Which of the following is not an undefined term?

point
ray
line
plane

Answer:

4/13

Step-by-step explanation:

There are 4 jacks in the deck and 13 spades. However 1 jack is a spade so we have a total of 16 cards which are either a jack or a spade. Therefore there are (13 + 4 - 1)/52 cards which are not a jack or a spade. Divided 16/52, thus the probability is 4/13.

The probability of drawing a spade or a jack from a standard deck of 52 cards is;

P(drawing either a spade or jack) = 4/13

We are told that the standard deck of cards has 52 cards.

Thus;

N = 52

Now,in a pack of cards there are usually 4 Jacks and 13 spades.

However, among the 4 Jacks, 1 of them is a spade. This means that 1 card will be both a spade and a jack. Thus,

Possible number of Jack's and spades = 13 + 4 - 1 = 16

Thus;

P(drawing either a spade or jack) = 16/52 = 4/13

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Answer:

x=4

Step-by-step explanation:

In order to solve for x, we must isolate x on one side of the equation.

x+3x+5=21

First, combine like terms. x and 3x are both terms with variables, and can be combined.

(x+3x) + 5=21

4x + 5=21

5 is being added to 4x. The inverse of addition is subtraction. Subtract 5 from both sides of the equation.

4x+5-5= 21-5

4x= 16

x is being multiplied by 4. The inverse of multiplication is division. Divide both sides by 4.

4x/4=16/4

x= 16/4

x=4

Let's check our solution. Plug 4 in for x and solve.

x+3x+5=21

4+3(4)+5=21

4+12+5=21

16+5=21

21=21

This solution checks out, so we know our answer is correct.

x is equal to 4, x=4.

Answer:

x = 4

Step-by-step explanation:

x + 3x + 5 = 21

4x + 5 = 21

4x = 21 - 5

4x = 16

x = 16/4

x = 4

verify:

4 + 3*4 + 5 = 21

4 + 12 + 5 = 21

Answer:

D

Step-by-step explanation:

From law of indices,( X^3)^2= x^3×2=x^6

Then the other one, also from law of indices, square

root of 5 is the same as 5 raised to power 1/2, then we multiply the powers, that will give us 5 and we have our complete expression which is x^6-5

Step-by-step explanation:

Let coordinates of B be ( x , y )

X coordinate of B = (-1 + x) / 2 = - 3

Y coordinate of B = (-1 + y) / 2 = -3

Therefore, coordinates of B are ( - 5, - 5 ).

Answer:

2n+3=3.2

2n=3.2-3

2n=0.2

n=0.2/2

n=0.1

The solution of the given equation for n will be -3.1.

There are many different ways to define an equation. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.

The equation must be constrained with some constraints.

As per the given equation,

2n + 3 = -3.2

2n = -3.2 - 3

n = -6.2/2

n = -3.1

Hence "The solution of the given equation for n will be -3.1".

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Answer:

The answer is below

Step-by-step explanation:

The graph used to estimate the consumption (in billions) in the United States for the years 1900 to  2007 is attached.

The year is plotted on the x axis and the number of cigarettes is on the y axis. To estimate the number of cigarattes smoked in year 2000, we have to find the y coordinate that corresponds to an x coordinate of 2000. This is done by drawing a line vertically to touch the graph from the point 2000 on the x axis. The point it touches the graph is then traced to the y axis to get the consumption as shown in the graph attached.

From the graph  the number of cigarettes smoked in 2000 is about 420 billion cigarettes

Answer:

The average value of the function [tex]f(x) = 6 - x^{2}[/tex] over the interval [tex][-1,4][/tex] is [tex]\frac{5}{3}[/tex].

Step-by-step explanation:

The average value of a function over an interval is represented by this integral:

[tex]\bar y = \frac{1}{b-a}\cdot \int\limits^{b}_{a} {f(x)} \, dx[/tex]

Where:

[tex]a[/tex], [tex]b[/tex] - Lower and upper bounds of the interval, dimensionless.

[tex]f(x)[/tex] - Function, dimensionless.

If [tex]a = -1[/tex], [tex]b = 4[/tex] and [tex]f(x) = 6 - x^{2}[/tex], the average value of the function is:

[tex]\bar y = \frac{1}{4-(-1)}\int\limits^{4}_{-1} {6-x^{2}} \, dx[/tex]

[tex]\bar y = \frac{6}{5}\int\limits^{4}_{-1} \, dx - \frac{1}{5}\int\limits^{4}_{-1} {x^{2}} \, dx[/tex]

[tex]\bar y = \frac{6}{5}\cdot x |_{-1}^{4} - \frac{1}{15}\cdot x^{3}|_{-1}^{4}[/tex]

[tex]\bar y = \frac{6}{5}\cdot [4-(-1)]- \frac{1}{15}\cdot [4^{3}-(-1)^{3}][/tex]

[tex]\bar y = \frac{5}{3}[/tex]

The average value of the function [tex]f(x) = 6 - x^{2}[/tex] over the interval [tex][-1,4][/tex] is [tex]\frac{5}{3}[/tex].

This question above is incomplete

Complete Question

Jim had 103 red and blue marbles. After giving 2/5 of his blue marbles and 15 of his red marbles to Samantha, Jim had 3/7 as many red marbles as blue marbles. How many blue marbles did he have originally?

Answer:

70 Blue marbles

Step-by-step explanation:

Let red marbles = R

Blue marbles = B

Step 1

Jim had 103 red and blue marbles.

R + B = 103.......Equation 1

R = 103 - B

Step 2

After giving 2/5 of his blue marbles and 15 of his red marbles to Samantha, Jim had 3/7 as many red marbles as blue marbles

2/5 of B to Samantha

Jim has = B - 2/5B = 3/5B left

He also gave 15 red marbles to Samantha

= R - 15

The ratio of what Jim has left

= Red: Blue

= 3:7

= 3/7

Hence,

R - 15/(3/5)B = 3/7

Cross Multiply

7(R - 15) = 3(3/5B)

7R - 105 = 3(3B/5)

7R - 105 = 9B/5

Cross Multiply

5(7R - 105) = 9B

35R - 525 = 9B............ Equation 2

From Equation 1, we substitute 103 - B for R in Equation 2

35(103 - B) - 525 = 9B

3605 - 35B - 525 = 9B

Collect like terms

3605 - 525 = 9B + 35B

3080 = 44B

B = 3080/44

B = 70

Therefore, Jim originally had 70 Blue marbles.

Answer:

The value of [tex]v[/tex] is ± 22.729.

Step-by-step explanation:

Let be [tex]a=m\cdot g -\frac{k\cdot v^{2}}{m}[/tex], the variable [tex]v[/tex] is now cleared:

[tex]\frac{k\cdot v^{2}}{m}=m\cdot g -a[/tex]

[tex]k\cdot v^{2} = m^{2}\cdot g- m\cdot a[/tex]

[tex]v^{2} = \frac{m^{2}\cdot g - m\cdot a}{k}[/tex]

[tex]v =\pm \sqrt{\frac{m^{2}\cdot g-m\cdot a}{k} }[/tex]

If [tex]a = 2.8[/tex], [tex]m=12[/tex], [tex]g = 9.8[/tex] and [tex]k = \frac{8}{3}[/tex], the value of [tex]v[/tex] is:

[tex]v=\pm \sqrt{\frac{(12)^{2}\cdot (9.8)-(12)\cdot (2.8)}{\frac{8}{3} } }[/tex]

[tex]v \approx \pm 22.729[/tex]

The value of [tex]v[/tex] is ± 22.729.

Step-by-step explanation: The correct graph is #6. Cubic Function

Answer:

24-8i

Step-by-step explanation:

(8-8i)(2+i)=8*2+8i-8i*2-8i^2=16+8i-16i-8*(-1)=16-8i+8=24-8i

Answer:

Your answer is -32

Step-by-step explanation:

First you add $220 and $12 together giving you $232

Then you subtract $76 from the $232 giving you $156

Then subtract $188 from $156 giving you a total of -$-32

Answer:

8

Step-by-step explanation:

If the two solids have the same height and same cross-sectional area at every level, this means that the radius of the oblique cylinder is the same as the radius of the right cylinder.

Since the radius of the right cylinder is 16/2=8, this means that the radius of the oblique cylinder must also be 8.

Algebraically, the area of the cross-section is given by:

[tex]A=\pi r^2[/tex]

If the areas of them are the same:

[tex]A_{right}=A_{oblique}[/tex]

Then:

[tex]\pi r_{right}^2=\pi r_{oblique}^2\\r_{right}=r_{oblique}[/tex]

Answer:

B' is (3,2)

Step-by-step explanation:

In the original B coordinate pair, 6 is the y-coordinate.  When we talk about shifting images or points up or down, we will normally see a change in the y-coordinate.  In this case, the image is being translated 4 units down, so subtract 4 from 6 to get 2 as your y-ccoordinate for B'.  Since no horizontal shift is being made, the x-coordinate from the original B point stays the same and B' becomes (3,2).

Answer:

b is (3,2)

Step-by-step explanation:

ggchvvbggggghhh

Answer:

2<∛13<3      1<∛6<2

Step-by-step explanation:

Lets find the integers a and b  ∛13 lies between.

a<∛13<b

a³<13<b³

=> a=2 so 2³=8   and b=3 so 3³=27    8<13<27

Similarly     a<∛6<b

a³<6<b³

a=1    and b=2

Answer:

Based on triangles of angles: 45-45-90:

chord/2=(radius√2)/2

chord/2=(10√2)/2

chord/2=5√2

chord=10√2

Step-by-step explanation:

Hope it helps ;)

Answer:

answer below

Step-by-step explanation:

from the question the

mean = ∑x/n

∑x = 317

n = 16

mean = 19.8125

x           x-Ц           x-Ц²

19       -0.8125      0.66015625

20       0.1875      0.03515625

19          -0.8125      0.66015625

20         0.1875      0.03515625

18         -1.8125       3.28515625

21          1.1875        1.41015625

17           -2.8125      7.91015625

19           -0.8125      0.66015625

24           4.1875       17.53515625

23            3.1875      10.16015625

21           1.1875        1.41015625

21            1.1875        1.41015625

17             -2.8125      7.91015625

20          -0.8125      0.66015625

20           -0.8125      0.66015625

18            -1.8125       3.28515625

∑(x-Ц)² = 56.44

s.d = 1.9

b.

19.81 + 2*1.9= 23.61

19.81-2*1.9 = 16.01

=

The answer is

29.12

hope this helps

Hi there! Hopefully this helps!

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Calculate 10000 to the power of [tex]\frac{3}{4}[/tex].

[tex]\frac{3}{4} = 0.75[/tex]

[tex]10000^{0.75}= 1000[/tex].

For example, let's say we had the equation x+10 = 30

We are adding 10 onto some unknown number x to get 30. To find x, we undo what is happening to x, so we subtract 10 from both sides. Subtraction is the inverse operation of addition.

Answer:

d, i took the test i can confirm its correct lol

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

15/3=5 when the y are 3 it division

Answer:

What the other guy said

Step-by-step explanation:

Answer:

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probabiity = expected outcome/total outcome

Let the total outcome be 100% = 1.0

Given three different colored balls: orange, green and purple. If the probability of randomly choosing orange ball from a bag is 45%. The probability of randomly choosing a green ball from bag is 0.10

The probability of choosing both orange ball and green ball is 0.45+0.10 = 0.55.

Since the total outcome of probability is 1, then the probability for Jared to randomly choose a purple ball from the bag will be expressed as;

Pr(purple) = 1 - [Pr(green)+Pr(orange)]

Pr(purple) = 1 - [0.45+0.10]

Pr(purple) = 1 - 0.55

Pr(purple) = 0.45

Hence it is 45% likely for Jared to randomly choose a purple ball from the bag.

Answer:

x=26

y=9

Step-by-step explanation:

5x-17+3x-11=180

8x=180+17+11

8x=208

x=26

3(26)-11=78-11=67

2y+5=90-67

2y=90-67-5

2y=18

y=9

Answer:

2(15 - 5) + 3(9 - 8)

Step-by-step explanation:

Profit for each $5 bracelet: 15 - 5

Profit for 2 $5 bracelets: 2(15 - 5)

Profit for each $8 bracelet: 9 - 8

Profit for 3 $8 bracelets: 3(9 - 8)

Total profit: 2(15 - 5) + 3(9 - 8)

Answer:

2(-5)+3(-8)+2(15)+3(9)=23

Step-by-step explanation:

For this expression, every time she payed for something we will use a negative number, and whenever she sold it we will use a positive number.

Lets start off with what she payed for, she bought two 5 dollar bracelets, and three 8 dollar bracelets.

2(-5)+3(-8)

Now we will see what she sold. She sold two bracelets for 15 dollars, and then sold three bracelets for 9 dollars.

2(15)+3(9)

Now we combine these to find out her profit.

2(-5)+3(-8)+2(15)+3(9)=23

Answer: D) relationship between y intercepts cannot be determined

The graph of f(x) is a vertical line. It is completely parallel to the y axis, so it never crosses the y axis. We need the graph to cross the y axis somewhere in order to form a y intercept. Therefore f(x) does not have a y intercept. So we cannot compare y intercepts if f(x) doesn't have one at all.

Answer:

x = ((30 sqrt(1462809) + 36253)^(2/3) - 131)/(60 (30 sqrt(1462809) + 36253)^(1/3)) + 7/60 or x = 7/60 - 1/60 ((-1)/(30 sqrt(1462809) + 36253))^(1/3) (131 (-1)^(1/3) + (30 sqrt(1462809) + 36253)^(2/3)) or x = 1/60 (131 (-1/(36253 + 30 sqrt(1462809)))^(1/3) + (-1)^(2/3) (36253 + 30 sqrt(1462809))^(1/3)) + 7/60

see atachement it's more legible.

Step-by-step explanation:

Solve for x:

(20 x^3 - 7 x^2 + 3 x - 7)/(-13 x^2 - 5) = 0

Hint: | Multiply both sides by a polynomial to clear fractions.

Multiply both sides by -13 x^2 - 5:

20 x^3 - 7 x^2 + 3 x - 7 = 0

Hint: | Look for a simple substitution that eliminates the quadratic term of 20 x^3 - 7 x^2 + 3 x - 7.

Eliminate the quadratic term by substituting y = x - 7/60:

-7 + 3 (y + 7/60) - 7 (y + 7/60)^2 + 20 (y + 7/60)^3 = 0

Hint: | Write the cubic polynomial on the left hand side in standard form.

Expand out terms of the left hand side:

20 y^3 + (131 y)/60 - 36253/5400 = 0

Hint: | Write the cubic equation in standard form.

Divide both sides by 20:

y^3 + (131 y)/1200 - 36253/108000 = 0

Hint: | Perform the substitution y = z + λ/z.

Change coordinates by substituting y = z + λ/z, where λ is a constant value that will be determined later:

-36253/108000 + (131 (z + λ/z))/1200 + (z + λ/z)^3 = 0

Hint: | Transform the rational equation into a polynomial equation.

Multiply both sides by z^3 and collect in terms of z:

z^6 + z^4 (3 λ + 131/1200) - (36253 z^3)/108000 + z^2 (3 λ^2 + (131 λ)/1200) + λ^3 = 0

Hint: | Find an appropriate value for λ in order to make the coefficients of z^2 and z^4 both zero.

Substitute λ = -131/3600 and then u = z^3, yielding a quadratic equation in the variable u:

u^2 - (36253 u)/108000 - 2248091/46656000000 = 0

Hint: | Solve for u.

Find the positive solution to the quadratic equation:

u = (36253 + 30 sqrt(1462809))/216000

Hint: | Perform back substitution on u = (36253 + 30 sqrt(1462809))/216000.

Substitute back for u = z^3:

z^3 = (36253 + 30 sqrt(1462809))/216000

Hint: | Take the cube root of both sides.

Taking cube roots gives 1/60 (36253 + 30 sqrt(1462809))^(1/3) times the third roots of unity:

z = 1/60 (36253 + 30 sqrt(1462809))^(1/3) or z = -1/60 (-36253 - 30 sqrt(1462809))^(1/3) or z = 1/60 (-1)^(2/3) (36253 + 30 sqrt(1462809))^(1/3)

Hint: | Perform back substitution with y = z - 131/(3600 z).

Substitute each value of z into y = z - 131/(3600 z):

y = 1/60 (30 sqrt(1462809) + 36253)^(1/3) - 131/(60 (30 sqrt(1462809) + 36253)^(1/3)) or y = -1/60 (-30 sqrt(1462809) - 36253)^(1/3) - (131 (-1)^(2/3))/(60 (30 sqrt(1462809) + 36253)^(1/3)) or y = 131/60 ((-1)/(30 sqrt(1462809) + 36253))^(1/3) + 1/60 (-1)^(2/3) (30 sqrt(1462809) + 36253)^(1/3)

Hint: | Simplify each solution.

Bring each solution to a common denominator and simplify:

y = ((30 sqrt(1462809) + 36253)^(2/3) - 131)/(60 (36253 + 30 sqrt(1462809))^(1/3)) or y = -1/60 (-1/(36253 + 30 sqrt(1462809)))^(1/3) ((30 sqrt(1462809) + 36253)^(2/3) + 131 (-1)^(1/3)) or y = 1/60 (131 ((-1)/(30 sqrt(1462809) + 36253))^(1/3) + (-1)^(2/3) (30 sqrt(1462809) + 36253)^(1/3))

Hint: | Perform back substitution on the three roots.

Substitute back for x = y + 7/60:

Answer: x = ((30 sqrt(1462809) + 36253)^(2/3) - 131)/(60 (30 sqrt(1462809) + 36253)^(1/3)) + 7/60 or x = 7/60 - 1/60 ((-1)/(30 sqrt(1462809) + 36253))^(1/3) (131 (-1)^(1/3) + (30 sqrt(1462809) + 36253)^(2/3)) or x = 1/60 (131 (-1/(36253 + 30 sqrt(1462809)))^(1/3) + (-1)^(2/3) (36253 + 30 sqrt(1462809))^(1/3)) + 7/60

Answer:

Yes

Step-by-step explanation:

Because a - - - - - - - - - - b

Same as b-----------------a

Answer:

Σ( xi ) / n ; $29

Step-by-step explanation:

Given the following data:

X= $27, $31, $30, $26, $25, $27, $37, $33, $32, $28, $26, $26

Number of observations (n) = 12

Mean formula (m) = ( Σ xi ) / n

Where i = each individual value in X

Mean water bill for the years is thus :

m = Σ [(27 + 31 + 30 + 26 + 25 + 27 + 37 + 33 + 32 + 28 + 26 + 26)] / 12

m = 348 / 12

m = 29

Hence, the mean water bill for the year is $29

Answer/Step-by-step explanation:

Length of rectangle = [tex] l [/tex]

Width of rectangle = [tex] \frac{1}{3} of l - 1 = \frac{1}{3}l - 1 = \frac{l}{3} - 1 [/tex]

A. Expression for finding area of the rectangle:

Area of rectangle is given as [tex] length*width [/tex]

[tex] Area = l(\frac{l}{3} - 1) [/tex]

Or

[tex] Area = l*\frac{l}{3} - l*1 [/tex]

[tex] Area = \frac{l^2}{3} - l [/tex]

b. Expression for finding perimeter:

Perimeter of rectangle is given as [tex] 2(Length + Width) [/tex]

[tex] Perimeter = 2(l + (\frac{l}{3} - 1)) [/tex]

Or

[tex] Perimeter = 2(l) + 2(\frac{l}{3} - 1) [/tex]

[tex] Perimeter = 2l + \frac{2l}{3} - 2) [/tex]

c. Quotient of Perimeter divided by area:

[tex] 2(l + (\frac{l}{3} - 1)) [/tex] ÷ [tex] l(\frac{l}{3} - 1) [/tex]

[tex]2(l + (\frac{l}{3} - 1))[/tex] ÷ [tex]\frac{l^2 - 3l}{3}[/tex]

Change the ÷ to × and flip the fraction on your right upside down.

[tex]2(l + (\frac{l}{3} - 1)) * \frac{3}{l^2 - 3l}[/tex]

[tex]2l + 2(\frac{l}{3} - 1) * \frac{3}{l^2 - 3l}[/tex]

Answer:

please mark my answer brainliest

Step-by-step explanation:

these types of input variables are called integer...