where is full question man
animal cell vs plant cell
Answer:
animal cell
Explanation:
How do you explain Meiosis?
Answer:
Chromosome pairs with its corresponding homologous chromosome to form a tetrad.
Two species of closely related frogs are found in the same pond high in the Andes of South America. Both species only have teeth on the top jaw. One has small teeth for holding small live prey prior to swallowing. The other species has very large sharp teeth for injuring and killing large prey prior to biting off pieces of flesh for consumption. The above is an example of:
Complete question:
Two species of closely related frogs are found in the same pond high in the Andes of South America. Both species only have teeth on the top jaw. One has small teeth for holding small live prey prior to swallowing. The other species has very large sharp teeth for injuring and killing large prey prior to biting off pieces of flesh for consumption. The above is an example of:
Directional selectionAnalogous structuresCharacter displacementHybridization Vestigial structuresAnswer:
Character displacementExplanation:
Competition is an ecological and evolutive process very common in nature. Competition might be intra- or interspecific. Competition between different species in a community or ecosystem might be due to the same resource use, or the same territory, shelter, etcetera. When a resource is useful for two or more species, and limited, they compete to gain it.
The principle of competitive exclusion states that different species with the same requirements sharing the niche can not coexist indefinitely based on the same limited resource. When two competing species coexist, this is because of niche partitioning or niche differentiation.
Differentiation of effective niche is closely related to character displacement.
Character displacement is the result of interspecific competition, in which two or more species that live in the same habitat manage to avoid competition by developing different traits. Morphological divergence, or any adaptative trait development, fixated genetically, is the product of niche segregation. Species tend to differentiate morphologically in the presence of strong competitors. Traits divergence favors coexistence in the same place.
In the exposed example, both species live in the same pond. But to avoid competition and competitive exclusion, species developed different teeth sizes to feed on different prey items.
Several genes in humans in addition to the ABO gene (I ) give rise to recognizable antigens on the surface of red blood cells. The MN and Rh genes are two examples. The Rh locus can contain either a positive or a negative allele, with positive being dominant to negative. M and N are codominant alleles of the MNgene. Suppose a child's blood type is B MN Rh(neg). The mother's blood type is O N Rh(neg). Check all of the blood types below that the father could have. (Assume no involvement of the Bombay phenotype; everyone is HH.)
a) O M Rh(neg)O M Rh(neg)
b) B MN Rh(pos)B MN Rh(pos)
c) A M Rh(pos)A M Rh(pos)
d) O MN Rh(pos)O MN Rh(pos)
e) B MM Rh(pos)B MM Rh(pos)
f) B NN Rh(neg)
In these imprinted cells, the SNRPN transcript overlaps with another gene, called UBE3A, which is transcribed in the opposite direction. This means that the region that the RNA polymerase transcribes in these two genes actually overlaps; in some cases, overlapping transcription in opposite directions leads to transcriptional interference, meaning that collisions between the polymerases traveling in opposite directions can interfere with transcription. It is believed that this takes place in this case, meaning that the more SNRPN transcription occurs, the more this disrupts transcription of UBE3A. Based on this information as well as information about the effects of imprinting on SNRPN transcription, which of the following statements about UBE3A transcription would be true?
a. The maternal copy of UBE3A is expressed and the paternal copy is silenced.
b. The paternal copy of UBE3A is expressed and the maternal copy is silenced.
c. Both copies of UBE3A are highly expressed.
d. Both copies of UBE3A are silenced.
Answer:
a. The maternal copy of UBE3A is expressed and the paternal copy is silenced.
Explanation:
When UBE3A chromosome is in neurons, paternal allele is silent and maternal allele is expressed in process of genomic imprinting. In some cases UBE3A is expressed from both paternal and maternal chromosomes. The paternal chromosome is blue whereas maternal chromosome is magenta.
Which of the cardiac cell characteristics describes the
ability to initiate an electrical impulse?
Answer:
The correct answer is: automaticity.
Explanation:
Cardiac muscle has several properties. These properties are: automaticity (given by the pacemaker cells), conductivity (meaning that each cardiac cell can transmit the electrical impulse to the next cardiac cells), contractility (like other types of muscles, cardiac muscle cells can contract), and irritability (each cell can contract on its own without the external stimuli).
Cardiac pacemaker cells are the ones with the capacity to initiate the electrical impulse by creating rhythmic impulses called action potentials, and thus directly regulating heart rate.
Pacemaker cells are located in the sinoatrial (SA) node, in the upper portion of the right atrial wall. In these cells, depolarization of the cardiac muscle begins, and the electrical impulse generated by it is transmitted to the atrioventricular (AV) node, the His bundle and then the Purkinje fibers - this order of events is necessary for the correct contraction of the heart to occur. All of these structures are part of the Conduction System of the heart.
Which of the following is a disadvantage of geothermal energy?
Answer:
B
Explanation:
The collection process of geothermal energy itself creates large amounts of pollution which damages the environment - especially toxicity in water.
Answer:
B. Collecting it damages the environment.
how does this show the relationship between photosynthesis and cellular respiration
Answer:
mark me brainlist
Explanation:
Photosynthesis makes the glucose that is used in cellular respiration to make ATP. The glucose is then turned back into carbon dioxide, which is used in photosynthesis. While water is broken down to form oxygen during photosynthesis, in cellular respiration oxygen is combined with hydrogen to form water.
.
This one too, please?
(3rd time)
I need explanation for your answers, even though it's multiple choices, I still need your explanation for it.
DUE TOMORROW!
If your answer is NONSENSE it will be deleted as soon as possible!
But if your answer is CORRECT, HELPFUL, HAS AN EXPLANATION, I'll chose your answer as the BRAINLIEST ANSWER!
Answer:
1, group 1
2 group 7
3 group 2
4 D
5 B
6 A
Answer:
7. A 1
8. C 17
9. B 2
10. (d) C and D
11. (b) reactivity
12. (a) corrosion
13. (c) activity series
Explanation:
7. , 8, and 9,
Group 1 elements are named as alkali metals
Group 2 elements are known as alkaline earth metals
group 17 metals are known as halogens
10.
Na and Xe have one valency whereas the other two elements have variable valency which is a property of transition metals so the answer is (d) C and D
11.
It;s the definition of reactivity
12.
Definition of corrosion
13.
definition of activity series
Suppose that 1 mL of an enzyme solution can completely catalyze 10 mL of substrate in 8 minutes. Now suppose that you change the amount of enzyme, the amount of substrate, or add another substance to the mixture. How would each type of change affect the reaction rate?
Match the results you would expect with each change to the experimental design. The same result may occur with more than one experimental change.
1. Use 0.5 mL of enzyme instead of 1 mL
2. Use 5 mL of substrate mixed with 5 mL water instead of 10 mL of substrate
3. Add a molecule to the mixture that preferentially binds and blocks the enzyme's active site
4. Use 20 mL of substrate instead of 10 mL
a. The reaction rate will be close to zero over the entire 8 minutes
b. The reaction rate will remain steady over the entire 8 minutes
c. The reaction rate will approach zero before 8 minutes.
Answer:
1. b. The reaction rate will remain steady over the entire 8 minutes.
2. c. The reaction rate approach zero before 8 minutes.
3. a. The reaction rate will be close to zero over the entire 8 minutes.
4. b. The reaction rate will remain steady over the entire 8 minutes.
Explanation:
When 0.5 mL of enzyme is introduced with water, the reaction will remain steady. When more substrate solution is mixed with water, then reaction will approach to zero depending on the amount of substrate mixed with water.
Which of the following statements depend on the absolute dating of events?
Answer:
The statement that depends on the absolute dating of events is this: The oldest Earth rocks are 3.9 billion years old. Absolute dating is the method of determining the specific date of an archaeological or paleontological artifact.
Answer:
It says that the oldest Earth rocks are 3.9 trillion years old, and they depend on the absolute adaptations of events. Absolute dating is the mechanism through which an archaeological or paleontological artifact determines a particular date.
120 million years ago, birds diverged from the related dinosaurs.3.9 billion years old is the oldest Earth rock.Explanation:
Geologists must often know the material age they encounter. They use absolute data systems, sometimes referred to as numerical dates, to provide rocks with the actual date or date range for years to come. It differs from relative dates, which only time-consuming geologic events.
In contrast to the relative date, the absolute date represents a certain age or range which places occurrences among events without age being measured. The most absolute ages for rocks are reached by radiometric methods. Minerals are radioactive in rocks like geological watches.
Recent discoveries in a cave at Pinnacle Point, South Africa, suggest that humans had achieved behavioral modernity as early as 164,000 B.P. All of the following were found at this site EXCEPT evidence of:_______
a. a diet that included shellfish and other marine resources.
b. the very early use of pigment, likely for symbolic behavior.
c. animal butchery for the first time.
d. bladelet stone-tool technology, previously dating to 70,000 years ago.
e. the human capacity to exploit coastal environments.
Answer: C. Animal butchery for the first time
Explanation: The discoveries in the cave suggest that humans were harvesting food from the sea (including shellfish and other marine resourses), the use of complex small stone tools and using red pigments in symbolic behavior 164,000 years ago.
A paleoanthropologist (with the Institute of Human Origins at Arizona State University); Curtis Marean, who was the Lead of the research team expressed the aforementioned discoveries while presenting their reports on the research.
He further indicate that these discoveries translates that humans must have been living along this coastal environment at that early time while exploiting it resourses.
based on the 1:2:1 proportions of carbon, hydrogen and oxygen, it can be determined that a glucose molecule is a
Answer:
Carbohydrate (monosaccharide)
Explanation:
Carbohydrates are one of the four biological molecules in nature. Carbohydrates are structurally composed of carbon, hydrogen and oxygen elements. However, these elements (C,H,O) are present in each carbohydrate in the ratio 1:2:1 respectively.
As stated in this question, glucose is an organic molecule made up of carbon, hydrogen and oxygen in the 1:2:1 proportion, hence, it is a CARBOHYDRATE. Since glucose possess one sugar component, it is classified as a MONOSACCHARIDE with a chemical formula C6H12O6.
What is an ecosystem?
21 Science 6 - CR Calculating the Density of Propane Use the mass and volume data to calculate the density of liquid propane to the nearest hundredth. Mass of propane = 4,300 g Volume of propane = 10,000 mL The density of liquid propane is g/mL. Intro
Answer:
0.43g/mL
Explanation:
Density of a substance is its mass per unit volume. It can be calculated thus:
Density = mass/volume
According to the information provided on propane in this question;
Mass of propane = 4,300g
Volume of propane = 10,000mL
Density = 4300/10000
Density = 0.43g/mL
Hence, the density of propane is 0.43g/mL.
Na + Cl2 --> NaCl if you were given 15 grams of sodium (with excess chlorine) and asked to determine the amount of NaCl that would be produced (in grams), how would you go about doing it. Be as specific as possible and include numerical values when necessary.
Answer:
The correct answer is - 38.15 gm of NaCl.
Explanation:
Write the balanced equation for this reaction of sodium (Na) and chlorine (Cl₂) to produce sodium chloride (NaCl):
2Na + Cl₂ —> 2NaCl
the mass of Na and the mass of NaCl :
Molar mass of Na = 23 g/mol
In the balanced equation = 2 × 23 = 46 g
Molar mass of NaCl = 23 + 35.5
= 58.5 g/mol
similarly in balanced equation = 2 × 58.5 = 117 g
From the balanced equation above,
46 g of Na reacted to produce 117 g of NaCl.
By converting it to 15 grams of Na.
Therefore,15 g of Na will react to produce = (15 × 117)/46 = 38.15 g of NaCl.
Thus, 38.15 g of Na
what precautions should you take to avoid exposure to blood borne pathogens
Explanation:
The Bloodborne Pathogens standard (29 CFR 1910.1030) and CDC's recommended standard precautions both include personal protective equipment, such as gloves, gowns, masks, eye protection (e.g., goggles), and face shields, to protect workers from exposure to infectious diseases.
Answer:
The Bloodborne Pathogens standard (29 CFR 1910.1030) and CDC's recommended standard precautions both include personal protective equipment, such as gloves, gowns, masks, eye protection (e.g., goggles), and face shields, to protect workers from exposure to infectious diseases.
The ability of the human body to break down the red color in beets is controlled by an autosomal dominant allele. The inability is recessive, detected by red coloration of the urine (we will call this phenotype 'secretor'). If a nonsecretor woman with a secretor father has children with a nonsecretor man who in a previous relationship had a secretor daughter, what is the probability that their first child will be...
Solution :
It is given that a woman is a nonsecretor but the father of that woman is a secretor. It means that the father's genotype is recessive, i.e. "ss".
The genotype of the nonsecretor mother would be Ss, who have received one recessive allele from her father.
Now the nonsecretor man have a secretor daughter from his previous marriage. That means that he is a carrier nd his genotype is Ss.
Now, we can cross between the heterozygous parents (Ss x Ss) will have offspring with the following genotypes :
1 SS -- Nonsecretor
2 Ss -- Nonsecretor
1 ss -- secretor
Thus the probability that their first child will be :
a). a secretor girl
[tex]$=\frac{1}{4} \times \frac{1}{2}$[/tex]
[tex]$=\frac{1}{8}$[/tex]
b). Non secretor girl
[tex]$=\frac{3}{4} \times \frac{1}{2}$[/tex]
[tex]$=\frac{3}{8}$[/tex]
c). a secretor boy
[tex]$=\frac{1}{4} \times \frac{1}{2}$[/tex]
[tex]$=\frac{1}{8}$[/tex]
What trait are narcissists likely to have that is associated with leader emergence but not effectiveness
Answer:
Agreeableness.
Explanation:
Agreeableness is the trait that narcissists likely to have which is negatively corelated and is associated with leader emergence but not effectiveness. The tendency toward self-interest would attract the person into follow his or her own goals rather than the interests of their group or company. The term Narcissism originated from Greek mythology, where a young man whose name is Narcissus fell in love with his own image reflected in a pool of water so that's why selfness and self interests refers to Narcissism.
which is more vulnerable to disturbances, a simple food web with only a few species or a more complex one
Answer:
few species
Explanation:
in a complex one im not sure as to how the question measures complexity but a complex one may have more options and more things to adapt to
produce three small cells that
Meiosis and unequal cytoplasmic division in seed plant
disintegrate and one large megaspore.
O a gametophytes
O b. pollen sacs
O c pollen grains
O d. microspores
o e ovules
Meiosis and unequal cytoplasmic division in seed plant produce three small cells that disintegrate and one large megastore
Explain how the results from testing Barley High Lysine (BHL) are related to the primary, secondary and tertiary structure of protein?
Answer:
Enhanced derivatives of barley chymotrypsin inhibitor-2 are known as Barley high lysine (BHL) proteins. BHL has tryptophan, threonine, and isoleucine in a folded structure similar as the tertiary structure of protein.
Derivatives of BHL are digestible in gastric juice and other fluid. Denaturation of these proteins shows proteins in gastric fluid minus pepsin which is looks as the secondary structure of protein. It has four soluble protein groups –
a) Albumins
b) globulin fraction in embryo and scutellary proteins
c) Prolamins
d) Glutelin
_____________ is a post-translational modification that occurs in the endoplasmic reticulum or Golgi apparatus to make proteins functional.
Answer:
Lipidation is a post-translational modification that occurs in the endoplasmic reticulum or Golgi apparatus to make proteins functional.
Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these alleles are at Hardy-Weinberg equilibrium, what is the frequency of the disease-causing CFTR alleles in this population
Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
n
Mauna Loa is the most active volcano on Earth.
O True
O False
h
Answer:
it's "True"
Mauna Loa is the most active volcano on Earth
Answer:
True
Explanation:
Because A^2+B^2=C^2
A part of an mRNA has the sequence CCG. Which change to this sequence
would indicate a missense mutation?
Phe UCC
UUG Leu/UCA
Messenger
Second base in codon
RNA Codons
U
C
A
G
UUU
UCU UAU UGU 1 U
UUC
UAC Tyr
U
UGC)
Cys
с
Ser
UUA
UM Stop UGA Stop A
UCG UAG Stop UGG Trp G
CUU
CCU CAU CGU
CUC ССС
CAC
His
CGC
с
Leu
Pro
CUA CCA
Arg
CAA CGA
Gin
ΓΑ
CUG CCG CAG CGG
AUU ACU
AAU
Asn
AGU
AUC
U
lle ACC ААС AGC
Ser
А
Thr
с
AUA ACA AAA AGA
Lys
AUGS ACG
Α
AAG AGG
GUU GCU GAU GGU
Asp
U
GUC GCC GAC GGC
G
Val Ala
GUA GCA
Gly
GAA
Glu
GGA
GUG) GCG
GAG) GGG)
GCA
First base in codon
OCOCODOC
Third base in codon
Arg
O O A. CCU
O B. CGG
Ос. ССА
D. CCC
The question is kind of confusing but from what I understand; missense mutations happen when an amino acid is changed to another amino acid. To find out more specifically, look at a codon chart trust me it helps so much lol (just search codon chart and go to images). missense mutations can also cause a premature stop codon so look for a changed amino acid and a stop codon when u look at the codon chart. maybe if u see the different pairs you can get a more specific answer. I hope this helps :)
11.
The temperature of a body of water influences
vegetation patterns
global warming
the formation of deserts
the temperature of the air above it
Which insect when compared with each other leaves a distinct frass trail?
Choose the best answer.
a. Citrus leafminer
b. Citrus peelminer
Among the two options, the insect that leaves a distinct frass trail is the citrus leafminer (option a).
The citrus leafminer (Phyllocnistis citrella) is a small moth that infests citrus trees. Its larvae mine within the leaves, creating serpentine tunnels or trails as they feed on the leaf tissue. These feeding tunnels are often accompanied by visible frass, which is the excrement or waste material produced by the insect.
The distinctive frass trail left by the citrus leafminer is a characteristic sign of its presence and activity. As the larvae tunnel through the leaf, they push out frass along the length of the feeding tunnel. This frass appears as dark, winding lines or trails on the surface of the leaf, following the path of the larval mining activity.
On the other hand, the citrus peelminer (Marmara gulosa) is another insect that infests citrus trees but does not leave a distinct frass trail. The larvae of the citrus peelminer mine under the citrus fruit peel, causing irregular winding tunnels within the fruit. However, they do not leave visible frass trails like the citrus leafminer.
Therefore, when comparing the two options, the citrus leafminer (option a) is the insect that leaves a distinct frass trail, making it a useful diagnostic characteristic for identifying its presence and distinguishing it from other pests infesting citrus trees.
To learn more about citrus leafminer, here
https://brainly.com/question/33967117
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You are out hiking and walk past a great outcrop of granite that is part of an exposed batholith. Looking closer you notice pieces of sandstone within the batholith. Which rock is OLDER, the granite or the sandstone?
Answer:
Sandstone is younger than the granite rocks
Explanation:
As the rocks layer found at the bottom are the oldest and closer to the ground surface are the younger. This is due to the law of superimposition and as when looking at the outcrops you will notice pieces of sandstone within the batholith that indicates that the base is formed by granite and is later cemented by sandstone rockBelow is a mature eukaryotic mRNA transcript. Translate this mRNA into a protein, also showing the tRNA anticodons involved. Make sure you start and end translation in the right place! Label the ends of the polypeptide chain as N and C terminus.
mRNA: 5'GMUUACAUGCGGCUCAGUUGAGGCGAAAAAA 3'
tRNA:
amino acids:
Answer:
mRNA ⇒ 5'GMU UAC AUG CGG CUC AGU UGA GGC GAA AAA A 3'
tRNA ⇒ UAC GCC GAG UCA ACU
protein ⇒ N - MET ARG LEU SER Stop - C
Explanation:
In protein synthesis, the ribosome reads mRNA in the 5´ to 3´ direction, and, according to the codons that are being readen, tRNA transfers the correct amino acids to build the polypeptide chain. A codon is a short sequence of three nucleotides that store the genetic information for the aminoacids´ assembly. Each tRNA has two important sites. One of them that couples with the codon of the mRNA molecule, named anticodon. The other site couples with an amino acid. tRNA allows amino acids to align according to the nucleotidic sequence in the mRNA molecule.
Once the new amino acid links to the growing peptidic chain, the binding between the amino acid and the tRNA molecule breaks. The tRNA is now free to join another amino acid and repeat the cycle.
The protein is synthesized from the amino terminus to the carboxy terminus, while the added amino acids to the chain are coded by a codon formed by three bases in the mRNA. mARNs also have a start and end codon that are the signals of the synthesis initiation and finish. When the ribosome reaches the end codon, protein synthesis is over.
Each of the codons represents one of the 20 amino acids used to build the protein. Each amino acid can be codified by more than one codon. From the total 64 codons, 61 codify amino acids, and one of them is a start codon. The left three codons are stopping translation points.
The codons indicating the initiation or stop points during the translation process are:
• The start codon AUG is the most common sequence used by eukaryotic cells and places near the 5´extreme of the molecule.
• The end codons are UAA, UAG, UGA.
Protein synthesis initiates in the AUG start codon -Metionin-, and ends when reaching either of the stop codons UAA, UAG, UGA.
In the exposed example we have the following mRNA.
mRNA ⇒ 5'GMU UAC AUG CGG CUC AGU UGA GGC GAA AAA A 3'
Codons are separated by a space left between them. AUG is the start codon placed near the 5´ extreme. UGA is the end codon near the 3´ extreme. tRNA will add amino acids from the start codon, not before.
tRNA ⇒ UAC GCC GAG UCA ACU
Anticodons are separated by a space left between them.
protein ⇒ N - MET ARG LEU SER Stop - C
Each mRNA codon codifies for an amino acid. The start codon codifies for methionine. AUG = Met, CGG = Arg, CUC = Leu, AGU = Ser, UGA = Stop codon. The amino terminus is represented as an N and the carboxy terminus is a C. The first extreme to be translated carries the amino-terminal group, while the other extreme carries the carboxy-terminus group.