Answers
F = mass × Acceleration ( give Acceleration is 9.8 )
So force of 5 kg mass on A is
F = 5 × 9.8 = 49N
Force of mass 1 kg on A
F = 1 × 9.8 = 9.8 N
Force of mass 10 kg on A is
F = 10 × 9.8 = 98N
Clearly the 10 kg ball experts the most force cause it has more mass
Related Questions
El. A horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. How much work is done by the 40 - N force?
E2. A woman does 160 J of work to move a table 4 m across the floor. What is the magnitude of the force that the woman applied to the table if this force is applied in the horizontal direction?
E3. A force of 60 N used to push a chair across a room does 300 J of work. How far does the chair move in this process?
E4. A rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. A frictional force of 120 N opposes this motion.
a. What is the work done by the force applied by the rope?
b. What is the work done by the frictional force?
c. What is the total work done on the crate?
Answers
The same formula of work can be applied to all the questions. The answers are:
E1. 100J
E2. 40N
E3. 5m
E4. a.) 360 J b.) 240 J c.) 120 J
El. If a horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. The formula to get the much work that will be done by the 40 - N force will be
Work done = force x distance
Work done = 40 x 2.5
Work done = 100 J
E2. If a woman does 160 J of work to move a table 4 m across the floor. We will use the same formula to calculate the magnitude of the force that the woman applied to the table assuming the force is applied in the horizontal direction.
Work done = force x distance
160 = 4F
F = 160/4
Force F = 40 N
E3. Given that a force of 60 N used to push a chair across a room does 300 J of work. Same formula to get how far the chair move in this process.
Work done = force x distance
300 = 60 x distance
distance = 300/60
Distance = 5 m
Therefore, the chair moved 5m away.
E4. Given that a rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. And a frictional force of 120 N opposes this motion.
a. The work done by the force applied by the rope can be found by
W = F x S
W = 180 x 2
W = 360 J
b. What is the work done by the frictional force?
W = [tex]F_{r}[/tex] x s
W = 120 x 2
W = 240 J
c. What is the total work done on the crate?
W = (F - [tex]F_{r}[/tex]) x distance
Where [tex]F_{r}[/tex] = frictional force
Substitute all the parameters
W = (180 - 120) x 2
W = 60 x 2
W = 120 J
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Please help is any one know Its correct answer
Answers
Answer:
a=Head
b=Tip
c=South pole of the magnet
d=North pole of the magnet
how to find time with acceleration and velocity
Answers
then divide by acceleration
Find B when θ=35, E=10V, t=5, N=250, A=1.20m^2
a. -0.321 T
b. -0.653 T
c. -0.231 T
d. -0.293 T
Answers
Answer:
its most definitely c. trust me
Explanation:
Definition of main energy level
Answers
Answer:
the orbital in which the electron is located relative to the atom's nucleus.
Explanation:
Answer:
the principal energy level of an electron refers to the shell or orbital in which the electron is located relative to the atom's nucleus.
Rafiq has heard that continued exposure to light for 10 days can change the colour of some blue dyes used to colour cotton clothing. He decides to test this. He takes a piece of clothing dyed with a blue dye which is suspected to lose colour on such exposure. He cuts the cloth into two pieces.
Which experiment is likely to help him conclude if the dye indeed can change colour?
He should expose, for 10 days-
A. Both pieces under 2 identical lamps.
B. One piece under a lamp; keep the other in darkness.
C. One piece for 5 days and one for 10 days under identical lamps
D. One piece folded and one piece spread out under 2 identical lamps.
Answers
A truck moves 60 kilometers east from point A to point B. At point B, It turns back west and stops 15 kllometers away from point A. What are the
total distance and total displacement of the truck?
Answers
Answer:
a). The truck's distance covered for the trip is
(60) + (60 - 15) = 105 kilometers .
b). Its displacement for the whole trip is the distance
and direction from the start-point to the end-point.
15 kilometers east .
Explanation:
Which design of the walls would be most desirable help avoid echoes?
A
They should use bumpy walls for all four sides.
B
They should use bumpy walls for only one side.
С
They should use smooth walls for all four sides.
D
They should use smooth walls for only one side.
Answers
Answer:
a
Explanation:
because the sound wont bounce off
define nuclear energy
Answers
Answer:
Nuclear energy is the energy stored in atoms that can produce electricity.
Hope that helps. x
The gravitational potential energy of a cucumber-harth system changes when which factor changes?
A) the cucumber's speed
B) the cucumber's mass
c) the cucumber's temperature
D) the length
Answers
If it’s heavier, the gravitational pull will bring it down faster.
I desperately need help with my Physics Exam I am failing this class will mark Brainliest to whoever helps the most: PART 1 (I don't want to overwhelm anyone so I'm posting my questions in parts) Also the questions marked are incorrect, so just work with the 3 remaining answers.
10000000 thank you's
Answers
If a spaceship travels at an average speed of 6x10^10 kilometers per year, how many years will it take the spaceship to travel 3x10^30 kilometers? Show work or explain your logic for full credit. a) 5x10^2 b) 5x10^19 c) 5x10^20 d) 5x10^21
Answers
First, you need to find out the speed of 6x10^10. Then find out the value of 3x10^30 after you do that, Make this visual,
3x10^30. 5x10 to the 19 power
_______.
6x10^10
The answer is c
If the spaceship travels a distance of 6 × 10¹⁰ kilometers with an average speed the time taken to travel 3 × 10³⁰ kilometers is 5 × 10¹⁹ years. Thus, option a is correct.
What is speed?Speed is a physical quantity associated with a moving body. It is the measure of distance travelled per unit time . Thus, mathematically it is the ratio of distance to the time.
If we have the time and speed known we can find the distance travelled and vice versa. As the speed increases, the distance covered per unit time will be higher.
Here the spaceship travels 6 × 10¹⁰ kilometers . Thus the time taken to travel 3 × 10³⁰ kilometers can be calculated as follows:
1 year - 6 × 10¹⁰ km
? - 3 × 10³⁰ km
Cross multiply them we get, 3 × 10³⁰ km/ 6 × 10¹⁰ km = 5 × 10¹⁹ years.Hence, option a is correct.
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describe how visible light is used with solar photovoltaic panels to produce electricity
Answers
Photovoltaic panels are used to produce alternating current using sunlight. It uses solar cells which are photoactive and produce a photoelectric effect and thereby a potential is created.
What is photoelectric effect?When photons from the light energy is hit on a metallic surface the photon collides with the electrons of the metals and electrons are ejected from the metal surface. This phenomenon is called photoelectric effect.
In a solar photovoltaic panel, photovoltaic cells layers of semi-conducting materials, such as silicon, are sandwiched photovoltaic cells. When photons from sunshine strike each layer, its unique electronic properties energise and produce an electric field.
The current required to generate electricity is produced through what is known as the photoelectric effect. Electricity produced by solar panels is in the direct current form. This is then transformed into an alternating current by passing via an inverter.
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What is number 10 for this?
Answers
Answer:
The wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Given data in the question;
Speed of wave;
Frequency of wave;
wavelength;
To determine the wavelength of the radio wave, we use the expression for the relations between wavelength, frequency and speed.
Where is wavelength, f is frequency and c is the speed.
We substitute our given values into the equation
Therefore, the wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Explanation:
e. Observe: notice or perceive
f. Infer:
g. Repetition:
h. Replication:
i. Data
Answers
The synonym of a word( observe, infer, repetition, replication and data) means another word that is nearest in meaning to the given word.
The synonym of the words given from the question is given below:
Observe: This means to notice or perceive something. Therefore the synonym is notice or perceive.Infer: This means to conclude something based on evidence and not from explicit statements. Therefore the synonym is deduce or conclude.Repetition: This means doing or saying something again. Therefore the synonym is recurrence.Replication: This means the process of reproduction. Therefore the synonym is duplicate.Data: This means information that is used to make decisions. The synonym is facts.Therefore, synonym of a word means another word that is nearest in meaning to the given word.
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A balance of forces is demonstrated by an object which is slowing to a stop true or false
Answers
Answer:
its true since i already did this last year, if i am wrong i apologize
Explanation:
the gravitational force acts on all objects in proportion to their mass. neglecting air resistance, why don’t heavy objects fall faster than light ones?
Answers
Answer:
Because in correspondence to the same distance from a mass, the gravitational acceleration is the same for all the bodies. It doesn't depend on the mass of the objects.
_____________ is the study of movement in athletes. A. Sports biomechanics B. Posture C. Dynamics D. Anatomy
Answers
Answer:
I believe its A: Sports biomechanics.
please help me with this
Answers
Answer:
>400N is needed to balance that lever
The normal force of a parked car on a level surface is 15,000 Newtons. What is the force of the car?
Answers
Answer:
The force of the car is 15000N.
Explanation:
The unit of force is Newtons (N), so based on the question, the force is 15000 Newtons.
yes that.
Read the excerpt below and then answer the question that follows:
The Book of Dragons
Chapter III The Deliverers of Their Country, an excerpt
By E. Nesbit
It all began with Effie's getting something in her eye. It hurt very much indeed, and it felt something like a red-hot spark—only it seemed to have legs as well, and wings like a fly. Effie rubbed and cried—not real crying, but the kind your eye does all by itself without your being miserable inside your mind—and then she went to her father to have the thing in her eye taken out. Effie's father was a doctor, so of course he knew how to take things out of eyes.
When he had gotten the thing out, he said: "This is very curious." Effie had often got things in her eye before, and her father had always seemed to think it was natural—rather tiresome and naughty perhaps, but still natural. He had never before thought it curious.
Effie stood holding her handkerchief to her eye, and said: "I don't believe it's out." People always say this when they have had something in their eyes.
"Oh, yes—it's out," said the doctor. "Here it is, on the brush. This is very interesting."
Effie had never heard her father say that about anything that she had any share in. She said: "What?"
The doctor carried the brush very carefully across the room, and held the point of it under his microscope—then he twisted the brass screws of the microscope, and looked through the top with one eye.
"Dear me," he said. "Dear, dear me! Four well-developed limbs; a long caudal appendage; five toes, unequal in lengths, almost like one of the Lacertidae, yet there are traces of wings." The creature under his eye wriggled a little in the castor oil, and he went on: "Yes; a bat-like wing. A new specimen, undoubtedly. Effie, run round to the professor and ask him to be kind enough to step in for a few minutes."
"You might give me sixpence, Daddy," said Effie, "because I did bring you the new specimen. I took great care of it inside my eye, and my eye does hurt."
The doctor was so pleased with the new specimen that he gave Effie a shilling, and presently the professor stepped round. He stayed to lunch, and he and the doctor quarreled very happily all the afternoon about the name and the family of the thing that had come out of Effie's eye.
But at teatime another thing happened. Effie's brother Harry fished something out of his tea, which he thought at first was an earwig. He was just getting ready to drop it on the floor, and end its life in the usual way, when it shook itself in the spoon—spread two wet wings, and flopped onto the tablecloth. There it sat, stroking itself with its feet and stretching its wings, and Harry said: "Why, it's a tiny newt!"
The professor leaned forward before the doctor could say a word. "I'll give you half a crown for it, Harry, my lad," he said, speaking very fast; and then he picked it up carefully on his handkerchief.
"It is a new specimen," he said, "and finer than yours, Doctor."
It was a tiny lizard, about half an inch long—with scales and wings.
So now the doctor and the professor each had a specimen, and they were both very pleased. But before long these specimens began to seem less valuable. For the next morning, when the knife-boy was cleaning the doctor's boots, he suddenly dropped the brushes and the boot and the blacking, and screamed out that he was burnt.
And from inside the boot came crawling a lizard as big as a kitten, with large, shiny wings.
"Why," said Effie, "I know what it is. It is a dragon like the one St. George killed."
And Effie was right. That afternoon Towser was bitten in the garden by a dragon about the size of a rabbit, which he had tried to chase, and the next morning all the papers were full of the wonderful "winged lizards" that were appearing all over the country. The papers would not call them dragons, because, of course, no one believes in dragons nowadays—and at any rate the papers were not going to be so silly as to believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail and great wings like bats' wings, only the wings were a pale, half-transparent yellow, like the gear-boxes on bicycles.
Based on the rising action in the bolded paragraphs, what do we know about Daddy? (5 points)
He is calm and curious.
He is angry and upset.
He is hysterical.
He is uninterested and bored.
Answers
believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail.
Explanation:
YOUR WELCOME :)
Answer:
its "calm and curious"
Explanation:
hope tis helps!!!
can somebody explain it to me please?
Answers
Range be R and height be h
[tex]\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}[/tex]
[tex]\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}[/tex]
u=initial velocity
theta is angle of projection.
g=acceleration due to gravity
ATQ
[tex]\\ \sf\longmapsto R=2h[/tex]
[tex]\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}[/tex]
Cancelling required ones
[tex]\\ \sf\longmapsto sin^2\theta=sin2\theta[/tex]
sin2O=2sinOcosO
[tex]\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta [/tex]
[tex]\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2[/tex]
[tex]\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2[/tex]
[tex]\\ \sf\longmapsto tan\theta=2[/tex]
[tex]\\ \sf\longmapsto \theta=tan^{-1}(2)[/tex]
[tex]\\ \sf\longmapsto \theta=63.4°[/tex]
Done
Option B is correct
Starting from rest an object accelerates on a straight line at rate of 2ms‐² for 10 seconds. what is the speed of the object at the end of the 10 seconds
Answers
Answer:
20 meters/sec
Explanation:
See attachment.
2m/s^2 = (v - 0)/10s
v = 20 m/s
A force f is applied horizontally to block A of mass m1 which is in contact with a block B of mass m2. If the surfaces are frictionless, the force exerted by A on B is given by?
Answers
Answer:
Reaction force = Weight
the force exerted by A on B is equal.
M1a = M2a
Explanation: I think the answer is right if wrong message me.
A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able
to slide past each other.
What is most likely the phase of the substance?
gas
o liquid
O solid
anggas
liquid and solid
Help
Me please I search this and there was only an asian answer
Answers
Answer:
A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. The most likely phase of the substance is liquid.
A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. What is most likely the phase of the substance?
gas. NO. Gases have expansibility, that is, they occupy all the space available, so they wouldn't occupy just one half of the container.
liquid. YES. The description fits the liquid phase.
solid and gas. NO. Solids occupy fixed positions and their atoms can't slide past each other.
liquid and solid. NO. Solids can't be present due to their lack of movement.
A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. The most likely phase of the substance is liquid.
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Explanation:
Which is the correct answer
Answers
Answer:
C
Explanation:
All of the other options are affecting the gravitational force and opposing force that pushed upwards, the diagram represents an object that is not moving up or down.
All satellite eventually lose their orbital energy and plummet to earth because of______.
Answers
Answer:
gravity
Explanation:
Even when satellites are thousands of miles away, Earth's gravity still tugs on them. Gravity—combined with the satellite's momentum from its launch into space—cause the satellite to go into orbit above Earth, instead of falling back down to the ground.
how to read a micrometer on a clark cm-100 vickers hardness tester
Answers
Answer:
Explanation:
Equipment manufactured by LECO(8 Corporation, St. Joseph, Michigan is warranted free from defect in material
and workmanship for a period of six months from the date of purchase. Equipment not manufactured by LECO is
covered to the extent of warranty provided by the original manufacturer and this warranty does not cover any
equipment, new or used, purchased from anyone other than the LECO Corporation. All replacement parts shall
be covered under warranty for a period of thirt days from date of purchase. LECO MAKES NO OTHER
REPRESENTATION OR WARRANTY OF ANY OTHER KIND, EXPRESSED OR IMPLIED, WITH RESPECT TO
THE GOODS SOLD HEREUNDER, WHETHER AS TO MERCHANTABILITY, FITNESS FOR PURPOSE, OR
OTHERWISE.
Expendable items such as crucibles, combustion tubes, chemicals and items of like nature are not covered by
this warranty.
LECO's sole obligation under this warranty shall be to repair or replace any part or parts which, to our
satisfaction, prove to be defective upon return prepaid to LECO Corporation, St. Joseph, Michigan. This
obligation does not include labor to install replacement parts, nor does it cover any failure due to accident, abuse,
neglect, or use in disregard of instructions furnished by LECO. In no event shall damages for defective goods
exceed the purchase price of the goods, and LECO SHALL NOT BE LIABLE FOR INCIDENTAL OR
CONSEQUENTIAL DAMAGES WHATSOEVER.
All claims in regard to the parts or equipment must be made within ten (10) days after Purchaser learns of the
facts upon which the claim is based. Authorization must be obtained from LECO prior to returning any other
parts. This warranty is voided by failure to comply with these notice requirements.
NOTICE
The warranty on LECO equipment remains valid only when genuine LECO replacernent parts are employed.
Since LECO has no control over the quality or purity of consumable products not manufactured by LECO, the
specifications for accuracy of results using LECO instruments are not guaranteed unless genuine LECO
consumables are employed in conjunction with LECO instruments. If purchaser defaults in making payment for
any parts or equipment, this warranty shall be void and shall not apply to such parts and equipment. No late
payment or cure of default in payment shall extend the warranty period provided herein.
LECO Corporation is not responsible for damage to any associated instruments, equipment or apparatus nor wil
LECO be held liable for loss of profit or other special damages resulting from abuse, neglect, or use in disregard
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The instrument should be operated only by technically qualified individuals who have fully read and understand
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The operator should follow all ,of the warnings and cautions set forth in the manual and the operator should follow
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LECO'" is a registered trademark of the LECO Corporatio
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is ____?
Answers
[tex]\purple{ \longrightarrow \bf{h_m = \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} }} [/tex]
Projectile is thrown with a velocity = v Angle of projection = θVelocity of projectile at a height half of the maximum height covered be [tex] \sf{v_0}[/tex][tex]\qquad[/tex]______________________________
Then –
[tex]\qquad[/tex] [tex]\pink{ \longrightarrow \bf{ \dfrac{h_m}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }}[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} \times \dfrac{1}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{4g} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2} = {v_0}^{2} \: {sin}^{2} \theta }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf{ \dfrac{ {v}^{2} }{2} = {v_0}^{2} }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \bf{v_0 = \sqrt{ \dfrac{ {v}^{2} }{2} } = \dfrac{v}{ \sqrt{2} } }[/tex]
Now, the vertical component of velocity of projectile at the height half of [tex] \sf{h_m}[/tex] will be –[tex]\qquad[/tex] [tex]\longrightarrow \bf{v_{(y)}=v_0 \: sin \theta }[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \bf{v_{(y)} = \dfrac{v}{ \sqrt{2} } \: sin \theta = \dfrac{v \: sin \: \theta}{ \sqrt{2} } }[/tex]
Therefore, the vertical component of velocity of projectile at this height will be–
☀️[tex]\qquad[/tex][tex] \pink {\bf{ \dfrac{v \: sin \: \theta}{ \sqrt{2} }} }[/tex]
Answer:
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is v sintheta / √2
A tennis ball is dropped from a height of 3 m and bounces back to a height of
1 m after hitting the ground (s = 0).
Use the equation V^2=U^2 + 2as to calculate the velocity of the tennis
ball when it hits the ground.
Answers
The velocity of the tennis ball when it hits the ground is calculated as 4.43m/s. Details about velocity can be found below.
How to calculate velocity?The velocity of a moving object can be calculated using the equation of motion as follows:
v² = u² + 2as
Where;
v = final velocityu = initial velocitya = accelerations = distancev² = 0² + 2(9.8) (1)
v² = 19.6
v = ✓19.6
v = 4.43m/s
Therefore, the velocity of the tennis ball when it hits the ground is calculated as 4.43m/s.
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