Which of the following is a description of the Remote Associates Test (RAT)?

Answer:

The tiger will land at 3.71 meters from the base of the rock

Explanation:

Horizontal Motion

When an object is thrown horizontally with a speed vo from a height h, the range or maximum horizontal distance traveled by the object can be calculated as follows:

[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]

The tiger leaps from a height of h=7.5 m with a speed of v=3 m/s. Substituting the values into the formula:

[tex]\displaystyle d=3\cdot\sqrt{\frac {2\cdot 7.5}{9.8}}=3.71\ m[/tex]

The tiger will land at 3.71 meters from the base of the rock

Answer:

The total force on the cart is:  

F = F(applied) - F(friction) = (18 N) - (15 N) = 3.0 N  

The acceleration of the cart is:  

a = (change in velocity)/(time) = (1.0 m/s)/(5.0 s) = 0.20 m/s^2  

Using F = ma, the mass of the cart is:  

m = F/a = (3.0 N)/(0.20 m/s^2) = 15 kg

Answer:

Both light and sound can be described in terms of wave forms with physical characteristics like amplitude, wavelength, and timbre. Wavelength and frequency are inversely related so that longer waves have lower frequencies, and shorter waves have higher frequencies

The ability of both to cause interference is the resemblance between sound waves and light waves.

While sound waves are mechanical, light waves are electromagnetic. Unlike sound waves, which are longitudinal, light waves are transverse. Light waves can go across a vacuum. Since sound waves need a physical medium to go through, they cannot move in a vacuum.

Both sound and light waves adhere to the rule of reflection, which states that the angle of incidence and angle of reflection are equal. Therefore, choice 2 is the right one. While light waves are transverse, sound waves are longitudinal.

In that, they both have an amplitude, a wavelength, a period, and a frequency, light, and sound waves are comparable to one another.

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Answer:

voltage

Explanation:

the current in a circuit, the voltage can be increased.

According to Ohm's law, when all other physical parameters, including temperature, are held constant, the voltage across a conductor is directly proportional to the current flowing through it.

From ohm's law, we can state that voltage is directly proportional to current.

Looking at the following formula:

I = V/R

Where V is voltage,

I is current, and

R is resistance

In the above equation, Current and Voltage are in a direct relationship such that if I is increased, V is also increased, and vice versa.

Therefore, To increase the current, the voltage should be increased.

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Answer:

your answer is wavelength

Explanation:

the the highest service part of a weight is called the crest and the lowest part is the trough the vertical distance between the crest and the trough is the waist height the horizontal disc distance between two adjacent Crest or troughs is known as wavelengths

Answer:

The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.

Explanation:

Volume of a Sphere

The volume of a sphere of radius r is given by:

[tex]\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3[/tex]

The volume of each little sphere is:

[tex]\displaystyle V_l=\frac{4}{3}\cdot \pi\cdot 2^3[/tex]

[tex]V_l=33.51\ mm^3[/tex]

When the seven little spheres coalesce, they form a single bigger sphere of volume:

[tex]V_b=7*V_l=234.57\ mm^3[/tex]

Knowing the volume, we can find the radius rb by solving the formula for r:

[tex]\displaystyle V_b=\frac{4}{3}\cdot \pi\cdot r_b^3[/tex]

Multiplying by 3:

[tex]3V_b=4\cdot \pi\cdot r_b^3[/tex]

Dividing by 4π:

[tex]\displaystyle \frac{3V_b}{4\cdot \pi}= r_b^3[/tex]

Taking the cubic root:

[tex]\displaystyle r_b=\sqrt[3]{\frac{3V_b}{4\cdot \pi}}[/tex]

Substituting:

[tex]\displaystyle r_b=\sqrt[3]{\frac{3*234.57}{4\cdot \pi}}[/tex]

[tex]r_b=3.83\ mm[/tex]

The surface area of the seven little spheres is:

[tex]A_l=7*(4\pi r^2)=7*(4\pi 2^2)=351.86\ mm^2[/tex]

The surface area of the bigger sphere is:

[tex]A_b=4\pi r_b^2=4\pi (3.83)^2=184.33\ mm^2[/tex]

The ratio between them is:

[tex]\displaystyle \frac{351.86\ mm^2}{184.33\ mm^2}=1.91[/tex]

The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.

Answer:

137.2J

Explanation:

Ep= mgh

Given,

and we know, g = 9.81 N/kg

Ep= 2 × 9.81 × 7

Ep= 137.2J

Answer:

Because water is polar and oil is nonpolar, their molecules are not attracted to each other. polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.

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use your brain :)

Substances that can dissolve both polar and nonpolar substances are called amphiphilic or amphipathic. This unique property arises due to their molecular structure, which contains both polar and nonpolar regions.

Amphiphilic molecules typically have a hydrophilic (water-attracting) or polar end and a hydrophobic (water-repelling) or nonpolar end. This dual nature allows them to interact with and dissolve in both polar and nonpolar solvents. Let's explore the reasons behind this ability:

Polar interactions: The hydrophilic end of the amphiphilic molecule can form hydrogen bonds and electrostatic interactions with polar solvents (like water) due to the presence of charged or partially charged atoms (such as oxygen or nitrogen). This makes them soluble in polar substances.

Nonpolar interactions: The hydrophobic end of the amphiphilic molecule is typically a long hydrocarbon chain or a nonpolar group. These nonpolar regions can interact with other nonpolar substances (like oils, fats, or hydrophobic portions of biomolecules) through van der Waals forces and London dispersion forces.

Emulsification: The presence of both polar and nonpolar parts in an amphiphilic molecule allows it to act as an emulsifier. It can stabilize the interface between polar and nonpolar substances, preventing them from separating. For example, in the formation of an oil-in-water or water-in-oil emulsion, amphiphilic molecules form a barrier between the two immiscible substances, keeping them dispersed and forming a stable mixture.

Examples of amphiphilic molecules include surfactants (detergents), phospholipids (essential components of cell membranes), and lipoproteins (transporters of lipids in the bloodstream). These substances play vital roles in various biological processes and industrial applications due to their ability to interact with both polar and nonpolar substances.

Hence, Substances that can dissolve both polar and nonpolar substances are called amphiphilic or amphipathic. This unique property arises due to their molecular structure, which contains both polar and nonpolar regions.

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Answer: B. 15.2s

Explanation: 600/39.5 = about 15.2

Answer: The answer is a

Explanation:

Answer: 30.641

Explanation: If you get the ave which is 38.0 then the vi which is 7.359

38.0-7.359=30.641/0.0 which is 30.641

Answer:

  P_a = 3P₀ ,  P_b = 2 P₀ ,       P_c = 3 P₀

P_c> P_b> P_a

Explanation:

To determine which circuit consumes more energy than is given by the expression

           P = V I

           V = I R

           I = V / R

           P = V² / R

As all circuits have the same battery, the value of the resistance to which the battery is connected determines the consumption

Circuit A

In this circuit the three bulbs are in series so the total resistance is

         R_total = 3 R

the power dissipated is

         P_a = V² / 3R

if we call

         P₀ = V² / R

we substitute

         P_a = P₀/3

Circuit B

Two bulbs are connected in series

           R_total = 2 R

power is

        P_b = V2 / 2R

        P_b =  P₀/2

Circuit C

The 3 bulbs are connected, but in parallel, the resistance is

        1 / R_totak = 1 / R + 1 / R + 1 / R

        R_total = R / 3

        P _c = V2 3 / R

        P_c = 3 Po

By reviewing these results, we can sort the circuits

        P_c> P_b> P_a

A book is sitting on a desk is due to the Gravitational force of Earth Gravity so D. the downward force the Earth pulls on the book.

The force of attraction between all masses that is objects in the universe, especially the attraction of the Earth's mass for bodies near its surface.

Einstein said that the shape of spacetime is responsible for the rise of force that we experience as gravity. A concentration of mass, such as the Earth or sun, bends space around it like a rock bends the flow of a river.

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Answer:

The  dimension is  [tex]D =  L ^{2} T^{-1}[/tex]

Explanation:

From the question we are told that

     [tex]J  =  -D \frac{dn}{dx}[/tex]

Here  [tex][J] = \frac{1}{L^2 T}[/tex]

       [tex][n] =\frac{1}{L^3}[/tex]

        [tex][x] = L[/tex]

So

    [tex]\frac{1}{L^2 T} =  -D \frac{d(\frac{1}{L^3})}{d[L]}[/tex]

Given that the dimension represent the unites of  n and  x then the differential  will not effect on them

So

[tex]\frac{1}{L^2 T} =  -D \frac{(\frac{1}{L^3})}{[L]}[/tex]

=>   [tex]D =  \frac{L^{-2} T^{-1} * L }{L^{-3}}[/tex]

=>   [tex]D =  L ^{2} T^{-1}[/tex]

Answer:

74 N to the right

Explanation:

the forces are going in opposite horizontal directions, meaning that they are directly opposing each other. this means that you can subtract the force applied in the direction that is greater from the direction that is less to get the net force for the greater direction

this means 182 N - 108 N = 74 N to the right

In a game of tug of war the magnitude and direction of the net horizontal force on the rope is 74 N.

A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

In a game of tug of war, a rope is pulled by a force of 182 N to the right and by a force of 108 N to the left. The magnitude and direction of the net horizontal force on the rope is,

F = 182 - 108

F = 74 N

The magnitude and direction of the net horizontal force on the rope is  74 N.

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Answer:

5.5 is the correct answer

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Answer:

To the extent that Stellar spectra look like blackbodies, the temperature of a star can also be measured amazingly accurately by recording the brightness in two different filters. To get a stellar temperature: Measure the brightness of a star through two filters and compare the ratio of red to blue light.

Explanation:

Answer:

(a) E = 3.6 x 10³ N/C = 3.6 KN/C

(b) ΔV = 1044 Volts

(c) K.E = 1.67 x 10⁻¹⁶ J

(d) Vf = 4.47 x 10⁵ m/s

(e) a = 3.45 x 10¹¹ m/s²

(f) F = 5.76 x 10⁻¹⁶ N

(g) E = 3.6 x 10³ N/C = 3.6 KN/C  

(h)  Both values are same in part (h) and (a)

Explanation:

(a)

Electric field between oppositely charged plates is given as follows:

E = σ/ε₀

where,

E = Electric Field Intensity = ?

σ = surface charge density = 32 nC/m² = 3.2 x 10⁻⁸ C/m²

ε₀ = Permittivity of free space = 8.85 x 10⁻¹² C²/N.m²

Therefore,

E = (3.2 x 10⁻⁸ C/m²)/(8.85 x 10⁻¹² C²/N.m²)

E = 3.6 x 10³ N/C = 3.6 KN/C

(b)

E = ΔV/r

ΔV = Er

where,

r = distance between plates = 29 cm = 0.29 m

ΔV = Potential Difference = ?

ΔV = (3.6 x 10³)(0.29)

V = 1044 Volts

(c)

Kinetic Energy of Proton = Work done on Proton

K.E = F r

but,  F = E q

K.E = E q r

where,

q = charge on proton = 1.6 x 10⁻¹⁹ C

Therefore,

K.E = (3600 N/C)(1.6 x 10⁻¹⁹ C)(0.29 m)

K.E = 1.67 x 10⁻¹⁶ J

(d)

K.E = (1/2)m(Vf² - Vi²)

where,

m = mass of proton = 1.67 x 10⁻²⁷ kg

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s

Therefore,

1.67 x 10⁻¹⁶ J = (1/2)(1.67 x 10⁻²⁷ kg)(Vf² - (0 m/s)²]

Vf² = (1.67 x 10⁻¹⁶ J)(2)/(1.67 x 10⁻²⁷ kg)

Vf = √(20 x 10¹⁰ m²/s²)

Vf = 4.47 x 10⁵ m/s

(e)

2as = Vf² - Vi²

2(a)(0.29 m) = (4.47 x 10⁵ m/s)² - (0 m/s)²

a = (20 x 10¹⁰ m²/s²)/0.58 m

a = 3.45 x 10¹¹ m/s²

(f)

F = ma

F = (1.67 x 10⁻²⁷ kg)(3.45 x 10¹¹ m/s²)

F = 5.76 x 10⁻¹⁶ N

(g)

E = F/q

E = (5.76 x 10⁻¹⁶ N)/(1.6 x 10⁻¹⁹ C)

E = 3.6 x 10³ N/C = 3.6 KN/C

(h)

Both values are same in part (h) and (a)

Answer:

Explanation:

The work done by an object can be found by using the formula

From the question

force = 25 N

distance = 3 m

We have

work done = 25 × 3

We have the final answer as

Hope this helps you

Complete Question

A number 14 copper wire has a diameter of 1.628 mm. Calculate the resistance of a 37.0 m long piece of such wire.

(Use 1.72×10-8 ?m for the resistivity of copper.)

For safety, the National Electrical Code limits the allowable amount of current which such a wire may carry. When used in indoor wiring, the limit is 15.0 A for rubber insulated wire of that size. How much power would be dissipated in the wire of the above problem when carrying the maximum allowable current?

What would be the voltage between the ends of the wire in the above problem?

What is the current density in the wire when it is carrying the maximum allowable current? (Current density is the current in the wire divided by the cross sectional area of the wire.)

What is the drift velocity of the electrons when the wire is carrying the maximum allowable current?

(The density of electrons in copper is 8.47×1028 m-3.)

Answer:

a

 [tex]R =0.3057 \ \Omega [/tex]

b

 [tex]P  = 68.78 \ W  [/tex]

c

 [tex]V  = 4.5855 \ V[/tex]  

d

 [tex]J  =   7.205 *10^{6}\ A/m^2 [/tex]

e

 [tex]v_d  =  0.0005316 \ m/s[/tex]

Explanation:

From the question we are told that

   The resistivity of copper is  [tex]\rho =  1.72* 10^{-8} \  \Omega \cdot m[/tex]

   The  current limit is  [tex]I  =  15 \ A[/tex]

     The diameter is  [tex]d= 1.628 mm= 0.001628 \ m[/tex]

    The length of the wire is  [tex]l  =  37.0 m[/tex]

    The density of electron is  [tex]n  =   8.47*10^{28} m^{-3}[/tex]

Generally the radius is mathematically represented as

       [tex]r =  \frac{d}{2}[/tex]

=>     [tex]r =  \frac{0.001628}{2}[/tex]

=>     [tex]r =0.000814 \ m [/tex]

Generally the resistance is mathematically represented as

          [tex]R =  \frac{\rho  *  l }{A}[/tex]

Here A is the area which is mathematically represented as    

      [tex]A = 3.142 *   (0.00081)^2[/tex]

=>   [tex]A = 2.082 *10^{-6}\ m^2 [/tex]  

=>    [tex]R =  \frac{1.72* 10^{-8}  *  37.0  }{2.082 *10^{-6}}[/tex]

=>    [tex]R =0.3057 \ \Omega [/tex]

Generally the power dissipated is mathematically represented as

       [tex]P  =  I^2 R[/tex]

=>   [tex]P  =  (15)^2 *  0.3057 [/tex]

=>   [tex]P  = 68.78 \ W  [/tex]

Generally the voltage is mathematically represented as  

     [tex]V  =  I  * R[/tex]    

=>    [tex]V  =  15 * 0.3057[/tex]  

=>    [tex]V  = 4.5855 \ V[/tex]  

Generally the charge density is mathematically represented as

      [tex]J  =  \frac{I}{A}[/tex]

=>   [tex]J  =  \frac{15}{2.082 *10^{-6}}[/tex]

=>     [tex]J  =   7.205 *10^{6}\ A/m^2 [/tex]

Generally the drift velocity is mathematically represented as

     [tex]v_d  =  \frac{I}{ n  *  A *  e}[/tex]

Here e is the charge on an electron with value  [tex]e =  1.60 *10^{-19} \  C[/tex]

So

         [tex]v_d  =  \frac{15}{ 8.47*10^{28}  * 2.082 *10^{-6} *  1.60 *10^{-19} }[/tex]

 =>  [tex]v_d  =  \frac{15}{ 8.47*10^{28}  * 2.082 *10^{-6} *  1.60 *10^{-19} }[/tex]

 =>  [tex]v_d  =  0.0005316 \ m/s[/tex]

Answer:

Not D, every substance in existence has mass and is made from it in any given form.

B and C

Explanation:

The statements which are true about photons are:

Discussion:

The photon is a type of elementary particle. It is the quantum of the electromagnetic field including electromagnetic radiation such as light and radio waves, and the force carrier for the electromagnetic force.

Additionally, Photons are massless, so they always move at the speed of light in vacuum, 3 × 10⁸ m/s.

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Answer: Force of magnitude 20.22lbf to the right at angle 8.5°

Explanation: The image named "Untitled" below shows the forces acting on the cart.

The second image, "Untitled2", demonstrate the vector diagram of the forces acting on the kart, in which:

f is force forward

f(left) is pull to the left

f(R) is the resulting force necessary for the kart to move

The drag force is not draw on the vector diagram because its value is already part of the force forward.

As we can see, the diagram forms a right triangle with f(R) as hypotenuse.

Using Pytagorean Theorem:

[tex][f(R)]^{2}=f^{2}+[f(left)]^{2}[/tex]

[tex][f(R)]^{2}=20^{2}+3^{2}[/tex]

[tex][f(R)]^{2}=409[/tex]

[tex]f(R)=\sqrt{409}[/tex]

f(R) = 20.22

Force forward equals 20.22lbf to the right.

The angle formed form the forward direction and the resulting force is

[tex]cos\theta=\frac{20}{20.22}[/tex]

cosθ = 0.989

θ = cos⁻¹(0.989)

θ = 8.5°

The forward force is to the right at angle 8.5° and magnitude 20.22lbf.

Answer:

D. an ellipse with the Sun at one focus

Explanation:

Based on Kepler's work, the orbit of a planet around the Sun is an ellipse with the Sun at one focus.

Hence according to Kepler's first law of planetary motion, the orbit of a planet around the Sun is an ellipse with the Sun at one focus.

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Answer: Yes

Explanation: Because Electromagnetic waves form a continuous spectrum and all types of electromagnetic wave travel at the same velocity through a vacuum (space) or air. The waves that form the electromagnetic spectrum are grouped in terms of their wavelength and their frequency.

Answer:

8

Explanation:

Finding time= t=change in velocity or distance/acceleration

so 32/9.5-5.5

32/4

8

Answer:

Motion map #3

Explanation:

because with velocity negative the arrows have to be the same size in the reverse direction.

Answer:

0.75 meters per second; north

Explanation:

speed (velocity)= distance/time

15 meters= distance

20 seconds= time

15/20= 0.75 meters per second; north

Hope this helps!

Answer:

Well we all know that bread and cake taste different. We do this on purpose.

Explanation:

When we make cake we add plenty of sugar to make it the delectable dessert we all know and love while when making bread we focus more on the corn starch and yeast's.