step explanation:
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Answers
Using the z-distribution, it is found that since the test statistic is greater than the critical value, it can be concluded that the mean length of jail time has increased.
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[tex]H_0: \mu = 2.5[/tex]
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in spring 2017, data was collected from a random selection of sta 2023 students. one of the question how many concerts they had attended in the past six months. for the 39 randomly selected upperclassmen, the sample mean was 2.31 and sample standard deviation was 2.32. for the 35 randomly selected underclassmen, the sample mean was 2.29 and the sample standard deviation was 2.64. what is the point estimate of the difference in the population mean difference in number of concerts attended between underclassmen and upperclassmen?
Answers
Answer:
Step-by-step explanation:
5
According to the point estimate, the population mean difference in the number of concerts attended by freshmen vs seniors is 0.02.
What is the difference in population mean's point estimate?The difference in sample means is a point estimate for the difference in population means.
What's the best way to respond to this query?Data were collected from a random sample of STA 2023 students in the spring of 2017 in order to answer the question. One of the questions they were asked was how many concerts they had gone to in the previous six months. The sample mean was 2.31, with a sample standard deviation of 2.32 for the 39 upperclassmen who were chosen at random. The sample mean was 2.29, and the sample standard deviation was 2.64 for the 35 randomly selected underclassmen.
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Upperclassmen sample mean - underclassmen sample mean = point estimate,
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