Which graph represents the equation 3x+y=-1?

The value of x is 0.918 for the equation 3.2x - 1.7x + 5.5 = 10.

To determine this equation 3.2x - 1.7x + 5.5 = 10,

3.2x - 1.7x + 5.5 = 10

Subtract 10 on both side,

3.2x - 1.7x + 5.5 - 10 = 10 - 10

3.2x - 1.7x + 4.5 = 0

Subtract 4.5 on both side,

3.2x - 1.7x = -4.5.

4.9x = -4.5

x = 0.918.

Therefore, the value of x is 0.918.

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The answer is 21.

First you Add both AB and BC which is 10x +14. Then you put 64 into the equation. 10x+14=64. Subtract 14 from 64 which is 50. So 10x=50. Then divide 10 from 50. which would be x=5. So if you plug it in. It would be 21.

Answer:

67100

1300

Step-by-step explanation:

You are rounding to the nearest hundreds place value (will be underlined and bolded). Note the number directly next to the place value (tens place value). If it is the digit 5 or greater, round up. If 4 or less, round down:

67103:

You are rounding to the hundreds place value. The tens place value is a 0. Because 0 is less than 5, round down.

67103 rounded to the nearest hundred is 67100.

1273:

You are rounding to the nearest hundreds place value. The tens place value is a 7. Because 7 is greater than 5, round up.

1273 rounded to the nearest hundred is 1300.

~

Answer: The answer will be -4

Answer:

Nine hundred seventy two thousand two hundred seventy four. Hope this helps

Answer:

10 11/15

Step-by-step explanation:

the improper fraction you would use is 23/5 and 7/3

to convert improper fractions you would take the whole number multiply by the denominator and then add the numerator so 4*5 which is 20 + 3

do that to both fractions then multiply

23     7    and you will get 161/15 which simplifies to 10 11/15

5       3

Answer:

Hi there!!

Your answer is:

[tex]10 \times \frac{11}{15} [/tex]

Step-by-step explanation:

[tex]4 \times \frac{3}{5} [/tex]

Multiply 4 by the denominator and add to the numerator!

4×5+3

20+3

23

23/5 ×

[tex]2 \times \frac{1}{3} [/tex]

2×3+1

6+1

7

7/3×

7/3 × 23/5

7× 23 = 161

3×5= 15

161/15

SIMPLIFY!

10 & 11/15

Hope this helps

Answer:  The first aircraft has 208 seats.

The second aircraft has 119 and the third has 74.

Step-by-step explanation:

The equation is x+89 + x + x-45 = 401

combine terms: 3x + 44 = 401  Subtract 44 from both sides  3x=357  

divide both sides by 3

x= 119

substitute x in each term of the equation to find the number of seats on each aircraft

119 + 89 = 208 for #1    x= 119 for #2    119- 45= 74 for #3

Answer:

What are you asking? What does it equal? W+2792=??

Answer:

there is no number that could fit, it actually could be anything, I think that there is a part of the problem not there that is a expression to solve that you need a equation

Step-by-step explanation:

Answer:

(a) The sample mean and sample standard deviation are 2.415 and 0.5342 respectively.

(b) Shown below.

Step-by-step explanation:

The data set provided is:

S = {1.75, 1.92, 2.62, 2.35, 3.09, 3.15, 2.53, and 1.91}

(a)

Compute the sample mean and sample standard deviation as follows:

[tex]\bar x=\frac{1}{n}\sum\limits_{i}{x_{i}} =\frac{1}{8}\times 19.32=2.415\\\\\\s=\sqrt{\frac{1}{n-1}\sum\limits_{i}{(x_{i}-\bar x^{2})^{2}}}=\sqrt{\frac{1}{8-1}\times 1.9976}=0.5342[/tex]

Thus, the sample mean and sample standard deviation are 2.415 and 0.5342 respectively.

(b)

Use SPSS to form a Box plot.

Go to Graphs → Legacy Dialogs → Boxplot

A dialog box will open.

Select "Simple".

Select "Summaries for Separate Variable"

Press "Define"

Another dialog box will open.

Select the variable.

Press OK.

The box plot is attached below.

Answer:

a

[tex]E[(3X+1)^2]= 8.5  [/tex]

b

[tex]P(1 <  X < 2)=0.1170 [/tex]

Step-by-step explanation:

From the question we are told that

   The parameter of  X  is  [tex]\lambda  =  2[/tex]

Generally the expected value of  X is  

    [tex]E(X) =  \frac{1}{\lambda }[/tex]

     [tex]E(X) =  \frac{1}{2}[/tex]

=>  [tex]E(X) =  0.50 [/tex]

Generally we have that

     [tex]E(X^2) =  E(X)^2 + E(X)^2[/tex]

=>  [tex]E(X^2) =  [\frac{1}{2}] ^2 + [\frac{1}{2} ]^2[/tex]

=>  [tex]E(X^2) =  0.5 [/tex]

Generally

    [tex]E[(3X+1)^2]= E(9x^2 + 1 + 6x)[/tex]

=>  [tex]E[(3X+1)^2]= 9E[X^2] + 1 + 6 E[X])[/tex]

=>    [tex]E[(3X+1)^2]= 9* 0.5  + 1 + 6 * 0.5 [/tex]

=>   [tex]E[(3X+1)^2]= 8.5  [/tex]

Generally  

   [tex]P(1 <  X < 2)=  P(X < 2) - P(X < 1)[/tex]

Here  [tex]P(X <  2 ) =  e^{- 2 * \lambda }[/tex]

=>      [tex]P(X <  2 ) =   e^{- 2 * 2 }[/tex]

=>       [tex]P(X <  2 ) =   e^{- 4}[/tex]

and  

    [tex]P(X <  1 ) =   e^{- 1 * \lambda }[/tex]

    [tex]P(X <  1 ) =   e^{- 1 * 2 }[/tex]

    [tex]P(X <  1 ) =   e^{-2 }[/tex]

So

   [tex]P(1 <  X < 2)= e^{-2 } -  e^{- 4} [/tex]

  [tex]P(1 <  X < 2)=0.1170 [/tex]

Answer:

a variable

Step-by-step explanation:

a variable.

Answer:

C

Step-by-step explanation:

x + 9 = 4(x-1)²

x + 9 = 4(x² - 2x + 1)                  Multiply (x - 1) times (x - 1)

x + 9 = 4x² - 8x + 4                  

4x² - 9x - 5 = 0                          Subtract x + 9 from both sides

Answer:

+-1, +-2,+-5, +-10

Step-by-step explanation:

you first find all the numbers that can go into the constant which is 10, so negative and positive 1 can go into 10, negative and positive 2 can go into 10 etc.

The possible rational roots of the polynomial equation

[tex]1,-1} , +\frac{1}{2} , -\frac{1}{2} , +2,-2, +5,-5, +\frac{5}{2} ,-\frac{5}{2} ,+10,-10[/tex]

Given :

The polynomial equation is

[tex]2x^{9}-3x^{7}+11x+10=0[/tex]

To find out possible rational roots, we use rational root theorem

Rational root of the form

[tex]\frac{p}{q}[/tex] where p is the constant and q is the leading coefficient

p=10  and q=2

Lets write all the factors of 10  and 2

Factors of 10 are 1,2,5,10

factor of 2 are 1,2

Rational root of the form

[tex]+- factors of \frac{p}{q} =+-\frac{1,2,5,10}{1,2}[/tex]

We consider both positive and negative factors. Ignore the repeated roots

So possible rational roots are

[tex]1,-1} , +\frac{1}{2} , -\frac{1}{2} , +2,-2, +5,-5, +\frac{5}{2} ,-\frac{5}{2} ,+10,-10[/tex]

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Answer:

112 $ is the original price

Step-by-step explanation:

[tex]x \times 0.75 = 84 \\ x = 84 \div 0.75 \\ x = 112[/tex]

you have to think that the original price multiplied by 0.75 (also known as 75%) gave the result of what he saves i.e 84 $. So we put up an equation with the original price multiplied by 75% which equals the 84 $ he saved on buying that item on sale

The value of x in the table above is $112.

Suppose the value of which a thing is expressed in percentage is "a'

Suppose the percent that considered thing is of "a" is b%

Then since percent shows per 100 (since cent means 100), thus we will first divide the whole part in 100 parts and then we multiply it with b so that we collect b items per 100 items(that is exactly what b per cent means).

Thus, that thing in number is

[tex]\dfrac{a}{100} \times b[/tex]

Given;

All the items on the sale rack were 75 percent off their original price.

Jill bought an item on the sale rack and saved a total of $84

Now,

Let the original price without off be x

84*100/x=75

8400/75=x

x=112

Therefore, the price without 75 percent of will be $112

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Answer:

If you simplify the first expression, you will not get the second expression. In the first expression, the x2 terms have coefficients of 1 and –1 and, when combined, the result is 0. Also, the x terms have coefficients of 8 and –6 and, when combined, the result is 2. Finally, the constant from the first expression is not in the second expression.

Step-by-step explanation:

Answer:

P(≥ 7 males) = 0.0548

Step-by-step explanation:

This is a binomial probability distribution problem.

We are told that Before 1918;

P(male) = 40% = 0.4

P(female) = 60% = 0.6

n = 10

Thus;probability that 7 or more were male is;

P(≥ 7 males) = P(7) + P(8) + P(9) + P(10)

Now, binomial probability formula is;

P(x) = [n!/((n - x)! × x!)] × p^(x) × q^(n - x)

Now, p = 0.4 and q = 0.6.

Also, n = 10

Thus;

P(7) = [10!/((10 - 7)! × 7!)] × 0.4^(7) × 0.6^(10 - 7)

P(7) = 0.0425

P(8) = [10!/((10 - 8)! × 8!)] × 0.4^(8) × 0.6^(10 - 8)

P(8) = 0.0106

P(9) = [10!/((10 - 9)! × 9!)] × 0.4^(9) × 0.6^(10 - 9)

P(9) = 0.0016

P(10) = [10!/((10 - 10)! × 10!)] × 0.4^(10) × 0.6^(10 - 10)

P(10) = 0.0001

Thus;

P(≥ 7 males) = 0.0425 + 0.0106 + 0.0016 + 0.0001 = 0.0548

Answer:

IDEK That is a bunch of numbers

Answer:

I think it's {3, 6, 12, 18}

Step-by-step explanation:

Domain: all x-values that are to be used (independent values).

Answer:

-19

Step-by-step explanation:

f(x)=5x+1

F(-4) - substitute -4 as the x

F(-4)=5(-4)+1

F(-4) = -20 + 1

f(-4) = -19

Answer:

(6,1)

Step-by-step explanation:

midpoint = ((x2+x1),(y2+y1)/2)

= (6+6)/2, (-5+7)/2

= 12/2, 2/2

= 6,1

Answer:

Step-by-step explanation:

x- coordinates same so the line is vertical and we'll only calculate the y-coordinate

So the point is

Answer:

2x² - 5x - 3 < 0

let the positive integer be 'X'

5x < 2x² - 3

-2x² + 5x + 3 < 0

The equation is 2x² - 5x - 3 < 0

Answer:

No

Step-by-step explanation:

Counterexample for the numbers 25 and 10

The actual LCM is 50

If you were to multiply both numbers together you would get 250 which is incorrect

Answer:

¢40 or $0.40

Step-by-step explanation:

270 - 250 = 20

20 ÷ 50 = 0.4

Answer:

The probability that they will teach different courses is [tex]\frac{2}{3}[/tex].

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here x represents the course taught by the first part-time instructor and y represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events E is the ratio of the number of favorable outcomes to the total number of outcomes.

[tex]P(E)=\frac{n(E)}{N}[/tex]

Compute the probability that they will teach different courses as follows:

[tex]P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}[/tex]

Thus, the probability that they will teach different courses is [tex]\frac{2}{3}[/tex].

Answer:   point-slope form is [tex](y -y_{1} ) = m(x - x_{1} )[/tex]

9.5 -(-6) = 1/2(0-7)

Step-by-step explanation: You can get a y-intercept by substituting the x and y values from the given coordinate into the slope-intercept form and solve for b.

y = mx + b

-6 = 1/2(7) + b

-6 = 3.5 + b

-9.5 = b  Slope-intercept equation for this question would be  y = x/2 - 9.5

Then use the coordinates of the y-intercept to create the point-slope equation

(-9.5 -[-6]) = 1/2(0-7)

Answer:

Insurance can cover you or your property in case of an accident, theft, or another unpredictable event.

Answer:

10^-3*1/3 = 10^-1=0.1