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how does temperature affect solubility
Answer:
The increase in kinetic energy that comes with higher temperatures allows the solvent molecules to more effectively break apart the solute molecules that are held together by intermolecular attractions.
Explanation:
Solubility is affected by temperature due to heatness.
Help please I need help fast.
Answer:
d) It incorrectly describes the two processes
Hope it helps you
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How many grams are in 2.3 moles of Aluminum
Answer:
62.1 gram
Explanation:
Al molar mass = 27 g/mol
mass = molar mass × no of moles
= 27 × 2.3 = 62.1 gram
What would happen to the density of a mass of air that is heated?
Would that mass of air rise above and float on top of cooler air above it or would it sink down below cooler air below it? (Assume that the majority of the masses do not mix.)
Answer: As air is heated its density decreases because its mass remains constant but its volume increases. As air is cooled, its density increases because its mass remains constant but its volume decreases. ... The decrease in density as air is heated causes it to rise above cooler, more dense air. Hope this helped.
Explain what happens to the imidazole side chain of histidine in a buffer of pH 4.0 and at pH 10.2.
Histidine, an essential amino acid, has as a positively charged imidazole functional group. The imidazole makes it a common participant in enzyme catalyzed reactions. The unprotonated imidazole is nucleophilic and can serve as a general base, while the protonated form can serve as a general acid.
Determine the subunit composition of a protein from the following information:
a. Molecular mass by gel filtration: 200 kD
b. Molecular mass by SDS-PAGE: 100 kD
c. Molecular mass by SDS-PAGE with 2-mercaptoethanol: 40 kD and 60 kD
Answer:
Explanation:
The protein comprises of two 60-kD polypeptides and two 40-kD polypeptides. Each one of the 40-kD chains has a disulfide-bond which is directly bonded to a 60-kD chain.
The 100-kD units attach noncovalently to produce a protein with a molecular mass of 200 kD. The interaction among the different subunits in the protein is not affected by the Gel filtration chromatography.
Hence, the protein seems to be 200 kD in size. When SDS-PAGE takes place samples are being subjected to heat and therefore undergoing denaturation conditions. The aftermath effect of this causes disorganization in the 100 kD units.
However, the reducing agent (BME) main task is the reduction of disulfide bonds in a protein.
It implies that BME is responsible for the reduction between the R1-S-S-R2 bond between 40 kD and 60 kD to R1-SH and R2-SH, resulting in seperate proteins.
1s22s22p63523p645230104p5
Which element is this?
answer : bromine
Answer:
indeed it 1s22s22p63523p645230104p5 is bromine
lead 2 nitrate and potassium iodide net ionic equation
Answer:
Pb2+(aq) + l+(aq) ------------pbl2(s) net ionic equation
Explanation:
Pb(NO3)2(aq) + kI(aq)------------PbI2(s) + kNo3(aq)
Pb2+ (aq)No3-(aq) + k+(aq) l-(aq) ______PbI2(s) + k+(aq) + NO32+(aq)
Pb2+(aq) + I-(aq). ------------Pbl2(s)
What is the slope of the line on the graph?
Answer:
6
Explanation:
slope= [tex]\frac{rise}{run}[/tex]
slope=[tex]\frac{6}{1}[/tex]
slope=6
Answer:
its one half
Explanation:
i learned this last week
Pure gold has a density of 19.32g/cm^3. You find a gold ring with a mass of 6g and a volume of 0.31cm^3.is this ring pure gold?
Answer:
Yes, this ring is pure gold because when we divide the mass by the volume we get our density for the ring, which comes out to about 19.32.
Explanation:
How many moles of Co would be required to react with 6.14m of P4
The number of moles of Co that would be required to react with 6.14 moles of P4 would be 36.84 moles
Stoichiometric calculationsFrom the equation of the reaction:
6Co + P4 → 2Co3P2
For every 1 mole of P4, 6 moles of Co is required for complete reaction.
Thus, the mole of Co that would be needed for 6.14 moles of P4 would be:
6 x 6.14 = 36.84 moles
More on stoichiometric calculations can be found here: https://brainly.com/question/8062886
A 2.74-g sample of a substance suspected of being pure gold is warmed to 72.1 oC and submerged into 15.2 g of water initially at 24.7 oC. The final temperature of the mixture is 26.3 oC. What is the heat capacity of the substance? Could the substance be pure gold?
(The specific heat capacity of water is 4.184 J/g oC)
J/g oC (Round to three significant digits)
Look up the specific heat capacity of gold.
Could the unknown substance be pure gold? Write yes or no in the following box:
1. The specific heat capacity of the sample of gold obtained is 0.81 J/gºC
2. The substance is not pure gold
1. How to determine the specific heat capacity of gold From the question given above, the following data were obtained:Mass of gold (M₉) = 2.74 gTemperature of gold (T₉) = 72.1 °CMass of water (Mᵥᵥ) = 15.2 g Temperature of water (Tᵥᵥ) = 24.7 °C Equilibrium temperature (Tₑ) = 26.3 °C Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC Specific heat capacity of gold (C₉) =?The specific heat capacity of the sample of gold can be obtained as follow:
Heat loss = Heat gain
M₉C₉(M₉ –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)
2.74 × C₉(72.1 – 26.3) = 15.2 × 4.184 (26.3 – 24.7)
C₉ × 125.492 = 101.75488
Divide both side by 125.492
C₉ = 101.75488 / 125.492
C₉ = 0.81 J/gºC
2. How to determine if the substance is pure Specific heat capacity of gold calculated = 0.81 J/gºC Specific heat capacity of pure gold = 0.13 J/gºCFrom the above we can conclude that the substance is not pure gold since the calculated and standard value of the specific heat capacity of the gold sample is not the same
Learn more about heat transfer:
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Number of electrons for all of these even the ones with a number by them ? Will give brain-list!!!!
Explanation:
s=2
p=6
d=10
f=14
I hope this was helpful
This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar):
CH. CO,H
An analytical chemist has determined by measurements that there are 4.2 moles of carbon in a sample of acetic acid. How many moles of hydrogen are in the
sample?
Be sure your answer has the correct number of significant digits.
Answer:
2.408 moles of hydrogen are in the sample.
Explanation:
Molecular formula of acetic acid =CH3COOH
Ratio of carbon to hydrogen :2/4:1/2
Measured number of moles of carbon atoms = 1.204
Let the moles of hydrogen be = x
Number of carbon atoms in 1.204 mol = 1.204mol*Avogadro number
Number of hydrogen atoms in x mol = x*Avogadro number
As we know that ratio of carbon to hydrogen atoms is 1:2.
1/2=1.204mol* avogadro/ x* avogadro
x = 2.408 moles
2.408 moles of hydrogen are in the sample.
How do you determine the chemical reactivity for nonmetals by using the periodic table?
elements increase in reactivity as they go down in groups and up in periods!!
What is the density at 27 °C of 28.0 milliliters of a liquid that has a mass of 4.05 grams?
Answer:
The answer is 0.14 g/mLExplanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\[/tex]
From the question
mass = 4.05 g
volume = 28 mL
We have
[tex]density = \frac{4.05}{28} \\ = 0.1446428571...[/tex]
We have the final answer as
0.14 g/mLHope this helps you
Write the name for each of the following chemical formulas.
d. P3N5 (for doping semiconductors)
Answer:
Triphorphorus Pentanitride
Explanation:
since there are three phosphorus use the prefix tri-, since there are five nitrogen use the prefix penta. tri=3, penta=5. then add a suffix -ide to the end of nitrogen. that will give you triphosphorus pentanitride.
squence the steps in constructing and interpreting an electron dot diagram
the # molecules in 52.1 grams of NH4OH
Answer:
Explanation:
Hey there!
From question;
The molecular mass of NH₄OH is 35.
Avogadro number = 6.023*10²³ molecules.
Then,
From mole concept,
Molecular mass = Avogadro number
So, 35 grams contains 6.023*10²³ molecules.
1 gram contains [tex]\frac{ 6.023*10^{23} }{35}[/tex] molecules.
52.1 grams contains [tex]\frac{6.023*10^{23} }{35} *52.1[/tex] molecules.
Therefore, 52.1 grams contains 8.96*10²³ molecules.
Hope it helps!
Mg + AgNO3 MgNO3 + Ag
How many grams of magnesium are needed to produce 5.0 moles of silver
Answer:
539.35 g
Explanation:
molar mass of Mg = moles of Ag * molar mass of Ag
x = 5 * 107.87
x = 539.35 g
what is the mass percent of a solution prepared from 50.0g nacl and 150.0g of water
Answer:
Explanation:
In this problem, we have 50.0 g of solute and 150.0 g of water. The total mass of the solution will thus be 50.0 g + 150.0 g = 200.0 g. The mass percent will be 50.0g/200.0 g (x100%) = 25.0 %.
Mass percent of a solution can be defined as grams of solute per 100 grams of solution. In this problem, we have 50.0 g of solute and 150.0 g of water. The total mass of the solution will thus be 50.0 g + 150.0 g = 200.0 g. The mass percent will be 50.0g/200.0 g (x100%) = 25.0 %. You can also look at it another way. Since you have 50 g solute in 200 g solution, you will have 25 g solute in 100 g solution. By the definition provided above, this is a 25% by mass solution.
The formula for the nitrate ion: NO3 NO2 NO3+
Answer:
NO3-
Explanation:
edge2020
no3-Edg 2020
Explanation
Brainliest
How do you know what’s inside of an atom
Answer:
microscope
Explanation:
At 600. K how many moles of gas are in a 1.00 L cylinder at atmospheric pressure?
Answer:
0.02moles
Explanation:
To answer this question, the general gas law equation is used. The General gas law is:
Pv = nRT
Where; P = standard atmospheric pressure (1 atm)
V = volume (L)
n = number of moles
R = Gas law constant
T = Temperature
For this question; volume = 1.00L, atmospheric pressure (P) = 1 atm, R = 0.0821 L-atm / mol K, T = 600K, n = ?
Therefore; Pv = nRT
n = PV/RT
n = 1 × 1/ 0.0821 × 600
n = 1/49.26
n = 0.0203moles
Hence, there are 0.02 moles of gas.
The number of mole of the gas present in the cylinder is 0.02 mole
From the question given above, the following data were:
Temperature (T) = 600 K
Volume (V) = 1 L
Pressure (P) = 1 atm
Number of mole (n) =?The number of mole of the gas present in the cylinder can be obtained by using the ideal gas equation (PV = nRT) as illustrated below:
Temperature (T) = 600 K
Volume (V) = 1 L
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Number of mole (n) =? PV = nRT1 × 1 = n × 0.0821 × 600
1 = n × 49.26
Divide both side by 49.26
[tex]n = \frac{1}{49.26}\\\\[/tex]
n = 0.02 moleThus, 0.02 mole of the gas is present in the cylinder.
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A rock has been placed in water. The mass of the rock is 20 g. What is the rock's density?
g/mL
Answer:
0.67 g mL-1
Explanation:
Every time a problem asks you to find the density of a substance, your goal will essentially be to determine the mass of one unit of volume of said substance.
What are the basis of making symbols of an element?
Each element is given its own chemical symbol, like H for hydrogen or O for oxygen. Chemical symbols are usually one or two letters long. Every chemical symbol starts with a capital letter, with the second letter written in lower case. For example, Mg is the correct symbol for magnesium, but mg, mG and MG are wrong...
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write the property of graphite? any two
Answer:
Allotrope of carbon.
High melting point.
Explanation:
Answer:
Density lower than that of diamond.
It has soft, slippery feel.
SOMEONE PLEASE HELP I WILL Mark u BRAINLIST
Answer:
answer 7.4 atm
Explanation:
i did this and got it correct
What's meant by chemistry
Answer: Chemistry is the properties, composition, and structure of elements and compounds, how they can change, and the energy that is released or absorbed when they change.
Explanation:
Answer:
The scientific study of the structure of substances and what happens to them in different conditions or when mixed with each other is known as Chemistry.
Please mark my answer the brainliest and rate me 5 star and follow me.HELP PLZ!!! A sample contains only the compound CaCl2 and water. When it is dried, its weight decreases from 5.00g to 4.24g. What is the mass percentage of water in the original sample? Round to three significant figures.
Answer:is 15.2%
Explanation:
Got it wrong and this the correct answer it told me
The percentage of water in the original sample is 15.2 %.
From the information provided in the question;
Weight of the wet sample = 5.00g
Weight of the dried sample = 4.24g
Loss in mass = 5.00g - 4.24g = 0.76 g
percentage of water in the original sample = Difference in mass between wet and dry sample/ mass of wet sample × 100/1
Hence, when we substitute values;
percentage of water in the original sample = 0.76 g/5.00g × 100/1
percentage of water in the original sample = 15.2 %
So, the percentage of water in the original sample is 15.2 %.
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