Answer:
dddddddddddddv
Step-by-step explanation:
Solve the following system of equations:
3x-5y=-11
7x+2y=-12.
Express your answer as an ordered pair. (x, y)
Answer: (-2, 1)
Step-by-step explanation:
We will graph the given equations. The point of intersection is the solution to the system of equations. See attached.
They intersect at the point (-2, 1) giving us an answer of x = -2 and y = 1, but this question asks for the answer as an ordered pair so we leave it as is.
Find the probability of winning a lottery by selecting the correct six integers, where the order in which these inte
The probability of winning a lottery by selecting the correct six integers, are
[tex]\begin{aligned}&(a) 1.68 \times 10^{-6} \\&(b) 5.13 \times 10^{-7} \\& (c) 1.91 \times 10^{-7} \\&(d)8.15 \times 10^{-8}\end{aligned}[/tex]
What is binomial distribution?The binomial distribution is a type of probability distribution that expresses the probability that, given a certain set of characteristics or assumptions, a value would take one of two distinct values.
Part (a); positive integers not exceeding 30.
To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the other twenty-four.
[tex]\frac{\left(\begin{array}{c}6 \\6\end{array}\right)\left(\begin{array}{c}24 \\0\end{array}\right)}{\left(\begin{array}{c}30 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}30 \\6\end{array}\right)}=1.68 \times 10^{-6}[/tex]
Part (b); positive integers not exceeding 36.
To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the other thirty.
[tex]\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}30 \\0\end{array}\right)}{\left(\begin{array}{c}36 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}36 \\6\end{array}\right)}=5.13 \times 10^{-7}[/tex]
Part (c); positive integers not exceeding 42.
To calculate the probability, use binomial coefficients. Pick six of the six accurate integers and none of the 36 other integers.
[tex]\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}36 \\0\end{array}\right)}{\left(\begin{array}{c}42 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}42 \\6\end{array}\right)}=1.91 \times 10^{-7}[/tex]
Part (d); positive integers not exceeding 48.
To calculate the probability, use binomial coefficients. Choose six of the six accurate integers and none of the other 42.
[tex]\frac{\left(\begin{array}{l}6 \\6\end{array}\right)\left(\begin{array}{c}42 \\0\end{array}\right)}{\left(\begin{array}{c}48 \\6\end{array}\right)}=\frac{1}{\left(\begin{array}{c}48 \\6\end{array}\right)}=8.15 \times 10^{-8}[/tex]
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The complete question is-
Find the probability of winning a lottery by selecting the correct six integers, where the order in which these integers are selected does not matter, from the positive integers not exceeding a) 30. b) 36. c) 42. d) 48.
What is the approximate side length of the square? 3.0 units 3.5 units 4.2 units 4.9 units
Answer:
(っ◔◡◔)っ ♥ the answer is C ♥
Step-by-step explanation:
The sum of 225 consecutive positive integers only has digits 1 or 0. What is the smallest possible value of the sum?
Answer:
1 +10=11 (since 0 is neither negative or positive the first and second positive integerswith 1 or 0
A boat traveled north for 28 miles, then turned x° southwest and traveled for 25 miles before stopping. When it stopped, the boat was 18 miles from its starting point.
A triangle shows the course of a boat. Starting at the dock, it travels 18 miles to the left, then 25 miles up and to the right, and then 28 miles down and back to the dock. The angle between 25 miles and 28 miles is x degrees.
Law of cosines:
By how many degrees did the direction of the boat change when it made its first turn? Round to the nearest degree.
30 degrees
39 degrees
46 degrees
The number of degrees that the direction of the boat change when it made its first turn is 39°.
How to calculate the value?From the information given, we would use the cosine function to solve the information.
This will be:
18² = 28² + 25² - 2(28)(25)(cos x)
324 = 784 + 625 - 1400cosx
x = 39.19
Therefore, the value is 39°.
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Read the excerpt from Chapter 3 of Wheels of Change . In 1881, as women in the United States continued to struggle with hoops and corsets and other fashion architecture, their counterparts in England formed the Rational Dress Society. This society called for more reasonable clothing solutions, including limiting the weight of a woman's undergarments to seven pounds. Why was the Rational Dress Society formed? to advocate for more functional cycling and athletic gear for women to push for more beautiful, intricate styles of clothing for women to encourage English women to dress differently than American women to promote safer, more comfortable styles of dress for women
Step-by-step explanation:
Chapter 3 of Wheels of Change .
But the bicycle craze had a more lasting impact on women’s clothing than just the use of bloomers. Thanks in large part to cycling, the innovation of rational dress reformers were starting to take effect by the end of the 1890s. Corsets were on their way out, dresses were getting shorter, and women no longer wore the heavy, bulky undergarments that gave them round, unnatural shapes. These changes went a long way toward unburdening women and setting the stage for them to be healthier and more active in the coming century.
Based on the excerpt, women in the 1890s became more independent and their lives improved as a result of
a rise in the popularity of bicycles.
a rise in the popularity of corsets.
cycling becoming less socially acceptable.
clothing becoming more restrictive.
Answer:
to promote safer, more comfortable styles of dress for women
Step-by-step explanation:
to promote safer, more comfortable styles of dress for women
The duration of shoppers' time in BrowseWorld's new retail outlets is normally distributed with a mean of 41.8 minutes and a standard deviation of 17.3 minutes. How long must a visit be to put a shopper in the longest 20 percent
A visit must be of at least 56.33 minutes to put a shopper in the longest 20 percent.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula. In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z=\frac{X-\mu}{\sigma}[/tex]
How long must a visit be to put a shopper in the longest 20 percent?
Here [tex]\mu=41.8 , \sigma=17.3[/tex]
The 100-20=80th percentile, which is X when Z has p-value of 0.8, so Z=0.84
[tex]Z=\frac{X-\mu}{\sigma}[/tex]
[tex]0.84=\frac{X-41.8}{17.3}[/tex]
14.532=X-41.8
X=14.532+41.8
X=56.33
A visit must be of at least 56.33 minutes to put a shopper in the longest 20 percent.
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Determine the intercepts of the line. Do not round your answers. 7x-5=4y-6
x intercept: (_),(_)
y intercept: (_),(_)
Please help!
The intercepts are x intercept: (-1/7,0) and y intercept: (0,1/4)
How to determine the intercepts?The function is given as:
7x-5=4y-6
Set y = 0 to determine the x-intercept
7x - 5 = -6
Add 5 to both sides
7x = -1
Divide by 7
x = -1/7
Set x = 0 to determine the y-intercept
- 5 = 4y - 6
Add 6 to both sides
4y = 1
Divide by 4
y = 1/4
Hence, the intercepts are x intercept: (-1/7,0) and y intercept: (0,1/4)
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Emily can read 30 pages in 45 minutes. At this rate, how many pages
will she read in 3 hours?
Explain how to solve 4^(x + 3) = 7 (x+3 being an exponent) using the change of base formula. Include the solution for x in your answer—round your answer to the nearest thousandth.
Using natural logarithms properties, we will see that:
x = -1.596
How to solve the equation?
Here we can use the property:
[tex]ln(a^b) = b*ln(a)[/tex]
Now we have the equation:
[tex]4^{x + 3 }= 7[/tex]
If we apply the natural logarithm in both sides, we get:
[tex]ln(4^{x + 3 })= ln(7)\\\\(x + 3)*ln(4) = ln(7)\\\\x + 3 = ln(7)/ln(4)\\\\x = ln(7)/ln(4) - 3 = log_4(7) - 3 = -1.596[/tex]
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Line $m$ is parallel to line $n$ and the measure of $\angle 1$ is $\frac 18$ the measure of $\angle 2$. What is the degree measure of $\angle 5$?
The angle of m∠5 is 116 degrees.
How to find angles when parallel lines are cut by a transversal?When parallel lines are cut by a transversal, angle relationships are formed. This include corresponding angles, alternate angles , vertical angles etc.
Therefore, line m and n are parallel lines cut by the a transversal.
Hence,
m∠2 = 64 degrees
Therefore,
m∠5 = m∠4 (alternate angles)
Therefore,
m∠5 + m∠2 = 180
m∠5 = 180 - 64
m∠5 = 116 degrees.
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The degree measure of the angle labelled 5; m<5 = 116°.
What is the measure of the angle labelled 5 in the task content?The angle measure of the angle labelled 5 as in the complete task content in the attached image can be determined as follows;
It follows from the complete task content that; that the measure of angle 2 is; 64°.
On this note, it follows from the sum of angle measures on a straight line theorem that; m<4 = 180° - 64° = 116°.
Additionally, it follows from the congruence of alternate angles theorem that <4 and <5 are congruent and hence, their measures are equal.
Therefore, m<5 = 116°.
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Can someone please help me on this
Answer:
? = 38°
Step-by-step explanation:
We can use the property of sine to find the missing angle value.
sin (angle) = opposite / hypotenuse
sin (?) = 16 / 26 <----- Insert values
? = sin⁻¹(16 / 26) <----- Rearrange
? = 37.97... <----- Solve
? = 38° <----- Round
Solve for xxx in the diagram below.
Answer:
x = 34
Step-by-step explanation:
The three angles form a straight line and are thus supplementary angles. The sum of a supplementary angles is always 180, so we can use the equation 180 = x + 12 + 100 + x to find x:
180 = 2x + 112
68 = 2x
x = 34
Which of the following statements about angles is NOT correct?
Complementary angles are two angles whose sum is 90 degrees.
The measure of an obtuse angle is always greater than the measure of an acute angle.
The measure of an acute angle and the measure of an obtuse angle added together will always
be supplementary.
Two right angles that share a leg are supplementary.
ANSWER: The third statement appears to be incorrect.
The area of the triangle shown is represented by A=s(s−12)(s−9)(s−7)−−−−−−−−−−−−−−−−−−−√, where s is equal to half the perimeter. What is the height h of the triangle? Round your answer to the nearest hundredth. (25 points to answer!! please))
The height h of the triangle is 5.42 ft
How to find height of a triangle?The height of the triangle can be found using the formula below:
Area = 1 / 2 bh
where
b = baseh = heightTherefore,
A = √s(s - a)(s - b)(s - c)
Hence,
s = 14 + 7 + 11 / 2 = 32 / 2 = 16
A = √16(16 - 11)(16 - 7)(16 - 14)
A = √1440
A = 37.947331922
A = 37.95 ft²
37.95 = 1 / 2 × 14 × h
h = 37.95 / 7
h = 5.42104741743
h = 5.42 ft
Therefore, the height h of the triangle is 5.42 ft
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Is the point (−2, 10) on the circle with radius 5 and center (2, 13)?
Answer:
yes
Step-by-step explanation:
The point can be demonstrated to lie on the circle by plotting both on a graph. It can also be shown to lie on the circle by showing the distance from center is equal to the radius.
GraphThe attachment shows a graph of the circle. Its equation is ...
(x -h)² +(y -k)² = r² . . . . . . for center (h, k) and radius r
We have (h, k) = (2, 13) and r = 5, so the equation is ...
(x -2)² +(y -13)² = 25 . . . . graphed equation
The point in question is also graphed, and is shown to lie on the circle.
DistanceIf the given point satisfies the circle's equation, it lies on the circle.
For (x, y) = (-2, 10), we find ...
(-2 -2)² +(10 -13)² = (-4)² +(-3)² = 16 +9 = 25 . . . . . the equation is satisfied
What is the distance between the points (4,3) and (1,-1) on the coordinate
plane?
A. 10 units
B. 50 units
C. 5 units
D. 25 units
Answer:
The distance between the points (4,3) and (1,-1) is C. 5 units.
Step-by-step explanation:
Can 1775 dollars buy 2 large balloons and 16 small balloons 1 large balloon = 300 cubic feet 1 small balloon - 40 cubic feet helium costs $1.60 per cubic foot
No, 1775 dollars cannot buy 2 large balloons and 16 small balloons if helium costs $1.60 per cubic foot.
Calculating the Costs of Balloons
It is given that,
Helium costs $1.60 per cubic foot.
Volume of one large balloon = 300 cubic feet
Thus, the price of one large balloon = $1.60 × 300
= $480
Volume of one small balloon = 40 cubic feet
Thus, the price of one small balloon = $1.60 × 40
= $64
How much buying 2 large and 16 small balloons costs?
So, as calculated above,
One large balloon costs $480, and one small balloon costs $64
Therefore, the cost of two large balloons = $480 × 2
= $960
Cost of 16 small balloons = $64 × 16
= $1024
Total cost of balloons = $960 + $ 1024
= $1984
Since, $1984>$1775,
Therefore, $1775 cannot buy all those balloons if helium costs $1.60 per cubic foot.
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Determine if y varies directly with x. Give the constant of variation, when appropriate. (picture below)
A) Does y vary directly with x?
B) What is the constant of variation?
Based on the given variation, y does not vary directly with x and the constant of variation are 8, 3.2 and 1.25 respectively.
Variationy = k × x
where,
k = constant of proportionality
y = -40
x = -5
y = k × x
-40 = k × -5
-40 = -5k
k = -40/-5
k = 8
when,
y = 8 and x = 2.5
y = k × x
8 = k × 2.5
8 = 2.5k
k = 8/2.5
k = 3.2
when,
y = 5 and x = 4
y = k × x
5 = k × 4
5 = 4k
k = 5/4
k = 1.25
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1. The length of a rectangle is four
times its width. If the area is 100m
what is the length of the rectangle
Answer:
20m
Step-by-step explanation:
write a equation duh
x * 4x = 100
u can split 100 into 5 x 20
x * 4x = 5 * 20
x = 5
and 4x = 20
please put it in expanded form and solve it
Answer:
1/xyz^3
Step-by-step explanation:
exponents are subtracted when divided
x^0 is 1
negative exponents are positive in the denominator
(4x^0y^-2z^-3) / (4xy-1)
(4xy^-2z^-3) / (4xy^-1)
x-1y^-1z^-3
1/xyz^3
Analyzing the Discrim
Which values of c will cause the quadratic equation-x²+3x+c=0 to have no real number solutions? Check all that
apply.
0-5
0 0 0
9
Intro
ant of a Quadratic Equation
Done
The values of x that will give the quadratic equation no real number solutions are -5 and 9
What are real roots of a quadratic equation?Real roots of a quadratic equation are values of x, whose numbers can be represented on a number line.
Analysis:
We have -[tex]x^{2}[/tex] +3x +c = 0
[tex]b^{2}[/tex] - 4ac is called the discriminant of a quadratic equation.
if [tex]b^{2}[/tex] - 4ac < 0, then the quadratic equation has no real root.
where a = -1, b = 3 c = c
[tex](3)^{2}[/tex] -4(-1)c < 0
9 + 4c < 0
4c < -9
c < -9/2
Which means values lower than -9/2 would give the solution no real root.
From, the options, only -5 would give no real solution, since it is lower than -9/2.
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The graph below shows two polynomial functions, f(x) and g(x): Graph of f of x equals x squared minus 2 x plus 1. Graph of g of x equals x cubed plus 1 Which of the following statements is true about the graph above? (4 points) f(x) is an even degree polynomial with a negative leading coefficient. g(x) is an even degree polynomial with a negative leading coefficient. f(x) is an odd degree polynomial with a positive leading coefficient. g(x) is an odd degree polynomial with a positive leading coefficient.
Last option. The correct statement about the graph is g(x) is an odd degree polynomial with a positive leading coefficient.
How to solve the questionWe have the function as
[tex]f(x) = x^2 - 2x + 1[/tex]
The polynomial that we have here is of an even degree. The highest degree we have here is 2. The coefficient that has the highest degree is 1.
Hence all of the options that have f(x) are incorrect.
The answer to the question is option 4.
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Solve the polynomial congruence x^2-3x+2 is congruent to 0 mod 5. Solve for x=? or x=?,when k is any integer
The solutions of x² - 3x + 2 ≡ mod 5 does not exist.
How to solve Polynomial Congruence?
We are given the Polynomial;
x² - 3x + 2 ≡ mod 5
Finding the roots of the equation gives;
x² - 2x - x + 2 = 0(mod 5)
x(x - 2) - 1(x - 2) = 0(mod 5)
Thus, RHS = 0(mod 5) = 0
The roots of the equation are;
x = 1 and x = 2
Thus, the solutions of x² - 3x + 2 ≡ mod 5 does not exist.
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Does anyone know how to do this
Considering the area of the rectangle, we have that the length is of 8 units and the width is of 10 units.
What is the area of a rectangle?The area of a rectangle of length l and width w is given as follows:
A = lw.
In this problem, the area is of 80 square units, while the length and the width are consecutive even integers, hence:
A = 80.w = l + 2.Then:
l(l + 2) = 80
l² + 2l - 80 = 0
(l + 10)(l - 8) = 0.
We need the positive measure, hence:
l - 8= 0 -> l = 8 units.
w = l + 2 = 10 units.
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Can someone pls pls PLS, help me out? ASAP!! (Geometry)
“Complete the proof”
1) [tex]\overline{AB} \perp \overline{BD}[/tex], [tex]\overline{AB} \cong \overline{DB}[/tex], [tex]\overline{AC} \cong \overline{DE}[/tex] (given)
2) [tex]\angle ABD[/tex] is a right angle (perpendicular lines form right angles)
3) [tex]\triangle ABD[/tex] and [tex]\triangle DEB[/tex] are right triangles (a triangle with a right angle is a right angle)
4) [tex]\triangle ABD \cong \triangle DEB[/tex] (HL)
5) [tex]\angle ACB \cong \angle DEB[/tex] (CPCTC)
Identify the factors of 6ab − 8a 21b − 28. (2a 4)(3b − 7) (2a − 4)(3b 7) (2a 7)(3b − 4) (2a − 7)(3b 4)
Answer: ) (2a+7)(3b- 4)
Step-by-step explanation:
11y^2-xy dxUse the method for solving homogeneous equations to solve the following differential equation.
The solution to the homogenous differential equation, (11y² - xy)dx + x²dy = 0, is [tex]y = \frac{x}{11 ln (x) + C}[/tex].
A homogeneous differential equation has a homogeneous function as one of its components, if f(λx, λy) = λⁿf(x, y), for any non-zero constant λ, the function is said to be homogenous. The homogeneous differential equation's generic form is of the type f(x, y).dy + g(x, y).dx = 0. The degree of the homogeneous differential equation is the same for the equation's variables x and y.
In the question, we are asked to solve the homogeneous differential equation, (11y² - xy)dx + x²dy = 0.
The given equation can be solved as follows:
Grouping by differentials, gives us: x²dy = (xy - 11y²)dx.We now substitute, u = yx, making y = ux, or, dy = u.dx + x.du.Making the substitutions, we get: x²(u.dx + x.du) = (u - 11u²)x²dx.Expanding the parentheses, we get: ux².dx + x³.du = ux².dx - 11u²x².dx.Reducing ux².dx, we get: x³.du = -11u²x².dx.Dividing by x³ and u², we get du/u² = -11/x.Now, we integrate both sides of the equation: [tex]\int \frac{1}{u^2}du = \int -\frac{11}{x}dx[/tex]Calculating the resulting integrals, we get: -1/u = C - 11 ln(x).Undoing the substitution, u = y/x, we get: -x/y = C - 11 ln(x)The final solution is: [tex]y = \frac{x}{11 ln (x) + C}[/tex]Thus, the solution to the homogenous differential equation, (11y² - xy)dx + x²dy = 0, is [tex]y = \frac{x}{11 ln (x) + C}[/tex].
The provided question is incomplete. The complete question is:
"Use the method for solving homogenous equations to solve the following differential equation.
(11y² - xy)dx + x²dy = 0".
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What are the solutions of sin(2theta)+sin(theta)=cos(theta) on the interval [0, 360]
The solutions are: θ = 90º, 270º, 30º, and 150º
Given,
sin2θ = cosθ
sin2 θ = 2sinθ cosθ
2sinθ cosθ = cosθ
2sinθ cosθ - cosθ = 0
factor
cosθ(2sinθ-1) = 0
cosθ = 0 or 2sinθ - 1 = 0
cosθ = 0 when θ=90º or θ=270º (look on the unit circle)
2sinθ - 1 = 0
2sinθ = 1
sinθ = 1/2
look at the unit circle and see that sinθ=1/2 when θ=30º
sin is positive in Quadrant2 as well as Quadrant 1
180º-30º=150º
θ=150º
answers: θ=90º, 270º, 30º, and 150º
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The lengths of three sides of a triangle are 2x + 1/5 feet , 4x + 1/2 feet , and x+ 1 5 . what is the perimeter of the triangle? the drondown menuto complete the answer
Answer:
7x + 9/10 ft
Step-by-step explanation:
To find the perimeter of a triangle, add the lengths of the three sides
P = 2x + 1/5 + 4x + 1/2 + x+ 1/ 5
Combine like terms
P = 7x + 2/5 +1/2
Get a common denominator
P = 7x + 2/5(2/2) + 1/2 * (5/5)
= 7x + 4/10 + 5/10
= 7x + 9/10