Which of the following is true about sound waves?
1:they move faster than light
2:they make wind
3:the vibrate the air
4: they move slower in water than air

Answer:

The value is  [tex]T = 1702.91 \ N[/tex]  

Explanation:

From the question we are told that

   The mass of the laser sensor is  [tex]m = 137 \ kg[/tex]

    The horizontal acceleration of the helicopter and the sensor is  [tex]a = 2.63 \ m/s^2[/tex]

Generally the net force on the cable is              

[tex]F = T - W = ma[/tex]

    Here W  is the weight of the sensor  which is evaluated as [tex]W = m * g = 137 * 9.8 = 1342.6 \ N[/tex]

     So

     [tex]T - 1342.6 = 137 * 2.63[/tex]

=>   [tex]T = 360.31 + 1342.6[/tex]  

=>   [tex]T = 1702.91 \ N[/tex]  

Answer:

  48 ft/s

Explanation:

Acceleration due to gravity decreased the upward velocity to zero in 1.5 seconds (half the total time), so the initial velocity must have been ...

  (32 ft/s^2)(1.5 s) = 48 ft/s

Explanation:

The beat is a word used for sound waves. The beat frequency is the difference in frequency of two waves. ... In sound, we hear said beat frequency as the rate at which the loudness of the sound varies whereas we hear the ordinary frequency of the waves as the pitch of the sound.

Explanation:

Beats :--

A wave not only travels in space but it also propagates through time, so if the two waves can produce interference by overlapping in space they should also produce an interference pattern when they overlap in time, this phenomenon is called beats.

Beat Frequency :--

The beat frequency is when two sound waves with different frequencies come across each other, then their amplitude gets added and subtracted alternatively for a given time period. This leads to the growth of the sound to louder and softer.

There would be two forces acting on the box parallel to the floor, with a net force of

∑ F = p - f = m a

where p = magnitude of the push, f = mag. of friction, m = mass of the box, and a = acceleration. To find p, we first need f .

There are also only two forces acting on the box perpendicular to the floor, with net force

∑ F = n - w = 0

where n = mag. of normal force of the floor on the box and w = weight of the box. The net force is 0 because the box is only accelerating parallel to the floor.

w = m g, where g = 9.8 m/s² is the mag. of the acceleration due to gravity, so we can solve for n :

n = w = m g

n = (22 kg) (9.8 m/s²)

n = 215.6 N

The kinetic friction is proportional to the normal force by a factor of the given coefficient of friction, µ = 0.17, such that

f = µ n

f = 0.17 (215.6 N)

f = 36.652 N

Now solve for the required pushing force:

p - 36.652 N = (22 kg) (1.9 m/s²)

p ≈ 78 N

Answer:

0

Explanation:

Answer:

length=2

Explanation:

You simply find the zeros of the quartic polynomial

The factored form is (x+1)(x-5)(x-2)=0

The zeros become -1,5 and 2

Dimension 5 is already given and the question says length>width and 2>-1

Therefore length=2

Answer:

The maximum height it reaches will be 20 m.

The time taken by it to reach the height will be: t = 2 seconds.

Explanation:

We know the equation of the motion under gravity

v² - u² = 2gs

u = initial velocity = 20 m/s

v = final velocity = 0 m/s

[tex]s\:=\:h_{max}[/tex]

so

[tex]v^{2} \:-\:u^{2} \:=\:2gs[/tex]

substituting u = 20 m/s, v = 0 m/s, g = -10 and [tex]s\:=\:h_{max}[/tex]

[tex]\left(0\right)^2-\:\left(20\right)^2=\:2\left(-10\right)\times h_{max}[/tex]

[tex]2\left(-10\right)\times h_{max}=-400[/tex]

[tex]\frac{2\left(-10\right)h_{max}}{-20}=\frac{-400}{-20}[/tex]

[tex]\:h_{max}=20[/tex] m

Therefore, the maximum height it reaches will be 20 m.

We know the equation

u = gt

substitute u = 20, g = 10

20 = 10 × t

t = 20/10

t = 2 seconds

Therefore, the time taken by it to reach the height will be: t = 2 seconds.

Answer:

The answer is True.

Answer:

22236 mi

Explanation:

Answer:

Quantity with direction and magnitude

Displacement

Explanation:

Answer:

B.

Explanation:

Intrusive and extrusive rocks are igneous rocks and marble is metamorphic, by the process of elimination, B would be the correct answer.

Answer:

answer is B

Explanation:

Answer:Moon phases are determined by the relative positions of the Moon, Earth, and Sun.

Explanation:

Instead, the Moon's phase depends only on its position relative to Earth and the Sun. The Moon doesn't make its own light, it just reflects the Sun's light as all the planets do.

Answer:

45C in a minute is

45/60 C in a second

.75 C in a second is 3/4 of an ampere.

Explanation:

The current through a circuit when it takes one minute for 45C of charge to pass to a point in an electric circuit is 0.75 Ampere.

The electric circuit: a way for current to travel. A battery or generator is a device that provides energy to the charged particles that make up the current, a device that uses current, such as a lamp, an electric motor, or a computer, and the connecting wires or transmission lines to make up an electric circuit. Ohm's law and Kirchhoff's rules are two fundamental laws that quantitatively define how electric circuits function.

Given information,

The charge, q = 45 coulombs,

the time, t =1 minute

t = 60 sec

A minute at 45C is, In one second, 45/60 C,3/4 of an ampere is equal to 0.75 C per second.

Therefore, the current through a circuit when it takes one minute for 45C of charge to pass to a point in an electric circuit is 0.75 Ampere.

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Answer:

light bulb

Explanation:

The answer Is kilometers

Answer:

The rate of heat transfer of the second object is greater than the first object.

Explanation:

[tex]\varepsilon[/tex] = Emissivity of the object

[tex]\sigma[/tex] = Stefan-Boltzmann constant = [tex]5.67\times 10^{-8}\ \text{W/m}^2/\text{K}^4[/tex]

[tex]T_1[/tex] = Temperature of surface 1 = [tex]25^{\circ}\text{C}+273.15=298.15\ \text{K}[/tex]

[tex]T_2[/tex] = Temperature of surface 2 = [tex]40^{\circ}\text{C}+273.15=313.15\ \text{K}[/tex]

[tex]T_0[/tex] = Surrounding temperature = [tex]25^{\circ}\text{C}+273.15=298.15\ \text{K}[/tex]

Rate of heat transfer is given by

[tex]P_1=\varepsilon \sigma (T_1^4-T_0^4)\\\Rightarrow P_1=\varepsilon \sigma A_1(298.15^4-298.15^4)\\\Rightarrow P_1=0\ \text{W}[/tex]

[tex]P_2=\varepsilon \sigma (T_2^4-T_0^4)\\\Rightarrow P_2=\varepsilon 5.67\times10^{-8} A_2(313.15^4-298.15^4)\\\Rightarrow P_2=\varepsilon A_297.2[/tex]

[tex]\varepsilon A_297.2>0[/tex]

So, [tex]P_2>P_1[/tex]

Hence, the rate of heat transfer of the second object is greater than the first object.

Answer:

1306.67 s

Explanation:

From the question given above, the following data were obtained:

Volume of water = 70 L

Power (W) = 18000 w

Specific heat capacity (C) = 4200 J/g℃

Initial temperature (T1) = 20 ℃

Final temperature (T2) = 100 ℃

Time (t) =?

Next, we shall determine the mass of the water. This can be obtained by converting 70 L to kg. This is illustrated below:

1 L = 1 kg

Therefore,

70 L = 70 Kg

Thus, the mass of the water is 70 kg.

Next, we shall determine the heat energy involved. This is can be obtained as follow:

Mass (M) of water = 70 Kg

Specific heat capacity (C) = 4200 J/g℃

Initial temperature (T1) = 20 ℃

Final temperature (T2) = 100 ℃

Heat Energy (Q) =?

Q = MC(T2 – T1)

Q = 70 × 4200 × (100 – 20)

Q = 294000 × 80

Q = 3520000 J

Thus, the heat energy involved is 3520000 J

Finally, we shall determine the time taken.

Power (W) = 18000 w

Heat Energy (Q) = 3520000 J

Time (t) =?

Power = energy / time

18000 = 3520000 / time

Cross multiply

18000 × time = 3520000

Divide both side by 18000

Time = 3520000 / 18000

Time = 1306.67 s

Answer:

If lone pairs of electrons, electrons not bonded to other atoms, are located in the molecule, this will change the molecular geometry, not the electron geometry. If all the electron groups are bonded, with no lone pairs, then the electron geometry and molecular geometry are the same.

Answer:  c or b

Explanation:

Answer:

20metere

Answer:

210 m/s

Explanation:

We will use this equation for an elastic collision:

In this case, m₁ = mass of golf ball (0.046 kg) and m₂ = mass of the golf club (0.22 kg).

v₁ is 0 m/s since the ball is at rest on the tee.

v₂ is 44 m/s, given in the problem.

v₁ is what we are trying to find.

v₂ is 0 m/s since the ball will be at rest on the ground.

Plug these values into the elastic collision equation:

Simplify this equation.

Get rid of the units.

Multiply the left side of the equation.

Divide both sides by 0.046.

The speed of the ball when it leaves the tee is about 210 m/s.

Answer:

its B

Explanation:

the movement of charged particles in a conductor

Charged particles move through a conductor best describes an Electric current.

A stream of charged particles, such as electrons or ions, traveling through an electrical conductor or a vacuum is known as an electric current.

Charge carriers, which can be any of a number of particle kinds depending on the conductor, are the moving particles. Electrons flowing over a wire are frequently used as charge carriers in electric circuits.

They can be electrons or holes in semiconductors. Ions are the charge carriers in an electrolyte, whereas ions and electrons are the charge carriers in plasma, an ionized gas.

Therefore, Charged particles move through a conductor best describes an Electric current.

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Explanation:

Most waves appear complex because they result from two or more simple waves that combine as they come together at the same place at the same time—a phenomenon called superposition. Waves superimpose by adding their disturbances; each disturbance corresponds to a force, and all the forces add

introurself please

Answer:

500ms times 2 would be when the ball reaches the max horizontal distance.

Then to find the angle, use the formula of time to reach max height t = u sin theta / g . With t being the max height time 500ms, u being 10m/s

For initial vertical velocity just use u sin theta.

The max horizontal height is "10 meters" and the initial vertical velocity is "4.9 m/s".

Given:

Horizontal velocity,

Time,

At max height,

(a)

→ Time to flight (T) will be:

= [tex]2t[/tex]

= [tex]2\times 0.5[/tex]

= [tex]1 \ second[/tex]

→ Horizontal distance will be:

= [tex]V_x\times T[/tex]

= [tex]10\times 1[/tex]

= [tex]10 \ meters[/tex]

(b)

→ The initial vertical velocity will be:

[tex]V_{yf} = V_y +gt[/tex]

   [tex]0 = V_y - 9.8\times 0.5[/tex]

  [tex]V_y = 4.9 \ m/s[/tex]

Thus the above answers are correct.

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Answer:

120V

Explanation:

Given parameters:

Current  = 6A

Resistance  = 20Ω

Unknown:

Voltage = ?

Solution:

According to ohms law;

           V = IR

Where V is the voltage

            I is the current

            R is the resistance

Now, insert the parameters and solve;

    V  = 6 x 20  = 120V

Answer:

Dr Hutson is the author of several books among them: John Adams and the Diplomacy of the American Revolution (1980); winner of the Gilbert Chinard Prize, 1981; To Make All Laws: The Congress of the United States, 1789-1989 (Washington and Boston, 1989-90; 4th edition, Washington, 1990); The Sister Republics

Answer:

Dr Hutson is the author of several books among them: John Adams and the Diplomacy of the American Revolution (1980); winner of the Gilbert Chinard Prize, 1981; To Make All Laws: The Congress of the United States, 1789-1989 (Washington and Boston, 1989-90; 4th edition, Washington, 1990); The Sister Republics: ... Explanation: HOPE I HELPED!!!!!

Answer:

The magnitude will be "353.5 N". A further solution is given below.

Explanation:

The given values is:

F = 500 N

According to the question,

In ΔABC,

⇒ [tex]\angle BCA = (90-30)[/tex]

⇒             [tex]=60^{\circ}[/tex]

then,

⇒ [tex]\angle BAC=(180-45-60)[/tex]

⇒             [tex]=75^{\circ}[/tex]

Now,

The corresponding angle will be:

⇒ [tex]\angle FAC=60^{\circ}[/tex]

⇒ [tex]\angle FAB=70+60[/tex]

⇒             [tex]=135^{\circ}[/tex]

Aspect of F across the AC arm will be:

= [tex]F\times cos(60)[/tex]

On putting the values of F, we get

= [tex]500\times (.5)[/tex]

= [tex]200 \ Newton[/tex]

Component F along the AC (in magnitude) will be:

= [tex]F\times cos(135)[/tex]

= [tex]500\times (-.707)[/tex]

= [tex]-353.5 \ N \[/tex]

Answer:

The final velocity of the car is 36 m/s.

Explanation:

Given;

initial velocity of the car, u = 20 m/s

time of the car acceleration, t = 4 s

acceleration of the car, a = 4 m/s²

the final velocity of the car is calculated as;

v = u + at

where;

v is the final velocity of the car

v = 20 + (4 x 4)

v = 36 m/s

Therefore, the final velocity of the car is 36 m/s.