Which of the following is a reason for needing to acquire a 1040X form?

Answer:

We need to isolate q on one side. 11q+5 <_ 49 Start subtracting 5 from both sides. 11q+5-5 <_ 49 -5 11q < 44 The answer will be B. q < 4.

Step-by-step explanation:

Answer:

the answer is B

Step-by-step explanation:

khan

9514 1404 393

Answer:

  y = -0.03x² +12

Step-by-step explanation:

For "tunnel" or "arch" or "bridge" problems, I like to start with the expression ...

  y = 1 - x²

It has a height of 1 and intersects the x-axis at ±1. This can be scaled to give the appropriate height and x-intercepts.

We want the x-intercepts to be ±20, so we can scale this horizontally by a factor of 20:

  y = 1 -(x/20)²

We want the height to be 12, so we can scale it vertically by a factor of 12:

  y = 12(1 -(x/20)²

  y = 12 -12(x²/400)

  y = -0.03x² +12

Answer:

x = 0,5

Step-by-step explanation:

Factor and set each factor equal to 0.

Answer:

Option B, False

Step-by-step explanation:

Step 1:  Get the surface area formulas for both shapes

Surface Area Formula for Cone:  [tex]A = \pi * r(r + \sqrt{h^{2} + r^{2}})[/tex]

Surface Area Formula for Cylinder:  [tex]A = 2\pi rh+2\pi r^{2}[/tex]

Step 2:  Plug in the values and solve

Cone:  [tex]A = \pi * r(r + \sqrt{(3r)^{2} + r^{2}})[/tex]

Cone:  [tex]A = \pi r^{2} + \pi \sqrt{10}r^{2}[/tex]

Cylinder:  [tex]A = 2\pi r*r+2\pi r^{2}[/tex]

Cylinder:  [tex]A=4 \pi r^{2}[/tex]

Step 3:  Compare

[tex]\pi r^{2} + \pi \sqrt{10}r^{2}\neq 4 \pi r^{2}[/tex]

They are not equal, therefore the answer is False.

Answer:  Option B, False

Answer:

ok so i just took this on a p 3 x and its true i have a screenshot . i got the question wrong it's definitely true .

Step-by-step explanation:

Answer:

Step-by-step explanation:

For every hour said student would've ran 3.5 km/hr

Answer: c

Step-by-step explanation:

Edge 2021

Answer:

a) (tri)ABC ~ (tri)CDE

b) AA

Step-by-step explanation:

a) Given in the question (the triangles are similar)

b) AA similarity is found by the vertical angle at <ACB and <DCE and the marked angles at <D and <A.

Answer:

29.3feet

Step-by-step explanation:

In ΔUVW, the measure of ∠W=90°, the measure of ∠U=19°, and WU = 85 feet. Find the length of VW to the nearest tenth of a foot.

From the triangle given

<W = 90 degrees

<U = 19 degrees

<V = 180 - (90+19)

<V = 180 - 109

<V = 71 degrees

Using SOH CAH TOA

tan theta = opp/adj

tan <V = WU/VW

tan 71 = 85/VW

VW = 85/tan 71

VW = 85/2.9042

VW = 29.27

Hence the length of VW to the tenth of a foot is 29.3feet

29.3 is in fact the correct answer

Answer:

1) A = 48 sq units  2) 42 sq units

Step-by-step explanation:

The formula to find the area of a trapezoid of a trapezoid is A = 1/2(b1+b2)h.

So for number 1, it is stated that the height of each unit is 2. Now let's substitute the variables in the formula with the actual bases and heights. I got A = 1/2(8+4)8, A=6*8, A=48 sq units.

For number 2, each unit also has a height of 2. Let's substitute the variables in the formula again. And we get A = 1/2(10+4)6, A = 7*6, A = 42 sq units.

This is how you find the areas of the trapezoids!

Answer:

x = 10

Step-by-step explanation:

If two tangent segments are drawn to a circle from an external point, then those segments are congruent.

x+11 = 2x+ 1

x = 10

Answer:

x=10

Step-by-step explanation:

x+11=2x+1

x+10=2x

10=2x-x

x=10

Brillianst!!!!!

Answer:

ugh wdym like 10 20 ,30 40 and so on ....

Answer10 20 30 40 50 60 70 80 90 100 110 120

Step-by-step explanation:

10x1=10

10x2=20

10x3=30

10x4=40

10x5=50

10x6=60

10x7=70

10x8=80

10x9=90

10x10=100

10x11=110

10x12=120

Answer:

B. 11

Step-by-step explanation:

Delta y over delta x

(8-2)/(k-1) = 3/5

6/(k-1) =3/5

6 = 3/5k - 3/5

6 3/5 = 3/5k

K = 11

Answer:

score a high  grade in another subject

Step-by-step explanation:

Answer:

AAA

Step-by-step explanation:

start filling out math and putting unnecary notes

Answer:

The answer is 50.

Hope this helps. sry if it is wrong

Answer:

82

Step-by-step explanation:

Since the sum of the two digits is 10, there are some pairs, such as 46, 64, 28, 82, 55,37, 73. And flip them around and see if the difference between the two numbers is 54. So one example is 82-28=54, so that is the answer. It can't be 28 or 46 because it said less than. I am not good at explaining, but I hope you guys understand. Thank you :D

9514 1404 393

Answer:

  a) {-6, 2}

  b) -12

  c) minimum: -16

Step-by-step explanation:

I find a graphing calculator to be a big help. Its graph is attached.

__

a) The function can be factored as ...

  f(x) = (x -2)(x +6)

The factors are zero at the x-intercepts: x = 2, x = -6.

__

b) The y-intercept is the function value when x=0. That is the constant in the function. The y-intercept is -12.

__

c) The leading coefficient of the function is positive, so its graph opens upward. The extreme value is a minimum. It is found on the axis of symmetry, at the x-value that is halfway between the x-intercepts: x = (2-6)/2 = -2. The function value there is ...

  f(-2) = (-2-2)(-2+6) = -4(4) = -16

The minimum is f(-2) = -16.

Answer:

I took the test.

A (6, -2)

b (-12)

c  Minimum -16

Step-by-step explanation:

Answer:

c.40

Step-by-step explanation:

........................

I have a trick for parallelograms and the formula is...[tex]\frac{b*h}{2}[/tex]

Yes the rectangle formula also wrks for parallelograms!!! You just gotta chop one end up and stick it on the other side!

So it is 5*8/2=20

Answer: A: 21.4

Step-by-step explanation:

For the figure, on the pole where, tower is attached, the measure of side DC is 21.4 feet.

In a right angle triangle, the ratio of the opposite side to the adjacent side is equal to the tangent angle between them.

[tex]\thn \theta=\dfrac{b}{a}[/tex]

Here, (a) is the adjacent side, (b) is the opposite side and [tex]\theta[/tex] is the angle made between them.

The height of the pole is 60 foot. Therefore,

[tex]AC=60\rm ft[/tex]

The distance of the wire from the base of the pole is 40 feet. Therefore,

[tex]BC=40\rm ft[/tex]

Therefore, the tangent angle can be given as,

[tex]\tan\angle(ABC)=\dfrac{60}{40}\\\angle(ABC)=\tan^{-1}(1.5)\\\angle(ABC)=56.31^o[/tex]

The angle DBC is half of the angle ABC. Thus,

[tex]\angle(DBC)=\dfrac{56.31}{2}\\\angle(DBC)=28.15^o[/tex]

Now, again in the triangle DBC, the tangent angle can be given as,

[tex]\tan(28.15)=\dfrac{DC}{40}\\DC=21.407\rm ft[/tex]

Hence, on the pole where, tower is attached, the measure of side DC is 21.4 feet.

Learn more about the right angle triangle property here;

https://brainly.com/question/22790996

Answer:

A:

i) ∠ABC is an inscribed angle

ii) ∠ATC is a central angle

B: ∠ABC = 150/2 = 75°

C: ∠ATC = 150°

Answer:

79

Step-by-step explanation:

x2 + 11x + 1,

first step substituion

6(2) + 11(6)+ 1

multiply

12+66+1

add like terms

79

Answer:

103

Step-by-step explanation:

Step-by-step explanation:

3x+18=4x+2

x= 16

measure of <A = 66°

Answer:

Step-by-step explanation:

∠EAD = ∠CAB = 53°

By Side-angle-side, △EAD is congruent to △CAB

∠E = 96°

∠D = 180-96-53 = 31°

x = 31°

Answer:

Step-by-step explanation:

9-3(2-5x)

9-6+15x

3+15x

Answer:

C

Step-by-step explanation:

9-3(2-5x)

9-6+15x=

3+15x