Which expression is equivalent to startroot 8 x superscript 7 baseline y superscript 8 baseline endroot? assume x greater-than-or-equal-to 0.

Answers

Answer 1

Expression which is equivalent to [tex]$\sqrt{8 x^{7} y^{8}}[/tex] is [tex]$=2 \sqrt{2} x^{3} y^{4} \sqrt{x}$[/tex].

What are equivalent expressions?

Expressions that function identically despite having distinct appearances are called equivalent expressions. If two algebraic expressions are equivalent, then when we enter the same value(s) for the variable, the two expressions have the same value (s).

Solution of the given equation [tex]$\sqrt{8 x^{7} y^{8}}[/tex].

      [tex]$\sqrt{8 x^{7} y^{8}}=\sqrt{8} \sqrt{x^{7}} \sqrt{y^{8}}$[/tex]

                    [tex]$=\sqrt{8} \sqrt{x^{7}} \sqrt{y^{8}}$[/tex]

Simplify [tex]$\sqrt{x^{7}}: x^{3} \sqrt{x}$[/tex]

                     [tex]$=\sqrt{8} x^{3} \sqrt{x} \sqrt{y^{8}}$[/tex]

Simplify [tex]$\sqrt{y^{8}}: y^{4}$[/tex]

                     [tex]$=\sqrt{8} x^{3} \sqrt{x} y^{4}$[/tex]

                [tex]$\sqrt{8}=2 \sqrt{2}$[/tex]

                     [tex]$=2 \sqrt{2} x^{3} \sqrt{x} y^{4}$[/tex]

                     

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The complete question is :

Which expression is equivalent to StartRoot 8 x Superscript 7 Baseline y Superscript 8 Baseline EndRoot? Assume x greater-than-or-equal-to 0. x y squared StartRoot 8 x cubed EndRoot 2 x cubed y cubed StartRoot x y squared EndRoot 2 x cubed y Superscript 4 Baseline StartRoot 2 x EndRoot 4 x cubed y Superscript 4 Baseline StartRoot x EndRoot


Related Questions

An account pays 8% per year simple interest. in year 1, the amount in the account is $850. how much is in the account in year 6?

Answers

Answer:

Step-by-step explanation:

$1,248.92

Alek is taking an inventory of styles of compression bandages for work. Here is the data he has collected.

Answers

The individuals in this data set that can be gotten is B) Compression bandage styles and this data set contains A) 3 variables, 1 of which is categorical.

What is  categorical variable ?

A categorical variables serve as the variable type that posses two or more categories.

This categories could be nominal variable, however considering the data , we can see that the first two are quantitative data and the data are:

WidthTotal lengthColor

THE COMPLETE QUESTION IS:

Alek is taking an inventory of styles of compression bandages for work. Here is the data he has collected.

The individuals in this data set are:Choose 1 answer:

A) Blood Centers

B) Compression bandage styles

C) Nurses

This data set contains:Choose 1 Answer:

A) 3 variables, 1 of which is categorical

B) 3 variables, 3 of which are categorical

C) 6 variables, 1 of which categorical

D) 6 variables, 3 of which are categorical

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The water was pumped out of a backyard pond. What is the domain of this graph?

Answers

quick answer (A)

ALL real numbers less than or equal to 8

What numbers are zeros of g(x) = x^2 - 2x - 4? take your time if you need to!

Answers

Answer:

[tex]x = 1 + \sqrt5, x = 1 - \sqrt5[/tex]

Step-by-step explanation:

Hello!

We can solve the quadratic by using the quadratic formula.

Standard form of a quadratic: [tex]ax^2 + bx + c = 0[/tex]

Quadratic Formula: [tex]x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}[/tex]

Given our Equation: [tex]g(x) = x^2 - 2x - 4[/tex]

a = 1b = -2c = -4

Plug the values into the equation and solve.

Solve[tex]x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}[/tex][tex]x = \frac{-(-2)\pm\sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}[/tex][tex]x = \frac{2\pm\sqrt{4 +16}}{2}[/tex][tex]x = \frac{2\pm\sqrt{20}}{2}[/tex][tex]x = \frac{2\pm\sqrt{4 * 5}}{2}[/tex][tex]x = \frac{2\pm(\sqrt4 * \sqrt5)}{2}[/tex][tex]x = \frac{2\pm2\sqrt5}{2}[/tex][tex]x = 1 + \sqrt5, x = 1 - \sqrt5[/tex]

PLEASE HELP IM STUCK

Answers

Step-by-step explanation:

[tex] \frac{y2 - y1 }{x2 - x1} = \frac{3 - - 2}{5 - 0} = \frac{5}{5} = 1[/tex]

Step-by-step explanation:
Hey there!
Here, given;
The points are; (0,-2) and (5,3).
Now, simply use slope formula.
slope(m)
y?-yl
7
^ 4.2
Put all values.
3+2
m
Simplify them to get answer.
3
Therefore the slope is 1.
Hope it helps…

How would I solve this?? My math course didn't teach me anything related to this sort of problem..

Answers

Answer:

See below

Step-by-step explanation:

The larger is  

7-6 = 1 unit bigger than the smaller....and this unit = 24 gallons

   each unit is 24 gallons

larger barrel holds   24 * 7 = 168 gal

smaller barrel holds  24 * 6 = 144 gal

Answer:

Small barrel=144 large barrel=168

Step-by-step explanation:

The ratio is 6 to 7 so lets assign x as a factor.

6x=Small barrel (S)

7x=Large barrel (L)

7x-6x=x

x is the difference so x is 24

x=24

6*24=144=S

7*24=168=L

(14x2 + 13x + 12) + (7x2 + 20x + 4)

Answers

Answer:

21x^2 + 33x + 16

Step-by-step explanation:

(14x^2 + 13x + 12) + (7x^2 + 20x + 4)

Combine like terms:

14x^2 + 7x^2 = 21x^2

13x + 20x = 33x

12 + 4 = 16

Thus:

21x^2 + 33x + 16

Answer:

21x^2 + 33x + 16.

Step-by-step explanation:

(14x2 + 13x + 12) + (7x2 + 20x + 4)   Remove the parentheses:

= 14x2 + 13x + 12 + 7x2 + 20x + 4    Bring like terms togethher:

= 14x^2 + 7x^2 + 13x + 20x + 12 + 4

= 21x^2 + 33x + 16.

In a math class of $30$ students, $12$ out of $15$ girls are freshmen and $11$ out of $15$ boys are freshmen. What is the probability that in a randomly selected group of five students from the class, there will be two freshmen girls and three freshmen boys

Answers

The probability of selecting five students from the class, where there will be two freshmen girls and three freshmen boys is 0.23 approximately.

What is Probability ?

Probability is the game of chance. Probability of an event is the ratio of the required outcome to the total possible outcome.

Given that In a math class of 30 students, 12 out of 15 girls are freshmen and 11 out of 15 boys are freshmen. In Probability, the word "and" means multiplication

The probability that in a randomly selected group of five students from the class, there will be two freshmen girls and three freshmen boys can be expressed as follow

12/15 x 11/14 x 11/15 x 10/14 x 9/13

132/210 x 990/2730

130680/573300

0.2279

Therefore, the probability that in a randomly selected group of five students from the class, there will be two freshmen girls and three freshmen boys is 0.23 approximately.

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(4x⁴-4x²-x-3) ÷ (2x²-3)


so far i have 2x²+1+?/2x²-3
what is the question mark? ​

Answers

Answer:

[tex]2x^2+1-\dfrac{x}{2x^2-3}[/tex]

Step-by-step explanation:

Use the long division method to divide polynomials:

[tex]\large \begin{array}{r}2x^2\phantom{)))))}+1\phantom{)}\\2x^2-3{\overline{\smash{\big)}\,4x^4-4x^2-x-3\phantom{)}}}\\\underline{-~\phantom{(}(4x^4-6x^2)\phantom{-b))))))}}\\0+2x^2-x-3\phantom{)}\\\underline{-~\phantom{()}(2x^2\phantom{))))}-3)}\\-x\phantom{))))))}\end{array}[/tex]

Therefore:

[tex]\dfrac{4x^4-4x^2-x-3}{2x^2-3}=2x^2+1-\dfrac{x}{2x^2-3}[/tex]

30 points please help me

Answers

The area of the shaded region = area of larger circle - area of smaller circle = 423.9 yd².

What is the Area of a Circle?

Area = πr²

Area of the shaded region = area of larger circle - area of smaller circle

Area of larger circle = πr² = (3.14)(16²) = 803.84 yd²

Area of smaller circle = πr² = (3.14)(11²) = 379.94 yd²

Area of the shaded region = 803.84 - 379.94 = 423.9 yd².

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Which system of equations can you use to find the roots of the equation 2x3 4x2 – x 5 = –3x2 4x 9? y = 2x3 x2 3x 5 y =9 y = 2x3 x2 y = 3x 14 y = 2x3 4x2 – x 5 y = –3x2 4x 9

Answers

Finding the roots of an equation is done using the equation systems  [tex]y=2x^{3}+4x^{2} -x+5[/tex] & [tex]y= -3x^{2} +4x+9[/tex] .

Determining the roots of the equation

This equation seems to have the following form:[tex]2x^{3}+4x^{2} -x+5= -3x^{2} +4x+9[/tex]

We must assess the appropriate set of equations that may be utilized to identify the equation's roots.

By drawing the equations' graph, we may determine the equation's root. We can suppose that the left and right sides of the following equations are two independent equations for the sake of graphing.

Therefore,

[tex]y=2x^{3}+4x^{2} -x+5[/tex]

[tex]y= -3x^{2} +4x+9[/tex]

The graphs of these two equations are now shown in the identical coordinate plane. The roots of the equation given will be the crossing point(s).

The equation system that we may utilize to get the root of the formula given is thus,

[tex]y=2x^{3}+4x^{2} -x+5[/tex]

[tex]y= -3x^{2} +4x+9[/tex]

So, the correct answer is option C.

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Calculate the first difference between 7, and where 7,-688. 2​

Answers

The difference between the numbers given is 6.882.

How to illustrate the information?

Based on the information given, it should be noted that difference means subtraction.

The difference between the numbers given will be:

= 7 - (7 - 6.882)

= 7 - 0.118

= 6.882

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x/2+y=4/5. x+y/2=7/10

Answers

Answer:

x = 2/5

y = 3/5

Step-by-step explanation:

**Disclaimer** Hi there! I assumed the question to be a system of equations. The following answer is a method for solving a system of equations. Thus, if it is not, please let me know and I will modify my answer.

Given information:

[tex]\frac{x}{2}+y=\frac{4}{5}[/tex]

[tex]x+\frac{y}{2} =\frac{7}{10}[/tex]

Eliminate fractions by multiplying 10 on both sides of the first equation:

[tex]10*\frac{x}{2}+10*y=10*\frac{4}{5}[/tex]

[tex]5x+10y=8[/tex]

Eliminate fractions by multiplying 10 on both sides of the second equation:

[tex]10*x+10*\frac{y}{2} =10*\frac{7}{10}[/tex]

[tex]10x+5y=7[/tex]

Current system:

[tex]5x+10y=8[/tex]

[tex]10x+5y=7[/tex]

Multiply the second equation by 2:

[tex]5x+10y=8[/tex]

[tex]20x+10y=14[/tex]

Subtract the first equation from the second equation:

[tex](20x+10y)-(5x+10y)=14-8[/tex]

[tex]20x+10y-5x-10y=6[/tex]

[tex](10y-10y)+20x-5x=6[/tex]

[tex]0+15x=6[/tex]

[tex]\boxed{x=\frac{2}{5} }[/tex]

Substitute the x value back to one of the equations to get the y value:

[tex]x+\frac{y}{2} =\frac{7}{10}[/tex]

[tex](\frac{2}{5}) +\frac{y}{2} =\frac{7}{10}[/tex]

[tex](\frac{2}{5}) +\frac{y}{2}-\frac{2}{5} =\frac{7}{10}-\frac{2}{5}[/tex]

[tex]\frac{y}{2} =\frac{3}{10}[/tex]

[tex]\frac{y}{2}*2 =\frac{3}{10}*2[/tex]

[tex]\boxed{y=\frac{3}{5} }[/tex]

Hope this helps!! :)

Please let me know if you have any questions

The answer is x = 2/5, y = 3/5 or (2/5, 3/5)

First, in order to avoid fractional values during calculation, multiply both equations by 10 to simplify.

10 (x/2 + y) = 10 (4/5) ⇒ 5x + 10y = 810 (x + y/2) = 10 (7/10) ⇒ 10x + 5y = 7

Multiply the 1st equation by 10 and 2nd equation by 5.

    3. 10 (5x +  10y) = 10 (8) ⇒ 50x + 100y = 80

    4. 5 (10x + 5y) = 5 (7) ⇒ 50x + 25y = 35

Subtract : 3rd equation - 4th equation

50x + 100y - 50x - 25y = 80 - 3575y = 45y = 3/5

Now, substitute for x in the 1st equation to find y.

x/2 + 3/5 = 4/5x/2 = 1/5x = 2/5

HELPPP PLEASEEEE

Other than translation, what transformation is used to create this frieze pattern?

horizontal reflection

glide reflection

vertical reflection

90° rotation

Answers

Answer:

I think glide reflection

Step-by-step explanation:

a certain video on yt had explained the examples of similar look alike this picture

Determine the missing coordinate in the ordered pair (?,5) so that it will satisfy x+6y=18

Answers

We can start by rewriting the equation:

x + 6y = 18

Because we already have our y-coordinate, we can plug it in for the equation.

x + 6(5) = 18

Now we can simplify.

x + 30 = 18

Since we are adding 30 to a number to get another number less than 30, we can presume that x equals a negative number. 30 - 18 = 12. That means that x would equal -12.

Now we can plug -12 in as x to see if our equation is valid.

-12 + 30 = 18

Because negative 12 added to 30 does equal 18, we know that our equation is correct.

Your final answer: The missing coordinate is -12. The final ordered pair is (-12,5). If you need help understanding, let me know and I will gladly assist you.

Which expression is equivalent to startfraction 3 x superscript negative 6 baseline y superscript negative 3 baseline over 15 x squared y superscript 10 baseline endfraction? assume x not-equals 0, y not-equals 0

Answers

The equivalent expression of [tex]\frac{3x^{-6}y^{-3}}{15x^2y^{10}}[/tex] is [tex]\frac{1}{5x^{8}y^{13}}[/tex]

How to determine the equivalent expression?

The expression is given as:

[tex]\frac{3x^{-6}y^{-3}}{15x^2y^{10}}[/tex]

Divide 3 and 15 by 3

[tex]\frac{x^{-6}y^{-3}}{5x^2y^{10}}[/tex]

Apply the law of indices

[tex]\frac{1}{5x^{2+6}y^{10+3}}[/tex]

Evaluate the sum

[tex]\frac{1}{5x^{8}y^{13}}[/tex]

Hence, the equivalent expression of [tex]\frac{3x^{-6}y^{-3}}{15x^2y^{10}}[/tex] is [tex]\frac{1}{5x^{8}y^{13}}[/tex]

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there are three red marbles 5 green marbles 2 blue marbles in a bag which of the follwing are true

Answers

Answer:

4 and 1

Step-by-step explanation:

how do you graph y=12/x

Answers

Answer: [tex]\frac{12}{x}[/tex] is an asymptote

Step-by-step explanation:

Apply a table, and plug in values of x into the equation.  For example f(2)=[tex]\frac{12}{2} =6[/tex]. That's one of the points on the graph that we just found (2,6)

What three-dimensional object would be generated by the rotation of the semi circle about the x axis ?

Answers

If a semicircle is rotated about the x axis of the graph then the resulting three dimensional shape will be a sphere.

Given a semicircle on a graph.

A semicircle is a half circle .A sphere is a geometrical object that is a three dimensional  shape , It is the set of points that are all at the same distance r from given point in three dimensional shape.

Rotation is basically an action of rotating around an object or an axis.

If a semicircle is rotated about x axis then the resulting figure will be a sphere. This is because of the fact that when the semi circle is rotated about the x axis then all the points will be at equal distance in all directions from the center.

Hence if a semicircle is rotated about x axis then the resulting figure will be a sphere.

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2. Rotate the following points 180°.

a.) B(-2,-5) →B'( )
b.) B(-4,1) B'( )

c.) In the graphs above connect the pre-image point B to the origin. Then connect
the origin to the image point B. What angle has been formed?

Answers

Answer:

hi helo bol ke gatu jama gol ke

Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options.


The radius of the circle is 3 units.
The center of the circle lies on the x-axis.
The center of the circle lies on the y-axis.
The standard form of the equation is (x – 1)² + y² = 3.
The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

Answers

The center of the circle lies on the x-axis

The radius of the circle is 3 units.

The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

How to determine the statements

The standard equation of a circle is expressed as:

[tex]x^2 + y^2 + 2gx + 2fy + C = 0[/tex]

Where

Centre is (-g, -f)radius = √g²+f²-C

Given a circle whose equation is

Let's get the center of the circle

2gx = -2x

2g = -2

We have that;

g = -1

Similarly, 2fy = 0

given that

f = 0

Centre = (-(-1), 0) = (1, 0)

This explains that the center of the circle lies on the x-axis

We move further to the radius

r = radius = √g²+f²-C

radius = √1²+0²-(-8)

radius =√9

= 3 units

The radius of the circle is 3 units.

For the circle x² + y² = 9, the radius is expressed as:

r² = 9

r = 3 units

Hence the radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

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The function f has the property that, for all x, 5(f)x=f(5x). If f(20)=40, what is the value of f(4)?

Answers

Using the given property, we conclude that:

f(4) = 8

What is the value of f(4)?

We know that our function has the property:

5*f(x) = f(5*x)

Now, we also know that:

f(20) = 40

Notice that we can rewrite:

f(20) = f(5*4)

Using the above property, we know that:

f(20) = f(5*4) = 5*f(4) = 40

Using the last part:

5*f(4) = 40

f(4) = 40/5 = 8

f(4) = 8

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what is the circumference?

Answers


1 : the perimeter of a circle The circle measures 22 inches in circumference. 2 : the external boundary or surface of a figure or object : periphery from the center to the circumference of the sphere.

Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.

x < 5
–6x – 5 < 10 – x
–6x + 15 < 10 – 5x
A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.

Answers

The correct statements are –6x + 15 < 10 – 5x and a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

Inequality expression

Inequality are expressions not separated by an equal sign. Given the inequality expression:

–3(2x – 5) < 5(2 – x)

Expand

-6x +15 < 10 - 5x

Collect the like terms

-6x+5x < 10 - 15

-x <-5

x > 5

Hence the correct statements are –6x + 15 < 10 – 5x and a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

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Speedy Swift is a package delivery service that serves the greater Atlanta, Georgia, metropolitan area. To maintain customer loyalty, one of Speedy Swift's performance objectives is on-time delivery. To monitor its performance, each delivery is measured on the following scale: early (package delivered before the promised time), on-time (package delivered within 15 minutes of the promised time), late (package delivered more than 15 minutes past the promised time), or lost (package never delivered). Speedy Swift's objective is to deliver 99% of all packages either early or on-time.
Speedy collected the following data for last month's performance:
On-time On-time Early Late On-time On-time On-time On-time Late On-time
Early On-time On-time Early On-time On-time On-time On-time On-time On-time
Early On-time Early On-time On-time On-time Early On-time On-time On-time
Early On-time On-time Early Early Early On-time Loss On-time Early
Late Late Late On-time On-time On-time On-time On-time On-time On-time
On-time Late Early On-time Early On-time Lost On-time On-time On-time
Early Early On-time On-time Late Early Early On-time On-time On-time
On-time On-time Early On-time Early On-time Early On-time Late On-time
On-time Early On-time On-time On-time Late On-time Lost On-time On-time
On-time On-time On-time On-time On-time Early Early On-time On-time On-time
(a) What scale is used to measure delivery performance? What kind of variable is delivery performance?
(b) Construct a frequency table for delivery performance for last month.
(c) Construct a relative frequency table for delivery performance last month.

Answers

(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.

The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.

(b) The frequency table of the given data is:

Variable Frequency

Early  23

On-time  65

Late            9

Lost            3

Total 100.

(c) The relative frequency table for the given data is:

Variable Frequency Relative frequency

Early  23           23/100 = 0.23 = 23%

On-time  65           65/100 = 0.65 = 65%

Late            9             9/100 = 0.09 = 9%

Lost            3             3/100 = 0.03 = 3%

(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.

The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.

(b) The frequency table is a table showing frequency of each variable for the number of times they appear in the data.

The frequency table of the given data is:

Variable Frequency

Early  23

On-time  65

Late            9

Lost            3

Total 100.

(c) The relative frequency for a variable is the ratio of its frequency to the total frequency.

The relative frequency table for the given data is:

Variable Frequency Relative frequency

Early  23           23/100 = 0.23 = 23%

On-time  65           65/100 = 0.65 = 65%

Late            9             9/100 = 0.09 = 9%

Lost            3             3/100 = 0.03 = 3%

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Answer:

C.

Step-by-step explanation:

the number 40 cannot be decomposed into prime factors

True
either
False​

Answers

[tex]\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\large{\textsf{\textbf{\underline{\underline{Answer : \:}}}}}}[/tex]

False, because the number 40 is a composite number, those that cannot be broken down are called Prime Numbers.

Prime numbers are numbers that are used to decompose any number, but prime numbers cannot be decomposed, since they only have two Divisors, which are 1 and itself.

[tex]~\sf{Atte: Murdock:)}[/tex]

Answer: False

Step-by-step explanation:

All whole numbers can be decomposed into prime factors. For the number 40, the prime factorization would be [tex]2 * 2 * 2*5[/tex]. Since all 4 of those numbers are prime numbers, the answer is false.

Solve the equation by completing the square

Answers

Answer:

Below.

Step-by-step explanation:

x^2 + 4x  = 18

x^2 + 4x + (2)^2 = 15 + 2^2

x^2 + 4x + 4 = 18 + 4

(x + 2)^2 = 22

x  + 2 = +/- √22

x = -2 + √22 and x =  -2 + √22

x = 2.7  and -6.7  to nearest tenth.

What are the solutions of the equation (2x 3)2 8(2x 3) 11 = 0? use u substitution and the quadratic formula to solve.

Answers

Answer:

Step-by-step explanation:

terrell watched 300 dogs being groomed. He found that 0.35 of the groomed dogs tried to bite the groomer. what percent of dogs did not try to bite the groomer?

Answers

The percentage of dogs who didn't try to bite the groomer is; 65%.

What is the percentage of dogs that did not try to bite the groomer?

If follows from the task content that the number of dogs is 300 of which, 0.35 faction of the whole tried to bite the groomer.

Hence, the faction that did not try to bite the groomer is; 0.65 which corresponds to 65% when expressed as a percentage.

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Someone help me please

Answers

Answer:

2√10

Step-by-step explanation:

We can use the Pythagorean theorem to solve this because it is a right triangle. a^2+b^2 = c^2

7^2-3^2 = x^2

49-9 = x^2

40 = x^2

√4*√10 = 2√10

Other Questions
Which of the following is NOT a monomial?OxO -2x-3O155 Help asap please!! I will mark brainlest and give me the work De la obra Romeo y Julieta describe las caractersticas que encuentres del renacimiento? A 12 kg object speeds up from an initial velocity of 10 m/s north to a final velocity of 15 m/s north. Calculate the change in momentum Unlike Electromagnetic waves, Mechanical waves need a totransfer energy ASAP mark Brainliest, Which of these details does not support the central idea central idea: even though one of Edisons investors failed, he never stopped trying out new ideas Help I will be marking brainliest!A. 65.99B. 70.19C. 52D. 65.52 Three shops A, B and C sold cars in January, Februaryand March. The total number of cars sold in this three-Three shops A.respectively. Both A and C sold the same number ofcars in January. The number of cars sold by A and C inMarch was also the same. A sold 120 cars in Februarywhich was half of the number of cars sold by C inMarch. Both A and B sold exactly the same number ofcars in February. The ratio of the number of cars sold byB in January and March was 1:4.What was the ratio of the total number of cars sold inJanuary, February and March by the three shops?month period by A, B and C were 460, 320 and 500 Help me out plz ??? Real k A weight of 6 lb stretches a spring a distance of 12 in. Find the constant k for the spring. Water, ice, wind, sand, and chemicals are constantly crumbling mountains, flattening hills, widening valleys, and deepening canyons. __________________ never stops After reading this text and looking at the picture, which new idea can Jillian form about Delicate Arch?Delicate Arch was probably called "Cowboy Chaps" because it looks like a pair of pants a cowboy would wear.It was probably very difficult for Olympic runners to pass through Delicate Arch.It is not likely that other natural arches like this are found anywhere else in the world.Arches are perhaps the only landforms made by wind and water. On a car trip you drive for 2 hours and 41 minutes on a highway at a speed of 107.0 km/h. Then you stop at a gas station to fill up your tank. You also eat a quick lunch. The whole break lasts 23 minutes. After the break you start your engine up and you switch to a state road. You drive for another 3 hours and 31 minutes at a speed of 67.0 km/h before you arrive to your destination. What was your average speed for the whole trip with the lunchbreak included PLEASE HELP OMGjust put this equation into y = mx + b7x + 8y = -12* my answer was y = -7/8x - 12/8(is there supposed to be two fractions? did i do it right?) During G1, there is a great amount of protein _____________________ occurring. pleade help and show work tan^2 30 +tan ^2 45+tan^2 60 It is true or false? The majority of Amazon tribes practice some form of animism. QUESTION 10 of 10: You are planning to place an ad in a local newspaper. The size of the ad is 6 inches long by 5 columns wide. Thenewspaper's rate per column inch is $20. How much will the ad cost?a) $600b) $625c) $635d) $645 Salesman Scott received $2,792.79 for selling a property. If the gross commission was 6.5 % of the sale price, the listing salesman received 12% of the gross commission and Scott received 45% of the balance, how much did the property sell for?