Answer:
HCl.
Explanation:
Of all the type of bond, Ionic bonds are the strongest. Among all the compounds in the options only HCl has ionic bond, rest have covalent bonds. So, the strongest intermolecular forces is in HCl. Ionic bond are formed with the transfer of electrons, one atom is donor and the other is acceptor.
A5 gram ball has a volume of 2.5 milliliters. What is the density of the ball?
(Mass is measure in grams, volume is measured in milliliters and density is measured in
grams/milliliter.)
Answer:
2 g/mL
Explanation:
The following data were obtained from the question:
Mass (m) = 5 g
Volume (V) = 2.5 mL
Density (D) =.?
Density is simply defined as the mass of substance per unit volume of the substance. Mathematically, it is expressed as:
Density (D) = mass (m) /volume (V)
D = m/V
With the above formula, we can obtain the density of the ball as follow:
Mass (m) = 5 g
Volume (V) = 2.5 mL
Density (D) =.?
D = m/V
D = 5/2.5
D = 2 g/mL
Therefore, the density of the ball is 2 g/mL.
Find the pH of a 0.350 M aqueous benzoic acid solution. For benzoic add. Ka = 6.5 x 10^-5.
a) 4.64
b) 4.19
c) 2.32
d) 11.68
Answer:
correct option is (a)
The solution would be using this: C6H5COOH = H+ + C6H5COO Ka = 6.5 x 10^-5 = (H+)(C6H5COO-) over
(C6H5COOH)
Let X = moles per liter (H+) and also = moles per liter (C6H5COO-)
Ka = 6.5 x 10^-5 = (X)(X) over .350 molar = acid solution 6.5 x 10^-5 = X^2 over .350
X^2 = 6.5 x 10^-5 times .350 which = 2.275 x 10^-5
x = V2.275 x 10^-5
X = 1.5083 x 10^-5 moles per liter H+
pH = -log(H+) = -log 1.5083 x 10^-5 which
= 4.6215
The pH of a 0.350 M aqueous benzoic acid solution is 4.64. The correct option is a).
What is pH?In chemistry, the pH scale is used to define the acidity or basicity of an aqueous solution. Historically, pH stood for "potential of hydrogen."
The solution would be using this: C₆H₅COOH = H+ + C₆H₅COO Ka = 6.5 x 10⁻⁵ = (H+)(C₆H₅COO-) over
(C₆H₅COOH)
Let X = moles per liter (H+) and also = moles per liter (C6H5COO-)
Ka = 6.5 x 10⁻⁵ = (X)(X) over .350 molar = acid solution 6.5 x 10⁻⁵= X² over .350
X² = 6.5 x 10⁻⁵ times .350 which = 2.275 x 10⁻⁵
x = V2.275 x 10⁻⁵
X = 1.5083 x 10⁻⁵ moles per liter H+
pH = -log(H+) = -log 1.5083 x 10⁻⁵ = 4.6215
Therefore, the pH is 4.6215. The correct option is a). round to 4.64.
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If a chemical has a pH of 3, how could you alter its pH value to be more basic?
Answer; If a chemical has a pH of 3, how could you change its pH value to be more basic? Adding water to a chemical will dilute the acid, thus lowering the pH value to more basic.
If a chemical has a pH of 3, that means it is strong acid.To alter its pH value to be more basic, we have add strong base in excess.
First, neutralization reaction occur. After adding excess strong base, the solution becomes basic and pH become more basic.
What is neutralization reaction?The reaction between strong acid and base to form salt and water is called neutralization reaction.
Example: HCl + NaOH → NaCl + H2O
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How much heat does it take to melt 5.0g solid copper?
Answer:
[tex]Q=1.04kJ[/tex]
Explanation:
Hello,
In this case, for latent heat (phase change) we need to consider the enthalpy associated with the involved process, here, melting or fusion; thus, the enthalpy of fusion of copper is 13.2 kJ/mol, therefore, the heat is computed as:
[tex]Q=m\Delta H_{fus}[/tex]
Nevertheless, since the given enthalpy is per mole of copper, we need to use its atomic mass to perform the correct calculation as follows:
[tex]Q=5.0g*\frac{1mol}{63.54}* 13.2\frac{kJ}{mol}\\ \\Q=1.04kJ[/tex]
Which is positive as it needs to be supplied to the system.
Best regards.
In cell notation, all species appearing to the left of the double vertical line represent:________.
a. the anode.
b. the cathode.
c. the salt bridge.
d. a phase boundary.
Answer:
a. the anode.
Explanation:
An anode is an electrode through which the conventional current enters into a polarized electrical device. This contrasts with a cathode, an electrode through which conventional current leaves an electrical device
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Answer: the cathode, by convention the components of the cathode are always listed last
NH3 is a weak alkali that does not dissociate fully into its solution. Which of the following is true about NH3?
A. It has a very low pH.
B. It's dissociation is a reversible reaction.
C. It has a high H+ concentration.
D. It will release all of its OH- ions.
Answer:
Answer:
B. It's dissociation is a reversible reaction
Explanation:
NH3 is a weak alkali that does not dissociate fully into its solution. Only parts of the ammonia takes part in the dissociation process.
NH3 + H20 —> NH4+ + OH-
This dissociation is reversible which means the reactants can be formed from the product gotten from the dissociation
It has a high pH due to its basic nature. It also has a Low concentration of H+ ions and not all the OH- ions are released.
Given the following equation and bond energies, determine which statement is true. N2+02 2NO N-N triple bond: 941 kJ/mol O-O double bond: 495 kJ/mol N-O bond: 201 kJ/mol
A. The reaction is exothermid
B. A nitrogen-oxygen bond is broken
C. The products have more energy than the reactants.
D. A triple bond between nitrogen atoms is formed
Answer:
The reaction is exothermic
Explanation:
If we look at this reaction system closely, we will discover that the energy of reactants is greater than that of the product. The excess energy possessed by the reactants must be given off at the end of the reaction.
Since ∆Hrxn = ∆Hproducts - ∆Hreactants and ∆Hreactants > ∆Hproducts hence ∆Hrxn is negative and the reaction is exothermic, hence the answer.
If the toxic quantity is 1.5 g of ethylene glycol per 1000 g of body mass, what percentage of ethylene glycol is fatal
Answer:
[tex]\%m/m=0.15\%[/tex]
Explanation:
Hello,
In this case, we are asked to compute the by mass percent representing the toxicity of ethylene glycol in the body mass. In such a way, since the by mass percent is computed as follows:
[tex]\%m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%[/tex]
Whereas the solute is the ethylene glycol in the body mass, we obtain:
[tex]\%m/m=\frac{1.5g}{1.5g+1000g} *100\%\\\\\%m/m=0.15\%[/tex]
Best regards.
The percentage of ethylene glycol that is fatal would be 0.15%.
The toxic quantity is 1.5 g of ethylene glycol for 1000 g of body mass.
The percentage toxic quantity in relation to the body mass can be calculated as:
Percentage = mass of toxic quantity/body mass x 100%
= 1.5/1000 x 100%
= 0.15 %
Thus, the fatal level of ethylene glycol is 0.15% of body mass.
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2 poit
2. For the question above, the measurement 0.2002 grams is a
measurement of what type of property?*
w
Mass
Volume
Density
Temperature
Answer:
Mass.
Explanation:
Hello,
In this case, we should remember that dimensions are useful to represent the quantity that a property has. For instance, when measuring mass, volume, density and temperature, the value that the property has at a specific condition must be accompanied with the corresponding unit. In such a way, since the measurement is given as 0.2002 grams, we can identify those grams accounts for mass.
Best regards.
Calculate the solubility of BaCO3 (a) in pure water and (b) in a solution in which [CO32-] = 0.289 M. Solubility in pure water = M Solubility in 0.289 M CO32- = M
Answer:
(a). The solubility of [tex]BaCO_{3}[/tex] in pure water is [tex]4.4\times10^{-5}\ M[/tex]
(b). The solubility of [tex]BaCO_{3}[/tex] in solution is [tex]6.92\times10^{-9}\ M[/tex]
Explanation:
Given that,
(a). The solubility of [tex]BaCO_{3}[/tex] in pure water
(b). The solubility of [tex]BaCO_{3}[/tex] in a solution
Solubility of [tex]CO_{3}^{-2}[/tex] is 0.289 M
We know that,
The solubility product constant of [tex]BaCO_{3}[/tex] is [tex]2\times10^{-9}[/tex]
Let the solubility of [tex]BaCO_{3}[/tex] is s.
We need to calculate the solubility of [tex]BaCO_{3}[/tex] in pure water
Using formula of solubility
[tex]ksp=s\times s[/tex]
[tex]ksp=s^2[/tex]
[tex]s=\sqrt{ksp}[/tex]
Put the value into the formula
[tex]s=\sqrt{2\times10^{-9}}[/tex]
[tex]s=4.4\times10^{-5}\ M[/tex]
(b). We need to calculate the solubility of [tex]BaCO_{3}[/tex] in solution
Using formula of solubility
[tex]ksp=s\times s[/tex]
Put the value into the formula
[tex]2\times10^{-9}=s\times 0.289[/tex]
[tex]s=\dfrac{2\times10^{-9}}{0.289}[/tex]
[tex]s=6.92\times10^{-9}\ M[/tex]
Hence, (a). The solubility of [tex]BaCO_{3}[/tex] in pure water is [tex]4.4\times10^{-5}\ M[/tex]
(b). The solubility of [tex]BaCO_{3}[/tex] in solution is [tex]6.92\times10^{-9}\ M[/tex]
When solid sodium hydroxide (NaOH) pellets are dissolved in water, the temperature of the water and beaker rises. The formation of an aqueous solution of sodium hydroxide is
Answer:
Exothermic
Explanation:
A reaction is said to be exothermic when heat is evolved in the process. The evolution of heat implies that the energy of reactants is greater than that of the products, hence energy is given off when the products are formed.
If you dissolve sodium hydroxide in water, the vessel feels hot when touched. This signifies that energy is given off during the process. Hence the formation of an aqueous solution of sodium hydroxide is exothermic.
Identify the polar solvent. Identify the polar solvent. toluene carbon tetrachloride diethyl ether acetone hexane
Answer:
Acetone.
Explanation:
Hello,
In this case, we can distinguish between polar solvent and nonpolar solvent by the nature of the bonds present in the compound. Thus, since the bonds C-Cl, C-C, C-H and C-O are nonpolar, which are contained in the toluene, carbon tetrachloride, diethyl ether and hexane, they are discarded as polar.
Nevertheless, since the carbonyl group contained in the acetone is a polar because of the formed positive and negative charges, it is actually the polar solvent, acting as an exception. This is substantiated by the fact the acetone is soluble in water whereas the other substances not,
Regards.
If the same amount of heat is added to 50.0 g samples of each of the metals which are all at the same temperature, which metal will reach the highest temperature?
Copper 0.385 J/gºC
Magnesium 1.02 J/gºC
Mercury 0.138 J/g °C
Silver 0.237 J/g °C
Lead 0.129 J/gºC
a. Copper
b. Magnesium
c. Mercury
d. Silver
e. Lead
Answer:
e. Lead
Explanation:
Hello,
In this case, since the equation to compute the heat in a heating or a cooling process is:
[tex]Q=mCp(T_2-T_1)[/tex]
We can see that the lower the specific heat of the substance, the higher the reached temperature as they are in an inversely proportional relationship. In such a way, we can say that e. Lead will reach the higher temperature if the same heat is added to same mass of the other metals.
Regards.
If the concentration of mercury in the water of a polluted lake is 0.250 μg (micrograms) per liter of water, what is the total mass of mercury in the lake, in kilograms, if the lake has a surface area of 18.5 square miles and an average depth of 39.0 feet?
Answer:
142.36 kg
Explanation:
volume of water in the lake = surface area x depth
= 18.5 x ( 1760 x 3 )² x 39 ft³
= 2.011 x 10¹⁰ ft³
= 2.011 x 10¹⁰ x 28.3168 liter .
= 56.945 x 10¹⁰ liter .
concentration of mercury = .25 x 10⁻⁶ g / liter
= 25 x 10⁻⁸ g / liter
= 25 x 10⁻¹¹ kg / liter
mass of mercury in the water of lake
= 25 x 10⁻¹¹ x 56.945 x 10¹⁰ kg
= 142.36 kg .
LiAlH4 reacts with acid chlorides to yield secondary alcohols after hydrolysis.
a. True
b. False
Answer:
a. True
Explanation:
In this reaction, we will have a hydride transfer to the carbon of the carbonyl group, moving the electrons of the double bond towards the oxygen producing a negative charge. The double bond is then regenerated by removing the chlorine atom from the molecule, producing an aldehyde.
Then, another molecule the LiAlH4 transfers another hydride to the carbon of the carbonyl group, again producing a negative charge on the oxygen. Finally, the hydrogen is protonated producing a primary alcohol.
See figure 1
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A 24.0 gram object has a volume of 6.0 mL. What is the density of the object?
Answer:
4 g/mL
Explanation:
The density of a object can be found using the following formula.
[tex]d=\frac{m}{v}[/tex]
where m is the mass and v is the volume.
We know that the mass of the object is 24.0 grams and the volume is 6.0 milliliters.
[tex]m= 24 g\\v=6 mL[/tex]
Substitute the values into the formula.
[tex]d= \frac{24g}{6mL}[/tex]
Divide 24 g by 6 mL.
[tex]d= 4 g/mL[/tex]
The density of the object is 4 grams per milliliter.
Answer:
4 g/mL
Explanation:
density = mass/volume
therefore, density = 24/6
ρ = 4 g/mL
Draw a Lewis structure for BCl3 and answer the following questions based on your drawing.
1. For the central boron atom:
A. The number of lone pairs = ___
B. The number of single bonds = ___
C. The number of double bonds = ___
2. The central boron atom __
A. Obeys the octet rule
B. Has an incomplete octet.
C. Has an expanded octet.
Answer:
1. For the central boron atom:
A. The number of lone pairs = 0.
B. The number of single bonds = 3.
C. The number of double bonds = 0.
2. The central boron atom B. Has an incomplete octet.
Explanation:
Hello,
In this case, as shown on the attached picture containing the required Lewis structure of boron chloride, we can see that:
1. For the central boron atom:
A. The number of lone pairs = 0 since all the three valance electrons are bonded with the chlorine atoms.
B. The number of single bonds = 3 as each chlorine atom needs only one bond to obey the octet.
C. The number of double bonds = 0 considering the previous explanation.
2. The central boron atom B. Has an incomplete octet since it reaches six electrons only from its initial three and other three provided by the three chlorine atoms.
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The cylinder of aluminum in class was approximately 13mm in circumference and 42mm in length. What would be it's approximate mass?
Answer:
Mass, m = 1.51 grams
Explanation:
It is given that,
The circumference of Aluminium cylinder, C = 13 mm = 1.3 cm
Length of the cylinder, h = 4.2 cm
We know that the density of the Aluminium is 2.7 g/cm³
Circumference, C = 2πr
[tex]r=\dfrac{C}{2\pi}\\\\r=\dfrac{1.3}{2\pi}\\\\r=0.206\ cm[/tex]
Density is equal to mass per unit volume.
[tex]d=\dfrac{m}{V}[/tex]
m is mass of the cylinder
V is the volume of the cylinder
[tex]V=\pi r^2h\\\\V=\dfrac{22}{7}\times0.206^2\times 4.2\\\\V=0.5601\ cm^3[/tex]
So,
[tex]m=d\times V\\\\m=2.7\times 0.5601\\\\m=1.51\ g[/tex]
So, the mass of the cylinder is 1.51 grams.
3. Explain why environmental science is an interdisciplinary science.
Answer:
Environmental science is also referred to as an interdisciplinary field because it incorporates information and ideas from multiple disciplines. Within the natural sciences, such fields as biology, chemistry, and geology are included in environmental science.
Explanation:
Environmental science is an interdisciplinary science because it integrates physics, biology, and geography to the study of the environment, and the solution of environmental problems.
What do you mean by the environmental science and interdisciplinary science ?Environmental science is the field of science that studies the interactions of the physical, chemical, and biological components of the environment and the relationships .
Interdisciplinary science allows you to study according to your professional and academic abilities and goals .
Environmental science is an interdisciplinary science because it integrates physics, biology, and geography to the study of the environment, and the solution of environmental problems.
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1 how many moles of sodium bicarbonate are needed to neutralize 0.9ml of sulphuric acid at stp
Answer:
0.0338 moles of sodium bicarbonate are required to react with 0.9 mL 100% sulphuric acid solution
Explanation:
Equation of the reaction:
Na₂CO₃(aq) + H₂SO₄(aq) ---> Na₂SO₄(aq) + H₂O(l) + CO₂(g)
Since the concentration of the sulphuric acid is not given in the question, the assumption is made that the sulphuric acid solution is 100% sulphuric acid solution.
The density of 100% concentrated sulfuric acid is 1.839 g/mL.
Amount of acid in 0.9 mL solution = 0.9 mL * 1.839 g/mL = 1.655 g
Number of moles of acid in 1.655 g = mass/molar mass
Molar mass of H₂SO₄ = 98 g/mol
Number of moles of acid in 1.471 g = 1.655 g / 98 g/mol = 0.0169 moles
From the equation of reaction, 1 mole of H₂SO₄ reacts with 2 moles of Na₂CO₃
0.0169 moles of H₂SO₄ will react with 0.0169 * 2 moles of Na₂CO₃ = 0.0338 moles
Therefore, 0.0338 moles of sodium bicarbonate are required to react with 0.9 mL 100% sulphuric acid solution
Which ONE of the following is an oxidation–reduction reaction? A) PbCO3(s) + 2 HNO3(aq) ––––> Pb(NO3)2(aq) + CO2(g) + H2O(l) B) Na2O(s) + H2O(l) –––> 2 NaOH(aq) C) SO3(g) + H2O(l) ––––> H2SO4(aq) D) CO2(g) + H2O(l) ––––> H2CO3(aq) E) C2H4(g) + H2(g) ––––> C2H6(g)
Answer:
E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g)
Explanation:
Which ONE of the following is an oxidation–reduction reaction?
A) PbCO₃(s) + 2 HNO₃(aq) ⇒ Pb(NO₃)₂(aq) + CO₂(g) + H₂O(l). NO. All the elements keep the same oxidation numbers.
B) Na₂O(s) + H₂O(l) ⇒ 2 NaOH(aq). NO. All the elements keep the same oxidation numbers.
C) SO₃(g) + H₂O(l) ⇒ H₂SO₄(aq). NO. All the elements keep the same oxidation numbers.
D) CO₂(g) + H₂O(l) ⇒ H₂CO₃(aq). NO. All the elements keep the same oxidation numbers.
E) C₂H₄(g) + H₂(g) ⇒ C₂H₆(g). YES. C is reduced and H is oxidized.
Explain what would happen if only 1 mole of oxygen gas were available to interact with naphthalene in this reaction.
Answer:
This question is incomplete but the completed question is below
a) Identify the chemical equation that represents what would occur if naphthalene (C₁₀H₈) is burned in the presence of O₂
b) Identify how many moles of carbon dioxide would be released from the equation in (a) if 25.0 g of naphthalene were burned in the presence of excess oxygen.
c) Explain what would happen if only 1 mole of oxygen gas were available to interact with naphthalene in this reaction.
The answers to the questions are below
Explanation:
a) The chemical reaction here will be a combustion reaction. A combustion reaction involves the burning of a substance (in this case an organic compound) in excess oxygen to produce carbon dioxide and water.
The balanced equation below shows what will happen when naphthalene (C₁₀H₈) is burned in the presence of O₂
C₁₀H₈ + 10O₂ ⇒ 10CO₂ + 4H₂O
b) The mass of naphthalene (C₁₀H₈) from the equation above is
when C= 12 and H = 1; C₁₀H₈ = (10 × 12) + (1 × 8) = 128 g
Mass of C₁₀H₈ from the equation in (a) above is 128 g
If 128g of C₁₀H₈ ⇒ 10 moles of CO₂
25g of C₁₀H₈ ⇒ X moles of CO₂
where X is the unknown
X = 25 × 10/128
X = 1.95 moles of CO₂
1.95 moles of CO₂ would be released from the equation in (a) if 25.0 g of naphthalene were burned in the presence of excess oxygen
(c) If just 1 mole of oxygen gas was available for the reaction in (a) above, the reaction would have been an incomplete combustion. An incomplete combustion is the process in which a substance burns in insufficient oxygen to produce carbon monoxide (CO) and water.
Which of the following should have the highest conductivity? a. 3.0 M NaCl b. 2.1 M Na3PO4 c. 2.4 M CaCl2 d. 3.2 M NH4NO3
Answer:
The correct answer is option b, that is, 2.1 M Na₃PO₄.
Explanation:
The solution with the largest concentration of ions will possess the highest conductivity.
a) 3.0 M NaCl
NaCl ⇔ Na⁺ + Cl⁻
Here the total number of ions is 2, therefore, the concentration of ions is 3.0 × 2 = 6.0 M
b) 2.1 M Na₃PO₄
Na₃PO₄ ⇔ 3 Na⁺ + PO₄³⁻
Here the total number of ions i 4. Therefore, the concentration of ions is
2.1 × 4 = 8.4 M.
c) 2.4 M CaCl₂
CaCl₂ ⇔ Ca²⁺ + 2Cl⁻
The total number of ions is 3. Therefore, the concentration of ions is
2.4 × 3 = 7.2 M
d) 3.2 M NH₄NO₃
NH₄NO₃ ⇔ NH₄⁺ + NO₃⁻
The total number of ions is 2. The concentration of ions will be,
3.2 × 2 = 6.4 M
Hence, the highest conductivity will be of 2.1 M Na₃PO₄.
Why is the pH scale important in science? Give several examples of scientific applications.
Answer:
See the answer below
Explanation:
The pH scale is important in science because it gives an indication of how acidic or basic a solution is. The scale ranges from 0 - 14 with 0 being the most acidic and 14 being the most basic while a pH of 7 is a neutral pH.
The pH scale is widely applicable in several scientific applications such as in medicine/health, agricultural processes, industrial processes, environmental monitoring, research and development, etc.
In medicine, the pH of the stomach is monitored in order to make some diagnosis. The normal pH of the human stomach ranges from 1.5 - 3.5 and a major deviation from this range can give an indication of wrong health.
In agriculture, the pH condition of the soil on which crops are grown is quite important. While some crops require slightly acidic soil, some will only do well in alkaline soil. Hence, the pH condition of the soil must be monitored to ensure the optimal yield of crops.
Several industrial processes require the monitoring of pH in order to ensure product's quality or monitor some important reactions. In food industries, for example, monitoring the pH of reactions is necessary in order to prevent contamination by pathogens or ensure a good organoleptic quality of the final product. It is also necessary to monitor the pH of industrial wastewaters in order to avoid polluting the environment.
Monitoring pH is also important for environmental monitoring, The pH of various water bodies or soil can give an indication of the level of pollution in the water or the soil.
The pH can be defined as the concentration of the hydrogen ions in the sample. The determination of pH helps in the designing of the study and investigating the reactions.
Some of the examples for the scientific application of pH has been:
The pH has application in medicines where it has been used for the determination of the pH of the stomach to test acidity, pH of the blood, pH of the urine for pathological investigations.The pH has been used in agriculture, for the determination of the soil sample, and the strength of the sample resulting in the crop analysis to be grown.The pH scale has application in the industrial process for the analysis of the compound formed and the reaction process.The pH scale in the environmental analysis helps for the analysis of the quality of the air, and other parameters study.For more information about the pH importance, refer to the link:
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Obtain a box of breakfast cereal and read the list of ingredients. What are four chemicals from the list? a. monoglycerides b. cocamide DEA c. folic acid d. iron e. chromium ion f. peroxide g. lauryl glucoside h. disodium phosphate
Answer:
B. cocamide DEA
C. folic acid
D. iron
G. lauryl glucoside
What is the concentration in %m/v of a 0.617 M aqueous solution of methanol (MM = 32.04 g/mol)?
Answer:
The correct answer is 1.977 % m/v ≅ 2% m/v
Explanation:
We have:
0.617 M = 0.617 moles methanol/ 1 L solution
We need:
%m/v= grams of methanol/100 mL solution
So, first we convert the moles of methanol to grams by using the MM (32.04 g/mol). Then, we multiply by 0,1 to convert the volume in liters to 100 mL by using the ratio: 100 mL= 0.1 L:
0.617 mol / 1 L x 32.04 g/mol 0.1 L/100 mL= 1.977 g/100 mL= %m/v
The concentration in [tex]\%_{m/v}[/tex] of a 0.617 M aqueous solution of methanol is 1.98%.
To find the [tex]%_{m/v}[/tex] concentration of methanol we need to use the following equation:
[tex] \%_{m/v} = \frac{m_{s}}{V_{sol}} \times 100 [/tex] (1)
Where:
[tex] m_{s}[/tex]: is the mass of methanol in grams
[tex] V_{sol} [/tex]: is the volume of the solution in milliliters
The molar concentration of methanol is:
[tex] C = 0.617 M = 0.617 \:\frac{mol}{L} [/tex]
From this concentration, we can find the mass of methanol
[tex] m = n*MM [/tex] (2)
Where:
n: is the number of moles = C*V
MM: is the molar mass = 32.04 g/mol
Then, the mass of methanol is (eq 2):
[tex] m = n*MM = C*V*MM = 0.617 mol/L*1 L*32.04 g/mol = 19.77 g [/tex]
Knowing that 1 L = 1000 mL, the [tex]%_{m/v}[/tex] concentration is (eq 1):
[tex] \%_{m/v} = \frac{m_{s}}{V_{sol}} \times 100 = \frac{19.77 g}{1000 mL} \times 100 = 1.98 \% [/tex]
Therefore, the concentration in [tex]\%_{m/v}[/tex] is 1.98%.
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Cross aldol condensation reaction was carried out by reacting Acetone with Benzaldehyde in presence of sodium hydroxide. How many alpha carbon are present in acetone
Answer:
Carbons 1 and 3
Explanation:
We must remember that by definition alpha carbons are the carbon (or carbons) next to the carbon that contains the main group. In this case, the main group is the carbonyl group (C = O) in the middle of the molecule. In the acetone molecule, we have three carbons, the carbons neighboring the carbon of the carbonyl group (carbon two) will be the alpha carbons. (Red and blue carbons or carbons one and three)
See figure 1 for further explanations.
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Which of the following describes what happens to the solubility of a slightly soluble ionic compound when a common ion is added to the solution?
a) The solubility of the ionic compound is reduced.
b) The ionic compound dissolves more rapidly.
c) The solubility of the ionic compound is increased.
d) There is no effect on the solubility of the ionic compound.
e) More of the ionic compound dissolves.
Answer:
a) The solubility of the ionic compound is reduced.
Explanation:
Let AB be the ionic compound . It will ionise as follows in solution .
AB ⇄ A⁺ + B⁻
In solution AB , A⁺ and B⁻ maintain a state of equilibrium . Now if we add A⁺ ion as common ion to the solution , the equilibrium will be shifted to the left ie less of AB will ionise to maintain equilibrium . Hence the solubility of AB will be reduced .
The solubility of an ionic compound reduces when any common ion is being added to any solution.
Solubility:
Solubility my be defined as the act of dissolving anything in it. It is the ability of a substance to dissolve a solvent in order to form a solution.Ionic compound :
Ionic compounds are chemical compounds.They are made up of ionic compounds which held them together.When some common ion adds into a solution, the solubility of a slightly soluble ionic compound gets reduced due to :
common ion effectreverse reaction to the ionization processLearn More :
https://brainly.com/question/24057916
In a concentration cell, the reaction is driven by: Select the correct answer below:
a. K
b. Q
c. E*cell
d. all of above
Answer:
b. Q
Explanation:
Equilibrium constant K is a measure of the ratio of the equilibrium concentration of the products of a reaction to the equilibrium concentration of the reactants with each concentration raised to the power corresponding to the coefficient in the balanced equation of the reaction.
On the other hand , the [tex]E^\theta_{cell}[/tex] is the standard electrode potential of the right-hand electrode minus the standard electrode potential of the left hand electrode, Thus, [tex]E^\theta_{cell}[/tex] will be zero if concentration cell in the two electrodes appears to be the same.
The Nernst equation correlates the cell E.M.F to a standard value E and the activities of the species that takes places in the cell reaction. Thus in a concentration cell, the reaction is driven by Q
The product of the following reaction H2C=CH-CHO + NaBH4 /H2O is:
Answer:
H2C=CH-CH2OH
Explanation:
Aldehydes are reduced to primary alcohols.
The first step in the reaction sequence is that the nucleophilic Hydrogen atom in the hydride reagent attacks the electrophilic Carbon in the polar carbonyl group of the aldehyde, there will now be a shift of electrons from the carbonyl to the Oxygen atom creating an intermediate metal alkoxide complex.
The reaction sequence is completed by a simple addition of a proton to the alkoxide oxygen which creates the primary alcohol product from the intermediate complex.