Answer:
it will be 322 because 8 + 4 is 12 and 1+2 is 3
In figure 5, what are the values of x and y?
(4x - 12)
(7y+12)°
(12x+8)°
Answer:
sorry
Step-by-step explanation:
Where is the figure?
Please help!!
I need to factor P(x)=x^4+50x^2+625
I thought the answer was P(x)=(x^2+25)^2
But it isn’t could someone please help with the answer?
x
4
+
50
x
2
+
625Rewrite
625
as
25
2
.
u
2
+
50
u
+
25
2
Check the middle term by multiplying
2
a
b
and compare this result with the middle term in the original expression.
2
a
b
=
2
⋅
u
⋅
25
Simplify.
2
a
b
=
50
u
Factor using the perfect square trinomial rule
a
2
+
2
a
b
+
b
2
=
(
a
+
b
)
2
, where
a
=
u
and
b
=
25
.
(
u
+
25
)
2
Replace all occurrences of
u
with
x
2
.
(
x
2
+
25
)
2
Plz help due tomorrow iff correct ill give brailiest
Identify the parent function that can be used to graph the function f(x)=2[x-6]
Answer:
F(x) =2(1/2 x2-6x) +C
Step-by-step explanation:
Hope it helps
Answer: the correct answer is B. f(x)=[x]
Step-by-step explanation:
1. The parent function of a Function part full is shown below:
f(x)=[x] (This is the simplest form) Because from this function we can make transformations that allow us to obtain the function f(x) =2[x-6]
2. If you take the parent function and make y=f(x-6), then you have:
f(x-6)=[x-6] (The function is shifted 6 units on the positive x-axis)
3. Then you if you make y = 2f(x-6), as following, you obtain:
y = 2f(x-6)=2[x-6] (The function It expands vertically in the y-axis).
4. That is how you obtain the final function.
Given right triangle JKL, what is the value of cos(L)?
1. 5/13
2. 5/12
3. 12/13
4. 12/5
Answer:
A 5/13
Step-by-step explanation:
Just took the test
The value of Cos L in the given right triangle JKL, is 5/13
What is a Cosine of the angle?The cosine of an angle is defined as the sine of the complementary angle.
The complementary angle equals the given angle subtracted from a right angle, 90°.
Also, the cosine of an angle is the length of the adjacent side (A) divided by the length of the hypotenuse (H).
Given is a right triangle JKL, we need to find the value of cos(L),
Since, the cosine of an angle is the ratio of the base and hypotenuse,
So, firstly of we will find the value of the hypotenuse,
Using the Pythagoras theorem,
12²+5² = hypotenuse²
hypotenuse = √(12²+5²)
hypotenuse = √169
hypotenuse = 13
Therefore, Cos L = 5/13
Hence, the value of Cos L in the given right triangle JKL, is 5/13
Learn more about cosine of the angles, click;
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Re-order the premises in each of the arguments to show that the conclusion follows as a valid consequence from the premises. It may be helpful to rewrite the statements in if-then form and replace some statements by their contrapositives. Exercises are adapted from Symbolic Logic by Lewis Carroll.
1. When I work a logic example without grumbling, you may be sure it is one I understand.
2. The arguments in these examples are not arranged in regular order like the ones I am used to.
3. No easy examples make my head ache.
4. I cant understand examples if the arguments are not arranged in regular order like the ones I am used to.
5. I never grumble at an example unless it gives me a headache. These examples are not easy.
Answer:
Step-by-step explanation:
1. If I do not grumble while doing the logic exam, then it is because I understand the questions.
2. If the arguments are not arranged in regular order, then I will not be used to these examples.
3. If my headaches, then it is probably because it is not an easy example.
4. If the arguments are not arranged in regular order like I am used to, then I will not be able to understand them.
5. If the example is not easy and I am grumbling, then it is because it is giving me a headache.
Employees at Pete's Packaging earn time-and-a-half pay for all hours worked beyond 40 hours.
Last week an employee worked a total of 44.5 hours. How much overtime pay did the employee
earn if his regular pay rate is $12.28 per hour?
Answer:
82.89
Step-by-step explanation:
If you owned a house, and the assessed value was $435,000.00, how much in property taxes would you have to pay per year if the rate was 0.79%? (be sure to use $ and a decimal. No need to use a comma)
a bit of help
The Amount of property taxes you would have to pay per year if the rate was 0.79% is $3,436.50.
If you owned a house and the assessed value was $435,000.00, the amount of property taxes you would have to pay per year
if the rate was 0.79% can be calculated as follows:SolutionTo calculate the amount of property taxes, multiply the assessed value by the tax rate.
We can represent this mathematically as:P = R × Vwhere:P = Property taxesR = Tax rateV = Assessed Value
We are given that:R = 0.79%V = $435,000.00
We need to convert the tax rate to a decimal value before we can use it in our calculation. This can be done by dividing the percentage value by 100. Therefore:R = 0.79 ÷ 100= 0.0079
Using the formula above, we can now calculate the property taxes as:P = R × V= 0.0079 × $435,000.00= $3,436.50
Therefore, the amount of property taxes you would have to pay per year if the rate was 0.79% is $3,436.50.
For more questions on Amount.
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I Need help with this question please
Answer:
8cm
Step-by-step explanation:
8×8×8
[tex] {8}^{3} {cm}^{3} [/tex]
PLEASE HELP ITS DONE IN 8 HOURSS!!!!!!
MY FRIEND NEED HELP !
find the least common denominator for the following fractions: 3/8 and 2/3
answer:
number 4
Step-by-step explanation:
24 ? 8×3=24
Is this table linear or not?
The first person that guess what game I play get free games...
Answers
rblx or among us
and I need help in math good luck
Answer:
amoug us
Step-by-step explanation:
Use the table to write a linear function that relates y to I.
X
-2
0
2
4
y
-7
- 7 - 7
- 7
=
10
Answer:
y = -7
Step-by-step explanation:
✔️Find the slope (m) using any two pairs of values, say (0, -7) and (2, -7):
Slope (m) = ∆y/∆x = (-7 -(-7))/(2 - 0) = 0/2 = 0
Slope (m) = 0
✔️Find y-intercept (b):
y-intercept is the value of y when x = 0. From the table, when x = 0, y = -7.
Therefore, y-intercept (b) = -7
✔️ Substitute m = 0 and b = -7 into y = mx + b (slope-intercept form):
y = 0(x) + (-7)
y = -7
find the common difference of the arithmetic sequence 10, 1, -8...
Can someone please help!!!
Please help!!! I'm very confused! Im giving points for it but if please tell the truth <3
Answer:
A
Step-by-step explanation:
It actually trying to trick you with a double negative
Answer:
A
Step-by-step explanation:
Squares do have right angles, if they did not have to then all other ssquares with no right angles would be considered rhombuses.
The question is sking which does not apply, a does not apply but thats what theyre asking so its a
Fill in the blanks please. Please show work
Step-by-step explanation:
1. given
2. vertical angles
3. alternate interior angles
4. AA I think
Answer:
number 1 hehehehej2b2ii2
How will the graph of the function f(x)=3^x translate the function is changed to f(x)=3(x-2)
Answer:shift two units to the right
Step-by-step explanation:
sabrina is making a snack mix. She uses these items. peanuts 5/6, chocolate chips 1/3, granola 1/2, raisins 3/4. What is the total weight Sabrina used
Answer:
29/12
Step-by-step explanation:
5/6+1/3+1/2+3/4
10/12+4/12+6/12+9/12
14/12+6/12+9/12
20/12+9/12
29/12
Is 4(4f-8)+5= 16f+37
A dilation produces a smaller figure. Which is a possible scale factor?
0 -2
O 1/3
O 1
O4
Answer:
1/3
Step-by-step explanation:
And can someone answer this question as well please
Answer:
a) 3
b) 725
c) 12100
d)3900
Plz plz plz, HELP!!!! I will give u brainlylist
What is the probability of landing on red and rolling a number greater than 2?
Answer: 1/4 I think
Step-by-step explanation:
Janice buys 74 packs of gum in a variety flavors. She chooses twice as many packs of green apple gun as packs of spearmint gum and 6 fewer packs of cinnamon gun than packs of green apple gum. How many packs of spearmint gum does Janice buy?
Answer:
16 packs of spearmint gum
Step-by-step explanation:
Let x = no. of packs of spearmint gum
2x = no. of packs of green apple gum
2x - 6 = no. of packs of cinnamon gum
x + 2x + 2x - 6 = 74
5x - 6 = 74
5x = 80
x = 16 packs of spearmint gum
2x = 2(16) = 32 packs of green apple gum
2x - 6 = 32 - 6 = 26 packs of cinnamon gum
Find the highest common factor (HCF) of 90 and 126
Answer:
18
Step-by-step explanation:
18*5=90
18*7=126
Erin loves to cook with fresh herbs. So, she decides to plant 8 different herbs and keep the
small pots on her kitchen windowsill. She starts with a 2-kilogram bag of soil and puts the
same amount of soil in each pot. If she uses all of the soil, how many grams does she add to
each pot?
This is a simple division problem, there are 1000 grams in 1 kilogram, so we do 2000/8, which is 250, so Erin put 250 grams of soil in each pot.
Look for Patterns Sally sees
a pattern in these numbers. Describe
the pattern.
500, 501, 502, 503, 504, 505
Answer:
Step-by-step explanation:
It is an arithmetic sequence. The nth term = 499 + n
) Express each of these statements using mathematical and logical operators, predicates, and quantifiers, where the domain consists of all integers. a) The sum of two negative integers is negative. b) The difference of two positive integers is not necessarily positive. c) The sum of the squares of two integers is greater than or equal to the square of their sum. d) The absolute value of the product of two integers is the product of their absolute values.
Answer:
a. ∀ a, b ∈ Z, if a < 0 ∧ b < 0 ⇒ a + b < 0
b. ∀ a, b ∈ Z, if a > 0 ∧ b > 0 ⇒ a - b < 0 ∨ a - b > 0
c. ∀ a, b ∈ Z, a² + b² ≥ (a + b)
d. ∀ a, b ∈ Z, |ab| = |a||b|
Step-by-step explanation:
a. The sum of two negative integers is negative.
First, we take the quantifier ∀ and write the two integers a and b as a element of the set of integers Z as ∀ a, b ∈ Z. Now, if a and b are negative, we write if a < 0 ∧ b < 0 where the logical operator ∧ represents "and". So, we have the statements ∀ a, b ∈ Z, if a < 0 ∧ b < 0. Then finally, we use the logical operator ⇒ to imply the summation of the two integers as ⇒ a + b. And since we are to show that their sum is less than zero, we write ⇒ a + b < 0.
Combining this statement with the previous expressions, we have
∀ a, b ∈ Z, if a < 0 ∧ b < 0 ⇒ a + b < 0
b. The difference of two positive integers is not necessarily positive.
First, we take the quantifier ∀ and write the two integers a and b as a element of the set of integers Z as ∀ a, b ∈ Z. Now, if there exists a and b that are positive, we write if a > 0 ∧ b > 0 where the logical operator ∧ represents "and". So, we have the statements ∀ a, b ∈ Z, a > 0 ∧ b > 0. Then finally, we use the logical operator ⇒ to imply the difference of the two integers as ⇒ a - b. And since we are to show that their difference is either less than zero or greater than zero, we write ⇒ a - b < 0 ∨ a - b > 0 where ∨ implies the logical operator "or".
Combining this statement with the previous expressions, we have
∀ a, b ∈ Z, if a > 0 ∧ b > 0 ⇒ a - b < 0 ∨ a - b > 0
c. The sum of the squares of two integers is greater than or equal to the square of their sum.
First, we take the quantifier ∀ and write the two integers a and b as a element of the set of integers Z as ∀ a, b ∈ Z. Now, since we are dealing with the sum of the squares of each integer, we write a² + b². And, we are to show that this sum is greater than the sum of the individual integers, we write their sum as a + b, and we show the previous sum to be greater than or equal to this as a² + b² ≥ (a + b).
Combining this statement with the previous expressions, we have
∀ a, b ∈ Z, a² + b² ≥ (a + b)
d. The absolute value of the product of two integers is the product of their absolute values.
First, we take the quantifier ∀ and write the two integers a and b as a element of the set of integers Z as ∀ a, b ∈ Z. Now, since we are to show that absolute value of the product of the integers equals the product of the absolute value of the individual integers, we write the that absolute value of the product of the integers as |ab| and the product of the absolute value of the individual integers as |a||b|.
Since we are to show that this expression and the previous expression are equal, we write |ab| = |a||b|.
Combining this statement with the previous expressions, we have
∀ a, b ∈ Z, |ab| = |a||b|