which of the following statements about the car's motion is true?​

Answer: It's a 80% increase

Step-by-step explanation:

The slope of the secant line joining (2, f(2)) and (7, f(7)) is 8.6.

Rise over run is the definition of a line's slope. A curve's secant line is a line that connects any two of its points. The slope of the secant line would change to the slope of the tangent line at the point when one of these points approaches the other. As a secant line is also a line, we may calculate its slope using the slope of a line formula.

The two points on the secant line are given as (2, f(2)) and (7, f(7)).

Substituting the values in the function we have:

f(x) = x² + 8x

f(2) = 2² + 8(2) = 20

f(x) = x² + 8x

f(7) = 7² + 8(7) = 63

Using the difference quotient the slope of the line is:

(f(7) - f(2)) / (7 - 2) = (63 - 20) / 5 = 8.6

Hence, the slope of the secant line joining (2, f(2)) and (7, f(7)) is 8.6.

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Answer:

I don't knowI am sorry I will let someone else answer

Step-by-step explanation:

The equation can be rearranged to the form y = -qx + r. This is the equation of a straight line, which can be graphed. The point of intersection of the two lines, ak + bl = 0 and y = -qx + r, is the solution for the two variables (k and l).

The equation ak + bl = 0 is a linear equation in two variables and is solved using the method of elimination. The equation can be written in the form ax + by = c, where a, b, c are constants. To solve this equation, both sides of the equation should be divided by the coefficient of one of the variables (a or b). This will result in a equation of the form x + qy = r, where q and r are constants. Then, the equation can be rearranged to the form y = -qx + r. This is the equation of a straight line, which can be graphed. The point of intersection of the two lines, ak + bl = 0 and y = -qx + r, is the solution for the two variables (k and l). The two variables can then be calculated using the point of intersection by substituting the x and y values into the two equations. In this way, the two variables k and l can be found such that ak + bl = 0.

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What are the integers k and l such that ak + bl = 0?

Answer:

We can solve for the unknown whole number by using the formula:

Dividend = Divisor × Quotient + Remainder

In this case, the dividend is z, the divisor is 19, the quotient is the unknown whole number, and the remainder is 16. We can substitute these values into the formula and solve for the unknown whole number:

z = 19 × Quotient + 16

To isolate the variable (Quotient), we can subtract 16 from both sides:

z - 16 = 19 × Quotient

Then, we can divide both sides by 19 to solve for Quotient:

Quotient = (z - 16) ÷ 19

Therefore, the unknown whole number is (z - 16) ÷ 19.

Answer:

To shift the graph of f(x) = |x| to have a domain of [-3, 6], we need to move the left endpoint from -6 to -3 and the right endpoint from 3 to 6.

A translation to the right by 3 units will move the left endpoint of the graph of f(x) to -3, but it will also shift the right endpoint to 6 + 3 = 9, which is outside the desired domain.

A translation to the left by 3 units will move the right endpoint of the graph of f(x) to 3 - 3 = 0, which is outside the desired domain.

A translation upward or downward will not change the domain of the graph, so options B and D can be eliminated.

Therefore, the correct answer is C g(x) = x - 3. This translation will move the left endpoint to -3 and the right endpoint to 6, which is exactly the desired domain.

Answer:

We need to find dz/dt given:

z = cos(x + 8y), x = 7t^5, y = 5/t

Using the chain rule, we can find dz/dt by taking the derivative of z with respect to x and y, and then multiplying by the derivatives of x and y with respect to t:

dz/dt = dz/dx * dx/dt + dz/dy * dy/dt

First, let's find dz/dx and dz/dy:

dz/dx = -sin(x + 8y)

dz/dy = -8sin(x + 8y)

Now, let's find dx/dt and dy/dt:

dx/dt = 35t^4

dy/dt = -5/t^2

Substituting these values, we get:

dz/dt = (-sin(x + 8y)) * (35t^4) + (-8sin(x + 8y)) * (-5/t^2)

Simplifying this expression, we get:

dz/dt = -35t^4sin(x + 8y) + 40sin(x + 8y)/t^2

Substituting x and y, we get:

dz/dt = -35t^4sin(7t^5 + 40/t) + 40sin(7t^5 + 40/t)/t^2

Therefore, dz/dt is given by -35t^4sin(7t^5 + 40/t) + 40sin(7t^5 + 40/t)/t^2.

Answer:

It looks like there might be a typo in the expression given. Assuming that "J" and "K" are just placeholders, we can write the expression as:

f(n) = 45 * |4 - 5(n-1)|

To find the recursive formula for this sequence, we need to determine how each term relates to the previous term. We can start by looking at the first few terms of the sequence:

f(1) = 45 * |4 - 5(1-1)| = 45 * |4 - 5(0)| = 45 * |4| = 180

f(2) = 45 * |4 - 5(2-1)| = 45 * |4 - 5(1)| = 45 * |-1| = 45

f(3) = 45 * |4 - 5(3-1)| = 45 * |4 - 5(2)| = 45 * |-6| = 270

From this, we can see that the sign of the expression inside the absolute value changes with each term, alternating between positive and negative. Furthermore, the magnitude of this expression increases by 5 with each term. We can use these observations to write the recursive formula:

f(1) = 180

f(n) = f(n-1) + (-1)^(n-1) * 5 * 45 for n >= 2

This formula says that the first term in the sequence is 180, and each subsequent term is found by adding or subtracting 225 (5 * 45) from the previous term, depending on whether n is odd or even.

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The quadrilaterals which have both line and rotational symmetry of order more than 1 are square, and rhombus

Symmetry is a fundamental concept in mathematics and geometry. It refers to the property of a shape that remains unchanged when it is transformed in a certain way.

Now, let's talk about quadrilaterals that have both line and rotational symmetry of order more than 1. One example of such a quadrilateral is a square.

Another example of a quadrilateral with both line and rotational symmetry of order more than 1 is a rhombus. A rhombus is a type of quadrilateral where all four sides are equal in length, and opposite angles are equal.

In summary, a square and a rhombus are examples of quadrilaterals that have both line and rotational symmetry of order more than 1.

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Complete Question:

Name the quadrilaterals which have both line and rotational symmetry of order more than 1.

Part A. The probability pf drawing a purple card out of the hat is 28%.

Part B. The experimental probability is 2% greater than the theoretical probability.

The probability that a specific event will occur is known as probability. The ratio of favourable outcomes to all other possible outcomes serves as a stand-in for the likelihood that an event will occur.

In numerous disciplines, including mathematics, statistics, physics, economics, and computer science, uncertain events are described and understood using probability theory. It is used to analyse risks, make decisions, and forecast events.

Now in the given question,

Total cards in the hat = 12 + 17 + 14 + 7 = 50 cards

Total purple cards in the hat = 14

Probability of getting a purple card from the hat = 14/50

= 0.28

= 28%

Now similarly for the experiment,

Probability = 324/1080

= 0.3

= 30%

Therefore, the experimental probability is 30% - 28% = 2% greater than the theoretical probability.

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The probability of a pitcher throwing exactly 5 pitches in an at-bat is 0.1 or 10%.

What is probability and how is it calculated?

Probability is a measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, where 0 indicates that the event is impossible and 1 indicates that the event is certain. The probability of an event A is calculated as the ratio of the number of outcomes that correspond to event A to the total number of possible outcomes.

Calculating probability of a pitcher throwing exactly 5 pitches :

To calculate the probability of a pitcher throwing exactly 5 pitches in an at-bat, we need to add up the frequencies of all the at-bats that have exactly 5 pitches. From the given table, we see that there are 8 at-bats that have exactly 5 pitches.

The total number of at-bats is the sum of the frequencies of all pitch counts.

Total number of at-bats = 12+16+32+12+8 = 80

Therefore, the probability of a pitcher throwing exactly 5 pitches in an at-bat is:

P(5) = Frequency of 5-pitch at-bats / Total number of at-bats

P(5)= 8/80 = 0.1 or 10%

Hence, the probability that a pitcher will throw exactly 5 pitches in an at-bat is 10%.

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The value of length of side g using the  similar triangles is found as 20 ft.

In the given figures:

DC || EA

So,

∠D = ∠A

∠C = ∠E

By Angle -Angle similarity both triangles are similar.

Thus,

Taking the ratios of their side, it will be also equal.

EA / DC = EB / BC

5 / 10 = g / 10

g = 10*10 / 5

g = 100 / 5

g = 20

Thus, the value of length of side g using the  similar triangles is found as 20 ft.

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The value of expression 40 divided by 160000 would be equal to 0.00025

When 'a' is divided by 'b', then the result we get from the division is part of 'a' that each one of 'b' items will get. Division can be interpreted as equally dividing the number that is being divided into total x parts, where x is the number of parts the given number is divided.

We need to find the expression of 40 divided by 160000

A negative divided by a negative is positive, then

40÷160000 = 0.00025

Therefore, The value of 40 divided by 160000 is; 0.00025

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Answer:

Let's start by setting up an equation to represent the problem. Let x be the cost of the meal:

x + 0.1x = 126.50

Simplifying the left side of the equation:

1.1x = 126.50

Dividing both sides by 1.1:

x = 115

Therefore, the cost of the meal was £115.

The position of the particle moving in the x-y plane is given by the parametric functions x(t) and y(t), where = t sin(n t'') and (3t+1). The position of the particle is (2) , 7) at time t = 3.

In mathematics, a parametric equation defines a set of quantities as a function of one or more independent variables called parameters. [1] Parametric equations are often used to represent the coordinates of points that constitute geometric objects such as curves or surfaces, called respectively parametric curves and parametric surfaces. In this case, the equations are collectively referred to as the object's parametric representation or parameter system or parametrization (or orthographic parametrization)

The velocity of the particle is zero at t = 1 second

v(x) = dx/dt

     = d/dt (3t²- 6t)

     = 6t−6.

At t = 1, v(x) = 0

v(y) =dy/dt

     = d/dt (t²−2t)

     =2t−2.

At t=1,

v(y) = 0

Hence v = [tex]\sqrt{v_x^2 + v_y^2}[/tex]  = 0

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Therefore, the expression [tex]\frac{7}{Tanb} +7Tanb[/tex] is equivalent to function. [tex]7*secb*cscb[/tex].

Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. It includes the study of trigonometric functions such as sine, cosine, tangent, cotangent, secant, and cosecant, as well as their properties and applications.

Trigonometry is useful in a wide range of fields, including engineering, physics, navigation, astronomy, and surveying. It is often used to solve problems involving triangles, such as determining the height of a tall object, finding the distance between two points, or calculating the trajectory of a moving object.

The origins of trigonometry can be traced back to ancient civilizations such as the Babylonians, Greeks, and Indians, who developed various methods for calculating angles and distances. Today, trigonometry is an important part of mathematics education and continues to be used extensively in many fields of study.

Given by the question.

To simplify the expression 7/tan b + 7 tan b, we need to first recall the following trigonometric identity:

tan(x) * cot(x) = 1

Using this identity, we can rewrite the expression as:

[tex]\frac{7}{Tanb} +7Tanb[/tex]

= [tex]\frac{7}{Tanb} +7Tan^{2} b*cotb\\[/tex]

=[tex]\frac{7}{Tanb} +7*(sin^{2}/cos^{2}b)*(cosb/sinb)[/tex]

= [tex]\frac{7}{Tanb} +7*(cosb/sinb)[/tex]

= [tex]7*(1/tanb+sinb/cosb[/tex]

[tex]=7*(cosb/sinb+sinb/cosb)\\=7*((cos^{2}b+sin^{2}b)/(sinb/cosb))\\ =7*(1/(sinb/cosb))\\=7*secb*cscb[/tex]

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The Dcpromo wizard will guide you through e. All of the above installation scenarios

A utility in Active Directory called DCPromo (Domain Controller Promoter) installs and uninstalls Active Directory Domain Services and promotes domain controllers. Since Windows 2000, every version of Windows Server contains DCPromo, which creates forests and domains in Active Directory. It works with Windows Server and houses all network resources as a centralised security management solution.

The functionality aids in building a completely new forest structure. It allows for both the addition of a new domain tree to an existing forest and the addition of a child domain to an existing domain. Additionally, it degrades the domain controllers and ultimately deletes a domain or forest.

Complete Question:

The dcpromo wizard will guide you through which of the following installation scenarios? [check all that apply]

Creating an entirely new forest structure.

Adding a child domain to an existing domain.

Adding a new domain tree to an existing forest.

Demoting domain controllers and eventually removing a domain or forest

All of the above

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Answer:

resultant force

Step-by-step explanation:

the body will move to the direction where greater force is applied

The derivative of S(t)= 1+e −t is  S'(t) = S(t)(1 - S(t)). So, the correct answer is (iii).

To find S'(t), we can use the chain rule:

S'(t) = (d/dt) [1 + e^(-t/2)]^-2 * d/dt [1 + e^(-t/2)]

Using the chain rule again for the second derivative:

d/dt [1 + e^(-t/2)] = (-1/2)e^(-t/2)

d/dt [1 + e^(-t/2)]^-2 = -2(1 + e^(-t/2))^-3 * (-1/2)e^(-t/2) = (1/2) e^(-t/2) / (1 + e^(-t/2))^3

Substituting into the expression for S'(t), we have:

S'(t) = [(1/2) e^(-t/2) / (1 + e^(-t/2))^3] * [1 - (1/2)e^(-t/2)]

S'(t) = (1/2) e^(-t/2) / (1 + e^(-t/2))^3 * [2 - e^(-t/2)]

S'(t) = e^(-t/2) / (1 + e^(-t/2))^3 * [2 - e^(-t/2)]

Taking the derivative of S(t), we have:

S'(t) = e^(-t/2) / (1 + e^(-t/2))^2

Comparing this to the given choices, we can see that:

S'(t) = S(t) is not true, since S(t) = 1 + e^(-t/2) and S'(t) is a different function.

S'(t) = (S(t))^2 is not true, since (S(t))^2 = (1 + e^(-t/2))^2 is a different function from S'(t).

S'(t) = S(t)(1 - S(t)) is true, since we can substitute S(t) and S'(t) from above and simplify:

S'(t) = e^(-t/2) / (1 + e^(-t/2))^3 * [2 - e^(-t/2)]

S(t)(1 - S(t)) = [1 + e^(-t/2)] * [1 - (1 + e^(-t/2))] = e^(-t/2) / (1 + e^(-t/2))

Therefore, S'(t) = S(t)(1 - S(t)) is true.

S'(t) = -S(-t) is not true, since S(-t) = 1 + e^(t/2) and -S(-t) is a different function from S'(t).

So the correct choice is (iii): S'(t) = S(t)(1 - S(t)).

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Answer:

Step-by-step explanation:

x= 0.45

Answer: 0.45 L of sparkling water

Step-by-step explanation:

1.65 - 0.2 = 1.45  

1.9 - 1.45 = 0.45

0.45 L of sparkling water

Answer:

I HOPE ITS HELPFUL

Step-by-step explanation:

Cost price of 300 articles = ₹1500Hence cost of each item = 1500/300 = ₹5With 20% profit, selling price of each item = 5 * 120/100 = ₹6Hence, total selling price of 260 items = 260 * 6 = ₹1560Selling price of balance items = 6/2 = ₹3Total selling price for balance items = 40 * 3 = ₹120Total selling price = 1560 + 120 = ₹1680Profit gained = 1680 - 1500 = ₹180Profit percentage = 180/1500 * 100 = 12

The equation of the tangent line to the curve at the point (2,4) is y = (-1/2)x + 5.

To use implicit differentiation to find an equation of the tangent line to the curve at the given point (2,4), we need an implicit equation of the curve. Let's assume the curve is given by the equation:

x² + y² = 16

We can use implicit differentiation to find the slope of the tangent line at any point on this curve. Taking the derivative of both sides with respect to x, we get:

2x + 2y (dy/dx) = 0

Simplifying for (dy/dx), we get:

dy/dx = -x/y

Now we can substitute the given point (2,4) into this equation to find the slope of the tangent line at that point:

dy/dx = -2/4 = -1/2

So the slope of the tangent line at (2,4) is -1/2. We can use this slope and the point-slope form of the equation of a line to find an equation of the tangent line. The point-slope form is:

y - y1 = m(x - x1)

where m is the slope and (x1, y1) is the given point. Substituting the values, we get:

y - 4 = (-1/2)(x - 2)

Simplifying, we get:

y = (-1/2)x + 5

Therefore, the equation of the tangent line to the curve at the point (2,4) is y = (-1/2)x + 5.

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Complete question:

Use implicit differentiation to find an equation of the tangent line to the curve at the given point (2,4)

By using the partial quotients method 1032/32 = 32 R8.

In mathematics, an expression is a combination of numbers, symbols, and operators that represents a mathematical quantity or relationship. It can be a single number, a variable, or a combination of both, and can also include mathematical operations such as addition, subtraction, multiplication, division, exponents, and roots. Expressions can be evaluated or simplified using mathematical rules and formulas.

Step 1: Estimate how many times 32 goes into 1032. It's helpful to find a multiple of 32 that is close to 1032. In this case, 32 x 30 = 960, which is less than 1032, and 32 x 31 = 992, which is greater than 1032. So we can estimate that 32 goes into 1032 around 30 to 31 times.

Step 2: Write 30 on top of a division symbol, and multiply 30 by 32. Write the result, 960, under 1032, and subtract.

    30

 -------

32|1032

   960

  ------

    72

Step 3: Write 72 next to the 30 on top of the division symbol. Then, add 72 to the partial quotient (30) to get 102. Write 102 under the partial difference (72) and bring down the next digit, which is 2.

    30  72

 -------

32|1032

   960

  ------

    72  

    64  

  ------

     8  

step 4: Estimate again how many times 32 goes into the new partial difference, 82. Since 32 x 2 = 64 is less than 82 and 32 x 3 = 96 is greater than 82, we estimate 32 goes into 82 two to three times.

Step 5: Write 2 on top of the division symbol, and multiply 32 by 2. Write the result, 64, under 82, and subtract.

    30  72  2

 ------------

32|1032

   960

  ------

    72  

    64  

  ------

     8  

tep 6: Write 2 next to the 30 and 72 on top of the division symbol, and add 2 to the partial quotient to get 32. Write 32 under the partial difference and bring down the next digit, which is 0.

    30  72  2

 ------------

32|1032

   960

  ------

    72  

    64  

  ------

     8  

     0  

Step 7: Since there are no more digits to bring down, we have the final answer. The quotient is 32 with a remainder of 8. Therefore, 1032 divided by 32 is equal to 32 with a remainder of 8.

Therefore, by using the partial quotients method 1032/32 = 32 R8 .

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The equation of the bird's height above the water as a function of time can be expressed as:

H(t) = A * sin (B * t + C) + D

Where:

A is the amplitude, which is the difference between the maximum and minimum

B is angular frequency (2πf)

C is the phase shift

D is the midline

The maximum height is 112 ft and the minimum height is 14 ft, so A = 98ft.

The frequency of the cycle is 4 seconds (1 cycle every 4 seconds).

Therefore, the angular frequency is 2π/4 = π/2

The bird was at maximum height of 112 ft at t=4s, so the phase shift C = 0.

The midline is the average of the maximum and minimum, so D = (112+14)/2 = 63 ft.

Therefore, the equation of the bird's height above the water as a function of time is:

H(t) = 98 * sin (π/2 * t + 0) + 63

Answer:

see step by step

Step-by-step explanation:

He can spin a lot of times the wheel, Notice IF THE SPINNER IS FAIR the probability must be equally, since the spinner have 4 options it must have 0.25 (25%) probability in each of the colors. Of course, since the probability is random the theoretically probability need to be closer to 0.25 for each one, to evade the randomness Klevon can spin the spinner a lot of times.


(for example, if he spins 100 times, he can get 28, 31, 25 and 20 and the spinner can still be fair, he can spin another 100 times to see the results, but if he have 5,5,80, 5 in the results, the probability is really low of this happening, so its probability unfair, but still, posible)

Answer:

the answer is 12/13 simplified

Step-by-step explanation:

simplified

10√10 is the dimensions of a rectangle with area 1,000 m² whose perimeter is as small as possible.

a. The smaller value is 10√10 m.

b. The larger value is 10√10 m.

We have to determine the dimensions of a rectangle with area 1,000 m² whose perimeter is as small as possible.

P = 2w + 2L

1000 = Lw

P = 2w + 2(1000/w)

P = 2w + 2000/w

P-prime = 2 -2000/w²

0 = 2 - 2000/w²

Add 2000/w² on both side, we get

2000/w² = 2

Multiply by w² on both side, we get

2000 = 2w²

Divide by 2 on both side

w² = 2000/2

w² = 1000

Taking square root on both side, we get

w = 10√10

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Step-by-step explanation:

i)

A = {2, 3, 5, 7}

as "1" can only be divided by one number (instead of the usual 2 numbers for prime numbers), if it's not part of that set.

out of U = {1, 2, 3, 4, 5, 6, 7, 8}

B = {1, 3, 5}

I am not sure what you mean by "y E 7".

I don't think you mean the E7 algebraic group.

I decided you mean y <> 7 (not equal to 7).

ii)

A u B (united) = {1, 2, 3, 5, 7}

A n B (elements in common) = {3, 5}

iii)

a set with n elements has 2^n subsets and (2^n) - 1 proper subsets (all subsets minus the equal one).

our U here has 8 elements, so the number of subsets is

2⁸ = 256.

the number of relations from A to B is 2^|A×B| = 2^(|A|·|B|).

|A| = 4

|B| = 3

so the number of relations from A to B are

2^(4×3) = 2¹² = 4096

remember, for the number of possible relations we have 4×3 = 12 possible combinations of elements of A and engender of B.

each of these combinations can be in the set of relations or not, which gives us 2 options per combination.

that gives us 2¹² relations.

the coordinates of point P are ((Ax + Bx) / 2, (Ay + By) / 2).

How to find?

If we want to find the coordinates of point P on the directed line segment from A to B such that P is the length of the line segment from A to B, we can use the following formula:

P = (1 - t)A + tB

where A and B are the coordinates of the two endpoints of the line segment, t is a scalar between 0 and 1, and P is the coordinates of the point we are trying to find.

When t = 1, we get the coordinates of point B, and when t = 0, we get the coordinates of point A. When t is between 0 and 1, we get a point on the line segment from A to B.

To find the point P that is the length of the line segment from A to B, we set t = 1/2, which gives us:

P = (1 - 1/2)A + (1/2)B

= (1/2)A + (1/2)B

So the coordinates of point P are the average of the coordinates of A and B:

Px = (Ax + Bx) / 2

Py = (Ay + By) / 2

where (Ax, Ay) and (Bx, By) are the coordinates of points A and B, respectively.

Therefore, the coordinates of point P are ((Ax + Bx) / 2, (Ay + By) / 2).

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Complete Question:

What are the Cartesian coordinates of point P on the directed line segment from point A to point B such that point P is located at a distance equal to the length of the line segment from point A to point B?