Which of the following statements is true?

1. The molar mass of Oz is 48 g/mol

2. A 100-gram sample contains at least 2 moles of Oz

3. 48 grams of O3 contains 6. 02 x 1023 molecules of Oz

Answer:

Explanation:

Image result for Summarize: What do you think would happen to the convection currents in the atmospheres and along the coastlines of the surface of the Earth warmed up? Do you think this could have any affect on the convection in the mantle? Why or why not? Your answer should be at least 3 sentences in length,

As the magma cools and solidifies, the convection currents will stop and the Earth will become geologically dead.

Explanation:

Answer:

here:)

Explanation:

Natural Sciences is the core of the branches of science as studies the nature of our physical world and the universe. The three branches of Natural Sciences are:

Physics, the Study of Universe.

Chemistry, the Study of Matter.

Biology, the Study of Life and Living Organisms.

Answer:

a solution with high amount of hydrogen ions is called an acidic solution

Answer:

The electron arrangement of the outer energy level of an atom determines whether or not it will form chemical bonds.

Explanation:

Answer:

In the kinetic molecular theory of gas behavior; the assumption is made that gas molecules move with a kinetic energy equal to their centigrade temperature_ move rapidly in random directions: are close together in their container which exerts pressure_ are attracted to each other by strong forces.

Explanation:

Answer:

A reaction is second order with respect to a reactant.

Rate =k[A]

2

(i) If the concentration of the reactant is doubled, the rate of reaction becomes 4 times .

(ii) If the concentration of the reactant is reduced to half, the rate of reaction becomes one fourth.

Explanation:

If a reaction is second-order with respect to a particular reactant, when the concentration of that reactant is increased by a factor of 4, the reaction rate will increased by factor 16.

Rate of the second order reaction will depends on the concentrations of one second-order reactant or two first-order reactants as:
Rate(1) = k[A]²

If the concentration of reactant becomes 4 times the initial concentration then rate will be:

Rate = k[4A]²

Rate(2) = 16k[A]²

Rate(2) = 16Rate(1)

Hence rate will increased by 16 times.

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75% dominant and 25% resistive

The  standard change in free energy is -35.76 kJ/mol. Values of standard free energy are obtained from thermodynamic tables.

The standard change in free energy can  be obtained using the relation;

ΔG°= ΔH° - TΔS

When;

ΔH°f(HI) = 26.466 kJ/mol

ΔH°f(H2) = 0 kJ/mol

ΔH°f(I2) = 0 kJ/mol

ΔS°f(HI) = 221.63 J/K/mol

ΔS°f(H2) = 145.64 J/K/mol

ΔS°f(I2) = 0 J/K/mol

Hence;

ΔH°freaction = [ 2(26.466)] - 0

= 52.932 kJ/mol

ΔS°freaction = [2(221.63 ) ] - [145.64 + 0]

= 443.26 - 145.64 = 297.62 J/K/mol

ΔG°= 52.932 * 10^3 - [298 * 297.62 ]

ΔG°= -35.76 kJ/mol

The  standard change in free energy is -35.76 kJ/mol.

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The change in free energy for the given chemical reaction between hydrogen and iodine gas is -31.068 kJ/mol.

Free energy change of any reaction will be calculated by using the below equation:

ΔG° = ΔH° - TΔS, where

ΔH° = change in enthalpy

T = absolute temperature = 298K

ΔS = change in entropy

Change in any quantity during the reaction will be find out by substracting the reactant values from product values.

Given chemical reaction is:

H₂(g) + I₂(g) → 2HI(g)

ΔH° = 2(26.466)] - 0 = 52.932 kJ/mol

ΔS = [2(206.6) ] - [131 + 0] = 413.2 - 131 = 282.2 J/K.mol = 0.282 kJ/K.mol

On putting values on above equation, we get

ΔG° = 52.932 - (298)(0.282) = -31.068 kJ/mol

Hence required free enrgy is -31.068 kJ/mol.

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Answer:

I recently answered this question. The response I submitted is included below. I beleive my answer should be correct.

Explanation:

Question 1:

C: 48.38g(1mol/12g) = 4.0317 

H: 8.12g(1mol/1.01g) = 8.12

O: 53.5g(1mol/16g) = 3.34375

Divide by the smallest amount (3.34375)

C = 4.0317/3.34375 = 1.206 = 1

H = 8.12/3.34375 = 2.42 = 2

O = 3.34375/3.34375 = 1

Empirical formula = CH2O

Question 2:

Molecular formula = n(empirical formula)

n = molar mass (compound)/molar mass (empirical)

Empirical formula: CH2O

Molar mass of CH2O = 12 + 2x1 + 16 = 30 g/mol

Molar mass of compound: 180.15 g/mol

[tex]n=\frac{180.15g/mol}{30g/mol}= 6[/tex]

Molecular formula = C6H12O6

Answer:

carbon = 3

hydrogen=5

nitrogen=3

Oxygen=9

Because gathering it leaves a negative impact on natural habitats.

Answer:

Explanation:

To round the number to 3 significant figures, look at the first 4 digits: 3545 which will round to 355. The number in 3 significant figures will be 3,550,000.

[tex]\\ \sf\Rrightarrow 3545530[/tex]

[tex]\\ \sf\Rrightarrow 354553[/tex]

[tex]\\ \sf\Rrightarrow 35455[/tex]

[tex]\\ \sf\Rrightarrow 3545[/tex]

[tex]\\ \sf\Rrightarrow 355[/tex]

Answer:

300.06 grams of glucose can be produced from a photosynthesis reaction that occurs using 10 moles of carbon dioxide.

Explanation:

Answer:

125.6168064 is the answer

The melting point is the temperature a substance must reach to go into its liquid phase (or solid) and a boiling point is the temperature a substance must reach to go into its gas phase (or liquid). For example, water must be 0ºC to melt or freeze and 100ºC to boil.

Answer:

adding water to an anhydrous compound forms a hydrate.

Explanation:

The statement which correctly describes the relationship between a hydrate, water, and an anhydrous compound is adding water to an anhydrous compound forms a hydrate. The correct option is A.

Anhydrous means without water, so the compounds that do not contain water are anhydrous compounds. Some examples are sodium sulfate, hydrogen fluoride, etc.

Hydrates are the compounds that contain water as the H2O molecules. These compounds lose their structure if water molecules are removed from the compound.

So, when water is added to the anhydrous molecules, it converts into hydrates. An example is sodium sulfate decahydrate.

Thus, the correct option is A. Adding water to an anhydrous compound forms a hydrate.

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Answer:

Molybdenum is M, Einsteinium is E, and N is Nitrogen. Lastly, S is sulfur.

Answer:

It would require 80 g of NaOH .

Explanation:

Explanation:

the sulfur ato is in group 6 of the periodic table. In order to become an ion the ato needs to gain 2 electrons so it has a full outer shell of electron and is stable. so the atom S goes to S2+ + 2e

Answer:

Aquatic life

Elevation

Salinity

Temperature

Explanation:

Aquatic life- animals living in water use up dissolved oxygen.

Elevation- the amount of oxygen in elevation increases.

Salinity- Salty water holds less oxygen than fresh water.

Temperature- cold water holds more dissolved oxygen than warm water.

Based on the equation of the reaction and the limiting reactant of the reaction, molarities of the ions are determined from the amount in moles of excess reactants and soluble products formed.

The limiting reactant is he reavtant that is used up in the reaction after which the reaction stops.

The limiting reactant is obtained from the mole ratio of the reactants in the equation of the reaction.

Equation of reaction is given as follows:

Molar mass of AgNO3 = 170 g/mol

Molar mass of Na3P = 100 g/mol

Molar mass of Ag3P = 355 g/mol

Molar mass of NaNO3 = 85 g/mol

Mass of AgNO3 reacting = 83.4 g

Moles of AgNO3 reacting = 83.4/170 = 0.49 moles

Mass of Na3P reacting = 62.9

Moles of Na3P reacting = 62.9/100 = 0.629 moles

Moles ratio of AgNO3 to Na3P = 3 : 1

Mole rational of AgNO3 and NaNO3 1 : 1

Based on the mole ratio;

At the end of the reaction, molarity of the ions are as follows:

Molarity of Na+ = {0.49 + (3 × 0.46)}/1.71

Molarity of P^{3+} = 0.465/1.71

Molarity of NO3^{-1} = 0.49/1.71

Therefore, molarities of the ions are determined from the amount in moles of excess reactants and soluble products formed.

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The curved arrow mechanism for the reaction as described is as represented in the attached image.

Nitriles, upon reaction with LiAlH4 can be converted to 1° amines.

Opon occurrence of this reaction, the hydride nucleophile attacks the electrophilic carbon in the nitrile to form an imine anion. Once stabilized by a Lewis acid-base complexation the imine salt can accept a second hydride to form a dianion.

On this note, the nitrile reduction of 4-methyl pentanenitrile and lialh4, followed by the addition of acid to give the major product is as represented in the attached image.

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the total mass is 187g. The total mass of the reactant is always equal to total mass of the products.

explanation:

as per the given details, the reactant involved in the reaction are 37g of magnesium and 150g of sulfuric acid . the total of the reactant is 187g.

Molar mass is the ratio of the mass to that amount of the substance. The mass of the barium nitrate in the formula unit is 23.0 grams.

The mass of a substance is the product of the molar mass of the compound and the number of moles of the compound.

Given,

Molar mass of barium nitrate = 261.35 g/mol

If, [tex]6.022 \times 10^{23}[/tex] have a mass of 261.35 g/mol then, [tex]5.30 \times 10^{22}[/tex] formula units will have a mass of,

[tex]\begin{aligned}& = \dfrac{261.35 \times 5.30 \times 10^{22}}{6.022\times 10^{23}}\\\\&= 23.0\;\rm gm\end{aligned}[/tex]

Therefore, option C. 23.0 gm is the mass of barium nitrate.

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Answer:

Explanation:

23.0g

The solutions to problems caused by nitrogen gas in solution at certain depths is by discouraging deep diving.

This involves moving around under water with the aid of special breathing equipment.

Limiting the depth of a dive should he encouraged as the maximum depth limit for a diver to use compressed air is 30 to 50 meters.

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Answer:

Quantitative data refers to any information that can be quantified, counted or measured, and given a numerical value. Qualitative data is descriptive in nature, expressed in terms of language rather than numerical values

Explanation:

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3 liters

________________

Answer:

D

Explanation:

12g of carbon produces....... 1 mole of methane

72g of carbon will produce..1÷12 × 72 = 6moles

The mass defect for the isotope thorium-234 if given mass is 234.04360 amu is 1.85864 amu.

Atomic mass (A) of any atom will be calculated as:

A = mass of protons + mass of neutrons

In the Thorium-234:

Number of protons = 90

Number of neutrons = 144

Mass of one proton = 1.00728 amu

Mass of one neutron = 1.00866 amu

Mass of thorium-234 = 90(1.00728) + 144(1.00866)

Mass of thorium-234 = 90.6552 + 145.24704 = 235.90224 amu

Given mass of thorium-234 = 234.04360 amu

Mass defect = 235.90224 - 234.04360 = 1.85864 amu

Hence required value is 1.85864 amu.

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