Answer:
Possibility of a single replacement reaction
Explanation:
The activity series of element can be used to predict the possibility of a single replacement reaction.
A single replacement reaction is one in which one substance is replacing the other. The replacement of a metallic ion in solution by a metal atom higher in the activity series than the metal in solution falls into this category of reactions. The relative position of the two elements in the activity series provides the driving force for this kind of reaction. If the element to replace the other is more reactive, the reaction will occur. If it is less reactive, the reaction will not occur.Answer:
Possibility of a single replacement reaction
Explanation:
A 10.0 cm³ sample of copper has a mass of 89.6 g. What is the density of copper?
Answer:
d = 8.96 g/cm³
Explanation:
Given data:
Volume of sample = 10.0 cm³
Mass of copper = 89.6 g
Density of copper = ?
Solution:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
d = 89.6 g/ 10.0 cm³
d = 8.96 g/cm³
Electromagnetic waves are ? and have ?
more energy moving from left to right on the electromagnetic
Electromagnetic waves are
radiation diagram
shorter/less
o longer/more
shorter/more
longer/less
Answer:
longer/less
Explanation:
In moving from left to right on the periodic table, electromagnetic waves have longer wavelength and less energy.
The electromagnetic radiation diagram is made up of electromagnetic waves.
From left to right, the energy of the wave decreases. Waves at the left most edge have the highest energy. As we move rightward, the wavelength also becomes longer. The frequency also reduces. Wavelength and energy are inversely proportional.Which of the following acts as a catalyst in catalytic converters?
Metal acts as a catalyst in catalytic converters
Write balanced equations for each of the processes, choosing from the following substances as reactants: BaCl2 O2 H2SO4 HNO3 C2H5OH H2O Ca(OH)2 K Na2CrO4 KOH Pb(NO3)2
Answer:
BaCl₂ and H₂SO₄
Explanation:
The reaction is the precipitation of BaSO₄ from solution.
This means that our reactants must contain the Ba ion and SO₄²⁻ ion. The reactants that meet this criteria are the; BaCl₂ aand H₂SO₄
The reaction is given as;
BaCl₂ + H₂SO₄ --> BaSO₄ + 2HCl
The Lewis dot diagram for LiBr
If 22.5 L of nitrogen at 90 Kpa are compressed to 40 Kpa at a constant temperature. What is the new volume?
Answer:
51 L
Explanation:
Step 1: Given data
Initial volume of nitrogen (V₁): 22.5 LInitial pressure of nitrogen (P₁): 90 kPaFinal volume of nitrogen (V₂): ?Final pressure of nitrogen (P₂): 40 kPaStep 2: Calculate the final volume of nitrogen
The volume of a gas is inversely proportional to the pressure. If we consider nitrogen as an ideal gas at a constant temperature, we can find the final volume using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 90 kPa × 22.5 L / 40 kPa
V₂ = 51 L
How many moles of sulfur atoms are there in 5.0 g of sulfur?
Answer:
Number of moles = 0.153 mol
Explanation:
Given data:
Mass of sulfur = 5 g
Number of moles of sulfur atom = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of sulfur is 32. 065g/mol.
By putting values,
Number of moles = 5 g/ 32.06 g/mol
Number of moles = 0.153 mol
Which of these compounds is most likely to contain an ionic bond?
O CaCl2
O CHA
SO2
O H2
Answer:
O CaCl₂
Explanation:
The compound most likely to contain an ionic bond is CaCl₂ because it is the only specie with a metal and non-metal.
The metal here is Ca and non-metal is Cl.
In this bond type, there is a transfer of electrons from the metal to the non-metal. There must be a significant electronegativity difference between the two bodies for this bond to form. The metal Calcium loses two electrons and becomes isoelectronic with argon. Two chlorine non-metal gain one of the electrons each and becomes stable. The electrostatic attraction between the oppositely charged ions results in the ionic bonding.One of the following bonds is nonbonding intermolecular interaction Select one: a. ionic bond b. Van der Waals C. covalent bond d. polar bond
Answer:
b. Van der Waals
Explanation:
Non-bonding intermolecular interaction is simply the same as intermolecular forces between molecules.
One such example from the given choice is the van der waals forces.
Van der Waals forces are weak forces of attraction joining non - polar molecules together. They exist between layers of substances. They are often described as non-bonding intermolecular interaction.Which atom has the most pronounced metallic properties
1) 1s²2s²2p⁵ 2) 1s²2s²2p³
3)1s²2s²2p⁶3s² 4) 1s²2s²2p⁶3s²3p⁴
Plzz helppppppppppppp
Answer:
i got you stop doing work and forget about this one class you will still pass trust me i did it it 8th grade and still made it to 9th but today im not even in school so just do better in your other classes
Explanation:
How many moles of water would be produced from 3 moles of oxygen in the following reaction? Don’t forget to include units in your answer.
Answer:
6moles of water
Explanation:
Given parameters:
Number of moles of oxygen = 3moles
Reaction equation:
2H₂ + O₂ → 2H₂O
Unknown:
Number of moles of water formed = ?
Solution:
To solve this problem;
compare the number of moles in the reaction.
1 mole of oxygen gas will produce 2 mole of water
3 moles of oxygen gas will produce 3 x 2 = 6moles of water.
A solution is prepared by dissolving 74.2 g NaI in 527 g of water. Determine the mole fraction of NaI if the final volume of the solution is 565 mL.
a. 8.84 times 10^-2
b. 1.40 times 10^-3
c. 6.04 times 10^-3
d. 1.32 times 10^-2
e. 1.65 times 10^-2
Answer:
The correct answer is option e, that is, 1.65 * 10^-2.
Explanation:
Based on the given information, the weight of NaI given is 74.2 grams and the weight of water given is 527 grams.
The final volume of the solution given is 566 ml.
The formula to calculate the moles is weight/molecular mass,
The moles of NaI will be,
= 74.2/150 = 0.494
Now moles of water will be,
= 527/18 = 29.3
The mole fraction of NaI will be,
= 0.494 / (0.494 + 29.3)
= 0.0165 or 1.65 * 10^-2
Hence, the mole fraction of NaI is 1.65 * 10^-2
9) Consider the reaction of C6H6 Br2 C6H5Br HBr a. What is the theoretical yield of C6H5Br if 42.1 g of C6H6 react with 73.0 g of Br2
Answer:
71.7 g of C₆H₅Br are produced at the theoretical yield.
Explanation:
The reaction is:
C₆H₆ + B₂ → C₆H₅Br + HBr
This is an easy excersie, stoichiometry is 1:1
We determine moles of reactants:
42.1 g / 78g/mol = 0.540 moles of benzene
73 g / 159.80 g/mol = 0.457 moles of hydrogen bromide
Certainly, the HBr is the limiting reactant, because I need 0.540 moles of HBr for 0.540 moles of benzene and I only have, 0.457 moles.
0.457 moles of HBr will produce 0.457 of bromobenzene, at the 100 % yield reaction (theoretical yield)
We convert the moles to mass: 0.457 g . 157 g/mol = 71.7 g
The theoretical yield of the reaction has been 0.457 mol.
The balanced chemical equation for the reaction can be given by:
[tex]\rm C_6H_6\;+\;Br_2\;\rightarrow\;C_6H_5Br\;+\;HBr[/tex]
Accordingly, 1 mole of benzene will give 1 mole of Bromobenzene and 1 mole of Hydrobromide.
The moles can be calculated as;
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
Moles in 42.1 grams Benzene:
Moles of Benzene = [tex]\rm \dfrac{42.1}{78}[/tex]
Moles of Benzene = 0.540 mol
Moles of Bromine = [tex]\rm \dfrac{73}{159.80}[/tex]
Moles of Bromine = 0.457 mol.
The limiting reactant in the reaction has been the one that has been present in the lesser quantity as the other reactant to continue to the product formation.
The 1 mole of Benzene requires 1 mole of bromine. So, 0.54 mol of benzene requires. 0.54 mol of bromine. Since the available bromine has been 0.457 mol, Bromine has been the limiting reactant.
The theoretical yield of the reaction will be based on the concentration of Bromine.
Thus, 1 mol of Bromine forms 1 mol of Bromobenzene.
0.457 mol of Bromine will form 0.457 mol of bromobenzene.
The theoretical yield of the reaction has been 0.457 mol.
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A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next few minutes? Molecules in both the metal and the surrounding air will start moving at lower speeds. Molecules in both the metal and the surrounding air will start moving at higher speeds. The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up. The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Answer:
150 gs for me aww thanks
Explanation:
Answer:
D) The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.
Explanation:
Edg
What is the atomic number of this atom?
Answer:
1
Explanation:
1. A gas at 116 kPa and 303 K fills a container at 2.0 x 105 L. If the temperature changes to 293 K, What is the new pressure?
Answer:
P₂ = 112.17 KPa
Explanation:
Given data:
Initial pressure = 116 KPa
Initial temperature = 303 K
Final temperature = 293 L
Final pressure = ?
Volume= constant
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
116 KPa / 303 K = P₂/293 K
P₂ = 116 KPa × 293 K / 303 K
P₂ = 33988 KPa. K / 303 K
P₂ = 112.17 KPa
7. A gas takes up a volume of 15 liters, has a pressure of 3.3 atm, and a temperature of 299 K. If I raise the
temperature to 350 K and lower the pressure to 1050 mmHg, what is the new volume of the gas?
8. I have an unknown volume of gas held at a temperature of 115 K in a container with a pressure of 60.0
atm. If by increasing the temperature to 225 K and decreasing the pressure to 30.0 atm causes the volume
of the gas to be 25 liters, how many liters of gas did I start with?
9. A gas has a temperature of 14oC, and a volume of 5.5 liters. If the temperature is raised to 29oC and the
pressure is not changed, what is the new volume of the gas?
10. A gas that has a volume of 28 liters, a temperature of 65oC, and an unknown pressure has its volume
increased to 36 liters and its temperature decreased to 35oC. If I measure the pressure after the change to
be 2.0 atm, what was the original pressure of the gas?
Answer:
See explanation
Explanation:
7) P1 =3.3 atm
V1= 15 litres
T1 = 299 K
T2 = 350 K
P2 = 1050 mmHg/760 = 1.38 atm
V2?
From;
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
V2 = P1V1T2/P2T1
V2 = 3.3 * 15 * 350/1.38 * 299
V2 = 17325/412.62
V2 = 42 litres
8) V1= unknown
T1= 115 K
P1 = 60 atm
T2= 225 K
P2 = 30 atm
V2 = 25 litres
From;
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
V1 = P2V2T1/P1T2
V1 = 30 * 25 * 115/ 60 * 225
V1 = 86250/13500
V1 = 6.4 litres
9) T1 = 14 + 273 = 287 K
V1 = 5.5 liters
T2 = 29 + 273 = 302 K
V2 = the unknown
From Charles law;
V1/T1 = V2/T2
V1T2 = V2T1
V2 =V1T2/T1
V2 = 5.5 * 302/ 287
V2 = 5.8 litres
10) V1= 28 litres
T1= 65 + 273 = 338 K
P1 = the unknown
V2 = 36 liters
T2 = 35 + 273 = 308 K
P2 = 2 atm
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
P1 = P2V2T1/V1T2
P1 = 2 * 36 * 338/ 28 * 308
P1 = 24336/8624
P1 = 2.82 atm
How are work and force related
Answer:
Work is done when a force that is applied to an object moves that object. The work is calculated by multiplying the force by the amount of movement of an object (W = F * d). A force of 10 newtons, that moves an object 3 meters, does 30 n-m of work. ... You have to exert a force AND move something to qualify as doing work.
Explanation:
L
shaped polygon name
Answer:
Yes, it's a hexagon, specifically a non-convex hexagon on account of having a concave angle. There's no specific official name that I'm aware of. "L-shaped hexagon" might actually be sufficient.
Explanation:
One answer is a right-angled concave hexagon, but you do need to cite some context. – Andrew Leach♦ Sep 8 '15 at 9:53. Well... since the Greek letters "gamma" and "lambda" are shaped roughly like the letter "L," you might call it "gammoid" or "lambdoid." I just invented these words.
In some molecules and polyatomic ions, the sum of the valence electrons is odd and as a result the octet rule fails.
a. True
b. False
Answer:
a
Explanation:
Answer:
True
Explanation:
as electronegativity difference increases, bond length decreases. when a metal gains an electron, the process is endothermic. ... atoms surrounded by 7 valence electrons tend to lose electrons
Which reactions have a positive ΔSrxn? 2A(g)+B(g)⟶4C(g) 2A(g)+3B(g)⟶4C(g) A(s)+2B(g)⟶C(g) 2A(g)+B(s)⟶3C(g)
Answer:
Most likely:
[tex]{\rm 2\, A}\, (g) + {\rm B}\, (g) \to 4\, {\rm C}\, (g)[/tex] (the first choice.)
[tex]2\, {\rm A}\, (g) + {\rm B}\, (s) \to 3\, {\rm C}\, (g)[/tex] (the fourth choice.)
Explanation:
[tex]\Delta S_\text{rxn}[/tex] denotes the entropy change in a reaction.
The value of [tex]\Delta S_\text{rxn}[/tex] is greater than zero if the reaction corresponds to an increase in entropy. In other words, entropy should be higher for the products of this reaction than for its reactants.
The exact entropy of each species depends on both the environment (temperature, pressure, etc.) and on the structure of the species. However, there are some general trends.
Consider one mole of some gaseous molecules and one mole of some solid particles. If that gas and that solid are under the same temperature and pressure, which one would have a higher entropy? Generally, the gas would have a higher entropy.
Also, the entropy of a gas is approximately proportional to the number of particles in that gas.
Therefore, it is likely that [tex]\Delta S_\text{rxn}[/tex] would be positive for a reaction if there are more gas particles among the products than among the reactants.
Note that [tex](s)[/tex] is the state symbol for solids, whereas [tex](g)[/tex] is the state symbol for gases.
In this question:
First reaction: [tex]{\rm 2\, A}\, (g) + {\rm B}\, (g) \to 4\, {\rm C}\, (g)[/tex].
In each unit of this reaction, there are:
two gas particles among the reactants.four gas particles among the products. The number of gas particles that this reaction produces is larger than the number of gas particles that it consumes. Therefore, it is likely that [tex]\Delta S_\text{rxn} > 0[/tex] for this reaction.Second reaction: [tex]{\rm 2\, A}\, (g) + 3\, {\rm B}\, (g) \to 4\, {\rm C}\, (g)[/tex].
In each reaction, there are:
five gas particles among the reactants.four gas particles among the products. The number of gas particles that this reaction produces is smaller than the number of gas particles that it consumes. Therefore, it is likely that [tex]\Delta S_\text{rxn} < 0[/tex] for this reaction.Third reaction: [tex]{\rm A}\, (s) + 2\, {\rm B}\, (g) \to {\rm C}\, (g)[/tex].
In each reaction, there are:
two gas particles among the reactants.one gas particle among the products. The number of gas particles that this reaction produces is smaller than the number of gas particles that it consumes. Therefore, it is likely that [tex]\Delta S_\text{rxn} < 0[/tex] for this reaction.Fourth reaction: [tex]{\rm 2\, A}\, (g) + {\rm B}\, (s) \to 3\, {\rm C}\, (g)[/tex].
In each unit of this reaction, there are:
two gas particles among the reactants (note that the state symbol [tex](s)[/tex] suggests that [tex]{\rm B}\, (s)[/tex] is not a gas.)three gas particles among the products. The number of gas particles that this reaction produces is larger than the number of gas particles that it consumes. Therefore, it is likely that [tex]\Delta S_\text{rxn} > 0[/tex] for this reaction.As a metal such as lead is heated past its melting point, what happens to the average kinetic energy of the atoms
Answer:
The kinetic energy increases
Explanation:
As a metal such as lead is heated past its melting point, the average kinetic energy of the atoms increases.
When temperature is increased the kinetic energy of the atoms increase which also increases the random movement of the atoms.
When such happens the distance between the atoms is usually decreased which leads to the elastic collision that occurs.
A closed container in lab contains a sample of oxygen gas. When the temperature in lab is 16.3 degrees Celcius, the pressure in the container is 9.30 atm. What would the temperature in lab be (in Celcius) if the pressure in the container was 17.7 atm? Assume the mol and volume of the container are constant. Record your answer as a number with the correct significant figures.
Answer:
T₂ = 550.60 K
Explanation:
Given data:
Initial temperature = 16.3°C (16.3+273 = 289.3 K)
Initial pressure = 9.30 atm
Final temperature = ?
Final pressure = 17.7 atm
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
9.30 atm / 289.3 K = 17.7 atm/T₂
T₂ = 17.7 atm × 289.3 K / 9.30 atm
T₂ = 5120.61 atm. K /9.30 atm
T₂ = 550.60 K
A normal saline solution for injecting hospital patients is 0.90 % NaCl. What is the mass of NaCl
dissolved in 50.0 g of 0.90 % saline solution Report only the numerical portion of the problem,
with two signifcant figures.
Answer:
0.45 g
Explanation:
What describes the behavior of an ideal gas?
A. It’s properties at absolute zero
B. The kinetic theory of gases
C. The phase diagram of the gas
D. The ideal gas law
Answer:
The answer is D
Explanation:
for a p e x
The ideal gas law describes the behavior of gases under ideal conditions.
What is the ideal gas law?It is a law that explains that an ideal gas is considered as part of the group of theoretical gases because it is composed of point particles that move randomly and do not interact with each other.
According to classical thermodynamics, this law is a formula that allows us to relate the properties of gases, such as pressure, the volume occupied by the gas and its temperature.
Therefore, we can conclude that the ideal gas law describes the behavior of gases under ideal conditions.
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How are put carbon, oxygen, and hydrogen different from the compound ethanol which contains all three of those elements
All the elements such as carbon, oxygen, and hydrogen found in ethanol but when they are seperated from ethanol they have totally different compound. They are pure element and ethanol is a mixture.
What is ethanol?Ethanol is a colourless liquid which catches fire easily and it is produced by the process of natural fermentation of sugars or alcohol.
The chemical formula of ethanol is C2H5OH, molar mass is 46.07 g/mol and its boiling point is 78.37 °C with density 789 kg/m cube.
Ethanol is also known as alcohol which is colourless and slightly toxic chemical compound and ethanol forms water as well as carbon dioxide.Ethanol is a colourless liquid which catches fire easily and it is produced by the process of natural fermentation of sugars or alcohol.
Therefore, All the elements such as carbon, oxygen, and hydrogen found in ethanol but when they are seperated from ethanol they have totally different compound. They are pure element and ethanol is a mixture.
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Give the name for the molecular compound with the the formula P2I4.
Answer:
Diphosphorus tetraiodide
Explanation:
Diphosphorus tetraiodide is an orange crystalline solid with the formula P2I4. It has been used as a reducing agent in organic chemistry. It is a rare example of a compound with phosphorus in the +2 oxidation state, and can be classified as a subhalide of phosphorus.
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The name of the molecular compound with the formula [tex]\rm P_2I_4[/tex] is diphosphorus tetraiodide.
The term "compound" refers to two or more elements joined together such that the elements have lost their individual identity in favor of a new set of properties.
The given molecular compound [tex]\rm P_2I_4[/tex] is diphosphorus tetraiodide.
This name is derived from the prefixes "di-" and "tetra-" which indicate that there are two phosphorus atoms and four iodine atoms in the molecule, respectively. The ending "-ide" is used to indicate that the compound is a binary compound consisting of two different elements.Therefore, diphosphorus tetraiodide is the name of the molecular compound with the formula [tex]\rm P_2I_4[/tex] .
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Calculate the work when a cylinder equipped with a piston changes volume from 0.200 L to 0.600 L against an external pressure of 3.00 atm (Remember that 101.3 J = 1 L∙atm)
Answer:
[tex]-121.56\ \text{J}[/tex]
Explanation:
[tex]V_1[/tex] = Initial volume = 0.2 L
[tex]V_2[/tex] = Final volume = 0.6 L
P = Pressure = 3 atm
[tex]W=-P\Delta V\\\Rightarrow W=-3(V_2-V_1)\\\Rightarrow W=-3(0.6-0.2)\\\Rightarrow W=-1.2\ \text{L atm}[/tex]
[tex]1\ \text{L atm}=101.3\ \text{J}\\\Rightarrow -1.2\ \text{L atm}=-1.2\times 101.3\ \text{J}=-121.56\ \text{J}[/tex]
Work done is [tex]-121.56\ \text{J}[/tex].
What else is produced during the combustion of butane, C4H10? 2C4H10 + 13O2 8________ + 10H2O H2O C4H10 CO2 O2
Answer:
CO2
Explanation:
took the test
Answer:
Co2
Explanation: