Which of the following statements are true for any triangle

Answer: 10

Step-by-step explanation: beacause you add both of the sides

The relationship between the two variables is y=4/3 x+3.

The general equation of a straight line is y=mx+c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis.

The coordinate points are (0, 3) and (3, 7)

Here, slope (m) = (7-3)/(3-0)

= 4/3

Substitute m=4/3 and (x, y)=(0, 3) in y=mx+c, we get

3=4/3(0)+c

c=3

So, the equation is y=4/3 x+3

Therefore, the relationship between the two variables is y=4/3 x+3.

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Answer: Function A is greater.

Step-by-step explanation:

just find the slope...

Slope for Function C = [tex]\frac{1}{3}[/tex] = [tex]0.33333[/tex] repeat...

and for Function A = [tex]\frac{5}{2}[/tex] = [tex]2.5[/tex]

to find the slope we use; [tex]s=[/tex] [tex]\frac{y}{x}[/tex].

The angle that the flagpole makes with the ground is 20°.

There are three commonly used trigonometric identities.

Sin x = 1/ cosec x

Cos x = 1/ sec x

Tan x = 1/ cot x or sin x / cos x

Cot x = cos x / sin x

We have,

Flagpole height = 16  feet

From figure  B,

The angle of elevation has increased this means,

The flagpole is leaning.

Now,

The angle that the flagpole makes with the ground.

Cos m = 15/16

Cos m = 0.9375

m = [tex]cos^{-1}[/tex] 0.9375

m = 20.36

m = 20°

Thus,

The angle that the flagpole makes with the ground is 20°.

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Answer:

Solve for B:

[tex]B = -b+\frac{5A}{6h}[/tex]

Step-by-step explanation:

[tex]A=1.2h(b+B)[/tex]

Use the distributive property to multiply [tex]1.2h by b+B[/tex]

[tex]A=1.2hb+1.2hB[/tex]

Swap sides so that all variable terms are on the left hand side.

[tex]1.2hb+1.2hB=A[/tex]

Subtract [tex]1.2hb[/tex] from both sides.

[tex]1.2hB= A - 1.2hb[/tex]

The equation is in standard form.

[tex]\frac{6h}{5} B=-\frac{6bh}{5} +A[/tex]

Divide both sides by [tex]1.2h[/tex].

[tex]\frac{5*(\frac{6h}{5})B }{6h} =\frac{5(-\frac{6bh}{5}+A) }{6h}[/tex]

Dividing by [tex]1.2h[/tex] undoes the multiplication by [tex]1.2h[/tex].

[tex]B = \frac{5(-\frac{6bh}{5}+A) }{6h}[/tex]

Divide [tex]A - \frac{6hb}{5}[/tex] by [tex]1.2h[/tex].

[tex]B = -b+\frac{5A}{6h}[/tex]

Solve For B:

[tex]B = -b+\frac{5A}{6h}[/tex]

The scale factor that has been used is 1/2

From the question, we have the following parameters that can be used in our computation:

Side length on red = 6 units

Corresponding side length on green = 3 units

Given that the red rectangle is the pre-image and the green rectangle is the image

We have

Scale factor = Green/Red

So, we have

Scale factor = 3/6

Evaluate

Scale factor = 1/2

Hence, the scale factor is 1/2

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The equation which models the problem is m - $23.94 = $12.75 and the value of m is $36.69.

A mathematical statement containing two algebraic expressions on two sides of an equal to sign is defined as an equation.

Given,

Cost of a reusable water bottle that Amanda bought = $23.94

Money remaining after buying the bottle = $12.75

Let m represent how much money Amanda had to start.

Then the equation can be written as,

m - $23.94 = $12.75

We have to solve the equation.

Adding $23.94 on both sides,

m = $12.75 + $23.94

m = $36.69

Hence the money at the start is $36.69.

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Answer:

Step-by-step explanation:

First, let's simplify the equation:

(x – 3)² + 9 = 0

(x – 3)² = -9

Now we can apply the square root principle:

x – 3 = ±√(-9)

x – 3 = ±3i

Solving for x:

x = 3 ± 3i

Therefore, the answer is (a) x = 3 + 3i, 3 – 3i.

Answer:

71%

Step-by-step explanation:

We know

Tyler went to the gym on 22 of the last 31 days.

Which of the following is closest to the percentage of days that Tyler went to the gym?

We take

22 divided by 31, times 100 = 71%

So, the answer is 71%

The area of a sector of a circle with radius 100 meters and central angle 1/8 radian is approximately 625 * π square meters.

The area of a sector of a circle with radius 100 meters and central angle 1/8 radian can be found using the formula:

A = [tex](\theta/2\pi )*\pi r^{2}[/tex]

where A is the area of the sector, Θ is the central angle in radians, π is Pi (approximately 3.14), and r is the radius of the circle.

Plugging in the given values, we have:

A = [tex](\frac{\frac{1}{8}}{{2\pi }} )*\pi *100^{2}[/tex]

A =[tex](1/16)*\pi *100^{2}[/tex]

A = [tex](\pi /16)*100^{2}[/tex]

A = (π/16) * 10000

A = 625 * π square meters

So, the area of the sector of the circle with radius 100 meters and central angle 1/8 radian is approximately 625 * π square meters.

The area of a sector of a circle is a portion of the circle's area enclosed by two radii and an arc. The central angle of the sector determines the fraction of the circle's circumference that the arc represents, and therefore the fraction of the circle's area that is enclosed by the sector.

To find the area of a sector, we first need to find the central angle in radians. The central angle is the angle formed by two radii at the center of the circle that intercept the circumference of the circle at the endpoints of the arc.

The formula for the area of a sector is given by:

A = [tex](\theta/2\pi )*\pi r^{2}[/tex]

where A is the area of the sector, Θ is the central angle in radians, π is Pi (approximately 3.14), and r is the radius of the circle.

In the given problem, the radius of the circle is 100 meters and the central angle is 1/8 radian. We plug these values into the formula and simplify to get the final answer.

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a. The probability that a person could give up her cell phone would be 0.69.

b. Probability that a person who could give up her cell phone could also give up television would be 0.45

c. The probability that a person who could not give up her ell phone could give up television would be 0.55.

d. Probability of giving up television is higher for people who could not give up their cell phone than for those who could give up their cell phone.

What is probability?

Probability is an area of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely a statement is to be true. The probability of an event is a number between 0 and 1, where 0 denotes the event's impossibility and 1 represents certainty.

a. The probability that a person could give up their cell phone is the sum of the probabilities in the "Could Give Up" column: 0.31 + 0.38 = 0.69.

Therefore, The probability that a person could give up her cell phone would be 0.69.

b. The probability that a person who could give up their cell phone could also give up television is the conditional probability of "Could Give Up Television" given "Could Give Up Cellphone." This is calculated by dividing the joint probability of "Could Give Up Television" and "Could Give Up Cellphone" (0.31) by the probability of "Could Give Up Cellphone" (0.69): 0.31 / 0.69 = 0.4493 or approximately 0.45.

c. The probability that a person who could not give up their cell phone could give up television is the conditional probability of "Could Give Up Television" given "Could Not Give Up Cellphone." This is calculated by dividing the joint probability of "Could Give Up Television" and "Could Not Give Up Cellphone" (0.17) by the probability of "Could Not Give Up Cellphone" (0.31): 0.17 / 0.31 = 0.5484 or approximately 0.55.

d. To compare the probabilities of giving up television for people who could or could not give up their cell phone, we need to calculate the conditional probabilities of "Could Give Up Television" given "Could Give Up Cellphone" and "Could Give Up Television" given "Could Not Give Up Cellphone" respectively.

Probability of giving up television if one could give up a cell phone: 0.31 / 0.69 = 0.4493 or approximately 0.45.

Probability of giving up television if one could not give up a cell phone: 0.17 / 0.31 = 0.5484 or approximately 0.55.

The probability of giving up television is higher for people who could not give up their cell phone than for those who could give up their cell phone.

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The measure of the angle that defines the orange arc is 144°.

We know that if we have a circle of radius R, and there is an arc defined by an angle θ, then the area of that arc is given by:

A = (θ/360°)*pi*R^2

Where pi = 3.14

Here we know that the diameter is 10 miles, then the radius is:

R = 10mi/2 = 5mi

We can see that the shaded area is a = 10*pi  mi²

Then we can write the equation:

(θ/360°)*pi*(5mi)^2 = 10*pi  mi²

We can divide both sides by pi to get:

(θ/360°)*(5mi)^2 = 10  mi²

We can solve this for θ.

(θ/360°)*(5mi)^2 = 10  mi²

(θ/360°)25 mi² = 10  mi²

(θ/360°) = (10/25)

θ = (10/25)*360° = 144°

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an = 3 + (15 - 1) * 4 = 3 + 14 * 4

= 3 + 56

= 59

So, the 15th term in the sequence is 59.

2. To find the sum of an arithmetic series with first term a1, last term an, and number of terms n, we use the formula: Sn = n/2 * (a1 + an). Plugging in the values, we get:

Sn = 20/2 * (5 + 119)

= 20/2 * 124

= 620

So, the sum of the series is 620.

3. To find the sum of an arithmetic series with first term a1, common difference d, and number of terms n, we use the formula: Sn = n/2 * (2a1 + (n - 1)d). Plugging in the values, we get:

Sn = 15/2 * (2 * 12 + (15 - 1) * 6) = 15/2 * (24 + 84)

= 15/2 * 108

= 810

So, the sum of the series is 810.

4.To find the nth term in a geometric sequence with first term a1, common ratio r, and nth term an, we use the formula: an = a1 * r⁽ⁿ⁻¹⁾. Plugging in the values, we get:

64 = 2 * r⁽⁶⁻¹⁾

64 = 2 * r⁵

32 = r⁵

r = [tex]2^{(5^{(1/5)} )}[/tex]

So, the 6th term in the sequence is 64.

5. To find the sum of a finite geometric series with first term a1, common ratio r, and number of terms n, we use the formula: Sn = a1 * (1 - rⁿ) / (1 - r). Plugging in the values, we get:

Sn = 2 * (1 - 4⁶) / (1 - 4)

= 2 * (1 - 4096) / -3

= 2 * (-4095) / -3

= 2730

So, the sum of the series is 2730.

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The statement that is true about the data shown in the stemplot is that the most common speed limit is 55.

What is stemplot ?
A stemplot, also known as a stem-and-leaf plot, is a type of chart used to display data. It shows the distribution of a set of values by separating each value into a stem and a leaf.

Given by the question:
Based on the values given, the stemplot titled "speed limit" could be constructed as follows:

1 | 0

4 | 5 5 5 5

5 | 0 5 5 5 5 5

6 | 0 0 0 5 5 5 5

7 | 0 0

The stem represents the tens digit of each value, and the leaves represent the ones digit. For example, the first value of 10 has a stem of 1 and a leaf of 0.

Based on the stemplot, we can make the following observations:

Therefore, the statement that is true about the data shown in the stemplot is that the most common speed limit is 55.

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The probability that when n=6,  [tex]Y_{1}[/tex] =3, [tex]Y_{2}[/tex]=1, [tex]Y_{2}[/tex]=2 is 0.0822.

We have to find the probability that n=6,  [tex]Y_{1}[/tex] =3, [tex]Y_{2}[/tex]=1, [tex]Y_{2}[/tex]=2

A rat has three possible exits to come out from the maze

The pmf of multinomial distribution is

P[tex](y_{1}, y_{2}, y_{3}......, y_{k} ) = \frac{n!}{{y_{1!} }y_{2}!....y_{k}! } p^y_1 1p^y_2 2......p^y_k k[/tex]

The probability of choosing one of the ways is 1/3

Then [tex]p_{1}[/tex]= 1 / 3,[tex]q_{1}[/tex] = 1-(1/3) = 2/3

        [tex]p_{2} = 1/3, q_{2} = 2/3\\ p_{3} = 1/3, q_{3} = 2/3[/tex]

[tex]P(y_{1}, y_{2}, y_{3} ) = P(1,2,3)\\ = \frac{6!}{3! 2! 1!} (\frac{1}{3} )3(\frac{1}{3} )2(\frac{1}{3} )1[/tex]

                      =60(0.00137)

                      =0.0822

Hence, the probability that when n=6,  [tex]Y_{1}[/tex] =3, [tex]Y_{2}[/tex]=1, [tex]Y_{2}[/tex]=2 is 0.0822.

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The correct question is:

A learning experiment requires a rat to run a maze (a network of pathways) until it locates one of three possible exits. Exit 1 presents a reward of food, but exits 2 and 3 do not. (If the rat eventually selects exit 1 almost every time, learning may have taken place.) Let [tex]Y_{i}[/tex] denote the number of times exit i is chosen in successive runnings. For the following, assume that the rat chooses an exit at random on each run.

a Find the probability that n = 6 runs result in [tex]Y_{1} = 3, Y_{2} = 1, and Y_{3} = 2.[/tex]

Answer:

Since the second box has inside dimensions four times those of the first box, its volume is $(4a)^3 = 64a^3$ times as much as the volume of the first box, whose volume is $a^3$. Therefore, the answer is (D) 64.

The transformation from f(x) to g(x) is a horizontal shift to the right by 2 units to obtain the graph of g(x).

In mathematics, transformation refers to a change in position, shape, size, or orientation of a figure or a function. There are various types of transformations, including translation, rotation, reflection, dilation, and more.

A translation is a transformation in which a figure is moved to a new position on the coordinate plane, while keeping its original size and orientation intact. A rotation is a transformation in which a figure is turned about a fixed point, called the center of rotation. A reflection is a transformation in which a figure is flipped over a line, called the line of reflection. A dilation is a transformation in which a figure is enlarged or reduced, while keeping its shape intact.

Transformations are used in various areas of mathematics, including geometry, engineering, computer graphics, and more. They provide a way to model real-world objects and processes and to solve problems related to size, position, and orientation. Understanding transformations is a fundamental aspect of mathematical skills and is crucial in many areas of study and research.

The transformation from f(x) = ln(x) to g(x) = ln(x + 2) is a horizontal shift to the right by 2 units. This is because when you replace x with x + 2 in the logarithmic function, you are shifting the graph to the right by 2 units. The x-intercepts of the graph of f(x) will be at x = 1 (since ln(1) = 0), whereas the x-intercepts of the graph of g(x) will be at x = -2 (since ln(2) = 0). So, in essence, the transformation is simply a horizontal shift of the graph of f(x) to the right by 2 units to obtain the graph of g(x).

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The proof of 8 sin26. sin34. sin60. sin86 = root3 sin78 is given below.

Equations using trigonometric functions that hold true for all possible values of the variables are known as trigonometric identities.

Given:

An equation,

8 sin26. sin34. sin60. sin86 = root3 sin78

LHS = 8 sin26. sin34. sin60. sin86

      = 0.9085192402

      ≈ 0.9 to the nearest tenth.

And RHS = 3 sin78

               = 0.89023679976

               ≈ 0.9 to the nearest tenth.

Therefore, 8 sin26. sin34. sin60. sin86 = root3 sin78.

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Answer:

Step-by-step explanation:

g(f(x)) = x2  -1 + 2 = x2 + 1

The function representing the number of bacteria present each day is f(t) = 2032[tex](0.85)^{t}[/tex].

Both the set X and the set Y are referred to as the function's domain and codomain, respectively.

Beginning in 2032, there will be a 15% daily decline in the number of microorganisms.

a function that displays the daily average amount of microorganisms.

f(x) = 2032[tex](1 - .15)^{t}[/tex]

f(x) = 2032[tex](0.85)^{t}[/tex]

Therefore f(t) = 2032[tex]0.85^{t}[/tex] is the correct answer.

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Yes , the arithmetic sequence ( written as sequences of the form (a , a+k , a+2k , a+3k for some constants a and k ) is a subspace of V .

To determine whether subsets of V in the arithmetic sequences are subspaces of V, we check if they satisfy the three conditions for a subset to be a subspace:

(i) The subset must contain the zero vector.

(ii) The subset must be closed under vector addition.

(iii) The subset must be closed under scalar multiplication.

Let S be a subset of V consisting of arithmetic sequences.

Now we check the three conditions :

(i) We find an arithmetic sequence in S that has all its terms equal to zero. The only arithmetic sequence that satisfies this is the sequence (0, 0, 0, 0, ...), which is in S.

So , the subset "S" contains zero vector.

(ii) Next we need to show that if u and v are two arithmetic sequences in S, then their sum "u + v" is also an arithmetic sequence in S.

Let U = (a, a+k, a+2k, a+3k, ...) and V = (b, b+l, b+2l, b+3l, ...) be two arithmetic sequences in S.

Then, their sum is ⇒ u+v = (a+b, a+k+b+l, a+2k+b+2l, a+3k+b+3l, ...).

This is also an arithmetic sequence,

So , subset "S" is closed under vector addition.

(iii) Next , we show that if U is an arithmetic sequence in S and C is a scalar, then CU is also an arithmetic sequence in S.

Let U = (a, a+k, a+2k, a+3k, ...) be an arithmetic sequence in S, and let c be a scalar.

we get , CU = (ca, ca+ck, ca+2ck, ca+3ck, ...) is also an arithmetic sequence,

So , subset "S" is closed under scalar multiplication.

we see that , S satisfies all three conditions, it is a subspace of V.

Therefore, any subset of V consisting of arithmetic sequences is a subspace of V.

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The given question is incomplete , the complete question is

Let V be the space of all infinite sequences of real numbers , Which of the subsets of V in The arithmetic sequences [i.e. sequences of the form (a , a+k , a+2k , a+3k for some constants a and k] are subspaces of V ?

it is not advisable to make only the minimum payment on a credit card if Jason wants to minimize the amount of interest he has to pay and pay off his debt faster.

A credit card is a payment card issued to users to enable the cardholder to pay a merchant for goods and services based on the cardholder's accrued debt.

Jason may not be doing the right thing by making only the minimum payment on his credit card, depending on the interest rate and penalty charges.

When a credit card holder makes only the minimum payment, the remaining balance accrues interest, which is added to the principal amount.

This means that the total amount owed on the credit card increases every month, even if no additional purchases are made.

The interest rate charged by the credit card company can significantly impact how much Jason ends up paying over time.

Hence, it is not advisable to make only the minimum payment on a credit card if Jason wants to minimize the amount of interest he has to pay and pay off his debt faster.

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A machine must produce a bearing that is within 0.02 inches of the correct diameter 4.1 inches. By writing this statement using absolute value notation is:

| x - 4.1 | ≤ 0.02

This notation expresses the requirement that the diameter of the bearing, represented by x, must be within 0.02 inches of the correct diameter of 4.1 inches. The absolute value of the difference between x and 4.1 must be less than or equal to 0.02 for the bearing to meet the specification.

The absolute value function is used to ensure that the difference between x and 4.1 is always positive, regardless of whether x is greater than or less than 4.1. This is important because the requirement is concerned with the magnitude of the difference, rather than its sign. If the absolute value of the difference is less than or equal to 0.02, then the diameter of the bearing is considered to be within the required tolerance.

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Experimental Probability

Just because the odds are 50% for both genders doesn't mean there is any reason for it to be even. It's like flipping a coin six times. there's no reason for it to land on tails 3 times and heads 3 times. Its just more likely

The properties are listed below.

Properties of addition and multiplication are defined for the various conditions and rules of addition and multiplication.  The properties are:

The product between any number and this one is zero. This comes from the existence of zero, which states that there must exist a value that represents nothingness, the zero.

This is the associative property of addition,

This is the reflexive property of equality, which says that every number is equal to itself.

This is the distributive property of addition which says ,

C*(A + B) = C*A + C*B

This is the inverse property of addition, this property says that for any real number x there exists a real number -x such that x+(-x)=0.

This is the symmetric property.

This is the transitive property, we can apply it in the next way

then x = z

This is the identity property of multiplication.

This is identity property of addition is that when a number n is added to zero, the result is the number itself i.e. n + 0 = n.

This is inverse property of multiplication. It states that if you multiply a number by its reciprocal, also called the multiplicative inverse, the product will be 1

Hence, the properties are identified.

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The trigonometry ratio values are tan(50) = 1.19 and cos(70) = 0.34

This can be calculated using a calculator

So, we have

tan(50) = 1.19 and cos(70) = 0.34

This can be calculated using a calculator

So, we have

sin(84) = 0.9945 and tan(75) = 3.7321

Here, we make use of the laws of cosines and sines

So, we have

cos(X) = 15/17 = 0.8824

sin(C) = 36/45 = 0.8

Here, we make use of the laws of tangents and sines

So, we have

tan(?) = 6/13 = 0.4615

? = 24.77

sin(?) = 41/59 = 0.6949

? = 44.01

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Answer:28

Step-by-step explanation: because add z and x

The interquartile range of the data is

The interquartile range (IQR) is a measure of variability in a dataset that is calculated as the difference between the third quartile (Q3) and the first quartile (Q1).

The IQR is the range of the middle 50% of the data, and it provides a measure of the spread of the central part of the distribution.

From the given information, we have:

Minimum value = 4

Q1 = 11

Median = 14

Q3 = 16

Maximum value = 20

To find the IQR, we subtract Q1 from Q3:

IQR = Q3 - Q1 = 16 - 11 = 5

Therefore, the interquartile range of the data is 5.

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The value of the game is equal to -20 and is the least loss for ABC (which is the maximum gain for XYZ).

The Minimax theorem, which states that in a two-person zero-sum game, each player minimizes the maximum loss conceivable, can be used to determine the best course of action for both stores.

ABC retailer:

If XYZ decides to use newspaper advertising, ABC could see a maximum loss of -80.

If XYZ chooses radio advertising, ABC might lose as much as -20.

If XYZ chooses television advertising, ABC will ultimately lose 50.

As a result, selecting the advertising medium that results in the lowest possible loss, which is radio advertising with a loss of -20.

XYZ retailer:

If ABC chooses newspaper advertising, XYZ might earn up to 40.

If ABC chooses radio advertising, XYZ might earn a maximum of 15.

If ABC chooses television advertising, XYZ might earn up to $20.

Therefore, by selecting the advertising medium that offers the highest possible gain, which is newspaper advertising with a gain of 40, XYZ optimizes the greatest gain.

Therefore, the value of the game is equal to -20 and is the least loss for ABC (which is the maximum gain for XYZ).

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Correct question:
In a small town, there are two discount stores ABC and XYZ. They are the only

stores that handle the festival goods. The total number of customers is equally divided

between the two because the price and quality of goods sold are equal. Both stores

have good reputations in the community, and they render equally good customer

services. Assume that a gain of customer by ABC is a loss to XYZ and vice versa.

Both stores plan to run annual pre-Christmas sale during the first week of December.

Sales are advertised through the local newspaper, radio and television media. With the

aid of advertising the payoff for ABC store is constructed and given below.

XYZ store

News paper radio Television

News paper 30 40 -80

ABC radio 0 15 -20

Television 90 20 50

Find optimal strategies for both stores and the value of the game.

On average, ABC can expect to earn 15 more customers than XYZ during the pre-Christmas sale.

In mathematics and computer science, a graph is a collection of points (called vertices or nodes) that are connected by lines or curves (called edges). Graphs can be used to represent many different types of relationships or structures, including social networks, transportation networks, electrical circuits, and mathematical functions.

A graph is usually represented visually as a set of points on a plane or in space, with lines or curves connecting them. The points can represent any type of object or entity, such as cities, people, or data points, while the edges represent the connections or relationships between them. Edges can be directed (with arrows indicating a one-way relationship) or undirected (with no preferred direction).

To find the optimal strategies for both stores and the value of the game, we can use the graphical method of solving 2-player zero-sum games.

First, we can create a payoff matrix using the given information:

markdown

Copy code

     |  Newspaper |  Radio  | Television |

--------------------------------------------

ABC   |     30     |    15   |     20     |

XYZ   |     40     |   -15   |     50     |

Note that the payoff for XYZ in the radio column is negative, indicating a loss.

Next, we can plot the payoffs on a graph, with ABC's strategies on the x-axis and XYZ's strategies on the y-axis. We can also draw a line at the minimum value of each column (the "minimax" line) and a line at the maximum value of each row (the "maximin" line).

The graph should look like this:

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           -15      15       20

             |-------|--------|

         30  |   30  |   15   |

             |       |        |

             |-------|--------|

         50  |   40  |  -15   |

             |       |        |

             |-------|--------|

               40       50

To find the optimal strategies, we need to find the intersection of the minimax and maximin lines. In this case, the intersection is at the point (Radio, Television) = (15, 50), so the optimal strategies are for ABC to advertise on the radio and XYZ to advertise on television.

The value of the game is the payoff at the intersection of the minimax and maximin lines, which is 15. This means that on average, ABC can expect to earn 15 more customers than XYZ during the pre-Christmas sale.

To know more about intersection  visit:

https://brainly.com/question/14217061

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Answer:

there are 1456 different ways that the six medals can possibly be given out.

Step-by-step explanation:

There are different ways to approach this problem, but one common method is to use combinations.

First, we need to determine how many ways we can choose three girls out of 14, and three boys out of 4. This can be calculated using combinations:

Number of ways to choose 3 girls out of 14: C(14,3) = 364

Number of ways to choose 3 boys out of 4: C(4,3) = 4

Now, we can use the multiplication principle to determine the total number of ways to give out the six medals:

Total number of ways = number of ways to choose 3 girls * number of ways to choose 3 boys = 364 * 4 = 1456

Therefore, there are 1456 different ways that the six medals can possibly be given out.