which gas law is not included in the combined gas law

Answer:

Explanation:

First convert the grams of Calcium Bromide to moles by using the atomic weight. Then use the formula for molarity, which is moles per liter.

CaBr2 = 199.9 g/mol

10/199.9 = 0.05 moles of CaBr2

[tex]0.5M=\frac{0.05mol}{x}[/tex]

x = 0.1L or 100mL

Answer:

3 × 10 L

Explanation:

Step 1: Given and required data

Step 2: Convert "T" to Kelvin

When working with gases, we need to use the absolute temperature. We can convert Celsius to Kelvin using the following expression.

K = °C + 273.15

K = 77°C + 273.15 = 350 K

Step 3: Calculate the volume (V) of the tank

We can calculate the volume occupied by the gas using the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 4.5 mol × (0.082 atm.L/mol.K) × 350 K/5 atm = 3 × 10 L

Answer:

a habitat with low rainfall and low sunlight

Explanation:

Because little to nothing grows in ground that is frozen year-round except for some forms of microscopic life

Answer:

I think the answer might be C.

Answer:

B

Explanation:

you can tell by looking at the image lol the wires have to be connected

(brainliest please? c:)

( although its fine if not im just glad to have helped )

Answer:

The answer is B

Explanation:

Answer:

1.5

Explanation:

From;

BO = ½(B – A)

BO= Bond order

B= Number of bonding electrons

A = Number of antibonding electrons

For the sigma bonds, there are 2 bonding electrons and 0 nonbonding electrons.

σ BO = ½(B – A) = ½(2 – 0) = 1

π bond order for 6 C-C bonds;

π BO = ½(B – A) = ½(6 – 0) = 3

For each  π bond, BO = 3/6 = 0.5.

Hence, for a single C-C bond in benzene, the total Bond order = σ + π = 1 + 0.5 = 1.5.

Answer:

C₁₅N₃H₁₅

Explanation:

Follow the sequence ...

%/100wt => grams/100wt => moles => mole ratio => reduce mole ratio (divide by smaller mole value) => empirical ratio.

Note: If the above calculation comes out with a fraction (for most textbook problems) do the following:

--.25 => multiply empirical ratio by 4

--.50 => multiply empirical ratio by 2

--.75 => multiply empirical ratio by 4

Or, if initial data is given in grams, convert to %/100wt. (example at end of problem)

This Problem:  

         %/100wt.   grams         moles =mass/formula wt.

%C = 75.95% => 75.95g => 75.95g/12.0107g·mol⁻¹ = 6.325 mole OS

%N = 17.72% =>  17.72g => 17.72g/14.0067g·mol⁻¹ = 1.2651 mole N  

%H =  6.33% =>   6.33g =>  6.33g/1.00794g·mol⁻¹ = 6.28 mol H              

(∑  =   100%    | assume 100g cpd  => ( grams => 100g compound would contain 75.95g C, 17.72g N & 6.33g H )

=> mole ratio =>  C : N : H => 6.3235 : 1.2651 : 6.28  

=> reduce mole ratio ( divide by smaller mole value ) ...

=> 6.3235/1.2651 : 1.2651/1.2651 : 6.28/1.2651 =>  empirical ratio is => 5:1:5

empirical formula => C₅NH₅

empirical formula wt. = 5C + 1N + 5H = 5(12) + 1(14) + 5(1) = 79

=> molecular ratio (n) => molecular wt (given) = N · empirical formula wt

=> N =  molecular wt / empirical wt = 240/79 = 3

∴ Molecular Formula is =>  C₅NH₅ X 3 => C₁₅N₃H₁₅

________________________________________

EXAMPLE: Empirical Formula Problem with initial data in grams:

Assume an oxide of Osmium (compd wt) = 2.89 grams contains 2.16 gram Osmium, what is the empirical formula?

Use given mass values to calculate %/100wt then use the sequence

% => grams => moles => reduce => emp. ratio => emp. formula

%Os = 2.16g/2.89g x 100% = 74.74%

%Oxy = [(2.89g -2.16g)/2.89] x 100% = 25.26% or use 100% - 74.74% = 25.26%

%  => g => moles => reduce => emp formula

%Os   = 74.74% => 74.74g => 74.74g/190.23g·mol⁻¹ = 0.3929 mol Os

%Oxy = 25.26% => 25.26g => 25.26g/16g·mol⁻¹ = 1.5788 mole Oxy

Reduce mole ratio (divide by smaller mole value) => empirical ratioo

=> Os:Oxy => 0.3929/0.3929 : 1.5788/0.3929 = 1 : 4

=> Empirical Formula => OsO₄

1.37 × 10²³ formula units MgCl₂

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 21.6 g MgCl₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Mg - 24.31 g/mol

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of MgCl₂ - 24.31 + 2(35.45) = 95.21 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.36619 × 10²³ formula units MgCl₂ ≈ 1.37 × 10²³ formula units MgCl₂

Answer:

Jupiter

Explanation:

Answer:

Limiting reactant: Cl2.

Max mass of PCl3 = 41.44 g.

P4 leftover = 5.51 g.

Explanation:

Hello!

In this case, since the undergoing chemical reaction is:

[tex]P_4+6Cl_2\rightarrow 4PCl_3[/tex]

In order to compute the maximum amount of PCl3, it is necessary to compute the grams of this product produced by each reactant, just as shown below, whereas molar masses and mole ratios are used:

[tex]m_{PCl_3}^{by\ P_4}=14.3gP_4*\frac{1molP_4}{123.89gP_4} *\frac{4molPCl_3}{1molP_4} *\frac{137.33gPCl_3}{1molPCl_3} =63.41gPCl_3\\\\m_{PCl_3}^{by\ Cl_2}=32.1gCl_2*\frac{1molCl_2}{70.91gCl_2} *\frac{4molPCl_3}{6molCl_2} *\frac{137.33gPCl_3}{1molPCl_3} =41.44gPCl_3[/tex]

Thus, since chlorine gas yields fewer grams of PCl3 than P4 we infer Cl2 is the limiting reactant and 63.41 grams of PCl3 product are yielded.

Finally, for the excess reactant, we see a difference of 63.41-41.44=21.97g, so we can compute of the leftover of P4 as follows:

[tex]m_{P_4}^{leftover}=21.97gPCl_3*\frac{1molPCl_3}{137gPCl_3} *\frac{1molP_4}{4molPCl_3} *\frac{137.33gP_4}{1molP_4} =5.5gP_4[/tex]

Best regards!

Answer:

[tex]\Delta Tfp_{NaCl}= -14.0\°C\\\\\Delta Tfp_{CaCl_2}=-11.1\°C[/tex]

Explanation:

Hello!

In this case, since the freezing point depression caused by the addition of a solute, we use the following formula:

[tex]\Delta Tfp= i*m*Kfp[/tex]

Thus, we first need to compute the molality of each solute, as shown below:

[tex]m_{NaCl}=\frac{220.g/(58.44g/mol)}{1.00kg} =3.76m\\\\m_{CaCl_2}=\frac{220.g/(110.98g/mol)}{1.00kg} =1.98m[/tex]

Next, since NaCl has two ionic species, one Na⁺ and one Cl⁻, and CaCl₂ three, one Ca²⁺ and two Cl⁻, the van't Hoff's factors are 2 and 3 respectively, therefore the freezing point depressions turn out:

[tex]\Delta Tfp_{NaCl}= 2*3.76m*-1.86\°C/m=-14.0\°C\\\\\Delta Tfp_{CaCl_2}= 3*1.98m*-1.86\°C/m=-11.1\°C[/tex]

It means that CaCl₂ is still better than NaCl because produces involves a higher melting point for the ice, so it would melt faster.

Best regards!

Answer:

A DC power supply, commutator, rotor armature, axle, and a field magnet.

Answer:

because all chemical reaction involve the rearrangement of atoms, the mass is an electron is negatively charged, it has a mass approximately 1/2000 that of a, Atoms of an element that contain the same number of protons but a different Copy and complete the following tables concerning the isotopes of silicon SI-28.

Explanation:

Answer:

No.2, No.3 and No.4 answers are same. Give the options properly.

Good News! Here is a sheet to show you how to perform mole calculations: http://www.sciencewithmrjones.com/downloads/chemistry/moles/how_to_perform_mole_calculations.pdf

Answer: The ionic bond. This involves ions of opposite charge. Eelectrostatically charged bodies with opposite charges, + and -, attract one another.

MARK ME BRAINLIST

Answer:

Sexual Reproduction

Explanation:

In Asexual Reproduction offsprings are know as ramets and many ramets are known as clowns. So, when two parents are involved genetic variations occur in offspring. Pollen possess male gamete (antherozoid/sperm) and ovule possess egg.

A part

Answer:

A

Explanation:

have a great day!!!!!!!!

Answer:

Ba(OH)₂ > NaOH >N₂H₂  > HOCl > HCl

Explanation:

To get a better understanding of this, we need to know what's the meaning of the pH values.

The pH value of any compound basically gives us information of how acidic or basic is a compound. If this value is higher (>7), means major basicity; if this number is lower (<7) means major acidity in the compound.

According to this, a strong acid would be the one with the lowest pH, and a strong base would be the one with the highest pH.

Among the 5 compounds we have here, only 2 of them are acid, and the rest is basic, so we can assume that both acid would have the lower pH, it's up to us to see which of them have the lowest pH.

To do that, we can use the following expression:

pH = -log[H⁺]

If all solutions have a concentration of 0.10, then the pH would be:

HCl:

pH = -log(0.1) = 1

HOCL:

This one is a weak acid, so it's not completely dissociated in solution and the [H⁺] would be <0.1 M. As its a weak acid, we can assume that it's pH would be near 4, 5 or 6. We cannot know with all certain, because we need the Ka of this acid, and see the dissociation of the acid in solution, but for this case, it's fine and HCl is one of the strongest known acid.

In this case the order is: HOCl > HCl

For the bases, we have 3 bases, 2 of them are strong bases, and 1 of them is a weak base so it doesn't dissociate completely (N₂H₂), so this would have the lowest pH among the bases. In the case of bases, we calculate pOH, (Same formula as before) and then, we substract 14 from the value of pOH. As for the other two:

Ba(OH)₂:

Concentration would be double because we have 2 OH, so:

[OH⁻] = 2 * 0.1 = 0.2 M

pOH = -log(0.2) = 0.69

pH = 14 - 0.69 = 13.31

NaOH:

pOH = -log(0.1) = 1

pH = 14 - 1 = 13

Therefore, Ba(OH)₂ is stronger than NaOH and N₂H₂. So, our order would be:

Hope this helps

Answer:

The composition of the objects because not all the planets have been explored

Answer:

Explanation:

First we convert the given masses of reactants to moles, using their respective molar masses:

2.39 kmol of CO₂ would react completely with (2.39 * 2) 4.78 kmol of NH₃. There are not as many NH₃ kmoles so NH₃ is the limiting reactant.

We calculate how much urea would form with a 100% yield, using the moles of limiting reactant:

We convert that amount to kg:

Finally we calculate the percent yield:

Answer:

Temperature is directly proportional to the kinetic energy of the atoms that a body is made of. This relation is valid concerning the velocities relative to the center of mass of the body. In other words, concerted movements like translation and rotation do not affect temperature.

Explanation:

Answer:

As stated in the kinetic-molecular theory, the temperature of a substance is related to the average kinetic energy of the particles of that substance. When a substance is heated, some of the absorbed energy is stored within the particles, while some of the energy increases the motion of the particles.

I hope it's helpful!

Answer:

just until it covers the sample

a low setting and increasing gradually

pipet

as little solvent as possible

Explanation:

In order to dissolve a chemical sample in a recrystallization solvent, add the room-temperature solvent just until it covers the sample in an Erlenmeyer flask on a hot plate. Turn on the heat, starting at a low setting and increasing gradually. Using a pipet, add additional solvent from a second container on the heat source. Swirl the sample flask after each addition, and try to add as little solvent as possible in order to dissolve the solid.

Answer:

bleach, hair spray,spay cleaner and idek

Explanation:

Answer:

Covalent bond involves the sharing of electrons, while metallic bonds have strong attractions and ionic bonds involve the transferring and accepting of electrons from the valence shell. The adhering property of an atom, in order to arrange themselves in a most stable pattern by filling their outermost electrons orbit.

Complete Question:

Check the file attached to get the complete question

Answer:

In the film Ice word Revenge, vehicle 2 did not fall of the cliff because,  but in Claire's test, vehicle 2 off the cliff because

Explanation:

In Claire's test, the weight of vehicle 1 is either equal to or greater than the weight of vehicle 2, so it was sufficient to push it down the cliff.  In the film Ice word revenge, the weight of vehicle 1 is less than the weight of vehicle 2, it is not sufficient to make it fall off the cliff ( Note: Looking exactly the same in the movie, as Claire claimed, does not mean they have the same mass). Therefore if Claire wants a collision that will not make the vehicle 2 fall off the cliff, he should collide it with a vehicle of lesser mass/weight.