Answer:
Rb
Explanation:
Ionization energy is defined required energy to eliminate or remove an electron from an ion or atom.
From the given elements Rb or Rubidium has the lowest ionization energy as it has lowest shielding effect, so it easy to remove electron from it's shell.
The ionization energy generally decreases from top to bottom in groups due to lower shielding effect and outer electrons are loosely packed so easy to remove and increases from left to right across a period because of valence shell stability.
Rubidium has atomic number 37 and lies below than other given elements and also placed in the left side in the periodic table.
Hence, the correct option is Rb
How many atoms are in 13.0 g Sr
Answer: 7.505
×
10
22
atoms. (rounded to third place of decimal)
Explanation:
n the space below, briefly explain why the average times for the two CO2 molecules you calculated should have been similar (or at least not significantly different). If a CO2 molecule starts out surrounded by other CO2 molecules, does this influence how quickly it will reach the other side of the leaf? You might find it helpful to reset the simulation and to re-examine the initial configurations of molecules. Collisions influence how molecules move, but do molecules only collide with other molecules of the same substance?
Answer:
See explaination
Explanation:
No, the neurons don't use diffusion to transfer messages rather they employ the use of electrical impulses which are very fast for example, if we drop something accidentally on our foot we immediately move back to prevent ourselves from injury this quick reaction is possible because the signals are transferred in the form of electrical impulses.If diffusion was there to transfer the message then it would have taken very long time and our foot would have been bleeding too as diffusion process is relatively much slower.
This is due to collision of CO2 molecule with other molecules of CO2 and vander vals interaction between them which results in slow down of CO2 molecule and the CO2 molecules also collide with walls of leaf as well which also decreases the speed of CO2 molecule resulting it in taking more time.
The name carbohydrate comes from the fact that many simple sugars have chemical formulae that look like water has simply been added to carbon. (The suffix hydrate from the Greek word hydor ("water") means "compound formed by the addition of water") The actual chemical structure of carbohydrates doesn't look anything like water molecules bonded to carbon atoms. But it is nevertheless possible to chemically extract all the hydrogen and oxygen from many simple carbohydrates as water, leaving only carbon behind. If you search the Internet for "reaction of sulfuric acid and sugar" you will find some impressive videos of this. Suppose you had (200. g) of ordinary table sugar, which chemists call sucrose, and which has the chemical formula C1,H2,0. Calculate the maximum mass of water you could theoretically extract. Be sure your answer has a unit symbol, and round it to the correct number of significant digits?
Answer:
The maximum mass of water produced is [tex]m__{H_2O}} =116 \ g[/tex]
Explanation:
From the question we are told that
The mass of sucrose is [tex]m_s = 200 \ g[/tex]
The chemical formula for sucrose is [tex]C_{12} H_{22} O_{11}[/tex]
The chemical equation for the dissociation of sucrose is
[tex]C_{12} H_{22}O_{4} \to 12C + 11H_2O[/tex]
The number of moles of sucrose can be evaluated as
[tex]n = \frac{m}{Z}[/tex]
Where Z is the molar mass of sucrose which has a constant value of
[tex]Z = 342 \ g/mol[/tex]
So
[tex]n = \frac{200}{342}[/tex]
[tex]n =0.585[/tex]
From the chemical equation one mole of sucrose produces 11 moles of water so 0.585 moles of sucrose will produce x moles of water
Therefore
[tex]x = \frac{0.585 * 11}{1}[/tex]
[tex]x = 6.433 \ moles[/tex]
Now the mass of water produced is mathematically represented as
[tex]m__{H_2O}} = x * Z__{H_2O}[/tex]
Where [tex]Z__{H_2O}[/tex] is the molar mass of water with a constant values of [tex]Z__{H_2O}} = 18 \ g/mol[/tex]
So
[tex]m__{H_2O}} = 6.43* 18[/tex]
[tex]m__{H_2O}} =116 \ g[/tex]
What evidence supports the claim that social media
had more of an influence outside of the Arab world than
inside it?
Sixty five percent of Egyptians do not use the
internet at all
Eighty four percent of internet users visit social
networking sites for political news,
College educated people are more likely to use the
internet
Social media sites use bitly links to help spread
information
Answer:
Option A) Sixty-five percent of Egyptians do not use the internet at all.
Explanation:
Did it on edg
Answer:
A. 65% of Egyptians do not use the internet at all
Explanation:
Brainliest Answer Please!
nswer the following questions relating to HCl, CH3Cl, and CH3Br.HCl(g), can be prepared by the reaction of concentrated H2SO4(ag), with NaCl(s), asa.represented by the following equation.H2SO4(ag) + 2 NaCl(s) → 2 HCl(g) Na2SO4(ag)A student claims that the reaction is a redox reaction. Is the student correct?i.Justify your answer.Calculate the mass, in grams, of NaCl(s), needed to react with excess H2SO4(ag)ii.to produce 3.0 grams of HCl(g). Assume that the reaction goes to completion
Answer:
It is an example of double displacement reaction.
4.8 g of NaCl is needed to react.
Explanation:
Balanced reaction: [tex]H_{2}SO_{4}(aq.)+2NaCl(s)\rightarrow 2HCl(g)+Na_{2}SO_{4}(aq.)[/tex]
Here, oxidation states of H, S, O, Na and Cl do not change during reaction. Hence it is not a redox reaction.
In this reaction, cations and anions of the reactants interchange their partners during reaction. Hence, it is an example of double displacement reaction.
As [tex]H_{2}SO_{4}(aq.)[/tex] remain in excess amount therefore NaCl (s) is the limiting reagent. Hence production of HCl entirely depends on amount of NaCl used.
Molar mass of HCl = 36.46 g/mol
So, 3.0 g of HCl = [tex]\frac{3.0}{36.46}[/tex] mol of HCl = 0.082 mol of HCl
According to balanced equation-
2 moles of HCl are produced from 2 moles of NaCl
So, 0.082 moles of HCl are produced from 0.082 moles of NaCl
Molar mass of NaCl = 58.44 g/mol
So, mass of 0.082 moles of NaCl = [tex](0.082\times 58.44)[/tex] g = 4.8 g
Hence 4.8 g of NaCl is needed to react.
does nitrous oxide in a car kill the car or help it
Answer:
it makes it go faster
Explanation:
What is the freezing point of a solution of 210.0 g of glycerol, formula C3H8O3, dissolved in 350. g of water? Careful. First get molar mass and use molar mass to determine molality concentration. Then use freeze pt. depression formula to determine the change in freezing pt. Then determine the new freeze point. The freezing point depression constant for water is Kf= -1.86 oCelcius/molal. Report your answer rounded to 1 decimal point and do not include units.
Answer:
- 12.1
Explanation:
M(C3H8O3) = 3*12.0 + 8*1.0 + 3*16.0 = 92 g/mol
210.0 g C3H8O3 * 1 mol C3H8O3/92 g C3H8O3 = 210/92 mol C3H8O3
350.g = 0.350 kg H2O
Molality = mol soluty/ kg solvent = (210/92 mol C3H8O3) /(0.350 kg H2O) = =6. 522 molal
ΔT =i* Kf* m
(T2 - T1) = i* Kf* m
(T2 - 0°C) = 1*(-1.86°C/molal *6.522 molal)
T2= - 12.1°C
The change in freezing point and the new freeze point are -12.1°C and -12.1°C.
Given the following data:
Mass of glycerol = 210.0 gramsMass of water = 350.0 grams to kg = 0.35 kgChemical formula of glycerol = [tex]C_3H_8O_3[/tex]Freezing point depression constant for water, Kf = 0.512 °C/mWe know that the temperature at which water freezes is 0°C.
To determine the change in freezing point and the new freeze point:
First of all, we would determine the molar mass of glycerol:
Molar mass of glycerol ([tex]C_3H_8O_3[/tex]) = [tex]12 \times (1 \times 8)\times (16 \times 3)[/tex]
Molar mass of glycerol ([tex]C_3H_8O_3[/tex]) = [tex]12 \times (8)\times (48)[/tex]
Molar mass of glycerol ([tex]C_3H_8O_3[/tex]) = 92 g/mol.
Next, we would find the number of moles of glycerol that is required:
[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{210.0}{92}[/tex]
Number of moles = 2.28 moles
To find the molality concentration:
[tex]Molality = \frac{moles\;of \;solute}{mass\;of \;solvent} \\\\Molality = \frac{2.28}{0.35}[/tex]
Molality = 6.51 molal.
Mathematically, the freezing point elevation of a liquid is given by the formula:
[tex]\Delta T = K_f m[/tex]
Where:
[tex]\Delta T[/tex] is the change in temperature. Kf is the molal freezing point constant. m is the molality of solution.
Substituting the parameters into the formula, we have;
[tex]\Delta T = -1.86 \times 6.51[/tex]
Change in temperature = -12.1°C.
Now, we can determine the new freeze point:
[tex]\Delta T = T_n - T_f\\\\T_n = \Delta T + T_f\\\\T_n = -12.1 + 0[/tex]
New freeze point = -12.1°C.
Read more: https://brainly.com/question/13750908
What is the net electric charge of an ionic compound?
Ionic compounds contain both cations and anions in a ratio that results in no net electrical charge
Metal plating is done by passing a current through a metal solution. For example, an item can become gold plated by attaching the item to a power source and submerging it into an Au³⁺ solution. The item itself serves as the cathode, at which the Au³⁺ ions are reduced to Au(s). A piece of solid gold is used as the anode and is also connected to the power source, thus completing the circuit. What mass of gold is produced when 15.1 A of current are passed through a gold solution for 31.0 min?
Answer:
172 g
Explanation:
Let's consider the reduction of Au³⁺ to Au.
Au³⁺(aq) + 3 e⁻ → Au(s)
In order to find the mass of gold produced, we will use the following relations.
1 min = 60 s1 A = 1 C/sThe charge of 1 mole of electrons is 96,468 C (Faraday's constant).1 mole of Au is deposited when 3 moles of electrons circulate.The molar mass of Au is 196.97 g/mol.The mass of gold produced when 15.1 A of current are passed through a gold solution for 31.0 min is:
[tex]31.0min \times \frac{60s}{1min} \times \frac{15.1C}{s} \times \frac{1mole^{-} }{96,468C} \times \frac{3molAu}{1mole^{-} } \times \frac{196.97gAu}{1molAu} = 172 gAu[/tex]
3. Consider the transport of galactose across a semi-permeable membrane from the extracellular space ([galactose] = 2 mM) to the cytosol ([galactose] = 10 mM) under biochemically standard conditions. (R = 0.08206 L atm/mol K = 8.314 J/mol K) (15 pts.) If ATP hydrolysis liberates 30.5 kJ/mol at standard conditions, approximately how many grams of ATP (507.2 g/mol) would be required to transport 260 g of galactose from the extracellular space to the cytosol?
Answer:
15.63.
Explanation:
So, from the question, we are given the following parameters or data or information for solving this particular Question and they are;
(1). "semi-permeable membrane from the extracellular space ([galactose] = 2 mM) to the cytosol ([galactose] = 10 mM) under biochemically standard conditions. (R = 0.08206 L atm/mol K = 8.314 J/mol K) (15 pts.) "
(2). "If ATP hydrolysis liberates 30.5 kJ/mol at standard conditions".
(3). " (507.2 g/mol) would be required to transport 260 g of galactose from the extracellular space to the cytosol"
Step one: determine the difference to transport of galactose from extracellular space to cytosol.
This can be done by using the formula below:
Ratio = intracellular/ extracellular.
=> 10/2 = 5 mM.
Step two: so, from statement (2) and (3), the if 507.2 g/mol ATP = 30.5 kJ/mol, then 260 g/mol = ???
Therefore, 260 × 30.5 / 507.2 = 15.63 is the energy required.
Iron (Fe) undergoes an allotropic transformation at 912°C: upon heating from a BCC (α phase) to an FCC (γ phase). Accompanying this transformation is a change in the atomic radius of Fe—from RBCC = 0.12584 nm to RFCC = 0.12894 nm. The highest density planes in BCC structure is (110) and for FCC structure is (111). i. Compare the planar density of the two. (110) in BCC and (111) in FCC iron. EA = − 1.436 r ER = 5.8 × 10−6 r 9 ii. Do you think a (111) plane in FCC structure is more amenable to dislocation motion or (110) plane in BCC structure? What is an implication of that on the mechanical properties of materials.
Answer:
The description including its given problem is outlined in the following section on the clarification.
Explanation:
The given values are:
RBCC = 0.12584 nm
RFCC = 0.12894 nm
The unit cell edge length (ABCC) as well as the atomic radius (RBcc) respectively connected as measures for BCC (α-phase) structure:
√3 ABCC = 4RBCC
⇒ ABCC = [tex]\frac{4RBCC}{\sqrt{3} }[/tex]
⇒ = [tex]\frac{4\times 0.12584}{\sqrt{3}}[/tex]
⇒ = [tex]0.29062 \ nm[/tex]
Likewise AFCC as well as RFCC are interconnected by
√2AFCC = 4RFCC
⇒ AFCC = [tex]\frac{4RFCC}{\sqrt{2}}[/tex]
⇒ = [tex]\frac{4\times 0.12894}{\sqrt{2} }[/tex]
⇒ = [tex]0.36470 \ nm[/tex]
Now,
The Change in Percent Volume,
= [tex]\frac{V \ final-V \ initial}{V \ initial}\times 100 \ percent[/tex]
= [tex]\frac{(VFCC)unit \ cell-(VBCC)unit \ cell}{(VBCC)unit \ cell}\times 100 \ percent[/tex]
= [tex]\frac{(aFCC)^3-(aBCC)^3}{(aBCC)^3}\times 100 \ percent[/tex]
= [tex]\frac{(0.36470)^3-(0.29062)^3}{(0.29062)^3}\times 100 \ percent[/tex]
= [tex]97.62 \ percent (approximately)[/tex]
Note: percent = %
The half-life of carbon-14 is 5,715 years. After 29,000 years (5 half-lives) have elapsed, how much carbon-14 remains in a sample
that originally contained 0.32 g of carbon-14
A 0.0409
B. 0.0809
C 0.109
D. 0.0109
E 0209
After 3 half-life, 12 of the 14 of the C-14 = 18 of the C-14 would remain.
Given the balanced equation representing a redox reaction:
2Al + 3Cu2+ → 2Al3+ + 3Cu
Which statement is true about this reaction?
The given question is incomplete, the complete question is:
Given the balanced equation representing a redox reaction:
2Al + 3Cu2+ --> 2Al3+ + 3Cu
Which statement is true about this reaction?
(1) Each Al loses 2e- and each Cu2+ gains 3e-
(2) Each Al loses 3e- and each Cu2+ gains 2e-
(3) Each Al3+ gains 2e- and each Cu loses 3e-
(4) Each Al3+ gains 3e- and each Cu loses 2e-
Answer:
The correct answer is option 2, that is, in the given reaction each of Al loses three electrons and each of the Cu^2+ ion acquires two electrons.
Explanation:
To understand the concept, let us suppose that when an atom A loses an electron, it turns into an atom A^1+, and becomes A^2+ when it loses two electrons. On the other hand, when an atom A gains an electron, it turns into A^1- and becomes A^2- when it acquires two electrons.
Therefore, in the given case, 2Al + 3Cu^2+ --> 2Al^3+ + 3Cu, each of the Al atom turns into Al^3+ when it loses three electrons, and when each of the Cu^2+ ions acquires two electrons, it turns into Cu (Cu^2+ ^2- = Cu).
Is HSO4- a polar or non polar molecule
Answer:
Polar molecule.
Explanation:
Hello,
In this case, hydrogen sulfate has in its structure sulfur-oxygen and oxygen-hydrogen bonds which are both polar since the electronegativity difference is between 0.7 and 1.7 (0.86 and 1.24 respectively), for that reason, such quality makes hydrogen sulfate a polar molecule, for that reason it is largely soluble in water.
Best regards.
Use the drop-down menus to fill in the
corresponding cells in the table to the right.
Answer:
a: 1 amu
b: +1
c: neutron
d: 1 amu
Explanation:
Substituents on an aromatic ring can have several effects on electrophilic aromatic substitution reactions. Substituents can activate or deactivate the ring to substitution, donate or withdraw electrons inductively, donate or withdraw electrons through resonance, and direct substitution either to the ortho/para or to the meta positions.
1. From the following list, select the substituents that have the indicated property. The substituents are written as -XY, where X is the atom directly bound to the aromatic ring.
a. Activation of the ring towards substitution
i. -CF3
ii. -NO2
iii. -OCOCH3
iv. -NH2
Answer:
iv. -NH₂
Explanation:
The amine group is an activating substituent and provides an ortho-para orientation.
The free electrons in the nitrogen atom provide stabilization by resonance in the sigma complex if the attack by the electrophilic reactant occurs in the positions ortho or para with regards to the nitrogen atom.
When Fe2O3(s) reacts with H2(g) to form Fe(s) and H2O(g), 98.8 kJ of energy are absorbed for each mole of Fe2O3(s) that reacts. Write a balanced thermochemical equation for the reaction with an energy term in kJ as part of the equation. Note that the answer box for the energy term is case sensitive. Use the SMALLEST INTEGER coefficients possible and put the energy term in the last box on the appropriate side of the equation. If a box is not needed, leave it blank.
Answer:
Explanation:
Fe₂O₃(s) + 3H₂(g) = 2Fe (s) + 3H₂O - 98.8 kJ .
one mole of ferric oxide reacts with 3 mole of hydrogen to give 2 mole of iron and 3 mole of water . 98.8 kJ of heat is absorbed .
If you pour 9.0 g of sodium chloride into water to produce 240 mL of solution, what will the molarity be?
Explanation:
Molarity = mol/liter
Solution 240 mL = NaCl 9.0 g
Solution 1000 mL = NaCl 9.0/240 × 1000 = ..... g
mol NaCl = g/MW
MW NaCl = ?....
...........
Molarity = ......... Molar
Watching the assignment without knowing how to solve the questions is the worst thing to experience hope someone can help with this question and the privous ones too
Answer:
- 622.5kJ
Explanation:
1) 2NH3 + 3N2O ----> 4N2 + 3H2O ΔH° 1= - 1010kJ
- 3 (N2O + 3H2 ---> N2H4 + H2O ΔH° 2 = - 317 kJ)
2) 2NH3 + 3N2O ----> 4N2 + 3H2O ΔH° 1= - 1010kJ
- 3N2O - 9 H2 ----> - 3N2H4 - 3H2O - 3ΔH° 2 = 3*317 kJ
2NH3 + 3N2H4 --->4N2+9H2, ΔH° 1 - 3*ΔH° 2
2NH3 + 3N2H4 --->4N2+9H2, ΔH° 1 - 3*ΔH° 2
3) -(2NH3 +1/2O2 ---> N2H4 + H2O, ΔH°3 = -143 kJ)
-2NH3 - 1/2O2 ---> - N2H4 - H2O, - ΔH°3 = 143 kJ
2NH3 + 3N2H4 --->4N2+9H2, ΔH° 1 - 3*ΔH° 2
-2NH3 - 1/2O2 ---> - N2H4 - H2O, - ΔH°3 = 143 kJ
4N2H4 + H2O ---> 4N2 + 9H2 + 1/2O2, ΔH° 1 - 3*ΔH° 2 - ΔH°3
4)
H2 + 1/2O2 ---> H2O, ΔH° 4 = - 286 kJ
9*(H2 + 1/2O2 ---> H2O, ΔH° 4 = - 286 kJ)
9H2+ 9/2 O2 ---> 9H2O, 9*ΔH° 4 = 9*(- 286) kJ
4N2H4 + H2O ---> 4N2 + 9H2 + 1/2O2, ΔH° 1 - 3*ΔH° 2 - ΔH°3
9H2+ 9/2 O2 ---> 9H2O, 9*ΔH° 4 = 9*(- 286) kJ
4N2H4 +4O2 --->4N2+8H2O, ΔH° 1 - 3*ΔH° 2 - ΔH°3 + 9*ΔH° 4
5)
1/4*(4N2H4 +4O2 --->4N2+8H2O, ΔH° 1 - 3*ΔH° 2 - ΔH°3 + 9*ΔH° 4
N2H4 +O2 --->N2+2H2O, 1/4( ΔH° 1 - 3*ΔH° 2 - ΔH°3 + 9*ΔH° 4)
6)
N2H4 +O2 --->N2+2,
1/4( ΔH° 1 - 3*ΔH° 2 - ΔH°3 + 9*ΔH° 4)=
=1/4(-1010kJ - 3*(-317kJ) - (-143kJ) + 9*(-286kJ))= - 622.5 kJ
what are the implications of increased amount of CO2 in the atmosphere
Answer:
global warming and destruction of the ozone layer
Explanation:
if Carbon dioxide are high in number , it will cause destruction of the ozone layer which will result to global warming
For a theoretical yield of 20 g and actual yield of 12 g, calculate the percent yield for a chemical reaction. Answer in units of %.
Please and Thank you!
Answer:
Percent yield for chemical reaction = 60%
Explanation:
Given:
Theoretical yield of chemical reaction = 20 gram
Actual yield of chemical reaction = 12 gram
Find:
Percent yield for chemical reaction = ?
Computation:
[tex]Percent\ yield \ for\ chemical\ reaction = [\frac{Actual yield}{Theoretical yield} ]100\\\\Percent\ yield \ for\ chemical\ reaction = [\frac{12}{20} ]100\\\\Percent\ yield \ for\ chemical\ reaction = [0.6 ]100\\\\Percent\ yield \ for\ chemical\ reaction = 60[/tex]
Percent yield for chemical reaction = 60%
Sketch the simple Lewis dot structures and the predicted VSEPR
shapes for each of the following species. Be sure to clearly indicate
lone pair electrons, multiple bonds (double or triple), and any three-
dimensionality (using dashes and wedges). For any ions, don’t forget
to account for the charge when calculating valence electrons! Only
expand the octet of the central atom when absolutely necessary.
A. CO2
B. CS2
C. SeCL
D. SO2
E. SO32-
F. CO32-
G. N3-
Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
Which of the two compounds, H_2NNH_2 and HNNH, has the strongest nitrogen-nitrogen bond, and which has the shorter nitrogen-nitrogen bond.
a. H_2NNH_2 has the strongest nitrogen-nitrogen bond and HNNH has the shorter nitrogen-nitrogen bond.
b. H_2NNH_2 has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
c. HNNH has the strongest nitrogen-nitrogen bond and H_2NNH_2 has the shorter nitrogen-nitrogen bond.
d. HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Answer:
d. HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Explanation:
The Lewis structure of HNNH comprises of a double bound between the two nitrogen atoms, therefore each nitrogen still carrying a lone pair of electron and a single bond between each nitrogen to it respective hydrogen.
Also for H_2NNH_2; there exists a single nitrogen to nitrogen bond because hydrogen is sharing two bonds already with the nitrogen; the nitrogen also possess a lone pair of electron and the last bond is a single bond between the nitrogen to nitrogen atom ( therefore obeying the octet rule).
The bond strength and bond angle is stronger and shorter in double bonds than single bonds, thus HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Answer:
d. HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Explanation:
The Lewis structure of HNNH comprises of a double bound between the two nitrogen atoms, therefore each nitrogen still carrying a lone pair of electron and a single bond between each nitrogen to it respective hydrogen.
Also for H_2NNH_2; there exists a single nitrogen to nitrogen bond because hydrogen is sharing two bonds already with the nitrogen; the nitrogen also possess a lone pair of electron and the last bond is a single bond between the nitrogen to nitrogen atom ( therefore obeying the octet rule).
The bond strength and bond angle is stronger and shorter in double bonds than single bonds, thus HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Which of the following terms is defined by the measure of mass per unit of volume?
gravity
density
weight
acceleration
Answer:
I'm glad you asked!
Explanation:
Gravity is a force which keeps people from floating around.
Density is usually used for mass or volume.
Weight is how heavy something is.
Acceleration is when something increases in height,speed etc.
The answer is Density.
assume you have a 500 g sample of a radioactive isotope with a half-life of 100 years. fill in the table showing how many grams of material will remain after the indicated time has passed.
How many ng are there 5.27x10-13 kg
Answer:
This involves metric conversion and one can easily use dimensional analysis, assuming you know the conversion factors.
1 ng = 10-9 g, or put another way 109 ng = 1 g
1 kg = 103 g
5.27x10-13 kg x 1 g/1x10-3 kg x 1x109 ng/g = 5.27x10-1 ng = 0.527 ng
Looking at the individual steps and following the units, we have...
5.27x10-13 kg x 1 g/1x10-3 g = 5.27x10-10 g (kg cancel leaving g)
5.27x10-10 g x 1x109 ng/g = 5.27x10-1 ng = 0.527 ng (g cancel leaving ng)
(14.1.50) 0.03 mol of helium are enclosed in a cylinder with a piston which maintains a constant pressure in the helium. Initially the helium is immersed in thermal bath with at 250K. Suddenly, the helium is removed from this thermal bath and plunged into a thermal bath at temperature 350K. Determine (a) the increase in the entropy of the helium. (Hint the entropy change for the helium is the same as if it had been taken through this temperature change by a reversible process.) (b) the increase in entropy of the universe. (Answer: 0.032 J/K)
Answer:
a) 0.210 j /k
b) 0.032 j/k
Explanation:
Find the attachment for solution
Which phase has the lowest entropy? Why? How does a change in phase affect entropy changes in a reaction?
Answer:
The solid phase has the lowest entropy.
Explanation:
Entropy (S) is the measure of how spread out or dispersed the energy of a system is among the different possible ways that system can contain energy. The greater the dispersal, the greater is the entropy.
In a solid, the atoms or molecules are confined to fixed positions, thus, the dispersal is minimal and the entropy is at its lowest.
Find the pH of a solution whose hydronium concentration is 1.0 x 10-11
Answer:
11
Explanation:
pH=-log(H+)
What is the unit volume in mL
Answer:
4.35 mL
Explanation:
The water line falls halfway inbetween the 4.4 and 4.3 mark.
The number halfway between 4.3 and 4.4 is 4.35.
Therefore, the volume of the liquid in the graduated cylinder is 4.35 mL.