Which of the following are situations that can be modeled with a quadratic function? Select all that apply.

Answer:

Here the answer is given as follows,

Step-by-step explanation:  

The last three parts are coming with a question mark, so can't answer those parts. post the image or write it properly  

a) Every student is taking at least one course.  

[tex]\forall x \exists y T(x,y)[/tex]  

So for all x, there is a y such that T(x,y) is a true will be given by the above statement  

b) There is a part-time student who is not taking any math courses.  

[tex]\exists x \forall y [A(x) \Lambda (M(y) \rightarrow ~T(x,y))][/tex]

Answer:

The answer is

[tex]2 {x}^{2} + 3x - 1 = 0[/tex]

Why? Below I explain

Step-by-step explanation:

That formula has three variables a, b and c.

So, a = 2, b = 3 and c = -1

Because the formula is written like

[tex] \frac{ - b + - \sqrt{ {b}^{2} - 4 \times a \times c} }{2 \times a} [/tex]

Step-by-step explanation:

the answer is in the above image

We are given the system of equations:

[tex] \large{ \begin{cases} y = 2x - 3 \\ y = - x + 3 \end{cases}}[/tex]

Since both are y-isolated equation, we can combine them together.

[tex] \large{2x - 3 = - x + 3}[/tex]

Isolate and solve for x-term.

[tex] \large{2x - 3 + 3 + x = - x + 3 + x + 3} \\ \large{2x + x = 6 \longrightarrow 3x = 6} \\ \large{ \frac{3x}{3} = \frac{6}{3} \longrightarrow \boxed{ \red{x = 2}}}[/tex]

Next, we find the value of y. Simply substitute x = 2 in one of these equations. The less coefficient values, the faster and better. I will substitute x = 2 in y = -x+3. You can substitute x = 2 in y = 2x-3 if you want but the result would be the same.

[tex] \large{y = - x + 3}[/tex]

Substitute x = 2 in the equation.

[tex] \large{y = - 2 + 3} \\ \large \boxed{ \blue{y = 1}}[/tex]

Therefore - when x = 2, y = 1. We can write in coordinate point or ordered pair as (2,1) from (x,y).

Answer

Answer:

3

Step-by-step explanation:

(10, 5) and (15,20)

m = rise/run

m = ∆y/∆x

m = (y₂ - y₁) / (x₂ - x₁)

m = (20 - 5) /(15 - 10)

m = 15/5

m = 3

Answer:

[tex]f(12) = 323.02[/tex]

Step-by-step explanation:

Given

[tex]f(-2.5) = 9[/tex]

[tex]f(7) = 91[/tex]

[tex]f(12) = 16.7 * 1.28^{12[/tex]

Required

[tex]f(12)[/tex]

An exponential function is:

[tex]f(x) = ab^x[/tex]

[tex]f(-2.5) = 9[/tex] implies that:

[tex]9 = ab^{-2.5}[/tex]

[tex]f(7) = 91[/tex] implies that:

[tex]91 = ab^7[/tex]

Divide both equations

[tex]91/9 = ab^7/ab^{-2.5}[/tex]

[tex]91/9 = b^7/b^{-2.5}[/tex]

Apply law of indices

[tex]91/9 = b^{7+2.5}[/tex]

[tex]10.11 = b^{9.5}[/tex]

Take 9,5th root of both sides

[tex]b = 1.28[/tex]

So, we have:

[tex]9 = ab^{-2.5}[/tex]

[tex]9 = a * 1.28^{-2.5}[/tex]

[tex]9 = a * 0.54[/tex]

[tex]a = 9/0.54[/tex]

[tex]a = 16.7[/tex]

f(12) is calculated as:

[tex]f(x) = ab^x[/tex]

[tex]f(12) = 16.7 * 1.28^{12[/tex]

[tex]f(12) = 323.02[/tex]

Answer:

[tex] -\frac{9}{2} [/tex]

Step-by-step explanation:

Rate of change of x and y can be calculated using the following formula and using any two given pair of values from the table:

Rate of change = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Using (-12, 60) and (-6, 33).

Where,

[tex] (-12, 60) = (x_1, y_1) [/tex]

[tex] (-6, 33) = (x_2, y_2) [/tex]

Plug is the values

Rate of change = [tex] \frac{33 - 60}{-6 -(-12)} [/tex]

Rate of change = [tex] \frac{-27}{6} [/tex]

Simplify

Rate of change = [tex] \frac{-9}{2} [/tex]

Rate of change = [tex] -\frac{9}{2} [/tex]

Answer:

First set: 0.95. Second set: 0.86. Third set: 0.88.

Step-by-step explanation:

Imagine that these are not decimals, they are regular numbers (for example: 0.88 is turned into 88). You would determine which one is the greatest depending on which one is higher (like 44 is higher than 32). Therefor the first set: 0.95 the second set: 0.86 the third set: 0.88.

Answer:

Therefore each suit cost $600 and each jean cost $199

Step-by-step explanation:

Let x represent the price of each suit and let y represent the price of each jeans.

Since 3 suits and 3 pairs of jeans cost $2397, this can be represented by the equation:

3x + 3y = 2397

Dividing through by 3:

3x/3 + 3y.3 = 2397/3

x + y = 799    (1)

Also, 8 suits and 11 pairs of jeans cost $6989, this can be represented by the equation:

8x + 11y = 6989      (2)

To find x and y, solve equation 1 and 2 simultaneously. Multiply equation 1 by 8 and subtract from equation 2 to get y:

3y = 597

y = $199

Put y = $199 in equation 1:

x + 199 = 799

x = $600

Therefore each suit cost $600 and each jean cost $199.

Answer:

Exponential Function

Step-by-step explanation:

y values increase by x4

Answer:

exponential function

the ans is b

Answer:

17 + 123 (4 - 1) + (36 / 18) 52 =

17 + 123 x 3 + 2 x 52 =

17 + 369 + 104 =

17 + 473 =

490

Step-by-step explanation:

hope this helps! i made up everything so i hope its okay!

Answer:

The correct answer is - 178.

Step-by-step explanation:

The standard deviation is a measure of the amount of dispersion in a set of values.

Given:

Mean of a normal distribution (m) = 154

Standard deviation (s) = 15

z-score = 1.6

Solution:

To find: value (x) that has a z-score of 1.6

z-score is given by = x-u/15

1.6*15 = x-154

=> 154+24 = x

x = 178

Answer:

5

Step-by-step explanation:

10/2=5

The scale factor of the given case that the distance from D to D' is 10 and the distance from A to D is 2 will be 5.

What is the scale factor?

The ratio between comparable measurements of an object and a representation of that object is known as a scale factor in mathematics.

The scale factor is the ratio between two big and small figures and the ratio is called a scale for the given geometry.

For example, if we have a triangle with a side of 10 meters and another triangle with a side of 5 then the scale ratio will be 10/5 = 2.

Given that

distance from D to D' is 10

distance from A to D is 2  

So the scale ratio will be

DD'/AD  = 10/2  = 5 hence scale ratio will be 5 for the given

geometry.

For more about scale ratio,

https://brainly.com/question/13770371

#SPJ2

Hi there!

We are given two ordered pairs which are:

If you are curious how do I get these ordered pairs, they come from those two big circles or dots. x and y make relation and can be written as (x,y).

1. Find the slope

[tex] \large \boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }[/tex]

Since we have two given points, we can substitute them in the formula.

[tex] \large{m = \frac{4 - 0}{5 - 0} } \\ \large \boxed{m = \frac{4}{5} }[/tex]

2. Form an equation.

[tex] \large \boxed{y = mx + b}[/tex]

Where m = slope and b = y-intercept. We substitute m = 4/5.

[tex] \large{y = \frac{4}{5} x + b}[/tex]

Next thing to remember is that when the graph intersects an origin point, b-term or y-intercept would be 0. Therefore b = 0 since the graph intersects (0,0).

[tex] \large \boxed{y = \frac{4}{5} x}[/tex]

3. Answer

Answer:

8

Step-by-step explanation:

Answer:

7/19

Step-by-step explanation:

7/19=square root of 11=22-3 19

Answer:

6 and 5 over 6

6 5/6

Step-by-step explanation:

it would be a mixed fraction because 6 can't go into 41 evenly

Answer:

6

Hope that this helps!

Answer:

All real number greater than equal to zero.

Step-by-step explanation:

The function is given by

[tex]f(x) = \frac{4}{5}\sqrt x[/tex]

The domain is defined as the input values so that the function is well defined.

here, the values of x should be all real number and zero also.

So, the correct option is  (d).

Answer:

D

Step-by-step explanation:

Solution :

Demand for cola : 100 – 34x + 5y

Demand for cola : 50 + 3x – 16y

Therefore, total revenue :

x(100 – 34x + 5y) + y(50 + 3x – 16y)

R(x,y)  = [tex]$100x-34x^2+5xy+50y+3xy-16y^2$[/tex]

[tex]$R(x,y) = 100x-34x^2+8xy+50y-16y^2$[/tex]

In order to maximize the revenue, set

[tex]$R_x=0, \ \ \ R_y=0$[/tex]

[tex]$R_x=\frac{dR }{dx} = 100-68x+8y$[/tex]

[tex]$R_x=0$[/tex]

[tex]$68x-8y=100$[/tex]  .............(i)

[tex]$R_y=\frac{dR }{dx} = 50-32x+8y$[/tex]

[tex]$R_y=0$[/tex]

[tex]$8x-32y=-50$[/tex]  .............(ii)

Solving (i) and (ii),

4 x (i)    ⇒       272x - 32y = 400

     (ii)   ⇒   (-)     8x - 32y = -50  

                        264x        = 450

∴   [tex]$x=\frac{450}{264}=\frac{75}{44}$[/tex]

     [tex]$y=\frac{175}{88}$[/tex]

So, x ≈  $ 1.70      and    y = $ 1.99

    R(1.70, 1.99) = $ 134.94

Thus, 1.70 dollars per cola

          1.99 dollars per iced ted to maximize the revenue.

Maximum revenue = $ 134.94

Answer:

$24.00=$21.50+r*$.50

Step-by-step explanation:

total cost= entrance fee + r (number of rides) * $0.50 (cost of rides)

$24.00=$21.50+r*$.50

2.50=r*.50

2.5/.5=r

r=5

Answer:

[tex]y = -4x + 2[/tex]

Step-by-step explanation:

Required

Determine the equation

From the question, we understand that, it is parallel to:

[tex]4x + y -10 = 0[/tex]

This means that they have the same slope.

Make y the subject to calculate the slope of: [tex]4x + y -10 = 0[/tex]

[tex]y = -4x + 10[/tex]

The slope of a line with equation [tex]y =mx + c[/tex] is m

By comparison:

[tex]m = -4[/tex]

So, the slope of the required equation is -4.

The equation is then calculated as:

[tex]y = m(x - x_1) + y_1[/tex]

Where:

[tex](x_1.y_1) = (2,-6)[/tex]

So, we have:

[tex]y = -4(x - 2) -6[/tex]

Open bracket

[tex]y = -4x + 8 -6[/tex]

[tex]y = -4x + 2[/tex]

Answer:

$5.5 per pound of meat

Step-by-step explanation:

$20.35 ÷ 3.7 = $5.50

Hope this is helpful

Step-by-step explanation:

The given expression is :

[tex]\dfrac{a^3b^{-2}}{ab^{-4}}[/tex]

We need to simplify the above expression.

a³ is in numerator and a is in denominator. It gts cancelled.

[tex]\dfrac{a^3b^{-2}}{ab^{-4}}=\dfrac{a\times a\times a\times b\times b\times b\times b}{a\times b \times b}\\\\=\dfrac{a^2\times b^{-2}\times b^4}{1}\\\\=\dfrac{a^2}{b^{-2}}[/tex]

Hence, this is the required solution.

Answer:y=log1x

Step-by-step explanation: