Which of the following equations describes the graph?
Identify a transformation of the function f(x) = x by observing the equation of the function g(x) = x − 90.

The base graph has been shifted down 90 units.

The base graph has been shifted right 90 units.

The base graph has been shifted left 90 units.

The base graph has been shifted up 90 units.

27.5 is the answer

For this case we know that the average rate of change of a function is given by this general expression:

m = f(b) - f(a)/ b-a

For this special case from the info in the table we have:

a =2 , f(2) = 9

a =4 , f(4) = 64

And replacing the data with the average rate formula we got:

m = 64 - 9/4 - 2 = 27.5

And then the best answer for this case would be:

27.5

The exponential function is a mathematical function represented by f (x) = \ exp or e ^ {x}. Unless otherwise specified, the term generally refers to a function of a positive value of a real variable, but it can also be extended to complex numbers or generalized to other mathematical objects such as matrices and Lie algebras.

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Answer:

y=-(2/3)x -9

Step-by-step explanation:

shuffle the equation so that y is alone in left hand side

The coefficient of x in the right hand side is the slope of line and the other term in right hand side is constant term

The slope-intercept form of the given equation will be y = -2x/3 - 9.

The meaning of slope-intercept form  is the equation of a straight line in the form y = mx + b where m is the slope of the line and b is its y-intercept.

Given an equation, 8x +12y = -108

Converting in  slope-intercept form,

12y = -108 - 8x

y = -2x/3 - 9

Hence, the slope-intercept form of the given equation will be

y = -2x/3 - 9.

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Answer:

Option A is probably the answer

If you have any question please contact me

Answer: A is the answer, should be right

$1799.10

Each year, the amount of money in the account is increased by 8%. This is the same as multiplying by 1.08 each year.

For 10 years, you multiply the original $100,000 by 1.08 a total of 10 times.

This tends to be simplified to:

[tex]100,000 * 1.08^{10}[/tex]

This gives $215892.4997.

This is paid back over 10 years, which is 10 x 12 months, or 120 months.

Divide the $215892.4997 by 120 to get the monthly payment of:

$1799.10 (round to 2 decimal places as it is a currency)

The obstacle has a total area of 69 square feet and a volume of 276 cubic feet.

To determine the total area, we calculate and add up the area of each shape.

The shapes in the figure are:

Using the area formula of each shape, the total area is:

Total = 0.5 * 1 * 6 + 0.5 * 5 * 8 + 2 * 2 + 7 * 6

Evaluate

Total = 69

Hence, the obstacle has a total area of 69 square feet.

This is calculated as:

Volume = Base area * Height

The height is 4.

So, we have:

Volume = 69 * 4

Evaluate

Volume = 276

Hence, the obstacle has a volume of 276 cubic feet.

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a)15000 square cm or 1.5 square meter

b)32

c)80 GSM

d)0.405 gram

refer to the following images for solutions :

Index cards are used for a wide range of applications and environments: in the home to record and store recipes, shopping lists, contact information, and other organizational data; in business to record presentation notes, project research and notes, and contact information; in schools as flashcards or other visual.

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Answer:

(0,3)

Step-by-step explanation:

The y-intercept is the point where the line touches the y-axis and x is 0.

Answer:

(0,3)

Step-by-step explanation:

The y-intercept is when the line crosses the y-axis, in this case the point is at (0,3)

Answer:

[tex]\huge\boxed{\sf C, \ D \ and \ E}[/tex]

Step-by-step explanation:

Given expression:

Distribute 2 to both terms.

We can also split 8f into 4f and 4f.

If we take 4 common

= 4(f + f + g)

[tex]\rule[225]{225}{2}[/tex]

Answer: Heya! ~

Step-by-step explanation:

Given: Expression 2(4f + 2g)

We have to choose an equivalent expression to the given expression  2(4f + 2g)

Consider the given expression 2(4f + 2g)  

Apply Distributive property, a( b + c) =ab + ac

We have,

a = 2, b = 4f and c = 2g

2(4f + 2g) = 8f + 4g

Now, take 4 common from each term, we have,

8f + 4f = 4 (2f + g)

Now, We have,

a = 2, b = 4f and c = 2g

2(4f + 2g) = 8f + 4g

Now, take 4 common from each term, we have,

8f + 4f = 4 (2f + g)

Now, an equivalent expression to the given expression  2(4f + 2g) is  8f + 4g and 4 (2f + g)

- Keira

i. Line BD = 6√2 cm

ii. Perimeter = 3 (π + 4) cm

iii. Area = 18 ( π - 2) cm

Let the length of BD = x

Since B is the midpoint of the arc AC, then ∠BOC = 15°

In ΔBDB

Let's use the trigonometric ration, tan

[tex]Tan 45 = \frac{BD}{CD}[/tex]

CD = x

Then, using the Pythagorean theorem

[tex]x^2 + x^2 = 12^2[/tex]

[tex]2x^2 = 144[/tex]

[tex]x^2 = \frac{144}{2}[/tex]

[tex]x = \sqrt{72}[/tex]

[tex]x = \sqrt{36 *2}[/tex]

[tex]x = 6\sqrt{2}[/tex]

Thus, line BD is [tex]6\sqrt{2}[/tex] cm

ii. Perimeter = BC + BD + CD

= 2πr/8 + x + r -  x

= π(12)/4 + r

= 3π + 12

= 3 ( π + 4) cm

iii. Area of shaded area = Area of BOC + Area of BOD

⇒ πr^2/8 × 1/2x^2

= π144/8 × 1/2(72)

= 18π - 36

= 18 ( π - 2) cm²

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The second bus is traveling at a speed of 33.3 miles per hour.

Given that the speed of first bus is 60 miles per hour , distance between both the buses is 700 miles after 8 hour.

We are required to find the speed of second car which is heading towards south.

If first car is travelling at a speed of 60 miles per hour then the distance of first car after 8 hours is 60*8=480 miles.

We have been given that the distance between both the cars after 8 hours is 700 miles,So,

Distance of second car after 8 hours=700-480=220 miles.

We know that the speed is equal to distance divided by time.

We know that we have calculated distance after 8 hours so the speed of second car will be =20/6

=33.3 miles per hour

Hence the speed of second car which is heading towards south is 33.3 miles per hour.

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The nth term of a sequence exists 2n2² - 4n+4 is 36.

The order of operations exists as a rule that describes the right sequence of measures for estimating a math expression. We can recognize the order utilizing PEMDAS: Parentheses, Exponents, Multiplication, and Division (from left to right), Addition, and Subtraction (from left to right).

[tex]$2*8*2^{2} - 4*8+4[/tex]

Follow the PEMDAS order of operations

Calculating the exponents, we get 2² = 4

[tex]= 2*8*4 - 4*8+4[/tex]

= 64-32 +4

= 36

Therefore, the nth term of a sequence that exists 2n2² - 4n+4 is 36.

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Answer:

C

Step-by-step explanation:

There are 6 outcomes and you are seeking 2 of them.  

2/6 or 1/3 1:3

Answer:

C = 364.24

Step-by-step explanation:

Comment

The circumference and the radius are related to one another. The constant relating them is pi which is a fixed number of 3.14 The formula for the circumference is C = 2*pi * r

Givens

pi = 3.14

r = 58 cm

Circumference = ?

Formula

C = 2*pi * r

C = 2 * 3.14 * 58

C = 364.24

Answer:

50a^6b^5

Step-by-step explanation:

I don't see answer choices, but this is the simplified version. To do this, multiply 10*5, a^3 * a^3 (which adds the exponents), and then b^3*b^2.

Answer:

Domain: ( Positive infinity, Negative Infinity)

Range: (-3, Positive Infinity )

Step-by-step explanation:

Answer:

it's only 2pi/B because the period of sin and cos is 2pi. If we were dealing with tan it'd be pi/B, since the period of tan is just pi.

The cost of one pen is Rs 15.

It is given that Ruby paid with a 500 rupee note and got Rs 90 back.

This means that she spent 410 rupees.

Therefore the cost of 24 books and 5 pens is Rs 410.

Let the cost of books be x and the cost of pens be y.

Therefore, we can form the following equations:

24x + 5y = 410                   (1)

12x + 10y = 280                   (2)

We have to find the value of y.

Multiply the second equation by 2:

24x + 20y = 560                   (3)

Now subtract the first equation from the third equation:

24x + 20y - 24x - 5y = 560 - 410

15y = 150

y = 15.

The variable y represents the cost of one pen.

This means that the cost of one pen is Rs 15.

Therefore, we have found that the cost of one pen is Rs 15.

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The cost of 1 bag of almond is $1.25

What is linear equation?

An equation in which the highest power of the variable is one is known as linear equation.

We can find the cost of 1 bag of almond as shown below:

Let the cost of 1 bag of peanut be $x

Let the cost of 1 bag of cashews be $y

Let the cost of 1 bag of almonds be $z

x + y + z=3      (1)

2x+2y=3.50

Dividing by 2

x + y=1.75

Putting in equation (1)

1.75+z=3

z=3-1.75

z=1.25

Hence, the cost of 1 bag of almond is $1.25

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A 99% confidence interval for the population mean of high school students that take the bus to school every day is b) ci=(44.34%, 54.43%)

We need to find the 99% confidence interval for the population mean of high school students that take the bus to school everyday

A confidence interval is a range of estimates for an unknown parameter. The confidence interval is calculated at the specified confidence level; the most common is the 95% confidence level, but sometimes other levels are used, such as 90% or 99%.

The confidence interval of proportions is given by:

π ± z √(π (1-π) /n)

π is the sample proportion.

z is the critical value.

n is the sample size.

For 99% confidence interval the value of z is 2.58

π = 321/650

The confidence interval is given by

=321/650 ± 2.58 √( (321/650) × [ 1 - (321/650) ] ÷ 650)

= (0.493846 ± 0.050594)

=(0.4434 , 0.5443)

=(44.34 % , 54.43 %)

Hence a 99% confidence interval for the population mean of high school students that take the bus to school every day is ci=(44.34%, 54.43%)

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Decreasing the pressure in the reaction vessel will keep this reaction from shifting to form more of the produce(ammonia).

This is defined as the force per unit area of a body and the S. I unit is in Pascal.

Ammonia production involves reaction between hydrogen and nitrogen gas in which pressure has an effect on the reaction rate unlike in solids and liquids. An increase in pressure will result in more products being formed and vice versa.

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Answer:

Step-by-step explanation:

hello :

the system is : y = 5x + 1

                        y = –x + 7

put : x=1  you have y = 6

Answer:

1. a)

[tex] \begin{gathered} \frac{2}{ \sqrt{3} - 1 } = \frac{2}{ \sqrt{3} - 1} \times \ \frac{ \sqrt{3} + 1}{ \sqrt{3} + 1 } \\ = \frac{2 \sqrt{3} + 2 } {( \sqrt{3} ) {}^{2} - 1 {}^{2} } = \frac{2 \sqrt{} 3}{3 - 1} = \frac{2 \sqrt{3} }{2} \\ = \sqrt{3} \end{gathered}[/tex]

[tex]\\[/tex]

b)

[tex]\begin{gathered} = > \: \: \frac{7}{ \sqrt{12} - \sqrt{5} } \\ \\ = > \: \: \frac{7}{ \sqrt{12} - \sqrt{5} } \times \frac{ \sqrt{12} + \sqrt{5} }{ \sqrt{12} + \sqrt{5} } \\ \\ = > \: \: \frac{7( \sqrt{12} + \sqrt{5} ) }{ {( \sqrt{12}) }^{2} - {( \sqrt{5}) }^{2} } \\ \\ = > \: \: \frac{7( \sqrt{12} + \sqrt{5}) }{12 - 5} \\ \\ => \: \: \frac{ \cancel{7}( \sqrt{12} + \sqrt{5} ) }{ \cancel{7}} \\ \\ => \: \: \sqrt{12} + \sqrt{5} \end{gathered}[/tex]

1-:

[tex] \displaystyle \frac{2}{ \sqrt{3} - 1 } [/tex]

[tex] \displaystyle = \frac{2}{( \sqrt{3} - 1)( \sqrt{3} + 1 } \\ [/tex]

[tex] \displaystyle2 \frac{ \sqrt{3} + 1 }{ \sqrt{3 {}^{2} - 1 {}^{2} } } [/tex]

[tex] \displaystyle2 \frac{ \sqrt{3} + 1}{3 - 1} [/tex]

[tex] \displaystyle \: \sqrt{3} + 1[/tex]

[tex] \displaystyle2 - ) \frac{7}{ \sqrt{12} - \sqrt{5} } [/tex]

[tex] \displaystyle\frac{ \sqrt{12} \sqrt{5} }{ \sqrt{12 {}^{2} } \times \sqrt{5 {}^{2} } } [/tex]

[tex] \displaystyle7\frac{ \sqrt{12} + \sqrt{5} }{7} = \sqrt{12} + \sqrt{5} [/tex]

[tex] \displaystyle3) = \frac{8 + 3 \sqrt{5} }{64 - 45} \\ = \frac{8 - 3 \sqrt{5} }{19} [/tex]

The plaintiff's testimony is admissible because plaintiff as personal knowledge of the statement of a party-opponent.

The recording is coincidental with firsthand knowledge. The person could testify based upon firsthand knowledge and could also lay the foundation under Article 9 to authenticate the tape.

In this case, the tape is not required as a matter of the original writing rule, giving the proponent options to offer testimony from memory, and/or the opportunity to corroborate the in-court testimony by a demonstrative exhibit

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Expression which is equivalent to [tex]$\sqrt{8 x^{7} y^{8}}[/tex] is [tex]$=2 \sqrt{2} x^{3} y^{4} \sqrt{x}$[/tex].

What are equivalent expressions?

Expressions that function identically despite having distinct appearances are called equivalent expressions. If two algebraic expressions are equivalent, then when we enter the same value(s) for the variable, the two expressions have the same value (s).

Solution of the given equation [tex]$\sqrt{8 x^{7} y^{8}}[/tex].

      [tex]$\sqrt{8 x^{7} y^{8}}=\sqrt{8} \sqrt{x^{7}} \sqrt{y^{8}}$[/tex]

                    [tex]$=\sqrt{8} \sqrt{x^{7}} \sqrt{y^{8}}$[/tex]

Simplify [tex]$\sqrt{x^{7}}: x^{3} \sqrt{x}$[/tex]

                     [tex]$=\sqrt{8} x^{3} \sqrt{x} \sqrt{y^{8}}$[/tex]

Simplify [tex]$\sqrt{y^{8}}: y^{4}$[/tex]

                     [tex]$=\sqrt{8} x^{3} \sqrt{x} y^{4}$[/tex]

                [tex]$\sqrt{8}=2 \sqrt{2}$[/tex]

                     [tex]$=2 \sqrt{2} x^{3} \sqrt{x} y^{4}$[/tex]

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The complete question is :

Which expression is equivalent to StartRoot 8 x Superscript 7 Baseline y Superscript 8 Baseline EndRoot? Assume x greater-than-or-equal-to 0. x y squared StartRoot 8 x cubed EndRoot 2 x cubed y cubed StartRoot x y squared EndRoot 2 x cubed y Superscript 4 Baseline StartRoot 2 x EndRoot 4 x cubed y Superscript 4 Baseline StartRoot x EndRoot

Assuming all the fishes caught by Bridget and her dad have the same total weight, then the first fish Bridget caught would weigh 5 ounces while the first fish caught by her dad weighed 17 ounces.

Weight can be defined as the force acting on an object or a physical body due to the effect of gravity. Also, the weight of a physical object (body) is typically measured in Newton or ounces.

First of all, we would determine the weight of all of the fishes caught by both Bridget and her father (dad) while translating the word problem into an algebraic equation as follows:

For Bridget, we have:

Bridget's fish = f + 2f + 3f + 2 + ½f + ⅗f

Bridget's fish = 7 f/10 + 2      ......equation 1.

For her dad, we have:

Dad's fish = 3f + 2 + ⅘f + 2f + 4 + ½f

Dad's fish = 6 3f/10 + 6            ......equation 2.

Equating eqn. 1 and eqn. 2, we have:

7 f/10 + 2 = 6 3f/10 + 6

7 f/10 - 6 3f/10 = 6 - 2

8f/10 = 4

8f = 40

f = 40/8

Bridget, f = 5 fishes.

Since her dad's fish weighed 2 more than 3 times, we have:

Dad = 3f + 2

Dad = 3(5) + 2

Dad = 15 +2

Dad = 17 ounces.

In conclusion, the first fish Bridget caught would weigh 5 ounces while the first fish caught by her dad weighed 17 ounces assuming all the fishes caught by Bridget and her dad have the same total weight.

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Complete Question:

Bridget went fishing with her dad. Bridget caught the first fish of the day, and it weighed f ounces. That day, she caught four more fish. One was 2 times the weight of the first fish, another was 2 more than 3 times the weight of the first fish, the next was 1/2 the weight of the first fish, and the last was 3/5 the weight of the first fish. Bridget’s dad caught four fish. The first fish he caught weighed 2 more than 3 times the weight of the first fish caught that day. One fish weighed 4/5 the weight of the first fish caught that day, one weighed 4 more than 2 times the weight of the first fish caught that day, and the last weighed 1/2 the weight of the first fish caught that day.

If all the fish Bridget caught have the same total weight as all the fish her dad caught, then the first fish Bridget caught weighed___ ounces and the first fish her dad caught___ weighed ounces.

Answer:

112

Step-by-step explanation:

If she takes 1/8 of an hour to complete one then she can finish 8 in 1 hour.

8 x 14 = 112

The total sale of the bedding set including 5% sale tax is $69.66

An equation is an expression that shows the relationship between two or more variables and numbers.

Discount = 20% of 86 = 0.2 * 86 = 17.2

Selling price of bed = 5% of 17.2 = 0.05 * 17.2 = 0.86

Total sale = 86 - 17.2 + 0.86 = 69.66

The total sale of the bedding set including 5% sale tax is $69.66

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Answer:

A

Step-by-step explanation:

[tex]\cos \theta=\frac{3}{8} \\ \\ \theta=\cos^{-1} \left(\frac{3}{8} \right) \\ \\ \theta \approx 68^{\circ}[/tex]